VOL. 18 NO. 4 (1995) 745-748
745
THE BEST APPROXIMATION AND AN EXTENSION
OFA FIXED POINT
THEOREM OF
RE.
BROWDERV.M. SEHGAUandS.P. SINGH
Dcpartmcnt of
Mathematics, Utverszlgof
IVyoming, Laramie, IVl’, 82071, U.S.A.Department of
Mathematics andStatistics, Memorzal Universityof Neu,foundlad,
St..I,,b, Newfoundland, Cauada, A IC5S7(Received March 17, 1994 and in revised form May 9, 1994)
ABSTRACT In this paper, theKKM principle has been used to obtain a theorem onthe best approximation ofa continuous function with respect to anaffine Inap. The nain result provides extensionsofsomewell-known fixedpoint theorems.
KEY
WORDSAND PItRASES. Bestapproximation, ftxed pointtheorem,KKM-map,
p-allinc map, inward set.MATHEMATICS SUBJECT CLASSIFICATIONS: Primary47H10,Secondary541125.
Let
E
bealocallyconvextopological vectorspaceandC’anon-empty subset ofE. At,al)ping p: (? E[0, co)is
a convex map ill" for each fixed :r (:,Z,(.r,-): E (0,
co)is,
,,,,v,.xfunction. Forx
C,
the inward setIt(x) {x +
,’(yx):
yC,,"
>0}.
Browder[1]
proved the followingextensionof theSchauder’s fixedpoint theorem.THEOREM 1.
(Bvowdev).
LetC be a compact, cotvexsubsetof
E andf
(!acontinuous map.
If
p:CE [0, co)
is acontinuous convexmap satisfying(I) for
eachxf(x),
there exists ayIt(x)
withp(z, f(x) y) < p(x, f(x) x),
the,,f
ba.,tfixed
point.It may be stated that theimportance of Theorexn 1 stems froInp being acontinuous convex map instead ofacontinuousseminormon E. Inthis paper, we usethe
KKM
principle toobtainaresulton the ’best approximation’ that yields Theorem 1 withrelaxedhypothesison compactness.
Let
X
be a non-empty subset of E. Recall that a mappingF X
2F is aKKM
map ifF(x) # 0
foreach xX,
andforany finite subsetA {x,,x,...,x,,}
C_X,C’0(A) U{ I"(.,’,):
1,2,...,
n},
whereCo(A)
denotes theconvexhullofA. Observethat ifFisaKKM
map,then xF(x)
for eachx X.It is shown by Fan
[2]
that ifF X
2E is a closed valuedKKM
nap, then the family{F(x):x X}
has thefinite intersectionproperty.Asanimmediate consequenceof the above result,wehave:
LEMMA
2.If X
is a non-empty compact, couvex subsetof E
attd 1" .\ 2E is aclosed valued Kh’Mmap, then
fq{F(x)
xX} # O.
746 V. M. SEHGAL AND S. P. SINGH
PROOF. DefineamapG X 2x by
:(.) !"()
X.Then
G(x)
is a nonempty compact subset ofX
and (; is aKKM
map. Consequently, i,y[2], {G(x)
x (X}
hasthe finite intersection property. Since X is compact, it follows thatf3{(/(.r)
xEThe
X}
followingO,
andhence,lemmatq{F(z)
isessentiallyxEX}
due to Kiln- O. [3]. We giveaproof forcompleteness.
Note:
In
thefollowing,C0(A):
stands for the closed convexhull ofA.LEMMA
3.If A
and 13 arccompact, convexsubsetsof E,
thenC0(A
tJ13)
,sa,’,,,,,I,,,,’t,convexsubset
of
E.PROOF. Since
A
andB
are convex,’it followsCo(A
UB)
B, A,
tt[0,1]
andA+
tt1}.
Clearly,C0(AU B)is
aclosed andconvexsubset ofE. Toshowtl,atCo(AU 13)is
compact,letC[0,1]
x[0,1] A
Bna
D{A+
t,:-ThenCisacompact subsetofY
[0, 1]
x[0,1]
xE
xE
in theproduct topologyonY. Further, the mappingf"
Y Edefined byf(A,
it,x,V)
Az+
trybeing continuous,it follows that !)f((,’)
is aconpact subset of
E
and, hence,C0(A
UB)
C_D
is compact.LEMMA
4. LetX
be anon-empty convexsubsetof E
andF" X
2E aclosed valu,,!Kh’M ,,tap.
If
there exists a compact, convexset S C_X
such that3{F(x)
xS}
is no,t-,’,,,pt!and compact, then
C){ F(x)
zX # .
PROOF.
Let
C3{F(x)
x ES}.
Then Cis non-etnpty and a compact subset of E. To prove the lemma, it suffices to show that the family{F(x)
C’ zX}
has the finiteintersectionproperty. ’1o provethis, let
A
beafinite subset ofX. ThenCo(A)
is conpactand by Lemma3,D Co(S
UC0(A))is
acompact andconvexsubset ofX. Consequently, by Lemma2,t3{F(z)
zD} # O.
Thisimplies that{F(x)
t3C zA} # O.
Thus,{l"(x)
C)(: .,:X}
has thefinite intersectionproperty. SinceC is compact andl"(z)
is closedfor each :r. ( X, it h,llowsthat
{F(z)t3
C zX} # .
Thisimplies thatt3{F(z):z X} # .
Let
X
beanon-exnptyconvexsubset ofE andp"X
xE [0, cx))
a convex map. A malpingg
X X
is a p-afline map iff for each triple{z,z,z2}
C_X,y E,
and A,# ([0,1]
withA+It=I,
p(x,V g(Ax, + ktx2)) _< max{p(z,y g(z,))" 1,2}.
Note: Ifg islinearoraft’meinthesenseof Prolla
[4],
thenpbeingconvex,itfollows that9isl-afline
inthe abovesense. Itis immediatethatif g isp-affme,then forany finiteset
A {z,x2,... ,z,,}
C_X
andAi _>
0with’= Ai
1,p(x,y g( A,x,)) <_ max{p(x,y g(xi)) 1,2,...,,t}
for each
Thefollowingisthemainresult of this paper.
THEOREM 5. Let
X
be a nonempty convcx subsetore
andpX
xE [0, oo)
acontinuous convex map. Let
f" X E
attdgX X
be continuous mappingswith g p-aJflnc.Suppose
there exista compact, convexsetS
C_X
anda compact setK
C_X
such that(2) for
eachyX\K
there exists anx Ssuch thatp(y, f(y)- g(y)) > p(y, f(y)- g(x)).
7’hcn there exists auX
thatsatisfies
(3) p(u,f(u)- 9(u))=
inf{p(u,f(u)-9(z))
ze X}
inf{p(u,f(v)-z)
ze
clIx(9(u))}.
PROOF. Wefirst provethe leftequality. Forthis,wedefineamapping G
X
2x byG(z) {y
X:P(Y,f(Y)-g(Y)) <- P(Y,f(Y)-g(x))}
A FIXED POINT THEOREM 747 Clearly,x E
G(x)
anditfollows thatG(.c)
isclosed for eachx E X. Weshowthat(;isaKKM
map.Let y
Z:’_-,
.\,.r,,A,0,:’=,
A, 1,x, .\" for each.
Suppose y. U{(;(.r,),, 1,2,...,,,}.
Then for each 1,2,...,7z,
p(y, f(y) g(y)) 3>p(y, f(y)
g(x,)).
This imphes that p(.q,f(y) g(y))
P(Y,f(!I)
g(,:’_-,A,x,)) _< ,nax{1,(!l,f(!l)
.q(.,’,)).,1,2,...,,z}
<I’(Y,f(Y)-g(y)).
This inequahty is impossible and, consequently, yU{t;(.r,)
1,2
,n},
that is, G is a closed valued map.Now,
since S is a compact convex subset ,,fX,
it follows by Lemma 2 that C{G(x)
xS}
is a nonempty closed subset of X. We show that C N. Suppose y C and assume that yXIf.
Then by hypothesis there ex- ists an x S such thatl’(:/,f(!/)- :/(Y))
> l’(Y,f(y)-9(.r)).
This implies that ,/ (;(,’) f,,rz S and, hence,
C,
contradicting the initial supposition. Thus, (’ h" and, hcnce,{G()
.rS}
is anonempty compact subset ofK. Henceby Lemma4,{(;(.r)’.r X} ,.
If u
{a(z)
xX},
then for each xX, p(u,f(u)- g(u)) S 1,(u,f(u)-
g(.r)). F,,rther,since u
X,
it follows thatp(u,f(u)- g(u)) inf{p(u,f(u)- g(x)) X}.
This proves the first equity in(3).
To prove right side of the equMity in(3)
we first show that fl,r eachz
Ix(g(u))X, p(u, f(u) g(u))
5 p(u,f(u) z).
Now zlx(g(u))X
i,nplies that thereis a’- + (1 })g(u). Hence,
by the first equalityand p being convex, X and r > such thaty=_
ittonowsthat
Z’(", f()- a("))
5P(’, f()- ) 5 }Z’(, f(")- )+ (1- )V(", f(")- ’(")).
thatis,
p(u, f(u)- g(u)) p(u, f(u) z)
for each zIx(g(u))X.
Since thelast inequality is also true for any zX,
it follows thatp(u,f(u)- S/(u)) p(u,f(u)- z)
for each z Ix(q(,)).Further, since the fuaios f,, ad p are continuous and
g(u) lx(.q(u)),
it follows thatp(,,,f()- ()) if{p(,f() )
d(x(g(u)))}.
This proves the second equality in(s).
Asa simpleconsequence ofTheorem 2,we have
COROLLARY 6. Supposc X zs a compact, convex subsct
of
E,p" X ia co,zlznuous convex
functzon
andf
XE
a contz,tuousfunction.
’l’hc,tfor
anyp-aJfiue mapg"
X X,
there ezistsauX
thatsatisfies (3).
Furthcr,(i) zJ" f(x)
cl(lx(g(x))) for
cachx qX
thenp(u,f(u)- 9(u))
O,(ii) if
fo,"adX,
,oahf() ()
th, c (6,(’(-,))) ’’
thatV(’, f(.’:)-:)
<p(x, f(x) g(x)),
thc,tf(u) g(u).
PROOF. Set S K
X
in Theorem 5. SinceX\K ,
condition(2)
in Theorem 5is satisfied.
Hence,
there is au EX,
that satisfies(3).
Clearly,(i)imphes p(u, f(u)- .rt(,t))
O.Toprove
(ii),
supposef(u) : 9(u).
Thenbyhypothesisp(u, f(u)- z) < p(u, f(u)- 9(u))
forsomez cl
(lx(9(u))).
Thelast inequahtycontradicts(3). Hence, f(u)= 9(u).
E]It may be remarked that if g is theidentity mappingof
X,
then Corollary 6 yields Browder’s Theorem 1and also extends arecent result ofSehgal, Singh, and Gastl[5]
iff
therein is a singlevalued map.
For the next result, let P denote the family ofnonnegative continuous convex futtctions on
X
E. Noteif p andp.P,
thensois p+
p2. Also,if p isacontinuous seminorm onE,
then generatesanonnegativecontinuousconvexfunctiononX E
definedby13(z, y) p(y).
Amal,l,ing gX X
isP afline if it isp-afllneforeachp P.Theresult belowis anextension ofanearlierresult ofFan.
THEOREM 7. Let
X
be a compact, convczsubsetof E
andf" X E
a cont,uousfunction.
Thenfor
any continuous19affine
mapg"X X,
()
eztherf(u) g(u) for
some uX,
748 V. M. SEHGAL AND S. P. SINGH
(5)
orthere czists ap P and auX
with 0< p(u,f(u)- 9(u))
inf{p(u,f(,t)-z):
z EIn pa,’ltcular,
tf f(x)
E cl(]x(g(x))) for
eachx, then(5)
holds.PROOF. Itfollows by Theorem 5 that foreach pE
P
thereisa u up .\" such thatp(u, fu-gu)
inf{p(u,f(u)- z):
zcl(Ix(g(u)))}.
Ifforsomep,p(u, f(u)-g(t))
>0,then(5)
istrue. Suppose then,
p(u,f(u)-g(u))
0for each p P. SetA. {u
X:p(,,,f(.)-q(.))0}.
Then Avis anonempty compact subset ofX. Furthermore, the family{Ap
pP}
has the finiteintersectionproperty. Consequently,thereis a uX
that satisfies(6) 1,(u, f(u) g(u))
0for eachpe
P.If
f(u) # g(u),
then sinceE
is separated, there exists a continuous seminorm 1’ onE
such thatp(f(u)- .q(u)) :#
0and, hence,(u, f(u)-
g(u)) > 0,contradicting(6).
Thus,f(u)
,g(u). llence,(5)
holdsinthe alternate case.REFERENCES
BROWDER,
F.E. Onasharpenedform of Schauderfixedpointtheoren, Proc. Natl. Acad. Sci.,U.S.A.,
76(1977),
4749-4751.FAN,
K. Extensionsoftwo fixed point theorems ofF.E. Browder,ax,_,
112(1969),
234-240.KIM,
W.K.Studieson theKKM-maps,
MSRI-Korea,Rep. Set.,
14(1985),
1-114.PB.OLLA,
J.B. Fixedpoint theorems for setvalued mappings and theexistence of bestal)l)roxi- mants,Numerical FunctionalAnalysis andOptimization,
5(4) (1982-83),
449-455.SEIIGAL, V.M., SINGII, S.P.,
ANDGASTL,
G.C. On a fixed point theorem for multivalucd maps, Proc. First Intern. Conf. onFixed PointTheory, Pitman Publishers, London, U.K.(1991),
377-382.Submit your manuscripts at http://www.hindawi.com
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