http://uoft.me/MAT334-LEC0101
LINE INTEGRALS
September 28th, 2020 and September 30th, 2020
Curves – 1
• A (complex)curveis a continuous function𝛾 ∶ [𝑎, 𝑏] → ℂwhere𝑎 < 𝑏. We say that𝛾(𝑎)is thestart-pointof𝛾and that𝛾(𝑏)is itsend-point.
Careful: it is quite common to designate by ”curve” either the function𝛾or its range𝛾([𝑎, 𝑏]).
• We say that a curve𝛾 ∶ [𝑎, 𝑏] → ℂissimpleif it doesn’t admit double points (i.e.
self-intersections), except maybe𝛾(𝑎) = 𝛾(𝑏), formally
(𝑎 ≤ 𝑡1< 𝑡2≤ 𝑏and𝛾(𝑡1) = 𝛾(𝑡2)) ⟹ (𝑡1= 𝑎and𝑡2= 𝑏)
• We say that a curve𝛾 ∶ [𝑎, 𝑏] → ℂisclosedif𝛾(𝑎) = 𝛾(𝑏).
Closed, simple. Not closed, simple.
Closed, not simple. Not closed, not simple.
Curves – 3
Jordan curve theorem – /ʒɔʀdã/
If𝛾 ∶ [𝑎, 𝑏] → ℂis a simple closed curve thenℂ ⧵ 𝛾 ([𝑎, 𝑏])consists of two disjoints open connected sets, one bounded (the inside) and one unbounded (the outside).
Outside Inside
This result seemsobvious, nonetheless it is quite difficult to prove (note that we only assume that 𝛾is continuous, so the curve can be quite nasty, e.g. Koch snowflake).
• We say that a curve𝛾 ∶ [𝑎, 𝑏] → ℂissmoothif𝛾is𝒞1.
Here𝛾is a function of a real variable, so by𝒞1, I mean thatℜ(𝛾)andℑ(𝛾)are𝒞1as real functions.
• We say that a curve𝛾 ∶ [𝑎, 𝑏] → ℂispiecewise-smoothif there exist𝑡0, … , 𝑡𝑛∈ [𝑎, 𝑏]such that𝑎 = 𝑡0< 𝑡1< ⋯ < 𝑡𝑛= 𝑏and𝛾is𝒞1on(𝑡𝑘, 𝑡𝑘+1)for𝑘 = 0, … , 𝑛 − 1.
Figure:A piecewise-smooth curve.
Curves – 5
Definition: concatenation/sum
Given two curves𝛾1∶ [𝑎1, 𝑏1] → ℂand𝛾2∶ [𝑎2, 𝑏2] → ℂsuch that𝛾1(𝑏1) = 𝛾2(𝑎2), we define the concatenation(orsum) of𝛾1and𝛾2by(𝛾1+ 𝛾2) ∶ [𝑎1, 𝑏1+ 𝑏2− 𝑎2] → ℂwhere
(𝛾1+ 𝛾2)(𝑡) ≔ {
𝛾1(𝑡) if𝑡 ∈ [𝑎1, 𝑏1]
𝛾2(𝑡 + 𝑎2− 𝑏1) if𝑡 ∈ [𝑏1, 𝑏1+ 𝑏2− 𝑎2] It is obviously a curve, i.e. it is continuous.
𝛾1(𝑎1)
𝛾1(𝑏1) = 𝛾2(𝑎2)
𝛾2(𝑏2)
𝛾1
𝛾2
𝛾1(𝑏1) = 𝛾2(𝑎2)
𝛾1(𝑎1) = 𝛾2(𝑏2)
𝛾1
𝛾2
Proposition
If𝛾1and𝛾2are piecewise-smooth then so is(𝛾1+ 𝛾2).
CAREFUL
It is possible for𝛾1and𝛾2to be smooth but for(𝛾1+ 𝛾2)not to be smooth, but only piecewise-smooth, since it may not be smooth at thegluing point.
𝛾1(𝑎1)
𝛾1(𝑏1) = 𝛾2(𝑎2)
𝛾2(𝑏2)
Curves – 7
Curves are naturally oriented by the usual orientation of[𝑎, 𝑏]:𝛾goes from𝛾(𝑎)to𝛾(𝑏).
Definition: reversed curve
For a curve𝛾 ∶ [𝑎, 𝑏] → ℂwe define(−𝛾) ∶ [𝑎, 𝑏] → ℂby(−𝛾)(𝑡) ≔ 𝛾(𝑎 + 𝑏 − 𝑡).
It is the same curve but with reversed orientation: it is traversed from𝛾(𝑏)to𝛾(𝑎).
𝛾
𝛾(𝑎) 𝛾(𝑏)
−𝛾
𝛾(𝑎) 𝛾(𝑏)
Definition: positive orientation (closed simple curves)
We say that a simple closed curve𝛾ispositively orientedif𝛾keeps its inside on its left.
Figure:A positively oriented simple closed curve Figure:A simple closed curve which is NOT positively oriented
Curves – 9
Examples
• 𝛾 ∶ [0, 1] → ℂ,𝛾(𝑡) = (1 − 𝑡)𝑧0+ 𝑡𝑧1.
𝑧0
𝑧1
• 𝛾 ∶ [0, 1] → ℂ,𝛾(𝑡) = 𝑒𝑖𝜋𝑡.
Example
Pick𝜀 ∈ (0, 1)and set𝛾 = 𝛾1+ 𝛾2+ 𝛾3+ 𝛾4where
• 𝛾1∶ [0, 𝜋] → ℂ,𝛾1(𝑡) = 𝑒𝑖𝑡.
• 𝛾2∶ [−1, −𝜀] → ℂ,𝛾2(𝑡) = 𝑡.
• 𝛾3∶ [0, 𝜋] → ℂ,𝛾3(𝑡) = 𝜀𝑒𝑖(𝜋−𝑡).
• 𝛾4∶ [𝜀, 1] → ℂ,𝛾4(𝑡) = 𝑡.
ℜ ℑ
Integrals
Definition
For𝑓 ∶ [𝑎, 𝑏] → ℂcontinuous we set
∫
𝑏 𝑎
𝑓 (𝑡)d𝑡 ≔
∫
𝑏 𝑎
ℜ(𝑓 (𝑡))d𝑡 + 𝑖
∫
𝑏 𝑎
ℑ(𝑓 (𝑡))d𝑡
Propositions
For𝑓 ∶ [𝑎, 𝑏] → ℂcontinuous,
ℜ(∫
𝑏 𝑎
𝑓 (𝑡)d𝑡 )=
∫
𝑏 𝑎
ℜ(𝑓 (𝑡))d𝑡
ℑ(∫
𝑏 𝑎
𝑓 (𝑡)d𝑡 )=
∫
𝑏 𝑎
ℑ(𝑓 (𝑡))d𝑡
Definition: line integral
Let𝑆 ⊂ ℂand𝑓 ∶ 𝑆 → ℂbe continuous. Let𝛾 ∶ [𝑎, 𝑏] → ℂbe a piecewise-smooth curve such that𝛾([𝑎, 𝑏]) ⊂ 𝑆. Pick a subdivision𝑎 = 𝑡0< 𝑡1< ⋯ < 𝑡𝑛= 𝑏of[𝑎, 𝑏]such that𝛾is𝐶1on(𝑡𝑘, 𝑡𝑘+1) then theline integral of𝑓 along𝛾is defined by
∫𝛾𝑓 (𝑧)d𝑧 ≔
𝑘−1
∑𝑘=0∫
𝑡𝑘+1 𝑡𝑘
𝑓 (𝛾(𝑡))𝛾′(𝑡)d𝑡
It doesn’t depend on the choice of the subdivision: any subdivision as above gives the same value for∫𝛾𝑓.
If𝛾is smooth, we can simply write
∫𝛾𝑓 (𝑧)d𝑧 =
∫
𝑏 𝑎
𝑓 (𝛾(𝑡))𝛾′(𝑡)d𝑡
Line integrals – 2
Proposition
• ∫−𝛾𝑓 = −
∫𝛾𝑓
• ∫𝛾
1+𝛾2
𝑓 =∫𝛾
1
𝑓 +∫𝛾
2
𝑓
• ∫𝛾𝛼𝑓 + 𝛽𝑔 = 𝛼
∫𝛾𝑓 + 𝛽
∫𝛾𝑔, 𝛼, 𝛽 ∈ ℂ
Homework
Prove the above properties.
Theorem: reparametrization
Let𝛾1∶ [𝑎1, 𝑏1] → ℂand𝛾2∶ [𝑎2, 𝑏2] → ℂbe two curves.
Assume that𝛾1= 𝛾2∘ 𝜑where𝜑 ∶ [𝑎1, 𝑏1] → [𝑎2, 𝑏2]is a𝒞1-diffeomorphism, then
• If𝜑is increasing then
∫𝛾
1
𝑓 =∫𝛾
2
𝑓,and we say that𝜑preserves the orientation.
• If𝜑is decreasing then
∫𝛾
1
𝑓 = −
∫𝛾
2
𝑓,and we say that𝜑reverses the orientation.
Line integrals – 4
Definition: length (or arclength) of a curve
The(arc)lengthof a piecewise smooth1curve𝛾 ∶ [𝑎, 𝑏] → ℂislength(𝛾) ≔
𝑛−1
∑𝑘=0∫
𝑡𝑘+1
𝑡𝑘 |𝛾′(𝑡)|d𝑡.
Proposition
If𝛾 ∶ [𝑎, 𝑏] → ℂis a smooth curve thenlength(𝛾) =
∫
𝑏
𝑎 |𝛾′(𝑡)|d𝑡.
Proposition
Let𝑆 ⊂ ℂ,𝑓 ∶ 𝑆 → ℂcontinuous. Let𝛾 ∶ [𝑎, 𝑏] → ℂbe a piecewise-smooth curve such that 𝛾([𝑎, 𝑏]) ⊂ 𝑆 then
|∫𝛾𝑓 (𝑧)d𝑧
|≤(max
𝛾([𝑎,𝑏])|𝑓 |)length(𝛾)
The max is achieved since𝛾([𝑎, 𝑏])is compact and|𝑓 |continuous.
1A continuous curve may not be rectifiable, e.g. Koch snowflake.
Green’s theorem (real version)
Let𝑆 ⊂ ℝ2be a regular region with a piecewise smooth boundary𝜕𝑆which is assumed to be positively oriented.
LetF∶ 𝑈 → ℝ2be a𝒞1-vector field where𝑈 ⊂ ℝ2is open and𝑆 ⊂ 𝑈.
Then
∫𝜕𝑆F⋅dx=
∬𝑆(
𝜕𝐹2
𝜕𝑥 −𝜕𝐹1
𝜕𝑦 )d𝑥d𝑦 or using the other notation for the line integral of a vector field
∫𝜕𝑆𝑃d𝑥 + 𝑄d𝑦 =
∬𝑆(
𝜕𝑄
𝜕𝑥 −𝜕𝑃
𝜕𝑦 )d𝑥d𝑦
I suggest you to review the details of Green’s theorem from your multivariable calculus course.
See for instance:
http://www.math.toronto.edu/campesat/ens/1920/0310-notes.pdf
The real Green’s theorem (from multivariable calculus) – 2
• 𝑆regular region means that𝑆is bounded and that𝑆 = 𝑆,̊
or equivalently that𝑆is bounded and that∀𝑢 ∈ 𝜕𝑆, ∀𝑟 > 0, 𝐷𝑟(𝑢) ∩ ̊𝑆 ≠ ∅.
• 𝜕𝑆positively oriented means that each piece of𝜕𝑆is parametrized by a closed simple curve such that the interior𝑆̊is on its left.
𝛾1
𝛾2
𝛾3
• If𝜕𝑆 = 𝛾1∪ 𝛾2∪ ⋯ ∪ 𝛾ℓthen
∫𝜕𝑆 =
∫𝛾
1
+ ⋯ +
∫𝛾
ℓ
.
Green’s theorem (complex version) - 1
Let𝑆 ⊂ ℂbe a regular region with a piecewise smooth boundary𝜕𝑆which is assumed to be positively oriented.
Let𝑈 ⊂ ℂopen such that𝑆 ⊂ 𝑈.
Let𝑓 ∶ 𝑈 → ℂbe such that(𝑥, 𝑦) ↦ (ℜ(𝑓 ), ℑ(𝑓 ))is𝒞1in the real sense (i.e. as a real multivariable function).
Then,
∫𝜕𝑆𝑓 (𝑧)d𝑧 = 𝑖
∬𝑆(
𝜕𝑓
𝜕𝑥 + 𝑖𝜕𝑓
𝜕𝑦 )d𝑥d𝑦 where
𝜕𝑓
𝜕𝑥 ≔ 𝜕ℜ(𝑓 )
𝜕𝑥 + 𝑖𝜕ℑ(𝑓 )
𝜕𝑥
and 𝜕𝑓
𝜕𝑦 ≔ 𝜕ℜ(𝑓 )
𝜕𝑦 + 𝑖𝜕ℑ(𝑓 )
𝜕𝑦 Homework: check it!
The complex Green’s theorem – version 2
Green’s theorem (complex version) - 2
Let𝑆 ⊂ ℂbe a regular region with a piecewise smooth boundary𝜕𝑆which is assumed to be positively oriented.
Let𝑈 ⊂ ℂopen such that𝑆 ⊂ 𝑈.
Let𝑓 ∶ 𝑈 → ℂbe such that(𝑥, 𝑦) ↦ (ℜ(𝑓 ), ℑ(𝑓 ))is𝒞1in the real sense (i.e. as a real multivariable function).
Then,
∫𝜕𝑆𝑓 (𝑧)d𝑧 = 2𝑖
∬𝑆
𝜕𝑓
𝜕𝑧 d𝑥d𝑦 where
𝜕𝑓
𝜕𝑧 ≔ 1 2 (
𝜕𝑓
𝜕𝑥 + 𝑖𝜕𝑓
𝜕𝑦 ) and
𝜕𝑓
𝜕𝑧 ≔ 1 2 (
𝜕𝑓
𝜕𝑥 − 𝑖𝜕𝑓
𝜕𝑦 )