C OMPOSITIO M ATHEMATICA
R OBERT E. K OTTWITZ
Base change for unit elements of Hecke algebras
Compositio Mathematica, tome 60, n
o2 (1986), p. 237-250
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237
BASE CHANGE FOR UNIT ELEMENTS OF HECKE ALGEBRAS Robert E. Kottwitz
e Martinus Nijhoff Publishers, Dordrecht - Printed in the Netherlands
One of the
ingredients
in thecomparison
of trace formulas involvesmatching
the orbitalintegrals
ofspherical functions;
this is whatLang-
lands
[L]
refers to as the "fundamental lemma". There is aspecial
caseof the fundamental lemma that has a
simple
localproof.
Let G be aconnected reductive group over a
p-adic
field F and assume that G isunramified
(that is, quasi-split
over F andsplit
over an unramifiedextension of
F).
Let E be a finite unramified extension ofF,
let 0 be agenerator
ofGal(E/F),
and let 1 =[ E : F ].
Consider a
hyperspecial point
xo in thebuilding
of G over F. Wedenote
by K
the stabilizer of x0 inG(F)
andby H = H(G(F), K )
thecorresponding
Heckealgebra.
Of course x0 alsogives
rise toKE
cG ( E )
and
-19 É = H(G(E), KE ).
There is a canonicalhomorphism b : HE ~ H,
characterized
by
thefollowing property:
for all
1 E £E
and all unramified admissiblehomomorphisms
qu :WF
~ IG. Here 03C8
denotes therestriction
of T toWE,
and03C0~ (resp. 03C003C8)
denotes the
K-spherical (resp. KE-spherical) representation
ofG(F) (resp. G(E)) corresponding to qp (resp. 03C8).
The fundamental lemma for the
homomorphism b : HE ~
H relatesthe stable orbital
integrals
ofb(f)
to the "stable" twisted orbitalintegrals
off
forany f ~ HE.
Theprecise
statementrequires
definitions for stableconjugacy,
stable orbitalintegrals,
the twistedanalogues,
andthe norm
mapping
J’V. All of these are easier to define if the derived groupGder
issimply
connected. Tokeep
theexposition simple
we willnow assume that
Gder
issimply connected,
and then in the last section of the paper we will sketch aproof
of thegeneral
case.There are two forms of the norm
mapping.
The first is themapping
N :
G(E) ~ G(E)
definedby
The second is a
mapping
JV’ fromG(E)
to the set of stableconjugacy
Partially supported by NSF Grant DMS-8200785.
classes in
G(F).
SinceGder
issimply connected,
stableconjugacy
is thesame as
G(F)-conjugacy, where
F is analgebraic
closure of F. Theconjugacy
class of N8 inG(F)
is defined over F and therefore containsan element Y E
G(F) (since
G isquasi-split, Gder
issimply connected,
and
char(F)
= 0[K2]). By definition,
N03B4 is the stableconjugacy
classof y. The fiber of X
through
8 is the stable twistedconjugacy
class of 8.The construction of X when
Gder
is notsimply
connected isgiven
in[K2].
Let
dg (resp. d gE )
be the Haar measure onG(F) (resp. G(E))
thatgives K (resp. KE )
measure 1. For03B3 ~G(F)
andlE CcOO(G(F))
wedenote
by O03B3(f)
the orbitalintegral
This
requires
a choice of Haar measure dt onG03B3(F),
but we leave themeasure out of the notation.
Let
I = ResE/FG.
Then theautomorphism 0
ofE/F
induces anF-automorphism
ofI;
thisautomorphism
agrees with 0 onI(F)
=G ( E ),
and we will abuse notation
slightly by using
0 to denote both of them.For 8 E
G(E)
andf E CcOO(G(E))
we have the twisted orbitalintegral O03B403B8(f), given by
where
188
denotes the fixedpoints
ofInt(03B4) o 03B8
on I. Of courseI03B403B8(F)
issimply
the twisted centralizer of 8 inG ( E ).
For
semisimple 03B3 ~G(F)
we have the stable orbitalintegral SOY,
given
as a linear form onCcOO( G( F)) by
where the sum is taken over a set of
representatives y’
for theconjugacy
classes within the stable
conjugacy
class of y, and wheree(G03B3’) = ± 1
isthe
sign [K3]
attached to the connected reductiveF-group G03B3’.
Thedistribution
SOY depends
on a choice of Haar measure onG03B3(F).
Thismeasure is then
transported
to the inner twistsGY,
and used to formO03B3’.
One
expects
thatSOy
is a stable distribution for allsemisimple
y. Ofcourse this is true
by
definition if y isregular semisimple.
For
03B4 ~ G(E)
such that N8 issemisimple
we have the "stable"twisted orbital
integral
where the sum is taken over a set of
representatives
8’ for the twistedconjugacy
classes within the stable twistedconjugacy
class of 8. In thesame way as for
SOY
we usecompatible
measures on the groupsI,6,0(F).
Let
fE E CcOO(G(E))
andlE CcOO(G(F)).
As usual we say thatfE, f
have
matching
orbitalintegrals
if for everysemisimple
y EG(F)
thestable orbital
integral SO03B3(f)
vanishes unless the stableconjugacy
classof y is
equal
to N03B4 for some 8 EG(E),
in which case it isgiven by
Of course we are
using compatible
Haar measures onG03B3(F), I03B403B8(F)
toform the orbital
integrals;
this has ameaning
sinceIse
is an inner twist ofGy [K2,
Lemma5.8].
The
(conjectural)
fundamental lemma for b :HE ~ H
asserts thatfE, b( fE)
havematching
orbitalintegrals
for allfE ~ HE.
The main result of this paper is thatfE, b( fE)
havematching
orbitalintegrals
iffE
is theunit element of
HE, namely,
the characteristic function ofKE (recall
that we normalized the measure on
G(E)
so thatKE
has measure1).
Inthis case
b(fE)
is the unit element ofYe, namely,
the characteristic function of K.For G =
GLn
this result is not new - it followsimmediately
fromLemma 8.8 of
[K1].
In fact that lemma shows that some otherpairs
offunctions have
matching
orbitalintegrals (characteristic
functions ofcorresponding parahoric subgroups
ofGLn(F), GLn ( E ),
dividedby
themeasures of the
subgroups). Following
asuggestion
of J.-P.Labesse,
thispaper also proves a
matching
theorem for moregeneral pairs
of func-tions.
This more
general matching
theorem is thesubject
of§1.
In§2
wemake some remarks about twisted K-orbital
integrals
of the functions considered in§1.
In§3
we return to the unit elements of£E’
P andfollow a
suggestion
of J. Arthurby proving
amatching
theorem for someweighted
orbitalintegrals.
In§4
we sketch what to do whenGder
is notsimply
connected.1. Main result
In this section our situation will be somewhat more
general
than in theintroduction. Let
F, E, 0,
1 be as before. Inparticular
we still insist thatE/F
be unramified. Let L denote thecompletion
of the maximal unramified extension E un of E. We have E un = F un and we denoteby
athe Frobenius
automorphism
of L over F.Let G be a connected reductive group over
F,
nolonger
assumed tobe unramified. We do assume,
however,
thatGder
issimply
connected.As before we write I for
ResElFG
and 0 for theF-automorphism
of Iobtained from the field
automorphism
0. LetKL
be an open boundedsubgroup
ofG(L) satisfying
thefollowing
three conditions:(a) 03C3(KL) = KL.
(b)
Themapping
k ~k-103C3(k)
fromKL
toKL
issurjective.
(c)
Themapping k ~ k-103C3(k)
fromKL
toKL
issurjective.
Let K
(resp. KE )
beG(F) ~ KL (resp. G(E) ~ KL).
Note that thesituation in the introduction can be recovered
by taking KL
to be thestabilizer in
G(L)
of thehyperspecial point
xo; then(a) is
obvious and(b), (c)
follow from a result ofGreenberg [G]
since thespecial
fiber of Gis
connected,
where G is the extension of G to a group scheme over o determinedby
xo( o
denotes the valuationring
ofF).
Let X, XE, XL
denoteG(F)/K, G(E)/KE, G(L)/KL respectively.
There are obvious inclusions X c
XE c XL
and a acts onXL.
Condition(b) (resp. (c)) implies
that the fixedpoint
set of a(resp. a 1)
onXL
isequal
to X(resp. XE ).
Choose Haar measures
dg, d gE
onG(F), G(E)
such thatK, KE
have measure
1,
and use these measures informing
orbitalintegrals.
Letf (resp. fE )
denote the characteristic function of K(resp. KE )
inG(F) (resp. G(E)).
The groups
G(F), G(E), G(L)
acton X, XE, XL respectively.
Furthermore 0 acts on
XE (by
some power ofa).
Let 8 EG(E).
Thenwhere g runs over a set of
representatives
for the elements ofsuch that
g-103B403B8(g) ~ KE . Writing x
forgKE E XE,
we haveg-103B403B8(g) ~ KE
if andonly
if 03B403B8x = x. LetI03B403B8(F)x
denote the stabilizer of x inI03B403B8(F).
ThenLet
XÉ60
denote the set of fixedpoints
of 80 onXE (the product
of 8 and0 is taken in the semidirect
product
ofG(E)
andGal(E/F)).
Then wehave shown that
where x runs
through
a set ofrepresentatives
for the orbits of180(F)
onX03B403B8E. Taking
thespecial
case E =F,
weget
acorollary
that for y EG ( F )
where x runs
through
a set ofrepresentatives
for the orbits ofG.Y(F)
onX Y,
the set of fixedpoints
of y on X.Choose an
integer j
such that 0 isequal
to the restriction ofai
to E.Of
course j
isrelatively prime
tol,
and hence we can chooseintegers a,
b such that bl -
aj
= 1. We aregoing
to define acorrespondence
betweenG ( F )
andG ( E ).
Let y EG(F)
and 8 EG(E).
We write 03B3 ~ 8 if there exists c EG ( L )
such that thefollowing
two conditions hold:In
(A)
and(B)
theequalities
are of elements in the semidirectproduct
of
G(L)
and the infinitecyclic group (a) generated by
03C3.Let (y, 0)
bethe
subgroup generated by
y, a. Then if y,8,
csatisfy (A)
and(B),
itfollows that
c(y, 03C3 ~ c-1 = ~03C3l, 03B403C3j~,
thepoint being
that03B3a03C3l, 03B3b03C3j
generate
the samesubgroup
as y, a. Let Y be any set on which the semidirectproduct
acts.Then y H
cy induces abijection
from the fixedpoints of (y, 0)
on Y to the fixedpoints of (01, 03B403C3j~
on Y.Taking
Y =
XL,
we see that x H cx induces abijection
from X Y toX03B403B8E. Taking Y=G(L)
withG(L) acting by conjugation,
we see thatg ~ cgc-1
induces an
isomorphism
fromGy(F)
toI03B403B8(F).
It is then immediate from theexpressions
we obtained forO03B403B8(fE)
andO03B3(f)
thatif the measures used on
G03B3(F), I03B403B8(F) correspond
under the isomor-phism
above.What remains is to
get
a betterunderstanding
of thecorrespondence
03B3 ~ 8. For which y E
G ( F )
do there exist 8 EG(E)
such that y ++ 8 ? Conditions(A), (B)
can be rewritten asIf 8
exists,
then(A’ )
can be solved.Conversely,
suppose that(A’)
can besolved. Then we can use
(B’)
to define 8 EG(L)
such that y,8,
csatisfy (A), (B).
But thenc(y, 03C3~c-1 = ~03C3l, 80j),
whichimplies
thatQl, 80j
commute, and this in turn
implies
that 8 EG(E).
We conclude that 8 exists if andonly
if(A’ )
can be solved. The element c EG(L) appearing
in
(A’)
isclearly
determined up to leftmultiplication by
an element ofG(E). Making
such achange
in creplaces
8by
a0-conjugate
underG(E).
Thus if03B3 ~ 03B4,
then 03B3 ~ 8’ if andonly
if8,
8’ are0-conjugate
under
G(E).
Next we consider 8 E
G(E)
and ask whether there exists y EG(F)
such that y ++ 8.
Inverting
the matrixwe see that
(A), (B)
areequivalent
to(of
course we areusing
that y, a commute and thata’, 8aj commute).
We can rewrite
(C), (D)
asIf Y
exists,
then(D’ )
can be solved.Conversely,
suppose that(D’)
can besolved. Then we can use
(C’ )
to define y EG ( L )
such that y,8,
csatisfy (C), (D).
But(C)
and(D) imply
that y, a commute and hence that y EG(F).
We conclude that y exists if andonly
if(D’)
can be solved.Furthermore
(D’)
determines c up toright multiplication by G(F),
andchanging
cby
an element ofG(F) replaces
yby
aconjugate
underG (F).
Thus if 03B3 ~8,
theny’ ++
8 if andonly
if y,y’
areconjugate
inG(F).
What we now know about the
correspondence
-y 8 can be sum-marized as follows. The
correspondence
sets up abijection
from the setof
conjugacy
classes inG ( F )
of elements y EG ( F )
such that(A’ )
can besolved to the set of
0-conjugacy
classes inG ( E )
of elements 8 EG(E)
such that
(D’)
can be solved.Furthermôre (C’)
tells us that if 03B3 ~8,
then J’V8 = y.
To
complete
thepicture
we need to know that there areenough corresponding
elements ofG(F), G(E).
First we show that if y EG ( F )
and X Y is
non-empty,
then there exists03B4 ~ G(E)
such that03B3 ~ 03B4.
Indeed, replacing
yby
aconjugate,
we may assume that y E K. Then ourassumption (c)
onKL implies
that(A’ )
can be solved.Next we show that if 8 E
G(E)
andX03B403B8E
isnon-empty,
then there exists y EG(F)
such that Y ~ 8.Indeed, replacing
8by
a0-conjugate
inG(E),
we may assume that 03B403B8 fixes the basepoint
ofXE = G(E)/KE.
Then
(03B403C3j)-a
andoai
both fix the basepoint
ofXL,
as does theirproduct (03B403C3j)-a03C3aj~G(L).
Therefore(03B403C3j)-a03C3aj~KL
and assump- tion(b)
onKL implies
that(D’)
can be solved.There is one further remark that we need to make before
stating
themain result of the paper.
Suppose
that03B3 ~ 03B4.
Choosec ~ G(L)
suchthat y,
8,
csatisfy (C), (D).
We havealready
seen that g Hcgc-1
induces an
isomorphism
fromG03B3(F)
toI03B403B8(F).
Since(C), (D)
determinec up to
right multiplication by
an element ofGy(F),
theisomorphism
iscanonical up to inner
automorphisms
ofGy(F).
THEOREM: The
correspondence
03B3 ~ 8 induces abijection from
the setof conjugacy
classesof
y EG(F)
such thatO03B3(f) ~
0 to the setof
0-con-jugacy
classesof
8 EG(E)
such thatO03B403B8(fE) ~
0. Moreoverif
03B3 ~8,
then y
= N03B4, G03B3(F) is isomorphic
toI88(F),
andO03B3(f)
=°88(IE).
Since
O03B3(f) ~
0(resp. O03B403B8(fE) ~ 0)
if andonly
if X’’(resp. X03B403B8E)
isnon-empty,
the theorem follows from the remarks made above.In order to use the theorem to prove that
f, fE
havematching
orbitalintegrals,
there is a technicalpoint
to check.Suppose
that y,8,
csatisfy (A), (B).
Then Lemma 5.8 of[K2] gives
us aninner twisting /3 : I03B403B8
-GY,
canonical up to inner
automorphisms
ofGy(F).
Assume now that y issemisimple.
We want to check that there exists anF-isomorphism
a :
I03B403B8 G03B3
whose restriction toI03B403B8(F)
isgiven by
g Hc- lgc
and whichdiffers from
03B2 by
an innerautomorphism
ofGy(L).
This will show that if we useg H c - lgc
totransport
a Haar measure onI03B403B8(F)
over toG03B3(F),
the two measures will becompatible
in the sense that arises inthe definition of
matching
orbitalintegrals.
It will also showthat
thesigns e(G03B3)
ande(I03B403B8)
areequal.
We see from[K2]
that if d EG ( F )
andN8 =
dyd-l,
then we can take03B2
to beInt(d)-1 o p,
where p :188
-GN8 (over E)
is the restriction to188
of theprojection
ofIE
=GE
X ... XGE
onto the factor indexed
by
theidentity
element ofGal(E/F) (the
1factors are indexed
by
the elements ofGal( E/F )). Let
a =Int(c)-l 0
p.Then a,
03B2
differby
an innerautomorphism
ofG03B3(L) (use (C’)
to seethis),
and what remains is to show that a is defined over F. It is obvious that a is defined over L. Since the functorA ~ IsomA(I03B403B8, Gy)
from(F-algebras)
to(sets)
isrepresentable by
a scheme over F(here
we usethat y is
semisimple
and thatGder
issimply
connected in order toconclude that the groups
G03B3, 188
are connected andreductive),
it isenough
to show that a commutes with o. We will do thisby showing
thata commutes with
ai
anda’;
this isenough
sincej,
1 arerelatively prime.
Direct calculation shows that
and
(A’), (B’) imply
thatSince y is central in
GY,
this proves that03C3j(03B1)
=03C3l(03B1) =
a.COROLLARY: The
functions f, fE
havematching
orbitalintegrals.
This follows
immediately
from the theorem and the technicalpoint
that we
just
checked.However,
we need to say a few more words about thecorollary.
If G is notquasi-split,
the most naturalnotiop
ofmatching
orbital
integrals
would involve "stable’ twisted orbitalintegrals
onG ( E )
and stable orbital
integrals
on aquasi-split
inner form of G. Infact,
if Gis not
quasi-split,
the stableconjugacy
class of N8 need not contain any F-rationalelements,
hence the stable norm N03B4 does notalways
exist inG(F).
Nevertheless thecorollary
is true and even has thefollowing supplement:
if .%8 does not exist inG(F),
thenSO03B403B8(fE)
= 0. To prove thesupplement,
note that ifSO03B403B8(fE) ~ 0,
then there exists a stable0-conjugate
8’ of 8 such thatO03B4’03B8(fE) ~ 0;
therefore there exists yG ( F )
such that 03B3 ~8’,
and then it follows that y =’/v8’ = N03B4.2. K-orbital
integrals
and thedependence
of 03B3 ~ 8 onj, a, b
We
keep
the notation andassumptions
of§1.
We have notyet
used the fullstrength
of the theorem in§1,
whichproved
amatching
result for orbitalintegrals,
notjust
stable orbitalintegrals.
Consider an element8 E
G(E)
such that N8 isregular
andsemisimple.
Then188
is a torus.For any stable
0-conjugate 03B4’ ~ G(E) of 03B4
there is an invariantmeasuring
the difference between8,
8’. This invariant sets up abijection
from the set of
0-conjugacy
classes in the stable0-conjugacy
class of 8 to the setAs usual we can define twisted K-orbital
integrals 0;0
for any character Kon the group
H1(F, 180) by putting
where 8’ runs over a set of
representatives
for the0-conjugacy
classes inthe stable
0-conjugacy
class of 8.Suppose
thatO03B4’03B8(fE) ~
0 for somestable
0-conjugate
8’ of 8. It does no harm toreplace 5 by 8’,
and so wemay as well assume that
O03B403B8(fE) ~
0. Then there exists y EG(F)
suchthat Y H 8. Of course y is
regular
andsemisimple,
andGY
is a torus T.Lemma 5.8 of
[K2] gives
us a canonicalisomorphism T I03B403B8, allowing
us to view K as a character on
H1(F, T )
and to form K-orbitalintegrals
where
y’
runs over a set ofrepresentatives
for theconjugacy
classes inthe stable
conjugacy
class of y.PROPOSITION 1:
O03BA03B403B8(fE) = O03BA03B3(f).
Of course the
significance
of theproposition
is that whenever one is able to express the K-orbitalintegrals
off
in terms ôf stable orbitalintegrals
of a function on anendoscopic group H
ofG,
theproposition
will then express
O03BA03B403B8(fE)
in terms of stable orbitalintegrals on H,
whichmay also be
regarded
as anendoscopic
group for thepair ( I, 03B8) [S].
To prove the
proposition
it isenough
to show that ify’
isstably conjugate
to y, if 8’ isstably 0-conjugate
to8,
and ify’ ~ 03B4’,
theninv( y, y’ )
=inv(03B4, 8’ ).
This is sufficient since the elementsy’,
8’ that do not takepart
in thecorrespondence
contribute zero toO03BA03B3f), O03BA03B403B8(fE).
In order to prove that
inv( y, y’ )
=inv(03B4, 8’)
it is convenient to use theinjection
defined in
[K4, §1],
whereB(T)
denotesH1(~03C3~, T(L)).
Choose c,c’ E
G(L)
such thaty, 8,
c andy’, 8’,
c’satisfy (A), (B).
SinceH1( L, T )
istrivial,
we can also chooseg E G(L)
such thaty’
=gyg- l.
The
image
ofinv(y, y’)
inB(T)
isrepresented by
the1-cocycle
of
~03C3~
inT(L).
As in
§1
we write p :188
~GN03B4 (over E)
for the restriction to188
ofthe
projection
ofIE = GE ···
XGE
on the factor indexedby
theidentity
element ofGal( E/F ).
The canonicalisomorphism
from188
to Tis
given by Int(c)-1 o
p. It is easy to see that there exists aunique
element h E
I(L)
such that(a)
theimage
of h under theprojection
ofI(L)
=G ( L )
X ... XG(L)
onto the factor indexed
by
theidentity
element ofGal(E/F)
isequal
todgc-l (note
thatdgc-’ conjugates
N8 intoN8’ ),
(b) 03B4’=h03B403B8(h)-1.
The
image
ofinv(03B4, 8’ )
inB(T)
isrepresented by
the1-cocycle
We will now show that with the choices we have made the two
1-cocycles
of(0)
inT( L)
areequal (not just cohomologous).
Sincej,
1are
relatively prime,
it isenough
to show thatfor k
= j,
1. First we take k= j.
Theequality
8’ =h03B403B8(h)-1 implies
thatp(h-103C3j(h))
isequal
toTherefore
(Int(c)-1 o p)(h-103C3j(h))
isequal
toUsing (B)
for 8and 8’,
we cansimplify
thisexpression, obtaining
Using y’
=gyg-1,
we cansimplify
itfurther, obtaining g-lal(g).
Next we take k = 1. Then
(Int(c)-l 0 p)(h-103C3l(h)
isequal
toUsing (A’)
for c and d we cansimplify
thisexpression, obtaining
Using y’ = gyg-l,
we cansimplify
itfurther, obtaining g-’O’(g).
Thiscompletes
theproof
of theproposition.
In order to define the
correspondence
03B3 ~ 8 we had to chooseintegers j, a, b
such that the restriction ofai
to E was 0 and such thatbl - aj = 1.
This raises an obviousquestion:
How does the correspon- dencedepend
on the choiceof j,
a, b? It turns out that the correspon- dence isindependent
ofj, b,
but isdependent
on a. To see how thecorrespondence changes when j,
a, b arereplaced by j’, a’, b’,
wesuppose that we have y,
y’ E G ( F ),
8 EG ( E ),
c, c’ EG ( L )
such that y,8,
csatisfy (A), (B)
forj, a, b
andy’, 8,
c’satisfy (A), (B)
forj’, a’,
b’.Then y,
y’
arestably conjugate
and we can measure the difference between the twocorrespondences by calculating inv( y, 03B3’) ~ H1(F, Gy)’
At this
point
we assume that y issemisimple,
so thatGY
is connected and we can embedH1(F, GY )
inB(Gy)’
The setB(G03B3)
can be identifiedwith the set of
o-conjugacy
classes inGy( L).
PROPOSITION 2: The
image of inv( y, y’)
inB( Gy)
isequal
to thea-conjugacy
classof 03B3-n in Gy(L),
where n isdefined by
theequality
a’=a+nl.
We also
write j’ = j
+ml;
then b’ = b +nj
+ ma + mnl. We havec03B3c-1 = N03B4 = c’03B3’(c’)-1,
and hence03B3’ = g03B3g-1,
whereg = ( c’ ) - lc.
Therefore the
image
ofinv(y, y’)
inB(Gy)
isequal
to thea-conjugacy
class We
of x,
will where x =g-103C3(g).
now show that x =
y - n.
We haveand
using (D)
for c’ and thenreplacing j’ by j
+ml,
we find thatFinally, replacing
a’by a
+ nl and thenusing (C)
and(D)
for c, we findthat
x = 03B3-n.
Incarrying
out thesesteps
we must remember thatai
Icommutes with 8. This finishes the
proof
of theproposition.
3.
Weighted
orbitalintegrals
We return to the situation in the
introduction,
so that G isagain
unramified. The
hyperspecial point
xo determines an extension of G to aconnected reductive group over the valuation
ring
oof F,
and we haveKL
=G(DL).
Let M be a Levisubgroup
of G over o. We write 03B1M for the real vector spaceHomz(HomF(M, Gm), R)
and define a
homomorphism
by requiring
that f or x EM( L )
for
all 03BB ~ HomF(M, Gm).
Here we have extended the normalized absolute value on F’ to an absolute value on Lx. Let P be aparabolic subgroup
of Ghaving
M as Levicomponent
and write N for theunipotent
radical of P. We define a functionby putting HP(g) = HM(m),
where g has been written as mnk forFor fixed g the functions X -+
vP(03BB, g)
form a(G, M) family [A],
andthis
(G, M) family
determines a numberVM(g).
In this way we haveconstructed a
weight
function vm onG(L);
it is left invariant underM( L )
andright
invariant underKL.
It is obvious that the restriction of vm to
G(F)
is theweight
functionon
G ( F )
that Arthur uses to defineweighted
orbitalintegrals.
Let y be aregular semisimple
element ofM(F).
Theweighted
orbitalintegral
thatwe are
referring
to isfor ~
EC~c(G(F)).
After
working through
Arthur’s definition is twistedweighted
orbitalintegrals,
one finds that the necessaryweight
function onG(E)
is noneother than the restriction of VM to
G(E) (up
to a scalar which will be 1 in a suitablenormalization).
Let03B4 ~ M(E)
and assume that N8 isregular
andsemisimple.
Then the twistedweighted
orbitalintegral
thatwe are
referring
to isfor 0
EC~c(G(E)).
As before we let
f, fE
denote the characteristic functions ofK, KE.
Suppose
that our elements y EM(F)
and 8 EM(E)
are relatedby
thecorrespondence 03B3 ~ 03B4
for the groupM,
so that there existsC ~ M(L)
such that y,
8,
csatisfy (A)
and(B).
The
proof
is aslight
variant of theproof
thatO03B403B8(fE) = O03B3(f).
Sincev M is
right
invariant underKL
it descends to a functionwM
onXL
=G(L)/KL.
We havewhere x runs
through
a set ofrepresentatives
for the orbits ofG03B3(F)
onXY. There is a similar formula for
WO03B403B8(fE).
Thebijection x H
cx fromXY to
X03B403B8E
matches up the terms in the twoformulas,
and to finish theproof
of theproposition
we haveonly
to note that the left invariance of vm underM( L ) implies
thatWM(X)
=wM(cx).
Before
finishing
this section we should observe thatenough
y, 8 arerelated
by
thecorrespondence
03B3 ~ 8 for M.Suppose
that y is aregular semisimple
element ofM(F)
such thatWO03B3(f) ~
0. Then there existsg E G(F)
such thatg-103B3g ~ K.
Choose aparabolic subgroup
P of Gwith Levi component M and
unipotent
radical N.Writing
g = mnk withm E
M( F ), n E N( F ), k E K
andusing
thatP(o)
=M( o ) N( o ),
we seethat
m -1 ym E M( o ).
The discussion in§1
then shows that there exists 8 EM( E )
such that 03B3 ~ 8 in the group M.Similarly,
ifWO03B403B8(fE) ~ 0,
then there exists y E
M(F)
such thaty ++ 8
in the group M.4.
Groups
G f or whichGder
is notsimply
connectedIn
proving
ourspecial
case of the fundamental lemma we assumed thatGder
wassimply
connected. We will now show that thisassumption
canbe
dropped.
Choose a finite unramified extension F’ of F thatsplits
Gand contains
E;
then there exists an extension H of Gby
a central torusZ such that
(a) Hder
issimply connected,
(b)
Z is aproduct
ofcopies
ofResF’/FGm.
In the
terminology
of[K2, §5]
H is an unramified z-extension of Gadapted
to E. Note thatH( F )
maps ontoG(F).
It is not hard to see that the fundamental lemma for
G, E, 0
followsfrom the fundamental lemma for
H, E,
0. Thepoint
is that there is asurjective homomorphism
from the Heckealgebra
of H(for
thehyper- special
maximalcompact subgroup
ofH(F) corresponding
toK )
to theHecke
algebra
ofG,
obtainedby mapping fH
tofG,
whereHere x. is an element of
H(F)
that maps to x and dz is the Haar measure onZ(F)
thatgives
measure 1 to the maximalcompact
sub- group ofZ(F).
Themapping fH ~ fG gives
us(by
means of the Satakeisomorphism)
amapping
where SG
is a maximalF-split
torus ofG, SH
is thecorresponding
maximal
F-split
torus ofH,
andQ(F)
is the relativeWeyl
group ofSG
in G. The
mapping
issimply
thehomomorphism
inducedby X*(SH) ~
X*(SG),
which issurjective
sinceH’(F, X*(Z))
is trivial. From this it isalso clear that
fH ~ fG
iscompatible
with the basechange
homomor-phisms b
for H and G.Furthermore,
the orbitalintegrals
offG
can beobtained from the orbital
integrals
offH by integrating
overZ(F).
There is an
analogous
statement for twisted orbitalintegrals,
in whichthe
integration
is overZ(E)j(O - id)Z(E). Finally,
theassumption
thatF’ contains E
implies
that the norm map induces anisomorphism
Putting
all thistogether,
one can now check that the fundamental lemma for Himplies
the fundamental lemma for G.References
[A] J. ARTHUR: The trace formula in invariant form. Ann. Math. 114 (1981) 1-74.
[G] M. GREENBERG: Schemata over local rings, II. Ann. Math. 78 (1963) 256-266.
[K1] R. KOTTWITZ: Orbital integrals on GL3. Amer. J. Math. 102 (1980) 327-384.
[K2] R. KOTTWITZ: Rational conjugacy classes in reductive groups. Duke Math. J. 49
(1982) 785-806.
[K3] R. KOTTWITZ: Sign changes in harmonic analysis on reductive groups. Trans. Amer.
Math. Soc. 278 (1983) 289-297.
[K4] R. KOTTWITZ: Isocrystals with additional structure. Compositio Math. 56 (1985)
201-220.
[L] R.P. LANGLANDS: Les débuts d’une formule des traces stable. Publ. Math. Univ. Paris VII 13 (1983).
[S] D. SHELSTAD: Base change and a matching theorem for real groups, in Non Com- mutative Harmonic Analysis and Lie Groups, Lecture notes in Mathematics 880.
Springer-Verlag (1981) pp. 425-482.
(Oblatum 28-X-1985) Department of Mathematics University of Washington Seattle, WA 98195
USA