R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
J OSEPH B ARBACK Regressive upper bounds
Rendiconti del Seminario Matematico della Università di Padova, tome 39 (1967), p. 248-272
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JOSEPH BARBACK
*)
1. Introduction.
The results
presented
in this paper were obtained when thefollowing problem
was considered : When does a denumerable col- lection of isols have aregressive
upper bouiad? It was provenby
J. C. E. Dekker and J.
Myhill [6,
Theorem 45(b)]
that a denume-rable collection of isols
always
has an upper bound in the isols.However,
it is easy to show that even finite collections of isols may have noregressive
upper bound. There are two main aims of this paper. The first is togive
a necessary and sufficient condition that a finite collection of isols have aregressive
upper bound and the second is to discuss the existence ofregressi ve
upper bounds for threeparticular types
of infinite collections of isols1 ).
2.
Preliminaries.
We shall assume that the reader is familiar with the termi-
nology
and main results of thepapers [1] ] through [6]
and[9];
inparticular
with theconcepts
ofregressive function, regressive set, regressive isol,
infinite series of isols and theordering
relations*) Indirizzo dell’A. : State University of New York Buffalo, New York-U.S.A.
1) I wish to express my thanks to F. Sansone for some rewarding conver-
sa,tions concerning some of the topics presented here. Research on this paper
was supported by a New York State Summer Research Fellowship.
* (between
functions andisols)
and(between isols).
When re-fering
to an upper bound we shallalways
mean an upper bound which is an isol. Theexpression
«regressive
upper bound » will sometimes be abbreviatedby writing
r.u.b. I)enumerable will meaneither finite or
denumerably infinite,
and c will denote the cardi-nality
of the continuum. We letE = the collection of all
non-negative integers
ll = the collection of all
isols,
llx
= the collection of allregressive
isols.It is known that L e where both E and ~1. -
AR
have
cardinality
c. Since every isol hasonly denumerably
manypredecessors
it follows that if a collection of isols has an upperbound,
then the collection is denumerable. It is for this reasonthat the
problem concerning
the existence of an upper bound is restricted to collections of isols which are denumerable.3. Fundamentat
properties.
Throughout
this section let 4 denote a denumerable collection of isols. We recall that an isol U will be an upper bound of L1 ifA c U,
for each AE Al i.e.,
if 4 is a subset of the collection ofpredecessors
of the isol U-~-
1. Thefollowing
twoproperties
ofisols and the relation ~ were proven
by
Dekker in[4].
LetA,
Band U be
isols,
thenIt is
readily
seen thatcombining (1)
and(2), yields
PROPOSITION 1. If L1 has a
r.u.b.,
thenIt was also proven in
[4]
that11~
is not closed under addition.If we let
A, B E AR ,
y such that A+ B ~ AR then,
in view of Pro-position 1,
we see that the collection(A~ B)
as well as any collec- tion 4 withA,
B E 4 will have noregressive
upper bound.We have earlier noted that every isol has
denumerably
manypredecessors. Further,
it is well known that every isol has c suc- cessors in the isols. If an isol has aregressive
successorthen, by ( 1 ),
the isol itself will also beregressive. Every
finite isol willhave c
regressive
successors, since there are c infiniteregressive
isols. On the other
hand,
(3)
every infiniteregressive
isol hasexactly No regressive
succes-sors.
To
verify (3),
first note that if A is aregressive
isol then eachof the isols A
+ 1,
A+ 2, ...
is aregressive
successor ofA ;
henceevery
regressive
isol has at leastNo regressive
successors.Also,
itwas proven
by
T. G.McLaughlin [7,
Lemma1]
that every infinite set has at most~o regressive supersets.
Since every non-zero isol containsNo sets,
it follows from this result that every infinite isol has at mostNo regressive
successors. This proves(3).
Withrespect
to
regressive
upperbounds,
it follows from(3),
that if 4 has ar.u.b. and also contains at least one infinite isol then J will have
exactly No regressive
upper bounds.We will now state another result that is related to
regressive
upper
bounds,
theproof
of which may be obtainedby
a construc-tion similar to that in the
proof
of[2,
Theorem1.3].
PROPOSITION 2. There exist infinite
regressive
isolsA, U
andV such that
:I(:
and U and V are not V related.
The V relation was introduced in
2 ;
it is abinary
relation defined betweenpairs
of infiniteregressive
isols and it is weaker then each of the relations e’* andC,
in the sense that elementssatisfying
either of the latter
already satisfy
the former relation.Assume that 4 has a
r.u.b.,
and let be the collection of allregressive
upper bounds of 4. Consider the two statements-(4)
I’ is closed under addition.(5)
h istotally
orderedby
the relation * or .If A c .E then both
(4)
and(5)
arefalse,
for in this caseAR - E
c r.In
addition,
if we let d =(A),
where A satisfies thehypothesis
ofProposition 2,
then it also follows that both(4)
and(5)
arefalse,
even
though
in this event I’ is denumerable. We do not know if it isalways
the case that both statements(4)
and(5)
are false.4. Finite collections.
Assume also in this section that J is a denumerable collection of isols. We know that if J has a r.u.b. then
In §
6 it will be shown that every denumerable collection d of isolssatisfying ([-])
either will have no r.u.b. or else can be extended toa denumerable collection of isols which satisfies
(0)
andhaving
no r.u.b..
However,
in thespecial
case that L1 is a finite collection ofisols,
then(0)
is a sufficient as well as a necessary condition for L1 to have ar.u.b. ;
and this is the main result of this section. Webegin
with thefollowing proposition.
PROPOSITION 3. Let
A,
B and C beregressive
isols such thatThen
PROOF. The result is immediate if either
A,
B or C is finite.Assume now that each of the isols
A, B,
and C is infinite.Then there will be
mutually separated (immune
andregressive)
setsand ð
belonging
toA, B
and Crespectively.
In view of thehypothesis,
each of the three setswill also be
regressive.
LetThen ~c is an immune
set,
because each of the sets and 6 is immune. Also n E A-~-
B-f- C,
and therefore tocomplete
theproof
it suffices to show that 17- is a
regressive
set. This will be ourgoal
as we divide the remainder of the
proof
into threeparts.
Part 1. Let an, cn, un, vn and wn be
(everywhere
defined and one-to-one) regressive
functionsranging
over the sets a,fl, 67 a + fl,
x-)- 3 and fl -~- 8 respectively,
and let S denote thefamily consisting
ofthese six functions. For each of the numbers a*E a, b* and c~‘E
5y
letSuppose
that a numbery E 7l
isgiven. Then y belongs
toexactly
one of the sets ond 6. Because the sets a,
fl
and 3 aremutually separated,
we can determine theparticular
set to which ybelongs.
Wecan then also determine to which two of the three sets a
+ P, a + 6 and fl + b that y
alsobelongs. Taking
into account that each of the functions in E isregressive,
it follows therefore that we caneffectively
find all of the numbers of the set4Yy .
IFor each
number y
E a, letWe note that for each function and number k E
E,
Also
by combining
our earlier remarks with the definition of the set my , we can conclude that from agiven
we caneffectively generate
all of the members of the set coy. Hence my will be an r.e. subset of ~c. Since n is an immuneset,
it follows that my will be a finite set for eachPart 2. It turns out to be convenient for the discussion which follows to assume that for has a
non-empty
intersection with each of the sets a,~8
and 6. For this reason, we shall assumethat the values of ao ,
bo
and co are known to us and that these numbers areplaced
in each (oy. It will bereadily
seen that thismodification will cause no
difficulty.
Some
terminology.
LetyEn.
Setk, 11m maximum numbers and >1*
respectively,
k, l, ,1n- such that ak# , E a)y *
We call the ordered
triple
of numbers(1~, l, m)
the torre-nnmber of y, and denote itby y.
An orderedtriple
of numbers is a torre-nuna- ber if it is the torre-number of somey E n.
Ift - (k, Z, m)
is atorre-number,
the number L(t)
= k-~- Z -f-
in is called thelength
oft. It
readily
follows from the remarks in Part1,
thatgiven
we caneffectively
find y y L(y )
as well as z and L(z)
for any z E coy.In
addition,
we have thefollowing property,
LEMMA 1. If
(ko 7 10 mo)
and(k1 , If , ml)
are eachtorre-numbers,
then
either,
or,PROOF. Assume otherwise and let
mo)
andm 1)
bethe torre-numbers
of yo
and y1respectively.
Without loss of gene-rality,
we may suppose thatConsider the two numbers
Since o, these are distinct numbers. Also each
belongs
toa
+ ~.
LetWe conside1’
separately
two cases : Case 1. q p. It follows froln(*)
that
1~0 + 1
C and therefore up E Thencombining
the twofacts
implies
thatThis means that
which contradicts the
assumption
that(kj , l1 , 1 mi)
is the tore-numbers of y1 ·Case
2. q
> p. One canproceed
here as in Case1 ;
we shallomit the details.
The contradictions obtained here establish the desired result of the lemma. This
completes
theproof.
We obtain
directly
from Lemma1,
thefollowing
two corollaries.COROLLARY 1. For all
COROLLARY 2.
Any
number n E E is thelength
of at mostone torre-number.
Part 3.
Combining
our remarks in Parts 1 and 2 with Corol-lary 1,
we can conclude thatgiven y E n,
we caneffectively
determine allthe numbers of the set
together
with theirrespective
torre-numbers.There will be
infinitely
manytorre-numbers ;
andby Corollary 2,
difierent torre-numbers will have different
lengths.
Letto ,
...be an enumeration of all
torre-numbers,
such that L(tn)
LDefine,
for each number EE,
Clearly,
Let In
be theunique
one-to-one functionhaving
domain E and range7l such that when
reading
from left toright
the numbers in theenumeration,
every number of
4p
appears before every number ofAp-tl,
and thenumbers of
d p
appear in their natural orderaccording
to size. Ifwe combine the
beginning
remarks of thispart together
with thedefinition of the sets
4k ,
it follows that the functionfn
has beendefined in such a way as to be
regressive i.e.,
themapping,
has a
partial
recursive extension. Hence a is aregressive set,
andthis
completes
theproof.
COROLLARY. Let
Ao, ... , Ak
beregressive
isols suchthat,
for0
k, Ai + Aj
EAR .
ThenPROOF. If k = 0 or k = 1 the result is clear. For
k ~ 2
useProposition 2, associativity
of isols under addition and finite indu- ction.We know that A A
-~-
B for any isols A and B.Combining
this fact with
Proposition
1 and theprevious corollary yields,
THEOREM 1. Let L1 be a finite collection of isols. Then L1 has
a r. u. b. if and
only
if5.
Two collections.
We want to consider two
particular types
of denumerable collec- tions of isols. Each of these will be defined in terms of recursive functions.DEFINITIONS AND NOTATIONS. We recall from
[1]
that an(every-
where
defined)
functionf (x)
isincreasing
ifand
eventually increasing
if for some number n, the function g(.x)
== f (x -~- n)
isincreasing. Let f (x)
be aneventually increasing
re-cursive function and let
Df (x)
denote its extension to One of the main results[1]
is thatDf
mapsd~
intoAR .
We let 0 denotethe
family
of allincreasing
recursive functions. Let h(i, x)
be any recursive function of the two variables iand x,
such that for eachi, h (i, x)
E 0. Henceforth we assume that the function h isfixed ;
also we shall sometimes
write hi (x)
for h(i, x).
For E, wedefine
Let T be an infinite
regressive
isol. We note that4Tc Tr .
Also it can be
readily
proven thatFT
is a denumerable collection ofregressive isols, in6nitely
many of which are infinite and which is closed under addition. This means thatI’T
as well asAT
will sati-sfy
the condition(~1).
We wish to establish thefollowing
two re- -sults.
THEOREM 2. Let then
AT
has a r. u. b..THEOREM 3. There is an infinite
regressive
isol T such thatrT
has a r.u.b..PROOF or THEOREM 2. Define the function
f (x) by,
Then f (x)
is a recursive function since h(i, x)
is a recursive fun-ction. In
addition,
it isreadily
seen that(1) f
is an(eventually) increasing
function and for eachnumber i~
(3)
the functionvs (x) = f (x) -= hi (x)
iseventually increasing.
It follows from
(1)
that Tocomplete
theproof
wenow show that
D f ( T )
is an upper bound ofAT.
For this purpose letand assume that
A = Dh (T),
whereh (x) = h (i, x).
Tn viewof
(2),
we obtainwhere v
(x)
= vi(x). Identity (4)
concernsonly
recursive functions and thereforeyields, by
a well known theorem ofNerode,
thatTaking
into account that T is an infiniteregressive
isol and thateach of the functions
f , v
and h iseventually increasing
and re-cursive,
we can conclude from(5)
thatHence
We have thus shown that
and this
completes
theproof.
With every
regressive
isol T andfunction an
from E intoE,
Dekker
[3]
introduced and studied an infinite We re-call the
principal definition,
in thespecial
case that T is an infiniteregressive
isol.NOTATIONS.
Let j
denote the familiarprimitive
recursive func- tion definedby j (x, y)
= x+ (x + y) (x -f - y + 1)/2.
For any numbern and set a, let v
(n) _ ~x I x n) and ,; (n, a)
={j (n, y) y E a).
Werecall that the
function j
maps.E2
onto .E in a one-to-one manner.DEFINITION.
Let an
be any function from E intoE,
and Tany infinite
regressive
isol. Thenwhere tn
is anyregressive
functionranging
over any set in T.By [3,
TheoremI], Zr an
is anisol,
anddepends
on the infi-nite
regressive
isol T but not on theparticular regressive
functionwhose range is in T. In the
special
casethat an
is a recursivefunction,
thenZTan
is aregressive
isol[1,
Theorem1 ].
Infiniteseries of isols summed with
respect
to a recursive function and the extension to~1R
ofincreasing
recursive functions areclosely
rela-ted. Let
TEAR-E;
then a useful result which can be obtained from[1]
isan a recursive function
I.
We shall use this
representation
ofFT
in the course ofproving
Theorem 3. We also need the
following
lemma.LEMMA 2.
Let 2cn
be any function from L~’ into .E. Then there exist retraceablefunctions tn
suchthat,
Un for n E E.PROOF. Let
where pn
denotes the n+
1stprime
number.Olearly tn
is a retrace-able function and satisfies the
property,
un for n E E.PROOF OF THEOREM 3.
Let ai (it)
be aneverywhere
definedfunction of the two variables i and n such
that,
every recursivefunction of one
variable,
and no otherfunction,
appears in the sequence Let thefunction un
be definedby
Apply
Lemma 2 and let tn be a retraceable function such thatLet T =
etn.
Then T is retraceable set. It was proven in[5]
that re-traceable sets are either recursive or immune. If T is a recursive set
then tn
will be a recursivefunction ;
but this is notpossible
in view of
(1)
and the definition of Hence is an immune re-gressive
set. Let T =Req
T. Then T is an infiniteregressive
isol.We claim that
I T
has a r. u. b..We first note that
combining
the remark before Lemma 2 and the definition of thefunction ai (n) implies,
Define the set
It follows from
(1)
1 forevery n E E.
Hence,is a one to-one enumeration of all the elements of the set o. An
easy consequence of the fact
that tn
is aregressive
function is that(*) represents
aregressive
enumeration of the elements of o.Hence a is a
regressive
set.Regressive
sets are either. r. e. or im-mune
[3,
p.90].
If o were an r.e. set it would then followthat tn
isa recursive
function,
which we know is not the case. Thus a is animmune
regressive
set. SetThen To
complete
theproof
we will show that U isan upper bound of
I’T .
For this purpose let and assume thatIt follows from
(1)
and the definition of thefunction un,
thatSet
It is
easily
seen that lVl and N areregressive
isols andWe would like to prove that A ~ U. In view of
(5), (9)
and(10),
it will be sufficient to show that M c N. For this purpose, we first note that
(6) implies
Hence
In addition since a,n is a recursive function
and tn
is aregressive function,
itreadily
follows from(7), (8)
and(11)
thati.
e.1 6 and q - 3
areseparated
sets.Finally, combining (7), (8), (12)
and
(13) implies
that This means that A U. We havetherefore shown
and hence
rT
has a r. u. b. Thiscompletes
theproof.
6.
The collection
In this section we wish to introduce and
study
aparticular
collection
ZT
ofregressive
isols associated with any infinite regres- sive isol T. Theprincipal properties
of~T
that will be proven are,(c) ¿T
is a denumerablecollection,
(g) ~T
has noregressive
upper bound.REMARK. Before we
proceed
togive
the formal definition of the collection;¿ T,
y we want to state some observations about the collection¿T
based on the aboveproperties.
We first note
that, by (a), (b)
and(e), 2.’T
will be a collection ofregressive
isolscontaining
T as well as every(regressive) predeces-
sor of T.
Regarding regressive
successors of1’,
some of these willbelong
to forexample, according
to(a), (b)
and(d), IT
willcontain T
+ n
and n - I’ for any2,
and each of these re-gressive
isols is a successor of T.However,
it need not be true thatevery
regressive
successor of Tbelongs to Zr .
To seethis,
recallthat, by Proposition 2,
there are infiniteregressive
isolshaving regressive
successors whose sum is notregressive.
If T is an isolof this
type then,
in view of(b)
and(d)
it follows that at leastone
regressive
successor of T will notbelong
to~T.
We also note that
combining (b)
and(d) gives,
Renee -YT
satisfies the condition(U).
It iseasily
seen, that if acollection of isols has a
regressive
upper bound then it has a re-gressive
upper bound which is infinite. Assume that 4 is a collec- tion of isolshaving
T as an(infinite) regressive
upper bound.Then,
in view of (e), it follows that
LI c :¿ ’1’.
If we combine theseprevious
remarks with
(a), (b), (c)
and(g),
we can draw thefollowing
con-clusion,
if a collection of isols has a r. u.
b. ,
then it is the subset ofa denumerable collection of isols
satisfying
the condition(0)
andhaving
no r. u. b..We shall now introduce the
preliminaries
necessary for the definition of the collection:¿ T .
PRELIMINARIES.
Throughout
thispart
letbn
and cn denote any functions from .E into E.We I if there is a
partial
recursive function p(x),
such thatWe
bn,
if there is one-to-onepartial
recursive functionp (x)
such that(1)
holds. It isreadily
verified thatAlso,
it was proven in[4] that,
if anand b.
are each one-to-onefunctions,
thenLet tn
be any(one to-one) regressive
function.Using
the defi-nition of the relation
c~,
it isreadily
shown that there areexactly
o functions a.
suchthat tn ~ ~r,~2 . Also, since tn
is aregressive function,
it followsthat tn
* ~z. From thisfact,
we can concludethat tn
* an , for every recursive function an .Let T be any infinite
regressive
isol. We write if there is aregressive function tn ranging
over a set in T such thatIt is well know that if Sn
and tn
are tworegressive
functions ran-ging
over sets thatbelong
to the sameisol,
tn . In view of(2)
and(4),
this means that if then for everyregressive function tn ranging
over a set in T. We also lave thefollowing properties,
(6)
an a recursive function --> T~~ an ,
yWe obtain
(5)
from(3),
and(6)
follows from the fact thatif tn
is anyregressive
functionand a,,
any recursivefunction, then tn
·To
verify (7), let tl’
be aregressive
functionranging
over a setin
T +
1. Let tn =Then tn
is aregressive
functionranging
over a set in T. We note
that tn ~~ t~~ ~ since t’n
is aregressive
aunction. Hence
by (2),
fnd this relation
implies (7).
For each infinite
regressive
isolT,
we letIt follows from our
previous
remarks thatF (T)
is adenumerably
infinite
family
of functions and every recursive functionbelongs
to it.
Also, by (5),
we haveThe
principali definition,.
Let T be any infiniteregressive
isol.Then
REMARKS. We shall assume from now on that T is an infinite
regressive
isol and held fixed. We letF = F (T),
andlet t’n
be aparticular regressive
functionranging
over a set in T-~- 1,
and let tn =t£+i . ’fhen tn
is also aregressive
function and it ranges overa set in T. We sets and T =
ot.
In order to establish the
properties (a)
to(g)
for the collectionIT
we shall need severalpropositions
and lemmas. The lemmas that follow can be verified in an easy manner and for this reason we shall omit theirproofs.
NOTATION. Let 8 be an infinite
regressive
isol. ThenPROPOSITION 4. T E
IT
and FcIT.
PROOF.
By (6),
we know that for every recursive function an . HenceNT ,
for every recursivefunction an .
Inparticular,
T EIT
becauseand k E for every
number k,
sinceTherefore and PROPOSITION 5.
ZTC
PROOF. Let and assume that
Then
Let oc denote the set
appearing
in(10).
To prove theproposition,
we want to show that A E and this is
equivalent
toshowing
that a is an isolated and
regressive
set.By
our remarksin § 5,
weknow that A E 11 and therefore a will be an isolated set. It remains to prove that a is
regressive.
Since finite sets areregressive,
wemay assume that a is an infiinite
(immune)
set. In view of the de- finition of a, it then follows that the setwill be infinite. Let
f (n)
be thestrictly increasing
functionranging
over A. Then
is an enumeration of all the elements of a.
Also,
this enumeration isone-to-one,
because each of thefuiactions t’ and j (x, y)
is one-to-one. We now
proceed
to show that the enumeration in(11)
is re-gressive.
Tobegin,
notethat, by (9),
and therefore alsoLet the number be
given.
We wish to show that we caneffectively
find each of the numbersUsing
theregressiveness
of thefunction tn
we can find the valueof f(n + 1),
as well as the numberstogether
with theirrespective
indices. In view of(12),
we can thencompute
thenumbers,
Because
f (n) +
1~ f (n + 1),
it follows thatby determining
thenumbers in
(14)
that arepositive,
we caneffectively
find the valueof af(n) and also the number
f (n).
Therefore the value of can befound. Since we know the value
of f (n),
we can locate the number among the elements in(13).
Hence the value of can alsobe found. We can conclude from these remarks that each of the
mappings,
has a
partial
recursive extension.Combining
thisproperty
withthe fact
that j (x, y)
is a one-to one recursive function it isreadily
seen that
(11) represents
aregressive
enumeration of the set a.Therefore a is a
regressive set,
and thiscompletes
theproof.
PROOF. Use
(5),
the definition of and Lemma 3.PROOF. Let the
function bn
be definedby, bo
= 0 and =Then
1’+
andby (7) also, T ~~ b~, . Clearly,
Therefore,
and hence
PROPOSITION 8. Let A C T. Then A for some function an with ’1’
~~ an .
PROOF. If A is
finite,
say ...1 =k,
then the result followsby letting
an be the(recursive)
functiongiven by, ao
= k and = 0.Assume now that A is an infinite
(regressive)
isol. Then therewill be a
strictly increasing
functionf (x)
suchthat,
if a =etf(n),
then
In this case, let the
function an
be definedby,
- a; it follows
that tn
and hence alsoIn
addition,
it isreadily
seen thatCombining (15)
and(16)
with the factthat a E A,
weobtain
This
completes
theproof.
COROLLARY. A C T > A E PROOF. Use
Propositions
7 and 8.LEMMA 4.
Let an
be any function suchthat, an > 1
for every number n. Then TREMARK. We wish to mention that while the infinite series referred to in Lemma 4 will be an isol it need not be a
regressive
isol.
LEMMA 5. Let 6 be a
regressive
set suchthat,
Then there is a
regressive function dn
that ranges over 6 and which also preserves the order of the set 7: as determinedby
the functionin the sense
that,
if 7:, thenPROPOSITION 9. Let Y E
All
and 1’::;: TT. Then there is a regres- sive isol B suchthat,
PROOF. Let 6 be a
regressive
setbelonging
to V. Because TmV,
it follows that there exists aregressive
set z*E1’~
suchthat
Both T and -c*
belong
to T and therefore 1: ~ z*. For reasons of no-tation,
we wish to assume that z = z~‘. Because z 2t?z*‘,
it will beseen that this modification does not cause any
difficulty
in theproof.
With this
identification, (18)
can be rewritten as,Apply
Lemma5,
and letdn
be aregressive
functionranging
overb and
satisfying (17), i.e.,
It will be seen that there is no loss in
generality
if we assumethat do
=to ;
and onceagain
for reasons ofnotation,
we shall as-sume from now on that this is true.
Let f (n)
be thestrictly
incre-asing
function suchthat,
We note that
combining (16),
with theregressiveness
of the func-tions tn
yyields
Define the function e
(n) by,
Then e
(o)
=0,
and for everynumber n,
e(~n + 1)
~ 1.Taking
intoaccount
that
is aregressive
function it follows from(20),
thatand hence also that
(24)
Set
Then,
in view of(24), B E ~T .
Inaddition,
sincee (o) = 0~
we havethat
and therefore
also,
Combining
Lemma 4 with the factthat,
e(n + 1)
> 1 for everynumber n,
it follows from(25)
thatWe have shown so far that both B E
IT
and T B. Tocomplete
the
proof
we nowverify that,
Let
In view of
(25),
B. We know that both T T is an in- finite isol. Because it follows therefore that B is an infiniteregressive
isoland P
is an infiniteregressive
set.By employing
an
argument
similar to the one in theproof
ofProposition 5,
onecan
readily
show thatrepresents
aregressive
enumeration of the setfl.
Let b.
be theregressive
functionranging over #
that is deter- minedby
this enumeration.Taking
into account the definitions of the functionsf(n)
ande (n),
we note that thefnnction bn
has thefollowing property;
In order to establish
(27),
it suffices to prove thatand this will be our
approach
here. For this purpose let the num-ber dn
begiven.
We wish to find the value ofSince dn
is aregressive
function we can find the number n. Let lc be the lar-gest
number suchit;
and recallthat tn
=d f(k~ .
Becausez
d
2013 Tand dn
is aregressive function,
we can determine both ofthe numhers
f (k)
andtk ;
and hence also the number r suchthat,
We can then
compute
thenumber,
In view of
(29),
this means that we caneffectively
find the value of We can conclude from these remarks that then>apping,
has a
partial
recursiveextension,
and thereforedn C~‘ b~ .
This pro-ves
(30),
andcompletes
theproof
of theproposition.
PROPOSITION 10.
IT
has noregressive
upper bound.PROOF. Assume otherwise and let U be a
regressive
upper bound of-YI7.
We first note that For if then also
U+ 1
which would mean that
U -t
1 since U is an upper boundof ~T .
But it is well known that the relationU -+-
1 U is falsefor isols.
Because 11 E
ZT
and U is aregressive
upper bound ofIT,
itfollows that T U. Hence
by Proposition 9,
there will be a re-gressive
isol B such andSince B E it follows that B ~ U and hence also that
Combining (31)
and(32) implies
thatThis would mean that which we
already
know is not thecase. We can conclude
therefore, that -YT
has noregressive
upper bound.REMARKS. This
completes
the results necessary in order toverify
theproperties (a)
to(g)
for the collectionZT .
We note thatproperties (a)
and(b)
follows fromPropositions
4 and 5.Property (c)
followsdirectly
from the definition of~,~
and the fact that F is a denumerable collection of functions.Property (d)
isProposition 6,
andproperty (e)
is thecorollary
toProposition
8.Lastly,
proper-ties
(f)
and(g),
arePropositions
9 and10, respectively.
BIBTJIOG RAFIA
[1]
J. BARBACK, Recursive functions and regressive isols, Math. Scand. vol. 15 (1964),pp. 29-42.
[2]
J. BARBACK, Two notes on regressive isols, Pac. J. of Math. vol. 16 (1966),pp. 407-420.
[3]
J. C. E. DEKKER, Infinite series of isols, Amer. Math. Soc. Proc. Sympos.Pure Math. vol. 5 (1962), pp. 77-96.
[4]
J. C. E. DEKKER, The minimum of two regressive isols, Math. Zeitschr. vol.83 (1964), pp. 345-366.
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J. C. E. DEKKER and J. MYHILL, Retraceable sets, Canad. J. Math. vol. 10(1958), pp. 357-373.
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J. C. E. DEKKER and J. MYHILL, Recursive equivalence types, Univ. California Publ. Math. (N.S.) vol. 3 (1960), pp. 67-213.[7]
T. G. McLAUGHLIN, Splitting and decomposition by regressive sets, MichiganMath. J. vol. 12 (1965), pp. 499-505.
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J. MYHILL, Recursive equivalence types aud combinatorial functions, Proc. of theInternational Congress in Logic and Methodology of Science, Stanford (1960), pp. 46-55.
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A. NERODE, Extensions to isols, Ann. of Math vol. 73 (1961), pp. 362-403.[10]
A. NERODE, Extensions to isolic integers, Ann. of Math. vol. 75 (1962), pp.419-448.
[11]
F. J. SANSONE, Combinatorial functions and regressive isols, Pac. J. of Math vol. 13 (1963), pp. 703-707.[12]
F. J. SANSONE, The summation of certain series of infinite regressive isols,Proc. Amer. Math. Soc. 16 (1965), pp. 1135-1140.