C AHIERS DE
TOPOLOGIE ET GÉOMÉTRIE DIFFÉRENTIELLE CATÉGORIQUES
X IANDONG C HEN
Stable closed frame homomorphisms
Cahiers de topologie et géométrie différentielle catégoriques, tome 37, n
o2 (1996), p. 123-144
<http://www.numdam.org/item?id=CTGDC_1996__37_2_123_0>
© Andrée C. Ehresmann et les auteurs, 1996, tous droits réservés.
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STABLY CLOSED FRAME HOMOMORPHISMS by CHEN XIANDONG
CAHIERS DE TOPOLOGIE ET
GEOMETRIE DIFFERENTIELLE CATEGORIQUES
Volume XXXVII-2 (1996)
RESUME. Dans cet
article,
on donne divers rdsultats sur les sommesfibr6es
d’homomorphismes
de cadres("frames").
Leshomomorphismes
stablement ferm6s et
parfaits
sont etudies et caractérisés dans lescategories
des cadres
coh6rents,
des cadres continus et des cadrescompl6tement réguliers.
As the
counterparts
of the classical closed continuous maps oftopological
spaces and dual to the open frame
homomorphisms,
closed frame homomor-phisms
have been definednaturally.
Theimportance
of this notion has been shown inDowker-Papert [13],
Pultr-Tozzi[21]
and Chen[11], dealing
withparacompactness,
thepointfree
Kuratowski-Mrowka theorem and local con-nectedness, respectively.
This paper arises from the desire to consider the frame
homomorphisms
whose
pushouts
in thecategory
of frames are closed. It is known that co-products
andpushouts
need not preserve closedness ofhomomorphisms
inthe
category
of frames. Thusperfect
andstably
closedhomomorphisms
are introducednaturally (Definition 2.2, 2.3),
and thenanalyzed
in section 2.Interesting
characterizations of thesehomomorphisms
in thecategories
ofcoherent
frames, regular
continuous frames andcompletely regular
framesare
presented
in sections3, 4,
and5, respectively. Finally,
weapply
the con-cept
ofperfect homomorphisms
to thestudy
ofperfect-injectives
and Gleasonenvelope
in thecategory
ofcompletely regular
frames.For
general background
onframes,
we refer to Johnstone[17].
1 General Facts
Let L be a frame. The
top ( bottom )
element of L will be denotedby
e(0).
For a E
L,
itspseudocomplement
is denotedby a*,
definedby
a* =Vlx
ELlx
A a =0}.
For a framehomomorphism
h : L ->M,
itsright adjoint
isdenoted
by h* :
M -> L and isgiven by h.(b) = V{x
EL|h(x) b}.
Ahomomorphism
h : L -> M is called dense ifh(x) -
0implies x
=0;
it is called codense ifh(x)
= eimplies x
= e.For a frame
L,
we use cL to denote its congruence frame. The correspon- dence c : Frm - Frm is a faithful functor suchthat,
forany h :
L -M,
ch : cL -> cM takes a congruence on L to the congruence
generated by
itsimage
under h x h. Theright adjoint
of ch issimply (h
xh)-I:
cM -> itL.The
top
and bottom of cL are denotedby
V and 6. For any a EL, Va
={(x,y)|rVa=y V a},
calledclosed,
is the least congruencecontaining (0, a); 6a
={(x, y)|x
^ a = y ^a},
called open, is the least congruence con-taining (e, a).
EachVa
iscomplemented
in cL withcomplement Aa.
Themap
VL :
L - (tL definedby
a ~>Via
is a frameembedding
which is also anepimorphism
inFrm, whereas,
the map a -4la
is a dualposet embedding
L - cL
taking finitary
A tofinitaryV
andarbitrary V
toarbitrary ^.
Let B be a
sub-join-semilattice
of L. We usecBL
to denote the subframe of (CLconsisting
of congruences of Lexpressible
asjoins
of congruences of the formVa
A6b,
where aE L and
b E B. We caneasily
obtain the nextresult,
which has beenpresented
in Jibladze and Johnstone[15]
for the caseof B as a subframe of L.
Proposition
1.1(1)
The mapVL :
L ->CBL defined by
x ~>Vx
is aframe embedding
which is also anepimorphism in
Frm.(2) VL :
L ->cBL is
universal among allhomomorphisms h :
L - Msuch that
h[B]
is contained in the Booleanpart BM,
the setof complemented
elements
of M.
(3)
For ahomomorphism h :
L ->M,
the restrictionof
(th oncBL
determines a
homomorphism cBh : cBL -> ch[B]M.
Moreover thefollowing
diagram
is apushout:
Now,
let us recall some results onbinary coproducts
in thecategory
of frames. Consider two framesL1
andL2,
and letD(Li
xL2)
be the frame ofall downsets of
L1
xL2.
Then thecoproduct L1 EÐ L2
isrepresented (cf. [6], [11]) by
the frameFix(rr),
where 7r is the nucleus onD(Li
xL2)
suchthat,
for any U E
D(Li
xL2),
U =rr(U)
if andonly
ifX x
{y}
C Uimplies (V X, y) E U,
and{x}
x Y C Uimplies (x, Vy)
E U.For a E
L1
andb E L2,
leta @ b denote ! (a, b) U ! (0, e)U I (e, 0),
thesmallest downset
containing (a, b)
and fixedby
7r.Then,
thecoproduct
mapsq; :
Li
->L1 EÐ L2 (i
=1,2)
aregiven by Q1(X)
= x @ e andq2(y)
= e 0 y.Before we recall
Proposition 1.2,
we introduce thefollowing
nuclei(
fordetail,
see[10], [12] ):
7r1,rr1,
rr2,fr2 : D(L1
xL2) -> D(L1
xL2)
are definedrespectively by
is finite and :
is finite
and
Proposition
1.2([2], [10], [12], [22])
For any U ED(L1
xL2), if a
EL1
is
compact
and(a, b)
E7r (U),
then(a, b)
E rr2 0*1(U).
Concerning
the frame version of Hausdorff spaces, thefollowing
resultsare known. For any frame
L,
thecodiagonal map V :
L e L -L, given by
x
EÐ y
~> A y, is thecoequalizer
of thecopoduct
maps: ql, q2 : L )LED
L.As
usual, V
has a dense factorization: V : L eL(.)Vs -> s --- L,
wheres =
V{a ® bla, b E L,
a A b =0},
called theseparator
of L.We shall call a frame L
separated
if thecodiagonal
map V isclosed,
thatis,
V =(.)
V s for s =V{a @ b|a, b
EL, a
A b =0} (
such L is also calledstrongly
Hausdorffby
Isbell[14]).
Proposition
1.3([1], [12])
Thefollowing
areequivalent for
anyframe
L:(1)
L isseparated.
(2)
In L ®L, (e
®a)
Vs = (a
EÐe)
V sfor
all a EL,
where s is theseparator
of L.
(3)
For anyhl, h2 :
L ->M, (.)
V t : M->! t
is thecoequalizer,
wheret = V{h1(a) ^ h2(b)la, b E L, a ^ b = 0}.
(4)
For anyhl, h2 :
L ->M, h1(a)
V t= h2(a)
V tfor
all a E L.Proposition
1.4 For anyframe homomorphism
h : L ->M,
there exists aunique
ontohomomorphism G(h) :
L ® M -> Mgiven by
x ® y ~>h(x)
A y,which is the
coequalizer of
(idL
EÐh)
o ql,(idL
EÐh)
o q2 :L => L
@ L-L EÐ M.Moreover,
thefollowing
square is apushout:
2 Closed Homomorphisms
Recall that a
homomorphism
h : L ) M is called closed ifh*(h(x)
Vy)
= x Vh.(y)
for any x EL, y
E M.An
interesting
characterization is that ahomomorphism h :
L -> M is closed if andonly
if(h
xh)-’(V.) = Vh.(u)
for each u E M.The next result
easily
follows from the definition.Proposition
2.1 ConsiderL-> f M->gN.
(1) If f
and g areclosed,
so is g of .
(2) If
g of
is closed and g is one-one , thenf
is closed.(3) If
g of
is closed andf
isonto,
then g is closed.Definition 2.1 For any
homomorphism
h : L -M, define
a setfor
allLemma 2.1
Ch(L)
is a sublatticeof
L.Lemma 2.2
If x
E L iscomplemented,
then x ECh(L)
and henceCh(L)
contains the Boolean
part
BL.PROOF. For any y E
M,
let r =h*(h(x)
Vy).
Then r =(r A x)
V(r A x*)
with
h(r
Ax*)
=h(r)
Ah(x*) (h(x)
Vy)
Ah(x*)
= y Ah(x*)
y, hencer x V
h*(y).
This showsh.(h(x)
Vy) x
Vh*(y),
thatis,
x ECh(L).
Lemma 2.3 Let h : L -> M be dense.
If x
ECh(L)
andh(x)
EBM,
thenx E BL.
PROOF. On the one
hand,
e =h*(h(x)
Vh(x)*)
= x Vh*(h(x)*).
On theother
hand, h(x) n hh*(h(x)’) h(x)Ah(x)*
=0, implying x n h*(h(x)*)
= 0.Hence
h*(Ix(x)*)
is thecomplement
of x. IProposition
2.2 Aframe
L is Booleanif
andonly if
anyhomomorphism
h : L - M is closed.
PROOF. The "
only
if "part
follows Lemma 2.2. For the " if "part, apply
Lemma 2.3 to the
homomorphism V :
L -> cL. I Given ahomomorphism
h : L -> M and a congruence 0 ECL,
thereexists an induced
homomorphism h8 LIO
->M/ch(8). Actually,
weget
apushout
square:Question:
When ishe
closed?Lemma 2.4 For
any 0
EO:L,
the closedquotient
mapsof L/8
areexactly
those
expressed
asL/8
-L/(8
VVu) for
some u E L.PROOF. The
following
squares arepushouts:
where
[u]
is theimage
of u under thequotient
map L --L/0.
ThereforeLIO -> ! [u]
is same asL/0
->L/(0
VVu).
IProposition
2.3 For anyframe homomorphism h :
L - M and 0 EcL,
the induced
homomorphism he : Z/0
->M/ch(8)
is closedif
andonly if, for
each u EM,
for
somePROOF. The
homomorphism he
is closed if andonly if,
for every u EM,
there exists v E L such that theright
square in thefollowing diagram
commutes and the
homomorphism g
is one-one.But the
right
square commutes if andonly
if the outer squarecommutes,
and the latter means(h
xh)-1(ch(8)
VVu)
= 0 VVv
when g is one-one. IProposition
2.4If h :
L -> M is closed and 0 iscomplemented
intL,
then
he : LIO
->M/ch(8)
is closed.PROOF.
By
Lemma2.2,
we havefor any But
(h
xh)-1(Vu) = Vh*(u)
since h is closed. Thereforewhich means that
he
is closedby Proposition
2.3. 1Remark: Recall
that,
intopological
spaces, for a closed continuous mapf : X -
Y and anysubspace
Aof Y,
the restriction mapfA : f -1 (A)
-> A is apullback
off
and is closed. To consider the framecounterpart
of thisfact,
it is natural to ask whether
Proposition
2.4 also holds fornon-complemented
0. We do not know the answer
yet.
In
general,
closedness is notpreserved
undercoproducts
andpushouts,
so we introduce two more
concepts concerning
closedness.Definition 2.2 A
homomorphism h :
L -> M is calledperfect if
h EÐidN :
L EÐ N - M e N is closed
for
anyframe
N.Remark:
Elsewhere,
the term"perfect"
has been introducedusing
sometopos
theoretical notionsinvolving
thecorresponding
sheaves(
Johnstone[20]).
We did notexplore
theprecise relationship
between these notions. Thepresent
definition isdirectly
motivatedby
the usualtopological definition,
translated into the
category
of frames.Definition 2.3 A
homomorphism h :
L -> M is calledstably
closedif
every
pushout of h is
closed.Since h EÐ
idN :
L e N -> M EÐ N is thepushout
of halong
L -L EÐ N,
we know that
Proposition
2.5Any stably
closedhomorrtorphism
isperfect.
Conversely,
we haveProposition
2.6If h :
L -> M isperfect
and L isseparated,
then h isstably
closed.PROOF.
Any homomorphism f :
L -> N can be factored asL 91 L e
N G(f) -> N.
Thefollowing
squares arepushout:
The
separatedness
of Limplies G( f )
is closedby Proposition
1.3 and 1.4.Then h
is closedby Proposition
2.4. 1Remark: We do not know whether this result holds without
assuming
theseparatedness
of L.Proposition
2.7Any
closed ontohomomorphism is stably
closed.PROOF. Consider a closed onto
homomorphism
h =(.)
V u : L-> i
u.For any
homomorphism g :
L-> M,
thepushout
of halong g
is(.)
Vg(u) :
M
T g(u).
’Proposition
2.8 ConsiderL-> f -M->g .N.
1.
If f ang g
areperfect ( stably closed,
so is g of.
2.
If
g of
isperfect
andf
isonto,
then g isperfect.
3.
If
g of
isstably
closed andf
isepic,
then g isstably
closed.4. If
g of
isperfect
and M isseparated,
then g isstably
closed.PROOF. 1. Trivial.
2. For any frame
Q,
considerThe
composite
is closed andf
eidQ
isagain onto,
andthus 9 EÐ idQ
is closedby Proposition
2.1.3. For any
homomorphism h :
M ->Q,
consider thediagram
where g
is thepushout of g along
h. Sincef
isepic, g
is also thepushout
ofg o
f along h
of , hence g
is closed.4. Consider the
commuting
square:Since M is
separated, G(g)
isclosed,
thereforeG(g)
isperfect
since it is onto.Again id M ® (g o f )
isperfect,
henceg o G( f )
=G(g) o ( id M ® (g o f ) )
isperfect, thus g
isperfect
sinceG( f )
is onto.Finally, applying Proposition 2.6,
weknow
that g
isstably
closed.Now,
we recall animportant result,
which isconstructively
valid and hasbeen studied
by [21], [22]
and[10].
Proposition
2.9 Aframe
M iscompact if
andonly if
q1 : L -> L ® M is closedfor
anyframe
L.Corollary If h :
L -> M isperfect
and L iscompact,
then M is alsocompact.
Proposition
2.10If L is separated
and Mcompact,
then any homomor-phism
h : L ) M isstably
closed.PROOF.
Considering
the standard construction ofpushouts,
we canget
thepushout
square as follows:.
where ql, q2 are the
coproduct
maps and p is thecoequalizer
of ql of, q2
o h.Since L is
separated,
p is closedby Proposition
1.3. And since M iscompact,
ql is closed
by Proposition
2.9. Thereforeh
= p o ql is closed. I3 Coherent Frames
Recall that a frame L is coherent if its
compact
elementsgenerate
L as a frameand
compact
elements of L form a sublattice KL ofL, including 0,
e E L.Coherent frames and coherent
(=compactness preserving) homomorphisms
constitute the
category
CohFrm.The
following
fact is well known:Lemma 3.1
Any
bounded distributive lattice A can be embedded into a Booleanalgebra
HA such that HA isgenerated,
in Booleanterms, by
A.Moreover,
the
correspondence
A ~> HA isfunctorial, providing
thereflection of
thecategory of
bounded distributive lattices to thecategory of
Booleanalgebra.
It is a familiar fact that a coherent frame L is
isomorphic
to the ideallattice
3KL
of KL.Thus,
for a coherent frameL,
theembedding
KL ->HKL induces a coherent
embedding
L =jKL -> 3HIiL. Moreover, Proposition
3.1 StFrm(the category of compact
0-dimensionalframes)
is
reflective
inCohFrm,
with thereflection
map L ->JH /( L.
Now consider
CK LL,
which is the subframe of cLconsisting
of congruencesexpressible
asjoins
of congruences of the formV
AOb
with a EL,
b E KL.Since the universal
property
ofVL :
L ->cKLL by Proposition 1.1,
thereis a
homomorphism z : CKLL
->3HIiL making
thediagram commuting:
Notice that
CKLL
is0-dimensional, thus I
is closed. It is easy to check thati
isdense,
therefore is one-oneaccording
to the fact that any dense closedhomomorphism is
one-one. ThusCKLL
iscompact
as a subframe of3HIiL.
For each x E
KL, Vx
is alsocompact
inCKLL,
thatis, VL :
L ->cKLL
is coherent. Now we can
easily
obtain the nextfact,
which could also be derived from results of Banaschewski and Br3mmer[8].
Proposition
3.2 The mapVL :
L ->4tKLL provides
thereflection
mapfor
StFrm to bereflective
in CohFrm.Definition 3.1 Let L be a coherent
frame.
A congruence 0 E cL is called coherentif
thequotient
map L ->L/8
is coherent.We have the
following
observations:(1) Any Va
is coherent.(2)
Forcompact
a EL, 4la
is coherent.(3)
A congruence 0 is coherent if andonly
ifL/(Ax
V8)
iscompact
forany
compact x
E L.(4) LIO
iscompact
if andonly if,
for any X CL, AVX cp implies
OV S cp
for some finite S X.(5)
If01, 02
arecoherent,
then01 A 02
is coherentby applying (3)
and(4).
(6)
For a set 0 of coherent congruences,B/{8|8
EO}
in cL is determinedby
themultiple pushout,
inFrm, of {L
->L/8|8
EO} .
Since coherentframes are
precisely
the free framesgenerated by
distributivelattices,
theclass of coherent frames is closed under colimits in Frm. Hence
VO
is co-herent.
Proposition
3.3 For a coherentframe L, cKLL
consistsof
all coherent con- gruencesof L.
PROOF . From the above
observation,
we know that any element ofcKLL
is coherent.
Now we show that any coherent congruence 0
belongs
to4EKLL.
Takewith
compact d, c},
then cp
0and 0
EcKLL.
We need to show 00.
Considerarbitrary Ax
AVy
0. For everycompact
c y,Aa,
AVc
8implies Ax
0 VAc.
By (4)
and(6)
there is acompact dc :5 x
such thatAdc
8 VAc,
then4lr
AVc cp
sinceAdc
AVc (8
V4lc)
AVc
8. ThereforeAx
AVy = V{Ax
AVc| compact
cy} 0.
This proves 8= 0
EcKLL.
I Lemma 3.2 Let h : L -> M be ahomomorphism
such thattLh :
tL ->th[L] M is
closed.(1) If h is
anembedding,
so ishe : L/8 - M/ch(0) for
every 0 E tL.(2) If h is closed,
so ishe : L/8
->M/ch(0) for
every 0 E O:L.PROOF. Notice that ch : CL -> (CM is factored as tL
CLh -> Ch[L]M
cmwhere
th[L]M --+-ftM
is the identicalembedding.
(1)
When h is anembedding,
th isdense, implying CLh
isdense,
and thenTLh
is one-one sincetLh
is closed. It turns out that Ch is one-one, which isequivalent
to the fact thathe : L/8
->M/ch(0)
is one-one for every 0 E T-L.(2) tLh :
4:L ->Ch[L]M
is closed means that(h
xh)->(Ch(8)
Vy)
= 6 V(h
xh)-1(y)
for any 0 E (tLand y
EChh[L]M·
In
particular,
forany 8
E (tL and uE M,
since
When h is also
closed,
we havewhich indicates that
ho : L/8
->M/ch(0)
is closedby Proposition
2.3. 1Lemma 3.3
If
h :L1
->L2
is coherent and one-one, thenh e idN : L1 EÐ
N ->L2 EÐ
N is one-onefor
everyframe
N.PROOF.. Take an
arbitrary
U ELi
e N. Put V=1 {(h(x), y) I (x, y)
EU},
then h ® idN(U) = rr(V).
It is easy to check that V is fixedby
xi . ThenConsider a e
bELl
e N such that a iscompact
andh(a)
e b h (BidN(U) = x(V).
We have(h(a), b)
E1r2(i1(V))
sinceh(a)
iscompact
andPropositon 1.2,
so there is a K C U such thath(a) A{h(x)|(x, y) E K}
and b
V{y|(x) y ) E K},
hence a x for every(x, y )
E K since h is one-one.Then
(a, b)
EU,
thatis,
a e b U. This proves that h eidN
is one-one. ILemma 3.4
If h :
L - M is closed and L has a basis B such thath(B)
consists
of
somecompact
elementsof M,
then h EÐidN :
L ® N -M EÐ N
is closedfor
everyframe
N.PROOF. See
Proposition
4.3 in[10].
INow we are
ready
for the main result of this section.Proposition
3.4 LetL,
M and h : L - M be coherent.(1) If
h isclosed,
then h isstably
closed.(2) If h is
one-one, then thepushout of
halong arbitrary homomorphism
g : L -> N is one-one.
PROOF.
First,
we have apushout
square in Frm:Since
h[KL] 9 KM, cth[KL]M
is a subframe of(EKMM-
Then(th[KL]M
iscompact.
It follows thathk
isstably
closedby Proposition
2.10.Let N be an
arbitrary
frame. Consider thefollowing pushout
squares:Since
hk
eidN
is thepushout
ofhk along CKLL
->CKLL
3N,
it followsthat
f
=CL@NH@ idN
is also apushout
ofhk.
Thereforef
is closed sincehk
is
stably
closed.Now,
forarbitrary homomorphism g :
L - )N,
thepushout
of halong g
is the same as the
pushout
of h ®idN along G(g) : L ®
N ->N,
as shownin the
following diagram:
(1)
If h isclosed, h e idN
is also closedby
Lemma 3.4.By
Lemma3.2,
the
pushout
of h EDidN along G(g) : L e
N -> N is closed.(2)
If h isone-one, h e idN
is also one-oneby
Lemma 3.3. Lemma 3.2 indicates that thepushout
of h eidN along G(g) : L e
N - N is one-one.I
Remark: In
Proposition
3.4(2),
thehomomorphism g
isarbitrary,
hencethis result is
stronger
than the known result thatpushout
preserves monomor-phisms
in thecategory
CohFrm. Also ourargument
is choice-free.4 Regular Continuous Frames
Recall
that,
on anycomplete
latticeL,
a « b means that bV
Simplies
aT for some finite T C S’ and that L is called continuous if x =
V{y
EL | y
«x}
for all x E L. For thebackground
ofregular
continuousframes,
we referto Banaschewski
[4].
In thissection,
we characterizeperfect (= stably
closedby Proposition 2.6 ) homomorphisms
betweenregular
continuous frames in terms of the relation «.For a
regular
continuous frameL,
we will useL
to denote the subframe of the ideal frame3L consisting
of all4-ideals,
where the relation "d" on Lis defined
by:
x 4 y iff z « y and
( 1 ) ! x*
iscompact,
or(2) T y
iscompact.
An
important
roleof L
is that itprovides
the framecounterpart
of the1-point compactification
of alocally compact
Hausdorff space.Recall
that,
in aregular
continuousframe, (1) x
« y if andonly
if z « y,Tx*
iscompact.
(2) x
« eimplies
x 4 e.Lemma 4.1 For
separated L,
continuous M andsurjective
h : L ->M,
there exist s m in L such that h restricted to
Is, m]
is anisomorphism.
PROOF. See
Proposition
5.1 of[10].
ILemma 4.2 For a
regular
continuousframe L,
let rraL ={x E Llx
«e}.
Then mL is a maximal element
of L and ! mL =
L.PROOF. For the map vL :
L ->
Ltaking
each 4-ideal to itsjoin
inL,
it is easy to check that mL
= {x
EL Ix
«e}
is the smallest 4-ideal sent to e E L.By
Lemma4.1, ! mL =
L. Themaximality
of mL isproved
in[4].
Therefore mL is the
only possible non-top
element ofL
with e as itsjoin
inL. I
Lemma 4.3 In a continuous
frame, T
a iscompact iff
a V c = efor
somec « e.
PROOF. Because
fclc
«e}
isupdirected
andV{c|c
«e} = e, T a
compact implies
a V c = e for some c « e.Conversely,
assume a V c = e forsome c « e.
Then,
forany X C Ta
withV X
= e, there exists a finite subset E C X such that cV E, then V E > a V c = e.
This shows thatT a is
compact.
IProposition
4.1 Forregular
continuousframes
L andM,
and a homomor-phism
h : L ->M,
thefollowing
conditions areequivalent:
(1)
h isperfect.
(2)
h preserves «, i.e. x « yimplies h(x)
«h(y).
(3)
h can be extended to ahomomorphism h : L ->
M in the sense that the square:is a
pushout.
PROOF.
(1
=>2).
If h isperfect, then,
for any a EL,
the inducedhomomorphism
ha:T a ---+ T h( a)
isperfect. Suppose x «
y, that is z « y andTx* compact,
whichimplies h(x) h(y),
and! h(x*)
iscompact
since! x* ->T h(x*)
isperfect,
henceT h(x)*,
as a subframe ofT h(x*),
must becompact,
thereforeh ( x )
«h(y).
(2 3).
SinceL and
M are the subframes of3’L
and3M, respectively, consisting
of all4 -ideal,
andany h :
L -> M induces ahomomorphism 3h : 3L
->3M,
we first claim that h preserves d , whichimplies
that3h
preserves
4-ideals,
therefore induces ahomomorphism W : L
--; M.Consider x 4 y in L. If
(i) x
y andTx*
iscompact,
which means x « y,then
h(x)
«h(y).
If(ii) x
yand Ty
iscompact,
the latter means y V c = e for some c « e in Lby
Lemma4.3 ,
thenh(y)
Vh ( c) -
e withh(c)
« e,which means
T h(y)
iscompact again by
Lemma 4.3. Inall, (i)
and(ii)
showthat
h(x)
4h(y).
To see
the corresponding
square is apushout,
it isenough
to showh(mL)
= mM since LE£imL
and M= ! mM : Indeed, h(mL) - {y
EM|y h(x)
for some x «e}
C mM since h preserves « ;and,
on the otherhand,
V h(mL)
= eimplies h(mL) =
mM since mM is the smallest d-ideal whosejoin
is e.(3 => 1). Apply Proposition
2.10. 15 Completely Regular Frames
We refer to
Banaschewski-Mulvey [9]
for thebackground
ofcompletely
reg- ular frames. TheStone-Cech compactification
of acompletely regular
frameL will be denoted
by (3L.
Lemma 5.1 Consider a
commuting
square:where V is
separated,
iand j
are dense onto.If
h : L -> M isperfect,
thenthe square is a
pushout.
PROOF.
Suppose
we have thepushout
square:then there exists a
homomorphism
g : N -> M suchthat g
o pi = h and 9 oP2 = j.
As apushout
ofi,
p2 isonto,
hence N isseparated
since Vis,
therefore g is
perfect by Proposition
2.8. On the otherhand, g
must be denseonto
since j
is dense onto and p2 is onto. Therefore g is anisomorphism
sinceany dense closed
homomorphism
is one-one. IProposition
5.1 Forcompletely regular frames
L andM,
the squareis a
pushout if
andonly if h is perfect.
PROOF.
By
Lemma 5.1 andProposition
2.10.Finally,
wepresent (without proofs)
anapplication
of theconcept
of per- fecthomomorphisms.
As ananalogue
of theprojectives
forcompletely
reg- ular spaces, we canstudy
theinjectives
in thecategory CRegFrm
of com-pletely regular
frames asfollows, using unexplained terminology
as in[5].
Definition
(1)
InCRegFrm,
L isperfect-injective if, for
anyperfect
em-bedding h :
M -> N and anyhomomorphism f :
M ->L,
there exists ahomomorphism g :
N -> L suchthat g o h = f .
(2)
A densehomomorphism
h : L -> M is calledessentially
denseif, for
anyframe homomorphism f :
M -N, f is
dense wheneverf
o h is.(3)
For L ECRegFrm,
its Gleasonenvelope
inCRegFrm
isdefined
to be a
completely regular demorgan frame G(L) together
with an essentialdense
perfect embedding yL :
L ->G(L).
By applying
theStone-Cech compactification
and the results inKRegFrm by
Banaschewski[5], together
with the characterization ofperfect
homomor-phism,
we obtainProposition: (1) Every frame of CRegFrm
has aunique
Gleasonenvelope
in
CRegFrm.
(2)
For any L ECRegFrm, BG(L)
=G(BL).
(3)
Sikorski Theorem that a Booleanalgebra
isinjective
iff it iscomplete
holds
if
andonly if
thecompletely regular deMorgan frames
areprecisely
theinjectives in CRegFrm.
Concerning
Gleasonenvelopes,
we have thefollowing
observation:Setting
p =
(.)** : L - L**,
andapplying
the functorB3,
we haveBp : BL -> BL**,
which is
given by
for each
Now
(3L.. together
with(3p
isactually
the Gleasonenvelope
of(3L.
Then theGleason
envelope
qL : L -G(L)
is thepushout
ofQp along VL : BL ->
Las shown in the
following diagram:
We close with an open
question:
How can one describe qL andG(L) directly
withoutgoing through f3 L ?
Acknowledgements.
This work was done when I was a Ph.D. student and then apostdoctoral
research assistantsupervised by
Professor B. Ba- naschewski at McMasterUniversity.
I amgrateful
for his invaluableguidance
and
suggestions.
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