C OMPOSITIO M ATHEMATICA
P AVEL E TINGOF
K ONSTANTIN S TYRKAS
Algebraic integrability of Schrodinger operators and representations of Lie algebras
Compositio Mathematica, tome 98, n
o1 (1995), p. 91-112
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
Algebraic integrability of Schrodinger operators
and representations of Lie algebras
PAVEL ETINGOF and KONSTANTIN STYRKAS
Department of Mathematics, Yale University, New Haven, CT 06520, USA Received 5 April, 1994; accepted in final form 20 June 1994
© 1995 Kluwer Academic Publishers. Printed in the Netherlands.
1. Introduction
A
Schrôdinger operator
is a differentialoperator
whosesymbol
is theLaplace’s operator.
Aquantum integral
of aSchrôdinger operator
is a differentialoperator
that commutes with it.A
Schrôdinger operator
in m variables is calledintegrable
if it has malge- braically independent quantum integrals
in involution(i.e. commuting
with eachother).
This notion is thequantum analogue
of the notion of Liouvilleintegrability
of a classical Hamiltonian
system.
A
Schrôdinger operator
in m variables is calledalgebraically integrable
if itis
integrable
but thealgebra
of itsquantum integrals
cannot begenerated by
moperators.
In the one-variable case,algebraically integrable operators correspond
to
finite-gap potentials [Kr].
One of the most
interesting examples
of anintegrable Schrôdinger operator
isthe
Calogero-Sutherland operator [C], [S], [OP].
This is the Hamiltonian of thequantum many-body problem
withrational, trigonometric,
orelliptic
interactionpotential.
TheCalogero-Sutherland operator depends
on aparameter
which iscalled the
coupling
constant.It has been observed
[CV 1 ], [CV2], [VSC]
that theCalogero-Sutherland
oper- ators becomealgebraically integrable
when thecoupling
constant takes a discreteset of
special
values. This isproved
for the rational andtrigonometric
case but stillremains a
conjecture
in theelliptic
case for two or more variables.These results can be
generalized
toCalogero-Sutherland operators
associatedwith root
systems,
which were defined in[OP].
In this paper we
study integrability
andalgebraic integrability properties
of cer-tain matrix
Schrôdinger operators.
Morespecifically,
we associate such anoperator (with rational, trigonometric,
orelliptic coefficients)
to everysimple
Liealgebra
g and every
representation
U of thisalgebra
with a nonzero but finite dimen- sional zeroweight subspace. (The Calogero-Sutherland operator
is aspecial
caseof this
construction).
Such anoperator
isalways integrable [E].
Our main resultis that it is also
algebraically integrable
in the rational andtrigonometric
case ifthe
representation
U ishighest weight.
Thisgeneralizes
thecorresponding
resultfor
Calogero-Sutherland operators ([CV1]).
We alsoconjecture
that this is true forthe
elliptic
case aswell,
which is ageneralization
of thecorresponding conjecture
from
[CV2].
The
proof
of the main result is based on the method of0-function -
ajoint eigenfunction
ofquantum integrals
of theSchrôdinger operator.
This method wasdeveloped
in[CV1].
Theproof
of existence anduniqueness
of the0-function
isbased on an
explicit
construction of this function which usesrepresentation theory
of the Lie
algebra
g. To be moreprecise,
the1b-function
is realized(up
to afactor)
as a
weighted
trace of anintertwining operator
between a Verma module over g andthe tensor
product
of this module with U. Such realization goes back to[E], [EK1 ],
where it is found that
joint eigenfunctions
ofquantum integrals
of aCalogero-
Sutherland
operator
can be realized as traces.Using
thetheory of Shapovalov
formfor g
([Sh], [KK]),
we prove that the trace function satisfies the axioms for the7P-function analogous
to those formulated in[CV1],
and is determineduniquely by them,
and then establishalgebraic integrability using
the method of[CV1].
The paper is
organized
as follows. In Section 2 we make the necessary defini-tions,
motivatethem,
and formulate the main result. In Section 3 wegive
infor-mation about Verma
modules, Shapovalov form,
andintertwining operators.
In Section 4 we define the7P-function
as a normalized trace, and prove twoproperties
of this function. In Section 5 we prove that these two
properties uniquely
determinethe
7P-function.
In Section 6 we provealgebraic integrability using
the1b-function.
In the
Appendix
we describe how toget Weyl
group invariantquantum integrals
from central elements
(Casimirs)
of U(g).
2. Main définitions and results
Let V be a finite-dimensional
complex
vector space.DEFINITION 2.1. A matrix differential
operator
is a differentialoperator
whose coefficients are End V-valued functions. A matrixSchrôdinger operator
is a differ-ential
operator
of the formwhere A is the
Laplacian
incm,
and A is ameromorphic
function in Cm withvalues in End V.
DEFINITION 2.2. A matrix
Schrôdinger operator
L is calledintegrable
if thereexist pairwise
commutative matrix differentialoperators L1
=L, L2,..., Lm
suchthat the
symbols
ofLi
have the formpi(~ ~x1,..., Il )Id,
where pi arealgebraically
independent polynomials (p1 (y)
=y2).
Theoperators L 1, ... , Lm
are called thequantum integrals
for L.Let R
~ h* =
Cm be the rootsystem
of asimple
Liealgebra
g of rank m, and letA+
be the set ofpositive
roots of R.DEFINITION 2.3. The
Calogero-Sutherland (CS) operator
for R is theoperator
where the scalar constant
Ca
maydepend only
on thelength
of the root a, and uis one of the
following potential
functions:(i) u(x)
=2/x2 (rational potential), (ii) u(x)
=2/ sinh2
x(trigonometric potential),
or(iii) u(x)
=2~(x|03C91, 03C92) (elliptic potential),
where~(x|03C91, 03C92)
is the Weierstrasselliptic
function withperiods
wl , w2, and K is a constant(Cases (i)
and(ii)
anddegenerations
of case(iii)).
Such
operators
were introducedby Calogero [C]
and Sutherland[S]
for the rootsystem Am
andby Olshanetsky
and Perelomov[OP]
ingeneral.
THEOREM 2.1. The operator L
given by (2-2)
isintegrable. Furthermore,
one canchoose the
integrals tLi,
i =1,..., ml
in such a way that theirsymbols
wouldgenerate the
algebra of Weyl
group invariantpolynomials on h.
For R =
Am (and
in some otherspecial cases)
this theorem wasproved
in[OP].
Cases(i)
and(ii)
forgeneral
rootsystems
were settledby
Heckman andOpdam [HO, Hl, O1, O2].
Case(iii)
forBm, Cm
andD?.,2
is settled in[Osh].
Thegeneral proof
for Case(iii) (and
hence Cases(i)
and(ii))
wasgiven recently by
I. Cherednik
[Ch].
If m = 1 then any
Schrôdinger operator
isintegrable by
the definition. In two or morevariables integrability
is a very rareproperty.
This is illustratedby
thefollowing
result.THEOREM 2.2.
[OOS, OS].
Let m 2. Let L be anintegrable Schrôdinger operator defined by (2-1)
with V = C. Assume that thequantum integrals Li, 1
i z m, are invariant under the
symmetric
groupSm+l acting irreducibly
inen,
and their
symbols generate
thering of Sm+1-symmetric polynomials
on en(the
operator
Li
isof order
i +1).
Then L coincides with(2-2) for
the rootsystem Am for
some valuesof the parameters.
Theorem 2.1 can be
generalized
to the matrix case, as follows.Let g be a
complex simple
Liealgebra, h
C g be a Cartansubalgebra,
Rc j*
be the root
system
of g,0+
be the set ofpositive
roots. ea,fa E 9
be the rootelements
corresponding
to thepositive
root a. Let U be arepresentation
of g suchthat the space V =
U [0]
of zeroweight
vectors in U is finite-dimensional. Define the matrixSchrôdinger operator
where u is
of type (i), (ii),
or(iii)
from Definition 2.3. Suchoperators
are consideredin
[E], [EK1].
THEOREM 2.3. The
operator (2-3)
isintegrable.
Thesymbols of
itsquantum integrals
aregenerators of
thealgebra of Weyl
group invariantpolynomials on fj .
This result is
proved
in[E]
for thespecial
case g =slm+1,
but the method used for theproof
works for any Liealgebra.
This method usesrepresentation theory
ofthe Lie
algebra
g in thetrigonometric
case, andrepresentation theory
of the affine Liealgebra g
in theelliptic
case. Thequantum integrals
ofHg,U,u
are constructed from central elements of the universalenveloping algebra.
We discuss this method in theAppendix.
As a
particular
case, Theorem 2.3 includes Theorem 2.1 for the rootsystem Am. Indeed,
let us take g =slm+1
and aspecial representation
of g :U03BC = (zl ... zm+1)03BCC[z1 z2,...zm zm+1, zm+1 z1], 03BC ~ C, with
the action ofg by
linear trans-formations of variables
(this representation
has nohighest weight).
Allweight subspaces
inU03BC
areone-dimensional;
inparticular,
V =U03BC[0]
= C. It is easy tocompute
thatf03B1e03B1|U[0]
=ti(M
+1). Therefore,
if y is chosen in such a way thatCa
=li(M + 1),
thenoperator (2-3)
transforms into(2-2)
for the rootsystem Am.
Krichever
[Kr]
introduced the notion of analgebraically integrable Schrôdinger
operator (see
also[CV1]).
Here wegeneralize
this definition to the matrix case.Let L be an
integrable
matrixSchrôdinger operator,
letL
1 =L,..., Lm
be itsquantum integrals,
and let thesymbols
ofLi
bepi(~/~x1,..., ~/~xm)Id,
wherepi are
algebraically independent polynomials.
DEFINITION 2.4. L is called
algebraically integrable
if there exists a matrixdifferential
operator Lo commuting
withL1, ..., Lm
withsymbol p0(~/~x1,
...,~/~xm)Id,
such that forgeneric E1, ..., Em
E C thepolynomial
po takes distinct values at the roots of thesystem
ofequations
pi(y i,..., ym )
=Ei , 1
i m.For V = C this definition coincides with the one in
[Kr], [CV1].
In the matrixcase and m = 1 the
property of algebraic integrability
of differentialoperators
was studied in[G].
It turns out that a
Calogero-Sutherland operator
isalgebraically integrable
for adiscrete
spectrum
of values of the constantsCa .
THEOREM 2.4.
[VSC]. If Ca
=1 203BC03B1(03BC03B1
+1)03B1, a) for
all roots aE 0+,
wherey,, is
aninteger depending only
on thelength of
a, then the operator(2-2)
isalgebraically integrable for
the rational andtrigonometric potential.
CONJECTURE 2.5.
[CV2].
Theorem 2.4 istrue for
theelliptic potential.
Conjecture
2.5 isproved only
for the case of the rootsystem Ai.
In this case,operator (2-2)
is the Laméoperator
L =â2 - Cp,
andalgebraic integrability
of this
operator
isequivalent
to the finite gapproperty,
which takesplace
forC =
11(y
+1), 03BC
~ Z[Kr].
In this case, there is aquantum integral Lo
of order203BC+1.
Now let us consider the case of the root
system Am. Looking
at theinterpretation
of the
Calogero-Sutherland operator
via therepresentation UI,
we seewhy
theinteger
values of y should bespecial: they
areexactly
those values for which therepresentation U03BC
has a finite dimensional submodule orquotient
module which isisomorphic
to asymmetric
power ofCm+1 (or (Cm+1)*).
Since the zeroweight
vector is contained in this finite-dimensional
module,
we can use it instead ofU03BC.
Thus we observe that
algebraic integrability
occurs at those valuesof y
whereU J.£
can be
replaced by
ahighest weight
module. This motivates thefollowing general
theorem which is the main result of this paper.
THEOREM 2.6.
If
U is ahighest weight g-module
thenH g,U,u
isalgebraically integrable for
the rational andtrigonometric potential.
In Sections 3-6 we prove this theorem for the
trigonometric
case. The rationalcase can be obtained in the
limit,
so we don’t discuss it.Note that Theorem 2.4 for the root
system Am
is aspecial
case of Theo-rem 2.6.
Finally,
we would like to formulate a naturalconjecture concerning
theelliptic
case.
CONJECTURE 2.7. Theorem 2.6 is
true for
theelliptic potential.
This
conjecture
containsConjecture
2.5 for the rootsystem Am.
We believethat it could be
proved by applying
the methods of this paper to theelliptic
caseand
using
thetechniques
ofrepresentation theory
of affine Liealgebras
andtheory
of vertex
operators
introduced in[E], [EK1].
3. Verma
modules, Shapovalov form, intertwining operators
Let g be a
simple complex
Liealgebra
withtriangular decomposition
g =n_~h~
n+. Fix an element À
~ h*.
Denoteby MA
the Verma module over g withhighest weight a,
i.e. the module with onegenerator
v03BB and relationsWe have the
decomposition M03BB
=~03BC03BBM03BB[03BC]
ofM03BB
into the direct sum of finite dimensionalweight subspaces M03BB[03BC].
Denote alsoM*03BB
=~03BC03BBM03BB[03BC]*
therestricted dual module to
Ma
with the actionof g
definedby duality.
Forgeneric À, M*03BB
is a lowestweight
module with the lowestweight
vectorv*-03BB
ofweight
-À.
We have a vector space
decomposition U(g)
=U( n_) 0 U(h) ~ U(n+).
Definethe Harish-Chandra
homomorphism ~: U(g)[0]
-U(h) by ~|U(h)
=Id,
and~(g)
=Oifg
EU(g)[0] can be represented as g
=gleforsomegl
EU(g),
e E n+.This in tum
gives
rise to a contravariant bilinearU(h)-valued
from F onU(n_)
defined
by
when gl, 92
belong
to the sameweight subspace
ofU(n_),
and0(gi , g2)
= 0otherwise. Here w is the Cartan
antiautomorphism
of g definedby
It is easy to see that this form is
symmetric.
As
U(h)
can be identified with the space of allpolynomials
onh*,
we canintroduce a
symmetric
contravariant C-valued form F onMA
definedby
Let
Q+ = 03A303B1~0394+Z+e03B1.
Let U be any
g-module
withhighest weight it
EQ+.
Thecompleted
tensorproduct M03BBU
=HomC(M*03BB, U)
has a naturalg-module
structure. We say thatan element v ~ u has order q if v E
M03BB[03BB - q]. Clearly, only
elements of order 1J EQ+
may occur. We say that v1J if v ~
qandq - v
EQ+.
Let u E U.
Let 03A6u03BB : MA - M03BBU
be anintertwining operator
such thatvA - u03BB ~ u +
{higher order terms}.
It is clear from the
intertwining property of 03A6u03BB
that u has to be a zeroweight
vector.
PROPOSITION 3.1.
If MÀ is
irreducible then03A6u03BB
exists and isunique for
anyu E
U [0] .
Proof.
BecauseMa
isfreely generated by
vA overU(n_ ),
weonly
need toprove that the module
MÀ0U
contains aunique singular
vector of the form va 0u +
thigher
ordertermsl.
This is the same as to construct a map 0398 :M*03BB ~
Usuch that
0398(v*-03BB) = u
and 0 is an+-intertwiner.
ButM*03BB
is a freeU(n+)-module generated by v*-03BB,
so 0 can beuniquely
extended fromv*-03BB
to the wholeM*03BB.
0It is known that
Ma
is irreducible forgeneric
À. Forspecial
À’sMA
may bereducible,
and ithappens
when the contravariant bilinear form onMa
isdegenerate.
Shapovalov [Sh]
obtained anexplicit
formula for the determinant of this form:where F03BC = (FJl)i,j, i, j
=1, 2,..., dim M03BB[03BB - y]
is the matrix of the restriction of the form toM03BB[03BB - y], K (y) -
the Kostantpartition function,
and the nonzeroconstant
depends
on the choice of basis inM03BB[03BC].
Let
The conditions for
reducibility
ofMa
can then be rewritten asNow we fix
weight li
and letn.
=max{n ~ N| U[-n03B1] ~ 0},
whereU[03B2]
is thesubspace
of vectors ofweight 0
in U. DenoteWe need the
following
LEMMA 3.2. Matrix elements
(F-103BC)i,j of
the inverse matrixF-103BC 1 can
be writtenin
the form
for
some suitablepolynomials P/j (A)
Proof. Shapovalov
formulaimplies
that matrix elements are rational functions in À withonly possible poles
inhyperplanes
definedby ~03B1n(03BB)
= 0. Ourgoal
is toshow that
only simple poles
may occur.Fix a E
0394+, n n03B103BC.
Take 03BB such that~03B2m(03BB)
= 0 iff m =n, 03B2
= a. ThenMa
is reducible and contains aunique
maximal submodule ofM.1, generated by
asingular
vector v03BB-n03B1.Fix z E
h*
such that(a, z) ~
0 for any a E0+,
and let t be anindependent
variable.
Using
theU(h)-valued
bilinear form F we can introduce a newC[t]-
valued bilinear form
F’
andMa
definedby
Clearly, specialization t
~ 0gives
the usualShapovalov
form.Denote N =
dim M03BB[03BB - 03BC]
=K(p),
M =dim M103BB[03BB - Jl]
=K(03BC - na).
Choose a basis vk in
Ma [À - y]
so thatf vil,
i =1, 2, ... , M,
would form a basis forM,1 [A - y].
Then the matrix elements(Ft03BC)i,j
will be divisibleby
tif i
M orj M:
where
fi,j
are somepolynomials
ina,
t. It is clear now that the determinantof any (N - 1) (N - 1)
submatrix ofFt03BC
is divisibleby tM-1. Shapovalov
formulaimplies
that detFt03BC
is divisibleby exactly
Mth power oft,
which means that whenwe
compute
the matrix elements of(Ft03BC)-1, only simple poles
will be allowed whent =
0,
or,equivalently, (F-103BC 1 ) j,j,
will have at mostsimple poles
on thehyperplanes
~03B1n(03BB)
= 0.Repeating
thisargument
for all 03BC, n, a we prove the lemma. a We canapply
this result toget
more information about theintertwining operator
03A6u03BB.
In theproof of Proposition
wedefined 03A6u03BBv03BB
as amap 03A8 : M*03BB ~
U. We wouldlike to obtain a more
explicit
formulafor,*’ vA
as an element ofMÀ0U.
For any basis vk =
g03BCkv03BB, 9" E U (n_)
ofMÀ[À - y]
we have the basis ofM [-03BB
+y] given by vZ == (03C9g03BCk)v*-03BB,
where w is the Cartan involution. It is clearthat v*i, vk>
=F(vi, vk).
Introduce another basis wk which is dual to
v*k
in the usual sense,Le. (vi, wj> = 8ij.
These twobases vk
and Wk are related via theF03BC
matrix:It is clear that in this notation
COROLLARY 3.3.
Suppose
we have anintertwiner 03A6u03BB : M03BB ~ MÀ0U,
whereU is a
highest weight g-module
with thehighest weight
8 EQ+.
(1)
There are noorder 03BC
terms in theexpression for 03A6u03BBv03BB,
unless f-l 0.(2) If y
8 then theorder 03BC part of 03A6u03BBv03BB
can be written aswhere
for some polynomials Pt( À).
(3)
Asufficient
conditionof
existenceof 03A6u03BB
can be written as~03B8(03BB) ~
0.(4)
For any basisgk of U(n_)
we can choosepolynomials S03BCkl(03BB)
so thatFor a rational function
R, represented
as a ratio of twopolynomials
R= P Q
weset
deg R
=deg
P -deg Q .
Note that all coefficients
(F-103BC)kl
are ofnegative degree
in A. Later we willwork with A in the
hyperplanes (a, A)
= const., so we introduce notationso that
03BB~
is a(dim h - 1 )-dimensional
vector and(a, 03BB~>
= o.We will use the
following
PROPOSITION 3.4. When restricted to the
hyperplane (a, A)
=C,
matrix ele-ments
(F-103BC)kl
arerational functions
in03BB~ of nonpositive degree,
andonly
con-stants may occur as terms
of degree
0.Proof.
We choose aspecial
basis inU(n-)[p].
For any sequence w ofpositive
roots
03B21 03B22 ··· 03B2r, where
denotes now thelexicographical order,
such that03A303B2i
= fi, setXw
=f03B21
...far.
Setdeg Xw
=Card({k 1 flk 54 03B1}).
The set of
Xw’s
is a basis inU(n_)[03BC].
We also haveIndeed,
we canonly
raise thedegree by commuting
some epand f03B2 for (3 ~
a,which results in the term
03B2, À)
+ const., which is linear inal.
Note also thatcommuting
with ea orfa
will not increase the total number of terms e03B2and f03B2
forall
(3 ~
a.Therefore,
the maximaldegree
cannot begreater
than half theoriginal
number of terms e03B2 and
f03B2, (3 ~
a. This proves formula(3-7).
The determinant of the form in the
hyperplane (À, a)
= C isequal
towhere the constant
depends
on C. Thenis the
degree
of the determinant aspolynomial in 03BB~. By
the sameargument
asin
[Sh],
from(3-7)
it follows that the03BB~-degree
of any minor of theShapovalov
matrix cannot exceed N.
Moreover, commuting
with ea orf03B1
does notchange
the set of
03B2 mod a,
and therefore any term ofdegree exactly
N hashighest
termproportional
to that of thedeterminant,
which proves theProposition.
~4. Matrix
Trace, 03C8-function
and itsproperties
Fix a
highest weight g-module
U withhighest weight
0 and finite dimensional zeroweight
spaceU [0].
Consider a newoperator
From
Corollary
3.3 it follows thatThis
expression
allows us todefine 4)’
even for Àwhere 03A6u03BB
itself was not defined.It is clear
that u03BB
is anintertwining operator
for alla,
and it has theproperty
Let 03C8(03BB, x)
be aEnd(U[0])-valued
functionon h* h
definedby
PROPOSITION 4.1. The
03A8-function defined
above has thefollowing properties:
where
(03BB, x)
is aEnd(U[0])-valued polynomial
in À with thehighest
termwhere we
put for brevity
na =no.
for
some03B1n(03BB)
EEnd(U[0]),
which is rational in Aof nonpositive degree,
and
only
constantoperators
may appear in it asdegree
zero terms.(That is,
thehighest
termof
the numerator coincides with thehighest
termof
thedenominator up to a
constant factor).
Proof.
The firstpart
is clear from the formulaand the fact that ail the
Tr|M03BB[03BB-03B2](u03BB)
are some combinations ofSrl’s,
and there-fore
polynomials
in À.Their highest terms
areobviously
ailequal
to03A003B1~0394+03B1,03BB>n03B1,
so the
highest
term ofP(03BB, x)
isequal
toWe now
prove the
secondproperty of the 03A8-function. Let 03B1, 03BB+03C1>-n 203B1, a)
=0 for some a
E A+, 1 n
na, but03B2,
À +03C1> - m 203B2, (3) ~
0 unless03B2 = 03B1,
m=n.From
Corollary
3.3 it follows thatu03BBv03BB
has no order v termsunless v
na.In
particular,
there are no order zero terms. On the otherhand, u03BBv03BB
has to be asingular
vector. Therefore we must havewhere v03BB-n03B1 is the
unique singular
vectorgenerating
the submoduleM103BB ~
MA-na .
Thisimplies that u03BB
is atriangular operator: u03BBM03BB
CM103BB ~ U,
soLet
u03BBv03BB-n03B1
= VÀ-na 0 w +thigher
orderterms}. Using
the fact thatM103BB ~
M03BB-n03B1
we see thatSet p = n03B1.
It is an easy calculation to show that
Introduce a linear
operator
We can rewrite
(4-7)
asTo
complète
theproof
weonly
need to show that03B1n(03BB)
satisfies therequired
condition. It is clear that
B03B1n (À)
is rational in À and is notsingular
in thehyperplane (a, À
+p) - n 203B1, a)
= 0. As we can rewritethe rest follows from the
Proposition
3.4. 0Now we can
introduce
our mainobject
ofstudy. Set 03BA = 03A303B1~0394 +
na. PutThe
properties
of Bl1-function can now be rewritten in thefollowing
form:COROLLARY 4.2.
(1) e-function
can berepresented
aswhere
P(A, x)
is apolynomial
in Aof
theform
where
B03B1s(03BB)
=03B1s(03BB 2 - p)
is arational End(U[0])-valued function of A
andcan be
represented
asfor
some constantb’
EEnd(U[0]).
REMARK. Consider the case g =
sl(n),
U =SknCn.
In this case na = k forall a, and it is easy to show that
B03B1s(03BB)
is notidentically
zero for any a, s k.Indeed,
if a is asimple
root then it is easy toget
from(4-8)
thatB03B1s(03BB)
= 1. Ifa =
ri
al(i j)
then choose À in such a way that03B1l, 03BB -
2s03A303BB-1m=i 03B1m>
=2s, l
=i,..., j.
Then(4-11) implies: 03C8(03BB,x)
=03C8(03BB - 2sa, x),
i.e.B03B1s(03BB)
= 1for this
particular
À. This means,Ba
is notidentically
0. Infact,
a more carefulanalysis
shows that it isidentically 1,
i.e. can be removed from(4-11).
This resultagrees with
[CV1].
The fact that
Bâ
is notidentically
zeroimplies
that in this case thepolynomial
~03B8(03BB)
isexactly
the common denominator of thecomponents
of theoperator 03A6u03BB.
Indeed,
if some functionf
=(a, À
+03C1> - s, 1 s z k,
does not occur in suchcommon
denominator,
thenby (4-5)
we would haveBa
= 0 on thehyperplane f
=0,
which isimpossible.
5.
Uniqueness
of the03C8-function
In this section we prove the
uniqueness property
of the function03C8(03BB, x), satisfying (4-10)
and(4-11).
PROPOSITION 5.1.
Suppose
we have anEnd(U[0])-valued function
where
Q(À, x)
is apolynomial
inÀ, satisfying (4-11).
Then thehighest
termof
Q(03BB, x)
is divisibleby
Proof.
Consider thehighest
term ofQ(03BB, x).
We need to show that it is divisibleby (a, 03BB>n03B1
for any aE 0+.
Fix an a
E 0+.
We canuniquely represent Q(03BB, x)
aswhere
Qkl(03BB~, x)
arehomogeneous End(U[0])-valued polynomials
in03BB~
ofdegree
1.The
highest
term ofQ(03BB, x )
will be some combination of the terms of03BBKl03B1QKll(03BB, x).
We claim that it isenough
to show thatKL
na.Indeed,
itwill follow then that the
highest
term will havedegree
at least L + na, and there-fore ail terms of the form
03BBKl03B1QKll(03BB, x ) contributing
to thehighest
term musthave
Kl
L + na - 1 na, which proves the statement.By
ourassumption 03C8(03BB, x )
satisfies(4-11),
so we can writewhere
( lower degree terms}
are understood withrespect
toÀ 1...
We can consider
homogeneous parts
of(5-2)
ofdegree
L inÀ 1... Formally, given
a function
f( À 1.. ),
we considerThis
gives
usfors =
1,..., J( L.
The rest is based on the
following.
LEMMA 5.2. Consider a
homogeneous
systemof
N linearequations
on K vectorvariables
Ak(z)
ECM,
which aremeromorphic
in some additional parameterz:
s =
1,...,N, Cs
EMatM(C).
If K
N then thissystem
hasonly
trivial solutionAk(z)
= 0.Proof of lemma.
We can think of thissystem
as asystem
of linearequations
onKM variables
(Ak)m
and rewrite(5-4)
in the block-matrix formSuppose K
N. Then the determinant of thesubmatrix, consisting
of first Il blocks(or, equivalently,
first KMequations)
is an entireMatm(C)-valued
functionof z with the
asymptotics
as z - + o0which is
equal
towhere the nonzero constant
is the Vandermonde determinant.
Therefore,
this determinant is a nonzero entirefunction,
whichimplies
that forgeneric z
it is not zero, so thesystem
hasonly
trivial solution. Themeromorphic
functions
Ak(z)
areequal
to zero forgeneric
z, and therefore must beidentically equal
to zero.The lemma is
proved.
0We now
apply
Lemma 5.2 to thesystem given by (5-3),
for N = na, Il =l(L
+1,
M =dim U[0]
andsetting C,
=(-1)k(b03B1s)t,
z = xa -2(a, x),
whereA’
is thetransposed
matrix A.Consider the rows of the
matrix, corresponding
to03C8(03BB~, x),
andtranspose
them so that
they
become columns.By (5-3)
all these columnssatisfy
thesystem
ofequations (5-4),
and as0-function
is notidentically equal
to zero, itimplies
thatthe
system (5-4)
has a nontrivial solution.By
Lemma5.2,
we haveKL
+ 1 > na, or,equivalently, KL
na.The
proposition
isproved.
~COROLLARY 5.3.
Any End(U[0])-valued function
satisfying (4-11),
can berepresented
asfor
someEnd(U[0])-valued polynomial q(A) -
Proof.
Theproof
is similar to theproof
of the Lemma in Section 1 of[CV1].
We use induction on the
degree
ofQ(03BB, x ).
If deg Q(03BB, x) deg P( À, x),
wherethen
by proposition
we haveQ(03BB, z ) m 0,
so we can takeq(03BB) ~
0.Suppose
we haveproved
the statement for allpolynomials
ofdegree
less thanthe
degree of Q(03BB, x). By Proposition
we can find aEnd(U [0]) -valued polynomial q1(03BB)
such thatConsider the function
Obviously,
it satisfies(4-11). Moreover,
it can beiepresented
aswhere
polynomial (03BB, x)
hasdegree
smaller than that ofQ(03BB, x ).
By
inductionhypothesis
we can introduce aEnd(U [0]) -valued polynomial q2(03BB)
such that
The
polynomial q(a)
=q1(03BB) + q2(03BB)
satisfies therequired property.
DCOROLLARY 5.4.
The function 03C8(03BB, x), satisfying
both(4-10)
and(4-11),
existsand is
unique.
Proof.
It is a direct consequence of(4-10)
andCorollary
5.3. ~6. Existence of differential
operators
The
properties
of the1b-function
obtained inChapters 4,
5 are very close to the axioms in[CV1].
The functionsatisfying
these axioms was used to construct aring
of differential
operators
that containeddim j algebraically independent operators, corresponding
to thegenerators
of thering
of W-invariantpolynomials,
but wasbigger
than thering generated by
thoseoperators.
Here we
apply
these ideas to construct a similarring
of matrix differential oper-ators and thus prove Theorem 2.6.
THEOREM 6.1. For any
End(U[0])-valued polynomial Q( À) satisfying
the prop- ertywhenever
(a, À)
=0,
there exists adifferential
operatorDQ
withcoefficients
inEnd(U[0]),
such thatThe
correspondence Q(03BB) ~ DQ
is ahomomorphism of rings.
Inparticular,
allDQ
commute with each other.Proof.
We use induction on thedegree
ofQ(03BB). If deg Q(A)
=0,
thenQ(A)
=const., so the
operator DQ
will bejust
theoperator
ofmultiplication by
thisconstant.
Suppose
we haveproved
the theorem for allpolynomials
ofdegree
less thanthat of
Q(03BB).
Let thehighest
term ofQ ( a )
beequal
towhere
(n)
is amultiindex, a(n)
EEnd(U[0]).
Consider theoperator DQ
definedby
It has the
property
thatand it also satisfies
(6-1).
Consider the differenceIt satisfies
(4-11)
and therefore can berepresented
asfor some
End(U [0]) -valued polynomial Q(03BB)
such thatdeg (03BB) deg Q(03BB). By
induction
hypothesis
we can introduce anoperator DQ
such thatand the
operator
has the
required property,
whichcompletes
theproof
of the inductionstep.
The assertion that the constructed
correspondence
is ahomomorphism
ofrings
follows from the fact that the
operator DQ1Q2 - DQl DQ2
annihilates the03C8-function
for any
a,
and therefore has to beidentically
zero. ~Among
thepolynomials Q(03BB), satisfying (6-1 ),
are all thegenerators
of thering
of W-invariant
polynomials
pl(03BB),..., pr(03BB).
It is known thatthey
arealgebraical- ly independent,
and thering generated by corresponding
differentialoperators
is aring
ofpolynomials
ingenerators Dp1,..., D pr .
There are also other
polynomials, satisfying (6-1),
which are not W-invariant.They give
rise to differentialoperators
which are not W-invariant and therefore do notbelong
to thering generated by Dp1,
i ...Dpr.
In
particular,
allpolynomials
contained in the idealgenerated by
satisfy
the(6-1).
PROPOSITION 6.2. The
differential operator corresponding
to theinvariantpoly-
nomial pl
(A) = (A, A),
isequal
toThis fact can be
proved by
a directcomputation.
Anotherproof
of itusing
therelationship
between the center ofU(g)
andcommuting
differentialoperators
is sketched in theAppendix (see
also[E]).
The
operator (6-3)
coincides with thegeneralized Calogero-Sutherland operator (2-3)
for thetrigonometric
case. We have shown that thisoperator
isalgebraically integrable.
Theorem 2.6 isproved.
Appendix
In conclusion we
briefly
describe how to constructquantum integrals
ofHg,U,u
withtrigonometric potential
from central elements ofU(g).
This construction works forarbitrary
moduleU,
notnecessarily highest weight.
PROPOSITION Al.
[E]
Let X EU(g)
be an elementof degree 0,
i.e.[h, X] = 0, h
Eh.
Then there exists aunique
matrixdifferential operator D(X)
withEnd(U[O])-valued coefficients
such thatfor any A
Eh*
and anyintertwining operator 4): MA - M03BB~U
The
proof
of this theorem and a recursive construction ofD(X)
isgiven
in[E].
We illustrate the idea of this constructionby computing D(EF) for g
=sI2 (E, F, H
are standardgenerators of g).
The main trick is to carry E around the trace,using
theintertwining property
of 03A6 and thecyclic property
of the trace:(where
a is thepositive
root ofg)
whichimplies
Further,
we havewhich
implies
Combining (A2)
and(A4),
we findThus
In
general,
it is not true thatD(XIX2) equals
eitherV(XI)V(X2)
orD(X2)D(XI).
However:PROPOSITION A2.
[E]. If Xl belongs
to the centerof U(g), then for any X2
onehas
D(X2)D(XI)
=V(XIX2).
This
proposition
follows from the fact that if 03A6 is anintertwining operator
then03A6X1
is also anintertwining operator.
COROLLARY.
If Xl, X2
are both in thecenter of U(g),
thenD(XI) and D(X2)
commute with each other.
Let
D(X)
be the differentialoperator
obtained fromD(X) by conjugation by
thefunction
TrIM-p(eX),
i.e. definedby D(X)03BE(x)
=Tr|M-03C1(ex)D(X)(03BE(x) Tr|M-03C1(ex)).
The
following
statement is checkedby
a directcomputation:
PROPOSITION A3.
[E].
Let B be an orthonormal basisof
g, andCI
=EaEBa2
be the Casimir element. Then
PROPOSITION A4. Let
Cl, ... , Cm
bealgebraically independent generators of
the center
of U(g).
LetLi
=D(Ci).
Then1, ... , m
arealgebraically indepen-
dent quantum
integrals of the Schrôdinger operator 1 given by (A7).
Thesymbols of L
1 generate thealgebra of Weyl
group invariantpolynomials on h.
Thefunction
T (A, x)
is ajoint eigenfunction for 1,
... ,Lm
witheigenvalues ~(Ci)(03BB),
where~
is the Harish-Chandrahomomorphism defined
in Section 3.Observe that