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www.elsevier.com/locate/anihpc

An extension theorem to rough paths

Terry Lyons, Nicolas Victoir

Mathematical Institute, 24–29 St Giles’, Oxford, OX1 3LB, UK

Received 22 April 2004; received in revised form 6 May 2006; accepted 12 July 2006 Available online 22 December 2006

Abstract

We show that any continuous path of finitep-variation can be lifted to a geometricq-rough path, whereq > p.

©2006 Elsevier Masson SAS. All rights reserved.

Résumé

Nous montrons que tout chemin continu dep-variation finie peut être relevé en un « geometricq-rough path », pourq > p.

©2006 Elsevier Masson SAS. All rights reserved.

Keywords:Differential equations; Rough paths

1. Introduction

Let

x:[0,1] →Rn, t

x1(t ), . . . , xn(t )

be a continuous function of bounded variation, andV1, . . . , Vnsome smooth functions fromRdinto itself. Then there exists a (unique) solution to the control differential equation

dy(t )=n

i=1Vi(y(t ))dxi(t ),

y(0)=y0. (1)

But without the smoothness assumption onx (which is for example almost surely not satisfied by Brownian motion), classical theory fails to give a meaning to the above equation. Rough paths theory [12,13,11] gives a meaning to Eq. (1), wheneverxis a continuous path of finitep-variation lifted to a “geometricp-rough path”.

To understand what a geometricp-rough path is, consider a smooth pathx:[0,1] →Rn, and define S(x)0,t=1+

0<s1<t

dxs1+

s<si1<···<si[p]<t

dxsi1 ⊗ · · · ⊗dxsi[p].

* Corresponding author.

E-mail address:[email protected] (N. Victoir).

0294-1449/$ – see front matter ©2006 Elsevier Masson SAS. All rights reserved.

doi:10.1016/j.anihpc.2006.07.004

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tS(x)0,ttakes its values inG[p](Rn), the free nilpotent group of step[p]overRn, thought of a manifold immersed in the tensor algebra[p]

k=0(Rn)k [12,14]. For a givenp1, the set of geometric rough paths is the closure under a givenp-variation metric of the set{S(x), xsmooth} (see definition (12)). A weak geometricp-rough path is a G[p](Rn)-valued path of finitep-variation, where thep-variation is computed using a homogeneous metric associated to the group. The distinction between these two spaces was glossed over in the paper [12] by the first name author. It is obvious that a geometricp-rough path is a weak geometricp-rough path and that a weak geometricp-rough path is a geometricq-rough path for anyq > p. There are examples of weak geometricp-rough paths that are not geometric p-rough paths [6]. The difference between weak geometric rough paths and geometric rough paths is a bit like the difference between Lipschitz functions andC1functions.

Ifxis a (weak) geometric p-rough path, xprojects onto a path x with values in Rn. The solution to Eq. (1) is uniquely defined for anyx, and the solution is also a (weak) geometricp rough pathy. Moreover, the mapxy is continuous in an appropriate topology. In the classical setting wherex is smooth, p=1. There is a functional relationship between x and the solution of the differential equation (1). Forp2, there will be infinitely many choices forx projecting ontox. The corresponding solution yand its projection y will in general depend on this choice.

There is often a “canonical” choice for the liftxofx (for example, ifx is smooth,S(x)is a canonical lift ofx to a geometricp-rough path, for anyp1). “Canonical” lifts have been constructed for Brownian motion [13,10], fractional Brownian motion with Hurst parameter greater than 1/4 [3,13], free Brownian motion [2,18], and a large class of random paths on fractals [1,8].

1.1. Our goal

Consider the following natural question: can every continuous path of finitep-variation inV (a Banach space) be lifted to a weak geometricp-rough path (aG[p](V )-valued path of finitep-variation)? We will see, that provided thatp is not an integer number greater than or equal to 2, the answer is affirmative. This is optimal, as a counter example forp=2 was provided in [18]. In particular, any path of finitep-variation inV can be lifted to a geometric q-rough path, for anyq > p. The theorem we prove is actually stronger.

Theorem 1.We fixp∈ [1,+∞). LetV be a Banach space andKa closed normal subgroup ofG([p])(V ). Ifxis a (G([p])(V )/K, · G([p])(V )/K)continuous path of finitep-variation, withp /∈N\{0,1}, then one can liftx to a weak geometricp-rough path.

Consider a pathx of finite p-variation with values in(G([p])(V )/K, · G([p])(V )/K), where K is as above. x projects to aRn-valued path, and so one can consider again the differential equation (1). This one only makes sense once we liftx to a geometricq-rough pathx, forq > p. The solution depends in general on the choice of the liftx.

We will identify conditions on the Lie algebra generated by the vector fields(Vi)1inin (1) so that the projectiony of the rough path solutionyof Eq. (1) does not depend on the lift ofx. In general,yandywill depend on the liftx ofx.

To help the comprehension of the paper, we start by presenting the main theorem forp(2,3)andV =R2, where no algebra is necessary and result are quite intuitive.

2. A simple case

We start with a non-surprising technical lemma, whose proof is inspired from the Kolmogorov–Centsov criteria [9].

Lemma 2.Lety be a map from

n0

2n

k=0{k2n}into(E, d), a metric space, such that for alln, k∈ {0, . . . ,2n}, d(yk

2n, yk+1

2n )C2n/p. (2)

Then, there exists a unique continuous pathy˜:[0,1] →(E, d)which coincides withy on

n0

2n

k=0{k2n}. More- over,y˜is1/p-Hölder.

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Proof. We fixr∈N, and show by induction onmthat for alls, tDmsuch that 0< ts <2r, d(ys, yt)2C

m

k=r+1

2k/p. (3)

Whenm=r+1, necessarily,(s, t )is of the form(2km,k2+m1),k∈ {0, . . . ,2m−1}, and so (3) is exactly formula (2).

Suppose now that formula (3) is valid for m=r+1, . . . , M−1. Takes, tDM such that 0< ts <2r, and considert1=max{uDM1;ut}ands1=max{uDM1;us}. Notice thatd(ys, ys1)andd(yt1, yt)are both bounded byC2M/p, and, by the induction assumption, that

d(ys1, yt1)2C

M1

k=r+1

2k/p. Therefore,

d(ys, yt)2C2M/p+2C

M1

k=r+1

2k/p

=2C

M

k=r+1

2k/p, which concludes the induction.

Now let us consider(s, t )

m0Dm, and letrbe the natural number such that 2(r+1)< ts <2r. From the induction, we obtain

d(ys, yt)2C

k=r+1

2k/pCp2(r+1)/p

Cp|ts|1/p. (4)

We finally definey˜t for 0t1 by

˜ yt= lim

r→∞y[2r t] 2r .

From (4), the limit exists andy˜satisfiesd(y˜s,y˜t)C|ts|z1/p. 2

Letx be aR2-valued path, which is 1/p-Hölder withp(2,3). We want to prove that we can liftx to a 1/p- Hölder path with values in the Heisenberg groupH1equipped with its Carnot–Caratheodory metric. Let us first recall a few fact about this group and its metric. The Heisenberg groupH1is equal toR3equipped with the product

(x1, y1, z1)×(x2, y2, z2)=

x1+x2, y1+y2, z1+z2+1

2(y1x2y2x1)

.

The Carnot–Caratheodory distance will be introduced later, the only property we need for this preliminary chapter is that there exists positive constantsc, Csuch that

cmax

|x1x2|,|y1y2|,

z1z2+1

2(y1z2y2z1) 1/2

d

(x1, y1, z1), (x2, y2, z2) , and

d

(x1, y1, z1), (x2, y2, z2)

Cmax

|x1x2|,|y1y2|,

z1z2+1

2(y1z2y2z1) 1/2

.

It is easy to see that to liftx to a 1/p-HölderH1-valued path, we need to construct the Levy area ofx, i.e. a map A:{0s < t1} →Rsuch that

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• for alls < t < u∈ [0,1], As,u=As,t+At,u+1

2

xs,t1 xt,u2xs,t2 xt,u1

; (5)

• for some constantC, for alls, t∈ [0,1],

|As,t|C|ts|2/p. (6)

Of course, ifxis of bounded variation,As,t=12s

s<v1<v2<t(dx1v1dxv22−dxv21 dxv21)satisfies the above condition.

As we do not assumexsmooth, we cannot use this area.

Proposition 3.Letxbe aR2-valued path, which is1/p-Hölder withp=2. Then, one can liftxto a1/p-Hölder path with values in the Heisenberg groupH1equipped with its Carnot–Caratheodory metric.

In rough paths language, using the fact that path of finitep-variation are 1/p-Hölder after a time change, this means that we can lift anyR2-valued path of finitep-variation to a geometricp-rough path, wheneverp(2,3).

Proof. Ifp <2, the result is just a easy consequence of Theorem 1 in [12], or just properties of Young integrals. We therefore assumep >2.

LetCx be the Hölder constant ofx. We construct inductively the area of x between dyadic times, Ak 2n,k+1

2n for k=0, . . . ,2n. We also define inductively

an=22n/p max

0k2n|Ak 2n,k+1

2n |.

First, we setA0,1=0, and therefore we havea0=0. Assume then, for a fixedn, that we have constructedAk 2n,k2+n1

fork=0, . . . ,2n. We defineA 2k 2n+1,2k+1

2n+1 andA2k+1 2n+1,2k+2

2n+1 so that they are both equal. Eq. (5) therefore forces them to be equal to

1 2Ak

2n,k2+n1 −1 4

x1k

2n,2k+1

2n+1

x22k+1

2n+1,k2+n1x2k

2n,2k+1

2n+1

x12k+1

2n+1,k2+n1

.

In particular

an+122(n+1)/p22n/pan 2 +Cx2

2 22(n+1)/p, i.e.

an+122/p1an+1 2Cx2.

It is easy to see by induction that, ifp >2, the sequencean is bounded. Transferring this information in terms of the pathx=(x, A), we see that we have constructed elementsxk2n of the metric space (H1, d) such that for all n, k∈ {0, . . . ,2n},

d(xk 2n,xk+1

2n )Mp2n/p. (7)

We conclude the proof with Lemma 2. 2

The above construction and idea will be the main argument of the proof of the main theorem. To be able to explain it, we need to introduce a few algebraic and geometric notions.

3. Algebraic preliminaries

3.1. Carnot groups

IfGis a simply connected nilpotent Lie group with Lie algebraG, then the Lie group exponential map exp :GG is a diffeomorphism [15,17]. In this case we let ln :GGdenote the inverse of the exponential function. We start with a couple definitions.

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Definition 4.A Carnot group1is a connected nilpotent Lie groupG, such that its Lie algebraGcan be written as G=W1⊕ · · · ⊕Wn,

where for alli, Wi+1= [W1, Wi]. For an elementg=exp(w1+ · · · +wn)G, withwiWi, we let, fort∈R, δtg=exp

t w1+ · · · +tnwn

. δis called the dilation operator.

Definition 5.A (symmetric sub-additive) homogeneous norm [5] on a Carnot groupGis a function · G:G→R+ such that

(i) gG=0 if and only ifgis the neutral element of the group, 1=exp(0), (ii) δtgG= |t|gG,

(iii) for allg, hG,ghGgG+ hG, (iv) for allg,gG= g1G.

Such a norm define a left invariant distance on the group bydG(g, h)= h1gG. We will say that(G, · G)is a normed Carnot group.

IfGis a fixed Carnot group with finite dimensional Lie algebra, all homogeneous norms onGare equivalent. The Carnot–Caratheodory norm is an example of a homogeneous norm on a Carnot group [7]. Any homogeneous norms · GonGleads to a left invariant distancedG(x, y)= y1x(in particular, the Carnot–Caratheodory norm leads to the Carnot–Caratheodory distance). LetGbe a normed Carnot group with Lie algebraG,Ka Lie subgroup ofG,with Lie algebraK. IfKis a closed normal Lie subgroup ofG, or equivalently ifKis closed ideal ofG, thenG/Kis then a Carnot group with Lie algebraG/K[15]. IfGis equipped with a homogeneous norm · G, then we equipG/K with the quotient homogeneous norm onG/K

· G/K:G/K→R, gK→ inf

kKgkG.

We will denote byπG,G/K the canonical homomorphism fromGontoG/K. Sometimes, it will be more convenient to writegKforπG,G/K(g).

Proposition 6.Let(G, · G)be a normed Carnot group, K a closed normal Lie subgroup ofG. There exists an injectioniG/K,G:G/KGsuch that

(i) πG,G/KiG/K,Gis the identity map ofG/K,

(ii) for allt∈R+,gKG/K,δt(iG/K,G(gK))=iG/K,Gt(gK)), (iii) for allgKG/K,gKG/KiG/K,G(gK)G2gKG/K.

Proof. By definition of the homogeneous norm onG/K, for allgGsuch thatgKG/K=1, the set Mg=

gksuch thatkKand 1gkG2 is non-empty. We defineiG/K,Gon the set of elements

gK, such thatgKG/K=1

to be any function which atgK associates an element of

mπG,G/K−1 (gK)Mm; such function exists by the axiom of choice. We then extendiG/K,GtoG/Kwith the help of the formulaiG/K,GtgK)=δtiG/K,G(gK). 2

1 In most definitions of a Carnot group,Gis assumed to be finite dimensional. We do not make such an assumption here.

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3.2. Free nilpotent groups

We know introduce a fundamental example of a Carnot group.

We fix (for the rest of the paper) a normed vector space(V , · 1). We letT (V )=

n=0Vnbe the tensor algebra overV.T (V )equipped with standard addition+, tensor multiplication⊗and scalar product is an associative algebra.

T(n)(V ),the quotient algebra ofT (V )by the ideal

m=n+1Vm,inherits this algebraic structure. One can define onT(n)(V )a Lie bracket by the formula

[a, b] =abba,

which makesT(n)(V )into a Lie algebra. We letG(n)(V )be the Lie subalgebra of T(n)(V )generated by elements inV. Note that

G(n)(V ) n

i=1

Vi, where

V1=V and Vi+1= [V , Vi]. (8)

G(n)(V )is the free nilpotent Lie algebra of stepn[12–14]. The exponential, logarithm and inverse function are defined onT(n)(V )by mean of their power series. We denote byG(n)(V )=exp(G(n)(V )). By the Baker–Campbell–Hausdorff formula,(G(n)(V ),)is a connected nilpotent Lie group, called the free nilpotent Lie group of stepnoverV. By construction,(G(n)(V ),)is a Carnot group, with Lie algebraG(n)(V ).

We are now going to equipG(n)(V )with a homogeneous norm. We first let · i be some norms onVi such that for all(ai, aj)Vi×Vj,aiaji+jaii + ajj. To simplify notations, we will write · for all these norms. Now define

gG(n)(V )= max

i=1,...,n

i!gi1/ i

+max

i!g1

i1/ i,

whereg=1+g1+· · ·+gn,giViis an element of the groupG(n)(V ), andg1is its inverse. The binomial equality quickly shows thatg→maxi=1,...,n(i!gi)1/ iis a sub-additive homogeneous norm (but a priori not symmetric). That implies that · G(n)(V )defines a homogeneous norm onG(n)(V ). We also let

dG(n)(V )(g, h)=h1g

G(n)(V ).

Proposition 7.Letg=exp(l1+ · · · +ln),withliVi. Then, cn max

i=1,...,nli1/ igG(n)(V )Cn max

i=1,...,nli1/ i, for some constantscnandCnwhich depends only onn.

Proof. Let us fixi∈ {1, . . . , n}and writeg=1+g1+ · · · +gn,withgiVi. By definition of the exponential function,

gk=

k

i=1

1 i! j1,...,ji

j1+···+ji=klj1

⊗ · · · ⊗lji.

Hence, k!gkk

1/ k

k

i=1

k! i! j1,...,ji

j1+···+ji=k

lj1 · · · lji 1/ k

k!(expk−1)1/ k

i=max1,...,nli1/ i.

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Applying this tog1,we obtain k!g1

k

k

1/ k

k!(expk−1)1/ k

i=max1,...,nli1/ i=

k!(expk−1)1/ k

i=max1,...,nli1/ i. That gives us the upper bound. For the lower bound, observe that by definition of the logarithm function,

lk=

k

i=1

(−1)i i j1,...,ji

j1+···+ji=k

gj1⊗ · · · ⊗gji,

which, when applied to bothgand its inverse, gives that for all 1kn, lk1/ kcn1gG(n)(V )

for a constantcn>0. 2

Corollary 8.LetK=exp(K)be a closed normal subgroup ofG(n)(V ). Then, ifg=exp(l1+ · · · +ln)withliVi,

cn gKG(n)(V )/K

maxi=1,...,n(infki∈K∩Vili+ki)1/ i Cn.

Corollary 9. LetC(G(n)(V ))be the centre ofG(n)(V ) andθ the canonical isomorphism betweenG(n1)(V )and G(n)(V )/C(G(n)(V )). Then the homogeneous norm · G(n−1)(V )andθ (·)G(n)(V )/C(G(n)(V ))are equivalent. We will therefore not distinguish between them.

4. Rough paths

In this paper, byE-valued path, we mean a function from[0,1]intoE.

4.1. Onp-variation

Definition 10.Let(E, d)be a metric space. A(E, d)-valued pathxis said to have finitep-variation if sup

D

#D1

i=1

d(xti, xti+1)p<,

where the supremum runs over all subdivisionsD=(0t1· · ·t#D1)of the interval[0,1].

Note thatx is continuous and of finite regularp-variation if and only if for allst,d(xs, xt)ω(s, t ),where (i) ω:{(s, t ),0st1} → R+is continuous.

(ii) ωis super-additive, i.e.∀s < t < u,ω(s, t )+ω(t, u)ω(t, u). (9) (iii) ω(t, t )=0 for allt∈ [0,1].

We will say in such case thatx has finitep-variation controlled byω.

We are going to show that a continuous(E, d)-valued path of finitep-variation is, up to reparametrisation of time, 1/p-Hölder continuous. Ifωsatisfies (9), then

(s, t )ω(0,1)

ω(0, t )

ω(0,1)−ω(0, s) ω(0,1)

is a continuous additive map, equal to zero on the diagonal, andω(0, t )ω(0, s)ω(s, t )(by the super-additivity ofω). Therefore, a path is of finitep-variation if and only if there exists an non-decreasing and continuous surjection γ from[0,1]onto[0,1]and a positive constantCsuch that

for allst, d(xs, xt)pCγ (t )−γ (s).

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For such aγ, we define γ1:[0,1] → [0,1],

t→inf

u, γ (u)=t . The following is straightforward to check.

Lemma 11.Let x be a continuous(E, d)-valued path of finitep-variation controlled by(s, t )C|γ (t )γ (s)|, whereγis a continuous increasing surjection from[0,1]onto[0,1]. Define

y:[0,1] →E, txγ1(t ).

Then,y is a1/p-Hölder(E, d)-valued path.

Reciprocally, ifyis a1/p-Hölder(E, d)-valued path then, it is a continuous path of finitep-variation controlled by(s, t )C|ts|.

4.2. Geometricp-rough paths

Definition 12.A weak geometricp-rough path is a(G([p])(V ),·G([p])(V ))-valued path which has finitep-variation.2 Whenx is a path with values in a group(G,), we will writexs,t=xs1xt.

5. The extension theorem

We first need an important lemma.

Lemma 13.Let(G, · G)be a normed Carnot group with graded Lie algebra G=W1W2⊕ · · · ⊕Wn.

DefineK to be a closed subgroup ofexp(Wn), which gives us a normed Carnot group(G/K, · G/K). Letx be a 1/p-Hölder(G/K, · G/K)-valued path. Then, ifp > n, there exists a1/p-Hölder(G, · G)-valued pathx˜ such thatπG,G/K(x)˜ =x.

Proof. As exp(Wn)is in the center ofG,K is a subgroup of the center ofG. In particular,K is a closed normal subgroup ofG.

To construct our pathx, we are first going to construct its increments˜ x˜s,twhens, tDm= {2km, k∈ {0, . . . ,2m1}}

withts=2m, doing this for allm.x˜s,t will be constructed in such a way that ˜xs,tGC|ts|1/p for a given C <∞. Multiplying the increments, we will then have definedxon all dyadics, and the proof will be finished thanks to Lemma 2.

So we define recursively onmsome elementsy k

2m,k2+m1K,k∈ {0, . . . ,2m−1},m∈N, in the aim of defining the elementsx˜ k

2m,k2+m1 with the formula

˜ x k

2m,k2+m1 =iG/K,G(x k

2m,k2+m1)y k 2m,k2+m1

whereiG/K,G is the injection of Proposition 6. This will ensure thatπG,G/K(x)˜ =x. First, we let,y0,1=exp(0).

Then, we assume thaty k

2m,k+12m (and hencex˜ k

2m,k+12m) has been constructed for all 0k2m−1 and a fixedm, and we define the two elementsy 2k

2m+1,2k+1

2m+1 andy2k+1 2m+1,2k+2

2m+1 to be both equal, and equal to the inverse of δ21/n

iG/K,G(x 2k 2m+1,2k+1

2m+1

)iG/K,G(x2k+1 2m+1,2k+2

2m+1

)⊗ ˜xk1

2m,k2+m1

.

2 The definition of a geometricp-rough path is presented quite differently in [12], as the notion of a homogeneous norm was not mentioned there.

Nonetheless, the difference is easily seen to be only notational.

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We easily check thatπG,G/K(y 2k 2m+1,2k+1

2m+1)=exp(0), i.e. that y 2k 2m+1,2k+1

2m+1 =y2k+1 2m+1,2k+2

2m+1K. As elements of K commute with elements ofG, and with the help of the formulaδ21/n(y)=y2foryK, we check that this choice fory 2k

2m+1,2k+1

2m+1 andy2k+1 2m+1,2k+2

2m+1 gives

˜ x k

2m,k+1

2m = ˜x 2k 2m+1,2k+1

2m+1 ⊗ ˜x2k+1 2m+1,2k+2

2m+1. We then defineam=2m/psupk∈{0,...,2m1}y k

2m,k+1

2mG. By the assumption thatx is 1/p-Hölder and by the defini- tion ofiG/K,G,

iG/K,G(x k 2m,k2+m1)

G2x k

2m,k2+m1G/K2C2m/p. Hence, from the previous inequality, we obtain that

21/n2(m+1)/pam+1am2m/p+2(m+1)/p22+1/pC, i.e.

am+121/p1/nam+22+1/p1/nC.

Asn < p, we have 21/p1/n<1 which forces the sequence am to be bounded. So we have constructed for every m0,k∈ {0, . . . ,2m−1}some elementsx˜ k

2m,k2+m1 =iG/K,G(x k

2m,k2+m1)y k

2m,k2+m1G, such that ˜x k

2m,k+1

2mG2x k

2m,k+1

2m G/K+ y k 2m,k+1

2mG

2C+sup

m

am

2m/p=Cp,n2m/p. Remember also that for all dyadic 2km,

˜ x k

2m,k2+m1 = ˜x 2k 2m+1,2k+1

2m+1 ⊗ ˜x2k+1 2m+1,2k+2

2m+1. That allows us to define

˜ x k

2m,2lm =

l1

j=k

˜ x j

2m,j2+m1.

We have proved that for alln, k∈ {0, . . . ,2n}, ˜x k

2m,k2+m1GC2m/p. (10)

The proof is therefore finished using Lemma 2. 2 We are now ready for our main theorem.

Theorem 14. We fix p∈ [1,+∞). Let K be a closed normal subgroup of G([p])(V ). If x is a (G([p])(V )/K, · G([p])(V )/K)continuous path of finitep-variation, withp /∈N\{0,1}, then there exists a continuous(G([p])(V ), · G([p])(V ))-valued pathx˜of finitep-variation such that

πG([p])(V ),G([p])(V )/K(x)˜ =x.

Proof. As noticed in Section 4.1, we assume without loss of generalities thatx is 1/p-Hölder. We denote byK1

· · · ⊕K[p]the Lie algebra ofK, withKiVi. We define fork=1, . . . , n, H(k)=G(k)(V )/exp(Kk)

and

M(k)=G(k)(V )/exp(K1⊕ · · · ⊕Kk) H(k)/exp(K1⊕ · · · ⊕Kk1).

(10)

We are going to construct recursively some H(k)-valued paths y(k) and G(k)(V )-valued paths x(k) which are 1/p-Hölder and such that the projections ofx,x(k), andy(k)ontoM(k)are equal, i.e. such that

πH(k),M(k)

y(k)

=πM([p]),M(k)(x), (11)

πG(k)(V ),M(k)

x(k)

=πM([p]),M(k)(x). (12)

Using Lemma 13,x(k)is easily constructed fromy(k), so we only need to construct the pathsy(k). Constructing those paths are not very difficult intuitively, as to constructy(k), we just need to “paste” togetherx(k1)andx.

Fork=1 y(1)=πM([p]),M(1)(x)is aH(1)=G(1)(V )/exp(K1)valued path, which is 1/p-Hölder.

We now assume that we have aG(k)(V )-valued pathx(k) which is 1/p-Hölder and which satisfies equality (12), and we aim to construct a 1/p-HölderH(k+1)-valued pathy(k+1).

The setZ(k+1)defined by

(g, m)G(k)(V )×M(k+1)such thatπG(k)(V ),M(k)(g)=πM(k+1),M(k)(m) equipped with the product

(g1, m1)(g2, m2)=(g1g2, m1m2)

is a group, and the applicationΨ:Z(k+1)H(k+1)defined by the formula: ifkV1⊕ · · · ⊕Vk andlk+1Vk+1, Ψ

exp(k),exp

k+lk+1 exp

K1⊕ · · · ⊕Kk+1

=exp(k)exp lk+1

exp(Kk+1), is easy seen to be an isomorphism by Baker–Campbell–Hausdorff formula.

Using Proposition 7 and Corollary 8, we see that there exists a constantCk+1such that for all(g, m)Z(k+1), Ψ (g, m)

H(k+1)Ck+1

gG(k)(V )+ mM(k+1)

.

For allt∈ [0,1],(xt(k), πM([p]),M(k+1)(xt))Z(k+1), hence we can define yt(k+1)=Ψ

xt(k), πM([p]),M(k+1)(xt) .

Note first thaty(k+1)satisfies the equality (11). BecauseΨ is an isomorphism,ys,t(k+1)=Ψ (xs,t(k), πM([p]),M(k+1)(xs,t)) and hence

ys,t(k+1)

H(k+1)Ck+1x(k)s,t

G(k)(V )+πM([p]),M(k+1)(xs,t)

M(k+1)

Ck+1x(k)s,t

G(k)(V )+ xs,tM([p])

. By hypothesis and induction hypothesis,

xs,t(k)

G(k)(V )+ xs,tM([p])(C+Ck)|ts|1/p, henceys,t(k+1)H(k+1)Ck+1|ts|1/p.

Using the induction step until we reach the level[p], we obtain aG([p])(V )-valued pathx([p])which is 1/p-Hölder and such that

πG([p])(V ),M([p])

x([p])

=πM([p]),M([p])(x)=x. 2 We ought to make a couple comments on our main theorem.

Remark 15.Note that we could have considered a continuous path of finitep-variation with values in a quotient space ofG(n)(V ),withn >[p]. IfK(n)is a closed normal subgroup ofG(n)(V )andx is a 1/p-Hölder path with values in (G(n)(V )/K(n), · G(n)(V )/K(n)), withp /∈N\{0,1}, then there exists a 1/p-HölderG(n)(V )-valued pathx˜such that

πG(n)(V ),G(n)(V )/K(n)(x)˜ =x.

To prove this, first letK([p])=πG(n),G([p])(K(n)). The canonical projection ofxintoG[p](V )/K([p])is a 1/p-Hölder path. Hence, by the previous theorem, there exists a 1/p-HölderG[p](V )-valued pathx([p])such that

πG([p])(V ),G[p](V )/K([p])

x([p])

=πG(n)(V )/K(n),G[p](V )/K([p])(x).

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