C OMPOSITIO M ATHEMATICA
J. V AN M ILL
Topological equivalence of certain function spaces
Compositio Mathematica, tome 63, n
o2 (1987), p. 159-188
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159
Topological equivalence of certain function spaces
J. van MILL
Subfaculteit Wiskunde en Informatica, De Boelelaan 1081, 1081 HV Amsterdam,
The Netherlands; and Mathematisch Instituut, Universiteit van Amsterdam, Roetersstraat 15, 1018 WB Amsterdam, The Netherlands
Received 16 April 1985; accepted in revised form 22 December 1986.
0. Introduction
If X is a space then
C*(X)
denotes the set of continuous bounded real- valued functions on X endowed with thetopology
of uniform convergence.There are classification results for these spaces. For details see
[18]
and[6].
There is another
topology
on function spaces that is of interest in abstract functionalanalysis, namely
thetopology of point-wise
convergence. For any spaceX,
the set of continuous real-valued bounded functions on X endowed with thetopology of point-wise
convergence shall be denotedby C;(X).
Fora recent survey on
point-wise
convergence function spaces, see[16].
Sofar,
no classification results have been obtained for the spaces
C*p(X).
Results in[3], [4]
and[17]
indicate that a classification result for the spacesC*p(X)
in the linear world
promises
to beextremely complicated. Trying
toget
atopological
classification result for the spacesC*p(X)
seems to be morepromising
since no obstacles forobtaining topological homeomorphisms
are known. The aim of this paper is to prove that if X is any
countable,
metric space which fails to be
locally compact
at somepoint
thenC*p(X)
ishomeomorphic
to the countable infiniteproduct
l2f l2f l2f
...,where
l2f = {x
El2 :
Xi 0 for almost alli 1
and12
denotes theseparable
Hilbert space of course. It is clear that "countable" is essential in this result.
In
addition,
"metric" is essentialby
results in[14].
1conjecture
that "failsto be
locally compact
at somepoint"
can bereplaced by
"is not discrete".1 am indebted to the referee for many valuable comments.
Compositio (1987)
© Martinus Nijhoff Publishers, Dordrecht - Printed in the Netherlands
1. Preliminaries
Unless otherwise
stated,
all spaces under discussion areseparable
metric. Allmappings
are continuous functions. Let X and Y be spaces. Ahomotopy
from X to Y is a map F: X x I ~ Y
(I denotes
the interval[0, 1] of course)
and for t E I we define
Ft:
X ~Y by Ft(x)
=F(x, t).
If F: X x I ~ Y isa
homotopy
and WY is an open cover ofY,
then we say that F islimited by
WY
provided
that for each x E X there exists an element U e WYcontaining F({x} I).
Now let e be a collection of open subsets of Y.Mappings f,
g:X - Y are called *-close if for each x E X
with f(x) ~ g(x)
there exists aU E 0/1
containing
bothf (x)
andg(x) (note
that we did notrequire 4Y
tocover
Y).
Observe thatif f:
Y - Y is *-close to theidentity
thenf
issupported
onUo/1,
i.e.f
restricts to theidentity mapping
onY/~U.
Theidentity mapping
on X shall be denotedby 1,
or, if no confusion seemslikely, simply by
1. We shallfrequently
use thefollowing
result due toAnderson
[1].
1.1. INDUCTIVE CONVERGENCE CRITERION.
Suppose
that a sequence{hn}~1 of homeomorphisms of
a compact space X is choseninductively
so that eachh,,
is
sufficiently
close to theidentity.
Thenlimn~~ hn ~···~ hl
exists and is ahomeomorphism of
X.We consider the Hilbert cube
Q
=II;[- 1, 1]i,
with metric d(x, y) = 03A3~1 2-ilxi - yi|.
A Hilbert cube is a spacehomeomorphic
toQ.
We shall nowdefine several notions
in Q
which are all stated inpurely topological
terms.For this reason we assume that we defined these
concepts simultaneously
forspaces
homeomorphic
toQ.
A closed subset F of a
space X
is a Z-set in X if everymap f: Q ~ X
canbe
approximated by
maps g:Q ~
X withg(Q) n
F =0.
Note that everyendface
ofQ (a
subset of the formni 11)
or03C0-1i({1}),
where ni :Q -
[-1, 1];
is theprojection)
is a Z-set inQ.
We letL(X)
denote the collection of all Z-sets in X. A countable union of Z-sets is called a (J-Z-set. We letL03C3(X)
denote the collection of Q-Z-sets in X. Animbedding
h: X - Y isa
Z-imbedding
ifh(X)
is a Z-set. Az-(J-pair
in X is apair (A, B)
withA E
L(X), B
EL03C3(X)
and B z A. If(A, B)
and(E, F)
are twoz-6-pairs
then we write
(A, B) (E, F)
whenever A z E and F n A = B.Observe that " " is a
partial
order on thefamily
of allz-Q-pairs
inX. For a discussion of Z-sets see
[6]
and[9].
We shall now define twoimportant concepts.
A skeleton in(a topological
copyof) Q
is anincreasing
sequence
A1 ~ A2 £;
... of Z-setsin Q having
thefollowing absorption
property:
For every e > 0 and n E N and
for
every Z EL(Q)
there exist ahomeomorphism
h:Q - Q
and an m ~ N such thatd(h, 1)
e,hIA,
=1,
and
h(Z) ~ Am.
The idea of a skeleton for a
given
class ofcompacta
is dueindependently
to Anderson
[2]
andBessaga-Pelczynski [5].
1.2. THEOREM. For every n E N let
An
=03A0~i=1 [- 1
+lin,
1 -lin];.
Thelfthe sequence
{An}~1
is a skeleton inQ.
For a
proof
of this basic result due to Anderson andBessaga-Pelczyùski,
see[9], chapter
5.If the sequence
lanllo
is a skeleton inQ
then A =lJ; An
is called askeletoid.
1.3. THEOREM.
If
A and B are skeletoids inQ
and K EL03C3(Q) then for
everycollection 0/1
of
open subsetsof Q
there is ahomeomorphism
h:Q ~ Q
thatis *-close to 1 while moreover
h((A ~ K)
nUo/1)
= B nUo/1.
For details see e.g.
[6],
pp.124,
129 and 131.Let X be a
compact
space. Anisotopy
on X is ahomotopy
H: X x I ~ Xsuch that for each t E I the
mapping H, :
X ~ X is ahomeomorphism.
Weshall also need the
following
consequence of a result due to Anderson-Chapman.
For details see[9], §19.
1.4. THEOREM. Let X be a compact space and let H: X x I ~
Q
be ahomotopy
such thatHo
andHl
areL-imbeddings.
Thenfor
every opencovering
Gllof Q
such that H is limitedby
0/1 there is anisotopy
F:Q
x I ~Q having
thefollowing properties:
1. F is limited
by 0/1,
2.
F0 = 1 and F1 ~ H0 = H1.
Finally,
we shall need thefollowing result, [9],
11.2.1.5. THEOREM.
If (A, Ao)
is a compactpair and f:
A ~Q
is a map such thatf JAO
is aZ-imbedding,
then there is aZ-imbedding
g: A ~Q
which agreeswith f on Ao. Moreover, g can be constructed arbitrarily
closeto f and
such thatg(ABA0)
misses apre-given
a-Z-set inQ.
2. N-skeletons
In this section we shall define the
concept
of anN-skeleton,
which isroughly speaking
adecreasing
sequence of skeletons with someabsorption
property.
Inaddition,
we prove that N-skeletons are"unique"
up tohomeomorphism.
Let X be a
compact space. A
L-matrix in X is a collection d ={Anm:
n,
m ~ N)
of Z-sets in Xhaving
thefollowing properties:
1.
An1 =
0 for every n EN,
2.
Anm ~ Anm+ 1 for
alln, m ~ N,
and3. An+1m ~ Anm
for all n, m ~ N.If A =
{Anm:
n,m ~ N}
is a L-matrix then for each n E N the union of the nth row of A shall be denotedby den),
i.e.Also,
for alln, m ~ N put
Observe that
(Am, Anm)
is az-03C3-pair.
Adecreasing
collectionof subsets of X is called an n-sieve if 1.
Zi ~ L(X)
for i n, and2.
Si
EL03C3(X)
for i n.We are now in a
position
to define theconcept
of an N-skeleton. An N-skeleton in X is a Y-matrix d ={Anm:
n,m ~ N} having
thefollowing absorption property:
For every e >
0, for
every n EN, for
everydecreasing
sequencei
1 ···in of
natural numbersand , f ’or
every n-sieveZ1 ~ S1
PZn ;2 Sn
in X such thatfor
everyk
n,there exist a
homeomorphism
h: X ~ X and adecreasing
sequencej,
···jn of natural
numbers such that 1.d(h, 1)
8,2. ~k n ~l ik:h(Akl) = Akl,
3.
~k
n:(h(Zk), h(Sk)) (Ai, Wjk,).
Observe that
by
2 many elements of the N-skeleton arekept
invariant underh,
but that h is nowhererequired
to be theidentity.
163 2.1. LEMMA. Let X be a compact space and let A =
{Anm:
n,m ~ N}
be anN-skeleton in X.
If
h: X ~ X ishomeomorphism
thenh(A) = {h(Anm):
n,
m ~ N}
is also an N-skeleton.Proof.
Use that h isuniformly
continuous and thatL(X)
is invariant underhomeomorphisms
of X. ~We now come to the main result in this section which we prove be a
complexification
of a standard back and forthtechnique,
cf.[6], chapter
4.2.2. THEOREM. Let X be a compact space and let A =
{Anm:
n,m ~ N}
andé4 =
{Bnm:
nm ~ N}
be N -skeletons in X. Thenfor
every e > 0 there is ahomeomorphism
h: X ~ Xhaving
thefollowing properties:
Proof.
Thehomeomorphism
h will have the formlimm~~ hm O... 0 hl
forsome
inductively
constructed sequence{hm}~m=1
ofhomeomorphisms
of X.From the construction it will be clear that each
hm
can be chosenarbitrarily
close to the
identity.
So without furthermentioning
it is understood that eachhm
is chosen in accordance with the Inductive convergence criterion 1.1.If in addition we also make sure that
03A3~m=1 d(hm, 1)
E, then in will follow thatd(h, 1)
e.We shall prove that there exist
a)
for each kEN astrictly increasing function 03BEk: N ~ N having
thefollowing properties:
b)
for each k ~ N astrictly increasing
function qk:NB{1}
~ Nhaving
thefollowing properties:
c)
a sequence{hm}~1
ofhomeomorphisms
of X withhl =
1 such that forevery m e N if we
put fm = hm o ··· o h,
thenSuppose
for a moment that weproved
statementsa) through e).
Put h =limm~~ hm o ··· o hl , By
the aboveremarks,
h is ahomeomorphism
of X ontoitself such that
d(h, 1)
e. Fixk
1 andk
2.By d),
for every m 1 +(k - 2)
we haveThe
continuity
of h and thecompactness
of X noweasily imply
that(notice
that k and 1 arefixed). Since 03BE and 1
arestrictly increasing,
from thisit now
directly
follows thati.e. h is as
required.
It remains to
give
aproof
of the statementsa) through e).
Wealready
know that
Since
A 1
=Bl - 0,
we also haveand
So now it is clear how to
proceed inductively. Suppose
that for certain m ~ N we definedf) ~k m
thefunction Çk
on theset {1, 2,
..., m -(k - 2)}
such thatfor every i x m + 1 we have
g) ~k m
the function Ik on the set{2, 3,
..., m -(k - 2)}
such thatfor every
2
1 x m + 1 we haveh)
thehomeomorphisms
then
d)
ande)
hold.such that
Some remarks seem necessary.
Among
otherthings,
we wish to construct astrictly increasing function 03BE1: N ~
N.By
the statement"03BE
1 on the set{1, 2,
..., m +1}"
we mean that wealready
know the values of the function we areconstructing
on theset {1, 2,
..., m +1}.
So in factwe are
dealing
with apartial function,
the domain of whichis {1, 2,
... ,m +
1}, which,
forconvenience,
we shall also denoteby ç 1 .
Atstage
m + 1 of the construction we shallenlarge
the domain of thepartial
functionç 1 .
So if we
discuss ji later
on, the domainof ji
should be taken into consider- ation. The same remarkapplies
to all of thefunctions 03BEk
and ~k.By f)
we havewhich
implies, by
the definition of anN-skeleton,
thatConsequently,
is an m-sieve. From
h)
it follows that this m-sieve and the natural numbers~1(m
+1),
... ,~m(2)
are "admissible" asinput
for the N-skeleton B. Soby
the definition of an N-skeleton there is a(small) homeomorphism
et:X ~ X and a
sequence i1 i2 ··· im
of natural numbers such thati) ~k m ~l ~k(m - (k - 2)): 03B1(Bkl) = Bkl,
j) Vk c
m:(03B1fm(Ak03BEk(m-(k-2))), 03B1fm(Ak03BEk(m-(k-2)))) (Bk’ Bkik).
It is clear that we may assume that for
every k m
we haveWe are now in a
position
to define foreach k
m + 1 thefunction ~k
inthe
point (m
+1) - (k - 2), namely,
weput
Now consider the natural
numbers Çl (m
+1) ··· 03BEm(2)
and them-sieve
By j),
these are admissible asinput
for the N-skeleton,(LEMMA 2.1). Consequently,
there exist a(small) homeomorphism 03B2:
X ~ X and a sequenceof natural numbers 03B51 03B52 ··· 8m such that k) ~k m
~lçk(m - (k - 2)): 03B203B1fm(Akl) = 03B1fm(Akl),
l)
~k m:(03B2(Bk~k(m-(k-3))), 03B2(Bk~k(m-(k-3)))) (03B1fm(Ak03B5k), 03B1fm(Ak03B5k)).
It is clear that for
every k m
we may assume thatWe are now in a
position
to define foreach k m
+ 1 thefunction Çk
inthe
point (m
+1)
-(k - 2), namely,
weput
Also,
definehm+1 = 03B2-1 ~ 03B1.
We claim that our choices are asrequired.
Claim
Indeed,
fixarbitrarily.
Case
If 1 =
2 then fm+1(Ak03BEk(l-1))
=Bk~k(l)
=0,sothenthereisnothingtoprove.
So assume that 1 > 2. Then
and
Case 2. k = m + 1.
Then l =
2.Since Am+103BEm+1(1)
=Am+11
=~ and Bm+1~m+1(2)
=0,thcreisnothing to prove.
Case
3. k m
and 1 =(m
+1)
-(k - 2) = m - k
+ 3.Then and Claim
Indeed, if k
= m +1 then Bk~k(m-k+3)
=0, so
assumethat k
m. Now theclaim follows
directly
from(1).
This
completes
the inductive construction and therefore also theproof
ofthe theorem. D
Let si =
{Anm:
n,m ~ N}
be a L-matrix in thecompact
space X. Define thekernel,
ker(A),
of Aby
ker
2.3. COROLLARY. Let X be a compact space and let d and A be N-skeletons in X. Then
for
each e > 0 there is ahomeomorphism
h: X - X such thatObserve that nowhere in this section we used
specific properties
ofZ-sets, except
thatY (X)
is atopological
class ofcompacta,
i.e. if h: X ~ X is anyhomeomorphism
thenh(L(X)) = L(X).
So we could have stated ourresults in a more
general
form.3. A-matrices
In this section we shall define the
comcept
of a 9-matrixin Q
and we shallprove that each 9-matrix is an N-skeleton.
Let A =
{Anm:n, m ~ N}
be a L-matrix in some compact space X.By
a T-set for A we shall mean a Z-set B z Xhaving
thefollowing property:
Let
J(A)
denote the collection of all T-sets for A.The
proof
of thefollowing
lemma isstraightforward
and is left to thereader.
3.1. LEMMA. Let X be a compact space and let A =
{Anm:
n,m ~ N}
be aA Q-matrix
in Q
is a L-matrix A ={Anm:
n,m ~ N} having
thefollowing properties:
In the
remaining part
of this section we shall prove that every 9-matrix isan N-skeleton. This result is our main tool in
recognizing
N-skeletons.Proof
Observe that 2 is atriviality
and 1 follows from the definitions andlemma 3.1. D
3.3. LEMMA. Let A =
iAm:
n,m ~ N}
be a 2-matrix inQ.
Then ~03B5 > 0there exist a
homeomorphism
h:Q - Q
and an element fil E N such thatProof.
Since{A1p: p ~ N}
is a skeleton inQ
there exist t m + p and animbedding
u :Zi - A1t
such thatu|Z1 ~ A1m =
1 andd(u, 1) e/3.
SinceA1t ~ (T
nAt )
is a J-Z-set inA1t
we may use Theorem 1.5 toget
animbedding
v:Z1 ~ At
such thatd(v, u) 8/3, v 1 T n ZI = u 1 T n Zl ( = 1)
and
v(Z1/T) ~ A1tBA1tBT. By
Theorem 1.4 we may extend v ~1 T
to ahomeomorphism v of Q
such thatd(v, 1) 203B5/3 .
SinceA1t
is a skeletoid inA1t
there exists ahomeomorphism w
ofAr
such thatw|A1t
n T = 1 andw((A1t ~ v(S1))BT) = A1tBT;
we mayrequire w
to be so close to 1 as toassure the existence of a
homeomorphism w of Q
that extends w u1 T
andsatisfies
d(w, 1) e/3,
see Theorems 1.3 and 1.4. Weput
h= w o v;
thenby
abuse of
notation,
Thus 2 and t m show that h and m = t have the desired
properties.
DThis Lemma has some nontrivial consequences.
3.4. LEMMA. Let A =
{Anm:
n,m ~ N}
be a Q-matrix inQ.
Then dE > 0~m E N 3ô > 0 ~1-sieve
Z1 ~ SI
withb’T E
5(d) Vhomeomorphism
h: T ~T ~p
E N such thatthere exist a
homeomorphism
H:Q - Q
and an m ~ N such thatProof.
Let 03B5 > 0. If m = 1put 03B4 = 03B5.
If m > 1let 0 03B4 = 03B42 03B43
...Jm+l
1 = E be so small that(*) ~2 i m VZ,
Z’~L (A1i) Vhomeomorphism f:
Z ~ Z’ withd( f, 1) ôi
there exists ahomeomorphism I.- A1i ~ A1i extending f with d(f, 1) 1 2 03B4i+1.
That these (5’s exist follows
directly
from Theorem 1.4. We claim that ô is asrequired. Let Zl ;2 SI
be a 1-sieve and choose an element T ~J (A),
ahomeomorphism
h : T - T and a natural number psatisfying (1) through (4). By
induction we shall prove that forevery i m
there exists a homeo-morphism hi: Ai
u T -Ai u
T such thatPut hl = h (if m
= 1 we are donealready). Suppose
that for i - 1 m thehomeomorphism hi-1
has been constructed. IfAI £;
T ~A1i-1
then definehi
=hi-1. If A1i ~
T ~A1i-1
thenA1i
n(T u A1i-1) ~ L(A1i) (Lemma 3.1)
from which follows that
By (2)
and(10)
we havehi-1(E) = E
and sinced(hi-1, 1) bi, by (*)
wecan extend
hi-liE
to ahomeomorphism
a:A1i ~ AI
withd(a, 1) 1 2 03B4i+1.
Since
et(d/)
and-çiil
are both skeletoids forAI, by
Theorem 1.3 there is ahomeomorphism 03B2: A1i ~ AI
such thatDefine
Then
hi
is ahomeomorphism
such thatIt is clear that for this we
only
need toverify that hi(d/) = d¡l. By (14)
thisfollows from
hi(A1i
nE) = A1i
nE,
which is a consequence of(10), (2) and (11).
Let F =
hm ;
Thend(F, 1)
E andby
Theorem 1.4 we may extend F to ahomeomorphism F: Q ~ Q
withd(F, 1)
e(the straight-line homotopy in Q
between1T~A1
and Fis"e-small",
so the existence ofF
followsdirectly
from Theorem
1.4m).
Let
21 = F(Z1)
and91 = F(S1), respectively.
Thenand
Observe that
(18)
followsdirectly
from(1)
and(16)m.
SinceFextends
Fandby (17)m
F extendsh, (19)
follows from(4).
Nowput i
= T ~A1m.
We shallprove that
for q
= max(p, m)
we haveThis is a
triviality
sinceby (18)
and(19), 21
ni
=Zl
n(T u A1m) = (21
nT) ~ A1m ~ A1q. Moreover,
By
Lemma3.3,
there are ahomeomorphism
a:Q ~ Q
and an elementm ~ N such that
It is easy to see that H = a o
F is
asrequired.
Let us now consider the
following
statement, where is a 2-matrix.that
1.
~k
n :(At, Akik) (Zk, Sk),
VreJ(A) bhomeomorphism
h : T - T4.
~k
n:(h(Zk ~ T), h(Sk
nT)) (Ak03BEk, Ak03BEk),
there exist a homeomor-phism
H:Q ~ Q
and elements03BE1,
... ,03BEn
E N withThe number ô shall also be denoted
by J(d, il... in , c) -
3.5. LEMMA. ~Q-matrix A Ve > 0 ~n E N
Vdecreasing
sequenceil
···Proof.
For n =1, simply apply
Lemma 3.4.Suppose
therefore thatS(A, k1 ··· ki, e)
is true for every Q-matrixA,
for every e >0,
forevery i n - 1
(n 2)
and for everydecreasing sequence k1 ··· ki
of natural numbers.
Let A
{Anm:
n,m ~ N}
be a2-matrix,
e >0, i1 ··· in, Z1 ~ SI ;2... ;2 Zn P Sn’ T ~ J (A), h:
T -T and 03BE1, ..., 03BEn
c-N be as in thedefinition
of S(A, i1 ··· in, E) (we
shallspecify ô
later ofcourse).
Forevery
2 k il
letf!Jk = (A)
nA1+nm :
n,m ~ N}. Then 4k
is a Q-matrixin the Hilbert cube
Al,
Lemma 3.2. Inaddition, put {An+1m :
n,m ~ N}.
Then E is a Q-matrix, Lemma 3.2. Let 03B3 = 03B4(E, i2 ··· in, e). Applying
our induction
hypothesis, by
downward induction it is easy to find for every2 k i1
aJ(k)
> 0 such thatIt will be convenient to write
ô (il
+1) =
y. We have to find a 03B4 > 0witnessing S(A, il
···in, e).
Weput
and we shall show that ô is as
required.
For every
k i1
we shall construct ahomeomorphism hk : A) - Ak
suchthat
then
hk
extendshl,
and
there are natural numbers ~2 , ... ,
’1n E N
such that for every2
1 nwe have
(hk(Zl
nA1k), hk(SI n A1k)) (Al~l, A1~l). (8)k
Since
A 1
= 0 we lethl
be theempty
function. Thenobviously (4)1 through (8)
are satisfied.Suppose
therefore that for somek i1 (k 1 ) the homeo- morphism hk-1 has
been definedproperly.
Put E =
A1k-1
1 u( T
nA1k)
and defineqJ: E -+ E by qJ
= h ~hk-1; by (4)k-
1 ~ is a well-definedhomeomorphism.
Claim 1.
d( qJ, 1) 03B4(k)
andif l k -
1 then ç extendshl.
This follows
directly
from(3), (5)k _ 1 and (6)k-1.
Claim
This follows from
(7)k - 1 and (3)
in the definitionof S(A, i1 ··· in, E).
Claim 3. There exist 03B32, ...,
03B3n ~ N
such that for every 2 x n we haveThis follows from
(8)k-1 and (4)
in the definition ofS(A, il
···in, E).
First observe that
Bk(1)
=.911
andBk(1)
n E =.911-1
1 u(d1 ~ T).
Consequently,
the claim follows from(7)k-1
1 and(3)
in the definition ofThen Ak - Ak
n(T
~A1k-1)
=(Ak
nT) ~ A1k-1
= E. Defineh k =
9-The easy
proof
thathk
and the numbers 03B32, ... ,Yn E N
found in Claim 3are as
required,
is left to the reader.Case 2..
Claim 5.
By
Lemma3.1,
E eJ(A)
so the claim follows from our definitions.Claim 6.
Z2 n Al ;2 S2 ~ A1k ~ ··· ~ Sn n Al
is an(n - 1)
sieve in theHilbert cube
Al
such thatNotice that
b) implies
thatZ2 n Ak ~ L(A1k)
sincedl
is a skeletoid inA1k.
In
addition, a)
followsdirectly
from(1)
in the definition ofS(A il ··· in, e).
SinceZ2 c-- Sl
we also haveby (1)
in the definitionBy
Claims1, 2, 3,
5 and 6 andby S(Bk, i2
···in , 03B4(k
+1))
there exista
homeomorphism f : A1k ~ Ak
andelement ~2, ..., 1 ll,,
E N such thatand
Let F =
f(Z2
nA1k) ~
E. Since bothdl and f(A1k)
are skeletoids forAk
there exists
by
Theorem 1.3 ahomeomorphism
a:A1k ~ Ak
such thatPut
hk = et of
We claim thathk
and theelements ~2 , ... , ~n
are asrequired.
That
(4)k, (5)k (6)k
and(8)k
hold is atriviality (use
that E =(T
nA1k) ~ Ak _ 1 and (9)-(13)).
Take2 x n ad y ix arbitrarily. By (10), f(A1k
nAxy) = A1k n A00FF and f(A1k
nAxy) = A’
nAxy.
Sincewe conclude that
Now take 1
i1 arbitrarily.
If l k thenhk(A1l
nA1k) = hk(A1l) = A1l = A1l
nAk
sincehk
extendshl . If k l
thenhk(A1l
nA1k) = hk(A1k) = Ak - A1l ~ A1k. Again,
assume that 1 k. Thenhk(A1l
nA1k) = hk(A1l) = hl(A1l) = A1l = A1l
nAl by (6)k . If k l
thenhk(A1l
nA1k) = hk(A1l) (*) =
A1k = A1l
nAl
in case(*)
holds. This is shown in thefollowing:
Claim
Indeed, by (14)
and(13)
we have(by
Claims 4 and6(b))
By (11), f(Z2
nA1k) ~ A2~2 ~ A1k ~ di.
From this we conclude thatThus the claim follows from
(14)
and(13).
Now
let f
=hll
u h andi = All u
T.By (4)il , f T - Fis
a homeomor-phism. Moreover, f
hasclearly
thefollowing properties:
there are natural numbers ~2 , ... ,
11n E N
such that for every 2 1 nwe have
(f(Zl ~ T), f(Sl
nT)) (Al~l, Al~l). (17)
(For (17)
observe thatif (A, B) (E, F)
and(C, D) (E, F)
then(A
nC,
B n
D) (E, F)).
Now consider the Q-matrix E ={An+1m: n, m ~ N}.
Clearly tE J(E). By S(E, i2 ··· in , e)
there exist ahomeomorphism 1: Q ~ Q
andelements 03BE2 , ... , 03BEn ~ N
such thatNow
put
T * =T ~ f(Z2).
Claim 8.
3p
E N such that T *n Aq ~ L(A1q)
forevery q
p.This follows from
(19)
and Lemma 3.1(notice
thatT u AÇ2 ~ L(Q),
henceis nowhere
dense,
and~~1A1m
is dense inQ).
Claim 9. 3m E N such that
Indeed,
let mIn
addition,
Also,
which proves the claim.
By
Lemma 3.4 there exist ahomeomorphism
a:Q ~ Q
and an element03BE1
E N such thatNow
put
H =ri 01
We claim that H is asrequired. Clearly, d(H, 1)
eand since
oc 1 T*
= 1 we haveH|T
= hby (18)
and(15).
That condition(6)
of the definition holds and that
follows from (16), (19) and (20) since Axy ~ f(Zk) ~ A1i1 ~ f(Z2) ~
T* and03B1|T* = 1.
Finally,
that(H(Z1), H(S1)) (At, A103BE1)
followsdirectly
from(21).
DWe now come to the main result in this section.
3.6. THEOREM. Let A =
{Anm:
n,m ~ N}
be a il-matrix inQ.
Then A is anN-skeleton.
Proof
Take T =0
inS(A, i1 ··· in, 03B5)
andapply
Lemma 3.5. D4. Some N-skeletons
In this section we shall prove that Q-matrices exist.
Compared
to all thework we did so far this turns out to be
surprisingly simple.
Let us fix some notation. For every n
EN,
letAn
be as in Theorem1.2,
i.e.Let
6 = 03A0~1Qi,
where6, = Q
for every i.Clearly, ~ Q.
For everyn, m ~ N
defineAnm ~ Q
as follows:4.1. THEOREM. A =
{Anm:
n,m ~ N} is a
Q-matrix inQ.
Proof.
To see thatis a
skeleton,
use Theorem 1.2 andChapman [8].
That
is easy since choose indices n, ...
nm ~ N, il, ..., im ~ NB{1}
anddefine natural numbers
p1 p2 ··· pm by
Then
is a
product
of Hilbert cubes and hence is a Hilbert cube itself. Thatis a skeleton in
nk=1 1 A"’
followseasily
fromChapman [8]
and the formula(*).
We shall prove that
So
take n,
... nm E Nand il, ... , im
E Narbitrarily
and suppose thatBy
the above formulas we can writewhere all but
finitely
manyEk’s (resp. Fk’s)
areequal to Q
and theremaining finitely
manyEk’s)
are elements of{An}n>1.
SinceTIf Fk
is a proper subsetof TIf Ek
we haveFk ~ Ek
forevery k
and there exists a k ~ N such thatFk
is a proper subsetThen
clearly Fk ~ L(Ek)
from whicheasily
follows that03A0~1Fk ~ L(03A0~1Ek).
D 4.2. COROLLARY. Let A be an N-skeleton in
Q.
Then ker(A) is
homeomor-phic to
(J (J).Proof
Let 03A3 =ur An’
whereAn
is defined as above. The Q-matrix A constructed in Theorem 4.1 is an N-skeletonby
Theorem 3.6 and ker(A) obviously equals
LOO . It is known that L ishomeomorphic
toFor details see
[6]. Consequently,
So the desired result now follows from
Corollary
2.3. 0We shall now
give
a differentexample
of an N-skeleton inQ.
Thisexample
will be of
importance
in the announced"applications"
to function spaces.It will be convenient to fix some notation. For x
E Q
write/Ix Il
=supi lxi 1.
Denote
points of Q by x
=(x(i)),
wherex(i) E Q
for all i. Inaddition,
writeBm
={x ~ Q: ~x(i)~ 1 - 1/m if i m
and~x(i)~
2-notherwise}.
It is clear that A
(Bfl :
n,m ~ N}
is a L-matrix inQ.
4.3. LEMMA. Vn E N:
{Bnm}m > 1 is a
skeletonProof
The standardproof
that{An}~1
is askeleton,
where eachAn
is as inTheorem
1.2,
caneasily
beadapted
to show that{Bnm}m> 1 is
a skeleton. Fordetails,
see[6], Proposition
3.1 on page 156. 0 4.4. LEMMA.~n1 ··· nm ~ N ~i1,..., im E NB{1}: ~mk=1 Bnkik ~ Q. 0
4.5. LEMMA.
Vp, q
E N:Bpq
EJ(B).
Proof. Take ni
... nm E N and p,q, il , ... , in
E N and write B =~mk=1 Bnkik. With A(03B5) = {x ~ Q: ~ x ~ 03B5} there
are sequences(8;)
and(Ji) of positive
numbers such that B =03A0iA(03B5i), B ~ Bpq
=03A0iA(03B4i).
Observe that 03B4 8implies
thatA(03B4) ~ L(A(03B5)). Therefore,
if B~ Bpq ~ L(B)
then03B4i
8i foreach i, i.e.,
B ~ B nB:.
Q4.6. LEMMA.
Vni
... nm e N~i1, ... , im
eNB{1} ~p
e N :{~mk=1 Bnkik
nBnmi +p}i > 1 is a
skeleton innm Bnkik .
Proof :
Write B =~mk=1 Bnkik . By
lemma4.5, B
nBnm +p ~ L(B)
for each i.A
straightforward adaptation
of the standardproof that {An}~1
is askeleton,
where each
An
is as in Theorem1.2,
now also shows that{~mk=1 Bnkik
nBnm +pi}i> 1 is
a skeleton innm Bnk
~4.7.
COROLLARY. B = {Bnm:
n,m ~ N} is an
N-skeleton inQ .
proof. Apply
Lemmas 4.3-4.6 and Theorem 3.6. D We shall nowtry
to find adescription
of ker(B)
in terms of function spaces.To this end we shall first introduce a test space T. The
underlying
set of Tis
(N
xN) ~ {~}.
The
points
of N x N are isolated and a basicneighborhood
of oo has theform
Clearly,
T is a countable metric space. Define4.8. LEMMA.
Proof
For(1), simply
observe that the function cp:C*p(T) ~ C*p,0(T)
Rdefined
by
is a
homeomorphism.
Define
and
respectively.
Define a functionit is easy to see that ‘Y is a
homeomorphism.
So in order to prove the firstpart
of(2),
it suffices to show that Z = ker(B).
This follows from thefollowing
observation:5. The space aw
In this section we shall derive some
topological properties
of the space U,,, which areprobably
knownalready
sincethey
followeasily
and rathermechanically
from known results.As noticed in the
proof
ofCorollary 4.2,
03C303C9 ishomeomorphic
to 03A3~ =HL Li’
where eachYi
is a copy of the space5.1. LEMMA. Let X be a 03C3-compact space. Then X admits a closed
imbedding
in the space L.
Proof.
LetyX
be acompactification
of X. Without loss ofgenerality, 03B3X ~ Q
andyX ~L(Q) (apply
forexample
Theorem1.7;
easierproofs
areknown of
course). By
Theorems 1.2 and 1.3 it follows that 03A3 is an absorber inQ. By
Lemma 3.3 there exists ahomeomorphism
a:Q - Q
such that03B1(03B3X)
n 03A3 =03B1(X). Consequently, 03B1(X)
is a closed copy of X in L. FI 5.2. COROLLARY. Let X be an absoluteF03C303B4.
Then X admits a closedimbedding
in 03A3~ ~ 03C303C9.
Proofs
Assume that X ~Q
and letFi ~ Q
be03C3-compact
for every i E N such that X =~~i=1 Fi. By
Lemma 5.1 there exists for every i E N a closedimbedding f : Fi
- 1. Nowdefine.f’:
X ~ LOOby
It is
well-known,
and easy to prove,that f is
a closedimbedding.
DBy
a linear space we mean atopological
vector space over the reals. Let E be a linear space andput
EE =
{x
EE"0: xi
= 0 for all butfinitely
manyi}.
In
[23], Torunczyk proved
that for everylocally
convex(metric)
linear space E we haveConsequently,
if we take E = (Jú) we obtainThis consequence of
Torunczyk’s
result can also be derivedby
theapparatus developed
in this paper since it is easy torepresent 03A303C303C9
as the kernel of someQ-matrix,
see§4.
For information on absolute
(neighborhood)
retracts(abbreviated:
A(N)R’s),
see Borsuk[7].
5.3. THEOREM. Let X be a space. The
following
statements areequivalent:
1. X x 03C303C9 ~ (Jm,
2. X is an absolute
Fô
and an AR.Proofs
1 ~ 2 is atriviality
since (Jw is an ARby Dugundji’s
Theorem[7, 7.1], and a.
isclearly
an absoluteF03C303B4.
For 2 ~1,
let X be an AR and an absoluteF03C303B4. By Corollary 5.2,
X admits a closedimbedding
in (Jw.By Torunczyk [20]
we may conclude that X x
03A303C303C9 ~ 03A303C303C9. Since,
as was observedabove,
la. ;:t
u. the desired conclusion follows. DLet X be a space Y is called an
X-manifold
if Y admits an opencovering by
sets
homeomorphic
to open subsets of X. The above theoremgeneralizes
without much
difficulty
to thefollowing
result: For anyspace X
the follow-ing
statements areequivalent: 1)
X x (J w is a (J w-manifold,
and2)
X is anabsolute
F03C303B4
and an ANR. Let us also mention thatby
resultsof Henderson, 03C303C9-manifolds
are characterizedby homotopy type,
i.e. if X and Y are(Jw -manifolds then X is
homeomorphic
to Y if andonly
if X and Y have thesame
homotopy type.
For details see[6], chapter
9.6. Function spaces
If X is a space
then,
as noted in theintroduction, C*(X)
denotes the set of continuous bounded real-valued functions on X endowed with thetopology
of uniform convergence. It is known that if X and Y are uncountable
compact (metric)
spaces thenC*(C)
andC*(Y)
arelinearly homeomorphic ([ 18], 21.5.10).
If X and Y arecountably
infinitecompact (metric)
spacesthen
C*(X)
andC*(Y)
need not belinearly homeomorphic, ([18], 21.5.13(A)).
Infact,
there areuncountably
manytypes
among the spacesC*(X),
where X is countable andcompact (metric) [5].
The Anderson-Kadec Theorem that all
separable
infinite-dimensional Fréchet spaces arehomeomorphic (in
thetopological sense),
see[6], chapter 6,
forbackground information,
shows that all function spaces of the formC* (X),
where X is any infinitecompact
space, arehomeomorphic.
Infact,
a moregeneral
result can be formulatedby applying
results from[22].
There is another
topology
on function spaces that is of interest in abstract functionalanalysis, namely
thetopology
ofpoint-wise
convergence. To avoidconfusion,
for anyspace X
the set of continuous real-valued bounded functions on X endowed with thetopology
ofpoint-wise
convergence shall be denotedby C*p(X). By [3],
if X and Y arecompact
Hausdorff andC*p (X)
is
linearly homeomorphic
toC*p(Y)
then X and Y have the same dimension(for
X and Ycompact
metric this was firstproved
in[16]).
From this we seethat for
example
the function spacesCp ([0, 1])
andC)([0, 1]2)
are notlinearly homeomorphic.
There even exist countable infinitecompact
metricspaces X and Y for which