arXiv:0710.5639v3 [math.PR] 22 Aug 2009
fra tional Brownian motion IvanNourdin
∗
,David Nualart
†‡
and Ciprian A.Tudor
§
Abstra t: In this paper, we prove some entral and non- entral limit theorems for renormalized weighted power variations of order
q ≥ 2
of the fra tional Brownian motion with Hurst parameterH ∈ (0, 1)
, whereq
is an integer. The entral limit holds for1
2q
< H ≤ 1 −
2q
1
, the limit being a onditionally Gaussian distribution. IfH <
1
2q
weshowthe onvergen e inL
2
to alimit whi h only depends on the fra tional Brownian motion, and if
H > 1 −
1
2q
we show the onvergen e inL
2
to a sto hasti integralwithrespe ttotheHermitepro essoforder
q
.Key words: fra tional Brownian motion, entral limittheorem, non- entral limit theorem, Hermite pro ess.
2000Mathemati sSubje t Classi ation: 60F05,60H05,60G15,60H07. Thisversion: August2009.
1 Introdu tion
The study of single path behaviorof sto hasti pro esses is often basedon thestudy of their powervariations,andthereexistsaveryextensiveliteratureonthesubje t. Re allthat,areal
q > 0
beinggiven,theq
-powervariationofasto hasti pro essX
,withrespe ttoasubdivisionπ
n
= {0 = t
n,0
< t
n,1
< . . . < t
n,κ(n)
= 1}
of[0, 1]
,isdened to bethesumκ(n)
X
k=1
|X
t
n,k
− X
t
n,k−1
|
q
.
For simpli ity, onsider from now on the ase where
t
n,k
= k2
−n
for
n ∈ {1, 2, 3, . . .}
andk ∈ {0, . . . , 2
n
}
. In thepresent paperwe wish to point out some interesting phenomena when
X = B
is a fra tional Brownian motion of Hurst indexH ∈ (0, 1)
, and whenq ≥ 2
is aninteger. In fa t, we will also drop the absolute value (when
q
is odd) and we will introdu e∗
LaboratoiredeProbabilitésetModèlesAléatoires, UniversitéPierre etMarieCurie,Boîte ourrier188, 4 Pla eJussieu,75252 ParisCedex5,Fran e,ivan.nourdinupm .fr
†
Department of Mathemati s,University of Kansas, 405 Snow Hall, Lawren e, Kansas 66045-2142, USA, nualartmath.ku.edu
‡
TheworkofD.NualartissupportedbytheNSFGrantDMS-0604207
§
2
n
X
k=1
f (B
(k−1)2
−n
)(∆B
k2
−n
)
q
,
q ∈ {2, 3, 4, . . .},
(1.1)where the fun tion
f : R → R
is assumed to be smooth enough and where∆B
k2
−n
denotes, hereandinall the paper,thein rementB
k2
−n
− B
(k−1)2
−n
.The analysis of the asymptoti behavior of quantities of type (1.1 ) is motivated, for instan e, by the study of the exa t rates of onvergen e of some approximation s hemes of s alar sto hasti dierential equations driven by
B
(see [7℄, [12 ℄ and [13 ℄) besides, of ourse, thetraditional appli ationsof quadrati variations to parameter estimation problems.Now,letusre allsomeknownresults on erning
q
-powervariations(forq = 2, 3, 4, . . .
), whi h aretodaymoreor less lassi al. First,assumethat theHurst indexisH =
1
2
,thatisB
isastandardBrownianmotion. Letµ
q
denotetheq
thmomentofastandardGaussianrandom variableG ∼ N (0, 1)
. By the s aling property of the Brownian motionand using the entral limittheorem, itis immediatethat, asn → ∞
:2
−n/2
2
n
X
k=1
h
(2
n/2
∆B
k2
−n
)
q
− µ
q
i
Law
−→ N (0, µ
2q
− µ
2
q
).
(1.2)Whenweightsareintrodu ed,aninterestingphenomenonappears: insteadofGaussianrandom variables, we rather obtain mixing random variables aslimit in (1.2 ). Indeed, when
q
isevenand
f : R → R
is ontinuous andhaspolynomialgrowth, itisa veryparti ular ase ofa moregeneral resultbyJa od [10℄ (seealso Se tion 2inNourdin andPe ati[16 ℄ forrelatedresults) thatwe have, as
n → ∞
:2
−n/2
2
n
X
k=1
f (B
(k−1)2
−n
)
h
(2
n/2
∆B
k2
−n
)
q
− µ
q
i
Law
−→
q
µ
2q
− µ
2
q
Z
1
0
f (B
s
)dW
s
.
(1.3)Here,
W
denotes another standard Brownian motion, independent ofB
. Whenq
is odd, stillfor
f : R → R
ontinuous withpolynomial growth,we have,this time,asn → ∞
:2
−n/2
2
n
X
k=1
f (B
(k−1)2
−n
)(2
n/2
∆B
k2
−n
)
q Law
−→
Z
1
0
f (B
s
)
q
µ
2q
− µ
2
q+1
dW
s
+ µ
q+1
dB
s
,
(1.4)seefor instan e[16 ℄.
Se ondly,assumethat
H 6=
1
2
,thatisthe asewherethefra tional BrownianmotionB
hasnot independent in rementsanymore. Then(1.2 ) hasbeenextendedbyBreuerand Major [1℄,Dobrushin and Major [5℄,Giraitis and Surgailis [6℄ or Taqqu [21 ℄. Pre isely,ve ases are onsidered, a ordingto the evenness ofq
and thevalue ofH
:•
ifq
iseven and ifH =
3
4
,asn → ∞
,1
√
n
2
−n/2
2
n
X
k=1
(2
3
4
n
∆B
k2
−n
)
q
− µ
q
−→ N (0, e
Law
σ
2
3
4
,q
).
(1.6)•
ifq
iseven and ifH ∈ (
3
4
, 1)
, asn → ∞
,2
n−2nH
2
n
X
k=1
(2
nH
∆B
k2
−n
)
q
− µ
q
Law
−→
Hermiter.v.. (1.7)•
ifq
isoddand ifH ∈ (0,
1
2
]
,asn → ∞
,2
−n/2
2
n
X
k=1
(2
nH
∆B
k2
−n
)
q Law
−→ N (0, e
σ
2
H,q
).
(1.8)•
ifq
isoddand ifH ∈ (
1
2
, 1)
, asn → ∞
,2
−nH
2
n
X
k=1
(2
nH
∆B
k2
−n
)
q Law
−→ N (0, e
σ
2
H,q
).
(1.9)Here,
e
σ
H,q
> 0
denotesome onstant depending only onH
andq
. The term Hermite r.v. denotes a randomvariablewhose distributionisthesame asthatofZ
(2)
at timeone,for
Z
(2)
dened inDenition 7 below.Now, let us pro eed with the results on erning the weighted power variations in the asewhere
H 6=
1
2
. Consider the following ondition on a fun tionf : R → R
,whereq ≥ 2
is aninteger:(H
q
) f
belongs toC
2q
and, for any
p ∈ (0, ∞)
and0 ≤ i ≤ 2q
:sup
t∈[0,1]
E
|f
(i)
(B
t
)|
p
< ∞
.Suppose that
f
satises(H
q
)
. Ifq
is even andH ∈ (
1
2
,
3
4
)
, then by Theorem 2 in León and Ludeña [11℄ (see also Cor uera et al [4℄ for related results on theasymptoti behavior of thep
-variationof sto hasti integrals withrespe t toB
)wehave,asn → ∞
:2
−n/2
2
n
X
k=1
f (B
(k−1)2
−n
)
(2
nH
∆B
k2
−n
)
q
− µ
q
Law
−→ e
σ
H,q
Z
1
0
f (B
s
)dW
s
,
(1.10)thisdire tionhasbeenobservedbyGradinaruetal [9℄. Namely,if
q ≥ 3
isoddandH ∈ (0,
1
2
)
, wehave,asn → ∞
:2
nH−n
2
n
X
k=1
f (B
(k−1)2
−n
)(2
nH
∆B
k2
−n
)
q
L
2
−→ −
µ
q+1
2
Z
1
0
f
′
(B
s
)ds.
(1.11)Also,when
q = 2
andH ∈ (0,
1
4
)
,Nourdin [14 ℄ proved thatwe have, asn → ∞
:2
2Hn−n
2
n
X
k=1
f (B
(k−1)2
−n
)
(2
nH
∆B
k2
−n
)
2
− 1
L
2
−→
1
4
Z
1
0
f
′′
(B
s
)ds.
(1.12)In view of (1.3 ), (1.4 ), (1.10 ), (1.11 ) and (1.12 ), we observe that the asymptoti be-haviors of the power variations of fra tional Brownian motion (1.1 ) an be really dierent, depending onthe valuesof
q
andH
. The aimof thepresent paperisto investigate what hap-pensinthewholegeneralitywithrespe ttoq
andH
. Ourmain toolistheMalliavin al ulus thatappeared, inseveralre ent papers, to be very useful inthestudy of thepower variations for sto hasti pro esses. As we will see, the Hermite polynomials play a ru ial role in this analysis. In the sequel, for an integerq ≥ 2
, we writeH
q
for the Hermite polynomial with degreeq
dened byH
q
(x) =
(−1)
q
q!
e
x2
2
d
q
dx
q
e
−
x2
2
,
andwe onsider,when
f : R → R
isadeterministi fun tion,thesequen eofweighted Hermite variationof orderq
dened byV
n
(q)
(f ) :=
2
n
X
k=1
f B
(k−1)2
−n
H
q
2
nH
∆B
k2
−n
.
(1.13)Thefollowing isthe main resultofthis paper.
Theorem 1 Fix an integer
q ≥ 2
, andsuppose thatf
satises(H
q
)
. 1. Assume that0 < H <
1
2q
. Then, asn → ∞
, it holds2
nqH−n
V
n
(q)
(f )
−→
L
2
(−1)
q
2
q
q!
Z
1
0
f
(q)
(B
s
)ds.
(1.14) 2. Assume that1
2q
< H < 1 −
2q
1
. Then, asn → ∞
, it holdsB, 2
−n/2
V
n
(q)
(f )
−→ B, σ
Law
H,q
Z
1
0
f (B
s
)dW
s
,
(1.15)where
W
isa standard Brownianmotion independent ofB
and3. Assume that
H = 1 −
1
2q
. Then, asn → ∞
, it holdsB,
√
1
n
2
−n/2
V
(q)
n
(f )
Law
−→ B, σ
1−1/(2q),q
Z
1
0
f (B
s
)dW
s
,
(1.17)where
W
isa standard Brownianmotion independent ofB
andσ
1−1/(2q),q
=
2 log 2
q!
1 −
1
2q
q
1 −
1
q
q
.
(1.18) 4. Assume thatH > 1 −
1
2q
. Then, asn → ∞
, it holds2
nq(1−H)−n
V
n
(q)
(f )
−→
L
2
Z
1
0
f (B
s
)dZ
s
(q)
,
(1.19) whereZ
(q)
denotes the Hermite pro ess of order
q
introdu ed in Denition7 below. Remark 1. Whenq = 1
, we haveV
(1)
n
(f ) = 2
−nH
P
2
n
k=1
f B
(k−1)2
−n
∆B
k2
−n
. ForH =
1
2
,2
nH
V
(1)
n
(f )
onverges inL
2
to the It sto hasti integral
R
1
0
f (B
s
)dB
s
. ForH >
1
2
,2
nH
V
n
(1)
(f )
onverges inL
2
andalmost surelyto theYoung integral
R
1
0
f (B
s
)dB
s
. ForH <
1
2
,2
3nH−n
V
n
(1)
(f )
onverges inL
2
to−
1
2
R
1
0
f
′
(B
s
)ds
. Remark 2. In the riti al aseH =
1
2q
(q ≥ 2
), we onje ture the following asymptotibehavior: as
n → ∞
,B, 2
−n/2
V
n
(q)
(f )
−→ B, σ
Law
1/(2q),q
Z
1
0
f (B
s
)dW
s
+
(−1)
q
2
q
q!
Z
1
0
f
(q)
(B
s
)ds
,
(1.20)for
W
a standard Brownian motion independent ofB
andσ
1/(2q),q
the onstant dened by (1.16 ). A tually,(1.20 )forq = 2
andH =
1
4
hasbeen proved in[2, 15 ,17℄ afterthat therst draftofthe urrentpaperhavebeensubmitted. Thereaderisalsoreferredto [16 ℄for thestudy ofthe weighted variationsasso iated withiterated Brownian motion, whi h is anon-Gaussian self-similarpro ess of order1
4
. WhenH
is between1
4
and3
4
,one an renepoint 2 ofTheorem 1asfollows:Proposition 2 Let
q ≥ 2
be an integer,f : R → R
be a fun tion su h that(H
q
)
holds and assumethatH ∈ (
1
4
,
3
4
)
. ThenB, 2
−n/2
V
n
(2)
(f ), . . . , 2
−n/2
V
n
(q)
(f )
(1.21)Law
−→
B, σ
H,2
Z
1
0
f (B
s
)dW
s
(2)
, . . . , σ
H,q
Z
1
0
f (B
s
)dW
s
(q)
,
where(W
(2)
, . . . , W
(q)
)
is a
(q − 1)
-dimensional standard Brownian motion independent ofB
understandingof the asymptoti behaviorofweightedpower variations offra tional Brownian motion:
Corollary 3 Let
q ≥ 2
be aninteger,andf : R → R
beafun tionsu hthat(H
q
)
holds. Then,as
n → ∞
: 1. WhenH >
1
2
andq
isodd,2
−nH
2
n
X
k=1
f (B
(k−1)2
−n
)(2
nH
∆B
k2
−n
)
q L
2
−→ qµ
q−1
Z
1
0
f (B
s
)dB
s
= qµ
q−1
Z
B
1
0
f (x)dx.
(1.22) 2. WhenH <
1
4
andq
iseven,2
2nH−n
2
n
X
k=1
f (B
(k−1)2
−n
)
(2
nH
∆B
k2
−n
)
q
− µ
q
L
2
−→
1
4
q
2
µ
q−2
Z
1
0
f
′′
(B
s
)ds.
(1.23)(We re over (1.12) by hoosing
q = 2
). 3. WhenH =
1
4
andq
iseven,B, 2
−n/2
2
n
X
k=1
f (B
(k−1)2
−n
)
(2
n/4
∆B
k2
−n
)
q
− µ
q
!
Law
−→
B,
1
4
q
2
µ
q−2
Z
1
0
f
′′
(B
s
)ds
+e
σ
1/4,q
Z
1
0
f (B
s
)dW
s
,
(1.24)where
W
isastandardBrownianmotionindependentofB
ande
σ
1/4,q
isthe onstantgiven by (1.26) justbelow. 4. When1
4
< H <
3
4
andq
iseven,B, 2
−n/2
2
n
X
k=1
f (B
(k−1)2
−n
)
(2
nH
∆B
k2
−n
)
q
− µ
q
!
Law
−→
B, e
σ
H,q
Z
1
0
f (B
s
)dW
s
,
(1.25) forW
a standard Brownian motionindependentofB
and5. When
H =
3
4
andq
iseven,B,
√
1
n
2
−n/2
2
n
X
k=1
f (B
(k−1)2
−n
)
(2
nH
∆B
k2
−n
)
q
− µ
q
!
Law
−→
B, e
σ
3
4
,q
Z
1
0
f (B
s
)dW
s
,
(1.27) forW
a standard Brownian motionindependentofB
ande
σ
3
4
,q
=
v
u
u
t
q
X
p=2
2 log 2 p!
q
p
2
µ
2
q−p
1 −
1
2q
q
1 −
1
q
q
.
6. WhenH >
3
4
andq
iseven,2
n−2Hn
2
n
X
k=1
f (B
(k−1)2
−n
)
(2
nH
∆B
k2
−n
)
q
− µ
q
L
2
−→ 2µ
q−2
q
2
Z
1
0
f (B
s
)dZ
s
(2)
,
(1.28) forZ
(2)
the Hermite pro ess introdu ed in Denition 7.
Finally, we an also give a new proof of the following result, stated and proved by Gradinaruet al. [8℄and Cheriditoand Nualart[3℄in a ontinuous setting:
Theorem 4 Assume that
H >
1
6
, and thatf : R → R
veries (H
6
). Then the limit inprobability, as
n → ∞
, of the symmetri Riemannsums1
2
2
n
X
k=1
f
′
(B
k2
−n
) + f
′
(B
(k−1)2
−n
)
∆B
k2
−n
(1.29)existsand isgiven by
f (B
1
) − f(0)
. Remark 3 WhenH ≤
1
6
, quantity (1.29) does not onverge in probability in general. As a ounterexample, one an onsider the ase wheref (x) = x
3
, see Gradinaru et al. [8 ℄ or CheriditoandNualart [3 ℄.
2 Preliminaries and notation
Webrieyre allsomebasi fa tsaboutsto hasti al uluswithrespe ttoafra tionalBrownian motion. One refers to [19 ℄ for further details. Let
B = (B
t
)
t∈[0,1]
be a fra tional Brownian motionwithHurst parameterH ∈ (0, 1)
. That is,B
is azero meanGaussian pro ess,dened ona ompleteprobabilityspa e(Ω, A, P )
,withthe ovarian e fun tionR
H
(t, s) = E(B
t
B
s
) =
1
2
s
2H
+ t
2H
We suppose that
A
is the sigma-eld generated byB
. LetE
be the set of step fun tions on[0, T ]
,andH
bethe Hilbertspa edened asthe losureofE
withrespe tto theinner produ th1
[0,t]
, 1
[0,s]
i
H
= R
H
(t, s).
The mapping
1
[0,t]
7→ B
t
an be extendedto an isometry betweenH
and theGaussian spa eH
1
asso iatedwithB
. Wewill denote thisisometry byϕ 7→ B(ϕ)
.Let
S
be the setof allsmooth ylindri al randomvariables,i.e. ofthe formF = φ(B
t
1
, . . . , B
t
m
)
where
m ≥ 1
,φ : R
m
→ R ∈ C
∞
b
and0 ≤ t
1
< . . . < t
m
≤ 1
. Thederivative ofF
withrespe tto
B
istheelement ofL
2
(Ω, H)
dened byD
s
F =
m
X
i=1
∂φ
∂x
i
(B
t
1
, . . . , B
t
m
)1
[0,t
i
]
(s),
s ∈ [0, 1].
Inparti ularD
s
B
t
= 1
[0,t]
(s)
. For any integerk ≥ 1
, we denotebyD
k,2
the losure of theset ofsmooth randomvariables withrespe tto thenorm
kF k
2
k,2
= E(F
2
) +
k
X
j=1
E
kD
j
F k
2
H
⊗j
.
TheMalliavin derivative
D
satisesthe hain rule. Ifϕ : R
n
→ R
isC
1
b
and if(F
i
)
i=1,...,n
isa sequen eofelements ofD
1,2
,thenϕ(F
1
, . . . , F
n
) ∈ D
1,2
and we haveD ϕ(F
1
, . . . , F
n
) =
n
X
i=1
∂ϕ
∂x
i
(F
1
, . . . , F
n
)DF
i
.
Wealsohavethefollowingformula,whi h aneasilybeprovedbyindu tionon
q
. Letϕ, ψ ∈ C
q
b
(
q ≥ 1
),and x0 ≤ u < v ≤ 1
and0 ≤ s < t ≤ 1
. Thenϕ(B
t
− B
s
)ψ(B
v
− B
u
) ∈ D
q,2
andD
q
ϕ(B
t
− B
s
)ψ(B
v
− B
u
)
=
q
X
a=0
q
a
ϕ
(a)
(B
t
− B
s
)ψ
(q−a)
(B
v
− B
u
)1
⊗a
[s,t]
⊗1
e
⊗(q−a)
[u,v]
,
(2.30)where
⊗
e
meansthe symmetri tensor produ t.The divergen e operator
I
is the adjoint of the derivative operatorD
. If a random variableu ∈ L
2
(Ω, H)
belongs to thedomain of thedivergen e operator,that is, ifitsatises
|EhDF, ui
H
| ≤ c
u
p
E(F
2
)
for any
F ∈ S ,
then
I(u)
isdened bythe duality relationshipE F I(u)
= E hDF, ui
H
forevery
F ∈ D
1,2
.
For every
n ≥ 1
, letH
n
be then
th Wiener haos ofB,
that is, the losed linear subspa e ofL
2
(Ω, A, P )
generated by the random variables
{H
n
(B (h)) , h ∈ H, khk
H
= 1}
, whereH
n
is then
th Hermite polynomial. The mappingI
n
(h
⊗n
) = n!H
n
(B (h))
provides a linearisometrybetween thesymmetri tensor produ tH
⊙n
(equipped withthemodiednorm
k · k
H
⊙n
=
√
1
n!
k · k
H
⊗n
) andH
n
. ForH =
1
2
,I
n
oin ideswiththemultipleWiener-Itintegral ofordern
. Thefollowing dualityformulaholdsE (F I
n
(h)) = E hD
n
F, hi
H
⊗n
,
(2.31)foranyelement
h ∈ H
⊙n
and any randomvariable
F ∈ D
n,2
.
Let
{e
k
, k ≥ 1}
bea ompleteorthonormal systeminH
. Givenf ∈ H
⊙n
andg ∈ H
⊙m
,forevery
r = 0, . . . , n ∧ m
,the ontra tion off
andg
oforderr
is theelement ofH
⊗(n+m−2r)
dened byf ⊗
r
g =
∞
X
k
1
,...,k
r
=1
hf, e
k
1
⊗ . . . ⊗ e
k
r
i
H
⊗r
⊗ hg, e
k
1
⊗ . . . ⊗ e
k
r
i
H
⊗r
.
Noti e that
f ⊗
r
g
is not ne essarily symmetri : we denote its symmetrization byf e
⊗
r
g ∈
H
⊙(n+m−2r)
. We have the following produ tformula: iff ∈ H
⊙n
andg ∈ H
⊙m
thenI
n
(f )I
m
(g) =
n∧m
X
r=0
r!
n
r
m
r
I
n+m−2r
(f e
⊗
r
g).
(2.32)Were all the following simpleformulafor any
s < t
andu < v
:E ((B
t
− B
s
)(B
v
− B
u
)) =
1
2
|t − v|
2H
+ |s − u|
2H
− |t − u|
2H
− |s − v|
2H
.
(2.33)Wewill also need the following lemmas:
Lemma 5 1. Let
s < t
belong to[0, 1]
. Then,ifH < 1/2
, one hasE B
u
(B
t
− B
s
)
≤ (t − s)
2H
(2.34) for allu ∈ [0, 1]
. 2. For allH ∈ (0, 1)
,2
n
X
k,l=1
E B
(k−1)2
−n
∆B
l2
−n
= O(2
n
).
(2.35)3. For any
r ≥ 1
,we have, ifH < 1 −
4. For any
r ≥ 1
,we have, ifH = 1 −
1
2r
,2
n
X
k,l=1
|E (∆B
k2
−n
∆B
l2
−n
)|
r
= O(n2
2n−2rn
).
(2.37)Proof: Toprove inequality (2.34),we justwrite
E(B
u
(B
t
− B
s
)) =
1
2
(t
2H
− s
2H
) +
1
2
|s − u|
2H
− |t − u|
2H
,
andobservethatwe have
|b
2H
− a
2H
| ≤ |b − a|
2H
for any
a, b ∈ [0, 1]
,be auseH <
1
2
. Toshow (2.35 )using(2.33 ), we write2
n
X
k,l=1
E B
(k−1)2
−n
∆B
l2
−n
= 2
−2Hn−1
2
n
X
k,l=1
|l − 1|
2H
− l
2H
− |l − k + 1|
2H
+ |l − k|
2H
≤ C2
n
,
thelast bound oming from a teles oping sum argument. Finally, to show (2.36 ) and (2.37), wewrite
2
n
X
k,l=1
|E (∆B
k2
−n
∆B
l2
−n
)|
r
= 2
−2nrH−r
2
n
X
k,l=1
|k − l + 1|
2H
+ |k − l − 1|
2H
− 2|k − l|
2H
r
≤ 2
n−2nrH−r
∞
X
p=−∞
|p + 1|
2H
+ |p − 1|
2H
− 2|p|
2H
r
,
and observe that, sin e the fun tion
|p + 1|
2H
+ |p − 1|
2H
− 2|p|
2H
behavesas
C
H
p
2H−2
for large
p
,theseries intheright-handside is onvergent be auseH < 1 −
1
2r
. Inthe riti al aseH = 1 −
2r
1
,this series isdivergent,and2
n
X
p=−2
n
|p + 1|
2H
+ |p − 1|
2H
− 2|p|
2H
r
behavesasa onstant time
n
. Lemma 6 Assume thatH >
1
2
.1. Let
s < t
belong to[0, 1]
. ThenE B
u
(B
t
− B
s
)
≤ 2H(t − s)
(2.38)2. Assume that
H > 1 −
1
2l
for somel ≥ 1
. Letu < v
ands < t
belong to[0, 1]
. Then|E(B
u
− B
v
)(B
t
− B
s
)| ≤ H(2H − 1)
2
2Hl + 1 − 2l
1
l
(u − v)
l−1
l
(t − s).
(2.39) 3. Assume thatH > 1 −
1
2l
for somel ≥ 1
. Then2
n
X
i,j=1
E ∆B
i2
−n
∆B
j2
−n
l
= O(2
2n−2ln
).
(2.40) Proof: We haveE B
u
(B
t
− B
s
)
=
1
2
t
2H
− s
2H
+
1
2
|s − u|
2H
− |t − u|
2H
.
But,when0 ≤ a < b ≤ 1
:b
2H
− a
2H
= 2H
Z
b−a
0
(u + a)
2H−1
du ≤ 2H b
2H−1
(b − a) ≤ 2H(b − a).
Thus,|b
2H
− a
2H
| ≤ 2H|b − a|
and therstpoint follows.
Con erningthe se ond point, using Hölderinequality,we an write
|E(B
u
− B
v
)(B
t
− B
s
)| = H(2H − 1)
Z
v
u
Z
t
s
|y − x|
2H−2
dydx
≤ H(2H − 1)|u − v|
l−1
l
Z
1
0
Z
t
s
|y − x|
2H−2
dy
l
dx
!
1
l
≤ H(2H − 1)|u − v|
l−1
l
|t − s|
l−1
l
Z
1
0
Z
t
s
|y − x|
(2H−2)l
dydx
1
l
.
DenotebyH
′
= 1 + (H − 1)l
andobserve that
H
′
>
1
2
(be auseH > 1 −
1
2l
). Sin e2H
′
− 2 =
(2H − 2)l
,we anwriteH
′
(2H
′
− 1)
Z
1
0
Z
t
s
|y − x|
(2H−2)l
dydx = E
B
H
′
1
(B
H
′
t
− B
H
′
s
)
≤ 2H
′
|t − s|
bytherst point of thislemma. Thisgivesthedesired bound. Weprove nowthethird point. We have
andthefun tion
|k +1|
2H
+ |k −1|
2H
−2|k|
2H
behavesas
|k|
2H−2
forlarge
k
. Asa onsequen e, sin eH > 1 −
1
2l
,thesum2
n
−1
X
k=−2
n
+1
|k + 1|
2H
+ |k − 1|
2H
− 2|k|
2H
l
behavesas
2
(2H−2)ln+n
andthethird pointfollows.Now, let us introdu e the Hermite pro ess of order
q ≥ 2
appearing in (1.19 ). FixH > 1/2
andt ∈ [0, 1]
. The sequen eϕ
n
(t)
n≥1
,dened asϕ
n
(t) = 2
nq−n
1
q!
[2
n
t]
X
j=1
1
⊗q
[(j−1)2
−n
,j2
−n
]
,
isaCau hy sequen einthe spa e
H
⊗q
. Indeed,sin e
H > 1/2
,wehaveh1
[a,b]
, 1
[u,v]
i
H
= E (B
b
− B
a
)(B
v
− B
u
)
= H(2H − 1)
Z
b
a
Z
v
u
|s − s
′
|
2H−2
dsds
′
,
sothat,for any
m ≥ n
Denition 7 Fix
q ≥ 2
andH > 1/2
. The Hermite pro essZ
(q)
= (Z
(q)
t
)
t∈[0,1]
of orderq
is dened byZ
(q)
t
= I
q
(µ
(q)
t
)
fort ∈ [0, 1]
. LetZ
(q)
n
be thepro ess dened byZ
(q)
n
(t) = I
q
(ϕ
n
(t))
fort ∈ [0, 1]
. By onstru tion,it is lear thatZ
(q)
n
(t)
L
2
−→ Z
(q)
(t)
as
n → ∞
,forallxedt ∈ [0, 1]
. Ontheotherhand,itfollows,from Taqqu [21 ℄ and Dobrushin and Major [5℄, that
Z
(q)
n
onverges in law to the standard and histori alq
th Hermite pro ess, dened through its moving average representation as a multiple integral with respe t to a Wiener pro ess with time horizonR
. In parti ular, the pro essintrodu edinDenition7hasthesamenitedimensionaldistributionsasthehistori al Hermitepro ess.Letusnallymentionthatit anbeeasilyseenthat
Z
(q)
is
q(H −1)+1
self-similar,hasstationary in rements and admits moments of all orders. Moreover, it has Hölder ontinuous pathsoforder stri tly lessthan
q(H − 1) + 1
. For further results,werefer to Tudor [22 ℄.3 Proof of the main results
Inthisse tionwewill providethe proofsofthemain results. Fornotational onvenien e,from now on, we write
ε
(k−1)2
−n
(resp.δ
k2
−n
) insteadof1
[0,(k−1)2
−n
]
(resp.1
[(k−1)2
−n
,k2
−n
]
). The following proposition provides information on the asymptoti behaviorofE
V
n
(q)
(f )
2
,as
n
tendsto innity, forH ≤ 1 −
1
2q
.Proposition 8 Fix an integer
q ≥ 2
. Suppose thatf
satises (H
q
). Then,ifH ≤
1
2q
, thenE
V
n
(q)
(f )
2
= O(2
n(−2Hq+2)
).
(3.41) If1
2q
≤ H < 1 −
2q
1
, thenE
V
n
(q)
(f )
2
= O(2
n
).
(3.42) Finally,ifH = 1 −
1
2q
, thenE
V
n
(q)
(f )
2
= O(n2
n
).
(3.43)Proof. Using the relation between Hermite polynomials and multiple sto hasti integrals, we have
H
q
2
nH
∆B
k2
−n
=
q!
1
2
qnH
I
q
δ
k2
⊗q
−n
. Inthis waywe obtain
tionship(2.31 )between themultiplesto hasti integral
I
N
andtheiteratedderivativeoperatorD
N
,obtainingE
V
n
(q)
(f )
2
=
2
2Hqn
q!
2
2
n
X
k,l=1
q
X
r=0
r!
q
r
2
×E
n
f (B
(k−1)2
−n
) f (B
(l−1)2
−n
) I
2q−2r
δ
⊗q−r
k2
−n
⊗δ
e
l2
⊗q−r
−n
o
hδ
k2
−n
, δ
l2
−n
i
r
H
= 2
2Hqn
2
n
X
k,l=1
q
X
r=0
1
r!(q − r)!
2
×E
nD
D
2q−2r
f (B
(k−1)2
−n
) f (B
(l−1)2
−n
)
, δ
k2
⊗q−r
−n
⊗δ
e
⊗q−r
l2
−n
E
H
⊗(2q−2r)
o
hδ
k2
−n
, δ
l2
−n
i
r
H
,
where
⊗
e
denotes the symmetrization of the tensor produ t. By (2.30 ), the derivative of the produ tD
2q−2r
f (B
(k−1)2
−n
) f (B
(l−1)2
−n
)
isequal to a sumof derivatives:D
2q−2r
f (B
(k−1)2
−n
) f (B
(l−1)2
−n
)
=
X
a+b=2q−2r
f
(a)
(B
(k−1)2
−n
) f
(b)
(B
(l−1)2
−n
)
×
(2q − 2r)!
a!b!
ε
⊗a
(k−1)2
−n
⊗ε
e
⊗b
(l−1)2
−n
.
Wemake thede omposition
D
n
= 2
2Hqn
q
X
r=1
X
a+b=2q−2r
2
n
X
k,l=1
E
n
f
(a)
(B
(k−1)2
−n
) f
(b)
(B
(l−1)2
−n
)
o
(2q − 2r)!
r!(q − r)!
2
a!b!
×hε
⊗a
(k−1)2
−n
⊗ε
e
⊗b
(l−1)2
−n
, δ
k2
⊗q−r
−n
⊗δ
e
⊗q−r
l2
−n
i
H
⊗(2q−2r)
hδ
k2
−n
, δ
l2
−n
i
r
H
,
for some ombinatorial onstants
α(c, d, e, f )
. That is,A
n
andB
n
ontain all thetermswithr = 0
and(a, b) = (q, q)
;C
n
ontains thetermswithr = 0
and(a, b) 6= (q, q)
;andD
n
ontainstheremaining terms.
For anyinteger
r ≥ 1
,we setα
n
=
sup
k,l=1,...,2
n
hε
(k−1)2
−n
, δ
l2
−n
i
H
,
(3.45)β
r,n
=
2
n
X
k,l=1
hδ
k2
−n
, δ
l2
−n
i
H
r
,
(3.46)γ
n
=
2
n
X
k,l=1
hε
(k−1)2
−n
, δ
l2
−n
i
H
.
(3.47)Then, underassumption (
H
q
), wehave the following estimates:|A
n
| ≤ C2
2Hqn+2n
(α
n
)
2q
,
|B
n
| + |C
n
| ≤ C2
2Hqn
(α
n
)
2q−1
γ
n
,
|D
n
| ≤ C2
2Hqn
q
X
r=1
(α
n
)
2q−2r
β
r,n
,
where
C
isa onstantdependingonlyonq
andthefun tionf
. Noti ethatthese ondinequality follows from the fa tthat when(a, b) 6= (q, q)
, or(a, b) = (q, q)
andc + d + e + f = 2q
withd ≥ 1
ore ≥ 1
,there will be at least a fa tor of theformhε
(k−1)2
−n
, δ
l2
−n
i
H
intheexpression ofB
n
orC
n
.Inthe ase
H <
1
2
,wehaveby(2.34 )thatα
n
≤ 2
−2nH
,by(2.36 )thatβ
r,n
≤ C2
n−2rHn
, andby(2.35 )thatγ
n
≤ C2
n
. Asa onsequen e,we obtain|A
n
| ≤ C2
n(−2Hq+2)
,
(3.48)|B
n
| + |C
n
| ≤ C2
n(−2Hq+2H+1)
,
(3.49)|D
n
| ≤ C
q
X
r=1
2
n(−2(q−r)H+1)
,
(3.50)In the ase
1
2
≤ H < 1 −
2q
1
, we have by (2.38 ) thatα
n
≤ C2
−n
, by (2.36 ) thatβ
r,n
≤ C2
n−2rHn
,andby(2.35 )thatγ
n
≤ C2
n
. Asa onsequen e,we obtain|A
n
| + |B
n
| + |C
n
| ≤ C2
n(2q(H−1)+2)
,
|D
n
| ≤ C
q
X
r=1
2
n((2q−2r)(H−1)+1)
,
whi h also implies(3.42). Finally, if
H = 1 −
1
2q
, we have by (2.38 ) thatα
n
≤ C2
−n
, by (2.37 ) thatβ
r,n
≤
Cn2
2n−2rn
,and by(2.35 )thatγ
n
≤ C2
n
. Asa onsequen e, we obtain|A
n
| + |B
n
| + |C
n
| ≤ C2
n
,
|D
n
| ≤ C
q
X
r=1
n2
n
q
r
,
whi h implies(3.43 ).3.1 Proof of Theorem 1 in the ase
0
< H <
1
2q
Inthis subse tion we aregoing to prove the rst point of Theorem 1. The proof will be done in three steps. Set
V
(q)
1,n
(f ) = 2
n(qH−1)
V
(q)
n
(f )
. We rst study the asymptoti behavior ofE
V
1,n
(q)
(f )
2
,using Proposition8.Step 1. Thede omposition(3.44 )leads to
E
V
1,n
(q)
(f )
2
= 2
2n(qH−1)
(A
n
+ B
n
+ C
n
+ D
n
) .
From the estimate (3.49 ) we obtain
2
2n(qH−1)
(|B
n
| + |C
n
|) ≤ C2
n(2H−1)
,
whi h onverges tozeroas
n
goesto innitysin eH <
1
2q
<
1
2
. Ontheother hand(3.50 )yields2
2n(qH−1)
|D
n
| ≤ C
q
X
r=1
2
n(2rH−1)
,
2
4Hqn−2n
q!
2
2
n
X
k,l=1
E
n
f
(q)
(B
(k−1)2
−n
) f
(q)
(B
(l−1)2
−n
)
o
hε
(k−1)2
−n
, δ
k2
−n
i
q
H
hε
(l−1)2
−n
, δ
l2
−n
i
q
H
−
2
−2n−2q
q!
2
2
n
X
k,l=1
E
n
f
(q)
(B
(k−1)2
−n
) f
(q)
(B
(l−1)2
−n
)
o
≤ C2
2Hn−n
,
whi h implies, asn → ∞
:E V
1,n
(q)
(f )
2
=
2
−2n−2q
q!
2
2
n
X
k,l=1
E
n
f
(q)
(B
(k−1)2
−n
) f
(q)
(B
(l−1)2
−n
)
o
+ o(1).
(3.52)Step 2: Weneed theasymptoti behaviorof thedoubleprodu t
J
n
:= E
V
1,n
(q)
(f ) × 2
−n
2
n
X
l=1
f
(q)
(B
(l−1)2
−n
)
!
.
Usingthesame argumentsasinStep1 we obtain
J
n
= 2
Hqn−2n
2
n
X
k,l=1
E
n
f (B
(k−1)2
−n
) f
(q)
(B
(l−1)2
−n
) H
q
2
nH
∆B
k2
−n
o
=
1
q!
2
2Hqn−2n
2
n
X
k,l=1
E
n
f (B
(k−1)2
−n
) f
(q)
(B
(l−1)2
−n
) I
q
δ
⊗q
k2
−n
o
=
1
q!
2
2Hqn−2n
2
n
X
k,l=1
E
nD
D
q
f (B
(k−1)2
−n
) f
(q)
(B
(l−1)2
−n
)
, δ
k2
⊗q
−n
E
H
⊗q
o
= 2
2Hqn−2n
2
n
X
k,l=1
q
X
a=0
1
a!(q − a)!
E
n
f
(a)
(B
(k−1)2
−n
) f
(2q−a)
(B
(l−1)2
−n
)
o
×hε
(k−1)2
−n
, δ
k2
−n
i
H
a
hε
(l−1)2
−n
, δ
k2
−n
i
q−a
H
.
It turns out thatonly the term with
a = q
will ontribute to the limit asn
tends to innity. For thisreason we make thede omposition|S
n
| ≤ C2
2Hn−n
,
whi h tends tozero as
n
goesto innity. Moreover, by(3.51 ), we have2
2Hqn−2n
q!
2
n
X
k,l=1
E
n
f
(q)
(B
(k−1)2
−n
) f
(q)
(B
(l−1)2
−n
)
o
hε
(k−1)2
−n
, δ
k2
−n
i
q
H
−(−1)
q
2
−2n−q
q!
2
n
X
k,l=1
E
n
f
(q)
(B
(k−1)2
−n
) f
(q)
(B
(l−1)2
−n
)
o
≤ C 2
2Hn−n
,
whi h also tendsto zeroas
n
goesto innity. Thus,nally, asn → ∞
:J
n
= (−1)
q
2
−2n−q
q!
2
n
X
k,l=1
E
n
f
(q)
(B
(k−1)2
−n
) f
(q)
(B
(l−1)2
−n
)
o
+ o(1).
(3.53)Step 3: By ombining (3.52 )and (3.53 ),weobtain that
E
V
(q)
1,n
(f ) −
(−1)
q
2
q
q!
2
−n
2
n
X
k=1
f
(q)
(B
(k−1)2
−n
)
2
= o(1),
as
n → ∞
. Thus, the proof of the rst point of Theorem 1 is done using a Riemann sumargument.
3.2 Proof of Theorem 1 in the ase
H > 1
−
1
2q
: the weighted non- entral limit theoremWeprove here thatthesequen e
V
3,n
(f )
,given byV
3,n
(q)
(f ) = 2
n(1−H)q−n
V
n
(q)
(f ) = 2
qn−n
1
q!
2
n
X
k=1
f B
(k−1)2
−n
I
q
δ
k2
⊗q
−n
,
onverges inL
2
as
n → ∞
to the pathwiseintegralR
1
0
f (B
s
)dZ
(q)
s
withrespe tto theHermite pro ess of orderq
introdu ed inDenition 7.Observerstthat,by onstru tionof
Z
(q)
(pre isely,seethedis ussionbeforeDenition 7 in Se tion 2), the desired result is in order when the fun tion
f
is identi ally one. More pre isely:Lemma 9 For ea h xed
t ∈ [0, 1]
, the sequen e2
qn−n 1
q!
P
[2
n
t]
k=1
I
q
δ
k2
⊗q
−n
onverges inL
2
to the Hermite random variableZ
Now, onsider the ase of a general fun tion
f
. We x two integersm ≥ n
, and de omposethe sequen eV
(q)
3,m
(f )
asfollows:V
3,m
(q)
(f ) = A
(m,n)
+ B
(m,n)
,
whereA
(m,n)
=
1
q!
2
m(q−1)
2
n
X
j=1
f B
(j−1)2
−n
j2
X
m−n
i=(j−1)2
m−n
+1
I
q
δ
i2
⊗q
−m
,
andB
(m,n)
=
1
q!
2
m(q−1)
2
n
X
j=1
j2
m−n
X
i=(j−1)2
m−n
+1
∆
m,n
i,j
f (B) I
q
δ
i2
⊗q
−m
,
withthenotation
∆
m,n
i,j
f (B) = f (B
(i−1)2
−m
) − f(B
(j−1)2
−n
)
. WeshallstudyA
(m,n)
andB
(m,n)
separately. Study ofA
(m,n)
. When
n
isxed, Lemma 9 yields thattherandom ve tor
1
q!
2
m(q−1)
j2
m−n
X
i=(j−1)2
m−n
+1
I
q
δ
i2
⊗q
−m
; j = 1, . . . , 2
n
onverges inL
2
,asm → ∞
,tothe ve torZ
j2
(q)
−n
− Z
(q)
(j−1)2
−n
; j = 1, . . . , 2
n
.
Then, asm → ∞
,A
(m,n) L
→ A
2
(∞,n)
,whereA
(∞,n)
:=
2
n
X
j=1
f (B
(j−1)2
−n
)
Z
j2
(q)
−n
− Z
(q)
(j−1)2
−n
.
Finally, we laim that when
n
tends to innity,A
(∞,n)
onverges inL
2
toR
1
0
f (B
s
) dZ
(q)
s
. Indeed, observe that the sto hasti integralR
1
0
f (B
s
) dZ
(q)
s
is a pathwise Young integral. So, to getthe onvergen e inL
2
itsu es to showthat the sequen e
A
(∞,n)
isbounded in
L
p
for
some
p ≥ 2
. The integralR
1
0
f (B
s
) dZ
(q)
s
hasmomentsof allorders, be ause for allp ≥ 2
if
γ < q(H − 1) + 1
andβ < H
. Onthe other hand,Young's inequalityimpliesA
(∞,n)
−
Z
1
0
f (B
s
) dZ
s
(q)
≤ c
ρ,ν
Var
ρ
f (B)
Var
ν
Z
(q)
,
where
Var
ρ
denotes the variation of orderρ
,andwithρ, ν > 1
su hthat1
ρ
+
1
ν
> 1
. Choosingρ >
H
1
andν >
1
q(H−1)+1
,theresultfollows.This proves that, by letting
m
and thenn
go to innity,A
(m,n)
onverges inL
2
toR
1
0
f (B
s
) dZ
(q)
s
.
Study of the term
B
(m,n)
: We provethatlim
n→∞
sup
m
E
B
(m,n)
2
= 0.
(3.54)Wehave, usingthe produ tformula(2.32) for multiplesto hasti integrals,
E
B
(m,n)
2
= 2
2m(q−1)
2
n
X
j=1
j2
m−n
X
i=(j−1)2
m−n
+1
2
n
X
j
′
=1
j
′
2
m−n
X
i
′
=(j
′
−1)2
m−n
+1
q
X
l=0
l!
q!
2
q
l
2
×b
(m,n)
l
hδ
i2
−m
, δ
i
′
2
−m
i
l
H
,
(3.55) whereb
(m,n)
l
= E
∆
m,n
i,j
f (B)∆
m,n
i
′
,j
′
f (B)I
2(q−l)
δ
i2
⊗(q−l)
−m
⊗δ
e
i
⊗(q−l)
′
2
−m
.
(3.56)By(2.31) and (2.30 ),we obtain that
b
(m,n)
l
isequal toE
D
D
2(q−l)
∆
m,n
i,j
f (B)∆
m,n
i
′
,j
′
f (B)
, δ
i2
⊗(q−l)
−m
⊗δ
e
i
⊗(q−l)
′
2
−m
E
H
⊗2(q−l)
=
2q−2l
X
a=0
2q − 2l
a
D
E
f
(a)
(B
(i−1)2
−m
)ε
⊗a
(i−1)2
−m
− f
(a)
(B
(j−1)2
−n
)ε
⊗a
(j−1)2
−n
e
⊗
f
(2q−2l−a)
(B
(i
′
−1)2
−m
)ε
⊗b
(i
′
−1)2
−m
− f
(2q−2l−a)
(B
(j
′
−1)2
−n
)ε
⊗b
(j
′
−1)2
−m
, δ
i2
⊗(q−l)
−m
⊗δ
e
i
⊗(q−l)
′
2
−m
E
H
⊗2(q−l)
.
Theterm in(3.55 ) orrespondingtol = q
anbe estimatedby1
q!
2
2m(q−1)
sup
|x−y|≤2
−n
E |f(B
x
) − f(B
y
)|
2
β
q,m
,
where
β
q,m
hasbeenintrodu edin(3.46 ). Soit onvergestozeroasn
tendstoinnity,uniformly inm
,be ause, by(2.40 )and usingthatH > 1 −
Inorderto handle thetermswith
0 ≤ l ≤ q − 1
,we makethe de ompositionb
(m,n)
l
≤
2q−2l
X
a=0
2q − 2l
a
X
4
h=1
B
h
,
(3.57) whereB
1
= E
∆
m,n
i,j
f (B)∆
m,n
i
′
,j
′
f (B)
D
ε
⊗a
(i−1)2
−m
⊗ε
e
⊗(2q−2l−a)
(i
′
−1)2
−m
, δ
i2
⊗(q−l)
−m
⊗δ
e
i
⊗(q−l)
′
2
−m
E
H
⊗2(q−l)
,
B
2
= E
f
(a)
(B
(j−1)2
−n
)∆
m,n
i
′
,j
′
f (B)
×
D
ε
⊗a
(i−1)2
−m
− ε
⊗a
(j−1)2
−n
e
⊗ε
⊗(2q−2l−a)
(i
′
−1)2
−m
, δ
i2
⊗(q−l)
−m
⊗δ
e
⊗(q−l)
i
′
2
−m
E
H
⊗2(q−l)
,
B
3
= E
∆
m,n
i,j
f (B)f
(2q−2l−a)
(B
(j
′
−1)2
−n
)
×
D
ε
⊗a
(i−1)2
−m
⊗
e
ε
⊗(2q−2l−a)
(i
′
−1)2
−m
− ε
⊗(2q−2l−a)
(j
′
−1)2
−n
, δ
⊗(q−l)
i2
−m
⊗δ
e
i
⊗(q−l)
′
2
−m
E
H
⊗2(q−l)
,
B
4
= E
f
(a)
(B
(j−1)2
−n
)f
(2q−2l−a)
(B
(j
′
−1)2
−n
)
×
D
ε
⊗a
(i−1)2
−m
− ε
⊗a
(j−1)2
−n
e
⊗
ε
⊗(2q−2l−a)
(i
′
−1)2
−m
− ε
⊗(2q−2l−a)
(j
′
−1)2
−n
, δ
i2
⊗(q−l)
−m
⊗δ
e
i
⊗(q−l)
′
2
−m
E
H
⊗2(q−l)
.
(3.58) By using (2.38 ) and the onditions imposed on the fun tionf
,one an bound the termsB
1
,B
2
andB
3
asfollows:|B
1
| ≤ c(q, f, H)
sup
|x−y|≤
2n
1
,0≤a≤2q
E
f
(a)
(B
x
) − f
(a)
(B
y
)
2
2
−2m(q−l)
,
|B
2
| + |B
3
| ≤ c(q, f, H)
sup
|x−y|≤
2n
1
,0≤a≤2q
E
f
(2q−2l−a)
(B
x
) − f
(2q−2l−a)
(B
y
)
2
−2m(q−l)
,
and,byusing (2.39 ),weobtain that
E
B
(m,n)
2
≤ R
n
+ c(H, f, q)2
2m(q−1)
sup
|x−y|≤
1
2n
,0≤a≤2q
f
(2q−2l−a)
(B
x
) − f
(2q−2l−a)
(B
y
)
+ (2
−n
)
q−1
q
!
×
2
n
X
j=1
j2
m−n
X
i=(j−1)2
m−n
+1
2
n
X
j
′
=1
j
′
2
m−n
X
i
′
=(j
′
−1)2
m−n
+1
q−1
X
l=0
2
−2m(q−l)
hδ
i2
−m
, δ
i
′
2
−m
i
l
H
≤ R
n
+ c(H, f, q)2
2m(q−1)
sup
|x−y|≤
1
2n
,0≤a≤2q
f
(2q−2l−a)
(B
x
) − f
(2q−2l−a)
(B
y
)
+ (2
−n
)
q−1
q
!
×
q−1
X
l=0
2
−2m(q−l)
2
m
X
i,j=0
hδ
i2
−m
, δ
i
′
2
−m
i
l
H
≤ R
n
+ c(H, f, q)
sup
|x−y|≤
2n
1
,0≤a≤2q
f
(2q−2l−a)
(B
x
) − f
(2q−2l−a)
(B
y
)
+ (2
−n
)
q−1
q
!
andthis onverges to zerodue to the ontinuity of
B
andsin eq > 1
. 3.3 Proof of Theorem 1 in the ase1
2q
< H
≤ 1 −
1
2q
: the weighted entral limit theoremSuppose rst that
1
2q
< H < 1 −
2q
1
. We study the onvergen e in law of the sequen eV
2,n
(q)
(f ) = 2
−
n
2
V
n
(q)
(f )
. We xtwo integersm ≥ n
,and de omposethis sequen e asfollows:V
2,m
(q)
(f ) = A
(m,n)
+ B
(m,n)
,
whereA
(m,n)
= 2
−
m
2
2
n
X
j=1
f B
(j−1)2
−n
j2
X
m−n
i=(j−1)2
m−n
+1
H
q
2
mH
∆B
i2
−m
,
andB
(m,n)
=
1
q!
2
m(Hq−
1
2
)
2
n
X
j=1
j2
m−n
X
i=(j−1)2
m−n
+1
∆
m,n
i,j
f (B)I
q
δ
⊗q
i2
−m
,
andwhere asbeforewe makeuseof thenotation
∆
m,n
i,j
f (B) = f (B
(i−1)2
−m
) − f(B
(j−1)2
−n
)
.Letus rst onsider the term
A
(m,n)
. From Theorem 1 in Breuer and Major [1℄, and takinginto a ount that