R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
N ICOLAE P OPESCU
C ONSTANTIN V RACIU
On the extension of a valuation on a field K to K(X ). - II
Rendiconti del Seminario Matematico della Università di Padova, tome 96 (1996), p. 1-14
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NICOLAE
POPESCU (*) -
CONSTANTINVRACIU (**)
SUMMARY - Let K be a field and v a valuation on K. Denote
by
K(X) the field of ra-tional functions of one variable over K. In this paper we go further in the
study
of the extensions of v to K(X). Now our aim is to characterize two types ofcomposite
valuations: r.a. extensions of first kind (Theorem 2.1) and thecomposite
of two r.t. extension (Theorem 3.1). The results obtained are basedon the fundamental theorem of characterization of r.t. extensions of a valua- tion (see [2], Theorem 1.2, and [6]) and on the theorem
of irreducibility
of lift-ing polynomials
(see [7],Corollary
4.7 and [9], Theorem 2.1). The result of this work can be utilised, forexample,
to describe all valuations on ... ,(the field of rational functions of n
independent
variables) and elsewhere. A first account of thisapplication
isgiven
in [10].1. - Notations. General results.
1) By
a valued field(K, v)
we mean a field K and a valuation v on it. We shall utilise the notationsgiven in [8, § 1]
for notions like:residue
field,
value group, etc. Denoteby
K a fixedalgebraic
closure ofK and denote
by v
a(fixed)
extension of v to K. ThenGv
isjust
the ratio-nal closure of =
Gv and kv
is analgebraic
closure ofkv .
Ifa E
K,
the number[K(a) : K]
will be denotedby deg
a(or degk
a if thereis
danger
ofconfusion).
An element be called aminimal
pair
withrespect
to(K, v)
if for any b EK,
the condition(*) Indirizzo dell’A.: Institute of Mathematics of the Romanian
Academy,
P.O. Box 1-764, RO-70700
Bucharest,
Romania.Partially supported by
the contract 4004.(**) Indirizzo dell’A.:
University
of Bucharest,Department
of Mathematics, Str. Academiei 14, 70109 Bucharest, Romania.Partially supported by
the «PECO» contract 1006.v(a - b) a 3 implies deg a ~ deg b.
We shall saysimply
«minimalpair»
if there are no doubts about
(K, v).
Let
K(X)
be the field of rational functions in an indeterminate Xover .K. If r E
K(X),
letdeg r
=[K(X) : K(r)].
A valuation w onK(X)
willbe called a r.t.
(residual transcendental)
extension of v toK(X)
if the(canonical) extension kv
ckw
is transcendental. The r.t. extensions of v toK(X)
areclosely
related to minimalpairs (a, ð)
E Kx Gv .
Let
(a, d )
be a minimalpair.
Denoteby: f
the monic minimalpolyno-
mial of a over K and let y
a’)),
where a ’ runs over allroots
of f.
a’Moreover let v’ the restriction of v to
K(a) (it
may beproved
that v’is the
unique
extension of v toK( a ) ) .
Finally
let e be the smallest non-zeropositive integer
such thatey e
Gvt.
let:
be the
f-expansion
of F. Let usput:
Then one has:
THEOREM 1.1
(see [2], [6]).
Theassignment (1) defines
a valuationon
K[X]
which has aunique
extension toK(X).
Thisvaluation,
denotedby
W(a,,3) is an r. t. extensionof
v toK(X).
Moreover one has:a) Gw(a,
6 =Gv’
+Zy
gGv .
b)
Let h EK[X]
be such thatdeg
hdegf
and that v’(h(a))
= ey.Then r =
f /h
is an elementof K(X) of
smallestdegree
such thatw(a, a ~
(r)
=0,
and such that r * theimage of
r in the residue is transcendental overkv .
One also has:kw(a, 5)
=kv, (r * ).
c) If (a, ð), ( a’ , d’ )
are two minimalpairs,
then = w(a - , a, ~ whenever 6 = d ’ andv( a - a’ ) :
3 .’ ’
d) If w
is a r.t. extensionof v
toK(X),
there exists a minimalpair (a, ~ ) (with respect
to(K, v))
such that W = w(~, a~ .If
W = W(a,,3), we shall say that w is definedby
the minimalpair ( a, d )
and v.Let W = W(a,,5) be an r. t. extension
of
v toK(X).
Wekeep
the nota-tions
of
theprevious
theorem. Let g be a monicpolynomial
ink,, [r * ],
(with respect
to the «indeterminate»r * ),
i. e.:By
alifting of g
toK[X]
withrespect
to w we mean(see [9])
apoLynomi-
al G e
K[X]
such that:It is clear that there are many
liftings
of g toK[X]
withrespect
to w.However one has the
following
result:THEOREM 1.2
([9]).
Let g be an irreduciblepolynomial of [r*]
with non-zero
free
term. Then anylifting
Gof
g to(with respect
tow)
is also an irreduciblepolynomial.
2)
The reader can refer to[11]
for the notion ofcomposite
valua-tions
appearing
in the next result.THEOREM 1.3. Let w = be a r.t. extension
of
v toK(X).
Letg E
kv’ [r* ]
be an irreduciblepolynomial
with non-zerofree
term andlet G be a
lifting of g
toK[X] (with respect
tow).
Let u ’ be the valuationon
(r * ),
trivial onkv, , defined by
irreduciblepolynomial
g. Denoteby
u the valuation onK(X) composite
with w and u’ . Then:i) Gu (the
value groupof u)
isisomorphic
to the directproduct Gw
xGu - ,
orderedlexicografically.
ii)
Let F EK[X ]
and letbe the
G-expansion of
F. Then one has:PROOF. It is well know that
G.,
= Z. We shall divide theproof
intwo
steps.
A)
At thispoint
we shall prove thatGu
=G~
xZ,
this last groupbeing
orderedlexicografically. According
to thegeneral theory
of com-posite
valuations(see (11)
or(5))
there exists the exact sequence of groups:where E and p are defined in a canonical way. Now look at the Theorem 1.1. Let a e
K(X).
SinceGw
=G,,
+Zy,
and ey E one hasw(a) =
= q +
ty, where q
EG,,,
and 0 ~ t e. Let us denote:For any a E
K(X)
there exists a’ E A such thatw(a)
=w( a’ ).
Thus onehas
w( a/a’ )
= 0 andu( a/a’ )
=ê(U’ «a/a’)*».
HenceNow we shall prove that the subset:
is a
subgroup
of G andB n e(Gu’)
= 0.Indeed,
let b =u(Hft)
e B. Thenp(b) =
=v’ (H(a))
+ty.
If b =E(c),
thenp(b)
=0,
and sov’ (H(a))
=0,
and t = 0. But then c= u’ (H(a)* )
=0,
sinceH(a)*
ekv, ,
and ~’ is trivial
over k.,.
Hence =0,
as claimed.Let
u(Hf t), u(H’ft’)
be two elements of B. In order to prove that B is asubgroup,
one must show that their difference: b =u«H/H’)ft-t’)
also
belongs
to B.First,
let us assume that t - t’ ~ 0. Let H" EK[X]
be such that
deg H" n
and thatw(H’ ’ )
=v’ (H"(a))
=w(H/H’ ).
Then
b = u(H"ft - t’). Indeed,
one hasw((H/H’ ) H")
= 0 and so,according
to([7], Corollary 1.4), ((H/H’ ) H")* E ku, . Therefore,
= 0,
and soE B.
Now consider the case t - t’ 0. Then
n, be such
that w(H") _
As
above,
one has:u«H/H’)ft - t’)
=u(H "f e + t - t’) E
B.Therefore B is a
subgroup
ofGu ,
andby (2)
it follows that there existsan
isomorphism
of groups:If B x
e( G u’)
is orderedlexicografically, then j
is anisomorphism
of or-dered groups.
Indeed,
let eK(X)
be such thatu(a) ~
Leta ’ ,
E A be such thatw(a)
=w( a’ )
and =w(~3’ ).
Then=
u(fl’ )
+E(u’ «{3/{3’)*».
Sinceu(a) 5
it follows thatw(a) ~
and so 0. Since the restrictionof p
to B defines an isomor-phism
of ordered groups to B ontoGw ,
it follows that~
u( a’ ).
Let us assume that
u( a )
andu( a’ )
=u(~3’ ).
Thenby (2),
it fol-lows :
~(u’ ((~/(3’ )* ))
>E(u’ ((a/a’ )* )).
Hence >j(u(a)),
asclaimed.
We have
already
noticed that B =Gw and
sinceGu,
= Z we may as-sume that
where the
right
hand side is orderedlexicografically. Moreover,
if a Eand a ’ E A is such that
w(a) = w( a’ ), then, by (2),
one has:u(a) = (w(a’ ), u’ «a/a’)*»
EGw
x Z.B)
Let G be alifting of g (with respect
tow).
Now we shall deter- mine uusing
G and w. Sincew(G)
= mey then we may choose H e A be such thatw(H) =
mey. Thenu(G) = (w(H), u’ ((G/H)*)).
But(GIH)* = /H)*
= ag, where a ek’ (see [7] Corollary 1.4).
Hence
u’ ((G/H)* )
= 1.Therefore,
one has:Now let be such that
deg F deg G.
We assert that:Indeed,
let a EA,
a =Hf
be such thatw(a)
=w(F). Also,
let F =Fo
+be the
f expansion
of F. Sincew(F) = w(a) =
=
v’(H(a))
+ty,
then the smallest index i such thatw(F)
=w(Fi)
+iy (see ( 1 ))
is necessarybigger than t,
and thusIt is clear that
if j -
t 00(mod e),
thenw(Fj lhfj - t)
> 0 and so we mayassume that
only
termswith j - t
=0(mod e)
appear in(4).
If we write for a such term:then, according
to([7], Corollary 1.4),
it follows(4)
is an element ofkv- [r * ]
whosedegree (relatively
to the variabler *)
is smaller than m ==
degg.
Henceu ’ ((Fla)*)
=0,
and so(3) holds,
as claimed.Furthermore,
let F E and let F =Fo
+Fl G
+ ... +Fq G q
bethe
G-expansion
of F. Let i be the smallest index such thatw(Fi)
++
iw( G ) ~ + jw( G )
forall j,
0~j ~
q, and such thatw(Fi)
++
iw(G) w(Fi)
+jw(G)
forall j
i. We assert that one has:(5) w(F)
=w(Fi)
+iw(G) .
For
that,
we shall prove that aninequality
in(5) (necessarily > )
leadsto a contradiction.
Indeed,
since 0 forall j ,
0% j 5
q,by
the choice of i one has:or
equivalently,
since = g,At this
stage
it is easy to see(according
to the aboveconsiderations)
that forall t,
the non-zero coefficientsof g
in(6)
are of the formU/V
where
U,
and thatdeg
U m,deg
V m(the degrees
withrespect
tor *).
This shows that(6)
isimpossible,
and so(5) holds,
asclaimed.
Furthermore
by (7)
it follows that so that=
E(u’ ((F/Fi G)*))
= 0. SincedegFi deg G
we thenhave
The
proof
of Theorem 1.3 is nowcomplete.
2. - Extensions of the first kind in
general setting.
We shall
freely
use the notations and definitionsgiven
in theprevi-
ous section.
Let
(K, v)
be a valued field. A valuation u onK(X)
will be called an r.a.(residual algebraic)
extension of v if u is an extension of v and the extensionkv c ku
isalgebraic.
The r.a. extension u is called of thefirst
kind if there exists an r.t. extension w ofv to
K(X)
such that u ~ w. Theorem 4.4 in[8]
describes all r.a.extensions of the first kind of v when K is
algebraically
closed.Now we shall describe these extensions in the
general setting (i.e.
K is not
necessarily algebraically closed).
The results of this sectiongeneralise
the resultsgiven
in([8],
Section3). Moreover,
wegive
a
simplified proof.
THEOREM 2.1. Let
(K, v)
be a valuedfield.
Let u be an r. a. exten-sion
of
thefirst
kindof v
toK(X).
Let w be an r. t. extensionof v
toK(X)
such that u ~ w. Let u be the valuation induced
by
u onkw
such that uis the
composite
with valuations w and u’ . Then one has:1)
There exists anisomorphism of
ordered groupsGu
=Gw
xZ,
the direct
product being
orderedlexicografically.
2)
Let u’ bedefined by
the monic irreduciblepolynomial
g EE
[r * ],
whosefree
term is not zero(i.
e.g 0 r * ). Let
G be alifting of g
toK[X]
withrespect
to w.If
F eK[X]
and F =Fo
+Fl
G + ... +Fq
G q isthe
G-expansion of F,
then one has:3)
Let u’ bedefined by
r* .If F e K[X]
and F =Fo
+F1f
+ ... ++
Fq f q
is thef expansion of F,
then one has:4) If
u’ is the valuation at theinfinity (i.e. defined by r*-1)
then:
(Here
means theintegral part of
cx realPROOF. The
points 1)
and2)
have beenproved
in Theorem1.3,
sowe have to prove
only 3)
and4).
Consider
again
the set A defined in theproof
of Theorem 1.3. Leta e A be such that
w( a )
=w(F).
Let i be the smallestindex j ,
suchthat, according
to(1),
one has:By
thisequality
it follows that i ; t. Hence:By (7)
it follows that forany j
suchthat j -
one has= 0.
Therefore,
we may assume that in the lastequality
only
termswith i - t
=0( mod e )
appear. Since every term in theright
hand side of the last
equality
may be written as:where
kv’ (see [7], Corollary 1.4),
and since ai ~0,
then onehas: .
if u ’ is defined
by r * ,
andif u’ is the valuation at
infinity. (Here
i’ is the smallestindex j
suchthat
w(F)
=The
proof
of3)
and4)
followsby
these two lastequalities
and(2).
3. -
Composite
of r.t. extensions.Now,
we areconsidering
the Theorem 4.3of [8]
in thegeneral
setting.
°Let
(K, v)
be a valued field(K
is notnecessarily algebraically closed)
and let w be an r.t. extension of v toK(X).
Asalways,
we pre-serve the notation and
hypotheses given
in Theorem 1.1. Let z’ be avaluation
on kv
and u ’ an extension of z ’ tokw
=kv’ (r*).
Let z be the valuation on Kcomposite
with the valuations v and z ’ and let u be the valuation onK(X) composite
with the valuations w and u’ . It is easy tosee that u is an extension of z to
K(X). Moreover, according
to([8],
Sec-tion
4.2),
it follows that u is an r.t. extension of z toK(X)
if andonly
if u’is an r.t. extension of z ’ to
l~v - ( r * ).
In this section we shall describe u
by
means ofz’ ,
z,u’ , v
and w. Weshall use also Theorem 4.3 of
[8].
_Let K be an
algebraic
closure of K and let z be an extension of z to K.Let u be a common extension of u and z to
K(X) (see [3],
Section2).
Lets :
G~ 2013~ Gw
be the canonicalhomomorphism
of ordered groups for which su = w. LetGw
=Gw
and let s :G~ - Gw
be theunique
ho-momorphism
of ordered groups whichnaturally
extends s. Let w = s u.It is easy to see that a valuation on
K(X)
which extends w. be the restriction of w to K. It is clear that v is _an extension of v to K and that w is a common extension of v and w toK(X).
Also it is easy to see that(under
the notation in[8])
one has: 3 % 5 and © % zu. Denoteby
~’the valuation induced
by u on kw
and denoteby
z’ the valuation inducedby i
on It is clear that u’ is an r.t. extension of z’ and z’ is an exten- sion of z ’ tokv . Moreover,
il’ is a common extension of u ’ and z’ toki5.
One should note that
kw
= where t is a suitable element ofkw ,
andt is transcendental
over kv ( t
will be definedlater).
Let w = W(a,,5)
(see
Theorem1.1).
Then * is also definedby
the mini-mal
pair ( a, ~ ) (with respect
to valuationv).
One has thefollowing
com-mutative
diagram,
whose rows are exact sequences:In this
diagram
s and s are defined above ande, E
are the natural inclu- sions. SinceGw
=Gv ,
then(see [8],
Theorem3.3)
we may assume thatG~
iscanonically isomorphic
to the directproduct Gw
xGü
orderedlexicografically.
Let
(a’ , 3’ ) e kv
xGz ,
be a minimalpair
withrespect kv’
such thatu’ is defined
by
this minimalpair
and z’ . Denoteby g
the monic mini- malpolynomial
of a’ Because r * is transcendentalover k,,
andkv,
is a finite extension ofkv ,
then we may assume that g ek_, [r * ].
Letus assume
that g #
r * or,equivalently,
a’ # 0. Let G be alifting of g in K[X]
withrespect
to w. Set A =(3, 3’ ) E’Gü.
One has the fundamental result:THEOREM 3.1. There exists a root c
of G
in K such that(c, I) is
a minimalpair
withrespect
to(K, z),
and that u isdefined by (c, À)
andz
(i. e.
one has: u =wee, ».
PROOF. Denote
by
m thedegree
of thepolynomial g
withrespect
tovariable r * .
According
to the definition of alifting polynomial,
one hasin
kw : g
= Now we shall determine theimage
ofG/h m
inkw .
Forthat,
we knowthat g
is transcendental overkv . Then, according
to([3], Proposition 1.1),
there exist the roots cl , ... ,cp
ofG(X)
such that( ci , ð)
is apair
of definition of w and~( a - ci ) ~ ð,
for all 1 ~% I 5 p. Moreover,
for other roots c’ ofG,
which do notbelong
to(ci , ... , cp I
one has:v(a - c’ )
6.Therefore,
inK(X),
we may write:p
G(X)
=fl (X - Ci) G1,
whereG1
EK[X].
It is clear that w(G1 (X)) =
i = 1
=
v (Gl (a)).
Let d e K be such thatv(d)
= 6. We may write:and thus:
where
Therefore,
in the fieldkw ,
one has:Now,
since w is an extension of w toK(X),
there exists the natural inclusionA~==/~(~*)2013~~==~(~).
That inclusion is definedby
thecanonical inclusion
k; ç kv
andby
theassignment:
q
where
(p(t)
is apolynomial
defined as follows: =TI (X - ai)fi,
i=l i
where a, = a, a2, ... ,
aq
are all the rootsof f such
thatv(ai - a) ~ a,
andfi
eK[X].
One has:(X))
=E( fi (a)),
and =v (h(a)).
Wemay write:
Therefore,
one has:On the other
hand,
ifai , ... , am
are all the roots ofg(r *)
inthen, according
to(8)
the lastequality
becomes:Denote
by
a’ .Then, by (9),
there exists a root c ofG(X)
such that
t - ((c - a)/d)*
is a root ofcp(t) - a’ ,
or,equivalently, 99(((c - a)/d)*)
= a’ . This c is the root we looked for Theorem 3.1.We assert that:
i.e. a ’ is the
image
in Hence we must show that this last element has animage
in~
and thisimage
isjust
a’ . In order to dothis,
we notice thatw(X - c)
=3,
orequivalently, v( a - c ) ~ ~ .
There-fore,
for any A EK[X]
withdegA
n, one has: v(A(a))
=w(A(X)) =
= v (A( c )) . Also,
one has:But
v(c - ai) ? inf (3 , 5(a - ai))
=w(X - ai),
and thusv ( f(c))) >
~
w( f(X))
= y. Inconclusion,
ey =w(h)
= v(h(c))
and thus0 i.e. there exists
( f e (c)/h(c))* .
On the other hand we can write:and thus:
In
proving (10)
we must show that the second factor in theright
handside of the last
equality
is 1. This will resultby
thefollowing
statement:
(A). -
LetB(X),E K[XI
and letb1, ... , bt
be the roots of B in K. As-sume
that,
for any 1 ~i ~ t,
one has:v( a - bi )
3 . Thenv( c - bi) 3,
1 ~
i ~ t, v (B(a))
= v(B(c))
and(B(a)/B(c))*
= 1.PROOF oF A . Since
v(a - c) ; 6, then, by hypothesis,
it follows thatv (B(a))
= v(B(c)). Furthermore,
we may write:and so, since
v( ac - c)
>v( c - ai),
1 ~i ~ t,
it follows that:(B(a)/B(c»*
=1,
as claimed.Now we are
proving
that(c, h)
is a minimalpair
withrespect
to(K, z ).
In order to do this let c ’ e K be such thatz( c - c’ ) ~
A. We must show that[ K( c ) : K] % [K( c’ ) : K]. According
to the definitionof Z,
onehas:
v( c - c’ ) * 3
whence( c’ , ð)
is also apair
of definition of w. Hencewe may write:
By
thehypothesis z(c - c’ ) ; ~,,
thefollowing
holds:Now,
since(a’ , d’ )
is a minimalpair
withrespect
to(kv, , z’ ), by (10)
and
(11)
it follows that the minimalpolynomial
ofcp«(c’ - a)/d)*)
overkv"
has thedegree
at least m.Suppose
that[K(c) : K]
>[K(c’ ) : K].
LetG1
be the monic minimalpolynomial
of c’ over K and letbe the
f-expansion
ofGi . By hypothesis,
onehas: q ~ (me - 1 ) n.
LetH E
K[X], degH
n and let 0 ~ t e be such that =w(Hf t).
Leti be the smallest
index j
such thatw( G1 )
=(see ( 1 )). Then, necessarily, i ~ t
and forany j ~ i, w«Aj/H)fj-t)
> 0if j - (mode).
Hencebelongs
to1~2; ( r * )
and itsdegree (with respect
tor * )
is at most m - 1. As above(see (A))
it is easy to see that( f e (c’ )/h(c’ ))* _ cp«(c’ - a)/d))*)
is a root of~1(7’*).
Butthis is a contradiction to
(11)
and to the result which claims that(cp(((c - a)/d))*), 6’)
is a minimalpair (with respect
toz’ )).
Inconclusion
(c, ~. )
is a minimalpair,
as claimed.To finish the
proof
we must show that u is definedby ( c, ~, ).
In orderto do this let
ul
be the r.t. extension of z toK(X)
definedby
thepair ( c, À) (see
Theorem1.1).
Since§(h)
=d,
andv( c - ac) ~
6 it follows that( c, ð)
is apair
of definition ofW,
hence one has: W.According
to([8], Proposition 3.2)
one hasnecessarily
thatu1
= u and so, the restric- tion of~c1
toK(X)
isjust
~c. Hence u is definedby
the minimalpair (c, A),
as claimed.
REFERENCES
[1] V. ALEXANDRU - N. POPESCU, Sur une classe de
prolongements
a K(X)d’une valuation sur un corps K, Revue Roum. Math. Pures.
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characteriza- tionof
residual transcendental extensionsof
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[8] N. POPESCU - C. VRACIU, On the extension
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als over local
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