A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
M ICHAEL G RÜTER
J ÜRGEN J OST
Allard type regularity results for varifolds with free boundaries
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 13, n
o1 (1986), p. 129-169
<http://www.numdam.org/item?id=ASNSP_1986_4_13_1_129_0>
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Type Regularity
with Free Boundaries.
MICHAEL
GRÜTER - JÜRGEN
JOST1. - Introduction.
In this paper, we
investigate
the behaviour of rectifiable n-varifoldsnear the free
boundary. Assuming
the varifold V intersects ahypersurface
in
orthogonally (in
ageneralized sense)
and that its mean curvature vector lies in some L?witm p
> n, we show that V is a submanifold of Rn+k(with boundary)
withtangent
spacesvarying
Holdercontinuously, locally diffeomorphic
to a half ballprovided
it isalready
close to a half ball in thesense that the mass of V inside small balls centered at the free
boundary
is not much
larger
than half the volume of the n-dimensional ball with thesame radius and the
density
of V is at least one at almost allpoints
of its
support.
For aprecise
statement of the mainresult,
see Theorem4.13. Some of our
lemmata,
like the reflectionprinciple
4.11(iii),
orthe
monotonicity formulae, 3.1, 3.4,
4.11(ii),
should also be ofindependent
interest.
As the title
already suggests,
our work may be considered as an extension of earlier results of Allard[AW1], [AW2].
We also use some of the tech-niques presented
in the lecture notes[SL]
of Leon Simon.Recently,
freeboundary
valueproblems
for minimal surfaces have at- tracted muchinterest,
and with thehelp
of the results of thepresent
paper,we can
actually
solve a well-knowngeometric problem, namely
to show theexistence of a nontrivial minimal embedded disk inside a
given
convexbody
in R3 which meets theboundary
of thisbody orthogonally.
This iscarried out in our
companion
paper[GJ].
This work was carried out at the Centre for Mathematical
Analysis
inCanberra. We thank Leon Simon for
inviting
us to Canberra and thusPervenuto alla Redazione il 15 Febbraio 1985.
making
itpossible
for us to work in the veryenjoyable atmosphere
of thisCentre. We are also
grateful
to him as well as to John Hutchinson for severalhelpful
discussions.2. - Notation and basic definitions.
We shall deal with rectifiable n-varifolds in which can be described
as follows. For further information the reader is referred to
[AWI], [AW2]
and
especially
to[SL];
thegeneral
referenceconcerning geometric
measuretheory
is of course[FH].
If is
countably
n-rectifiable andJC*n-measurable,
and6>0
alocally Jen-integrable
function on if we define therectifiable n-varifold v(M, 0)
as theequivalence
class of allpairs (M, 6),
whereM
iscountably
n-rectifiable with u
M))
= 0 and where 6=6,
Jen - a.e.on if r1
lit.
As usual we call 6 the
multip Zicity f unction
ofv ( M, 0).
is a C 2-submanif old of dimension m -
1,
we use thefollowing
notation.
For b E B let
and
where A1 denotes the
orthogonal complement
of asubspace A
cFor convenience we denote
by 7:(b)
andv(b)
also theorthogonal projections
of Rm onto these spaces. We assume that
x > 0
is the smallest number such thatwhenever b, b’ E B,
and if a E Rm we sete(a):=
dist(a, B).
x-1 may be considered as a radius of curvature for B. If and if there exists b E B with =la- bl,
then b isunique
and is denotedby ~(a),
sothat ~
is theprojection
onto B.For the
proof
of thefollowing
lemma the reader is referred to[AW2],
Lemma 2.2.
2.1 LEMMA:
(i) ~ is defined
andcontinuously differentiable
on an open set.is
symmetric,
and2.2 REMARK. We use two
equivalent
norms on Hom(ltm,
IfA E Hom
(Rm, Rm)
we setand
we have the
inequalities
We now assume so that
well defined.
In this case we set
then x is the reflection of x across B and we note that and
If w E Rm we set
Then ix
is anisometry
withIf b E B we
get
from(*)
which
implies
forwhere
If we have for
because" :!.
This on the other hand
implies
as well as
We denote
by wn
the volume of the n-dimensional ball of radius one.In the course of the paper C will denote different constants. The pa- rameters on which C
depends
will be obvious from the context.We often write x E as
and denote this
orthogonal splitting
of Rn+kby
Also in this notation
3. -
Monotonicity
results.Let be a C2-submanifold of dimension
n -~-- 1~ - 1 having
thefollowing properties (compare
section 2 fornotation):
(i.e.
B has noboundary
insideB1(0)) .
Then for each a E
B1(O), ~(a)
E B is defined and thus consists of two opencomponents B1(O)
andB1(0).
In this section we assume V=
v(M, 0)
is a rectifiable n-varifold such thatwhenever with for and where
From now on we write Il = pv. .
The aim of this section is to prove
monotonicity
results for V(up
toerror terms
involving integral
norms of H and curvature bounds forB).
Compared
to the interiorregularity theory,
y here an additionaldifficulty
arises from the fact that the balls we are
looking
at ingeneral
intersectthe free
boundary
but are notnecessarily
centered on it. Since for severalreasons it is not convenient at this
stage
to reflect the varifold across the freeboundary,
our idea is to reflect the balls across thisboundary
and addthe mass of V in such a ball and its mass in the reflected ball and prove
monotonicity
formulae for this sum.We now fix and choose for
(7)
the vector fieldwith and where is such
that
for for and
where e
> 0 is such that distNote that because of the definition
of x, ix
this vector field is admissiblein
(7).
Using
theproperties
of theprevious
section weget by
asimple
calculationanalogous
to the one in[SL, § 17]
for for whichTx M
existsdiv
where and where
, , >
has to beinterpreted appropriately.
Thus
(7)
leads to thefollowing integral identity.
Now
take 0 EF 01(R)
such that for for andfor all t and use
(8)
withNoting
thatwe
get
where
Multiplying by
weget
By letting ø
increase to we obtain(x always
denotes characteristicfunctions)
This is the fundamental
monotonieity identity
which reduces to the well knowncorresponding
formula used in the interiorregularity
in case ee(a)
= dist
(a, B),
because thenp(Be(a))
= 0.By
theinequalities
of section 2 we have thefollowing
estimatesAs a first consequence of
(9)
weget
3.1 THEOREM.
If
where
and dist then
whenever or and
if C ~ c .R
we havePROOF. We
only
have to show(13),
because(12)
isjust
the statement of[SL],
17.7.From
(9)
weget, using
Holder’sinequality,
By (11)
we haveand
Thus we
get
the differentialinequality
Integration
from ato e yields
Integrating by parts
we may estimateRearranging
terms andletting §
increase towe get (13). 0
3.2
COROLLARY. If for
some p > n, then thedensity
exists at every
point
x EB1(O),
andis an
upper-semi-continuous f unction
inB1(0).
PROOF. For
xEB1(O)
we have = 0.If x E we
get by (12) (note
thatp(ifj(z))
= 0 for JC ~ (x ))
thatis
non-decreasing
for a~O (x),
and thus exists andequals
0"(p, x). ITO
Now if x E B we argue as follows.
First we note that
by (13)
exists.
With and
1,(or)
as in section 2 weget
Using lim li(a)
=1, i
=1, 2,
we can noweasily
check thatx)
cr 0 ï
exists and that
It remains to show the
upper-semi-continuity
of8~(~u, x).
This is well known ifx 0 B.
Now for
B1(O) (as 0>0y
weonly
have to consider suchy)
and for y
(1, ix - y
E and O and E smallenough
weget
from(12)
and(13)
Letting
weget
on the left hand side of thisinequality [on(li,
Now let 6 > 0 be
given
and choosefirst e
> 0 and then 0 ee
so that theright
hand side of theinequality
can be estimatedby
This
yields
provided ly
-xi s(b).
Thus thecorollary
isproved.
113.3 REMARKS:
(i)
If in . then for each(ii)
If with andsuch that dist then we have for
provided
whereIn fact
by
Holder’sinequality
we haveOn the other hand
letting
in(12)
and(13)
weget
Another
application
of themonotonicity identity (10)
is3.4 THEOREM. If and
if
f or
all where dist thenis
non-decreasing
on(0, R]
andfurthermore
we havewhenever 2vhite
if
weget
Here c, c’ are
positive
constantsdepending only
on n, k.3.5 REMARKS:
(i)
In the situation of 3.3(ii)
we see that(15)
is true withand C as in
(14).
(ii)
As in[SL], 17.6,
weget
the reverseinequalities corresponding
to
(16)
and(17)
if wereplace by provided
PROOF. Because of
[SL], 17.6,
it is sufficient to prove(17).
Denoteand
Then
(10)
and(15) imply together
with(11)
which
implies
Multiplying by
exp andintegrating
from o~to ~
wededuce
(17).
C1Before
concluding
this section with a technical lemmaconcerning
den-sities we have to make a different choice of the vectorfield X in
(7).
If with we use
in
(7)
if distAs
we
get (compare
the derivation of(10))
whenever while for we have
3.6. LEMMA.
Suppose
such that dist and suppose
with
I
and where q is
the
orthogonal projection of
Rn+k onto Rk. Thenwhere
The statement of the lemma can be illustrated in the
following
way:If,
forsimplicity, x
= 1~ = 0 and the mass of V inBR(a)
is close to the massof a half
ball,
then we cannot havepoints
in thesupport
of V withparallel tangent planes
whose connection is almost vertical to theseplanes.
Later on in
4.2,
when we want torepresent
V as agraph
over atangent plane,
Lemma 3.6 will be used to control thegradient
of thisrepresentation.
PROOF. In the
proof,
we shallapply
themonotonicity
formula twice.Once we use 3.4 with radii « C ~
and ~
== y, z and let T - 0 toget
thedensities on the left hand side. On the other
hand,
we use(19) (or (18))
with radii a
e
and a cut-off function h whichequals
1 on thecylinder
over
B§($)
and 0 outside thecylinder
overB’(~).
Thegradient
of h thencontributes the
integrals
A careful choice of aand e finally gives
the desiredinequality.
Here are the details.
Because of
(*),
Remarks 3.3(ii),
3.5(i)
we mayapply
Theorem 3.4with ~
= y or z instead of a and with(1-
instead of .R. We thusget
that
is
non-decreasing
on Since weget
forwhere and or
We now combine
(18)
and(19) choosing
wherewith
for for
and
Noting
that for I we have and for I we have(cf.
section2),
weget
for andwhere we have used the fact that
Combining (**)
with thisestimate, letting
andusing (14)
of Re-mark 3.3
(ii)
weget
for a =and e = (1-
afteradding
upCollecting
terms we deduce the desired result. CJ4. - The
regularity
theorem.In addition to the
assumptions
made in section 3 we assume thefollowing
for the next theorem
where E
(0, 1).
Furthermore we define4.2 THEOREM
(Lipschitz Approximation). Suppose v(O)
c R". Under theassumptions of
section 3 andof
4.1 there exists y =y(n,
a,k, p)
E(0, 2 )
such,that
if
l E(0, 1]
there existsf
=(fl,
...,f k) : B;R(O)
--* Rk withwhere
4.3 REMARK. As before
PROOF. We first
apply
3.6 with a = y = 0 and z E nspt,u,
where we
define P = lzllb
and h =lq(z)IIB,
so that we may take I= hff1°
(we
may assumefl,
h E(0, 1)). Using
4.1 andCauchy-Schwarz
weget
We now
pick
so that for we havewhich
implies
Now we would
get
a contradiction if we hadfor some small 3. Thus for some c as in
(1)
weget
which
finally implies
for any z EBYIR(O)
nspt,u
Let now
6, 1
E(0, 1)
bearbitrary.
Then we may assumebecause if .RnEt-2n-2 is not small the claim follows
trivially by setting
0 and
choosing
csuitably,
aslong as 6 = 3(n,
oc,k, p).
Now letp
E(0, 2 )
and consider the set
Next observe that
by
themonotonicity
formula 3.4 andby
4.1 we havefor
any; E SPt p
r1 and any 0 (1(1- ).R
if
6, #
are smallenough.
Note that theappropriate
choice of 6 indeeddepends only
on n, «,k, p by
4.1.Now let y, Z E G. We
again apply
3.6 with a = y and .R’ =z ~
instead of .R and
1/(l + 1)
insteadof 1,
and conclude(note
thatfor fJ, ð
smallenough, using
an easyargument by contradiction,
or
By
Kirszbraun’s Theorem weget
a function withsuch that
Thus, taking (3)
intoaccount,
weget (1)
for anyy min
andit remains to prove
(2).
We now want to control
spt ,u ~ G.
The idea is clear: Since on thecomplement
ofG,
is
large,
this set has to besmall,
or, moreprecisely,
its measure is controlledby
E.By
the definition of G we have foreach ~
Espt it
r1BP.R/20(O)
- G a radiusa(~)
E(0, Rf10)
such thatand
by (5)
we thereforeget
If however en
(9)
istrivially
true for somesmall
~(~).
By
a well knowncovering argument
we can now selectpoints ~,,
~2’
...E BpR/20(0)
- G such that~B~(~~)(~~)~
isdisjoint
and~B5a(~~)(~~)~
stillcovers
B~R~2o(O) ~
G.Summing over j
weget
Since for we
get using (8)
andincorporating
3-1 into the constant c
To estimate the measure of the
remaining
set we take anyand
pick (0,
such that andThis
implies ~
J and 3.4 in connection with 3.5(ii) yields (F
=graph f )
Now, using
the fact thatv(O)
c l~n and thatwe
get
Here we used the fact that
as well as
By
theproperties
listed in section 2 we haveand the above
inequality
followseasily.
Since we can assume we may conclude
Now the condition
together
with(5)
ensures thatWriting
we see that(11)
and(12) imply
This is true for any and the
covering
lemma
gives
Here
(10)
was usedtogether
with SinceLip
the theorem isproved
with4.4 DEFINITION. The tilt-excess is defined as usual
by
where is a rectifiable
n-varif old,
and T ann-dimensional
subspace
ofIt measure the mean L2-deviation of the
tangent planes
of M from somefixed
plane.
We have the
following
lemmaconcerning
tilt-excess andheight.
4.5 LEMMA. Under the
general assumptions of
section 3 we,have : If
and T is an n-dimensional
subspace of
Rn+k such that thenfor
some constantPROOF. We may assume T = R" and consider the vector-field
where with in
spt
andAs for we see that X is admissible.
By
the definition ofdivM
and because of weget
forHere and in the
following (eii)
and(Tij)
are thecomponents
of thematrices of and 1’.
Now we observe that
((Ei» being
the matrix ofso that
by (7)
of section 3 we havewhere
and
Using
the estimates for D~ from section 2 weget (13).
C7The
following
«Tilt-excess-decay-Theorem »
is the mainstep
in theproof
of the
regularity
theorem.We consider the
following assumptions
where T an n-dimensional
subspace
ofRn+k ,
and whereis defined
by
4.7 THEOREM. 2 any oc E
(0, l)y
> n there are constants(0, l) depending only
on n, p,k,
DC such that theassumptions (4.6) imply
for
some n-dimensionalsubspace
where4.8. REMARKS:
(i)
Suchautomatically
satisfiesas one sees from 4.7 and 3.3
(ii), using
(ii)
The condition8 c 1 -)- ~
canprobably
bedropped.
This wasrecently
shown in the case of interiorregularity by
J.Duggan
in his thesis
[DJ].
PROOF OF 4.7. We may of course
assume ~
= 0 and T = Ign.By
theLipschitz-Approximation-Theorem
4.2 there is and afunction :
satisfying
and
where
The scheme of the
proof
now is as follows:We let
H:(O)
denote the half ball wherev(0)
is chosen to
point
into E* then controls theintegrated
differencebetween
Vmfj
and and we deriveand that
fi
is close to a harmonic function in the sense that for a test func-tion C 1
(cf. (28)
and(27)). Therefore, f
can beapproximated by
a harmonic func- tion uj withvanishing
normal derivative on{.y:.r’(0)==0}
the meanDirichlet
integral
of which is likewise controlledby E,~ .
Standard estimates for harmonic functions thenimply
that on smaller half balls uj is close to aconstant. This in turn
yields enough
information aboutf
to prove the claim.Note that this is the old device of De
Giorgi.
The details are as follows. Because of the
height
estimate(3)
in theproof
of 4.2 weget for j
= n+ 1, ... ,
n+ k
~o that
by assuming
we haveThis
implies
Now let and note that
agrees with a
function
( in aneighbourhood
of iConsider the vector-fields and We
get
were
Since
this
can be written asNow p - a.e.
on lii
= ~ r1graph f
we have whereand therefore
Thus we
get
The terms on the
right
hand side are now estimated as follows.By (14)
we
get
and 4.6
implies
In order to estimate
D,(~)
we observe thatbecause of and the usual estimates for Di.
Combining
theseestimates we arrive at
Since we see that
(18) yields
Using
and weget
and hence
(19)
and(13) imply
By
the sameargument
we deduce from(20)
By
the area formula we see that(21) and (22) imply
in view of(13)
.and
(14)
as well as
where and Since
and we conclude
and
Now let where e is chosen in such a
way that it
points
into and define the half-ballFor we
get
dist
so that
dist
This
yields
which
implies
Thus
(25)
and(26) respectively imply
and
Applying
Lemma 5.1 of theappendix
to we see that for anygiven 6 >
0 there is Eo =Eo(n, k, 3)
such that if 4.6 holds there areharmonic functions
u1, ..., uk :
~ R with theproperties
and
where cr = fle
and denotes the normal derivative.Defining li by li(x)
=+ x · grad Ui(O)
we note that(29), (31) imply for 17
E(0, -1], using
standard estimates for harmonicfunctions,
yThus we
get by (30)
Since sup
implies
Now let I =
(t1,
...,lk) :
Rk and let S be the n-dimensionalsubspace graph (t - 1(0)).
Note that(31) implies v(O)
c S.Note furthermore that we also
get by (26a)
if we assume
But
(35)
nowimplies
where 7: =
(0, 1(0)).
If we assume : we
get by (34)
that sothat
(4.5)
and(37) imply
To
complete
theproof
of 4.7 we argue as follows.Let 77 E
(0, 2]
such thatc1}2:1 (y/4)2(1-n/p) and 6 >
0 such thatcq-"-2 3 I (r~~8/4)2(1-’~m> (in
both cases c is the constant from(38)). Finally
chooseEo such that for all the conditions
required
in theproof
hold as well asCEO 1 (n#/4)2(l - n/v) (in particular
80 mustsatisfy
the conditionsleading
to(16), (29), (30), (36), (37)
and(38)).
Thus weget for 7y
=qflf4
Since we
trivially
haveas well as we conclude
and this finishes the
proof
of Theorem 4.7. 1:3We are now in a
position
to prove(one
versionof)
theRegularity
Theorem.It will follow rather
easily
from iteration of 4.7.4.9 THEOREM.
Suppose
a E(0, 1)
acnd p > n aregiven.
There are constantsand such that
if (4.6)
holds withas well as the
general assumptions of
sections 2 and3,
thenthere is a
C1 ~a function
such thatx
graph u for graph u,
and
where and
PROOF.
By
themonotonicity
result3.4,
Remark 3.3(ii)
we see that forand for we
get (using 4.6)
so that for
fl, s
smallenough
we havefor and
At first let us consider the case
By
theTilt-Excess-Decay-Theorem
4.7 and(41) (replace e by
(1, aby by )
we know that there are Eand q
such that for 6 cand’
as in(*)
if
So
c is any n-dimensionalsubspace
withv(~)
cSo
andSi
a suitablen-dimensional space c JLgn+k with
11(’)
c81. By
induction weget
a sequence of n-dimensionalsubspaces v(’) c 8i
such thatE*(~,
6,So)
éimplies
and
by
Remark 4.8Now note that for
So = v(~’) -E- T~,
where and for~
E B r1B(l/2(O),
weget
cSo
as well aswhich
implies
for this choice ofSo
and a =e/2
If thus 4.6 holds
with ~
=0,
T = and c-1 E inplace
of 8(c
as in(45)),
we see that
(45)
in connection with(43)
and(44) yields
for with
So = v(~) -~- T~. Obviously (47) implies
the existenceof an n-dimensional
subspace
c R"+ksatisfying v(C)
c such that forall
in
particular
weget for j
= 0If r E
(0, Q/2)
then(46)
and(48) yield
in the usual wayfor and each
0 C r c ~O/2.
Notice that(49)
and
(50) imply
forIf now on the other hand
we
get (cf. [SL])
from the interiorregularity
if as well as
Now let such that and choose
such that
.. - - ~=
Then
(52)
and(53) respectively imply
with
To (Si
as in(46) depending
on~)
andSi+i
=Tj
and
As above this
implies
the existence of an n-dimensionalsubspace S(,)
such that for
and
We also
get analogous
to(50)
and(51)
for 0 r cand I
as in( **)
and
Thus we
get
forsufficiently
small 8(by (51)
and(59))
that if G is as inthe
proof
of 4.2(with I
=811(2n+3))
thenG)
= 0(fl, 8
smallenough) :
That is
where is
Lipschitz
withf (0)
= 0 andWe shall now show that we even have
Suppose
there is a Since0 E spt ,u
there is 0 such that
now take If B we see that
(63),
(60), (61)
and8 c 1 -E- ~ imply ~*)
1(if 8
issufficiently small)
whichcontradicts the fact that for any Note
that we make use of the upper
semicontinuity
of On. If on the other handC*
E B we know that~*) ~ 2 .
But sinceboth ~ and I*
are in(63)
would
again imply 8 n (,u, ~* ) C 2 .
Thus(62)
is established.Using
the area formula we see that(62) implies
for any n-dimensionalsubspace
=graph 1,
where I : is linear withIgrad
=1,
and
by (49), (50)
and(57), (58) respectively
thisimplies
that for each there is a linear function R" - Rk such thatfor
If then for small
enough r
wehave. so that
(64) yields, letting r~0, grad
The
only
other case to consider is Be-cause of
(61)
and ourassumptions
about B weget
which also
implies grad
Now, using (64) again,
we concludeif and This
clearly implies
for The theorem now follows
with
Let us
finally
show that the conclusions of theRegularity-Theorem
remain true if we make the
following assumptions
for some
where is to be
specified.
Repeating
theargument
which led to(41)
in theproof
of(4.9)
weget
for and
if
I and is smallenough (j
is definedby
and we have used
c Be (0 ) ) .
Thus to show that the
assumptions (4.10) imply
theassumptions (4.6)
we have to find a suitable
subspace
T such that.E(~,
6,T)
can be made assmall as we wish. In view of Lemma 4.5 it is sufficient to bound the
height appropriately.
This will be done in the next lemma.Let us first make some
important
remarks.4.11 REMARKS:
(i)
Let us first show that theassumptions (4.10) imply
for
some f1 =
> 0 and 6 > 0 smallenough.
From(67)
and the uppersemicontinuity
of6n(,u, ~ ) (c.f. Corollary 3.2)
it follows thatfor Since
0 > I /-z -
a.e. weget (*).
Thus from nowon we may assume
(ii)
We consider the total first variation of V =v(M, 0),
defined asusual as the
largest
Borelregular
measure~~
such that for all openWe are now
going
to show that~~
is a Radon measure onB1(0).
Asin
[AW2, 3.1]
this will follow from amonotonicity
formula for tubularneighbourhoods
of thesupporting
surface B. Weproceed
as follows.For any
V c- C’(B,(O)), y >0,
we consider the vector-fieldwhere is
decreasing
and satisfies(0 h «1)
Obviously X
is admissible and asimple
calculationyields
Here we used the fact that
As in section 3 we take such that for for
t > 1, §’ 0
and setSetting
we
get
theequation
which after
multiplying by
h-2 can be written asLetting
we obtain thefollowing monotonicity identity for
tubularneighbourhoods
of BIntegrating (68)
from h to h’(0 h h’)
andletting h§0
weget
theexistence of
h(~),
definedby
Note that
11 Q
From the
representation (69)
we see that r is adistribution,
but since ris
positive
it induces a Radon-measure onB1(0),
i.e. it can be defined for Now consider any and any with0 ~ spt cp’ . Defining
Xv and XZby
we
get
furthermore we have
Letting suitably
andusing
the fact thatp(B)
= 0 weget
Since
grad
weget
this
yields
Together
with the considerations made above weget
that~~
is aRadon measure on
Bl(0)
and that we have theinequality (1’
as in(69))
By
well knownrepresentation
theorems there exists aY 11 -measurable
function such that for any
(iii)
In thespecial
case where H = 0 and B is ahyperplane
we havethe
following
reflectionprinciple (cf. [AW2], 3.2).
First we note that(70) implies
for any - such that
Consequently
wehave
spt 11
c B andfor
IlðV11 -
a.e. x E B.If we now consider the reflection across
B and the reflected varifold we
get
for Thus we see that is
stationary
inB,
i.e. for any we have
We are now
ready
to prove the final lemma.4.12 LEMMA. For
any one-dimensional subspace
Y c and any 8 > 0 there exists6,,
> 0 such that thefollowing
is true.If
B andV satisfy
thegeneral assumptions
made at thebeginning of
section 2and
additionally
= Y as well as(4.10) ðo
then there exists an n-dimensionaZsubspace
T with Y c T such thatPROOF. We may assume (! = 1 and argue
by
contradiction. So suppose there is E > 0 and a sequence ofB i , Tr2
such that for any n-space T withY c T we have
and such that
(4.10)
holdswith e
= 1 andbi
=1/i. Passing
to asubsequence (again
denotedby i)
weget
the existence of a varifold C such that = C in the space of n-varifolds and such that thecorresponding Bi
converge to B = in an obvious sense. We conclude that C is a rectifiable n-varifold inJ5i(0)~~ satisfying
for any with because any such X can be
approximated by Xi
such that and forFrom
(67)
we conclude thatand
by [AW1, 5.4]
weget
for yc - a.e. x E
B1(0).
Note that the conditionlim inf ~~ ( W )
oo forany open
easily
follows from therepresentation
of 1~ in(69).
Since B is a linear
subspace
isincreasing
on(0,
1-R)
ifx E B r1
BR(O) (the
vectorfield used in theproof
of the interiormonotonicity
is
admissible!).
Thus forany
1- 2-1/n = : R* and x E B nBR(O)
because of
(72).
In view of(75)
thisimplies
By
the reflectionprinciple,
Remark 4.11(iii),
we see that C’= C-f-
isstationary
inBR.(O)
and thatUsing again
themonotonicity
as well as
(72), (75)
weget
for
By [AW1, 5.3]
thisimplies
the existence of ann-space such that
It follows that
for and since
we conclude and thus
By
the definition of P we now see that Y = B1 c T. Now(71) implies
that there is a sequence
Since
sptu,
c T weget
for ilarge enough
where c is
independent
of i(use monotonicity);
as 6 > 0 can be madearbitrarily
smallby choosing i large enough
weget
a contradiction.This proves the claim of the lemma. 0
Altogether,
we haveproved
4.13 THEOREM. For any there exist
with the
following property.
If
is ahypersurface of
class C2 withand the curvature
of
Bsatisfies
and
if
is arectifiable n-varifold
withf or
all with andthen there is a and an
isomery 1
of
Rn+k withgraph u
forand
5. -
Appendix.
In the
proof
of Lemma 4.7-cf. theargument leading
to(29)
and(30)
we needed the
following simple
lemmaconcerning
harmonic functions. It is an easy consequence of Rellich’s Theorem.5.1 LEMMA. Given
a%g 6
> 0 there is a constant8(n, ð)
> 0 such thatif
satisfies
and
f or
acny then there is a harmonicfunction u
on Hsatisfying
on such that
and
PROOF. If the lemma were false there would exist 6 > 0 and a sequence such that for any
and
but
whenever u is harmonic on and
If then
by
the Poincaréinequality. By
Rellich’s Theorem there is asubsequence
such that
f k, - ~k, --~ ?,v ( -~
means weak convergence in~H2 )
andin
L2(g),
whereBy (1 )
we havef or any This
implies
that w is harmonic on Handon xn = 0. With we
get
This contradicts
(3)
and the lemma isproved.
C(REFERENCES
[AW1]
W. K. ALLARD, On thefirst
variationof
avarifold,
Ann. Math., 95(1972),
417-491.
[AW2]
W. K. ALLARD, On thefirst
variationof
avarifold: boundary
behavior, Ann.Math., 101
(1975),
418-446.[DJ]
J. DUGGAN,Regularity
theoremsfor varifolds
with mean curvature, Ph.D.thesis, Australian National
University,
1984.[FH]
H. FEDERER, Geometric measuretheory, Springer-Verlag, Berlin-Heidelberg-
New York, 1969.
[GJ]
M. GRÜTER - J. JOST, On embedded minimal disks in convex bodies, to appear in:Analyse
non Linéaire.[SL]
L. SIMON, Lectures ongeometric
measuretheory, Proceedings
of the Centrefor Mathematical
Analysis,
Australian NationalUniversity,
Canberra,Vol. 3, 1983.
Mathematisches Institut der Universitat Diisseldorf Universitatsstrasse 1 D-4000 Diisseldorf 1