R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
Y OSHIAKI F UKUMA
On k-very ampleness of tensor products of ample line bundles on abelian surfaces
Rendiconti del Seminario Matematico della Università di Padova, tome 101 (1999), p. 209-227
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
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of Ample Line Bundles
onAbelian Surfaces (*).
YOSHIAKI
FUKUMA (**)
ABSTRACT - In this paper, we
study
abelian surfaces X andample
line bundlesL1,
... ,L,
such that L:= L1
+ ...+ Lt
is notk-very ample
for t = k, k + 1. Andwe also
study polarized
abelian surfaces (X, L) such that ( k - t ) L is not k-very
ample
with t ~ 1 under some condition. As corollaries of the above re-sults, we get the classification of (X, L ) such that ( k - t ) L is not
k-very ample
fort=-1,0,1 and 2.0. Introduction.
Let X be an abelian
variety
over thecomplex
number field C and let L be anample
line bundle on X. Then it is well-known that 2L isspanned
and 3L is very
ample. (See [LB].)
In[BaSzl]
and[BaSz2],
Bauer andSzemberg
studied a sufficient condition ofk-very ampleness
ofL1
+ ... ++
Lk
+ 1 forample
line bundlesLl ,
... ,Lk
+ 1. Inparticular,
in[BaSz2],
as acorollary, they proved
thatL1
+ ... +Lk
+ 2 isk-very ample
for anyample
line bundles
L1,
... ,Lk
+ 2 .Next the
following question
arises from theBauer-Szemberg
re-sult ;
(*) Research Fellow of the
Japan Society
for the Promotion of Science.(**) Indirizzo dell’A.: E-mail:
[email protected].
Current Address:Department
of Mathematics,College
of Education, NarutoUniversity
of Educa- tion, Takashima, Naruto-cho, Naruto-shi 772-8502,Japan;
E-mail: fukuma@na-ruto-u. ac. j p
QUESTION.
Let X be an abelianvariety
X and letL1,
... ,L,
beample
line bundles on X for s ~ k + 1. Then
classify (X, Li , ... , Ls )
such thatL1
+ ... +L,
is notk-very ample.
Ohbuchi
([0])
studiedpolarized
abelian varieties(X, L)
such that 2L is not veryample.
In sect.
2,
westudy
abelian surfaces X andample
line bundlesL1, ... , Lt
such thatL : = L1 + ... + Lt
is notk-very ample
fort = k,
k+1.
In sect.
3,
westudy polarized
abelian surfaces(X, L)
such that(k -
-
t)
L is notk-very ample
with t > 1 under some condition. Inparticular,
we characterize
(X, L)
such that( k - t)L
is notk-very ample
with t =1or 2.
(See
Theorem 3.4 and Theorem3.5.)
We work over the
complex
number field and we use thecustomary
notation in
algebraic geometry.
Acknowledgment.
The author would like to express hishearty
thanksto Professor Tomasz
Szemberg
forgiving
him some useful commentsand
suggestions.
The author also would like to thank the referee forgiv- ing
him useful comments.1. Preliminaries.
DEFINITION 1.1.
(See [BeSo].) -
Let(X, L)
be apolarized
surface.Then L is called
k-very ample
if for any 0-dimensional subscheme(Z,
withlength
c9z = k +1,
the mapis
surjective.
LEMMA 1.2. Let X be an abelian
surface.
Assume that X contains asmooth
elliptic
curve D. Then there exists anelliptic fibration f:
X ~ Csuch that C is a smooth
elliptic
curve, D is afiber of f,
and anyfiber of f
is
isomorphic
to D.PROOF.
By
a translation ofD,
we may assume that D contains theorigin
of X and D is an abeliansubvariety
of X. Then there exist the quo- tientXID
and thesurjective homomorphism f:
ThenXjD
is asmooth
elliptic
curve and every fiberof f is isomorphic
to the fiber overthe
origin
ofXID
which is Dby
construction.LEMMA 1.3. Let X be an abelian
surface.
Assume that there exist asmooth
elliptic
curve C and asuryective mor~phism f :
X -~ C with con-nected
fibers
such thatf
has a section S. Then X = C x F andf
is identi-fied
with thefirst projection
via thisisomorphism,
and S is afiber of
the second
projection,
where F is afiber of f.
PROOF. We remark
that f is
anelliptic
fibration such that any fiber off is
smooth since X is an abelian surface. Let S be a sectionof f.
Thenby
Lemma
1.2,
there exist a smoothelliptic
curve C’ and anelliptic
fibrationh : X ~ C’ ‘ such that any fiber of h is a smooth
elliptic
curve and S is afiber of h. Moreover any fiber of h
(resp. f)
is a section off (resp. h).
Inparticular
C’ = F. Then there exists amorphism
suchthat and where P,
(resp. P2)
is theprojection
C x C’ 2013>C
(resp.
Cx C" 2013>C’).
We remark that it isbijective by
con-struction. Let
F f = f * ( x )
andFh = h * ( y ),
where andY E C ’.
Thenand Then
Hence a is birational. Therefore
by
Zariski MainTheorem,
we obtainthat .7r is
an,isomorphism. 0
REMARK 1.3.1. Let
(X, L)
be apolarized
abeliansurface,
and let Dbe an effective divisor on X such that LD = 1. Then D is irreducible and reduced.
By Hodge
indexTheorem,
weget
thatD 2
= 0. Moreover D is asmooth
elliptic
curve since X is an abelian surface andg(D)
= 1.By
Lem-ma
1.2,
there exists a fiberspace f :
X- C such that C is a smoothelliptic
curve, D is a fiber of
f,
and any fiber off
isisomorphic
to D. Sinceh ° (L)
> 0 and LD =1,
there exists a sectionof f.
Soby
Lemma1.3,
X = C x F for a fiber F
of f, and f is
identified with the firstprojection
viathis
isomorphism.
THEOREM 1.4
(Terakawa).
Let(X, L)
be apolarized
abelian sur-face.
Then L isample if
andonly if L 2 ~
4 k + 6 and there existsno
effective
divisor Dsatisfying
theinequalities
PROOF. See Theorem 3.15 in
[Te].
THEOREM 1.5. Let
(X, L)
be apolarized
abeliansurface. If g(L) =
=
2,
then(X, L)
is oneof
thefollowing:
(I)
X =J(B),
and L is the classof
a translationof
the theta divi- sor, where B is a smoothprojective
curveof
genustwo, J(B)
is thejaco-
bian
variety of
B.(II)
X =El
xE2 ,
and L =P1*
6D, Q9P2* ~2 ,
whereE1 and E2
aresmooth
elliptic
curves, pi:E1
xE2 --~ Ei
is the i-thprojection,
and EE Pic
(Ei )
withdeg
(J)1 =deg
=1.PROOF. See
[OoU], [BeLP],
or[Fil. m
THEOREM 1.6. Let
(X, L)
be apolarized
abeliansurface
withL 2 ;
; 2 a, where a E l~. Assume that there exists an irreducible reduced curve
D on X such that LD = 2 and
D 2 =
0. Then(X, L) satisfies
oneof
thefollowing:
(1 )
X =E1
xE2
and L =pt
~31(9 P2*
IB2 withdeg
$1 ~ 1 anddeg B2
== 2,
ordeg B1 = 2
and(2)
There exists asurjective morphism f :
X -~ C with connectedfibers
such that C is a smoothelliptic
curve and anyfiber of f
is asmooth
elliptic
curve, and(X, L)
is oneof
thefollowing:
(2-1)
There exists anample spanned
vector bundle 8of
rank twoon C such that 8 = 8’ Q9 J[1 with
deg
J[1 ~~a/2 ~ ,
X is a doublecovering of IE~( ~ )
whose branch locus is smooth andlinearly equivalent
to- 2 I~~~ ~ y f =
and L =C9(T) Of*
(2-2)
X =J(B)
and L =(9x(A) Of* ~1~
such that A is a transla- tionof
the thetadivisor,
AF = 2for
afiber
Fof f,
anddeg
~
~(a -1 )/2 ~ ,
(2-3)
X =E1
XE2
and L =P1*
6D, Q9P2* 6D2 Q9f* ~
such that anyfiber of
Pi is a sectionof f for
i= 1, 2, deg
(J)1 =deg (J)2
=1,
anddeg ME3 -> ~(a - 1 )/2 ~ ,
where in
(1)
and(2-3) E1
andE2
are smoothelliptic
curves, pi:E1
xx
E2 - Ei
is the i-thprojection, Bi, Di
E Pic(Ei) for
i =1, 2,
E Pic( C),
in
(2-1)
8’ =oc for
21 E Pic(C)
withoc
and2.el -= (9c, 3111
EE Pic ( C),
p:I~( ~ )
-~ C is the naturalprojection,
:Jl:X ~ P( 8)
is thedouble
covering,
and T is a smoothelliptic
curve with TF = 2for
a
fiber
Fof f,
and in(2-2)
B is a smoothprojective
curveof
genustwo, J(B)
is thejacobian variety,
and E Pic(C). (For
x ER, ~x]
denotes the smallest
integer
which isgreater
than orequal
tox.)
REMARK 1.6.1. In the case(2-2)
in Theorem1.6,
B cannot be gener- al.Actually
if B isgeneral,
then the Neron-Severi group NS(X)
is gener- atedby
the class of the theta divisor. Inparticular,
X does not containany
elliptic
curve.PROOF. This can be
proved by
the sameargument
as in theproof
ofTheorem 2.2 in
[Fk]. By assumption,
D is a smoothelliptic
curve. Henceby
Lemma1.2,
there exists asurjective morphism f :
X- C such that C isa smooth
elliptic
curve, D is a fiberof f,
and any fiberof f is
smooth. Since LF = LD = 2 for any fiber Fof f,
weget that f * o f * (L )
-~ L issurjective.
Let 8 :
= f * L.
Then 8 is alocally
free sheaf of rank two onC,
and thereexists a
morphism : X -~ lh( ~ )
suchwhere : P(8)
- C is the bundle map.By construction,
Jt is a doublecovering.
Since X is anabelian
surface,
the branch locus B is smooth andlinearly equivalent
to- 2
Kp(,).
Furthermore L = Jt *(H(8))
and 8 isample
with a, whereH(8)
is thetautological
line bundle onP(8). Since I - I
hasa smooth
member, by
the sameargument
as in theproof
ofProposition
2.3 in
[Fkl],
we can prove that there exists a vector bundle 8’ on C and aline bundle J1 on C such that 8 = 8’
(9 M,
and 8’ and 311satisfy
one of thefollowing
threetypes;
(G~
there exists a nontrivial extensionand
where c4EPic(C)
withLet
c : IE~( ~ ) -~ Ih( ~’ )
be theisomorphism
such that Let JT(1)
The case in which 8’ is thetype (A)
or(B).
Let
Co
E[ H( 8’ ) [
ThenCo
is an irreducible reduced curveby Proposi-
tion 2.8 in
[Ha,
Ch.V].
Let B be the branch locus of We remark that-
2Kp(8’)
> =4 H( ~, ).
Since -2Kp(8’)CO=0,
weget Co c B
orCo n B = 0.
(1-1)
The case in whichCo c B.
Then =
2 B1.
Since LF = 2 for a fiberF of f
andB1
is not contained in a fiberof f, B1
is a sectionof f.
Henceby
Lemma1.3,
X == C x F and
f
is identified with the firstprojection,
andB1
is a fiber ofthe second
projection
h : C x F ~ F. So weget
where 1P e Pic
(F)
withdeg 1P
= 2. Therefore weget
thetype (1)
in Theo-rem 1.6.
(1-2)
The case in whichCo
n B = 0. Then we obtain one of thefollowing:
where Bi
is an irreducible reduced curve fori = 2, 3,
4 with First we consider the case(1-2-1).
PROOF. We remark that
B2
is a smoothelliptic
curve. Henceby
Lem-ma
1.2,
there exists asurjective morphism fl :
X -C1
such thatC1
is asmooth
elliptic
curve andB2
is a fiberof fl .
Hence=
h ° (B2 )
= 1. On the otherhand,
since 7r’ is a doublecovering,
we haveh ° ((,~’ ) * ( C° ) ) = h ° (H( ~’ ) ).
Hence~(~))=1.
Therefore ~’ is thetype (B).
Thiscompletes
theproof
of Claim 1.7.Since L =
(jr’)*(Co)0/*~
we obtain thetype (2-1)
in Theorem 1.6.We remark that
B2 F
= 2 for a fiberF of f.
Next we consider the case
(1-2-2).
If =
B3
+B4 ,
then weget
= 0 and = 0. SinceB3
andB4
are not contained in a fiberof f,
weget
thatB3 F
=B4 F
= 1 fora fiber F
of f because
= 2. HenceB3
andB4
are sectionsof f.
Hence
by
Lemma1.3,
weget
that X = C xF, f
is identified with the firstprojection,
andBi
is a fiber of the secondprojection
h : X ~ F fori = 3, 4.
Hence
by
the sameargument
as the case(1-1),
we obtain Lf* X 0
® h * ~’,
where 0’ EPic (F)
withdeg
1P’ = 2.Therefore we
get
thetype (1)
in Theorem 1.6.(2)
The case in which 8’ is thetype (C).
Then
H(8’)
isample
withH(8’ )2
= 1. Weput ox(A) = (Jt ’ )* (H(8’)).
Then AF = 2 for a fiber
F of f.
SinceA 2 =
2 and X is an abeliansurface,
we obtain
g(A)
= 2 and weget
that(X, A)
is one of thetype (I)
or(II)
in Theorem 1.5. We remark that L =(jr’ )* (H(~’ ) ) ® f *
J1 =Of*
If
(X, A)
is thetype (II)
in Theorem1.5,
then any fiberof f is
not con-tained in a fiber of pi and any fiber of pi is a section
of f for
i= 1,
2 since AF = 2. Therefore if(X, A)
is thetype (I) (resp. (II))
in Theorem1.5,
then weget
thetype (2-2) (resp. (2-3))
in Theorem 1.6. Thiscompletes
the
proof
of Theorem 1.6.DEFINITION 1.8. Let X be an abelian surface and let
L, L1, ... , Ln
be
ample
line bundles on X.(A)
If(X, L)
is thetype (2-1) (resp. (2-2), (2-3))
in Theorem 1.6 withL 2 ; 2 a,
then we say that(X, L)
is thetype (I; a) (resp. (II; a), (III; a)).
(B)
If X =J(B)
andLi
= B for a smooth curve B of genus two and i= 1, ... ,
n, then we call(X, L1, ... , Ln )
thetype (J),
where * denotes numericalequivalence.
(0
If X =El
XE2
and L =pt(CD1) ® ~2 ( ~2 )
with(deg(JJ1, ( a , b)
or(deg 6D,, ( b , a),
then we call(X, L )
thetype
(P; {a, 6}),
whereEl and E2
are smoothelliptic
curves, pi is the i-th pro-jection,
and for i =1,
2.(D) If X = El
XE2
andLi
= withdeg Di
= ai , then wecall
(X, L)
thetype (PS; t;
aI, ... ,an ),
whereEl
andE2
are smoothellip-
tic curves, pt is the t-th
projection, Si
is a section of pt, and ~2 E Pic(Et)
for
i = 1, ... , n.
2. The case in which
L1 + ... + Lt
is notample
for t = k + 1 or 1~ . THEOREM 2.1. Let X be an abeliansurface,
and letL1
andL2 be ample
line bundles on X. Weput
L : =L1
+L2 .
Then L is not veryample if
andonly if (X, L1, L2 ) satisfies
oneof
thefoLLowing:
(1) (X,
thetype (J),
(2) (X , L1, L2 )
is thetype
with a1 >0,
a2 >0,
andt = 1, 2.
PROOF. First we prove the «if»
part.
If
(X, L1, L2 )
is thetype (1),
thenL 2
=(L1
+L2 )2
= 8 andh ° (L ) _
= L 2 /2
= 4. If L is veryample,
then X is ahypersurface
ofdegree
8 inp3.
But this is
impossible
because X is an abelian surface. Hence L is not veryample.
If
(X, L1, L2 )
is thetype (2),
thenLF,
=2,
whereF1
is a fiber of pi . If L is veryample,
thenF1
= But this isimpossible
because X is anabelian surface.
Next we prove the
«only
if»part.
Assume that L is not veryample.
Then
L 2
=(L1
+L2 )2 ~
8 because2, 2,
and 2.(A)
The case in whichL 2
= 8.Then
L1 L2
= 2 andL2
= 2.By Hodge
indexTheorem,
we obtainthat
Li = L2.
Sinceg(L1 )
=2,
weget
that(X, L1 )
is thetype (I)
or(II)
inTheorem 1.5.
If
(X, L1 )
is thetype (I),
thenL2
--- B.If
(X, L1 )
is thetype (II),
then we caneasily
proveL2=pi*(Di0
®p2*D’2,
where6D! E Pic (Ei )
withdeg D’1
=deg 6D2’
= 1.(B)
The case in whichL 2 ;
10.By
Reider’sTheorem,
there exists an effective divisor D on X such that(LD , D 2) = (2, 0) or (1, 0)
because the value ofD 2
is even. Since L =L1
+L2
andLi
isample
for i =1, 2,
weget (LD , D 2 )
=( 2 , 0 ).
So wehave
Li D
= 1 for each i.By
Remark1.3.1,
there exists a fiber spacef :
X- C such that C is a smoothelliptic curve, X
= C xF, f
is identified with the firstprojection
via thisisomorphism,
and D is a fiberof f,
whereF is a fiber
of f.
SinceLi F =
1 for eachi,
we obtain that0 for i =
1, 2,
wheremj
E Pic(C) and Si
is a sectionof f.
SinceLi
isample,
weget Li Si
> 0. Hencedeg 6Di
> 0 becauseSi2
= 0. Thiscompletes
the
proof
of Theorem 2.1.COROLLARY 2.1.1. Let X be an abelian
surface
and let L be an am-ple
line bundle on X. Then 2L is not veryample if
andonly if (X, L) satisfies
oneof
thefollowing:
(1) (X, L) is
thetype (J),
(2) (X, L) is
thetype (P; ~ a , b 1)
with a > 0 and b = 1.PROOF. We
put L1=
L andL2
= L. Then weget
the above resultby
Theorem 2.1. We remark that if then we use Lemma 1.3.
THEOREM 2.2. Let X be an abetian
surface
and letL1, ... , Lk
+ 1 beample
line bundles on X. Assume that k ~ 2. Weput
L : =L1
+ ... ++
Lk
+ 1. Then L is notk-very ample if and onLy if (X, L1,
... ,Lk + 1 )
is thetype (PS; t;
... ,ak + 1 )
with ai > 0for any i,
and t =1,
2.PROOF. First we prove the «if»
part.
LetFl
be a fiber of Then+ 1. But
by
Theorem1.4,
L is notk-very ample.
Next we prove the
«only
if»part.
ThenAssume that L is not
k-very ample.
Thenby
Theorem1.4,
there exists aneffective divisor D such that
Because LD =
(L1
+ ...+ Lk + 1 ) D,
there exists anample
line bundleLi
such that
Li D
= 1. We may assume that i = 1.By
Remark1.3.1,
there exists a fiberspace f :
X - C such that C is a smoothelliptic
curve, X == C x
F, f is
identified with the firstprojection
via thisisomorphism,
and Dis a fiber
of f,
where F is a fiberof f.
On the otherhand, by
Theorem1.4,
we
get
LD ~ k + 1 sinceg(D)
= 1. HenceLi D
= 1 for any i. Since D is afiber
of f and
> 0 for i =1,
... , k +1,
weget
thatLi == f* CDi Q9
Q9 for i =
1, ... , k
+1,
where6Di
E Pic( C), Si
is a sectionof f.
SinceLi
is
ample,
weget Li Si
> 0. Hencedeg 6Di
> 0 becauseS 2
= 0 for any i. Thiscompletes
theproof
of Theorem 2.2.By
Theorem2.2,
we can prove thefollowing Corollary.
COROLLARY 2.2.1. Let X be an abelian
surface
and let L be an am-ple
line bundle on X Thenfor
k ~2, (k
+1 ) L
is notk-very ample if
andonLy if (X, L) is
thetype (P; {o, b 1)
with a > 0 and b = 1.THEOREM 2.3. Let X be an abelian
surface
and letL1,
... ,Lk be
ample
line bundles on X. Assume that k a 3. Weput L : = L1 + ... + Lk.
Then L is not
k-very ample if
andonly if (X, L1, ... , Lk )
is oneof
thefollowing:
(1) k
= 3 and(X, L 1, L2 , L3 ) is
thetype (J),
(2) (X, L1,
... ,Lk - 1 )
is thetype (PS; t;
ai , ... , ak _1 ),
andLk
== put*
0 where6Dk
E Pic(Et )
withdeg
6Dk0,
pt is the t-th pro-jection,
T is a divisor on X withTFt
= 2for
afiber Ft of
pt, ai is apositi-
ve
integer for
i= 1,
... , k -1,
and t =1, 2,
(3)
thetype (PS; t;
aI,... , ak )
with ai > 0for
...,
k,
andt=1, 2.
PROOF. First we prove the «if»
part.
If
(X, L1,
... ,Lk)
is thetype (1)
in Theorem2.3,
then k =3,
LB =- (L1
+L2
+L3) B
=6, and g(B)
= 2. Thenby
Theorem1.4, L
isnot 3-very ample.
If
(X, L1,
... ,Lk )
is thetype (2)
or(3)
in Theorem2.3,
then~ k + 1 for a
fiber F1
of pi. Thenby
Theorem1.4,
L is notk-very ample.
Next we prove the
«only
if»part.
We calculate
L 2 :
Since 1~ ~
3,
weget 2 k 2 ~ 41~ + 6.
So we haveL2>-
4 k + 6. Assume that L is notk-very ample.
Thenby
Theorem1.4,
there exists an effective divi-sor D on X such that
We may assume that
Then we obtain that 2.
By Hodge
indexTheorem,
weget D 2 2.
(2.3.1 )
The case in whichD 2 =
2.Then
L1 D
= 2 andL1=
Dby Hodge
index Theorem. Sinceg(L1 )
=2,
we obtain that
(X, L1 )
is thetype (I)
or(II)
in Theorem 1.5. On the otherhand, by g(D) = 2, L1 D = 2,
and Theorem1.4,
weget
Hence k = 3 and
L1 D
=L2 D
=L3 D
= 2. Soby Hodge
indexTheorem,
we
get L1 = L2 = Z.3
= D. Therefore weget
thetype (1)
or(3)
in Theorem2.3.
(2.3.2)
The case in whichD 2
= 0.(2.3.2.1)
The case in whichL1 D
= 2.Then
by assumption,
we have LD ~ 2 k. Henceby
Theorem1.4,
weget
2 k ~ LD ~
2 g(D )
+ 1~ - 1 = l~ + 1. Therefore k 5 1 and this is a contra- diction.(2.3.2.2)
The case in whichL1 D
= 1.By
Remark1.3.1,
there exists a fiberspace f :
X- C such that C is asmooth
elliptic curve, X =
C xF, f
is identified with the firstprojection
via this
isomorphism,
and D is a fiberof f,
where F is a fiberof f.
Sincek~(L1+...+Lk)D~2g(D)+k-1 =k+1,
weget
type (2)
in Theorem2.3,
and if(L1 D , ... , Lk _ 1 D , Lk D ) _ ( 1,
... ,1, 1),
then
(X, L1,
... ,Lk)
is thetype (3)
in Theorem 2.3by using
the same ar-gument
as in theproof
of the above Theorems. Thiscompletes
theproof
of Theorem 2.3.
THEOREM 2.4. Let X be an abelian
surface
and let L be anample
Line bundles on X. Then
for k ~ 2,
kL is notk-very ample if
andonly if (X, L)
is oneof
thefollowing:
(1) k
= 2 or3,
and(X, L) is
thetype (J),
(2) (X, L)
is thetype (P; {a, b 1)
with a > 0 and b = 1.PROOF. For k a
3,
this is acorollary
of Theorem 2.3. Assume that k = 2.By
the sameargument
as in theproof
of Theorem2.3,
we canprove the «if»
part.
So we prove the«only
if»part.
Assume that L is not2-very ample.
(2.4.1)
The case in whichL 2 ~ 4.
Then
( 2 L )2 ~ 16,
andby
Theorem1.4,
there exists an effective divisor D on X such that(2L)
D ~2g(D)
+ 1 ~ 5. IfD 2
>0,
thenby Hodge
in-dex
Theorem,
weget
LD ~ 3 and this isimpossible.
HenceD 2 =
0 andg(D)
= 1. Therefore 2 LD ~3,
thatis,
we obtain LD = 1. So D is a smoothelliptic
curve.By
Lemma 1.2 and Lemma1.3,
we can prove that(X, L )
is thetype (P; ~ a , b 1)
with a > 0 and b = 1.(2.4.2)
The case in whichL 2 =
2.Then
(X, L)
is one of thetype
in Theorem 1.5.This
completes
theproof
of Theorem 2.4.3. The case in which
(n - t) L
is notk-very ample
for t =1 and 2.THEOREM 3.1. Let
(X, L) be
apolarized
abeliansurface.
Let(k, t)
be apair of integer
whichsatisfies
thefollowing inequalities;
(A) k ; 3t + 1, (B) t ~
1.Then
( k - t)L
is notk-very ample if
andonly if
oneof
thefollowing types holds;
(1) (k, t)
=(4, 1), (5, 1 ),
or(7,2),
and(X, L) is
the thetype (J), (2) (X, L)
is thetype (P; {a, b 1)
with a > 0 and b = 1.PROOF. First we remark that
( k - t )2 L 2 ;
4 k + 6 unless(L 2 , k , t )
=- (2, 4, 1 ).
We prove the «if»
part
of Theorem 3.1. If(X, L)
is thetype (1)
in Theorem3.1,
then( k - t)
LB ~2g(B)
+ k - 1 ~ 2 k + 1. Henceby
Theo-rem
1.4,
L is notk-very ample.
If(X, L)
is thetype (2)
in Theorem3.1,
then(k - 2g(Fl )
+ k - 1 ~ 2k + 1 for any fiberF1
of Pl. Hence L is notk-very ample by
Theorem 1.4.Next we prove the
«only
if»part.
(3.1.1 )
The case in whichL 2 ~
4.Since
(k - t)2 L 2 ~ 4 k + 6, by
Theorem1.4,
there exists an effective divisor D on X such that( k - t)
LD ~2 g(D )
+ k - 1 ~ 2 k + 1.Assume that
D 2
> 0.Then, by Hodge
indexTheorem,
weget
LD ~ 3.Hence
3(k-t)~(k-t)LD~2k+1,
and we obtain k~3t+1.By hy- pothesis
we have k = 3 t + 1 and LD = 3. So weget D 2
= 2 andg(D)
= 2.By
Theorem1.4,
we have3( 2 t
+1)
=(k - t)
LD ~ k + 3 == 3 t + 4,
and so we have t 1 /3. But this is a contradiction.Hence
D 2
= 0 andg(D)
= 1.By
Theorem1.4,
we obtain( k - t ) LD ~
~k+ 1.
Assume that LD ~ 2. Then we
get
k - 1 ~ 2 t. Sincek ~ 3 t + 1,
we
get
3 t ~ 2 t. This isimpossible
because t ~ 1. Hence LD = 1.Therefore D is a smooth
elliptic
curve andby
the same method as inthe
proof
of the abovetheorems,
weget
that(X, L)
is thetype
(P; {a,
with a > 0 and b = 1.(3.1.2)
The case in whichL 2 = 2.
Then
by
Theorem1.5,
weget
that(X, L )
is one of thetypes
in Theo-rem 1.5.
In order to prove Theorem
3.1,
it is sufficient tostudy
the case inwhich X =
J(B)
and L =B,
where B is a smoothprojective
curve of genus 2 andJ(B)
isits jacobian variety.
If( k , t)
=(4, 1),
then( k - t )2 L 2
4 k + 6 and
( k - t ) L
is notk-very ample by
Theorem 1.4. So we assumethat
( k , t ) ~ ( 4 , 1 ).
Then( k - t )2 L 2 ~ 4 k + 6.
Thenby
Theorem1.4,
there exists an effective divisor D on X such that( k - t)
LD ~2g(D)
++ k - 1 ~ 2 k + 1. Here we remark that we can prove LD ~ 2
by
Remark1.3.1 since L * B.
(3.1.2.1)
The case in which LD ~ 3.Then 3k-3t;
(k-t)LD~2k+1.
So we have k~3t+1.By hy- pothesis,
weget
k = 3 t + 1 and LD = 3. SinceL 2
=2,
we obtainD 2 ;
4.Hence2k-5 ~3t. and 4. Be-
cause k = 3 t
+ 1,
we obtain(k, t)
=(4, 1 )
and this is a contradiction.(3.1.2.2)
The case in which LD = 2.If
D~
=0,
theng(D)
= 1. Soby
Theorem1.4,
weget 2(k - t) _
= (k - t)
LD ~ k + 1. Hence k - 1 ~ 2 t. Since k ~ 3 t +1,
this isimpossi-
ble because t ~ 1.
If
D 2
>0,
then L = D since LD = 2 andL 2
= 2.By
Theorem1.4,
weget 2(k-t) _ (k-t)LD~k+3.
Hence k-3 ~2t. Sincek~3t+1,
weget
3 t - 2 ~ 2 t. Therefore t S 2.If
t = 1,
then2(k -1 ) _ (k - t) LD ~ k + 3.
Hence k ~ 5. Because4 = 3 t + 1; k,
weget
k = 5by
theassumption
that(k, t) # (4, 1 ).
If
t = 2,
then2(k - 2 ) _ (k - t) LD ~ k + 3.
Hence k ~ 7. Because7=3t+1 ;k,
weget
k=7.This
completes
theproof
of Theorem 3.1.THEOREM 3.2. Let
(X, L)
be apolarized
abetiansurface.
Let( k , t)
be apair of integers
with 3 t ; k ~ 2 t +1,
t ~1,
and( k , t ) ~ ( 3 , 1 ).
Then(k - t)
L is notk-very ample if
andonly if
oneof
thefollowing
holds:
and
tg ~ 3,
and(X, L) is
the thetype (J),
(2) (X, L) is
thetype (P; {a, b ~ )
with a ~ 1 andb = 1,
(3) k = 2 t + 1
and(X , L )
is thetype (P; ~ a , b 1)
with a ~ 1 andb = 2,
(4) k
= 2 t + 1 and(X, L)
is one of thetype (I; 2), (II; 2),
or(III; 2).
PROOF. First we prove the «if»
part.
If(X, L)
is thetype (1)
in Theo-rem
3.2,
then( k - t )
LB ~2 g(B )
+ k - 1 ~ 2 k. Hence L is notk-very
am-ple by
Theorem 1.4. If(X, L)
is thetype (2)
or(3)
in Theorem3.2,
then(k - t) 2g(Fl)
+ k - 1 ~ 2k for a fiberF1
of pl. Hence L is not k- veryample by
Theorem 1.4. If(X, L)
is thetype (4)
in Theorem3.2,
then(k - t )
LF ~2 g(F)
+ k - 1 ; 2 k for a fiber Fof f.
Hence L is notk-very ample by
Theorem 1.4.Next we prove the
«only
if»part.
(A)
The case in whichL 2 ~
4.First we remark that
(k - t)2 L 2 ;
4 k + 6by assumption.
Henceby
Theorem 1.4 there exists an effective divisor D on X such that
(k - t) LD 2g(D) + k -1 2k + 1.
If LD ~
4,
then4(k - t) ~
2 k +1,
thatis,
2 k ~ 4 t + 1. Since k ~ 2 t ++ 1,
weget
that 4 t + 1 ; 2 k ~ 4 t + 2. But this isimpossible.
HenceLD~3.
If
LD = 3,
thenD 2 ~ 2
sinceL 2 ~ 4.
Therefore3(k - t) =
= (k - t) LD £ k + 3 because g(D ) ~ 2.
So we have 2 k ~ 3 t + 3.Since k ; 2 t + 1,
we obtain that 3 t + 3 ~ 4 t + 2. Since t ~
1,
we have t = 1 and k = 3. Butby assumption
this is a contradiction. Hence LD ~ 2 andD 2
= 0.If LD =
1,
or LD = 2 such that D is not an irreducible reduced curve, then there exists an irreducible reduced curve B such that LB = 1. Thenby
Lemma 1.2 and Lemma1.3,
weget
thetype (2)
in Theorem 3.2.If LD = 2 such that D is an irreducible curve, then D is a smooth el-
liptic
curve. Then2(k - t )
=( k - t )
LD ~2 g(D )
+ k - 1 = k + 1. Hence k ~ 2 t + 1.By assumption
k = 2 t + 1 in this case. Thenby
Theorem1.6,
we
get
thetype (3)
or(4)
in Theorem 3.2.(B)
The case in whichL 2 =
2.Then
(X, L)
is thetype (I)
or(II)
in Theorem 1.5. If(X, L)
is thetype (II)
in Theorem1.5,
then(X, L)
is thetype (2)
in Theorem 3.2. So it is sufficient tostudy
the case in which(X, L )
is thetype (I)
in Theorem1.5.
Assume that X =
J(B)
and L is the class of a translation of the thetadivisor,
where B is a smoothprojective
curve of genus 2 andJ(B)
is itsjacobian variety.
Then we remark that( k - t )2 L 2 ~ 4 k + 6 (resp.
( k - t )2 L 2 4 k + 6)
if t ~ 4(resp. t ~ 3).
Ift ~ 3,
then weget
that( k - t ) L
is notk-very ample by
Theorem 1.4. Since 3 t ~ k ; 2 t + 1 and(k, t ) ~
~
( 3 , 1 ),
weget
that( k , t)
=(9, 3),(8, 3),(7, 3),(6, 2)
or( 5 , 2 ).
Assume that t ~ 4. Then
by
Theorem1.4,
there exists an effective di- visor D on X such that( k - t)
LD ~2 g(D )
+ k -1 ~ 2 k + 1.IfLD ~
4,
then this isimpossible by
the sameargument
as in the case(A).
Hence LD ~ 3. We remark that LD ~ 2 since L is the class of atranslation of the theta divisor. Since
L 2 = 2,
weget
thatD 2 ~ 4
andg(D) ~
3.If LD =
3,
then3(k - t ) ~ k
+ 5. Hence 2 k ~ 3 t + 5. Sincek ; 2 t + 1,
we
get 4 t + 2 ~ 2 k ~ 3 t + 5,
thatis,
t ~ 3. But this is a contradiction.If LD =
2,
thenD 2-
2.If D 2= 2,
theng(D)
= 2 and2(k - ~) ~
+ 3.Thus we have k ~ 2 t + 3. Hence k = 2 t +
1,
2 t +2,
and 2 t + 3.If
D 2
=0,
theng(D)
= 1 and2(k - t) ~
k + 1. Hence k ~ 2 t + 1. Sincek;2t+1,
weget k=2t+1.
This
completes
theproof
of Theorem 3.2.COROLLARY 3.3. Let
(X, L)
be apolarized
abeliansurface.
Assumethat k a 2 t +
4 for ( k , t)
E~T®2.
Then( k - t)
L is notk-very if
andonly if (X, L)
is thetype (P; ~ a , b 1)
with a > 0 and b =1.PROOF. This is obtained
by
Theorem 3.1 and Theorem 3.2.THEOREM 3.4. Let
(X, L) be
apolarized
abeliansurface.
Assumewith k ~ 3. Then
(k - 1 )L is
notk-very ample if
andonly if
one
of
thefollowing
holds:( 1 )
k =3, 4,
or5,
and(X, L)
is thetype (J),
(2) (X, L)
is thetype (P; I a,, a2 1)
with a1 > 0and a2
=1,
(3) k = 3
and(X, L) is
thetype b2 ~ )
with andb2=2,
(4)
k = 3 and(X, L) is
oneof
thetype (1; 2), (II; 2),
or(III; 2),
(5)
k=3 andL2=4.
PROOF. We can
easily
prove the «if»part by
Theorem 1.4. So weprove the
«only
if»part.
If k ~4,
then this is acorollary
of Theorem3.1,
and
(X, L)
is one of thetype (1)
or(2)
in Theorem 3.4. So we may assume that k = 3.(A)
The case in whichL 2 ;
6.Then
4 L 2
=( k -1 )2 L 2 ;18
= 4 k + 6. Henceby
Theorem1.4,
there exists an effective divisor D on X such that 2 LD ~2g(D)
+ 2 ~ 7. Hence LD 3. SinceL 2 ~
6 weget
thatD 2
= 0 andg(D )
= 1. Therefore 2 LD ~~ 4,
thatis,
LD ~ 2.If LD =
1,
or LD = 2 and D is not irreducible andreduced,
then thereexists an irreducible and reduced curve B on X such that LB = 1. Hence
by
Lemma 1.2 and Lemma1.3,
weget
that(X, L)
is thetype (2)
in Theo-rem 3.4.
If LD = 2 and D is irreducible and
reduced,
thenby
Theorem 1.6 weget
that(X, L)
is one of thetype (3)
or(4)
in Theorem 3.4.(B)
The case in whichL 2
= 2.Then
by
Theorem1.5,
weget
that(X, L )
is one of thetype (1)
or(2)
in Theorem 3.4.(0
The case in whichL 2
= 4.Then
(X, L)
is thetype (5)
in Theorem 3.4.This
completes
theproof
of Theorem 3.4.THEOREM 3.5. Let
(X, L)
be apolarized
abeliansurface.
Assumewith k ~ 4. Then
(k - 2 ) L
is notk-very ample if
andonly if
one
of
thefollowing
holds:( 1 )
k =4 , 5 , 6,
or7,
and(X, L)
is thetype (J),
(2) (X, L)
is thetype (P; I a,, a2 1)
with a1 > 0and ct2
=1,
(3) k
= 4 or5,
and(X, L)
is thetype b2 ~ )
with andb2
=2,
(4) k
= 4 or5,
and(X, L)
is oneof
thetype (I; 2), (II; 2),
or(III; 2),
(5)
k=4 andL2=4.
PROOF. We can
easily
prove the «if»part by
Theorem 1.4. So weprove the
«only
if»part.
If k ;7,
then this is acorollary
of Theorem3.1,
and