On coefficient valuations of Eisenstein
polynomials
par MATTHIAS
KÜNZER
et EDUARD WIRSINGRÉSUMÉ. Soit p ~ 3 un nombre premier et soient n > m ~ 1.
Soit 03C0n la norme de
03B6pn -
1 sousCp-1.
AinsiZ(p)[03C0n]Z(p)
estune extension purement ramifiée d’anneaux de valuation discrète de
degré pn-1.
Lepolynôme
minimal de 03C0n surQ(03C0m)
est unpolynôme
de Eisenstein; nous donnons des bornes inférieures pour les 03C0m-valuations de ses coefficients.L’analogue
dans le cas d’uncorps de
fonctions,
comme introduit par Carlitz etHayes,
estetudié de même.
ABSTRACT. Let p ~ 3 be a prime, let n > m ~ 1. Let 03C0n be the norm of
03B6pn
- 1 underCp-1,
so thatZ(p)[03C0n]|Z(p)
is apurely
ramified extension of discrete valuation rings of
degree pn-1.
Theminimal
polynomial
of 03C0n overQ(03C0m)
is an Eisensteinpolynomial;
we give lower bounds for its coefficient valuations at 03C0m. The function field
analogue,
as introducedby
Carlitz andHayes,
isstudied as well.
CONTENTS
0. Introduction 802
0.1. Problem and methods 802
0.2. Results 803
0.3. Notations and conventions 805
1. A
polynomial
lemma 8062. Consecutive
purely
ramified extensions 8062.1.
Setup
8062.2. Characteristic 0 807
2.3. As an illustration:
cyclotomic polynomials
8082.4.
Characteristic p
8093. Towers of
purely
ramified extensions 8104. Galois descent of a
divisibility
8115.
Cyclotomic
number fields 8125.1. Coefficient valuation bounds 812
lVlanuscrit requ le ler f6vrier 2004.
5.2. A different
proof
of(5.3. i, i’)
and some exact valuations 8135.3. Some traces 814
5.4. An upper bound for
N(p)
8176.
Cyclotomic
functionfields,
after Carlitz andHayes
8186.1. Notation and basic facts 818
6.2. Coefficient valuation bounds 820
6.3. Some exact valuations 822
6.4. A
simple
case 822References 823
0. Introduction
0.1. Problem and methods. Consider a
primitive
root ofunity (pn
overQ,
where p is aprime
and n > 2. One hasCpn-l
i X To isolate the p-part of thisextension,
let 7rn be the norm of underCp_ 1;
thatis,
theproduct
of the Galoisconjugates (~pn -1 ) ~,
where a runs over the
subgroup Cp_ 1.
Then/ J- ’B
We ask for the minimal
polynomial !11fn,Q(X) == Z (X ~
of over
Q. By construction,
it is an Eisensteinpolynomial;
thatis,
1
for j
E1 ~ ,
andvp(ao)
=1,
where vp denotes the valuation at p.More is true,
though.
Our basicobjective
is togive
lower boundsbigger
than 1 for these
p-values vp(aj), except,
of course, forvp (ao) .
As abyprod-
uct of our method of
proof,
we shall also obtain congruences between certain coefficients forvarying
n.A consideration of the trace
yields
additional informationon the second coefficient of
!11fn,Q(X). By
the congruencesjust mentioned,
this also
gives
additional information for certain coefficients of the minimalpolynomials
with l > n; these coefficients nolonger
appear as traces.Finally,
acomparison
with the different idealthen
yields
some exact coefhcientvaluations,
notjust
lower bounds.Actually,
we consider theanalogous question
for the coefficients of theslightly
moregeneral
relative minimalpolynomial
where n >m >
1,
which can be treatedusing essentially
the samearguments.
Note that 7r1 = p.Except
for the traceconsiderations,
the wholeinvestigation
carries overmutatis mutandis to the case of
cyclotomic
function fieldextensions,
asintroduced
by
CARLITZ[1]
and HAYES[5].
As an
application,
we mention the Wedderburnembedding
of the twistedgroup
ring (with
trivial2-cocycle)
to which we may reduce the
problem
ofcalculating Z(p) ~~pn ~ ~ l (Cpn-l
XCp_ 1 ) by
means of Nebedecomposition.
Theimage
is thecompanion
matrixof
!17fn,Q(X).
To describe theimage
of the wholering,
we may
replace
this matrix modulo a certain ideal. To do so, we need toknow the valuations of its
entries,
i.e. of the coefficients of!17fn,Q(X),
or atleast a lower bound for them. So
far,
this could be carriedthrough only
forn=2
~10~.
In this
article, however,
we restrict our attention to the minimalpolyno-
mial itself.
0.2. Results.
0.2.1. The number
field
case. Letp >
3 be aprime,
and let(pn
denote aprimitive pnth
root ofunity
overQ
in such a way that= ~pn
for alln > l. Put
so
Q] = P’. Letting
we have =
Q(7,,).
Inparticular,
fix m and write
Theorem
(5.3, 5.5, 5.8).
Assertion
(iv) requires
thecomputation
of a trace, which can be refor- mulated in terms of sums of(p - I )th
roots ofunity
inQp (5.6). Essentially,
one has to count the number of subsets of C
Qp
of agiven cardinality
whose sum is of a
given
valuation at p. We have not been able to go muchbeyond
thisreformulation,
and this seems to be aproblem
in its ownright
- see e.g.
(5.9).
To prove
(i, i’, ii, ii’),
weproceed by
induction. Assertions(i, i’)
alsoresult from the different
Moreover, (ii) yields (iii) by
anargument using
the different(in
thefunction field case
below,
we will nolonger
be able to use the different for the assertionanalogous
to(i, i’),
and we will have to resort toinduction).
Suppose
m = 1. Let us call anindex j
E~1, p2 - 1] exact,
if eitherj p2(p-2)-1) and piJr m exactly divides j ai,j, or j 2: pi (p - 2) / (p - 1)
and
pi exactly
divides If i = 1 and e.g. p E{3, 19, 29, 41},
then allindices j
E[I, p - 1]
are exact. If i >2,
we propose to ask whether the number of non-exactindices j asymptotically equals
as p - oo.0.2.2. The
function field
case. Letp >
3 be aprime, p >
1 and r =pP.
We write Z =
Fr~Y~ and Q
=Fr(Y).
We want tostudy
a function fieldanalogue over Q
of the number field extensionCa (~pn ) ~ (a.
Since 1 is theonly pnth
root ofunity
in analgebraic
closureQ,
we have toproceed differently, following
CARLITZ[1]
and HAYES[5].
First ofall,
the poweroperation
ofp~
onQ
becomesreplaced by
a moduleoperation
of¡n
onQ,
wheref
E Zis an irreducible
polynomial.
The group ofpnth
roots ofunity
’
becomes
replaced by
the annihilator submoduleInstead of
choosing
aprimitive pnth
root ofunity (pn,
i.e. a Z-linear gen-erator of that abelian group, we choose a Z-linear
generator On
of thisZ-submodule. A bit more
precisely speaking,
theelement 0,, E ~ plays
therole of
dn
:=~ 2013
1 EQ.
Now is the function fieldanalogue
ofSee also
[3,
sec.2].
To state the
result,
letf (Y)
be a monic irreduciblepolynomial
andwrite q =
r deg f
. LetçY
:=Y~ + çT
define the Z-linear Carlitz module structure on analgebraic
closureQ,
and choose a Z-Iineargenerator On
ofann.fn Q
in such a way thatBn+1 - On
forall n >
1. We write = soTheorem
(6.6, 6.7, 6.9) .
. I., -
A
comparison
of the assertions(iv)
in the number field case and in the function field case indicatespossible generalizations
- we do not know whathappens
for for 2 in the number field case; moreover, we do not know whathappens
forf #
Y in the function field case.0.3. Notations and conventions.
(o)
Within achapter,
thelemmata, propositions
etc. are numbered con-secutively.
(i)
Fora, b
EZ,
we denoteby [a, b]
:={c
E Z : a cb~
the intervalin Z.
(ii)
For m E Z -,f 0}
and aprime
p, we denoteby m[p]
:=p’p(’)
thep-part of m, where vp denotes the valuation of an
integer
at p.(iii)
If R is a discrete valuationring
with maximal idealgenerated by
r,we write
vr(:r)
for the valuation of x E R --,~0~
at r, i.e.x/rvr(x)
is aunit in R. In
addition,
:= +oo.(iv)
Given an element xalgebraic
over a fieldK,
we denoteby Px,K (X)
EK[X]
the minimalpolynomial
of x over K.(v)
Given a commutativering
A and an element a EA,
we sometimesdenote the
quotient by A/a
:=A/aA - mainly
if Aplays
the role ofa base
ring.
Forb,
c EA,
we write b ma c if b - c E aA.(vi)
For an assertionX,
whichmight
be true or not, we let{X} equal
1if X is true, and
equal
0 if X is false.Throughout,
letp >
3 be aprime. I
1. A
polynomial
lemmaWe consider the
polynomial ring Z[X, Y].
Lemma 1.1. We have I
where the second
inequality
followsfrom j
> 2 if =0,
and fromCorollary
1.2.Corollary
1.3.2. Consecutive
purely
ramified extensions2.1.
Setup.
LetT~S
and81R
be finite andpurely
ramified extensionsof discrete valuation
rings,
of residue characteristicchar R/rR
= p. The maximal ideals ofR,
S and T aregenerated by
r ER, s
E S and t ET,
and the fields of fractions are denoted
by K = frac R,
L = frac S andM =
fracT, respectively.
Denote m =[M : L]
and 1 =[L : K~.
We mayand will assume s = and r =
We have S =
R[s]
withand T =
R[t]
with.
Cf.
[9, I.§7,
prop.18].
The situation can be summarized in thediagram
Note that
rip,
and that for z EM,
we havevt (z)
= =mZ.vr(z).
2.2. Characteristic 0. In this
section,
we assume char K = 0. Inpartic- ular, Z(p)
C R.Assumption
2.1.Suppose given x, y E T
and k E[1, Z
-1]
such thatLemma 2.2. Given
(2.1),
we have c ~I !-ls,K(tm) . Proof.
We maydecompose
Now since tm = s + zy for some z E T
by (2.1.i~,
we haveThe
following proposition
will serve as inductivestep
in(3.2).
Proposition
2.3. Given andProof.
From(2.2)
we takeSince the summands have
pairwise
different valuationsat t,
we obtain2.3. As an illustration:
cyclotomic polynomials.
For n >1,
we chooseprimitive
roots ofunity (p.
overQ
in such a manner that(P,+l - (pn.
We abbreviatedn = ~ 2013
1.We shall show
by
induction on n thatwriting
This
being
true for n = 1 since =( (X -~ 1 )p -1 ) /X ,
we assumeit to be true for n - 1 and shall show it for n, where n > 2. We
apply
theresult of the
previous
section to R =Z~p~,
r = -p, S = s =and T = = In
particular,
we have 1 =pn-2(p - 1)
andfinally,
we havelfpn (X
+1).
We may x =
pn-2
and k =pn-2 (p - 2)
+ 1 in(2.1).
Hence c =
By (2.3),
we obtain thatdivides
lf j
-p 0 and that it dividesdn,j if j ~p
0. Since thecoefficients in
question
are inR,
we may draw thefollowing
conclusion.By induction,
this establishes the claim.Using (1.4),
assertion(I)
also follows from the moreprecise
relationfor n >
2,
which we shall show now. Infact, by ( 1.4)
we have Iand the result follows
by
divisionby
the monicpolynomial
Finally,
we remark thatwriting
we can
equivalently
reformulate(II)
to2.4. Characteristic p. In this
section,
we assume char Is~ = p.Assumption
2.4.Suppose given
and 1~ E(1, l - l~
such thatLemma 2.5. Given
(2.4),
we have c ~Proof.
We maydecompose
Now since i
Proposition
2.6. Given(2.4),
we haveThis follows
using (2.5),
cf.(2.3).
3. Towers of
purely
ramified extensionsSuppose given
a chainof finite
purely
ramified extensions of discrete valuationsrings,
withmaximal ideal
generated by
ri ERï,
of residue characteristic charRi /rj Ri
=p, with field of fractions
Ki
=frac Ri,
and ofdegree Ki]
=p’ =
q for i >0,
where ~ ~ 1 is aninteger stipulated
to beindependent
of i. Wemay and will suppose that = ri for i ~ 0. We write
For j > 1,
we denotevq(j)
:=max{ 0152
E mqm01.
Thatis, vq(j)
isthe
largest integer
below Weabbreviate g
:=(q - 2)/(q - I).
Assumption
3.1.Suppose given f
ERo
such that ri_l for alli > 0. If char
Ko
=0,
then suppose pI f q.
If charKo
= p, then supposeH)!/.
Proposition
3.2. Assume(3.1).
Proof.
Consider the casecharKo
= 0. To prove(i, i’),
weperform
aninduction on
i,
the assertionbeing
true for i = 1by (3.1 ) .
So supposegiven
i > 2 and the assertion to be true for i - l. Toapply (2.3),
we letR =
Ro,
r = ro, S =Ri_1,
s = ri_1, T =Ri
and t = ri.Furthermore,
welet y =
rq 1 f, ~ _ Ji-1
and k =qi-1 - (qi-1 - 1)/(q - 1),
so that(2.1)
issatisfied
by (3.1)
andby
the inductiveassumption.
We have c =Consider j
E~1, q2 - 1]. If j ©q 0,
then(2.3) gives
whence
f 2
divides ai,j;f ’
Zstrictly
divides ai,jif j
since0(~-1)-~=1/(9-!)!.
If j
mq0,
then(2.3) gives
whence
f
i divides ai,j - ai-1,j/q;strictly, if j q2g. By induction,
divides ai-1,j/q’
.
strictly, q2 1 g .
But ai,j, and therefore divides also ai,j;strictly, if j q’g.
This proves(i, i’ ) .
The case
(3
= 1 of(ii, ii’)
has been established in the course of theproof
of
(i, i’) .
Thegeneral
case followsby
induction.Consider the case
char Ko
= p. To prove(i, i’),
weperform
an inductionon
i,
the assertionbeing
true for i = 1by (3.1).
So supposegiven
i > 2 and the assertion to be true for z - l. Toapply (2.6),
we let R =Ro, r
= ro,S = ri _ 1, T =
Ri
and t = ri .Furthermore,
we let g =x and k =
qi-1- (qi-1-1 ) ~ (q _ 1 ),
so that(2.4)
is satisfiedby (3.1 )
and
by
the inductiveassumption.
Infact,
= dividesfi-1-Vq(j)
bothif j ~p
0 andif j
-p0;
in the latter case we make use of theinequality p‘~-1 (p -1 ) > a ~-1
for 0: ~1,
which needsp >
3. We obtainc - .
Using (2.6)
instead of(2.3),
we may continue as in the former case toprove
(i, i’), and,
in the course of thisproof,
also(ii, ii’).
D4. Galois descent of a
divisibility
Let
be a commutative
diagram
offinite, purely
ramified extensions of discrete valuationrings.
Let E Tgenerate
therespective
maximal ideals. Let L =
frac S,
M =frac T, L
=frac S and
M = frac T denote therespective
fields of fractions. We assume the extensionsMIL
and
LIL
to belinearly disjoint
and M to be thecomposite
of M and L.Thus m :=
[M : L] = [M : L]
and[L : L] = [M : M].
We assumeilL
to begalois
andidentify
G :=Gal(LIL)
=Gal(MIM)
via restriction. We may and will assume that s =NLIL(a),
and that t =Lemma 4.1. In
T ,
the element 1 -im /s
divides 1 -Proof. Let d
= 1 -P’19,
so that =s(1 - d).
We conclude5.
Cyclotomic
number fields5.1. Coefficient valuation bounds. For n >
1,
we let(pn
be aprimitive pnth
root ofunity
overQ.
We make choices in such a manner thatǧn
=p
- . -- - - .. pn -
The minimal
polynomial (X
+1 )p -
1 shows thathence also Note that 7ri = p and
Ei
=Q.
Let 0 be the
integral
closure ofZ(p)
inEn .
Since = 7r1 = p,we have
Z(p)/pZ(p) 2013~ O/7rnO_.
Inparticular,
the ideal in 0 isprime.
U*. Thus 0 is a discrete valuation
ring, purely
ramified ofdegree pn-l
overZ(p),
and so 0 =[9, 1.§7,
prop.18].
Inparticular, En
=Q(7rn) .
Remark 5.1. The
subring
ofQ (7rn) , however,
is notintegrally
closedin
general.
Forexample, if p = 5
and n =2,
then =X5 - 20X4
+100X3 - 125X2
+ 50X - 5 has discriminant5g ~ 76,
which does not divide the discriminant of(D52 (X),
which is535.
Lemma 5.2. We have
Now suppose
given
m ~ 1. Toapply (3.2),
we letf
= q = p,Ri
=Z(p) [7r.+il and r2 =
7rim+1 for i > 0. Wekeep
the notationTheorem 5.3.
Assumption (3.1)
is fulfilledby
virtue of(5.2),
whence the assertions followby (3.2).
Example
5.4. For p =5,
m = 1 and i =2,
we haveNow
v5 (a~,22)
=6 -I-
5 =v5 (a4,5.22),
so the valuations of the coefficients considered in(5.3.ii)
differ ingeneral. This, however,
does not contradictthe assertion a;3,22 =54 a4, 5~22 from loc. cit.
5.2. A different
proof
of(5.3. i, if)
and some exact valuations. Let m ~ 1 and i > 0. Wedenote Ri -
ri = ’7rm+i,Ki
=frac Ri, Ri
= andri
=Denoting by 0
therespective
different[9, III.g3],
we =( rp- 2 ) [9, III.§3,
prop.13],
whence
/ I
cf.
[9, III.§3,
cor.2]. Therefore,
divides forj
E~1, pi - 1~,
and(5.3. i, i’)
follow.Moreover,
sinceonly for j
=p2 - (pi - 1)/(p - 1)
the valuations at ri ofPir?i-1-(pi_1)/(P-1)
andJ’a’ .r1-1
arecongruent
modulop2,
we concludeby
(*)
thatthey
areequal,
i.e. thatp2 exactly
dividesCorollary
5.5. The elementexactly
dividesfor Proof.
This followsby (5.3.ii)
from what we havejust
said. DE.g.
in(5.4), 51 exactly
divides a2,25-5 = a2,20, and52 exactly
dividesa2,25-s-1 = a2, 19.
5.3. Some traces. Let denote the group of
(p - l)st
roots ofunity
in
Qp.
We choose aprimitive (p - l)st
root ofunity
E and maythus view C
Qp
as a subfield. Note that[Q((p-1) : Q]
=p(p - 1),
where cp denotes Euler’s function. The restriction of the valuation vp at p on
Qp
to(a(~p),
is aprolongation
of the valuation vp onQ
to(there
arecp(p - 1)
suchprolongations).
Proposition
5.6. For n >1,
we havewhere
We have so =
0,
and 5~ E Zfor n >
0. The sequence becomesstationary
at someminimally
chosenNo(p).
We haveAn upper estimate for
N(p),
hence forNo(p),
isgiven
in(5.13).
Proof. For j
E~l, p - 1]
thep-adic
limitsexist since
jPn-l
= pnjP" by (1.3). They
are distinct since~(j) -p j, and,
thus,
form the group =~~(j) ~ j
E(1,p- 1~~. Using
the formulaand the fact that we obtain
whence
Now so = 0 E Z
by
the binomial formula.Therefore, by induction,
weconclude from E Z that E Z. Since
(p -
EZ,
too, weobtain sn
E Z.As soon as n >
N(p),
the conditions+00 on H C become
equivalent,
and we obtainwhich is
independent
of n. ThusLemma 5.7. We have s, = 1. In
particular,
Proof.
SinceTrQIQ(p) -
p, and since so =0,
we have sl = 1by (5.6).
The congruence for followsagain by (5.6).
DCorollary
5.8. We have2.
Proof. By
dint of(5.7),
this ensues from(5.3. i’, ii).
DExample
5.9. The last n for which we list snequals N(p),
except if there is aquestion
mark in the next column. The table was calculatedusing
Pascal
(p 53)
andMagma (p > 59).
In the lastcolumn,
we list the upperbound for
N(p)
calculated below(5.13).
11 1 1 1 1 1
So for
example if p
=31,
then =271~313-315-312,
whereas=
259 ~ 317 - 259 ~ 31~. Moreover, No(31)
=N(31)
= 4 6.Remark 5.10.
Vanishing (resp. vanishing
modulo aprime)
of sums ofroots of
unity
has been studiedextensively.
See e.g.[2], [6],
where alsofurther references may be found.
Remark 5.11. Neither do we know
whether sn
> 0 nor whether 0always
hold.Moreover,
we do not know aprime
p for whichNo(p) N(p).
Remark 5.12. We calculated some further traces
appearing
in(5.3); using Maple
andMagma.
For For For For
where
5.4. An upper bound for
N(p).
We view as a subfield ofQp,
and now, in
addition,
as a subfield of C. Sincecomplex conjugation
com-mutes with the
operation
ofGal(Q((p-1)IQ),
we haveand therefore
N(p) tp(p - 1).
We shall ameliorate this boundby
alogarithmic
term.Proposition
5.13. We haveProof.
It suffices to show that We willactually
show that
from which this
inequality
followsusing x3/6
andp >
5.Choose H C such that
JE(H)L ]
is maximal. Since p - 1 is even, the(p - I )st
roots ofunity
fall intopairs (q, 20137~).
The summands ofE(H)
contain
exactly
one element of each suchpair,
since+ 2 +
r12
=21(H)12
+2 shows that at least one of theinequalities +r1 ]
andJE(H) - ]
fails.By maximality, replacing
a summand qby
-q inE(H)
does not increasethe value of
I E(H)1,
whenceand thus
Therefore,
the(p - 1)/2
summands ofE(H)
lie in onehalf-plane,
whencethe value of . D
6.
Cyclotomic
functionfields,
after Carlitz andHayes
6.1. Notation and basic facts.
We shall
give
a brief review whilefixing
notation.Let
p >
1 and r :=pP.
Write Z :=Fr ~Y~ and Q
:=Fr (Y),
where Y isan
independent
variable. We fix analgebraic closure Q
ofQ.
The Carlitz rrtodule structureon Q
is definedby
theFr-algebra homomorphism given
on the
generator
Y asWe write the module
product of ~ E ~
with e E Z asÇe.
For each e EZ,
there exists a
unique polynomial P,(X) C Z[X]
that satisfies forall
EQ.
Infact, Pl (X )
=X,
= YX +Xr,
and+ for i > 1. For a
general
e EZ,
thepolynomial Pe(Y)
is
given by
theaccording
linear combination of these.Note that
Pe(0)
=0,
and that = e, whencePe (X )
isseparable,
i.e. it
decomposes
as aproduct
of distinct linear factors in~~X~.
Letbe the annihilator submodule.
Separability
ofPe (X )
shows that#~e
=deg
=rdege.
Given aQ-linear automorphism
Q ofQ,
we have(~e) 0’
=pe(~)a - Pe(~a) - (~)~.
Inparticular, Àe
is stable under or.Therefore,
Q(Àe)
is a Galois extension ofQ.
Since
#anneÀe
=#Aj
=rdeg e
for ee,
we haveZ/e
as Z-modules.It is not
possible, however,
todistinguish
aparticular isomorphism.
We shall restrict ourselves to
prime
powers now. We fix a monic irre- duciblepolynomial f
= andwrite q
:=rdeg f .
For n >1,
we letOn
be a Z-lineargenerator
We make our choices in such a manner that== On for n >
1. Note that = since the elements ofare
polynomial expressions
in0~.
Suppose given
tworoots ~, ~ G Q
ofi.e.
~, ~ Since ~
is a Z-lineargenerator of Àfn,
there isan e E 2 such
that ~ = Çe.
Sinceçe/ç
= is amultiple of ~
inReversing
theargument,
we seethat ~
is in fact aunit
multiple of ~
inZ [0,,].
Lemma 6.1. The is irreducible.
Fi (X) in
its distinct monic irreducible factorsFi(X)
EZ [X] .
Oneof the constant terms, say
Fj (0),
is thus a unitmultiple
off
inZ,
whilethe other constant terms are units.
Thus, being conjugate
under the Galoisaction,
all rootsof Fj (X)
in are non-units in and theremaining
roots of are units. But all roots
of W¡n(X)
are unitmultiples
ofeach other. We conclude =
Fj (X)
is irreducible. DBy (6.1),
is the minimalpolynomial
of9n
overQ.
Inparticular, [Q(O.) : Q]
=qn-1(q - 1),
and soIn
particular, Z(f )
is a discrete valuationring
with maximal ideal gen- eratedby On, purely
ramified of indexqn-1(q - 1)
over~~ f),
cf.[9, 1.§7,
prop.
18].
There is a groupisomorphism
well defined since
Bn
is a root too;injective
sinceOn generates
a fn
over.~;
andsurjective by cardinality.
Note that the Galois
operation corresponding
to e Ecoincides with the module
operation
of e on the elementOn,
but not every- where. Forinstance,
iff # Y,
then the Galoisoperation corresponding
toY sends 1 to
1,
whereas the moduleoperation
of Y sends 1 to Y + 1.The discriminant of over Z is
given by
Lemma 6.2. The
ring Z[On]
is theintegral
closureof Z
inQ(On).
Proof.
Let e E Z be a monic irreduciblepolynomial
different fromf .
WriteC~o
~_Z(e)
and let C~ be theintegral
closure ofC~o
inQ( On).
LetThen
C7~
C (7 C(~+
Cot.
But00
=ot,
since theZ-linear
determi-nant of this
embedding
isgiven by
the discriminant which is aunit in El
We resume.
Proposition
6.3([1],[5],
cf.[3,
p.1151).
The extensionQ(O,)IQ
is ga-lois
of degree [Q(On) : Q] = (q - l)qn-l,
with Galois groupisomorphic
to(~/f’n)*.
Theintegral
closureof Z
inQ(On)
isgiven by
We haveIn
particular, On
is aprime
elementof 3 [On],
andthe extension
[On] of
discrete valuationsrings
ispurely ramified.
6.2. Coefficient valuation bounds. Denote ’
-- - . _ -~ -- 1 -
The minimal
polynomial
=together
with thefact that X divides shows that = whence
= Note that =
0? = W/(0) = f.
The extension is a discrete valuation
ring
with maximal idealgenerated by purely
ramified of indexqn-1
over~(n.
Inparticular,
=
Example
6.4. Let r = 3 andf (Y) = y2
+1,
so q = 9. AMagma
calculation shows that
With
regard
to section6.4,
we remark that~72 7~ =L
Lemma 6.5. We have
n
n / wn-1for n > 2.
Proof.
We claim that8n
Infact,
thenon-leading
coefficients of the Eisensteinpolynomial BI!f(X)
are divisibleby f ,
so that the congruencefollows
by 9n_ 1-8n
= =Letting f
=and
(~~~) = (4.1)
shows that 1 - divides1 -
Therefore, I Wn-1 -
DNow suppose
given
1. Toapply (3.2),
we letR.L
= andri = for i ~ 0. We continue to denote
Theorem 6.6.
-. __ ., .
Assumption (3.1)
is fulfilledby
virtue of(6.5),
whence the assertions followby (3.2).
6.3. Some exact valuations.
an
empty
assertionif j
-p 0. Thus(6.6. i, i’)
do not followentirely.
However,
sinceonly for j
=qi - (qi -1)~(q -1)
the valuations at ri of and arecongruent
moduloq2,
we concludeby
i ’t,J i ,
(**)
thatthey
areequal,
i.e. thatf exactly
dividesCorollary
6.7. The elementexactly
dividesProof.
This followsby (6.6.ii)
from what we havejust
said. D6.4. A
simple
case.Suppose
thatf (Y)
= Y and m > 1. Note thatLemma 6.8. We have
, -rrB
Proof. Using
the minimalpolynomial
Corollary
6.9. Letm, i >
1. We haveProof.
This follows from(6.8) using (6.6.ii).
DRemark 6.10. The assertion of
(6.8)
also holdsif p = 2.
Conjecture
6.11. Let 1. We use the notation of(#) above,
nowin the case
f (Y)
= Y.For j
E[1, qi],
we writeq’ - j
=dkqk with
[0, q - 1].
Consider thefollowing
conditions.(i)
There exists k E[0,
i -2]
such thatd~.
(ii)
There exists 1~ E~0, i
-2]
such thatvp(dk+1)
>vp(dk)-
If
(i)
or(ii) holds,
then = 0. If neither(i)
nor(ii) holds,
thenRemark 6.12. We shall compare
(6.7)
with(6.11). If j - q2 - (qi _ 1)
for some0
E[0, i - 1], then q2 - j
=qi-1
-F- ... +qf3.
Hence -
0,
and soaccording
to(6.11), VWm(ai,j)
shouldequal qm-1(i - 0),
which is in fact confirmedby (6.7).
References
[1] L. CARLITZ, A class of polynomials. Trans. Am. Math. Soc. 43 (2) (1938), 167-182.
[2] R. DVORNICICH. U. ZANNIER. Sums of roots of unity vanishing modulo a prime. Arch. Math.
79 (2002), 104-108.
[3] D. Goss, The arithmetic of function fields. II. The "cyclotomic" theory. J. Alg. 81 (1) (1983), 107-149.
[4] D. Goss. Basic structures of function field arithmetic. Springer, 1996.
[5] D. R. HAYES. Explicit class field theory for rational function fields. Trans. Am. Math. Soc.
189 (2) (1974), 77-91.
[6] T. Y. LAM. K. H. LEUNG. On Vanishing Sums of Roots of Unity. J. Alg. 224 (2000), 91-109.
[7] J. NEUKIRCH, Algebraische Zahlentheorie. Springer, 1992.
[8] M. ROSEN. Number Theory in Function Fields. Springer GTM 210, 2000.
[9] J. P. SERRE, Corps Locaux. Hermann, 1968.
[10] H. WEBER. M. KÜNZER. Some additive galois cohomology rings. Arxiv math.NT/0102048,
to appear in Comm. Alg., 2004.
Matthias KIJNZER Universitat Ulm Abt. Reine Mathematik D-89069 Ulm, Allemagne
E-mail : kuenzerCdmathemat ik . uni-ulm . de
Eduard VVIRSING Universitat Ulm Fak. f. Mathematik D-89069 Ulm, Allemagne
E-mail : ewirs ing@mathemat ik . uni -ulm . de