A NNALES DE L ’I. H. P., SECTION A
K RISTIAN S EIP
Curves of maximum modulus in coherent state representations
Annales de l’I. H. P., section A, tome 51, n
o4 (1989), p. 335-350
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335
Curves of maximum modulus in coherent state
representations
Kristian SEIP
Division of Mathematical Sciences, University of Trondheim, N-7034 Trondheim-NTH, Norway
Vol. 51, n° 4, 1989, Physique theorique
ABSTRACT. - We consider functions of the form
e - °‘ ~ Z ~ 2 f (z), f
entireanalytic (Bargmann case),
andf analytic
iny > 0 (Bergman case).
We describe curves
along
which the moduli of such functions attain local maxima. Such a curve determinesuniquely (up
to a constantfactor)
afunction f.
If the curve is closed and iff
hasexactly
one zero in thedomain bounded
by
the curve, then the curve is aquantized
circle. In thisway we obtain the
quantized
classical orbits of the harmonic oscillator and thehydrogen
atom, their wave functions and the correct spectra. In theBargmann
case thefamily
of curves of maximum modulus is shown to consist of allstraight
lines and thequantized circles,
while in theBergman
case thisfamily
is found to be much richer. It is believed that this represents aninteresting approach
to thestudy
of some quantum mechanical operators.RESUME. 2014 Nous considerons des fonctions
e-03B1|z|2 f (z), f entiere analy- tique (cas
deBargmann),
etV/(z), f analytique
pour(cas
deBerg- man).
Nous decrivons des courbes Ielong desquelles
les modules de cesfonctions
atteignent
des maximums locaux. Une telle courbe determineuniquement
unefonction f (à
un facteur constantpres).
Si la courbe est fermee et quef ait
exactement un zero dans Ie domaine borne par lacourbe,
alors celle-ci est un cerclequantifie. Ainsi,
nous obtenons les orbitesclassiques quantifiees
de l’oscillateurharmonique
et de l’atomed’hydrogène,
leur fonctions ondulatoires et les spectres corrects. Dans Iecas de
Bargmann,
nous montrons que la famille de courbes de module maximal consiste de toutes les droites et les cerclesquatifies,
tandis queAnnales de /’Institut Henri Poincaré - Physique théorique - 0246-0211 Vol. 51/89/04/335/16/$3.60/(6) Gauthier-Villars
dans Ie cas de
Bergman,
cette famille estbeaucoup plus
riche. On croit que cela est unefagon
interessante d’aborder l’étude de certainesoperateurs
de la
mecanique quantiquc.
1. INTRODUCTION
This paper presents a
geometrical approach
to thestudy
of somefundamental operators in quantum mechanics.
Actually,
it is first of all astory
of
geometry, the quantum mechanics comes into the game as anapparently
miraculousby-product.
As a story of quantum mechanics this paper may be taken as an argument for the usefulness of coherent staterepresentations.
We shall work with two
representations
of coherent states, the canonicalcase of
Bargmann (see
e. g.[3])
and theBergman
case as studiedby
Th. Paul
[4],
the latter casebeing
related to the radial harmonic oscillator and thehydrogen
atom.The
geometrical setting
is as follows. Given somecomplex
domainQ,
the class of functions
f analytic
in Q and somepositive weight
function wwhich here is associated to a characteristic kernel of the domain Q. We look for
possible
curves r(called
M-curvesbelow)
in Q such that to acurve r there exists an
analytic
functionf
with the property thatw (z) attains
maximaalong’r.
It turns out that the
family
of such curves is rather restricted and w~find that certain natural subfamilies
give
all information abouteigen-
functions and spectra of fundamental quantum mechanical operators like the Hamiltonians of the harmonic oscillator and the coulomb
potential problem
of thehydrogen
atom(see
Theorem 4.1 and Theorem5. 2).
Suchsubfamilies will be the
quantized
classical orbits of theoperators
inquestion.
One should notice that in this way we obtain the orbits withoutleaving
the framework of quantummechanics,
thatis,
withoutgoing
tosome
asymptotic
limit.Before
starting
thediscussion,
let us remark that this is the first paper in aplanned
series of works related to the above idea. Theaspects
that will beexplored
aregeneralizations
tohigher dimensions, perturbations
and further quantum mechanical
interpretations.
Aspointed
out belowthere are also some
problems presented
in the present text that will beinvestigated
further.Annales de /’Institut Henri Poincaré - Physique theorique
2. DEFINITION OF M-CURVES In the
Bargmann
case we are concerned with functionswhere a > 4 is some fixed number
and f (z)
is an entire function. In theBergman
case ourobjects
of interest are functionsagain
with some fixed (x>0 andnow f (z) analytic
in the upperhalf-plane
U={z=x+~: ~>0}.
It is often convenient to switch to the unit disk4 = f z : ~ z I 1 }
in which case we consider functionswith f (z) analytic
in A. IfS (z)
is of the form(3)
thenis of the form
(2)
andFor our purposes this relation tells us that the two cases are
equivalent
and that we are allowed to move
freely
between them.We shall be interested in curves of the
following
kind.DEFINITION. - A curve r is an M-curve = =0
along r,
where S isof the form (1), ( 2)
or(3).
We shall often find it convenient to say that r is an M-curve
of f when
r
by
this definition is an M-curve ofS and f are
relatedby ( 1 ), ( 2)
or( 3) .
It is
costumary
toimpose
somegrowth
restriction on thefunctions,
e. g.that functions of the form
(1), (2)
or(3) belong
to L2 or L 00 overthe domain in
question.
We find however such a restriction somewhat unnecessary since in all ourexamples
the functions S will be bounded.These
examples
include allpossible
M-curves in theBargmann
case, inwhich case there is
definitely
no need for such a limitation. Weconjecture
that a function of the form
(2)
or(3)
is bounded if it has an M-curve.3. ELEMENTARY PROPERTIES OF M-CURVES
We start
by listing
someelementary
facts about M-curves. Thisgives
useful information in the
Bergman
case but may to some extent seemVol. 51, n° 4-1989.
superfluous
in theBargmann
case in view of thesimple
characterizationwe shall
give
in the next section. We have included both cases here since it can be done athardly
any extra cost and since weby
thisemphasize
some
important
common characteristics.PROPOSITION 3. 1. -
Being
in either theBargmann
or theBergman
case, suppose S has an M-curve r. Then(i) I
SI
is constantalong
r;(ii) I
SI
attains local maximaalong
r;(iii)
S is determined up to a constantfactor by
any subsetof
rcontaining
an accumulation
point.
Proof - (i)
is obvious sinced I S I =
ax dx+dy=0 along
r. Weay
prove
(ii)
and(iii)
for theBargmann
case.By (i)
andanalyticity,
S #0along
r. If we writef (z)
=If (z) I
~~~ we haveby
theCauchy-Riemann equations
wherever
Along
r we thus haveIt will be shown later that an M-curve is differentiable
(actually analytic).
We can hence compute
with
an obvious modification if2014
does notexist).
Since~
~7
we have
by ( 9)
Annales de /’Institut Henri Poincaré - Physique ’ theorique "
along
r.Putting
this into(6)
and(7)
leads towhich in
conjunction
with(i)
showthat I S attains
local maximaalong
r.To prove
(iii),
let Zo be an accumulationpoint
of some subsetr
of r.Then there exists a
simply
connected domain Qcontaining
zo such that2014 In /= 20142014
isanalytic
inn, which
means that2014 In/is
the derivativedz
f (z)
dzof some function in Q.
By (8), ~
Inf
isgiven
atr.
Henceby
thedz
assumption
onr, r
determines2014 ln f in Q,
~ thus Inf
u p to an additivedz
constant in Q and
f
itself up to a constant factor. Thiscompletes
theproof
in theBargmann
case.The
proof
in theBergman
case iscompletely analogous
and isomitted. D
Remark. - Notice the content of
(iii). Simply
the set ofpoints
rdetermines S. Given r and the value of
f
at somepoint
zo of r we findby
the aboveproof that f can
be foundby
the formulaalong
r in theBargmann
case and(see below) along
r in thehalf-plane Bergman
case.Notice that
( 6)
and( 7) implies
In
I s I
is hencesuperharmonic
wherever it is defined and theonly
localminima of
I s I
are the zeros. Inparticular,
if an M-curve r is a closedpath
then S has at least one zero in theregion
boundedby
r.We shall need the
analogues
of(6)
and(7)
for theBergman
case. If weuse the
half-plane
model thenVol. 51, n° 4-1989~
This
gives
along
randso what was
just
said about theBargmann
case is also valid for theBergman
case.If we use the disk model we find
and thus
along
r. Let us stress theimportance
of(8), ( 19)
and(23).
PROPOSITION 3. 2. - A curve r is an M-curve
of
Sif
andonly if (i) (8)
holdsalong
r in theBargmann
case;(ii) ( 19)
holdsalong
r in thehalf-plane Bergman
case;(iii) (23)
holdsalong
r in the diskBergman
case.4. M-CURVES IN THE BARGMANN CASE
It turns out that
Proposition
3.2 enables us characterize allpossible
M-curves in the
Bargmann
case.THEOREM 4. 1. - In the
Bargmann
case, a curve is an M-curveif
andonly if
it is astraight
line or a circle with radiusn ,
n apositive integer.
2a
Proof. -
We letfbe
any entire functionhaving
an M-curve r.Writing
we have
Annales de /’Institut Henri Poincaré - Physique ’ theorique "
along
rby Proposition
3.2. Associated to F we introduce the mero-morphic
function F defined in the usual wayby
The function
(F F) (z) = F (F (z))
isanalytic
in the wholecomplex plane
exceptpossibly
at an infinite set ofsingular points.
Sincealong r, (FF) (z) = z
in its whole domain ofanalyticity.
It follows that thesingularities
of FF are removable and that(28)
is valid for all z in theextended
complex plane.
From(28)
we see that F is a one-to-one confor- mal map of the extendedcomplex plane
ontoitself,
and F must thus be aMobius transformation.
By
therequirement
F-1= F we hence havewith b,
c real.We
finally
check these candidates.First,
ifc=0, (29)
becomesThen
F (z) = z along
the linereal,
and anystraight
line canof course be
parametrized
in this way.Second,
if we can assumec =1 and write
( 29)
asClearly, 1
aI2
+ b mustequal
apositive integer
times 2 oc, and we see thatF(z)=z along I z - a I 2 = I a ( 2 + b.
0From the above
proof
we may now extract the entire functions corres-ponding
to the curves in the theorem.COROLLARY 4.2. - The
functions corresponding
to the curves inTheorem 4. 1 are the
following.
For the circles centered at athey
are, modulo constantfactors,
The
function
associated to astraight
lineparametrized by
z = at +ib/a (b real)
is, modulo a constantfactor,
Vol. 51, n° 4-1989.
5. M-CURVES IN THE BERGMAN CASE
In the
Bergman
case it is useful to notice thefollowing
invarianceproperty
of M-curves.PROPOSITION 5. 1. - In the
Bergman
case the setof
M-curves is invariantunder Mobius
self-maps. If
r is an M-curveof f (z)
then T-1(h)
is anM-curve
of (T’ (z))CX f (T z) for
any Mobiusself-map
T.Remark. - We remind the reader that a Mobius
self-map
T of theupper
half-plane
is a linear transformation of the formwith a, b,
c, dE R and AMobius self-map
T of the unit disk is a linear transformation of the formwith
Closely
related * to the groups of Mobiusself-maps
are theBergman
kernels which we use in the below
proof.
TheBergman
kernel of U isand the
Bergman
kernel of A isFor an introduction to such kernels and the associated
geometry,
see[1].
Proo, f: -
Both in thehalf-plane
and in the disk case our functions areof the form
for some constant C where
B (z, 0
denotes theBergman
kernel of the domain inquestion.
Theproposition
followsby
theelementary property
of theBergman
kernelvalid for all Mobius
self-maps
T of thehalf-plane
or the disk. 0Our first
example
of M-curves in theBergman
case isprovided by
thefollowing
theorem.THEOREM 5.2. - In the
Bergman
case, assume r is a closedpath
andan M-curve
off
and thatf
hasexactly
one zero zo in theregion
boundedby
Annales de l’Institut Henri Poincare - Physique theorique
r,
the zerobeing of
order n. Then r is the circleof hyperbolic
radius2 ln
( n + 1 + n
with hyperbolic
center zo.
Conversely,
there are no other circles(properly
contained in the domainin
question)
that are M-curves.Proof. -
We use the diskmodel,
and soby Proposition
5.1 we canassume without any loss of
generality
that zo = o. Thenzf’ (z)/f (z)
isanalytic
in theregion
S2 boundedby
r andby (23)
along
r. Thus theimaginary
part of theanalytic
functionvanishes on the
boundary
of Q andconsequently, by
the maximumprinciple,
it vanishesthroughout
Q. This means thatzf’ (z)/f (z)
is a cons-tant which
by assumption
mustequal
n.By (40) I z I2/(1- I z I2) = n/2 oc
along
r which proves the first part of the theorem.The second part is trivial. For if r was a circle of radius R centered at 0 we would have
by ( 23)
But
f or f to
beanalytic
we mustrequire
to be apositive integer.
DWe see that
during
the aboveproof
we have found the functionsf corresponding
to the circles in Theorem 5. 2.COROLLARY 5 . 3. -
If
Zo = 0 thefunctions
associated to the circles in Theorem 5. 2 are, modulo constantfactors, the powers
zn.It is now natural to ask if there are other closed
M-curves,
in other words if we can find M-curvesenclosing
several zeros of theircorrespond- ing
functions. The next theorem tells us that this is indeedpossible.
THEOREM 5. 4. - In the
Bergman
case we canfind
an M-curve r suchthat its
corresponding function f has
two zeros in the domainbounded by
r.We
give
theproof
in theappendix
since it may have anindependent
interest. It shows how to solve certain "free
boundary
valueproblems".
Let us also remark that for this
proof
we will make use of the last theoremof this paper.
We find the above existence result for the
Bergman
caseinteresting
butas it stands it is of course
unsatisfactory.
We intend toexplore
this casecarefully
in aforthcoming
paper: describe thequantization,
discuss the geometry of the curves andstudy
their quantum mechanicalsignificance.
We will then also consider the case of more than two zeros.
Vol. 51, n° 4-1989.
Let us now leave the closed M-curves and look at some
examples.
Straight
lines as M-curves in the halfplane Bergman
caseLet us first treat the case of horizontal lines Then
by ( 19)
along
the line andconsequently
Let next
r (a)
be thestraight
line x = ay, a E R. Thenby ( 19)
along
and thusNotice that
by Proposition
5.1 and Theorem 5. 2 we have now treated allpossible
circles in theBergman
case.To be able to
generate
moreexamples
wegive
arecipe
forchecking
ifa
given
curve is an M-curve or not.We consider now the
half-plane
model. DefineLet zo be any
point
of r such thatF’ (zo) ~ 0. By
the inverse function theorem there exists thus aneighbourhood
Q of Zo such that F is invertible inQ,
say with inverse function F-1analytic
inF (S2). Along corresponding
to someinterval 1/t2y1/t1,
we haveby ( 19)
The function
H(Q=F~(Q-~ -
isanalytic
in someneighbourhood
con-taining t2)
and for t~(t1,t2)
We have thus found that r
~ 03A9
admits theparametrization
where
Z
isanalytic
in ./’Institut Henri Poincaré - Physique theorique
r is thus an
analytic
Jordan arc and inparticular,
the tangent is well defined at eachpoint
of r. A necessary and sufficient condition forF’ (zo) ~ 0
is seen to be that the tangent at zo be non-horizontal. We seethat we have
proved
thefollowing.
THEOREM 5. 5. - A curve r is an M-curve in the
half-plane Bergman case if
andonly if the following
holds. ananalytic
Jordan arc andaround any
point
Zoof
r where thetangent is
non-horizontal r admits aparametrization of
theform (49).
The inversef unction of
i- ç 1
+ H(Q
can becontinued
meromorphically throughout U,
the result F(z) being independent of z0
andsatisfying (46) for analytic
in U.Notice that the last
requirement
tells us thatF (z)
canonly
havesimple poles,
each of residue apositive integer
times1 /i a.
The
assumption
about a non-horizontal tangent is of course not essen- tial. We could have assumed a non-vertical tangent and derived a similar result.Let us now check a few families of curves with the
help
of the abovetheorem.
The
half-plane Bergman
case,x=a/y,
We
apply
Theorem 5 . 5. We findH (~) = a ~,
and thus to find theright
inverse function we must
find ç
from theequation
that is
But this function cannot be continued
meromorphically throughout
Usince
z2 - 4 ai
will have a zero in U for all ~0. We conclude that thecurves x =
a/yare
not M-curves.The
half-plane Bergman
case,x = ay2,
a ~ 0 Our task is now to solveVol. 51, n° 4-1989.
with respect to
~, giving
Now 4az-1 never vanishes for
zeU,
thus(53)
can be continuedanalyti- cally throughout U,
and the curve is an M-curveby
Theorem 5. 5. Wesee that the square root must be in U and after some
computation
wefind from
(53)
thatBy
the samereasoning
as above we find that theparabolas
x = a~,
are not M-curves and that circles are the
only ellipses
that can beM-curves.
6. M-CURVES AND DIFFERENTIAL OPERATORS
We shall close
by
verybriefly pointing
out the announced link between M-curves and quantum mechanicaloperators (more
will be said about this in aforthcoming paper).
Proposition
3.2 tells us that to an M-curve r there exists aunique homogeneous
linear differentialequation
of order one whose solution isthe
function/corresponding
to r. The families of circles andstraight
linesabove define likewise differential
operators
and the individual M-curvesgive
theireigenfunctions
and theireigenvalues.
It is of course well-known that the Hamiltonian of the harmonic oscilla- tor takes the form z
2014
in theBargmann
case, which as we have seen isdz
the differential
operator corresponding
to circles centered at 0. TheseM-curves
give
hencedirectly
theeigenfunctions
and thespectrum
of this Hamiltonian.Using
the results in[4],
one may check thefollowing.
Thedifferential operator
corresponding
to circles with the same Euclidean center in thehalf-plane Bergman
caseis,
forappropriate
choices of ex, the Hamiltonian of the Coulombpotential problem
of thehydrogen
atom.Circles with the same
hyperbolic
center,again by using [4],
are found tocorrespond
to the Hamiltonian of the radial harmonic oscillator.Annales de /’Institut Henri Physique theorique
7. APPENDIX
Proof of Theorem 5. 4 For this
proof
we will use the disk model.We have confined ourselves to discuss
only
the case n = 2 but it is natural to start with anarbitrary
n > 1. Thatis,
we assume there exists aclosed M-curve r whose
corresponding
functionf
hasexactly n
zeros inthe domain Q bounded
by
r. We shall show how his leads us to an actual construction ofsuch
a curve for the case n = 2.By
Theorem 5. 2 and induction on n we may assume Q to besimply connected,
indeed a Jordan domainby
Theorem 5. 5.Also, by Proposition 5.1,
we may assumethat f has
zeros at distinctpoints 0 = wo,
wl, ... , with0,
wl, ...,By (23),
our first task is therefore to find ameromorphic function z F (z)
in Q withexactly
n -1poles,
allsimple
and located at thepoints
wl, ..., such thatalong
r.We use the Riemann
mapping
theorem to formulate this in the unitdisk A. To this
end,
let C be theunique
univalent function~’ (o) > 0
thatmaps Q
onto A. Then since D is a Jordandomain,
this transformation is one-to-one and continuous in the closure of Q( see [2],
p.
86).
We thus seek a functionH (z) meromorphic
in A withexactly
n -1
poles,
which are allsimple
and located at.... ,
~n -1= ~ (wn -1 ),
andsatisfying
along
the unit circle T.Let us now "move" all the
poles
to 0by considering
the functionfor which we have
Vol. 51, n° 4-1989.
along
T.G (z)
hasonly
onepole
inA,
thepole being
of order n-1 and located at 0. It has thus a Laurentexpansion
but
by ( 58)
for allk,
thusWe will now use
( 58)
and( 60)
tofind 1>-1.
We startby rewriting ( 58)
as
where
P(z)
is thepolynomial
By ( 58) P (z)
has no rootsalong
T. It is easy to see thatif ç
is a root ofP(z)
then1/~
is also a root ofP(z). Similarily,
the denominator of(61)
may be written
as
withQ (z)
apolynomial
with the sameproperty
as
P (z): If ç
is a root ofQ (z)
then1 /~
is also a root ofQ (z). Letting
z 1, ..., and ..., denote the roots of
P (z)
andQ (z),
respec-tively, lying
outside ofA,
we can thus write(disregarding
thepossibility
of
degree
along T, with Zn -1 ( ~
The function~ -1 (z)/z
isanalytic
andby assumption
zero-free in A. Since then isanalytic
in A and we know its realpart along T, ~-1 (z)
is determined apart from a constant factor of modulus one
by (63).
ThusLet us consider the case n = 2 and first
carefully
describe what restrictionswe have.
We must have a
corresponding
functionf analytic
in A. This meansthat the residues of must be
positive
andinteger-valued.
Wefind that
Annales de I’Institut Henri Poincaré - Physique " theorique "
and that
(putting ~ _ ~ 1 )
,where
We notice that
Next,
the necessary and sufficient condition for univalence is found to beFurthermore,
to insure that H(z)
bepositive along
T we mustrequire Finally
we findIt remains to be decided if the
polynomial
can have both its roots outside of A while at the same time the residues
( 65), ( 66)
and( 67)
are of theright
kind and( 69)
and( 70)
are bothsatisfied. -
We show that this is
possible
for convenient choices of the parameters.We go
"backwards", showing
how one may choose the parameters ao, al andç.
We let E
1, M,
N be threepositive
numbers. We putWe see that
by
this the residue in(65) equals
M and so M must be apositive integer
times 2 a. We notice also thatWriting Q (z) = al
z2 + + a i we findVol. 51, n° 4-1989.
We now fix some E 1 and some
positive integer M/2a.
We observethat
Zi=N/M8+0(l), fi=N/(M+1)8+0(1)
and thatCMj(M+l)
as N ~ oo. Thus for
sufficiently large
N both(69)
and(70)
will be satisfiedand the roots of R
(z)
will lie outside of A.Finally,
from(68)
and(74)
wesee that Res is real-valued and tends
continuously
toinfinity
as N grows. There is hence a discrete and unbounded set of values of N for which this residue ispositive
andinteger-valued.
Thiscompletes
the
proof.
ACKNOWLEDGEMENTS
I would like to thank Alex Grossmann for very
helpful
discussions and forexplaining
to me the quantum mechanical relevance of the above results. I am alsograteful
to Henrik H. Martens for valuable comments andsuggestions
and forpointing
out anobscurity
in anearly
version ofthis
manuscript.
Most of this work was done while I wasvisiting
Centrede
Physique Theorique, C.N. R. S., Luminy, Marseille,
whosehospitality
Iacknowledge.
[1] S. BERGMAN, The Kernel Function and Conformal Mapping, Amer. Math. Soc. Math.
Surveys V, New York, 1950.
[2] C. CARATHÉODORY, Conformal Representation, Camebridge University Press, 2nd ed., London, 1952.
[3] J. R. KLAUDER and B. S. SKAGERSTAM, Coherent States, World Scientific, Singapore,
1985.
[4] Th. PAUL, Affine Coherent States and the Radial Schrödinger Equation I: Radial Harmonic Oscillator and Hydrogen Atom, Preprint, Centre de Physique Théorique, C.N.R.S., Luminy, Marseille, 1984.
( Manuscript received April 14th, 1989.)
Annales de l’Institut Henri Physique théorique