Cubic hypersurfaces over finite fields
Olivier DEBARRE
(joint with Antonio LAFACE and Xavier ROULLEAU)
Ecole normale sup´´ erieure, Paris, France
Moscow, HSE, September 2015
Theorem (Chevalley–Warning)
Any subscheme ofPmFq defined by equations of degrees d1, . . . ,ds with d1+· · ·+ds ≤m has anFq-point.
→any cubicFq-hypersurface of dimension ≥2 contains an Fq-point.
What about Fq-lines?
Olivier DEBARRE Cubic hypersurfaces over finite fields 2 of 22
The scheme F (X )
X ⊂Pn+1k cubic of dimension n.
F(X)⊂Gr(1,Pn+1k ) projective scheme of lines contained in X.
F(X) connected ifn ≥3.
Sing(X) finite =⇒ F(X) lci of dimension 2n−4 and ωF(X) =OF(X)(4−n).
X smooth =⇒ F(X) smooth.
High dimensions
Theorem
AnyFq-cubic of dimension≥5 contains anFq-line.
Proof. Let x∈X(Fq). The scheme of lines through x contained in X is the intersection inPn of hyperplane, a quadric, and a cubic
→Chevalley–Warning when n≥6.
WhenX is smooth,F(X) is Fano whenn ≥5
→Esnault, and Fakhruddin–Rajan to extend to all X. We now look at cubic surfaces, threefolds, and fourfolds.
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Cubic surfaces
The diagonal cubic surface
x13+x23+x33+ax43 = 0 contains noFq-lines when a∈Fq is not a cube.
aexists wheneverq ≡1 (mod 3)
There are smooth cubicFq-surfaces with no Fq-lines forq arbitrarily large.
The Galkin–Shinder “beautiful formula”
X ⊂Pn+1F
q Fq-cubic F(X)⊂Gr(1,Pn+1F
q ) scheme of lines contained in X Nr(X) := Card(X(Fqr))
Nr(F(X)) = Nr(X)2−2(1 +qnr)Nr(X) +N2r(X) 2q2r
+q(n−2)rNr(Sing(X)).
This formula comes from a relation between the classes ofX and F(X) in the Grothendieck ring of varieties.
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Y smooth projective scheme defined over Fq
Pi(Y,T) := det(Id−TF∗,Hi(Y,Q`)) =:
bi(Y)
Y
j=1
(1−Tωij)∈Z[T] where|ωij|=qi/2. The trace formula (n:= dim(Y))
Nr(Y) = X
0≤i≤2n
(−1)iTr(F∗r,Hi(Y,Q`)) = X
0≤i≤2n
(−1)i
bi(Y)
X
j=1
ωrij
implies, for the zeta function, Z(Y,T) := expX
r≥1
Nr(Y)Tr r
= Y
0≤i≤2n
Pi(Y,T)(−1)i+1.
Zeta function of F (X )
X ⊂P4F
q smooth cubic.The trace formula reads Z(X,T) =
Q
1≤j≤10(1−qωjT)
(1−T)(1−qT)(1−q2T)(1−q3T), withωj algebraic integers and |ωj|=q1/2.
The Galkin–Shinder formula implies Z(F(X),T) =
Q
1≤j≤10(1−ωjT)Q
1≤j≤10(1−qωjT) (1−T)(1−q2T)Q
1≤j<k≤10(1−ωjωkT)
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Cohomology of F (X )
This formula gives the Betti numbers ofF(X). Actually, the full Galkin–Shinder relation gives isomorphisms of Gal(Fq/Fq)-modules
H3(X,Q`) ∼ //H1(F(X),Q`(1))
V2
H1(F(X),Q`) ∼ //H2(F(X),Q`) V2
H1(A(F(X)),Q`) ∼ //
∼OO
H2(A(F(X)),Q`)
∼OO
The first one can also be obtained using the incidence correspondence.
The second one can also be deduced by smooth and proper base change from the statement in char. 0.
Existence of lines
Theorem
Any smoothFq-cubic threefold contains at least 10Fq-lines if q≥11.
Proof. Write the Frobenius eigenvalues asω1, . . . , ω5, ω1, . . . , ω5. Setrj :=ωj+ωj ∈[−2√
q,2√
q]. Use the trace formula N1(F(X)) = 1− X
1≤j≤5
rj − X
1≤j≤5
qrj +q2
+ 5q+ X
1≤j<k≤5
(ωjωk +ωjωk +ωjωk +ωjωk)
= 1 + 5q+q2−(q+ 1) X
1≤j≤5
rj + X
1≤j<k≤5
rjrk and study the minimum of this real function...
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Examples
We found smooth cubic threefolds overF2,F3,F4, andF5 with no lines.
The cubic threefold inP4F
5 with equation
x13+ 2x23+x22x3+ 3x1x32+x12x4+x1x2x4+x1x3x4
+ 3x2x3x4+ 4x32x4+x2x42+ 4x3x42+ 3x22x5+x1x3x5 + 3x2x3x5+ 3x1x4x5+ 3x42x5+x2x52+ 3x53 is smooth and contains noF5-lines and 126F5-points.
RemainsF7,F8, andF9...
Average numbers of lines
Average numbers of lines computed on random samples of 105 F2-cubic threefolds
all cubics; average∼9.651 smooth cubics; average∼6.963.
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Singular threefolds
LetX ⊂P4Fq Fq-cubic with a single singular point, of typeA1 or A2.
The curveC of lines in X through the singular point is smooth of genus 4 and canonically embedded inP3F
q. It has two pencilsg31 andh13, used to embedC in C(2) by
x7→g31−x
Clemens–Griffiths, Kouvidakis–van der Geer
F(X) is the non-normal surface obtained by gluing in C(2) these two copies ofC.
Lines on singular threefolds
Theorem
For any r≥1, set nr := Card(C(Fqr)). We have
Card(F(X)(Fq)) =
1
2(n12+n2)−n1 if g31 6=h31 are defined overFq;
1
2(n12+n2) +n1 if g31 6=h31 are not defined overFq;
1
2(n12+n2) if g31 =h31.
Again, this can also be obtained with the Galkin–Shinder method.
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Lines on singular threefolds
Corollary
When q≥4, any cubic threefold X ⊂P4F
q defined over Fq with a single singular point, of type A1 or A2, contains an Fq-line.
Proof. We need to exclude
n1=n2 = 1 andg316=h13 defined overFq. Write C(Fq) =C(Fq2) ={x}, andg31≡x+x0+x00.
g31 is defined over Fq ⇒ x0+x00 defined overFq
⇒ x0,x00 are defined over Fq2
⇒ x0 =x00=x
⇒ g31≡3x≡h13 Contradiction.
Lines on singular threefolds
n1=n2 = 0. Thenq≤7 (Howe–Lauter–Top).
Weil conjectures forC:
Frobenius rootsω1, . . . , ω4,ω¯1, . . . ,ω¯4, with|ωj|=√ q;
H monic with (real) rootsrj:=ωj+ ¯ωj with|rj| ≤2√ q has integral coefficients;
P
1≤j≤4rj =P
1≤j≤8ωj =q+ 1−n1=q+ 1;
P
1≤j≤4rj2=P
1≤j≤8(ωj2+2q) =q2+8q+1−n2=q2+8q+1.
Hence
H(T) =T4−(q+ 1)T3−3qT2+aT+b, with |b|=|r1r2r3r4| ≤16q2 and|a|=|P4
j=1b/rj| ≤32q3/2 integral.
Computer search: such polynomials with 4 such real roots and q ∈ {2,3,4,5,7}only exist for q ≤3.
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Examples
We found nodal cubics threefolds overF2 and F3 with no lines.
OverF2:
x23+x22x3+x33+x1x2x4+x32x4+x43+x12x5+x1x3x5+x2x4x5 contains noF2-lines and
H(T) =T4−3T3−6T2+ 24T −15.
OverF3:
2x13+ 2x12x2+x1x22+ 2x2x32+ 2x1x2x4+x2x3x4
+x1x42+ 2x43+x2x3x5+ 2x32x5+x2x52+x53 contains noF3-lines and
H(T) =T4−4T3−9T2+ 47T −32.
Zeta function of F (X )
X ⊂P5F
q smooth cubic.The trace formula reads
Z(X,T) = 1
(1−T)(1−qT)(1−q3T)(1−q4T)Q23
j=1(1−qωjT),
withωj algebraic integers,|ωj|=q, andω23=q.
The Galkin–Shinder formula implies Z(F(X),T) = (1−T)(1−q4T)Q 1
j((1−ωjT)(1−q2ωjT))Q
j≤k(1−ωjωkT).
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Cohomology of F (X )
Again, the Galkin–Shinder relation implies that there are isomorphisms of Gal(Fq/Fq)-modules
H4(X,Q`) ∼ //H2(F(X),Q`(1))
Sym2H2(F(X),Q`) ∼ //H4(F(X),Q`) The first also follows using the incidence correspondence.
The second one can also be deduced by smooth and proper base change from statement in char. 0 (Beauville–Donagi, Bogomolov).
Existence of lines
Theorem
Any smoothFq-cubic fourfold contains at least 26Fq-lines if q≥5.
One can use another trace formula (Katz). If Sing(X) finite, the cohomology ofOF(X) is very simple (Altman–Kleiman):
dimFqHj(F(X),OF(X)) = 1
forj ∈ {0,2,4}, the others are 0, and the multiplication H2(F(X),OF(X))⊗H2(F(X),OF(X))→H4(F(X),OF(X)) is an isomorphism of Galois modules (Serre duality).
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The Katz trace formula
N1(F(X)) ≡
4
X
j=0
(−1)jTr(F,Hj(F(X),OF(X))) (mod p)
≡ 1 +t+t2 (modp) Corollary
Assume q≡2 (mod 3). AnyFq-cubic fourfold with finite singular set contains anFq-line.
This applies toq = 2 and leaves only the casesq ∈ {3,4} open for the existence of a line on a smooth cubic fourfold.
Final question
The computer found a smooth cubic fourfold overF2 with a single line.
Question
We found no cubic fourfolds without lines. Do they exist?
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