A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
S ERGE N ICAISE
About the Lamé system in a polygonal or a polyhedral domain and a coupled problem between the Lamé system and the plate equation. I : regularity of the solutions
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 19, n
o3 (1992), p. 327-361
<http://www.numdam.org/item?id=ASNSP_1992_4_19_3_327_0>
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and
aCoupled Problem
betweenthe Lamé System
andthe
Plate Equation
I: Regularity of the Solutions
SERGE NICAISE
1. - Introduction
This paper is the first of a series of two, devoted to the
regularity
of thesolutions of some
problems
related to the linearelasticity theory
and to theexact
controllability
of the associateddynamical problems.
Part I concerns theregularity,
while Part II willstudy
the exactcontrollability.
On a first step, we
study
the Lame system in apolygonal
domain of theplane
or apolyhedral
domain of the space. The interior datum is assumed tobe in
L2,
and theboundary
conditions are mixed andnon-homogeneous.
Thismeans that on a
part
of theboundary
weimpose
Dirichletboundary
conditions(i.e.
thedisplacement
vector field isfixed)
and on the remainder of theboundary
we
impose
Neumannboundary conditions,
in the sense that the normal traction is fixed. Wegive
thesingular
behaviour of the weak solution of this systemnear the comers
and,
in dimension3,
alsoalong
theedges.
In dimension2,
this is provenby
P. Grisvard in[9] (see
also[21]).
In dimension3, partial
resultswere
given
in[9]
and[20];
hereadapting Dauge’s
technics of[3],
wegive
vertex
singularities
andedge singularities
up to the vertices butonly
for smallregularity
for theregular
part(namely H3/2+ê,
for some 6’ >0).
With these
results,
it ispossible
to findgeometrical
conditions on the do- main which ensure theregularity H3/2+ê,
for some , - > 0, for the weak solu- tion. Asclassically (see [22], [8], [16], [11]),
toget
thisregularity result,
it suffi-ces to establish the existence of a
strip
free ofpole.
When theboundary
condi-tions are
purely
of Dirichlettype,
thestudy
of suchstrips
is wellknown(see [22], [4], [21] in
dimension 2 and[16], [11]
in dimension3).
When theboundary
con-ditions are
mixed,
it seems to be new. In dimension2,
our conditions are neces-sary and
sufficient,
while in dimension3,
in view of Grisvard’s results about theLaplace operator
in[8],
we think that it isperhaps possible
toimprove
them.Pervenuto alla Redazione il 20 Marzo 1991.
As an
application
of these results(and
this isactually
one of our moti-vations to prove
them),
westudy
theregularity
of the solution of acoupled problem
between the linearelasticity system
in the unit cube ofJR3
with aplane
crack and theplate equation
on aplane
domain. Thisproblem
differsfrom the
problem
obtainedby [2] only by
theboundary
conditions. But as weshall
explain
at the end of this paper, this is necessary toget positive
results.Unfortunately,
ourproblem
isperhaps
no so realistic from the mechanicalpoint
of view.
Nevertheless,
we may say that we answer to thequestion
ofregularity
raised in
Paragraph
6 of[2].
Ourcoupled problem
is similar to the modelproblem
studied in[19]
but the obtainedregularity
results and the methods ofproof
are different since theLaplace operator
is more convenient than the Lame system.In the second part of this paper, we shall consider the exact
controllability
of the associated
dynamical problems.
As in[8]
and[19],
theseregularity
resultswill be useful in order to
adapt
the HilbertUniqueness
Method of J.-L. Lions[13].
Let us now introduce some notations. Let Q be a bounded open connected subset of E
{2, 3}. We
suppose that theboundary
8Q of Q is the union ofa finite number of faces
fk, where,
in dimension2,
eachrk
isactually
alinear
segment, while,
in dimension3, rk
is aplane
face(it
is more convenientto assume that
rk
isopen!).
If Q hasslits,
we assume that each slit issplit
up into two faces.In order to consider mixed
boundary conditions,
we fix apartition
of 7into D U
.N,
where D willcorrespond
to Dirichletboundary conditions,
while N to Neumannboundary
conditions.. Given a function w or a vector
field u
defined on as2, it will be convenientto denote
by w (k) , respectively p,(k),
its restriction tork,
for allMoreover,
for a vector u of R~ we denoteby
ui its i-thcomponent,
for all i E{ 1, ... , ?~},
i.e. u =
We associate with the
displacement
vector field u the linearized straintensor
e(u)
definedby
and the linearized stress tensor
u (u) given by
Hooke’slaw, using
the Lamecoefficients A
and it (A and o
arealways
assumed to bepositive):
We introduce the Lame
operator
For all k E
I,
we also denoteby -Yk
the trace operator on the facerk, V(k)
the outward normal unit vector onr~
andGiven a vector field f E
(L2(S2))n (which
represents the forcedensity applied
to thebody Q)
andg~~>
E(H1/2(rk))n,
for all k EN,
we consider the weak solution u E(H 1 (SZ))n
of the Lame systemwith mixed
boundary
conditionsThis
problem
admits thefollowing
variational formulation: we introduce the Hilbert spaceand the continuous
sesquilinear
formTherefore,
we shall say that u is a weak solution ofproblem ( 1.1 )-( 1.3),
ifu E V is a solution of
...
where,
from now on,(., . )
denotes the innerproduct
in Cn.In all this paper, we shall use the Sobolev spaces
defined,
forinstance,
inParagraph
1.3.2 of[6],
when s E R and p > 1. When p =2, they
are
usually
denotedby Moreover,
we also use theweighted
Sobolevspaces defined in
(AA.2)
of[3],
when s >0, I
E R and r is a cone ofR".
2. -
Regularity
of the solution of the Lam6system
in dimension 2The behaviour of a solution u of
( 1.4)
near the vertices of Q iswellknown;
using
Theorem I of[9],
we obtainimmediately
thefollowing (see
also[21]):
THEOREM 2.1. Let u E V be a solution
of (1.4) with data
f E(L2 (SZ))2,
E
(H 1 ~2 (r~ ))2,
Vk E .N . Let usfix j,
kEN such thatrj ~b
and let usdenote
by
S their common vertex andby
w the interiorangle
betweenr~
andrk.
Then there existcoefficients
ca,lI such thatwhere W is a
neighbourhood of
S, the sum extends to all roots a c Cof
in the
strip R(a) E]O,
2 -2/p[. N(a)
is themultiplicity of
a in(2.2) (N(a)
= 1or
2,
see[22]). Finally,
are the so-calledsingular functions defined by (1.4) of [9].
This result holdsfor
all p 2 such that theequation (2.2)
has noroot on the line
R(a)
= 2 -2/p.
If j,
this result remains trueif
wereplace (2.2) by
in that case, the Q "w ’s are
defined
inParagraph
6.1of [9].
If j
EN,
kE 1) or j
EV,
k EN,
thenagain
this result still holds when(2.2)
isreplaced by
the o, l,"s
being defined
inParagraph
6.2of [9].
In view of this
theorem,
if we want toget
a maximalregularity
for u, itis necessary to show that a
strip R(a) E]0,2 - 2/p[
has no root of(2.2), (2.3)
or
(2.4).
This is the purpose of theTHEOREM 2.2.
If
wE]0,27r[,
then theequations (2.2)
and(2.3)
have noroot in the
strip R(a)
P( )
E1 0,1?/2] , 2
On the other hand,
the equation (2.4)
q ( )
has no
root in the same
strip if
wBefore
proving
thisresult,
let usgive
its consequence:THEOREM 2.3.
If
Qsatisfies
theassumption
(H2) b’j,
such thatr~ nll’k 4 0,
the interiorangle
w betweenr~
and ]Fkfulfils
w 27r and moreover,if j
and w 7r.Then a solution u E V
of (1.4)
with data f E(L2 (SZ))2
andg(k)
E(H 1 /2 (]Fk))2,
Vk E Nsatisfies
PROOF.
By
Theorem 2.2 and thehypothesis (H2),
thestrip
E1 o 12
is free of root at each vertex of S2.
Moreover,
it is wellknown that in a fixedstrip
E[a, b],
with a, b E R, theequations (2.2)
to(2.4)
haveonly
a finitenumber of isolated roots; therefore there exists p
E]4/3, 2[ (sufficiently
closedto
4/3
ifnecessary)
such that thestrip E]o, 2 - 2/p]
is free of root at each vertex of Q.Owing
to Theorem2.1,
we deduce that u E(W2,p(i2))2,
for sucha p.
Using
the Sobolevembedding
theorem(see
Theorem 1.4.4.1 of[6]),
weobtain
(2.5)
since theassumption (H2) implies
that Q has aLipschitz boundary.
D PROOF OF THEOREM 2.2. The
equation (2.2)
was studiedby
a lot ofauthors
(see [22], [14], [7], [4]
forinstance). Actually,
our result for(2.2)
is adirect consequence of
§5
of[4].
Let us nowstudy
the roots ofwith K
e]0,1].
l > > Thisequation
q(2.6) ( )
recovers(2.3) ( ) since 2013~- ~1~
it alsoa+3 >
> Lrecovers
(2.2) by taking
K = 1. It is obvious that a is a solution of(2.6)
if andonly
if a fulfils(2.7)
or(2.8)
below:Let us show that if w
e]0,27r[,
then(2.7)
has no root in thestrip
E]0, 1/2].
Ananalogous
argument shows the same result for(2.8).
Writing
a= ~ + ir~,
with~,
q E R, andtaking
the realpart
andimaginary part
of(2.7),
we arrive to thesystem
For a
fixed ?7
e R, consider the two functions:Then we
easily
chech thatSince
f
1 is concave in the interval[0,7r/o;] (notice
that1/2 7r/w),
weget
forTherefore
(2.9)
has nosolution ~
in theinterval ~
E0 , 2 ,
so does(2.7).
Let us now pass to the
equation (2.4)
under thehypothesis w
E[0, ir[.
Itcan be written
where we set and
Writing
, withFirst case. If
1] f 0,
then asolution ~
> 0 of(2.13)
fulfilsIndeed, (2.13)
is thenequivalent
toWe obtain
(2.14)
since on theinterval ~
c1 JO, -~-
2W,
the left-hand side of(2.15)
is
positive,
while theright-hand
side isalways negative.
Second case. If q = 0, then
(2.12)
has no solutioncase,
(2.12)
becomesIn that
By
a directcomputation,
we check that the left-hand side is(strictly)
lower thanthe
right-hand
sideat - 1. 2
2 We obtain the result since in the intervalL 0
’2w ’
2wthe left-hand side of
(2.16)
isincreasing,
while itsright-hand
side isdecreasing
1 7r
(notice
that w 7rimplies
Joining together
the two cases, we obtain the result for(2.4).
This com-pletes
theproof
of Theorem 2.2. DREMARK 2.4. The
geometrical assumptions
made in Theorem 2.3 toget
theregularity
result(2.5)
areexactly
the same as for theLaplace operator
with mixedboundary
conditions madeby
P. Grisvard in[8]. Moreover, they
arein accordance with some
figures given
in[21]
for someparticular examples.
They
are our motivations to establish Theorems 2.2 and 2.3.Moreover, they
are necessary in. the sense that if
(H2)
fails then there existsingularities
whichdo not
belong
toH3/2+ê(Q))2.
3. - Vertex and
edge singularities
of the Lamesystem
in dimension 3 In dimension3,
the behaviour of a solution u ofproblem (1.4) along
theedges
wasgiven by
P. Grisvard in[9]. Moreover,
it ispossible
to prove ageneral regularity
result at the vertices andalong
theedges
as Theorem 17.13 of[3]
when theboundary
conditions(1.2)-(1.3)
arehomogeneous (adapting Paragraphs 17, 22,
23 and 24 of[3]
to thisproblem).
A sketch of theproof
was
given
inParagraph
1 of[20].
Since we are interested innon-homogeneous boundary
conditions and since we allow crackeddomains,
it isimpossible
touse a trace theorem to go back to
homogeneous boundary
conditions.Therefore,
we shall show that Theorem 17.13 of
[3]
still holds for oursystem (1.1)-(1.3)
but
only
with aregular part
inH 3/2+,(12)
for some e > 0(instead
ofH2).
Fortunately,
it is sufficient for theapplications
to the exactcontrollability (see [8]).
Let us start with the
singularities
at the vertices. To dothat,
we fix a ver-tex ,S of Q. In a
sufficiently
smallneighbourhood
ofS,
Q coincides with apolyhedral
coners
ofR3.
We denoteby Szs
the intersection betweenrs
and the unitsphere
centered at S. We shall also usespherical
coordinates(r, w)
withorigin
at S ; in that way, we haveLet us denote
by Ts,
the set of faces ofrs,
i.e.J’s
={ k
E 7 : ,S EFk).
Foreach k E
Fs,
we shall denoteby rk
the face ofrs containing
the facerk
ofQ; h’k
will be thecorresponding
arc of theboundary aQs
ofFinally,
wemisuse the notation ik for the trace operator on
rk
orrk,
for all k EFs.
Obviously,
thepartition
D U N of 7 induces apartition Ds
U ofls.
We are now able to set
fulfilling
fulfilling
Using
a cut-offfunction,
tostudy
the behaviour of a solution u of(1.4)
nearthe vertex S, we may suppose that u has a
compact
support, let us sayand that it fulfils
for all v E
V(Fs);
where f E(L2(rs))3, g~k>
E(H( 1/2)(V k))3,
for all kE .Ns
witha compact support.
As usual
[10], [15],
theasymptotic
behaviour of u near ,Sdepends
on afamily
ofoperators
withcomplex parameter
a, that we now introduce(in
a variationalway):
we write the operatorDj
inspherical
coordinates andwe set
For cx E C and a vector field v, we set
For all a E C, we introduce the continuous
sesquilinear
formas(a)
onV(Qs)
definedby
Finally,
theoperator
is definedby
We shall now
give
a resultanalogous
to Lemma 17.4 of[3];
itsproof
issimilar but
using
the variational formulation as inProposition
24.1 of[3].
AsM.
Dauge,
we shall use the Mellin transform. Let us recall that for u Ethe Mellin transform of u,
M[u],
is definedby
In the
following,
we shall use without comment theproperties
of the Mellin transformgiven
in theAppendix
AA of[3].
Since u E and has a
compact support,
we deduce thatis
analytic
with values in(HI (i2s))’
in thehalf-space R(a) - 1/2.
In the sameway, if we set -
we know that F
(respectively G~k~ )
isanalytic
with values in(L2(Qs))3 (respec-
tively
for1/2.
Using
thechange
of variable r = el and the Parsevalidentity,
we seethat
(3.2) implies
that(roughly speaking,
itcorresponds
toapply
the Mellintransform to
(3.2))
for when
is defined
by
But
arguing
as inProposition
8.4 of[3]
andusing
the fact that Kom’s ine-quality
holds onrs,
we can prove theLEMMA 3.1. For
~3,
-1 E II~fixed,
there exist two constants andsuch that
for
all afulfilling ~(a)
Eand Aa,,~,
we havefor
all u E(H1(Qs))3 (see (AA.17) of [3] for
thedefinition of
the normof Moreover,
it is easy to see that for all a, a’ E C,As(a) - As(a’)
isa compact
operator. Owing
to theanalytic
Fredholmtheorem,
is mero-morphic
on C. So there exists - > 0 such thatAs(a)
is one-to-one on the line~2(«) _
ê.We now conclude as in Lemma 17.4 of
[3];
we seton the line
R(a) =
ê. Then the estimate(3.4)
and the definition ofAs(a) imply
that there exists a constant C > 0 such that
So
by
the Mellin inversion formula on the lineR(a)
= 6:, weget
that the functionuo belongs
to(H’ i_,(Fs)) ,
since thehypotheses
made on f andinsure that
Since on the line
%(a) =
e,N[uo](a) = v(a)
and F and(G (k) )klv,
areholomorphic
in aneighbourhood
of thisline,
the Parsevalidentity
allows us toshow that uo fulfils
for all’ such that supp i
By
a standard argument(see [10])
based upon theCauchy
formula forrav(a)
onrectangular paths tending
to the infinitepath R(a) = - 1/2, R(a) =
ê,we get that
(it
is easy to show that is one-to-one on the lineR(a) = - 1/2)
where the sum extends to all a in the
strip
does not exist and
such that ,
Therefore,
it is clear that there existQ(a)
E N and functions q Ef Q(a)}
defined onQs
such thatLet us now show that all and
satisfy (3.9)
below:Firstly,
if we compare(3.2)
with(3.6),
u - uo fulfilsHence,
u - uo isregular (i.e.
inH2) far
from the vertex S and theedges
ofrs .
Taking
test-function v E n(Ð(rs))3
such that v = 0 in aneighbourhood
of the
edges
ofrs, by
Green’sformula,
we deduce that u - uo fulfils(3.9).
Writing
L andT(k)
inspherical
coordinates andusing
the fact that functions of the form with different aiand qi E N,
i =1,..., N,
arelinearly independent,
we conclude that andsatisfy (3.9).
In summary, we have proven the
THEOREM 3.2. Let f E
(L2(rs))3,
E(H1/2(r~))3,
b’k EJVs
and letu E
V(rs)
be a solutionof (3.2)
with a compact support. Then there exists3
e > 0 and a
function
uo E which is a solutionof (3.6),
suchthat
where the sum extends to all a in the
strip
thatwhere the sum extends to all a in the strip
( )
G]
2 such thats( )
does not exist;
the function
admits theexpansion (3.8)
andsatisfy (3.9).
Now,
in order to getedge singularities
up to the vertexS,
let us introducesome notations
(see § 17.B
of[3]):
. denotes the set of vertices of
SZs (it
is the set ofedges
ofrs ).
. If x e there exists a local chart X~
sending
aneighbourhood
of xin
SZs
onto aneighbourhood
of 0 in a coneCx
of withopening
wx.Since x
corresponds
to the commonedge
betweenrk
andr~ ,
for somej, k
e Wx is the interior dihedralangle
betweenr~
and rk . We shalldenote
by zz
the cartesian coordinates inOx.
will be thesingularities
introduced in
Paragraph
2 associated with the Lamesystem
in the coneCx
withboundary
conditions inducedby
theboundary
conditionsimposed
on
rj
andrk,
when a is a solution of(2.2), (2.3)
or(2.4)
with w = Wx. Inthe same way, we introduce the
singularities aax’
of theLaplace
operator inthe cone
C.,
withboundary
conditions inducedby
theboundary
conditionsimposed
onr~
andrk.
Moreprecisely, using polar
coordinates(rx, 0z) in
the cone
C.,
such that0z
= 0 onrk and 0z
= w2 onrj,
we set, then i and
, the I and
, then for all and
If j, k
e then a’ =m7r/wx,
for all m e N* and is definedby (3.12).
For e > 0, we set
is a solution of such that
equal
to orFinally,
we introduce thesmoothing
operator definedby
where ~p2 is a cut-off function defined on
Qs
such that 1 in aneigh-
bourhood of x and pz = 0 in a
neighbourhood
of the othervertices. 0
is thefunction introduced
by
M.Dauge
in(16.6)
of[3]
i.e.when
r ( E, zx ) _
X is a continuous function on R suchthat x >
1on R and
x(t) _ ~ It I
if t > to > 0and p
is arapidly decreasing
function on II~+such
that p
= 1 in aneighbourhood
of 0.By
c *t0,
we mean. We also introduce the matrix
This matrix allows us to pass from u to
(ur,
uo, theprojections
of the vectoru in cartesian coordinates onto the
spherical
basis i.e.Now,
we areready
togive
theanalogue
of Theorem 17.13 of[3]
to our system.THEOREM 3.3. Let f E
(L2(rs))3,
E(H 1/2(r-I k))3,
Vk ENs,
and letu E
Vcrs)
be a solutionof (3.2)
with a compact support. Then there existse > 0 such that
where ur
PROOF. In view of Theorem
3.2,
it suffices tostudy
theregularity
of thefunction Uo E
(H~1/2-ê(r 8))3,
solution of(3.6).
Let usperform
thechange
ofvariable r = et and set
By
Theorem AA.3 of[3],
we can show that(recall
that f and havecompact
supports
inrs ) :
Moreover,
the Dirichletboundary
conditions fulfilledby
uo onrs
inducedanalogous boundary
conditions on R xnamely
w EV(R
x when weset
where uk
denotesimproperly
the traceoperator
on R xT’k. Finally, by
thischange
of variable and(3.14),
theidentity (3.6)
becomeswhere we have set
This shows that w is solution of a
boundary
valueproblem
on the dihe-dral cone R x So to obtain
(3.13),
it suffices togive
thesingularities
ofw
along
theedges
of R xQs.
This is proven as Theorem 16.9 of[3], using
Theorem 2.1 on
SZS
for thecomponent
and Theorem 4.4.3.7 of[6]
for wr, instead of Theorem 5.11 of
[3]
because we noticethat, using
the localchart xz, the
principal part
of theoperator As,
inducedby
thesesquilinear
forma, frozen at 0, is the
system
ofelasticity
inC2
for(wo,
and theLaplace
operator for wr.
Finally,
theassumption
on coerciveness for thisprincipal part
holds here since Kom’sinequality
is true on the coneCz. Actually,
if SZ has acrack at x, then
C.,
=I1~2~I1~+,
with the convention ={(Xl, 0) : 01;
then toget Kom’s
inequality
onC2,
it suffices tosplit
upex
into twohalf-spaces
whereKom’s
inequality
holds.Therefore,
as in Theorem 16.9 of[3],
we deduce thatw admits the
following expansion
where wr r E
(H3/2+e(R X
s , xH1/2+E-R(a)(R)
, z .Let us notice that this result holds if the
equation (2.2), (2.3)
or(2.4)
withw = w2 has no solution on the line =
1/2+6-,
for all x E Since theset of solutions of these
equations
is finite in a fixedstrip
and the set of a, suchthat does not
exist,
is also finite in a fixedstrip,
it isalways possible
to find a c > 0 such that the line =
1 /2 + ~
has no solution of theequation (2.2), (2.3)
or(2.4)
at each vertex ofS2S
and suchthat,
on the lineR(a) =
e,exists
(at
thebeginning
of thisproof,
we take thecorresponding uo).
Using (3.16),
thechange
of variable(3.14)
and theexpression (3.10)
ofu, we obtain the
expansion (3.13)
for u, whenThis
completes
theproof
since Theorem AA.3 of[3]
allows us to conclude that/ 3 3
and this last space is
obviously
embedded into . D REMARK 3.4. Theproof
of theedge
behaviour of uo is different from theproof
ofProposition
17.12 of[3].
Our idea consists insetting (3.14)
andtherefore to go back to the
boundary
valueproblem (3.15)
in the dihedral coneR x This allows us to avoid the localization arguments of
[3].
4. - Maximal
regularity
for the Lamesystem
in dimension 3Theorem 3.3 shows that if we want to
give
a maximalregularity
for asolution u of
problem (1.4),
we need to control theedge
and vertexsingularities.
The
edge singularities
do not pose anyproblem
sincethey correspond
to vertexsingularities
in dimension 2. It remains the vertexsingularities.
When theboundary
conditions on all the faces are of Dirichlet type, an estimate of astrip
free ofpole
for can be deduced from[16]:
LEMMA 4.1. Let S be a
fixed
vertexof
Q.If Qs
isdifferent from
the unitsphere ,S’2
andNs
=0,
then existsfor
all a in thestrip R(a)
E[-1, 0].
PROOF. Let us suppose that there exists cx in the
strip R(a)
E[-1,
0] such that does not exist. In that case, Theorem 3.2 shows that there existsa function on
Qs
such that fulfils(3.9).
But Theorem 1 of[16]
excludes the existence of such a solution in the
strip
for some ao > 0. This is a contradiction since this
strip
islarger
than ours. DUnfortunately,
Theorem 1 of[16]
uses in a basic way the Dirichletboundary
conditions and it seems to beimpossible
to extend it to mixedboundary
conditions. Forpurely
Neumannboundary conditions, using
a differentmethod, Maz’ya
and Kozlov prove in Theorem 3 of[ 11 that,
ifSZs
has nocrack,
then the conclusion of Lemma 4.1 still holds. Under ageometrical assumption,
we now prove that their method can be
adapted
to mixedboundary
conditions.For a fixed vertex S of Q, let us set
with the
agreement
thatCS,D (respectively CS,N)
is empty ifDs (respectively NS )
is empty.THEOREM 4.2. Let S be a
fixed
vertexof
Q.If S2s
has no crack andCs,D n Cs,N
=0,
theni) If 0, As (a) -
1 existsfor
all a in thestrip R(a)
E[-1, 0].
ii) If Ds = 9~, As (a)-1
1exists for
all a in thestrip R(a) E [-1, 0]
exceptfor
a = 0 and -1, where
kerAs(a)=C3.
PROOF. The case
Ds = 0
isprecisely
Theorem 3 of[ 11 ] (see
Remark 2 of[ 11 ]).
So from now on, we can suppose thatDs f 0.
Wefirstly
establish that exists for all a on the line = 0. To dothat,
as in Lemma4.1,
we show that a functionu ~ 0
in the formwith some
function
defined onS2s
and = 0, cannot be a solution of(3.9).
Let us suppose the
contrary.
Then theassumption
thatQs
has no crack insure that thefollowing
Green formula has ameaning
for u:for all m
e {1,2,3},
all EE]O, 1[,
when we setLet us remark that the
boundary
termscorresponding
to r = 6 and r = 1 cancelsince
~(a)
= 0. Let us fix m E{ 1, 2, 3}
and 6e]0,1[. Taking
the real part of(4.2)
and since we assume that u fulfils(3.9),
we getNow, using
theeasily
checkedidentity
and
integrating by parts, (4.3)
becomesIt is obvious that
Moreover
using
the fact thatwe can prove the
following identity
For all k E
Fs,
let us setThen
using (4.5)
to(4.7)
into(4.4),
we arrive toLetting
m vary into{ 1, 2, 3}, (4.8)
isequivalent
toTherefore the
assumption imply
thatSince E is
arbitrary
in]o, 1 [,
wefinally
obtainAt this
step,
we follow Theorem 3 of[ 11 ] .
The functionfulfils
(owing
to(4.9)
and(3.10))
Since v has the form
with some
function V)
defined onusing
Theorem 4.3hereafter,
we deducethat
Therefore,
for alli, j
E{ 1, 2, 3 }
the function fulfils(4.10) (owing
to(4.9)
and
(3.9))
and admits theexpansion (4.11).
Soagain
Theorem 4.3implies
thatThis shows that the
displacement
field u is arigid body
motion. But this isincompatible
with(4.1 )
except if a = 0. In that last case, we deduce that there exists a vector a E such thatSince
Ds f 0,
we arrive toThis proves that exists for all a on the line = 0. But
using
thedefinition of
As(a),
we see thatTherefore,
exists also for all a on the line~(a) _ -1.
For all t E
[o,1 ],
let us set thefamily
of operators(defined
onQs analogously
to associated with thefollowing boundary
valueproblem:
Using
theprevious argument,
we can show that exists for all a on the lines = 0 and~(a) _ -1,
forany t
E[o,1 ]. Moreover,
Theorem 4.3 hereafter shows that exists for all a in thestrip
E[-1, 0] . Arguing
as at the end of theproof
of Theorem 1 of[ 11 ],
we conclude thatexists for all a in the same
strip.
0As we remark in the
proof
of Theorem4.2,
we need tostudy
thefamily
of
operators
withcomplex parameter
a associated with thefollowing
boundary
valueproblem,
when S is a fixed vertex of Q:It is defined
variationally
as follows: we setwhen Then
Bs(a)
is theoperator
frominto its dual defined
by
THEOREM 4.3. Let S be
a fixed
vertex then I existsfor
all a in thestrip
E[-1, 0];
whileif Ds
=0,
the same holds exceptfor
a = 0 and a = -1, where
ker Bs(a) = C.
PROOF. Let us denote
by
the sequence(in increasing order)
of theLaplace-Beltrami
operator(let
us recall that it is anonnegative selfadjoint operator
with acompact resolvant).
SinceBs (a)
=Bs(O) - a(a+ 1)1,
we see thatBs(a)
is one-to-one if andonly
ifThis proves the result since
Ao
> 0 if and A = 0 is ofmultiplicity
1 whenDs - ~.
0REMARK 4.4. Theorem 4.3 is
implicitly
proven inParagraph
5.1 of[8]
and itprecisely
proves the fact that no vertexsingularity
for theLaplace
operator appear in thestrip ~(a)
E[-1, o]
without anygeometrical assumption
onSZS.
So we
conjecture
that the conclusions of Theorem 4.2 still hold without thegeometrical assumptions
made in Theorem 4.2.With our
notations,
we haveLet us mention two
particular
situations where theassumption OS,DnCS,N
=0
is fulfilled:i)
ifrs
isnondegenerate
trihedral cone, then for every choice of~s
and,Ns,
thisassumption
is true.ii)
If card 1 or card 1, and ifrs
is convex, then itholds;
while if cardDs >
2 and 2, it may fail. DCollecting
theprevious results,
we arrive to theTHEOREM 4.5. Let u E V be a solution
of problem (1.4)
with dataf E
(L2(n))I,9(k)
E(Hl/2(rk»)3,
Vk E N.If
theassumptions (H3E)
and(H3V) hereafter
arefulfilled,
then(H3E) Vj,
k c 7 such thatri 0,
the interior dihedralangle
wjk betweenr j
andrk belongs
to]0,27r[
[ andif moreover j
and k E .N, then7r-
I For all vertex S
of
Q, eitherand 0.
has no crack
5. -
Setting
of thecoupled problem
Let us recall some notations introduced in
§ 1
of[19] (when
n =3):
We sometimes
identify
r and w with the open sets]0, l[x] - 1, 1 [
and]o, 2[ x ] - 1,1 [ of I1~2, respectively.
We notice that Q is the unit cube with a slitalong
thehalf-plane
~2 = 0, 0(see Figure 1).
Figure
1According
to the conventionof § 1,
the slit r of Q will besplitted
up into r+ and r_ , so we denoteby
u+u(respectively
the trace of a function uon r from above
(respectively
frombelow)
in Q. Theboundary
aSZ of Q willbe
decomposed
as follows:It is also convenient to
split
uprl
1 andr2
into theirplane
faces i.e.,v-...
We denote
by
-Yik, the trace operator on the facerik
in Q.Inspired
from[2],
we consider thefollowing boundary
valueproblem:
given
f E(L2(SZ))3 and g
EL 2(W),
find weak solutions u E(H1 (SZ))3
andç
EH2(w)
ofproblem (5.1 )-(5.7)
hereafter:where , and 0 elsewhere
In order to
give
the variational formulation of thisproblem,
we introducethe two Hilbert spaces:
this last one
being equipped
with the norm of(Hl(Q))3
xH2(w).
We define thecontinuous
sesquilinear
form on V as follows:for all where au is defined
in § 1
andLet us notice that this form
bw
is amultiple
of the form(2.13)
of[18], using
the classical convention of linear
elasticity.
LEMMA 5.1. For all
(f, g)
E H, there exists aunique
solution U E Vof
PROOF. Let us set
Using
Kom’sinequality
in Sz+ and Q- andadding
theresults,
we deduce theexistence of a constant a > 0 such that
Moreover,
theinequality (2.14)
of[18]
may be writtenfor some constant a2 > 0. The addition of
(5.10)
and(5.11)
shows that a isV-coercive,
i.e. there exists a > 0 such thatThe conclusion follows from the
Lax-Milgram
lemma. DIn order to show that
U,
solution of(5.9),
isactually
a solution of theboundary
valueproblem (5.1)-(5.7),
we need the extension of Theorems 1.5.3.10 and 1.5.3.11 of[6]
in dimension 3 for the Lamesystem
instead of theLaplace operator.
This is the purpose ofTHEOREM 5.2. a bounded open set
of R3,
with apolyhedral
N _
boundary
a8, 0lying
ononly
one sideof
itsboundary
and set a0 =U rj,
j=l where