R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
C ARLO G RECO
Infinitely many spacelike periodic trajectories on a class of Lorentz manifolds
Rendiconti del Seminario Matematico della Università di Padova, tome 91 (1994), p. 251-263
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on a
Class of Lorentz Manifolds.
CARLO
GRECO (*)
ABSTRACT - Let us consider R4
equipped
with a Lorentzian tensor g withsigna-
ture ( + , + , + , - ). In this paper we prove, under suitable
assumptions
on g, the existence ofinfinitely
manyspacelike geodesics
z(s) _(x(s), t(s))
withthe
periodicity
conditions x( s + 1) = x( s ), t( s + 1) = t( s ) + T ( T > 0) on the Lorentz manifold(R4 , g).
1. Introduction.
Let us consider the manifold
(R4 , g),
whereg(z)
=g(x, t)
is a Lorentz tensor onR4 ,
withsignature (+, +, +, -).
Letz(s) =
=
(x(s), t(s))
be ageodesic
on(R4 , g),
and suppose thatt(0)
=0,
and there exist a, T > 0 such thatx(s
+a)
=x(s), t(s
+a)
=t(s)
+ T for every s E R. Then we shall say that z is ao-periodic T-trajectory
on(R4 , g ). Moreover,
if z is ageodesic,
there existsEz
E R such thatI(s)] = Ez ,
and z calledspacelike,
null or timelike ifEz
> 0 or,respectively, Ez
=0, Ez
0(see [14],
p.69).
Suitable Lorentz manifolds are used in
Relativity theory
in order todescribe the
physical space-time. Then,
timelike(or, respectively, null) periodic trajectories corresponds
toperiodics
orbits of aparticle
of po- sitive mass(or, respectively,
of alight ray). Spacelike geodesics
are nottrajectories
ofparticles,
butthey
areimportant
in order tostudy
geo- metricalproperties
of a semiriemannian manifold.Some
multiplicity
results for timelikeperiodic trajectories
on(R4 , g)
aregiven,
forinstance,
in[5]
and[9]
under theassumption
that(*) Indirizzo dell’A.: Universita
degli
Studi di Bari,Dipartimento
di Mate- matica,Campus
Universitario, Via G. Fortunato, 70125 Bari,Italy.
Work
supported by
MURST andby
GNAFA of CNR.the
gravitational
field vanish atinfinity,
sothat g
tends to theMinkowski metric at
infinity (see
Remark 1.3 below for furtherinformations).
In this paper we consider a
completely
different behavior atinfinity
for g, and we are able to prove
that,
for any T >0,
there areinfinitely
many
spacelike 1-periodic T-trajectories
on the semiriemannian mani- fold(R4 , g ).
Let {gij li, j
=1, ..., 4 be thecomponents
of g. We supposethat g
not de-pend
to thetime,
gij = gji EC 1 (R3 , R ),
andgi4=0
for i =1,2,3.
Weset,
for = sothat we
have,
for every x andevery
ER4 :
Moreover we assume that there exist >
0, p
> 2 and q E]0,
p -2[
such that forevery x, ~
ER3 :
Then we have the
following
theorem.THEOREM 1.1.
If (1.1)-(1.6)
aresatisfied, then, for
every T >0,
there exist
infinitely
manyspacelike 1-pe?iodic T-trajectories
on(R4 , g).
REMARK 1.1. If and =
0,
it is easy to check thatz(s) = (xo , Ts)
is a trivialperiodic trajectory.
We shall see later thatthe
trajectories given by
Theorem 1.1 are nottrivial,
and aregeometri-
cally
distinct.REMARK 1.2. Condition
(1.3)
is a sort ofsuperquadraticity
condi-tion at
infinity.
It has been introducedby
P. H. Rabinowitz in the the- ory of Hamiltoniansystems. (1.4) implies
that there exists ci > 0 suchthat,
for every x ER3 ,
withI x I
; R:Condition
(1.3)
means thatsatisfied,
forinstance,
ifMoreover,
because of(1.3),
there exists c2 > 0 such thatfor 1.
Infact,
let with 1. Sincewe have
REMARK 1.3. The
problem
ofgeodesics
for a Lorentz manifold(M, g)
has beenrecently
studiedby
many authors(see [2]-[5], [7]-[12]).
If
particular,
in the papers[5], [9],
aregiven multiplicity
results fortimelike
periodic trajectories
on(I~4 , g )
under theassumption f3(x)
bounded.
The main difficult in the variational
approach
of this kind ofprob-
lems is that the action functional
is
strongly indefinite,
i.e. it is not of the formidentity
+compact,
even«modulo
compact perturbations».
In ordert to avoid thisdifficult,
weuse the
convexity
of the functional withrespecto to i
and search for the criticalpoints
of a functionalf depending only
on x.If is bounded as in
[9] (or
it issubquadratic),
the functionalf
isbounded from
below,
and satisfieseasily
the Palais-Smalecompactness
condition. In our case
f
isunbounded,
so we need somelinking
argu-ment ;
moreover more care isrequired
in order to provecompactness
conditions.
In Section 2 we expose the functional framework and we prove the
compactness
conditionusing assumptions (1.1)-(1.5).
Then we prove Theorem 1.1 with a mountain passargument by using (1.6).
2. Proof of the results.
In the
following
we assume that(1.1)-(1.5)
hold. Let as consider ageodesic z(s) _ (x(s), t(s))
on(R4 , g);
then z satisfies thegeodesic equations:
If z is a
a-periodic T-trajectory,
we shall call the minimalperiod
of x, the minimalperiod
of z. Noticethat,
if zl =(xl , tl )
and z2 =(X2, t2)
areJ-periodic T-trajectories
on(I~4 , g),
with z, ;6 z2 , then zl and z2 are geo-metrically
distinct.In
fact,
if z2(s)
= zl(P(S))
for somereparametrization ~(s),
fromgeodesic equations
we havep(s)
= as + b for some a, b E R(see [14],
p.69),
so thatt2 (s)
=tl (as
+b).
Sinceil (s) -
0 for any s ER,
fromtl (0) =
= 0 =
t2 (0)
= we have b =0,
and fromaa)
=t2 ( s
+o~)
==
t2 (s)
+ + we have and a =1,
which is im-possible.
In
particular,
if zl and z2 have not the same minimalperiod,
then itsare
geometrically
distinct.REMARK 2.1. We observe now
that,
ifz(s) _ (x(s), t(s))
is ak -1- periodic
Tk-1-trajectory,
x andi
are also1-periodic
andt( s
+1 )
==
t(s)
+ T .Infact,
it is easy to chek thatt( s
+1)
=t(s
+( k - h )/h)
++
Th/k
for every h =1, ..., k;
then z is a1-periodic T-trajectory
on(R4 , g),
with minimalperiod
less orequal
to1 /k. So,
in order to proveTheorem
1.1,
we can show that there existsko
E N suchthat,
for every k E N with k >ko ,
there exists ak-1-periodic Tk-1-trajectory z(s) =
- (x(s), t(s)),
0.Let k E N be free for the
moment,
and let us consider the functionaldefined on where is
the Sobolev space of
k-’-periodic
functions x:R -~ R3
withx, x E L 2 ([ 0, 1 /1~]),
andIt is easy to check
that,
if(x, r¡)
is a criticalpoint
ofI,
thens
z(s)
=(x(s), t(s)),
wheret(s)
=Ts/Ak +f n ds
is a criticalpoint
of the ac-tion functional 0
so, it is a
1-periodic T-trajectory
on(R4 , g),
with minimalperiod
less orequal
to1 /k (see
Remark2.1).
Notice
that,
because of(1.4),
forevery x E H
---H 1 ~ 2 (SIlk, R3 ),
the1/k
functional is
strictly
convex, so it possess ao
unique
minimumpoint n x
ER). Let f :
H -~ R be the functionalLEMMA 2.2. The
function
is continuousfrom
H toLo R );
moreoverR)
acndso
that,
x E H is a criticalpoint of f if
andonly if ( x,
is a criticalpoint of
I.PROOF. The
proof
is contained in[9].
We recall it for the reader con- 1/kvenience. First of all we observe that
cause is a critical
point
of the functional i, and then
Now,
let x, y E H.Clearly
Moreover,
sinceusing (2.1)
weget I(x,
as y - r, sof
is continuous.We prove now that is continuous.
Infact, arguing by
contra-diction,
we suppose that there exist x EH, (xn)
c H and s > 0 such that1 I,-
is
strictly
convex, we haveSince
(,u n)
is boundedand rn
~ x, weget I(x, ~u n) - I(xn ,
-~0,
and and then we have a contradiction.Finally,
fix x, y EH,
and let 7 > 0. From(2.2)
we haveso the lemma is
REMARK 2.3. Notice that for every
In other
words,
there existscx E R
such thatf3(x(s))(T /k
+ 77 x(s))
= cx for every s E R. Since 0implies T/k
+where M =
x ~ I
~p ~,
andI I
is theLebesgue
measureof
I.PROOF. Let cx be as in Remark
2.3,
so that +’1)x(s)
=for every s E R. If
s E I,
we have and thenIntegrating
onI,
we have:Then
cz £
, so that the lemma isproved. 0
LEMMA 2.5. Let 0 r p acnd
(xn)
c H be such that0) ~
p. Thenwhere M = max
because of Lemma 2.4.
Moreover,
since0) ~
r, we have p -r ~ In ~ 1~2 ,
and the lemma follows.In
We say that a functional
f:
H -~ R verifies the Palais-Smale-Cerami(PSC)
condition(see [6])
if every sequence(xn)
c H such that -~ c E R and
( f ’ (xn),
~ 0 possesses aconvergent
subse-quence.
We have the
following
lemma.LEMMA 2.6. There exists
ko
E N suchthat, for every k a ko,
thefunctionals f satisfies
the PSC-condition.PROOF. Let
(R
is defined in(1.3)),
and let
l~o
E N be such that a o -T2 M/k6
> 0. Fix k E N ivith k ako ,
andlet us consider a sequence
(xn)
c H such that c E R and( f ’ (xn), xn~ -~
0 as n ~ ~ . First ofall,
we prove that~~2)
is boundedmodulo
subsequences. Infact,
wedistinguish
two cases:1) case:
for everyn E N, (modulo
subse-quences).
Then(Xn (s)) ~ xn (s))
for every s(see (1.3)),
so,from - c we
get (setting
77n *Since
( f ’ (xn), xn) --~ 0,
we haveso that
then
(~~xn~~2)
is bounded because of(1.2).
2)
case: for everyn E N, dist (Im (xn), 0)
R(modulo
subse-quences). Then,
if isbounded,
we havef3(xn (s)) ~ MI
for nE N,
1/k
s E
R, so M1 T2 fk3,
and the claim follows fromo
the fact as n - oo.
So,
we canassume IIxnIIoo
- 00. LetIn = {s E [ o,
+1 ~;
from Lemma 2.5(with r = R and p = R + 1 ),
we haveThen,
since - c,so that
(see (1.1)):
claim follows.
We set now
shall prove that is bounded. In
fact,
we can assume that yin - yweakly
inHI,2
andstrongly
inL °° ;
thenfor n
large enough,
sothat,
sinceso is bounded. Let us suppose xn - x
weakly
inH1~ 2
andstrongly
L °° . Then
because of
(2.1)
we have that isbounded,
so, the fact thatstrongly
inH,
and the lemma isproved.
Let H =
R3) = R3
XY,
whereAs well-known
(see
e.g.[13],
p.9),
for every y e Y we have11?i112
aand where a =
2kn( 1
+4k2 n2)-1/2,
and b =(1~12k)1 2.
We have now the
following
lemma.LEMMA 2.7. There exist a, p > 0 such that
f(y) >
afor
every y e Y withIIyll
= P. Moreover a isindependent of
k.PROOF. Fix c > 0 such that ao -
ET2/V12
> 0.(1.5) implies
thatthere exists p 1 > 0 such that + for
lxl I
~ p 1. Set p =p 1 /b
and
so
Since
a 2 ( a o - ~T2 b 2 /1~ 3 ) p i /b 2 > ~
for every the lemma isproved.
REMARK 2.8. Lemma 2.5
implies
that the functionalunder
assumption (1.3)
is notsuperquadratic
atinfinity
on finite-dimen- sionalsubspaces
of H. This fact make notpossible
toapply
the standardlinking
theoremof f.
In order to avoid thisdifficult,
we consider the sub- space E= ~ x
EH I x(s
+1 /2k) _ - x(s)~. Clearly
E cY;
moreover wehave the
following
lemma.LEMMA 2.9. Let us suppose that
(1.6)
holds.Then,
every criticalpoint
x E Eof
thefunctional
is a criticalpoint of f.
PROOF. Let x E E be a critical
point
and z EH;
we shall provethat ~ f ’ (x), z)
= 0. Infact,
set z1(s)
=z(s) - z(s
+1/2k),
andZ2(S) =
=
z(s) - z1(s),
so thatZIEE,
and Z=ZI+Z2.Since (f’(x),zl)=O,
we have( f ’ ( x ), z)
=( f ’ ( x ), z2 ~.
From Remark2.3,
there exists cx > 0 such that + 77 x(s))
= cx .Since f3
is even and x EE,
we have that Y)x(s
++
1/2k)
=77 x (s),
and then it is easy tocheck, by using (1.6),
that~ f ’ ( x ), Z2) = -(f’ ( x ), z),
and the lemma isproved. 0
PROOF OF THEOREM 1.1. Let us suppose that
(1.1)-(1.6) hold,
letko
E N be as in Lemma2.6, ~
> 0 as in Lemma2.7,
and such that k ako
> 0. From Lemma2.6,
the functional satis- fies the PSC condition on E. Letsin (2kns), 0);
cleary w
EE,
and since arP +b,
we haveso that
(see
Remark1.2)
+PoT 2Ik’, and f (w)
0for r large enough (we
recallthat q
+ 2p).
SetLet p be as in Lemma
2.7; since f (0)
= 0 and we can assumellwll
> P, we have ~ ~ c + oo . From the mountain pass lemma(see [1]),
we havethat c is a critical value for the
functionalfiE.
From Lemma 2.9 weget
acritical
point X
e Hof f with f(x)
= c. Since c >0,
we have 0. Because of Remark2.1, z(s) = (x(s), t(s)),
wheret(s)
periodic T-trajectory
on(R4 , g).
Finally,
in order to prove that z isspacelike,
we observe thatso that
Ez
>0,
and Theorem 1.1 isproved.0
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Manoscritto pervenuto in redazione il 27 novembre 1992.