A NNALES DE L ’I. H. P., SECTION B
C. M UELLER
E. P ERKINS
Extinction for two parabolic stochastic PDE’s on the lattice
Annales de l’I. H. P., section B, tome 36, n
o3 (2000), p. 301-338
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Extinction for two parabolic stochastic PDE’s
on
the lattice
C. MUELLER, E.
PERKINS
a Department of Mathematics, University of Rochester, Rochester, NY 14627, USA
b Department of Mathematics, University of British Columbia, Vancouver, BC V6T 1Z2, Canada
Received in 24 March 1999, revised 17 September 1999
© 2000 Editions scientifiques et médicales Elsevier SAS. All rights reserved
ABSTRACT. - It is well known
that, starting
with finite mass, the super- Brownian motion dies out in finite time. Thegoal
of this article is to show that with some additionalwork,
one can show finite time die-out for twotypes
ofsystems
of stochastic differentialequations
on the latticeZ~.
For our first
system,
let1/2 ~
y1,
and considernon-negative
solutions of
Here A is the discrete
Laplacian
and x EZd}
is asystem
ofindependent
Brownian motions. We assume that uo has finitesupport.
When y =
1 /2,
the measure whichputs
massu (t, x)
at x is a super- random walk and it is well-known that the process becomes extinct in finite time a.s. Finite-time extinction is known to be a.s. false if y = 1.For
1 /2
y1,
we show finite-time die-outby breaking
up the solution intopieces,
andshowing
that eachpiece
dies in finite time. Unlike the superprocess case, thesepieces
will not ingeneral
evolveindependently.
1 E-mail: [email protected]. Research supported in part by an NSA grant and
an NSERC Collaborative Grant.
2 E-mail : [email protected].
Research supported in part by an NSERCResearch Grant and an NSERC Collaborative Grant.
Our second
example
involves themutually catalytic branching system
of stochastic differentialequations
onZd,
which was first studied in Dawson and Perkins( 1998).
By using
a somewhat differentargument,
we showthat, depending
onthe initial
conditions,
finite time extinction of onetype
may occur withprobability 0,
or withprobability arbitrarily
close to 1. @ 2000Editions scientifiques
et medicales Elsevier SASKey words: Heat equation, White noise, Stochastic partial differential equations RESUME. - 11 est bien connu que le
super-mouvement
Brownien s’ eteint a un instant fini s’ il commence avec une masse totale finie. Dans cet article nous montrons que cettepropriete
reste encore valide pour deux autressystemes d’équations
differentiellesstochastiques
dansZ~.
Le
premier systeme
estou
1/2 ~
y1, u ) 0,
A est leLaplacien discret,
et{Bx:
x E estune famille de mouvements Browniens
independants.
Nous supposons que{x: 0~
est fini. Si y =1/2
la mesurequi
donne la masseu (t, x)
aupoint
x est unesuper-marche
aleatoire et il est bien connuque le processus s’ eteindra a un
temps
fini. Cettepropriete
est fausse siy = 1. Si
1 / 2
y1, nous
montrons l’ extinction à untemps
fini à I’ aide d’unedecomposition
de la solution en solutions d’equations
auxiliaires.A la difference du cas des superprocessus, ces solutions n’évoluent pas
independamment.
Le deuxieme
exemple
est unsysteme d’ équations
differentielles sto-chastiques
enZd
associe a un mecanisme de branchement mutuellementcatalytique :
Ce
systeme
a ete etudie par Dawson and Perkins( 1998).
Nous demon- trons que selon les conditionsinitiales,
l’un des deuxtypes
s’éteint entemps
fini avecprobabilite zero,
ou inversement avecprobabilite
arbitrai-rement
proche
de 1. @ 2000Editions scientifiques
et médicales Elsevier SAS1. INTRODUCTION
Recently,
the Dawson-Watanabe process, orsuper-Brownian motion,
has attracted
great interest,
and manyfascinating properties
have cometo
light.
See Dawson[ 1 ]
for a survey. These results oftenrely
onthe
multiplicative property
of the process. This allows one tostudy
the process as an infinite
system
ofnoninteracting particles,
each withinfinitesimal mass.
However,
it is often much more difficult to prove similar results forsystems
with interactions.In this
article,
we concentrate on the finite time extinctionproperty.
Let
Zt
be the total mass of the Dawson-Watanabe process, and assume that the initial massZo
oo. As is wellknown, Zt
satisfies the Fellerequation
and with
probability 1, Zt
reaches 0 in finite time. See Theorem 4.3.6 of[6]
for the exact extinctionprobabilities.
Ourgoal
is tostudy
finitetime extinction for 2
types
ofsystems
of stochastic differentialequations (SDE),
related tosuper-random walks,
on the latticeZ~.
First,
we considernon-negative
solutionsu (t, x), t > 0,
x EZd
to thefollowing system
of stochastic differentialequations
on the latticeZd,
for1/2 ~/1.
Here and
throughout
the paper, A is the discreteLaplacian
onZ~.
Inother
words, if N (x)
is the set of 2d nearestneighbors
of x eZd,
and iff (x )
is a function onZd,
then(A/)(~)
=Also,
is a collection of
independent
motions onsome filtered
probability
space(03A9, 0, 0t , P) satisfying
the usualright- continuity
andcompletion hypotheses,
as will all our filteredprobability
spaces in this work. We assume that
uo (x) equals
0except
at a finite number ofpoints, F,
inZd.
Pathwise existence anduniqueness
holds forsolutions of
(1.2) by
the well-known method of Yamada and Watanabe which we recall below(Lemma 2.1 ).
If y =
1,
solutions to(1.2)
can berepresented
in terms of theFeynman-Kac
formula.Let ~ (t)
be a continuous time random walk onZd
with infinitesimal
generator A
andsemigroup Pt ,
which isindependent
of the Brownian motions
Bx.
IfEx
denotes theexpectation
withrespect to ~ ,
= x, then we haveSince
exp[.]
isalways strictly positive,
and since for each t > 0 there isa
positive probability that ~ (t)
lies in thesupport
of uo, it follows thatu (t, x)
> 0 for all t >0,
x EZd.
Gartner and Molchanov[5]
have foundmany
fascinating properties
of solutions for the case y = 1. We also mention inpassing
that a class of processes called "linearsystems"
hasbeen studied in the
particle systems
literature. Suchsystems
areformally
similar to solutions of
(1.2)
with y =1,
andLiggett, [8] gives
sometheorems about the
asymptotic
die-out of mass as t - oo.Next,
for y =1 /2,
the measureu (t, x) (where ~
is thecounting measure),
is thesuper-Brownian
motion withunderlying spatial
motion~ (t) .
Its total mass satisfies( 1.1 )
andtherefore, u (t, x)
= 0 for all x andlarge enough
t.In
light
of the above two results it is natural to consider thequestion
of finite time extinction for
1 /2
y 1. In this case one can view solutions to(1.2)
as interactivesuper-random
walks in which there isa
density dependent branching
rate ofu(t, x)Y-1~2
at(t, x). Clearly,
forsome Brownian motion
B (t),
the total massZ (t)
satisfiesSuppose
that H(t) ) cZY (t),
whereH (t)
isnonanticipating.
It is known that withprobability 1,
solutions to d Z = H d B die out in finite time.See,
for
example,
Lemma 3.4 of[9]. Unfortunately,
if u(t, x )
is verythinly spread, u2Y (t, x)]1~2
may be much smaller than ZY(t). Thus,
the coefficient ofdB(t)
which appears in( 1.3)
may be much smaller than ZY(t).
This is the maindifficulty
inproving
Theorem 1.THEOREM 1. -
Suppose
that1 /2
y1, d > 1,
thatu(t, x) satisfies ( 1.2),
and thatuo (x)
isequal
to 0 except ona finite
set F.Then,
with
probability 1,
u(t, x)
dies out infinite
time. Thatis,
there exists analmost
surely finite
random time t = t(w)
such thatu (t, x)
= 0for
allt 03C4 and x ~ Zd.
The
strategy
of ourproof
is to show that u(t, x)
is notthinly spread,
and therefore
Z (t)
satisfies anequation
like dZ = Hd B,
wherefor some random number c. It is known that solutions to such
equations
die out in finite time.
Actually, u (t, x)
shows ahigh degree
ofclumping
as x varies.
Here,
we wereguided by
known results for superprocesses.Without the
clumping,
we would not be able to show aninequality
suchas
(1.4).
Finite-time extinction is often useful for
establishing
thecompact support property
of solution to continuousparameter parabolic
stochasticPDE’s. The
compact support property
states that if the initial data hascompact support
in R then the same is true of the solution at anypositive
time.Often,
thecompact support property
of solutions isproved by showing
that finite-time die-out occurs for theparts
of the solutioncorresponding
tolarge
values of x. Forexample,
this is done in[9]
and
[3].
Infact,
Theorem 3.10 of[9]
proves the continuousanalogue
of Theorem 1 but we were unable to extend that
approach
to our latticesystems.
At a crucialstep
in theproof
in[9],
we used Jensen’sinequality.
To prove Theorem 1 we
again
use Jensen’sinequality,
but we also need toknow that the mass of
u (t, x)
tends to cluster at a small number of sites.Next,
we introduce asystem
of SDE’s introduced in[4].
LetMF(Zd)
be the space of finite measures on
Zd
with thetopology
of weakconvergence. Consider
Here,
i-1,2 is a collection ofindependent Ft-Brownian
motions
(~
are asabove)
and A is the discreteLaplacian
onZ~ .
Such a
pair
of processes arise as thelarge population
limit of twointeracting branching populations
in which thebranching
rate of eachtype
at x EZd
isproportional
to the amount of the othertype
at x. As eachtype "catalyzes"
thereproduction
of the othertype,
it is called themutually catalytic branching
process. One reason for interest in thissystem
is that it was anextremely simple example
of interactivebranching
for whichuniqueness
in law was not known.[10]
and[4]
proved
weak existence anduniqueness
of solutions to( 1.5) by
means of aself-duality argument proposed by Mytnik. Uniqueness
in law forgeneral systems involving
interactivebranching
rates remains unresolved even forquite
smooth rates. Theoriginal
reason for interest in( 1.5)
was thequalitative
behaviour of its continuumanalogues
in 2 or more dimensions(the
one dimensional case is treated in[4]).
Thesingularity
of super- Brownian motion(for d > 2)
and the fact that eachtype
solves the heatequation
in the absence of theother, suggests
that the twotypes separate
and have densities away from their "interface". In[2]
thisdescription
ismade
precise,
atleast
for d = 2.The
components U. ,
V are continuousMF(Zd)-valued
processes a. s.,so let
PU0, V0
denote the law of the solution onC ([0, (0), MF(Zd)2).
Weset
(!7, ~) =
forbounded ~
and UE MF (Zd ) .
Thelong
time behavior of solutions to
(1.5)
was studied in[4].
It is easy to see that((U~ , 1), ( Vt , 1))
is a conformalmartingale
in the firstquadrant
andhence converges a.s. as t ~ oo to
({!7oo, 1), (V 00’ 1)),
say.[4]
showedthat in the recurrent case
(d 2), (Voo, 1)(Voo, 1 ) =
0 a.s., while in the transient case(d ) 3), 1)(Voo, 1) > 0)
> 0. Theself-duality
then allowed one to use these results to
study
thelong
time behaviour from infinite initial conditions. For finite initial conditions the above results lead one to ask:( 1 )
Is there finite-time extinction of onetype
ifd
2?(2)
Howlarge
is1 )
>0)
ford )
3?The next two results show
that, depending
on the initial conditions andindependent
of thedimension,
finite time extinction can occur withprobability
zero orprobability
very close to one. Inparticular,
this showsthat in the transient case,
1) > 0)
may bearbitrarily small, depending
on(Vo, Vo).
Our first theorem about this
system
establishes conditions under which finite time die-out does not occur. As usual_ ~ y x ) ,
where
pt (x , y)
=P(03BEt = x|03BE0 = y). If x = (x1,.., Xd) E Zd, then Ixl
==d
!r!THEOREM 2. - Assume that
for
tlarge enough (say
t >to),
Then
1)~Vt, 1)
> 0 Vt >0)
= 1.In
Proposition
4.1 wegive
alarge
class of initial conditions whichsatisfy (1.6).
Our second result about this case says that under certain
conditions,
finite time extinction can occur, at least for one of the
species.
THEOREM 3. - Assume
À1 ~ À2
>0, Ào
>4À1 - 3À2,
andfor
someFor any £ > 0 and tl >
0 31]
> 0 such thatif
1] thenNote the above conditions are satisfied in
particular
ifÀo
>Â1
=~2.
We will see that to achieve smaller values of ~, we must take smaller values of ~. Both of the above results will be stated and
proved
for moregeneral generators
than A in Section 4.If
( U, V)
solves(1.5),
then so does(c U, cV) (with
a modified initialcondition).
We can take c = in the above result to see that ifÀi
areas
above, M > 1,
and then for any > 0 there is a cisufficiently large
so that the conclusion of Theorem 3 holds wheneverHere is the
plan
of our article. We will first deal with(1.2).
Section 2contains some
lemmas, including uniqueness
for(1.2).
In Section 3 weprove Theorem 1. In Section 4 we turn to
( 1.5)
and prove moregeneral
versions of Theorems 2 and 3.
2. SOME LEMMAS
In this
section,
we prove somepreliminary
facts and lemmas. Our first lemmagives uniqueness
for(1.2).
This result follows from themethod of Yamada and Watanabe
(see
Theorem V.40.1 ofRogers
andWilliams
[ 11 ]).
Almost the sameproof
isgiven below,
but we include itfor
completeness.
LEMMA 2.1. -
Suppose
thatuo(x)
oo. Thenpathwise uniqueness
holdsfor ( 1.2).
Proof - Suppose
thatu (t, x), v (t, x)
are 2 solutions of( 1.2).
An easyapplication
of Fatou’s lemma shows thatand in fact with a bit more work one can show
equality
holds in the above.Note
sincey>
Therefore, proceeding
as in[1 1],
SectionV.40,
we find that for eachNote that
by
the definition ofA,
Taking expectations
andsumming
over x EZd
in(2.2),
andusing (2.3),
we find that
Thus, (2.1 )
and Gronwall’s lemmaimply
thatand Lemma 2.1 follows. 0
Standard
arguments
show weak existence of solutions to( 1.2) (e.g.,
asin Section 2 of
[4]),
andjust
as for finite-dimensional SDE(see
V. 17. I of[ 11 ] ),
this and the above resultimply pathwise
existence for solutions of( 1.2)
and theuniqueness
of its law onC([0, oo), MF(Zd)).
Let Y be a Poisson random variable with
parameter À,
and suppose that H is anon-negative integer. Then, by Stirling’s formula,
The next lemma follows from an easy
application
of Itô’s lemma. SeeChapter
5 of[ 12]
for the result in the more delicate continuumsetting.
LEMMA 2.2. -
( 1 .2)
isequivalent
to thefollowing
systemof integral equations.
where
G(t, x)
is thefundamental
solutionof
the discrete heatequation
on
Zd .
A standard consequence of
pathwise uniqueness
isLEMMA 2.3. -
(1.2)
has the strong Markov property with respect to thea -fields 01 .
If x E
Zd,
let xi denote the i thcomponent
of the vector x. Fix an in-teger
N >0,
and letDN
={x
EZd : I xi ~
N for all i =1,..., d ~ .
Notethat
DN
has at most(3N)d
sites. LetaDN
be theboundary
ofDN.
In otherwords,
letaDN
be the set ofpoints
in which are nearestneighbors
of somepoint
inDN.
Recall that x, y EZd
are nearestneigh-
bors if the Euclidean distance between then is 1. For future use, we denote
DN
=DN
UaD N.
We reserve the notationu (t, x)
for theunique
solutionof
( 1.2).
LEMMA 2.4. - Let
vo(x)
be anon-negative function supported
onDN. Suppose
thatfor
t > 0 and x EZd, vet, x) satisfies
with
uo (x).
For x EZdBDN,
letv (t, x)
= 0.Then,
withprobabil- ity 1, for all (t, x)
E[0, oo)
xZd
we have~(~, jc) ~ u (t, x).
Proof -
The lemma follows from standardcomparison arguments.
See,
forexample, [7].
DAs in Lemma
2.2,
the solution v to(2.6)
willsatisfy
where
GN (t, x)
is the fundamental solution of the discrete heatequation
on
Zd
with 0boundary
conditions onBDN.
We will at times use the
following
consequence of Jensen’sinequality.
Let M >
0,
suppose that p >1,
and that ai , ... , aM arenon-negative
realnumbers.
Then,
For the
following lemma,
let #S denote thecardinality
of the set S.LEMMA 2.5. -
Suppose
thatv (t, x) satisfies (2.6),
and letLet
~-DN
be thepoints
inDN
which are nearestneighbors
to Thenthere exists a Brownian motion
B(t)
and apredictable functional H (t)
such that
Vet) satisfies
thefollowing
stochasticdifferential equation:
Proof - Summing
over x EDN, combining
the Brownian motions andusing (2.8) with p
=2y,
weget
the lemma. 0The
following
lemma is aspecial
case of Lemma 3.4 of[9].
Let t be the
first
time t thatZ(t)
=0,
and let t = 00if Z(t)
neverreaches 0. There is a constant
C(y) depending only
on y such thatLemma 2.6 has the
following simple corollary.
LEMMA 2.7. - Let
Xt,
tT,
be a continuousnon-negative
super-martingal e
withmartingale
partfor
some Brownian motionBt
andfor
somepredictable
processHt. If L >
1 and A >0,
thenProof - Let
=du ,
whereand define
r(s)
=inf{t:
>s},
if sa(Tx);
andt (s)
=Tx,
if s > a(Tx).
ThenZt
=XT(t)
is aright
continuousnon-negative
supermartingale
with continuousmartingale part given by AZS d BS
for some Brownian motion
B .
Z mayonly
havenegative jumps. Let Yt
be the
unique
solution ofA well-known
comparison
theorem(Theorem
V.43.1 of[ 11 ]
iseasily
modified to cover this
case)
shows that for allt )
0 a.s. and soit follows
easily
thatX t C Ya(t)
for allt >
0 a.s.Clearly
and T
Tx imply a(T)) T /L . Recalling
that both X and Y will stickat 0 after
they
first hit0,
we see thatand Lemma 2.6
completes
theproof.
DLEMMA 2.8. -
Suppose
thatf
and g arenon-negative functions
onZd
such thatThen
Proof - By
Holder’sinequality,
Our final result shows that we can
split
up solutions at t = 0 in anappropriate
manner. First we observe that since2 y
>1,
ifa, b
> 0then
LEMMA 2.9. - Fix n >
0,
and let uo :Zd
-+[0, oo).
For each1
~
i~
n, letSi
bea finite
subsetof Zd,
and letWi,O(.)
be anon-negative function supported
onSi .
Assume thatThen on some
filtered probability
space,(D, P),
we maydefine
in-dependent Ft-Brownian
motions} Bi,x :
1 i n, x EZd}, independent Ft-Brownian
motionsf Bx :
x EZd} (the
2 collections will not be mu-tually independent),
andnon-negative (Ft)-predictable continuous func-
tions
u ( . , x)
andwz (~, x), Hi ( . , x) (i ~
n, x E such that thefollowing
holds.
First,
the wi(t, x) satisfy
and
u (t, x ) satisfies ( 1.2). Secondly,
Finally,
withprobability 1, for
all t~ 0,
x EZd,
we haveProof -
Wegive
a brief outline of theproof, leaving
the details to thereader. Observe that if the continuous function
hi :
RnR+
is definedby
then
and
Let be a sequence of
Lipschitz
functions onRn,
which convergeto
hi uniformly.
Morespecifically,
we define a function§m : R+ --~
R asfollows. Let agree with wY on
[1/~, oo )
and at0,
and defineby
linearinterpolation
on(0, 11m).
Define ashi
i but withWk)
in the numerator. It follows thatconverges to
(~=1 uniformly
oncompacts.
Let be theunique
solution ofLet
x)
be theunique
solution ofwhere
wi,o(x)
are chosen such thatThen,
standardcomparison
theorems show that withprobability 1,
Furthermore,
we can take asubsequence
mk such thatconverges in distribution to
(Wi(t, x), Zi(t, x)),
where(wi )
satisfy (2.10)
withHi (t, x)
=hi (wl (t, x),..., wn (t, x))
and2:7=1 1 zi (t, x)
satisfies
( 1.2). Clearly
withprobability 1,
This
implies
Lemma 2.9. D3. PROOF OF THEOREM 1
Our
proof depends heavily
on thedecomposition
in Lemma 2.9. Weemphasize
that thisdecomposition
is a weak existencetheorem,
so we arealways dealing
with achanging
set of Brownian motions and solutions.First,
we set up some notation which we will use in theproof.
Fix8 > 0. Let lC be the event that for some T >
0, u ( T , x )
= 0 for all x EZ~.
For
T ) 0,
let/C(F)
be the event thatu ( T , x )
= 0 for all x EZd.
Notethat as T
t
oo, the events/C(T)
increase to /C. Infact,
we show that there exists a time too such thatThen
(3 .1 ) implies
Theorem 1. From now on, we fix £ > 0 and concentrate onproving (3.1 ).
Let E N be so
large
thatand then choose 0 8 small
enough
so thatWe will
specify
aninteger
no > 0 later. LetWe define 0
= tno
...inductively
as follows. Let m be the smallestinteger m
such thatand let
If n > n o and if we are
given
tn, we letClearly,
there exists a finite accumulationpoint
Fix K > 0 and let
Ao
=Ao(K)
be the event thatLet
jii
= Note that theintegrability
in(2.1 ) easily gives
that
jii
is a continuousnon-negative martingale.
Let i =i (T, K)
be thefirst time
t #
T thatt
K. If there is no suchtime,
let i = T.Using
the
optional sampling
theorem and Markov’sinequality,
weget
For n ) no, tn # t #
tn+1, x EZd,
we willinductively
define asequence of random functions
u (t, x)
as follows. Since the definition ofvn (t, x)
for n > no is thesimplest,
we start with that case.Suppose
that we have definedvn_ 1 (t, x) u (t, x)
fortn_ 1 t
tn. LetFor tn t
tn+1, letvn (t, x) satisfy Eq. (2.6) (of
Lemma2.4),
withN =
Nn,
so thatvn (t, jc) ~ u (t, x) by
Lemma 2.4.Now we
give
the morecomplicated
definition ofvno (t, x) .
For 1~
we call the time intervals
[ (m - 1)(~), m(l)) stages,
and we call the subintervals[k, k
+1)
c[(m - 1) (.~), m (.~)) substages.
In order todefine vno
(t, x),
we first define a collection of functions wk,z(t, x)
for~ ~ ~ (k
+1)~, 0 k iii,
z Esatisfying
We let x +
Dk
denote the set{x
+ y : y EDk } .
LetAssume that either k = 0 or that Wk-1,z has
already
been defined forz E
DNno
and satisfies(3.6).
Letand let
Therefore
(3.6)
holds for t = In either case,using
Lemma 2.9 withSz
= z +z E DNno ,
we let wk,z(t, x) satisfy
thefollowing equation
for t
~ (k
+where
Hz(t, x)
is as in Lemma2.9,
and areindependent
Brownian motions. Lemma 2.9 now
implies (3.6)
and our inductiveconstruction is
complete.
Finally,
for0 C t
we definevno (t, x)
as follows. LetD§§ no
bethe set of those
points zED Nno
such thatThe reason for
defining D0Nn0
is that we do not want to include anypoints
z for which has any
support
outside ofDNno.
Ifx
letvno(t, x)
= 0. If x ED0Nn0
and t ml = choose0 k
suchthat
~ ~ ~ (k ~ l)l
and letExtend vn, wk,z to be
identically
0 outside their initial domains of definition and letFt
be theright-continuous
filtrationgenerated by
theprocesses vn, wk,z, u, and
Bz,x
up to time t asn , k, z, x
rangethrough
their
respective
domains. Now we label the mass that has "leaked out".For
n )
no, letWe will often work with the
following
sets.DEFINITION 3.1. - For
n )
no let be the event thatand let
A2,n
be the event thatDefine
to be the entire spacefor
i = 1 or 2.Our definitions
imply
thatThe
following
lemmaplays
an essential role in theproof
of Theorem 1.LEMMA 3.1. -
If no
islarge enough
andn >
no, thenand in
particular, for
nolarge enough,
Proof -
Tobegin
theproof
of Lemma3.1,
we consider the case n > no.The
key
to theproof
is the observation that on the set we havevn(tn, .)
=u (tn , .) .
This follows from the definitionsof vn
and the event~4i~-i. Let $f
be ouroriginal
continuous time randomwalk,
started from x, and letT:
be the first time t that~t ~ DNn .
Theintegral equations (2.5)
and
(2.7) imply
that on ENow use
(2.5) again
to see thatDenote
Let St
be the number ofsteps that
has taken Of course, sincethe
steps
are of size1,
we have thatRecall the definition of
Mn . Also,
from the definition oftno
and tn, we seethat for
Using (2.4),
we conclude thatif n is
large enough,
and thus if no islarge enough. Using
Markov’sinequality,
we haveThis proves Lemma 3.1 for n > no because 8 1.
Next,
we turn to the case n = no. Note thatMno
consists of 2 kinds ofmass. Let
Mno
refer to the first kind of mass, which escapes from each of the small cubes x +DN- .
LetMno
refer to the second kind of mass, which escapes from thelarge
cubeDNno
or becomespart
of the functionswk,z (t, x),
for those z E To beprecise,
letand let
Clearly M~o
=Mno
~--Mno .
First we deal with Let i
be ,
the first time t l that03BEt ~ DNn0
where
~o
= 0. If there is no suchtime,
let t = .~ .Using
theanalogue
of(2.7)
for the wk,Z, as in(3.8),
weget
In the last line we have used
(3.6)
and the fact that at timesk£,
the redistribution of the mass among thewk,z’s
preserves the total mass ofTherefore
The last term is at most
K P(f f).
Now iterate the above mtimes, noting
that~x u (0, jc) = ~ ~ wo,Z (o, x),
and argue as in(3.9) using (2.4)
toget (for
nolarge again)
if no is
large enough. Again using
Markov’sinequality,
we haveNow we consider On the last interval
[(m 2014 1)~,
is a
supermartingale
and soUse
(3.6)
to bound the aboveby (no large enough)
# K
sup P(~x
exitsDNn
before time(m - 1)~)
~~F 0
Another
application
of(2.4) (as
in(3.9))
shows that for nolarge enough
the above is at most
8-2n~ ,
andtherefore, by
Markov’sinequality,
Putting together (3.10)
and(3.11 ),
we obtainThis proves Lemma 3.1. D
Our next
goal
is to estimate theprobability
of LetLEMMA 3.2. -
Ifno
>n (~, E), then for
n > no,Proof -
Ourargument
uses Lemma 2.7. We need to boundBy
Lemma2.5,
on the event,,42, n _ 1,
we can writewhere
Then, by
Lemma2.7,
we haveThis proves Lemma
3.2,
if no islarge enough.
0Next,
we treat the morecomplicated
case of n = no.LEMMA 3.3. -
Ifno ) n (E, K),
thenTo prove this we will deal with the
stages (of length l)
and thesubstages (of length 1 )
which we defined earlier. We first show that for at least half of thestages,
at the end of the l - 1substages,
there areonly
asmall number of sites Z E
DNno
such that Wk ’ Z is still alive.(Recall
that wesay a function is alive if it is not
identically 0.)
To state thiskey
lemmaprecisely,
for0 k iii,
we letand for as
above,
setThen we have the
following.
LEMMA 3.4. -
If no )
y,6~)
thenAssume for the moment that Lemma 3.4 holds and let us
give
theProof of
Lemma 3.3. - Notethat,
as in Lemma2.5, Wk,z
is a non-negative supermartingale
withmartingale part Hk,z d B,
whereLemma 2.5 also shows that
Vno(t)
=Wk,z(t) (for
t(k
+1)~)
is a continuoussupermartingale
withmartingale part Ht d Bt ,
where
by (3.12)
and Jensen’sinequality,
fork.~ t (k
+1 )£
Therefore on
,r43, k (.~ -1 )
and for t E[k£ + ~ - 1, (k +1)~],
we have(note
that
c)
.
~B-x -*’~(JB’~’ .
Thus we may
apply
Lemma 2.7along
with our choices of l and 03B4(recall
(3.2)
and(3.3))
to conclude thatfor
no # nee, K).
Thistogether
with Lemma 3.4completes
theproof
ofLemma 3.3. D We now turn to the
Proof of
Lemma 3.4. - Fix0 ~
k hi. For0 j
.~ let =By (3.12)
we may use Lemma 2.7 to seethat
for 1j ~
Now note that on
-1, K ) ,
we haveEz + j - 1) ~
K(by (3.6)).
Weapply
Lemma 2.8 withto see that on
A3, k ( j - 1 ) ,
Markov’s
inequality implies
for 1j ~,
the last
by (3.3).
Since there are at most3d2nod
sites z inDNno ,
P(A3,k(0))
= 1 and so from the above wehave,
°
if no > ~, y). Allowing k
to vary, letand
Mn = ~k-1 dk -
n ~c.Clearly (Mn,
is amartingale
and so ifno > K ,
y,E),
The
probability
we have to bound is nobigger
than that on the left-handside of the above
equation
and so theproof
iscomplete.
0Now we can
complete
theProof of
Theorem 1. - Recall thatUsing (3.4),
choose K solarge
thatand then no
large enough
so that all of the above bounds are valid. Takecomplements
in the above inclusion and consider the first value of n sothat w E or
A2,n
to see that(recall 1 is
the entirespace)
Therefore Lemmas
3 .1, 3 . 2
and 3.3 and our choice of Kimply
This proves
(3.1 ),
and finishes theproof
of the theorem. D4. PROOF OF THEOREMS 2 AND 3
We first introduce a
setting
formutually catalytic branching
models.Let Q
=(qxy)
be theQ-matrix
for a continuous timeZd-valued
Markovchain 03BE1
withsemigroup Pt
and transition functionsIf Ixl = I(X1, ..., ]
=] (x
EZd),
we assume thefollowing hypotheses
introduced in[4] :
(HI) ~q~~ = supx|qxx| 00.
(H2)
For each x, y EZd,
qxy = qyx and soy)
=x).
(H3)
There areincreasing positive
functionsc ( T , À)
andÀ’(À)
suchthat
These conditions are satisfied
by
a continuous timesymmetric
randomwalk with
subexponential
tail(Lemma
2.1 of[4] )
and inparticular by
thenearest
neighbor
random walk considered in the introduction for whichqxy =
1(lx - y
=1) - 2dl(x
=y).
Ourgeneralized mutually catalytic system
is thenHere,
is a collection ofindependent Ft-Brownian
mo-tions on some filtered
probability
space. The weak existence andunique-
ness of solutions in
C([0, oo) , MF(Zd)2)
described in the introduction forQ
= A continues to hold and we letPUo,
vo continue to denote theunique
law of the solution on this space of
paths.
Theorem 2 continues to hold without
change
in this moregeneral setting
as we now show.Proof of
Theorem 2. -By
Theorem2.2(b)(ii)
of[4] Vt (x)
has meanUo Pt (x )
and varianceBy Chebychev’s inequality
By ( 1.6)
if ~ > 0 and t > to, we may choose xo so thatand so
Since (Ut, 1)
is anon-negative martingale
this shows thatThe result follows
by symmetry.
DIt is easy to choose initial conditions
satisfying (1.6)
forsimple symmetric
random walk inZd.
PROPOSITION 4.1. - Assume
Q
= ð so that{~t}
issimple symmetric
random walk on
Zd
withjump
rate 2d.Suppose
there are m > n in Zsuch that
Then
( 1.6)
holds and henceWe need an
elementary
estimate forsimple
random walk.LEMMA 4.1. - Let
{~t}
besimple symmetric
random walk on Thenwhere we recall
that Ix I = ~d ~ xi I .
Proof. - Suppose
d = 1 and~t jumps
with rate À > 0. Then forx ) 0,
(ç
has n + xsteps
to theright
up to timet)
Clearly
Put this into
(4.3)
and usesymmetry
in x toget
Since =
x)
=1 pt l~ (x~ ),
the result follows. DProof of Proposition
4.1. - Choose v EZd
withv 1 >
m such thatVo(v)
> 0. Then(4.2)
shows that for t >2, x
= v2 , ... ,vd)
andXi > VI,
where =
03A3y2...yd U0(y1,
y2, ...,yd)
is the firstmarginal
ofUo.
Setting k
= m - Y1, we see that.This,
and asymmetrical argument
for thereciprocal,
establish( 1.6)
andwe are done. 0
Next,
we turn to the main task of thissection, proving
Theorem 3 inour more
general
Markov chainsetting.
In this case we need to add apair
of
hypotheses.
THEOREM 4. - Assume
and
Under the
hypotheses
onVo
in Theorem3,
the conclusionof
that result holds.Remark. - The
hypotheses
added above hold for any continuous time random walk withsubexponential jump distributions,
as(4.6)
is trivial and(4.5)
isproved
in Lemma 2.1 of[4].
Notation. -
~~, (x)
= for x EZd .
LEMMA 4.2. - Assume the
hypotheses of
Theorem 4. Then VÀ >0,
£ >
0,
T > 0 there is a > 0 such thatProof -
For the lowerbound,
observe thatfor all
t
Tby (4.6).
For the upper
bound,
note that(H2) implies
and so for
t
TThis finishes the
proof
of Lemma 4.2. DProof of
Theorem 4. - Thehypotheses
on{~,l }
allow us to choose,B
such that
and then a such that