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R ENDICONTI

del

S EMINARIO M ATEMATICO

della

U NIVERSITÀ DI P ADOVA

Y OSHIAKI F UKUMA

On k-very ampleness of tensor products of ample line bundles on abelian surfaces

Rendiconti del Seminario Matematico della Università di Padova, tome 101 (1999), p. 209-227

<http://www.numdam.org/item?id=RSMUP_1999__101__209_0>

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(2)

of Ample Line Bundles

on

Abelian Surfaces (*).

YOSHIAKI

FUKUMA (**)

ABSTRACT - In this paper, we

study

abelian surfaces X and

ample

line bundles

L1,

... ,

L,

such that L

:= L1

+ ...

+ Lt

is not

k-very ample

for t = k, k + 1. And

we also

study polarized

abelian surfaces (X, L) such that ( k - t ) L is not k-

very

ample

with t ~ 1 under some condition. As corollaries of the above re-

sults, we get the classification of (X, L ) such that ( k - t ) L is not

k-very ample

fort=-1,0,1 and 2.

0. Introduction.

Let X be an abelian

variety

over the

complex

number field C and let L be an

ample

line bundle on X. Then it is well-known that 2L is

spanned

and 3L is very

ample. (See [LB].)

In

[BaSzl]

and

[BaSz2],

Bauer and

Szemberg

studied a sufficient condition of

k-very ampleness

of

L1

+ ... +

+

Lk

+ 1 for

ample

line bundles

Ll ,

... ,

Lk

+ 1. In

particular,

in

[BaSz2],

as a

corollary, they proved

that

L1

+ ... +

Lk

+ 2 is

k-very ample

for any

ample

line bundles

L1,

... ,

Lk

+ 2 .

Next the

following question

arises from the

Bauer-Szemberg

re-

sult ;

(*) Research Fellow of the

Japan Society

for the Promotion of Science.

(**) Indirizzo dell’A.: E-mail:

[email protected].

Current Address:

Department

of Mathematics,

College

of Education, Naruto

University

of Educa- tion, Takashima, Naruto-cho, Naruto-shi 772-8502,

Japan;

E-mail: fukuma@na-

ruto-u. ac. j p

(3)

QUESTION.

Let X be an abelian

variety

X and let

L1,

... ,

L,

be

ample

line bundles on X for s ~ k + 1. Then

classify (X, Li , ... , Ls )

such that

L1

+ ... +

L,

is not

k-very ample.

Ohbuchi

([0])

studied

polarized

abelian varieties

(X, L)

such that 2L is not very

ample.

In sect.

2,

we

study

abelian surfaces X and

ample

line bundles

L1, ... , Lt

such that

L : = L1 + ... + Lt

is not

k-very ample

for

t = k,

k+1.

In sect.

3,

we

study polarized

abelian surfaces

(X, L)

such that

(k -

-

t)

L is not

k-very ample

with t &#x3E; 1 under some condition. In

particular,

we characterize

(X, L)

such that

( k - t)L

is not

k-very ample

with t =1

or 2.

(See

Theorem 3.4 and Theorem

3.5.)

We work over the

complex

number field and we use the

customary

notation in

algebraic geometry.

Acknowledgment.

The author would like to express his

hearty

thanks

to Professor Tomasz

Szemberg

for

giving

him some useful comments

and

suggestions.

The author also would like to thank the referee for

giv- ing

him useful comments.

1. Preliminaries.

DEFINITION 1.1.

(See [BeSo].) -

Let

(X, L)

be a

polarized

surface.

Then L is called

k-very ample

if for any 0-dimensional subscheme

(Z,

with

length

c9z = k +

1,

the map

is

surjective.

LEMMA 1.2. Let X be an abelian

surface.

Assume that X contains a

smooth

elliptic

curve D. Then there exists an

elliptic fibration f:

X ~ C

such that C is a smooth

elliptic

curve, D is a

fiber of f,

and any

fiber of f

is

isomorphic

to D.

PROOF.

By

a translation of

D,

we may assume that D contains the

origin

of X and D is an abelian

subvariety

of X. Then there exist the quo- tient

XID

and the

surjective homomorphism f:

Then

XjD

is a

smooth

elliptic

curve and every fiber

of f is isomorphic

to the fiber over

the

origin

of

XID

which is D

by

construction.

(4)

LEMMA 1.3. Let X be an abelian

surface.

Assume that there exist a

smooth

elliptic

curve C and a

suryective mor~phism f :

X -~ C with con-

nected

fibers

such that

f

has a section S. Then X = C x F and

f

is identi-

fied

with the

first projection

via this

isomorphism,

and S is a

fiber of

the second

projection,

where F is a

fiber of f.

PROOF. We remark

that f is

an

elliptic

fibration such that any fiber of

f is

smooth since X is an abelian surface. Let S be a section

of f.

Then

by

Lemma

1.2,

there exist a smooth

elliptic

curve C’ and an

elliptic

fibration

h : X ~ C’ such that any fiber of h is a smooth

elliptic

curve and S is a

fiber of h. Moreover any fiber of h

(resp. f)

is a section of

f (resp. h).

In

particular

C’ = F. Then there exists a

morphism

such

that and where P,

(resp. P2)

is the

projection

C x C’ 2013&#x3E;C

(resp.

C

x C" 2013&#x3E;C’).

We remark that it is

bijective by

con-

struction. Let

F f = f * ( x )

and

Fh = h * ( y ),

where and

Y E C ’.

Then

and Then

Hence a is birational. Therefore

by

Zariski Main

Theorem,

we obtain

that .7r is

an,isomorphism. 0

REMARK 1.3.1. Let

(X, L)

be a

polarized

abelian

surface,

and let D

be an effective divisor on X such that LD = 1. Then D is irreducible and reduced.

By Hodge

index

Theorem,

we

get

that

D 2

= 0. Moreover D is a

smooth

elliptic

curve since X is an abelian surface and

g(D)

= 1.

By

Lem-

ma

1.2,

there exists a fiber

space f :

X- C such that C is a smooth

elliptic

curve, D is a fiber of

f,

and any fiber of

f

is

isomorphic

to D. Since

h ° (L)

&#x3E; 0 and LD =

1,

there exists a section

of f.

So

by

Lemma

1.3,

X = C x F for a fiber F

of f, and f is

identified with the first

projection

via

this

isomorphism.

THEOREM 1.4

(Terakawa).

Let

(X, L)

be a

polarized

abelian sur-

face.

Then L is

ample if

and

only if L 2 ~

4 k + 6 and there exists

no

effective

divisor D

satisfying

the

inequalities

PROOF. See Theorem 3.15 in

[Te].

(5)

THEOREM 1.5. Let

(X, L)

be a

polarized

abelian

surface. If g(L) =

=

2,

then

(X, L)

is one

of

the

following:

(I)

X =

J(B),

and L is the class

of

a translation

of

the theta divi- sor, where B is a smooth

projective

curve

of

genus

two, J(B)

is the

jaco-

bian

variety of

B.

(II)

X =

El

x

E2 ,

and L =

P1*

6D, Q9

P2* ~2 ,

where

E1 and E2

are

smooth

elliptic

curves, pi:

E1

x

E2 --~ Ei

is the i-th

projection,

and E

E Pic

(Ei )

with

deg

(J)1 =

deg

=1.

PROOF. See

[OoU], [BeLP],

or

[Fil. m

THEOREM 1.6. Let

(X, L)

be a

polarized

abelian

surface

with

L 2 ;

; 2 a, where a E l~. Assume that there exists an irreducible reduced curve

D on X such that LD = 2 and

D 2 =

0. Then

(X, L) satisfies

one

of

the

following:

(1 )

X =

E1

x

E2

and L =

pt

~31

(9 P2*

IB2 with

deg

$1 ~ 1 and

deg B2

=

= 2,

or

deg B1 = 2

and

(2)

There exists a

surjective morphism f :

X -~ C with connected

fibers

such that C is a smooth

elliptic

curve and any

fiber of f

is a

smooth

elliptic

curve, and

(X, L)

is one

of

the

following:

(2-1)

There exists an

ample spanned

vector bundle 8

of

rank two

on C such that 8 = 8’ Q9 J[1 with

deg

J[1 ~

~a/2 ~ ,

X is a double

covering of IE~( ~ )

whose branch locus is smooth and

linearly equivalent

to

- 2 I~~~ ~ y f =

and L =

C9(T) Of*

(2-2)

X =

J(B)

and L =

(9x(A) Of* ~1~

such that A is a transla- tion

of

the theta

divisor,

AF = 2

for

a

fiber

F

of f,

and

deg

~

~(a -1 )/2 ~ ,

(2-3)

X =

E1

X

E2

and L =

P1*

6D, Q9

P2* 6D2 Q9f* ~

such that any

fiber of

Pi is a section

of f for

i

= 1, 2, deg

(J)1 =

deg (J)2

=

1,

and

deg ME3 -&#x3E; ~(a - 1 )/2 ~ ,

where in

(1)

and

(2-3) E1

and

E2

are smooth

elliptic

curves, pi:

E1

x

x

E2 - Ei

is the i-th

projection, Bi, Di

E Pic

(Ei) for

i =

1, 2,

E Pic

( C),

in

(2-1)

8’ =

oc for

21 E Pic

(C)

with

oc

and

2.el -= (9c, 3111

E

E Pic ( C),

p:

I~( ~ )

-~ C is the natural

projection,

:Jl:

X ~ P( 8)

is the

double

covering,

and T is a smooth

elliptic

curve with TF = 2

for

a

fiber

F

of f,

and in

(2-2)

B is a smooth

projective

curve

of

genus

(6)

two, J(B)

is the

jacobian variety,

and E Pic

(C). (For

x E

R, ~x]

denotes the smallest

integer

which is

greater

than or

equal

to

x.)

REMARK 1.6.1. In the case

(2-2)

in Theorem

1.6,

B cannot be gener- al.

Actually

if B is

general,

then the Neron-Severi group NS

(X)

is gener- ated

by

the class of the theta divisor. In

particular,

X does not contain

any

elliptic

curve.

PROOF. This can be

proved by

the same

argument

as in the

proof

of

Theorem 2.2 in

[Fk]. By assumption,

D is a smooth

elliptic

curve. Hence

by

Lemma

1.2,

there exists a

surjective morphism f :

X- C such that C is

a smooth

elliptic

curve, D is a fiber

of f,

and any fiber

of f is

smooth. Since LF = LD = 2 for any fiber F

of f,

we

get that f * o f * (L )

-~ L is

surjective.

Let 8 :

= f * L.

Then 8 is a

locally

free sheaf of rank two on

C,

and there

exists a

morphism : X -~ lh( ~ )

such

where : P(8)

- C is the bundle map.

By construction,

Jt is a double

covering.

Since X is an

abelian

surface,

the branch locus B is smooth and

linearly equivalent

to

- 2

Kp(,).

Furthermore L = Jt *

(H(8))

and 8 is

ample

with a, where

H(8)

is the

tautological

line bundle on

P(8). Since I - I

has

a smooth

member, by

the same

argument

as in the

proof

of

Proposition

2.3 in

[Fkl],

we can prove that there exists a vector bundle 8’ on C and a

line bundle J1 on C such that 8 = 8’

(9 M,

and 8’ and 311

satisfy

one of the

following

three

types;

(G~

there exists a nontrivial extension

and

where c4EPic(C)

with

Let

c : IE~( ~ ) -~ Ih( ~’ )

be the

isomorphism

such that Let JT

(1)

The case in which 8’ is the

type (A)

or

(B).

Let

Co

E

[ H( 8’ ) [

Then

Co

is an irreducible reduced curve

by Proposi-

tion 2.8 in

[Ha,

Ch.

V].

Let B be the branch locus of We remark that

-

2Kp(8’)

&#x3E; =

4 H( ~, ).

Since -2Kp(8’)CO=0,

we

get Co c B

or

Co n B = 0.

(7)

(1-1)

The case in which

Co c B.

Then =

2 B1.

Since LF = 2 for a fiber

F of f

and

B1

is not contained in a fiber

of f, B1

is a section

of f.

Hence

by

Lemma

1.3,

X =

= C x F and

f

is identified with the first

projection,

and

B1

is a fiber of

the second

projection

h : C x F ~ F. So we

get

where 1P e Pic

(F)

with

deg 1P

= 2. Therefore we

get

the

type (1)

in Theo-

rem 1.6.

(1-2)

The case in which

Co

n B = 0. Then we obtain one of the

following:

where Bi

is an irreducible reduced curve for

i = 2, 3,

4 with First we consider the case

(1-2-1).

PROOF. We remark that

B2

is a smooth

elliptic

curve. Hence

by

Lem-

ma

1.2,

there exists a

surjective morphism fl :

X -

C1

such that

C1

is a

smooth

elliptic

curve and

B2

is a fiber

of fl .

Hence

=

h ° (B2 )

= 1. On the other

hand,

since 7r’ is a double

covering,

we have

h ° ((,~’ ) * ( C° ) ) = h ° (H( ~’ ) ).

Hence

~(~))=1.

Therefore ~’ is the

type (B).

This

completes

the

proof

of Claim 1.7.

Since L =

(jr’)*(Co)0/*~

we obtain the

type (2-1)

in Theorem 1.6.

We remark that

B2 F

= 2 for a fiber

F of f.

Next we consider the case

(1-2-2).

If =

B3

+

B4 ,

then we

get

= 0 and = 0. Since

B3

and

B4

are not contained in a fiber

of f,

we

get

that

B3 F

=

B4 F

= 1 for

a fiber F

of f because

= 2. Hence

B3

and

B4

are sections

of f.

Hence

by

Lemma

1.3,

we

get

that X = C x

F, f

is identified with the first

projection,

and

Bi

is a fiber of the second

projection

h : X ~ F for

i = 3, 4.

Hence

by

the same

argument

as the case

(1-1),

we obtain L

f* X 0

® h * ~’,

where 0’ E

Pic (F)

with

deg

1P’ = 2.

Therefore we

get

the

type (1)

in Theorem 1.6.

(8)

(2)

The case in which 8’ is the

type (C).

Then

H(8’)

is

ample

with

H(8’ )2

= 1. We

put ox(A) = (Jt ’ )* (H(8’)).

Then AF = 2 for a fiber

F of f.

Since

A 2 =

2 and X is an abelian

surface,

we obtain

g(A)

= 2 and we

get

that

(X, A)

is one of the

type (I)

or

(II)

in Theorem 1.5. We remark that L =

(jr’ )* (H(~’ ) ) ® f *

J1 =

Of*

If

(X, A)

is the

type (II)

in Theorem

1.5,

then any fiber

of f is

not con-

tained in a fiber of pi and any fiber of pi is a section

of f for

i

= 1,

2 since AF = 2. Therefore if

(X, A)

is the

type (I) (resp. (II))

in Theorem

1.5,

then we

get

the

type (2-2) (resp. (2-3))

in Theorem 1.6. This

completes

the

proof

of Theorem 1.6.

DEFINITION 1.8. Let X be an abelian surface and let

L, L1, ... , Ln

be

ample

line bundles on X.

(A)

If

(X, L)

is the

type (2-1) (resp. (2-2), (2-3))

in Theorem 1.6 with

L 2 ; 2 a,

then we say that

(X, L)

is the

type (I; a) (resp. (II; a), (III; a)).

(B)

If X =

J(B)

and

Li

= B for a smooth curve B of genus two and i

= 1, ... ,

n, then we call

(X, L1, ... , Ln )

the

type (J),

where * denotes numerical

equivalence.

(0

If X =

El

X

E2

and L =

pt(CD1) ® ~2 ( ~2 )

with

(deg(JJ1, ( a , b)

or

(deg 6D,, ( b , a),

then we call

(X, L )

the

type

(P; {a, 6}),

where

El and E2

are smooth

elliptic

curves, pi is the i-th pro-

jection,

and for i =

1,

2.

(D) If X = El

X

E2

and

Li

= with

deg Di

= ai , then we

call

(X, L)

the

type (PS; t;

aI, ... ,

an ),

where

El

and

E2

are smooth

ellip-

tic curves, pt is the t-th

projection, Si

is a section of pt, and ~2 E Pic

(Et)

for

i = 1, ... , n.

2. The case in which

L1 + ... + Lt

is not

ample

for t = k + 1 or 1~ . THEOREM 2.1. Let X be an abelian

surface,

and let

L1

and

L2 be ample

line bundles on X. We

put

L : =

L1

+

L2 .

Then L is not very

ample if

and

only if (X, L1, L2 ) satisfies

one

of

the

foLLowing:

(1) (X,

the

type (J),

(2) (X , L1, L2 )

is the

type

with a1 &#x3E;

0,

a2 &#x3E;

0,

and

t = 1, 2.

(9)

PROOF. First we prove the «if»

part.

If

(X, L1, L2 )

is the

type (1),

then

L 2

=

(L1

+

L2 )2

= 8 and

h ° (L ) _

= L 2 /2

= 4. If L is very

ample,

then X is a

hypersurface

of

degree

8 in

p3.

But this is

impossible

because X is an abelian surface. Hence L is not very

ample.

If

(X, L1, L2 )

is the

type (2),

then

LF,

=

2,

where

F1

is a fiber of pi . If L is very

ample,

then

F1

= But this is

impossible

because X is an

abelian surface.

Next we prove the

«only

if»

part.

Assume that L is not very

ample.

Then

L 2

=

(L1

+

L2 )2 ~

8 because

2, 2,

and 2.

(A)

The case in which

L 2

= 8.

Then

L1 L2

= 2 and

L2

= 2.

By Hodge

index

Theorem,

we obtain

that

Li = L2.

Since

g(L1 )

=

2,

we

get

that

(X, L1 )

is the

type (I)

or

(II)

in

Theorem 1.5.

If

(X, L1 )

is the

type (I),

then

L2

--- B.

If

(X, L1 )

is the

type (II),

then we can

easily

prove

L2=pi*(Di0

®p2*D’2,

where

6D! E Pic (Ei )

with

deg D’1

=

deg 6D2’

= 1.

(B)

The case in which

L 2 ;

10.

By

Reider’s

Theorem,

there exists an effective divisor D on X such that

(LD , D 2) = (2, 0) or (1, 0)

because the value of

D 2

is even. Since L =

L1

+

L2

and

Li

is

ample

for i =

1, 2,

we

get (LD , D 2 )

=

( 2 , 0 ).

So we

have

Li D

= 1 for each i.

By

Remark

1.3.1,

there exists a fiber space

f :

X- C such that C is a smooth

elliptic curve, X

= C x

F, f

is identified with the first

projection

via this

isomorphism,

and D is a fiber

of f,

where

F is a fiber

of f.

Since

Li F =

1 for each

i,

we obtain that

0 for i =

1, 2,

where

mj

E Pic

(C) and Si

is a section

of f.

Since

Li

is

ample,

we

get Li Si

&#x3E; 0. Hence

deg 6Di

&#x3E; 0 because

Si2

= 0. This

completes

the

proof

of Theorem 2.1.

COROLLARY 2.1.1. Let X be an abelian

surface

and let L be an am-

ple

line bundle on X. Then 2L is not very

ample if

and

only if (X, L) satisfies

one

of

the

following:

(1) (X, L) is

the

type (J),

(2) (X, L) is

the

type (P; ~ a , b 1)

with a &#x3E; 0 and b = 1.

(10)

PROOF. We

put L1=

L and

L2

= L. Then we

get

the above result

by

Theorem 2.1. We remark that if then we use Lemma 1.3.

THEOREM 2.2. Let X be an abetian

surface

and let

L1, ... , Lk

+ 1 be

ample

line bundles on X. Assume that k ~ 2. We

put

L : =

L1

+ ... +

+

Lk

+ 1. Then L is not

k-very ample if and onLy if (X, L1,

... ,

Lk + 1 )

is the

type (PS; t;

... ,

ak + 1 )

with ai &#x3E; 0

for any i,

and t =

1,

2.

PROOF. First we prove the «if»

part.

Let

Fl

be a fiber of Then

+ 1. But

by

Theorem

1.4,

L is not

k-very ample.

Next we prove the

«only

if»

part.

Then

Assume that L is not

k-very ample.

Then

by

Theorem

1.4,

there exists an

effective divisor D such that

Because LD =

(L1

+ ...

+ Lk + 1 ) D,

there exists an

ample

line bundle

Li

such that

Li D

= 1. We may assume that i = 1.

By

Remark

1.3.1,

there exists a fiber

space f :

X - C such that C is a smooth

elliptic

curve, X =

= C x

F, f is

identified with the first

projection

via this

isomorphism,

and D

is a fiber

of f,

where F is a fiber

of f.

On the other

hand, by

Theorem

1.4,

we

get

LD ~ k + 1 since

g(D)

= 1. Hence

Li D

= 1 for any i. Since D is a

fiber

of f and

&#x3E; 0 for i =

1,

... , k +

1,

we

get

that

Li == f* CDi Q9

Q9 for i =

1, ... , k

+

1,

where

6Di

E Pic

( C), Si

is a section

of f.

Since

Li

is

ample,

we

get Li Si

&#x3E; 0. Hence

deg 6Di

&#x3E; 0 because

S 2

= 0 for any i. This

completes

the

proof

of Theorem 2.2.

By

Theorem

2.2,

we can prove the

following Corollary.

COROLLARY 2.2.1. Let X be an abelian

surface

and let L be an am-

ple

line bundle on X Then

for

k ~

2, (k

+

1 ) L

is not

k-very ample if

and

onLy if (X, L) is

the

type (P; {o, b 1)

with a &#x3E; 0 and b = 1.

THEOREM 2.3. Let X be an abelian

surface

and let

L1,

... ,

Lk be

ample

line bundles on X. Assume that k a 3. We

put L : = L1 + ... + Lk.

(11)

Then L is not

k-very ample if

and

only if (X, L1, ... , Lk )

is one

of

the

following:

(1) k

= 3 and

(X, L 1, L2 , L3 ) is

the

type (J),

(2) (X, L1,

... ,

Lk - 1 )

is the

type (PS; t;

ai , ... , ak _

1 ),

and

Lk

=

= put*

0 where

6Dk

E Pic

(Et )

with

deg

6Dk

0,

pt is the t-th pro-

jection,

T is a divisor on X with

TFt

= 2

for

a

fiber Ft of

pt, ai is a

positi-

ve

integer for

i

= 1,

... , k -

1,

and t =

1, 2,

(3)

the

type (PS; t;

aI,

... , ak )

with ai &#x3E; 0

for

...,

k,

and

t=1, 2.

PROOF. First we prove the «if»

part.

If

(X, L1,

... ,

Lk)

is the

type (1)

in Theorem

2.3,

then k =

3,

LB =

- (L1

+

L2

+

L3) B

=

6, and g(B)

= 2. Then

by

Theorem

1.4, L

is

not 3-very ample.

If

(X, L1,

... ,

Lk )

is the

type (2)

or

(3)

in Theorem

2.3,

then

~ k + 1 for a

fiber F1

of pi. Then

by

Theorem

1.4,

L is not

k-very ample.

Next we prove the

«only

if»

part.

We calculate

L 2 :

Since 1~ ~

3,

we

get 2 k 2 ~ 41~ + 6.

So we have

L2&#x3E;-

4 k + 6. Assume that L is not

k-very ample.

Then

by

Theorem

1.4,

there exists an effective divi-

sor D on X such that

We may assume that

Then we obtain that 2.

By Hodge

index

Theorem,

we

get D 2 2.

(2.3.1 )

The case in which

D 2 =

2.

Then

L1 D

= 2 and

L1=

D

by Hodge

index Theorem. Since

g(L1 )

=

2,

we obtain that

(X, L1 )

is the

type (I)

or

(II)

in Theorem 1.5. On the other

hand, by g(D) = 2, L1 D = 2,

and Theorem

1.4,

we

get

(12)

Hence k = 3 and

L1 D

=

L2 D

=

L3 D

= 2. So

by Hodge

index

Theorem,

we

get L1 = L2 = Z.3

= D. Therefore we

get

the

type (1)

or

(3)

in Theorem

2.3.

(2.3.2)

The case in which

D 2

= 0.

(2.3.2.1)

The case in which

L1 D

= 2.

Then

by assumption,

we have LD ~ 2 k. Hence

by

Theorem

1.4,

we

get

2 k ~ LD ~

2 g(D )

+ 1~ - 1 = l~ + 1. Therefore k 5 1 and this is a contra- diction.

(2.3.2.2)

The case in which

L1 D

= 1.

By

Remark

1.3.1,

there exists a fiber

space f :

X- C such that C is a

smooth

elliptic curve, X =

C x

F, f

is identified with the first

projection

via this

isomorphism,

and D is a fiber

of f,

where F is a fiber

of f.

Since

k~(L1+...+Lk)D~2g(D)+k-1 =k+1,

we

get

type (2)

in Theorem

2.3,

and if

(L1 D , ... , Lk _ 1 D , Lk D ) _ ( 1,

... ,

1, 1),

then

(X, L1,

... ,

Lk)

is the

type (3)

in Theorem 2.3

by using

the same ar-

gument

as in the

proof

of the above Theorems. This

completes

the

proof

of Theorem 2.3.

THEOREM 2.4. Let X be an abelian

surface

and let L be an

ample

Line bundles on X. Then

for k ~ 2,

kL is not

k-very ample if

and

only if (X, L)

is one

of

the

following:

(1) k

= 2 or

3,

and

(X, L) is

the

type (J),

(2) (X, L)

is the

type (P; {a, b 1)

with a &#x3E; 0 and b = 1.

PROOF. For k a

3,

this is a

corollary

of Theorem 2.3. Assume that k = 2.

By

the same

argument

as in the

proof

of Theorem

2.3,

we can

prove the «if»

part.

So we prove the

«only

if»

part.

Assume that L is not

2-very ample.

(2.4.1)

The case in which

L 2 ~ 4.

Then

( 2 L )2 ~ 16,

and

by

Theorem

1.4,

there exists an effective divisor D on X such that

(2L)

D ~

2g(D)

+ 1 ~ 5. If

D 2

&#x3E;

0,

then

by Hodge

in-

dex

Theorem,

we

get

LD ~ 3 and this is

impossible.

Hence

D 2 =

0 and

g(D)

= 1. Therefore 2 LD ~

3,

that

is,

we obtain LD = 1. So D is a smooth

(13)

elliptic

curve.

By

Lemma 1.2 and Lemma

1.3,

we can prove that

(X, L )

is the

type (P; ~ a , b 1)

with a &#x3E; 0 and b = 1.

(2.4.2)

The case in which

L 2 =

2.

Then

(X, L)

is one of the

type

in Theorem 1.5.

This

completes

the

proof

of Theorem 2.4.

3. The case in which

(n - t) L

is not

k-very ample

for t =1 and 2.

THEOREM 3.1. Let

(X, L) be

a

polarized

abelian

surface.

Let

(k, t)

be a

pair of integer

which

satisfies

the

following inequalities;

(A) k ; 3t + 1, (B) t ~

1.

Then

( k - t)L

is not

k-very ample if

and

only if

one

of

the

following types holds;

(1) (k, t)

=

(4, 1), (5, 1 ),

or

(7,2),

and

(X, L) is

the the

type (J), (2) (X, L)

is the

type (P; {a, b 1)

with a &#x3E; 0 and b = 1.

PROOF. First we remark that

( k - t )2 L 2 ;

4 k + 6 unless

(L 2 , k , t )

=

- (2, 4, 1 ).

We prove the «if»

part

of Theorem 3.1. If

(X, L)

is the

type (1)

in Theorem

3.1,

then

( k - t)

LB ~

2g(B)

+ k - 1 ~ 2 k + 1. Hence

by

Theo-

rem

1.4,

L is not

k-very ample.

If

(X, L)

is the

type (2)

in Theorem

3.1,

then

(k - 2g(Fl )

+ k - 1 ~ 2k + 1 for any fiber

F1

of Pl. Hence L is not

k-very ample by

Theorem 1.4.

Next we prove the

«only

if»

part.

(3.1.1 )

The case in which

L 2 ~

4.

Since

(k - t)2 L 2 ~ 4 k + 6, by

Theorem

1.4,

there exists an effective divisor D on X such that

( k - t)

LD ~

2 g(D )

+ k - 1 ~ 2 k + 1.

Assume that

D 2

&#x3E; 0.

Then, by Hodge

index

Theorem,

we

get

LD ~ 3.

Hence

3(k-t)~(k-t)LD~2k+1,

and we obtain k~3t+1.

By hy- pothesis

we have k = 3 t + 1 and LD = 3. So we

get D 2

= 2 and

g(D)

= 2.

By

Theorem

1.4,

we have

3( 2 t

+

1)

=

(k - t)

LD ~ k + 3 =

= 3 t + 4,

and so we have t 1 /3. But this is a contradiction.

Hence

D 2

= 0 and

g(D)

= 1.

By

Theorem

1.4,

we obtain

( k - t ) LD ~

~k+ 1.

(14)

Assume that LD ~ 2. Then we

get

k - 1 ~ 2 t. Since

k ~ 3 t + 1,

we

get

3 t ~ 2 t. This is

impossible

because t ~ 1. Hence LD = 1.

Therefore D is a smooth

elliptic

curve and

by

the same method as in

the

proof

of the above

theorems,

we

get

that

(X, L)

is the

type

(P; {a,

with a &#x3E; 0 and b = 1.

(3.1.2)

The case in which

L 2 = 2.

Then

by

Theorem

1.5,

we

get

that

(X, L )

is one of the

types

in Theo-

rem 1.5.

In order to prove Theorem

3.1,

it is sufficient to

study

the case in

which X =

J(B)

and L =

B,

where B is a smooth

projective

curve of genus 2 and

J(B)

is

its jacobian variety.

If

( k , t)

=

(4, 1),

then

( k - t )2 L 2

4 k + 6 and

( k - t ) L

is not

k-very ample by

Theorem 1.4. So we assume

that

( k , t ) ~ ( 4 , 1 ).

Then

( k - t )2 L 2 ~ 4 k + 6.

Then

by

Theorem

1.4,

there exists an effective divisor D on X such that

( k - t)

LD ~

2g(D)

+

+ k - 1 ~ 2 k + 1. Here we remark that we can prove LD ~ 2

by

Remark

1.3.1 since L * B.

(3.1.2.1)

The case in which LD ~ 3.

Then 3k-3t;

(k-t)LD~2k+1.

So we have k~3t+1.

By hy- pothesis,

we

get

k = 3 t + 1 and LD = 3. Since

L 2

=

2,

we obtain

D 2 ;

4.

Hence2k-5 ~3t. and 4. Be-

cause k = 3 t

+ 1,

we obtain

(k, t)

=

(4, 1 )

and this is a contradiction.

(3.1.2.2)

The case in which LD = 2.

If

D~

=

0,

then

g(D)

= 1. So

by

Theorem

1.4,

we

get 2(k - t) _

= (k - t)

LD ~ k + 1. Hence k - 1 ~ 2 t. Since k ~ 3 t +

1,

this is

impossi-

ble because t ~ 1.

If

D 2

&#x3E;

0,

then L = D since LD = 2 and

L 2

= 2.

By

Theorem

1.4,

we

get 2(k-t) _ (k-t)LD~k+3.

Hence k-3 ~2t. Since

k~3t+1,

we

get

3 t - 2 ~ 2 t. Therefore t S 2.

If

t = 1,

then

2(k -1 ) _ (k - t) LD ~ k + 3.

Hence k ~ 5. Because

4 = 3 t + 1; k,

we

get

k = 5

by

the

assumption

that

(k, t) # (4, 1 ).

If

t = 2,

then

2(k - 2 ) _ (k - t) LD ~ k + 3.

Hence k ~ 7. Because

7=3t+1 ;k,

we

get

k=7.

This

completes

the

proof

of Theorem 3.1.

THEOREM 3.2. Let

(X, L)

be a

polarized

abetian

surface.

Let

( k , t)

be a

pair of integers

with 3 t ; k ~ 2 t +

1,

t ~

1,

and

( k , t ) ~ ( 3 , 1 ).

Then

(15)

(k - t)

L is not

k-very ample if

and

only if

one

of

the

following

holds:

and

tg ~ 3,

and

(X, L) is

the the

type (J),

(2) (X, L) is

the

type (P; {a, b ~ )

with a ~ 1 and

b = 1,

(3) k = 2 t + 1

and

(X , L )

is the

type (P; ~ a , b 1)

with a ~ 1 and

b = 2,

(4) k

= 2 t + 1 and

(X, L)

is one of the

type (I; 2), (II; 2),

or

(III; 2).

PROOF. First we prove the «if»

part.

If

(X, L)

is the

type (1)

in Theo-

rem

3.2,

then

( k - t )

LB ~

2 g(B )

+ k - 1 ~ 2 k. Hence L is not

k-very

am-

ple by

Theorem 1.4. If

(X, L)

is the

type (2)

or

(3)

in Theorem

3.2,

then

(k - t) 2g(Fl)

+ k - 1 ~ 2k for a fiber

F1

of pl. Hence L is not k- very

ample by

Theorem 1.4. If

(X, L)

is the

type (4)

in Theorem

3.2,

then

(k - t )

LF ~

2 g(F)

+ k - 1 ; 2 k for a fiber F

of f.

Hence L is not

k-very ample by

Theorem 1.4.

Next we prove the

«only

if»

part.

(A)

The case in which

L 2 ~

4.

First we remark that

(k - t)2 L 2 ;

4 k + 6

by assumption.

Hence

by

Theorem 1.4 there exists an effective divisor D on X such that

(k - t) LD 2g(D) + k -1 2k + 1.

If LD ~

4,

then

4(k - t) ~

2 k +

1,

that

is,

2 k ~ 4 t + 1. Since k ~ 2 t +

+ 1,

we

get

that 4 t + 1 ; 2 k ~ 4 t + 2. But this is

impossible.

Hence

LD~3.

If

LD = 3,

then

D 2 ~ 2

since

L 2 ~ 4.

Therefore

3(k - t) =

= (k - t) LD £ k + 3 because g(D ) ~ 2.

So we have 2 k ~ 3 t + 3.

Since k ; 2 t + 1,

we obtain that 3 t + 3 ~ 4 t + 2. Since t ~

1,

we have t = 1 and k = 3. But

by assumption

this is a contradiction. Hence LD ~ 2 and

D 2

= 0.

If LD =

1,

or LD = 2 such that D is not an irreducible reduced curve, then there exists an irreducible reduced curve B such that LB = 1. Then

by

Lemma 1.2 and Lemma

1.3,

we

get

the

type (2)

in Theorem 3.2.

If LD = 2 such that D is an irreducible curve, then D is a smooth el-

liptic

curve. Then

2(k - t )

=

( k - t )

LD ~

2 g(D )

+ k - 1 = k + 1. Hence k ~ 2 t + 1.

By assumption

k = 2 t + 1 in this case. Then

by

Theorem

1.6,

we

get

the

type (3)

or

(4)

in Theorem 3.2.

(B)

The case in which

L 2 =

2.

(16)

Then

(X, L)

is the

type (I)

or

(II)

in Theorem 1.5. If

(X, L)

is the

type (II)

in Theorem

1.5,

then

(X, L)

is the

type (2)

in Theorem 3.2. So it is sufficient to

study

the case in which

(X, L )

is the

type (I)

in Theorem

1.5.

Assume that X =

J(B)

and L is the class of a translation of the theta

divisor,

where B is a smooth

projective

curve of genus 2 and

J(B)

is its

jacobian variety.

Then we remark that

( k - t )2 L 2 ~ 4 k + 6 (resp.

( k - t )2 L 2 4 k + 6)

if t ~ 4

(resp. t ~ 3).

If

t ~ 3,

then we

get

that

( k - t ) L

is not

k-very ample by

Theorem 1.4. Since 3 t ~ k ; 2 t + 1 and

(k, t ) ~

~

( 3 , 1 ),

we

get

that

( k , t)

=

(9, 3),(8, 3),(7, 3),(6, 2)

or

( 5 , 2 ).

Assume that t ~ 4. Then

by

Theorem

1.4,

there exists an effective di- visor D on X such that

( k - t)

LD ~

2 g(D )

+ k -1 ~ 2 k + 1.

IfLD ~

4,

then this is

impossible by

the same

argument

as in the case

(A).

Hence LD ~ 3. We remark that LD ~ 2 since L is the class of a

translation of the theta divisor. Since

L 2 = 2,

we

get

that

D 2 ~ 4

and

g(D) ~

3.

If LD =

3,

then

3(k - t ) ~ k

+ 5. Hence 2 k ~ 3 t + 5. Since

k ; 2 t + 1,

we

get 4 t + 2 ~ 2 k ~ 3 t + 5,

that

is,

t ~ 3. But this is a contradiction.

If LD =

2,

then

D 2-

2.

If D 2= 2,

then

g(D)

= 2 and

2(k - ~) ~

+ 3.

Thus we have k ~ 2 t + 3. Hence k = 2 t +

1,

2 t +

2,

and 2 t + 3.

If

D 2

=

0,

then

g(D)

= 1 and

2(k - t) ~

k + 1. Hence k ~ 2 t + 1. Since

k;2t+1,

we

get k=2t+1.

This

completes

the

proof

of Theorem 3.2.

COROLLARY 3.3. Let

(X, L)

be a

polarized

abelian

surface.

Assume

that k a 2 t +

4 for ( k , t)

E

~T®2.

Then

( k - t)

L is not

k-very if

and

only if (X, L)

is the

type (P; ~ a , b 1)

with a &#x3E; 0 and b =1.

PROOF. This is obtained

by

Theorem 3.1 and Theorem 3.2.

THEOREM 3.4. Let

(X, L) be

a

polarized

abelian

surface.

Assume

with k ~ 3. Then

(k - 1 )L is

not

k-very ample if

and

only if

one

of

the

following

holds:

( 1 )

k =

3, 4,

or

5,

and

(X, L)

is the

type (J),

(2) (X, L)

is the

type (P; I a,, a2 1)

with a1 &#x3E; 0

and a2

=

1,

(3) k = 3

and

(X, L) is

the

type b2 ~ )

with and

b2=2,

(4)

k = 3 and

(X, L) is

one

of

the

type (1; 2), (II; 2),

or

(III; 2),

(5)

k=3 and

L2=4.

(17)

PROOF. We can

easily

prove the «if»

part by

Theorem 1.4. So we

prove the

«only

if»

part.

If k ~

4,

then this is a

corollary

of Theorem

3.1,

and

(X, L)

is one of the

type (1)

or

(2)

in Theorem 3.4. So we may assume that k = 3.

(A)

The case in which

L 2 ;

6.

Then

4 L 2

=

( k -1 )2 L 2 ;18

= 4 k + 6. Hence

by

Theorem

1.4,

there exists an effective divisor D on X such that 2 LD ~

2g(D)

+ 2 ~ 7. Hence LD 3. Since

L 2 ~

6 we

get

that

D 2

= 0 and

g(D )

= 1. Therefore 2 LD ~

~ 4,

that

is,

LD ~ 2.

If LD =

1,

or LD = 2 and D is not irreducible and

reduced,

then there

exists an irreducible and reduced curve B on X such that LB = 1. Hence

by

Lemma 1.2 and Lemma

1.3,

we

get

that

(X, L)

is the

type (2)

in Theo-

rem 3.4.

If LD = 2 and D is irreducible and

reduced,

then

by

Theorem 1.6 we

get

that

(X, L)

is one of the

type (3)

or

(4)

in Theorem 3.4.

(B)

The case in which

L 2

= 2.

Then

by

Theorem

1.5,

we

get

that

(X, L )

is one of the

type (1)

or

(2)

in Theorem 3.4.

(0

The case in which

L 2

= 4.

Then

(X, L)

is the

type (5)

in Theorem 3.4.

This

completes

the

proof

of Theorem 3.4.

THEOREM 3.5. Let

(X, L)

be a

polarized

abelian

surface.

Assume

with k ~ 4. Then

(k - 2 ) L

is not

k-very ample if

and

only if

one

of

the

following

holds:

( 1 )

k =

4 , 5 , 6,

or

7,

and

(X, L)

is the

type (J),

(2) (X, L)

is the

type (P; I a,, a2 1)

with a1 &#x3E; 0

and ct2

=

1,

(3) k

= 4 or

5,

and

(X, L)

is the

type b2 ~ )

with and

b2

=

2,

(4) k

= 4 or

5,

and

(X, L)

is one

of

the

type (I; 2), (II; 2),

or

(III; 2),

(5)

k=4 and

L2=4.

PROOF. We can

easily

prove the «if»

part by

Theorem 1.4. So we

prove the

«only

if»

part.

If k ;

7,

then this is a

corollary

of Theorem

3.1,

and

(X, L)

is one of the

type (1)

or

(2)

in Theorem 3.5.

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