R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
J. A. L ÓPEZ M OLINA
M. J. R IVERA
A note on natural tensor products containing complemented copies of c
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Containing Complemented Copies of
c0.J. A.
LÓPEZ MOLINA(*) -
M. J.RIVERA (*) (**)
ABSTRACT - Let H be a Frechet lattice
containing
apositive
sequenceequivalent
to the unit basis of c,o . We prove that the natural tensor
product H X
u X con-tains a
complemented subspace isomorphic
to co for every infmite dimension- al Banach space X, whichgeneralizes
aprevious
result of Cembranos and Freniche.-
0. - Introduction.
Cembranos
[4]
shows in 1984 thate(K, X)
contains acomplemented subspace isomorphic
to co if K is an infinitecompact
Hausdorff space and X an infinite dimensional Banach space. The theorem was extended in 1986by
E. Saab and P. Saab[14]
whoproved
that theinjective
ten-sor
product X ©
Y of two infinite dimensional Banach spaces X and Y contains acomplemented
copy of co if X or Y contains co ,using
aproof inspired by
the Cembranos’s one. However both results have been ob- tained also in1984,
indeed in a little moregeneral version,
in a paper of Freniche[8].
On the otherhand,
Emmanuele[7]
showed in 1988 that if(Q,
a,v)
is a notpurely
atomic measure space and X is a Banach spacecontaining
co , the space1 ~ p
oo , of Bochnerintegrable
X-valued
functions,
contains acomplemented
copy of co .(*) Indirizzo
degli
AA.: E.T.S.Ingenieros Agrdnomos,
Camino de Vera,46071 Valencia,
Spain.
(**)
Supported
in partby
the DGICYT,project
PB91-0538.106
The spaces used
by Freniche,
Cembranos and Emmanuele are par- ticular cases of the Levin natural tensorproduct H Q9
X of a Banach lat- tice H and a Banach space H(see
theoriginal
paper[11]
and also[5]).
The main purpose
of
this paper is to extend the above results to thismore
general setting.
Our method will be useful also to deal with thesame
problem
in the case of theSaphar
tensorproduct
Y(see [15]).
d°°The notation and
terminology
is standard(see [10]
forgeneral
the-ory of
locally
convex spaces and[1]
for Banachlattices).
If H is aFrechet space
(resp.
a Frechetlattice), ( ~ (
will be anincreasing
fundamental
system
of continuous seminorms(resp.
continuous latticeseminorms)
in H and EH ~1}.
The usual Schauder basisof f1
and co will be denotedby ( en )n =1.
A sequence( hi )
in the Frechet space H is said to beweakly absolutely
summableif,
for every n theinequality
holds. We denote
by l1 (H)
the set of allweakly absolutely
summablesequences in H and
by
the set of all(hi)
E suchthat,
forevery n
e N,
we have1. - Levin natural tensor
products.
Let H be a Frechet lattice and F a Frechet space. The Levin
(or natural)
tensorproduct H 0
F is thecompletion
of H®
F where9 U
p is the
topology
definedby
thefamily
of seminorms andThis tensor
product
was introducedby
Levin[11]
in the caseof a Banach lattice H and a Banach space
G, although
with a differentequivalent definition, (see [9]
for aproof
of theequivalence)
andby Chaney [5]
and Lotz[13]
with thepresent
definition. The,u-topology
verifies that
E 5 p £
;r(E
and Jr are theinjective
andprojective topologies
of Grothendieckrespectively) but ,u
is not a tensornormsince it does not
verify
ingeneral
the metricmapping property.
If H =
e(K)
or H = L ’(v) then u
coincides with E. If H is anL1(1/-)
space, p = yr
(see [5]).
The
importance
of the Levin tensorproduct
lies in the fact thatmany usual function spaces can be
represented by
means of such aproduct.
Forinstance,
let( S~,
be acomplete
a-finite measurespace and
3K(Q, a)
be the set ofclasses,
moduloequality
almost every-where,
of measurable real functions on( S~, a).
A K6the function space(or
a Banach ideal functionspace)
on( S~,
a,p)
will be a Banach space H which is an ideal ina).
Given a Banach spaceX,
we defineH(X)
as the set of
strongly
measurable such thatIlf(. )11
EE H endowed with the It can be
proved (see [ 11 ], [2], [3]) that,
when H has an order continuous norm, we haveH(X) =
= H ~
X. Inparticular,
the familiarLebesgue-Bochner
spaces Lp(Y. X),
oo , are isometric to
Lp (Q) 0 X.
03BCWe shall need the
following
result about therepresentation
of theelements
03BC
LEMMA 1. Let H be a Frechet lattice and F a Frechet space.
Every
z F has a
representations
z ® xiwith hi > 0,
where(Xi)t’=
103BC i=1 i
is a bounded sequence in F and
Moreover, if
n EN, for
every suchrepresentation of
z andWeN /
where the
infimun
is taken over all rep- resentactionsof
z acs above.PROOF. If z
e H © F,
there exists a sequence( zn )n =
o c H Q9 F suchthat lim 0 for each k E N.
Choosing
asubsequence
if it is~
needed,
we can suppose that z = zo+ I ( zn - zn _ 1 )
with~=1 1
For every there exists a
representation ,
such that 0 and
By
themonotony
of thelattice
seminorms,
z can berepresented by
aconvergent
series in^ m m
H X F,
02:= E
with everyhk ; 0, and E Ilxk Ilnhk
k=1
converges in H for every n E N. We define a sequence
in
K asfollows: there are
n, i e N,
1 ;i ; j ( n ),
such that Xk = xni -108
representation
of the announcedtype.
Infact,
it is clear that(xk /ak)k =1
is a bounded sequence in E. On the other
hand,
H’ is a lattice with its canonical order.Denoting Vn == {~
E1},
we have thatVn
is an - 1
solid set in H’ .
Then,
if~
= 1+ ¿ j( i),
we havei=1
and
thus,
is in~(jH~).
n
mn
Finally,
we fix n e N. It is clear that n forevery
representation
of z of the abovetype.
Given one ofthem,
forevery E >
0,
there is 1 ako
such forevery k * ko ,
~ ~ ; = i2 Ilxjllnhj II
ne/3.
Putting
Wk= E
we have03BCn(z - wk) E/3.
Now it ispossible
j=1
- _
-
to take a new
representation
of Wk, say Wk= .¿ hj Q9 Xj with hj > 0,
suchthat j -1
t -
m
Then z
= ~ hj 0 - + E hj 0 ~ ~
so weget
anotherrepresentation
z ="
Xi
*’ H cc m11
of the above mentioned
type, satisfying ll 2 lln
n 5i = 1 i=1 1 n
03BCn(z)
+ E. Theremaining inequality
followseasily.
2.
Complemented copies
of Co in Levin tensorproducts.
Next result
generalizes
the theorem of Cembranos and Frenichequoted
in theintroduction
from the latticepoint
of view.THEOREM 2. Let H be a Frechet lattice which contains a ve sequence
equivalent
to the unit basisThen for
everyinfinite
di-mens’ional Banach space
E, H Q9
E contains acomplemented subspace
isomorphic
to 11PROOF. Let
( bn )n =1
be a sequence in H +equivalent
to the standard basis( en )n =1
of coby
anisomorphism ~ : co - H
such that =bn .
As co is
isomorphic
to asubspace
ofH, e1
isisomorphic
to aquotient
ofHp.
The sequence(~)~=i
i is also boundedin e1
and verifies that= As the
quotients
of the DF spaces lift bounded sets[10, 12.4.8],
there exist a bounded sequence( bn )n =1
i inH~
such thatSince
( bn )n =1
i isequicontinuous,
there is suchthat, ( bn )n =1
cUk
holds.By
the theorem ofJosefson-Nissenzweig,
thereis a
a(E’ , E )
null sequence( an )n =1 in
E’ such =1,
dn e N.An
application
of theprinciple
of localreflexivity gives
us a sequence( an )n =1
i in E suchan)
= 12,
for every n e N.We define
Q :
co - HQ9
E such that@
ai , for every11 i = 1
(Ei)
e co . The mapQ
is well defined: 1being equivalent
to i, we have thatMoreover, Q
is linear and continuous: infact, given
s e NThen we define
T: H Q9
E - co in thefollowing
way.By
Lemma1,
^ 03BC oo
every H 0
E can berepresented
as zQ9 Vi where,
for eachi = 1
110
and sup M for some M > 0. Then we
put
i e N
The map T is well defined: it is easy to see that
bi @ an
eH ~ E ;
onthe other
hand,
since(u)t= 1
is bounded inH,
we haveMk: =
: = sup 00; as
bi
eUk
for all nE N,
from( 1 ), given
E >0,
thereieN
is h E N such
that,
for all n E Nand since
(an)n =1
isa(E’, E) null,
there is no such that for everyn > n0
and hence
T(z)
E co .Moreover T is continuous. In
fact, by
Lemma1,
for every z EH ® E,
00 Ii
given E
>0,
there exist arepresentation
z= 2 he (9 xi with hi > 0,
such that i =1
As
Uf
is a solid set we havebn
=for each n Then we obtain
and hence
2,uk (z).
It is easy to see that for every
(lj) e co,
andthen is a
complemented
ofH ~ E isopmorphic
to co .
’ /1 ’ itREMARK 3. If K is an infinite
compact
Hausdorff space,e(K)
con- tains asubspace isomorphic
to coby
apositive isometry,
and this fact isimplicit
in the Cembranos’sproof
and moreexplicit
in the Freniche’sone. To see
that,
take a sequence(G,,)’= 1 of
open nonempty pairwise disjoint
sets inK,
and a sequence( tn )n =1, tn E Gn ,
TheUrysohn
lemmagives
us a sequence c~(K)+
such thatbn :
K --
[ o, 1 ] with bn ( tn )
= 1and bn ( t )
= 0 ift eKBGn.
L et F be the linear span The mapQ:
F -~ co such thatQ(bn)
= en is anisometry
s
since then
f sup I A i I
and it isi=1 1 I i e N
clearly positive. Moreover,
if we takebn 6 tn (the
Dirac measure attn ), choosing ( an )
as in Theorem2,
weget
an easyrepresentation
of the pro-jection
P frome(K, X) _
onto the closure of the linear span~
EXAMPLE 4. If
M(t)
is an Orlicz function which does not satisfies theA 2
condition at0,
the Orlicz sequence spacehM
has a sublattice or-der
isomorphic
to co(see [3]
and[12])
and eoo is not asubspace
ofhM . By
Theorem
2,
for every infinite dimensional Banach spaceX,
Co is a com-plemented subspace
of X.f.1
COROLLARY 5. Let
(Q,
be acomplete
measure space such thatL °° (,u ) is infinite
dimensional. Let X be a Banach space which does not contain co. Then L °°(p) complemented
inL ~ (~ ~ X).
~PROOF.
By
Theorem2,
co iscomplemented
in L °°(,u) 0 X. By [6],
ifIU
c,o were
complemented
in L °°(,u, X),
co would be asubspace
of X. Thenthe result follows.
We note
also,
for the sake ofcompleteness,
the alternative re-sult :
THEOREM 6. If H is an order continuous norm K6the
function
space,
H(X)
=H ~ X
contains acomplemented
copyof
coif X
has acopy
of
co . f.lPROOF. It is
essentially
the same one of Emmanuele forLP (/-l, X)
in[7]. 0
Our method can be
easily applied
also in the context of thedoo-ten-
sor
product
ofSaphar (see [15]
for definitions anddetails):
112
THEOREM 7. Let F be a Fréchet space
containing
asubspace
iso-mor~phic
to co . Thenfor
everyinfinite
dimensional Banach spaceX,
FOX
contains acomplemented subspace isomorphic
to co .doo
PROOF. It is similar to the
proof
of Theorem2,
since thetopology
ofF ~ X
is determinedby
the seminormsgiven,
for each z Eb y
d. d.
m
where the infimum is taken over all
representations
z= ¿
yi ® xi , such thatsup llxi II 00
and( yi )
Efo (F).
i = 12EN
A Grothendieck space is a Banach space X such that
a(X’ , X)
anda(X’ X" )
null sequences in X’ are the same. In consequence a Grothendieck space can not contain acomplemented
copy of co . Thenwe have:
COROLLARY 8. Let
H,
G be Banach lattices such that H contains apositive
sequenceequivalent
to the standard basisof co
and G is a Köthefunction
space with order continuous norm. Let X and Y beinfinite
di-mensional Banach spaces such that Y contains a
subspace isomorphic
to co . Then neither
G( Y), H ~
X norY ~
X are Grothendieck spaces.IU d.
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Manoscritto pervenuto in redazione il 7 febbraio 1995.