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HAL Id: hal-02119677

https://hal.archives-ouvertes.fr/hal-02119677v2

Preprint submitted on 2 Sep 2020 (v2), last revised 18 Aug 2021 (v3)

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Big Birkhoff sums in d-decaying Gauss like iterated function systems

Lingmin Liao, Michal Rams

To cite this version:

Lingmin Liao, Michal Rams. Big Birkhoff sums in d-decaying Gauss like iterated function systems.

2020. �hal-02119677v2�

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ITERATED FUNCTION SYSTEMS

LINGMIN LIAO AND MICHA L RAMS

Abstract. The increasing rate of the Birkhoff sums in the infinite it- erated function systems with polynomial decay of the derivative (for example the Gauss map) is studied. For different unbounded potential functions, the Hausdorff dimensions of the sets of points whose Birkhoff sums share the same increasing rate are obtained.

1. Introduction

Denote by N = {1,2, . . .} the set of positive integers. Consider the so- called Gauss infinite iterated function system {Tn}n∈N on the unit interval [0,1] defined by

Tn(x) := 1

x+n forx∈[0,1].

It is well-known that the limit set of the Gauss iterated function system is the set of all irrational numbers in the unit interval [0,1]. In fact, for any x ∈[0,1]\Q, there exists a unique infinite sequence (a1, a2, . . .) ∈NN satisfying

x= lim

n→∞Ta1 ◦ · · · ◦Tan(1) = 1

a1+ 1

a2+ 1 a3+. ..

.

The latter is the regular continued fraction expansion of x. The digits aj = aj(x) are called the partial quotients ofxin its continued fraction expansion.

For any n ≥ 1, denote Sn(x) = Pn

j=1aj(x). In the literature, we are interested in the sum Sn(x) of partial quotients which is a special Birkhoff sum with respect to the Gauss iterated function system{Tn}n≥1. In fact, the functions Tn are inverse branches of the Gauss transformation T : [0,1]→ [0,1] defined by

T(0) := 0, and T(x) := 1

x (mod 1), forx∈(0,1].

Thena1(x) =⌊x−1⌋(⌊·⌋stands for the integer part) andaj(x) =a1(Tj−1(x)) forj ≥2. Thus

Sn(x) = Xn j=1

aj(x) = Xn j=1

a1(Tj−1x),

2010 Mathematics Subject Classification: Primary 11K50 Secondary 37E05, 28A80 1

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is a Birkhoff sum of the potential function x 7→ a1(x) with respect to the Gauss transformation.

In 1935, Khintchine [7] showed thatSn(x)/(nlogn) converges in measure (Lebesgue measure) to the constant 1/log 2. In 1988, Philipp [12] proved that there is no normalizing sequence Φ(n) such thatSn(x)/Φ(n) converges to a positive constant Lebesgue almost surely. Motivated by such a phe- nomenon, people then turn to study the sums Sn(x) from the point of view of multifractal analysis. Precisely, one is concerned with the Hausdorff di- mension of the sets

E(Φ) =

x∈(0,1) : lim

n→∞

Sn(x) Φ(n) = 1

,

where Φ : N → R+ is an increasing function. When Φ(n)/n has a finite limit as n→ ∞,E(Φ) is the classical level set of Birkhoff averages, and its Hausdorff dimension has been determined by Iommi and Jordan [4]. The particular attention is thus paid to the cases when the sumsSn(x) are bigger, that is, when

n→∞lim Φ(n)

n =∞,

In this direction, if Φ(n) = na with a ∈ (1,∞) or Φ(n) = exp(nα) with α ∈(0,1/2), Wu and Xu [14] proved that dimHE(Φ) = 1. Here and in the follows, dimH stands for the Hausdorff dimension. Later, Xu [15] proved that if Φ(n) = exp(nα) with α ∈ [1,∞) then dimHE(Φ) = 1/2; and if Φ(n) = exp(βn) withβ >1 then dimHE(Φ) = 1/(β+ 1). The gap for the case Φ(n) = exp(nα) withα∈[1/2,1) was finally filled by the authors in [9]

where we proved that dimHE(Φ) = 1/2 for all α∈[1/2,1). Hence there is a jump of Hausdorff dimension from 1 to 1/2 for the class Φ(n) = exp(nα) at α = 1/2.

The present paper aims at generalizing the above results on the Birkhoff sums of the potential x 7→ a1(x) in Gauss infinite iterated function system associated to continued fractions to Birkhoff sums of a general potential function in some general infinite function systems. We are especially inter- ested in big Birkhoff sums. Before stating our main results, let us give some notations and definitions.

Definition 1.1. Letd >1 be a real number. A family{fn}n∈NofC1 maps from the interval [0,1] to itself is called a d-decaying Gauss like iterated function system if the following properties are satisfied:

(1) for anyi, j∈N, fi((0,1))∩fj((0,1)) =∅;

(2) S

i=1fi([0,1]) = [0,1);

(3) iffi(x)< fj(x) for all x∈(0,1) theni < j;

(4) there existsm∈Nand 0< A <1 such that for all (a1, ..., am)∈Nm and for all x∈[0,1]

0<|(fa1◦ · · · ◦fam)(x)| ≤A <1;

(5) for anyδ >0, we can find two constantsK1 =K1(δ), K2 =K2(δ)>

0 such that for i∈Nthere exist constants ξi, λi such that

∀x∈[0,1], K1

id+δ ≤ξi ≤ |fi(x)| ≤λi ≤ K2

id−δ.

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We have a natural projection Π :NN→[0,1] defined by Π(a) = lim

n→∞fa1◦ · · · ◦fan(1).

Its inverse gives for points x∈ [0,1] their symbolic expansions in NN. The symbolic expansion is unique for most points, but there can exist countably many points that have zero or two symbolic expansions. When the symbolic expansion is unique, we write x = (a1(x), a2(x), . . .) the expansion of x ∈ [0,1].

For each n∈N, and each word a1· · ·an∈Nn, the set In(a1,· · · , an) =fa1 ◦ · · · ◦fan([0,1])

is called a basic interval of order n or an n-basic interval. Except for a countable set, then-basic intervalIn(a1,· · · , an) is identical with the set of points x ∈ [0,1] whose symbolic expansions begin with a1,· · ·, an. Write In(x) then-basic interval containingx∈[0,1].

Denote by|I|the diameter of an intervalI. We say thed-decaying Gauss like iterated function system {fn}n∈N satisfies the bounded distortion prop- ertyif there exist positive constants K3 andK4 such that for any two finite wordsa1a2· · ·an and b1b2· · ·bm, we have

K3 ≤ |In+m(a1,· · ·, an, b1,· · · , bm)|

|In(a1,· · · , an)| · |Im(b1,· · ·, bm)| ≤K4. (1.1)

Consider a potential function ϕ : [0,1] → R+, such that ϕ is a constant on the interior of I1(a1) for alla1∈N. For n∈N, the n-th Birkhoff sum of ϕ at x∈(0,1) is defined by

Snϕ(x) = Xn j=1

ϕ(aj), if x∈In(a1,· · · , an).

We remark that except for a countable set, the above Birkhoff sums are well defined.

For a positive growth rate functionΦ :N→ R+, we are interested in the following set

Eϕ(Φ) :=

x∈(0,1) : lim

n→∞

Snϕ(x) Φ(n) = 1

. (1.2)

We will calculate dimHEϕ(Φ). As in the Gauss iterated function system, when Φ(n)/nhas a finite limit asn→ ∞, the setEϕ(Φ) is the classical level set of Birkhoff averages and its Hausdorff dimension has been well studied in [13, 6, 3, 4, 2, 8], and many other papers. In this paper we will consider the case when Φ(n)/n → ∞, thus necessarily the potential function ϕ is unbounded in [0,1].

For all j ∈ N, denote by ϕ(j) the constant value of ϕ on the interior of 1-basic interval I1(j). We obtain the following multifractal analysis results on the Hausdorff dimension of Eϕ(Φ), according to different choices of ϕ and Φ. We will see that as in the case of Gauss iterated function system, the jump of Hausdorff dimension also happens but at different places.

Theorem 1.2. Suppose ϕ(j) =ja for all j≥1, witha >0.

(I) When Φ(n) =enα with α >0, we have

(I-1) dimHEϕ(Φ) = 1 if α < 12 and the distortion property (1.1) holds;

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β = 1+

0 α= 12

1 d

1 dimHEϕ(Φ)

1 dβ−β+1

exponentialenα super-exponentialeβn Figure 1. dimHEϕ(Φ) for ϕ(j) =ja.

(I-2) dimHEϕ(Φ) = 1/d if α > 12.

(II) When Φ(n) =eβn with β >1, we have dimHEϕ(Φ) = dβ−β+11 . Theorem 1.3. Suppose ϕ(j) =e(logj)b for allj≥1, withb >1.

(I) When Φ(n) =enα with α >0, we have

(I-1) dimHEϕ(Φ) = 1 if α < b+1b and the distortion property (1.1) holds;

(I-2) dimHEϕ(Φ) = 1/d if α > b+1b .

(II) When Φ(n) =eβn with β >1, we have dimHEϕ(Φ) = 1

1b−β1b+1. Theorem 1.4. Suppose ϕ=ejc for allj≥1, with0< c <1.

(I) When Φ(n) =enα with α >0, we have

(I-1) dimHEϕ(Φ) = 1 if α <1 and the distortion property (1.1) holds;

(I-2) dimHEϕ(Φ) = 1−cd if α >1.

(II) When Φ(n) =eβn with β >1, we have dimHEϕ(Φ) = 1−cd .

(III) When Φ(n) =eeγn with γ >1, we have dimHEϕ(Φ) = dγ−(1−c)(γ−1)1−c . Theorem 1.5. Suppose ϕ(j) =ejc for all j ≥1, with c≥1. When Φ(n) = enα, with α >0, we have

(I-1) dimHEϕ(Φ) = 1 if α <1 and the distortion property (1.1) holds;

(I-2) dimHEϕ(Φ) = 0 if α≥1.

The Hausdorff dimensions in Theorems 1.2-1.5 are depicted in Figures 1-4.

Remark 1. The critical cases α= 12 in Theorems 1.2, α= b+1b in Theorem 1.3, and α = 1 in Theorems 1.4 and 1.5 are not investigated in this paper.

However, Theorem 1.2 in [9] suggests that the Hausdorff dimension function has jumps at these points.

Remark 2. Theorem 1.2 was announced in [9, Theorem 4.1.], but with an erroneous formula in the part (iii) (now part II).

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β = 1+

0 α= b+1b

1 d

1 dimHEϕ(Φ)

1 1b−β1b+1

exponential enα super-exponentialeβn Figure 2. dimHEϕ(Φ) for ϕ(j) =e(logj)b.

β= 1+

0 α=12 γ= 1+

1−c d

1 dimHEϕ(Φ)

1−c dγ−(1−c)(γ−1)

exponential enα super-exp eβn sup-sup-expeeγn Figure 3. dimHEϕ(Φ) for ϕ=ejc with 0< c <1.

Remark 3. For simplicity, in our proofs, we assume δ = 0 in the condition (5) of Definition 1.1 of the d-decaying Gauss like iterated function system.

For the general case, the proofs are the same. We need only to replace dby d+δ for the lower bound and by d−δ for the upper bound, then take the limit δ→0.

To prove our main theorems, we give four technical lemmas in Section 2. Lemma 2.1 is useful to prove full Hausdorff dimension results. Lemma 2.2 is mainly devoted to proving a lower bound of Hausdorff dimension (sometimes, we can also use it for upper bound). Lemmas 2.3 and 2.4 are two combinatorial lemmas serving for the upper bounds of Hausdorff dimension.

We believe that our lemmas have independent interests for the future study on multifractal anlysis and Diophantine approximation in infinite iterated

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α= 1 0

1

dimHEϕ(Φ)

exponential enα

Figure 4. dimHEϕ(Φ) for ϕ=ejc with c≥1.

function systems or interval maps with infinitely many branches which are often associated to some expansions of numbers. We also stress that though some preliminary versions of our lemmas have already appeared in [14], [15], [3] and [9], some more efforts are needed to make them applicable for more general settings. Our lemmas are non-trivial generalizations of the corresponding results in [14], [15], [3] and [9].

The rest of the paper is organized as follows. In Section 3, we give the proofs for (I-1) of Theorems 1.2-1.5 and (I-2) of Theorem 1.5. The remaining proofs are given in the last section.

2. Technical lemmas

In this section, we prove four technical lemmas. The first lemma serves for the proof of full dimension in the theorems, i.e., the proofs for (I-1) of Theorems 1.2-1.5.

Recalling Remark 3, we remind that we assume δ = 0 in the condition (5) of Definition 1.1 through all of our proofs.

Let (nk)k≥1 be a positive sequence satisfyingnk/k→ ∞andnk+1/nk→1 as k→ ∞. Let uk be a positive sequence such that

(2.1) lim

k→∞

1 nk

Xk j=1

loguj = 0.

For each M ∈N, set

EM :={x∈(0,1) :ank(x) =uk, and 1≤aj(x)≤M if j6=nk}.

Then we have the following lemma whose idea comes from the proof of Theorem 1.4 of [14].

Lemma 2.1. Suppose the d-decaying Gauss like iterated function system {fn}n∈N satisfies the distortion property (1.1). Then we have

Mlim→∞dimHEM = 1.

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Proof. For anyk≥1, let Ink(a1· · ·ank) be annk-basic interval intersecting EM. By the condition (5) of Definition 1.1 and the distorsion property (1.1), we have

|Ink| ≥K32k−1K1k Yk j=1

|Inj−nj−1−1(anj−1+1,· · · , anj−1)| ·a−dnj, where by convention n0 = 0.

Let s(M) be the Hausdorff dimension of the set of points x such that all aj(x) ≤ M. Then s(M) is increasing to 1, see for example, [11, Theorem 3.15]. Further, there exists a probability measure ν living on [0,1] and a positive constant CM such that for any basic intervalIn(a1, . . . , an) we have

ν(In(a1, . . . , an))≤CM|In(a1, . . . , an)|2s(M)−1.

Define a probability measureµon each basic intervalInk intersectingEM by

µ(Ink) = Yk j=1

ν(Inj−nj

1−1(anj

1+1,· · · , anj−1)).

By Kolmogorov Consistence Theorem, µis well defined and is supported on EM.

Then for each x∈EM, we have

|Ink(x)|2s(M)−1 ≥(K32k−1K1k)2s(M)−1CM−kµ(Ink(x))

 Yk j=1

a−dnj

s(M)−1

. (2.2)

Observe that (2.1) implies that Pk

j=1loganj ≪ nk, while the part (4) of of Definition 1.1 implies that

(2.3) log|Ink(x)| ≤ logA m nk.

Thus, using (2.2) and (2.3), by simple calculations, we have (2.4) logµ(Ink(x))

log|Ink(x)| ≥2s(M)−1−o(1) for large k.

This allows us to estimate the local dimension lim infr→0 logµ(Br(x)) logr of the measure µ at x. Here and the follows, Br(x) denotes the ball of radius r centered at x. Let us first observe the following two facts.

Fact 1. Forr =|Ink(x)|,

Br(x)∩EM ⊂Ink(x).

Indeed, the pair (Ink(x), Ink−1(x)) is an image of the pair (I1(ank),[0,1]) under the map fa1 ◦. . .◦fank−1. By the condition (5) of Definition 1.1, the basic interval I1(ank) has length ≈a−dnk and lies in distance ≈ a−d+1nk from the endpoints {0,1}. Further, the map we apply has bounded distortion, hence it roughly preserves the proportions. Thus, Ink(x) is also short and far away from the endpoints of Ink−1(x). By the definition of EM, inside

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Ink−1(x) there is only one nk-basic interval (which is Ink(x)) intersecting EM. Thus we obtain the assertion of the fact.

Fact 2. When k→ ∞,

log|Ink+1(x)|

log|Ink(x)| →1.

Indeed, by the condition (5) of Definition 1.1,

|Ink+1(x)|

|Ink(x)| ≥K1nk+1−nk·(K1M−d)nk+1−nk·K1·a−dnk+1. (2.5)

By the hypothesis nk+1/nk → 1, we have (nk+1−nk)/nk → 0. Then the statement follows from the formulae (2.3) and (2.5).

The first fact implies that when r=|Ink(x)|we can use (2.4) in the local dimension calculation. The second fact implies that we do not need to check anyr not of the formr =|Ink(x)|. Thus, by the Mass Distribution Principle (see [1, Principle 4.2]), we have

dimHEM ≥2s(M)−1.

Passing with M to infinity, we complete the proof of the lemma.

The second lemma is an improved version of [3, Lemma 3.2], [5, Proof of Theorem 1.3], [9, Lemma 2.2] and [10, Lemma 2.2]. We often apply it for the lower bounds of Hausdorff dimension. However, we will see that it is also useful for upper bounds.

Let{sn}n≥1,{tn}n≥1be two positive real sequences. Assume thatsn> tn, sn, tn→ ∞as n→ ∞, and

lim inf

n→∞

sn−tn sn >0.

(2.6)

For N ∈N, let

B({sn},{tn}, N) :=

x∈(0,1) :sn−tn≤an(x)≤sn+tn, ∀n≥N . We remark that whennis large, by the assumption tn→ ∞, we can always have integers choices foranin the interval [sn−tn, sn+tn]. However, for the first terms, there might be no positive integer in the interval [sn−tn, sn+tn], and hence the set B({sn},{tn}, N) is empty. There is no interest to study such an empty set. Without loss of generality, by modifying the values of finitely many first terms, we always assume that our sequences {sn},{tn}) are such that B({sn},{tn}, N) is nonempty. Further, we will see from our formule of the Hausdorff dimension ofB({sn},{tn}, N) that the modification of the first finite number of terms of the sequences will not change the Hausdorff dimension.

Lemma 2.2. We have

dimHB({sn},{tn}, N) = lim inf

ℓ→∞

P

i=1logti dPℓ+1

i=1logsi−logtℓ+1.

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Proof. Within this proof, we writef(n)∼g(n) iff(n) andg(n) differ by at most an exponential factor, that is

lim sup

n→∞

1 n

logf(n) g(n) <∞.

We give the proof for the case N = 1. For the general case, note that B({sn},{tn}, N) = [

a1···aN−1∈NN−1

fa1◦· · ·◦faN−1(B({sn+N−1},{tn+N−1},1)) is a countable union of bi-Lipschitz images of B({sn+N−1},{tn+N−1},1).

Since the bi-Lipschitz maps preserve the Hausdorff dimension, we have dimHB({sn},{tn}, N) = dimHB({sn+N−1},{tn+N−1},1).

On the other hand, notice that the dimensional formula of the lemma we will obtain does not depend on the finite number of first terms of the two sequences {sn} and{tn}, we then have

dimHB({sn},{tn}, N) = dimHB({sn},{tn},1).

Fix ℓ≥1. LetI(a1, . . . , a) be anℓ-basic interval with nonempty inter- section withB({sn},{tn},1). Then for each 1≤k≤ℓ,ak ∈[sk−tk, sk+tk].

Define

D(a1, . . . , a) :=

x∈I(a1, . . . , a) :aℓ+1(x)∈[sℓ+1−tℓ+1, sℓ+1+tℓ+1] . We have

B({sn},{tn},1) =

\ ℓ=1

[

a1,...,a

ai∈[si−ti,si+ti]

I(a1, . . . , a)

=

\ ℓ=1

[

a1,...,a

ai∈[si−ti,si+ti]

D(a1, . . . , a).

At level ℓ, we have ∼ Q

i=1ti intervals I(a1, . . . , a) and thus ∼ Q i=1ti corresponding D(a1, . . . , a). By the condition (5) of Definition 1.1, and the assumption (2.6), each I(a1, . . . , a) is of size ∼Q

i=1s−di . Moreover,

|D(a1, . . . , a)|

|I(a1, . . . , a)| ∼

sℓ+1+tℓ+1

X

i=sℓ+1−tℓ+1

i−d∼tℓ+1s−dℓ+1.

Thus, using for a givenℓthe setsD(a1, . . . , a) as a cover forB({sn},{tn},1), we need ∼Q

i=1ti of them, each of size∼tℓ+1Qℓ+1

i=1s−di . Therefore, by reg- ular calculation, we can obtain the upper bound

dimHB({sn},{tn},1)≤lim inf

ℓ→∞

P

i=1logti dPℓ+1

i=1logsi−logtℓ+1.

To get the lower bound, we consider a probability measure µ uniformly distributed onB({sn},{tn},1), in the following sense: givena1, . . . , aℓ−1, the probability of a taking any particular value between s−t and s+t is the same. The basic intervalsI(a1, . . . , a) and correspondingD(a1, . . . , a) have the measure ∼Q

i=1t−1i .

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Our goal is to apply the Mass Distribution Principle, hence we need to calculate the local dimension of the measure µ at a µ-typical point x ∈ B({sn},{tn},1). Fix anyx∈B({sn},{tn},1). Denote byrthe diameter of the set D(a1(x), . . . , a(x)) and by r the diameter of I(a1(x), . . . , a(x)).

When r =r, we have logµ(Br(x))

logr = logµ(Br(x))

logr = logµ(D(a1(x), . . . , a(x)))

logr .

Since µ(D(a1, . . . , a))∼Q

i=1t−1i and r∼tℓ+1Qℓ+1

i=1s−di , we have lim inf

ℓ→∞

logµ(Br(x))

logr = lim inf

ℓ→∞

P

i=1logti dPℓ+1

i=1logsi−logtℓ+1. (2.7)

For r < r < r, the ball Br(x) still does not intersect any point from B({sn},{tn},1)\ D(a1(x), . . . , a(x)), hence it has the same measure as Br(x), but a larger diameter. Thus, for r< r < r,

logµ(Br(x))

logr < logµ(Br(x)) logr .

Finally, since each basic interval Iℓ+1(a1(x), . . . , a(x), j) contained in D(a1(x), . . . , a(x)) has the same measure and approximately the same di- ameter, we have for rℓ+1< r < r,

µ(Br(x))≤2· r

rℓ+1 ·µ(Br(x))

2tℓ+1 ≤2·4d· r

rµ(Br(x)).

Applying the obvious fact that logz1z2 logz1z3

> logz2 logz3

for all z1<1 andz3 < z2 <1, we see that for rℓ+1 < r < r, logµ(Br(x))

logr < log(µ(Br(x))·r/r)

logr ≤ logµ(Br(x))−log(2·4d)

logr .

Thus, the minimum of the functionr →logµ(Br(x))/logrforrℓ+1< r < r is equal to its value at r, up to an error term that vanishes as ℓ → ∞.

Therefore,

lim inf

r→0

logµ(Br(x))

logr = lim inf

ℓ→∞

logµ(Br(x)) logr .

Applying the Mass Distribution Principle, by (2.7), we obtain the lower bound for dimHB({sn},{tn},1). The proof is thus completed.

The remaining two lemmas are generalizations of Lemma 2.1 of [9]. They are the key to prove the upper bounds of Hausdorff dimension. In the proofs, the Riemann zeta function ζ(·) will be often used.

For m, n∈N,a >0 andε >0, let A(m, n, a, ε) :=

(

(i1, . . . , in)∈Nn: Xn k=1

iak∈[m, m(1 +ε)]

) .

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For s >1/d, write

G(m, n, a, ε, s) = X

i1···in∈A(m,n,a,ε)

Yn k=1

i−dsk .

Lemma 2.3. There exist positive constants C1=C1(a, s), C2 =C2(s), and C3 =C3(a), such that for all C3·(m32−n)−1/a < ε≤1/3, we have

G(m, n, a, ε, s)≤C1C2n−1εm1−dsa .

Proof. The proof goes by induction. First consider the case n = 2. Note that if ia1 +ia2 ∈ [m, m(1 +ε)] then at most one of ia1, ia2 is strictly larger than m(1+ε)2 . We divide the sum in the definition ofG(m, n, a, ε, s) into two parts, one is ia1 > m(1+ε)2 , the other is ia1m(1+ε)2 . However, by permuting i1 and i2, the latter is not smaller than the former. Thus,

G(m,2, a, ε, s)≤2

(m(1+ε)2 )a1

X

k=1

k−ds(m−ka)dsa ·Nm,a,ε(k), with Nm,a,ε(k) :=♯{i2:m−ka≤ia2 ≤m(1 +ε)−ka}.

Assuming ε≤1/3, we can estimate for a≥1

Nm,a,ε(k)≤ ⌈a−1εm(m−ka)a1−1⌉ ≤ ⌈εm1/a·a−131−1/a⌉, while for a <1

Nm,a,ε(k)≤ ⌈a−1εm(m(1 +ε)−ka)1a−1⌉ ≤ ⌈εm1/a·a−1(4/3)1/a−1⌉.

That is, in both cases we will get an upper estimation in the form

⌈εm1/a·C4(a)⌉.

If z >1, we can write⌈z⌉ ≤2z. Thus, for ε >1/(m1/a·C4(a)) we have Nm,a,ε(k)≤2εm1/a·C4(a).

Hence

G(m,2, a, ε, s)

≤2

(m(1+ε)2 )1a

X

k=1

k−ds(m

3)dsa ·2εm1a ·C4(a)

≤4·ζ(ds)·3dsa ·C4(a)·εm1−dsa . (2.8)

Let

C1= 2·3dsaC4(a), C2= 6·3dsa1 ·ζ(ds).

Then by (2.8), we have

G(m,2, a, ε, s)≤C1C2εm1ads.

Assume now that the assertion is satisfied for all n < N for someN >2, we will prove by induction that it holds for n=N as well.

As above, there is at most one ik such that iak > m(1+ε)2 . Thus the sum of G(m, N, a, ε, s) can be divided into two parts, one is ia1m(1+ε)2 and the

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other is ia1 > m(1+ε)2 . Again, the latter is smaller than the former because we can permute i1 and i2. Thus

G(m, N, a, ε, s)≤2

(m(1+ε)2 )1a

X

k=1

k−ds X

i2···inA(m,n,k,a,ε)e

Yn k=2

i−dsk ,

where

A(m, n, k, a, ε) :=e (

(i2, . . . , in)∈Nn: Xn k=2

iak ∈[m−ka, m(1 +ε)−ka] )

.

Further, observe that 3(m−ka)ε≥mε. Then the sum range [m−ka, m(1 +ε)−ka]

in A(m, n, k, a, ε) is covered by the union ofe

[m−ka, (m−ka)(1 +ε)], [(m−ka)(1 +ε), (m−ka)(1 +ε)2], and

[(m−ka)(1 +ε)2, (m−ka)(1 +ε)3].

Hence,

G(m, N, a, ε, s)≤2

(m(1+ε)2 )1a

X

k=1

k−ds X2 j=0

G (m−ka)(1 +ε)j, N −1, a, ε, s .

Note that

(m−ka)(1 +ε)j ≥ m

3, forj= 0,1,2.

(2.9)

Substituting the induction assumption, we get G(m, N, a, ε, s)≤6·C1C2N−2ε(m

3 )1−dsa

(m(1+ε)2 )1a

X

k=1

k−ds

≤6·3ds−1a C1C2N−2εm1−dsa ζ(ds)

=C1C2N−1εm1−dsa ,

where the last equality comes from the definition ofC2. Remember, however, when we prove our lemma for the case n= 2, we have assumed

1

m1/aC4(a) < ε≤1/3.

So, by (2.9), when we conduct the induction we need to assume that 1

(m3i)1/aC4(a) < ε≤1/3, fori= 0, . . . , N −2.

That is we need to assume

ε∈ (m32−N)−1/a(C4(a))−1, 1/3 .

Taking C3= 1/C4(a), we finish the proof.

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The next lemma is very similar. Let A(m, n, b, ε) :=b

(

(i1, . . . , in)∈Nn: Xn k=1

e(logik)b ∈[m, m(1 +ε)]

) ,

and for s >1/d, write

G(m, n, b, ε, s) =b X

i1···inA(m,n,b,ε)b

Yn k=1

i−dsk .

Lemma 2.4. There exists a positive constant Cb = C(s)b such that for all e−(log(m32−n))1/b < ε≤1/3, we have

G(m, n, b, ε, s)b ≤6·Cbn−1ε·e(1−ds)(logm)1/b.

Proof. The proof goes again by induction. First consider the case n = 2.

Similar to the proof of Lemma 2.3, we have G(m,b 2, b, ε, s)≤2

e(log(m(1+ε)/2)1/b

X

k=1

k−dse−ds(log(m−e(logk)b))1/b·Nbm,b,ε(k), with

Nbm,b,ε(k) :=♯n

i2 :m−e(logk)b ≤e(logi2)b ≤m(1 +ε)−e(logk)bo . For ε≤1/3, short calculations give us the following estimation

Nbm,b,ε(k)≤ ⌈3ε·e(logm)1/b⌉.

Hence, if ε > e−(logm)1/b,

Nbm,b,ε(k)≤6ε·e(logm)1/b. Thus, by noting elog(m/3))1/b13e(logm)1/b, we obtain

G(m,b 2, b, ε, s) ≤12·3dsζ(ds)e(1−ds)(logm)1/b.

Assume now that the assertion is satisfied for all n < N for someN >2, we will prove by induction that it holds for n=N as well. We have

G(m, N, b, ε, s)b ≤2

e(log(m(1+ε)/2)1/b

X

k=1

k−ds X2 j=0

G((m−eb (logk)b)(1+ε)j, N−1, b, ε, s).

Substituting the induction assumption, we get

G(m, N, b, ε, s)b ≤12·3dsCbN−2εe(1−ds)(logm)1/bζ(ds).

Thus, we have proved the assertion for Cb= 2·3dsζ(ds) under the assumption

ε∈ e−(log(m32−N))1/b, 1/3 .

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3. Proofs for (I-1) of Theorems 1.2-1.5 and (I-2) of Theorem 1.5 3.1. Proofs for (I-1) of Theorems 1.2-1.5. For these parts of proofs we suppose the d-decaying Gauss like iterated function system satisfies the distortion property (1.1). We will apply Lemma 2.1.

Note that in all cases we are going to prove, the function Φ is taken as Φ(n) =enα. Letε >0. Takenk=kα1(1−ε) anduk−1(Φ(nk)−Φ(nk−1)).

Then evidently the sequence (nk)k≥1 satisfies the assumption of Lemma 2.1.

We can also check that EM ⊂Eϕ(Φ). In fact, for any x∈EM we have Φ(nk)< Snkϕ(x)<Φ(nk) +nkϕ(M).

Since Φ(n)/n→ ∞, we see that

Snkϕ(x) Φ(nk) →1.

However, as nk+1/nk→1 andSnϕis increasing, this is enough to have limn

Snϕ(x) Φ(n) = lim

k

Snkϕ(x) Φ(nk) and we are done.

Now we need only to check for each case of ϕ in Theorems 1.2-1.5, the condition (2.1) is satisfied. First notice that

Φ(nk)−Φ(nk−1) =ek1ε−e(k−1)1ε ≈(1−ε)k−εek1ε. Thus when ϕ(j) =ja, we have

uk≈ (1−ε)k−εek1ε1/a

, and, if α <1/2 and εis small enough,

k→∞lim 1 nk

Xk j=1

loguj = lim

k→∞

Pk

j=1j1−ε/a kα1(1−ε) = 0.

When ϕ(j) =e(logj)b, then

uk≈e(log((1−ε)k−εek1−ε))1/b, and, if α < b+1b , and εis small enough,

k→∞lim 1 nk

Xk j=1

loguj = lim

k→∞

Pk j=1j1bε kα1(1−ε) = 0.

When ϕ(j) =ejc, we have

uk≈log((1−ε)k−εek1−ε)1/c, and, if α <1 and εis small enough,

k→∞lim 1 nk

Xk j=1

loguj = lim

k→∞

Pk j=11−ε

c logj kα1(1−ε) = 0.

Hence in all cases the condition (2.1) is satisfied.

Applying Lemma 2.1, we complete the proofs.

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3.2. Proof for (I-2) of Theorem 1.5. We will use a natural covering.

Suppose Φ(n) =enα withα >1. For each x∈Eϕ(Φ), for any smallε > 0, for all large enough n, we have

(1−ε)Φ(n)≤ Xn k=1

ϕ(ak)≤(1 +ε)Φ(n).

Thus

(1−ε)Φ(n)−(1 +ε)Φ(n−1)≤ϕ(an)≤(1 +ε)Φ(n)−(1−ε)Φ(n−1).

Note that for α >1, we have

(1 +ε)Φ(n)−(1−ε)Φ(n−1) = (1 +ε)enα −(1−ε)e(n−1)α ≤(1 +ε)enα, and

(1−ε)Φ(n)−(1 +ε)Φ(n−1) = (1−ε)enα−(1 +ε)e(n−1)α ≥(1−2ε)enα. Then

(1−2ε)enα ≤ϕ(an)≤(1 +ε)enα.

However, for ϕ(j) =ejc with c≥1, there is at most onej such that (1−2ε)enα ≤ϕ(j)≤(1 +ε)enα.

Hence Eϕ(Φ) is a countable set which has Hausdorff dimension 0.

4. Remaining proofs

We will divide the case I-2 of Theorem 1.2 into two subcases: subcase I-2a for 1/2 < α < 1, and subcase I-2b for α ≥1. Similarly, we will divide the case I-2 of Theorem 1.3 into subcase I-2a (b/(b+ 1) < α <1) and subcase I-2b (α≥1).

Theorem 1.2, case II; Theorem 1.2, subcase I-2b; Theorem 1.3, case II;

Theorem 1.3, subcase I-2b; Theorem 1.4, case I-2; Theorem 1.4, case II;

Theorem 1.4, case III are all obtained by applying Lemma 2.2.

4.1. Proof of Theorem 1.2, case II. Let x ∈ Eϕ(Φ). Fix some small ε >0. Then there exists N ∈Nsuch that for alln > N,

Φ(n)(1−ε)< Snϕ(x)<Φ(n)(1 +ε).

This implies

ϕ(an(x)) =Snϕ(x)−Sn−1ϕ(x)

Φ(n)(1−ε)−Φ(n−1)(1 +ε), Φ(n)(1 +ε)−Φ(n−1)(1−ε) (4.1)

forn≥N. Substituting the formula for Φ, we get ϕ(an(x))∈

eβn(1−2ε), eβn(1 + 2ε) . Hence a further substitution of the formula for ϕgives us

eβn/a(1−3ε/a)< an(x)< eβn/a(1 + 3ε/a).

Put sn=eβn/a and tn= 3εeβn/a/a. Then Eϕ(Φ)⊂[

N

B({sn},{tn}, N).

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By Lemma 2.2, we have the upper bound dimHEϕ(Φ)≤lim inf

ℓ→∞

P

j=1log 3εeβj/a/a dPℓ+1

j=1logeβj/a−log 3εeβℓ+1/a/a

= lim inf

ℓ→∞

P

j=1βj/a dPℓ+1

j=1βj/a−βℓ+1/a

= 1

dβ−β+ 1.

On the other hand, let εn be a sequence of positive numbers converging to 0. Let x∈B(eβn/a, εneβn/a,1). For large nwe have

eβn(1−εn)a< Snϕ(x)< eβn(1+εn)a+

n−1X

i=1

(1+εi)a·eβi < eβn(1+aεn+o(1)).

Thus,

Eϕ(Φ)⊃B(eβn/a, εneβn/a, 1).

Applying Lemma 2.2 and doing almost the same calculation as above, we obtain the lower bound.

4.2. Theorem 1.2, case I-2b. We can repeat the proof of Theorem 1.2, case II. From the formula (4.1), we get

ϕ(an(x))∈

enα(1−2ε), enα(1 + 2ε) . Hence,

Eϕ(Φ)⊂[

N

B(enα/a, 3εenα/a/a, N).

On the other hand, for a sequence of positive numbers εn converging to 0, we have

Eϕ(Φ)⊃B(enα/a, εnenα/a, 1).

Applying Lemma 2.2, we have dimHEϕ(Φ) = lim inf

ℓ→∞

P

j=1jα/a dPℓ+1

j=1jα/a−(ℓ+ 1)α/a = 1 d.

4.3. Theorem 1.3, case II. From the formula (4.1), we get ϕ(an(x))∈

eβn(1−2ε), eβn(1 + 2ε) . Hence,

Eϕ(Φ)⊂[

N

B

eβn/b, 3ε

b βn(1/b−1)eβn/b, N .

On the other hand, for a positive sequence εn converging to 0, we have Eϕ(Φ)⊃B eβn/b, εnβn(1/b−1)eβn/b, 1

. Applying Lemma 2.2, we have

dimHEϕ(Φ) = lim inf

ℓ→∞

P j=1βj/b dPℓ+1

j=1βj/b−β(ℓ+1)/b = 1

1/b−β1/b+ 1.

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4.4. Theorem 1.3, case I-2b. From the formula (4.1), we get ϕ(an(x))∈

enα(1−2ε), enα(1 + 2ε) .

Hence,

Eϕ(Φ)⊂[

N

B

enα/b, 3ε

b nα(1/b−1)enα/b, N .

On the other hand, for a sequence of positive numbers εn converging to 0, we have

Eϕ(Φ)⊃B enα/b, εnnα(1/b−1)enα/b, 1 . Applying Lemma 2.2, we have

dimHEϕ(Φ) = lim inf

ℓ→∞

P j=1jα/b dPℓ+1

j=1jα/b−(ℓ+ 1)α/b = 1 d.

4.5. Theorem 1.4, case I-2. From the formula (4.1), we get ϕ(an(x))∈

enα(1−2ε), enα(1 + 2ε) .

Hence,

Eϕ(Φ)⊂[

N

B

nα/c, 3ε

c nα(1/c−1), N .

On the other hand, for a sequence of positive numbers εn converging to 0, we have

Eϕ(Φ)⊃B nα/c, εnnα(1/c−1), 1 . We then apply Lemma 2.2 to obtain

dimHEϕ(Φ) = lim inf

ℓ→∞

P

j=1α(1/c−1) logj dPℓ+1

j=1α/clogj−α(1/c−1) log(ℓ+ 1) = 1−c d .

4.6. Theorem 1.4, case II. From the formula (4.1), we get ϕ(an(x))∈

eβn(1−2ε), eβn(1 + 2ε) .

Hence,

Eϕ(Φ)⊂[

N

B

βn/c, 3ε

c βn(1/c−1), N .

On the other hand, for a positive sequence εn converging to 0, we have Eϕ(Φ)⊃B βn/c, εnβn(1/c−1), 1

. Applying Lemma 2.2, we obtain

dimHEϕ(Φ) = lim inf

ℓ→∞

P

j=1j(1/c−1) logβ dPℓ+1

j=1j/clogβ−(ℓ+ 1)(1/c−1) logβ = 1−c d .

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4.7. Theorem 1.4, case III. From the formula (4.1), we get ϕ(an(x))∈

eeγn(1−2ε), eeγn(1 + 2ε) . Hence,

Eϕ(Φ)⊂[

N

B

e1cγn, 3ε

c eγn(1/c−1), N .

On the other hand, for a positive sequence εn converging to 0, we have Eϕ(Φ)⊃B e1cγn, εneγn(1/c−1), 1

. Applying Lemma 2.2, we get

dimHEϕ(Φ) = lim inf

ℓ→∞

P

j=1(1/c−1)γj dPℓ+1

j=11/cγj −(1/c−1)γℓ+1 = 1−c

dγ−(1−c)(γ −1). We also apply Lemma 2.2 for the lower bounds of Theorem 1.2, subcase I-2a and Theorem 1.3, subcase I-2a. But for the upper bounds we need Lemma 2.3 and Lemma 2.4 respectively.

4.8. Proof of Theorem 1.2, case I-2a. We first show the lower bound.

Let x be points such that ϕ(an(x))∈

αnα−1enα(1−εn), αnα−1enα(1 +εn) . where εn is a summable positive sequence. Then

Xn j=1

αjα−1ejα(1−εj)≤ Xn j=1

ϕ(aj(x))≤ Xn j=1

αjα−1ejα(1 +εj), which implies

enα −2 Xn j=1

αjα−1ejαεj ≤ Xn j=1

ϕ(aj(x))≤enα−2 Xn j=1

αjα−1ejαεj.

Note that

Xn/2 j=1

αjα−1ejαεj ≤ Xn/2 j=1

αjα−1ejα ≤e(n/2)α,

and by the summability of {εn}, Xn

j=n/2

αjα−1ejαεj ≤αnα−1enα Xn/2 j=1

εj =o(enα).

Hence, these points x are all inEϕ(Φ), that is Eϕ(Φ)⊃B

(αnα−1enα)1/a, εn

a(αnα−1enα)1/a, 1 . Applying Lemma 2.2, we obtain the lower bound.

Now we turn to the upper bound.

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