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Developable domains in hexagonal liquid crystals
M. Kleman
To cite this version:
M. Kleman. Developable domains in hexagonal liquid crystals. Journal de Physique, 1980, 41 (7),
pp.737-745. �10.1051/jphys:01980004107073700�. �jpa-00209299�
Developable domains in hexagonal liquid crystals (*)
M. Kleman
Laboratoire de Physique des Solides (**), Bât. 510, Université Paris-Sud, 91405 Orsay and S.E.S.I., C.E.N., 92260 Fontenay
auxRoses, France
(Reçu le 17 décembre 1979, révisé le 29 février, accepté le 3
mars1980)
Résumé.
2014Les configurations d’une phase mésomorphe du type cristal liquide hexagonal
nepossédant pas
d’énergie élastique mais seulement de l’énergie de courbure sont caractérisées géométriquement par l’existence de repères locaux
nondistordus par rapport à celui propre
aucristal parfait, et par l’absence de déformation de
divergence (div t
=0). Ces contraintes conduisent à
unegrande classe de solutions, sans déformation de torsion
(t. rot t
=0),
avecdéformation de flexion (t
~rot t ~ 0). On démontre que
cessolutions
sanstorsion
se carac-térisent par l’existence de plans physiques perpendiculaires
auxalignements moléculaires
encolonnes (pour les disquotiques)
ou entuyaux (pour les lyotropes) de la structure. Ces plans enveloppent
unesurface développable, type de solution d’abord mis
enévidence par Bouligand. Nous étudions
endétail
sespropriétés géométriques et
montrons comment obtenir tous les domaines développables à partir d’une représentation plane de la configura-
tion spatiale. Nous donnons aussi des méthodes de calcul de l’énergie. Cette théorie est illustrée par deux exemples simples : l’un où le domaine développable équivaut à
unedisclinaison, l’autre où il équivaut à
unpoint singulier.
Abstract.
2014Configurations without strain (as opposed to curvature) in
amesomorphic phase made of long thin
rods (like hexagonal liquid crystals)
arecharacterized by local frames of reference undistorted with respect to the ground state and by absence of splay deformation (div t
=0). These constraints lead to
animportant class
of solutions, without twist deformation (t. rot t
=0), with bend deformation (t
~rot t ~ 0). It is shown that
this class of solutions is characterized by the existence of physical planes perpendicular to the rods, enveloping
a
developable surface. This is the solution first devised by Bouligand. We study its geometrical properties in
details and solve the problem of obtaining all the so-called developable domains by using a plane representation
of the space configuration. We also give methods to calculate its energy. Two simple examples
aregiven, one in
which the developable domain is equivalent to
adisclination, another
onein which it is equivalent to
asingular point.
Classification
Physics Abstracts
61.30 - 61.70
61.30
201361.70
The recent discovery of mesomorphic phases whose building molecules are disk-like [1] (the so-called
discotic phases) and are stacked in cylindrical rods
which are themselves hexagonally packed [2], raises
a number of interesting questions concerning the arrangements of these cylindral rods and the energy attached to various arrangements. Such questions
could as well have arisen a long time ago with the well-known hexagonal phases of soaps and lipid-
water systems, first discovered by Luzzati et al. [3].
Although some observations of textures either by optical microscopy [4] or by electron microscopy of
freeze-etched specimens [5], have been made in such systems, and have provided us with standard pictures
of these textures, there is however no systematic description of the specific features of the organization
of hexagonally packed long thin rods, when the long
range order is perturbed. As it is well known now
by the example of nematics and other classical meso-
morphic phases, such a description has necessarily to
use altogether geometrical concepts (for the distor- tions with short wave vectors) and topological
concepts (for the understanding of the singularities
and defects of the order parameter at long wave
vectors [6]).
This paper will deal essentially with geometrical concepts ; recent observations in the polarizing micro-
scope of inverted hexagonal phases of complex detergents [7] and of discotics [8, 9] have led to models
for the repartition of molecular cylinders. In parti- cular, it has been assumed [8] and checked on some
examples that the distortions of low energy are such that all the long thin rods are perpendicular to a
one-parameter familÿ of planes (in which case the long thin rods suffer only bend). We shall justify this assumption on well defined energetical grounds. This
condition is akin to the condition of parallelism of
smectic layers in smectic phases, which lead to the (*) Work partially supported by DRET contract 79/352.
(**) Associé
auC.N.R.S.
Article published online by EDP Sciences and available at http://dx.doi.org/10.1051/jphys:01980004107073700
738
existence of cofocal domains [10] ; as in this last case, it allows for a vanishing strain energy (strain as opposed to curvature).
We shall therefore discuss in details the case of pure bend, for which we shall extend Y. Bouligand’s
results [8]. The discussion of other cases, as well as
of topological concepts, will be left for a forthcoming
paper. We also leave for another publication a
detailed discussion of experimental observations of
defects, in the light of the present study.
We shall assume that the reader is familiar with the structural properties of hexagonal phases [1, 2, 3].
1. Free energy density and general considerations.
-Let us call t a unit vector along a long thin rod (1) ;
t is a function of position r. We symbolize the rod by
a curve T along its central axis. The free energy
density pf contains a term of curvature pic and a
term of strain pis. By analogy with other liquid crystals [11] we have
The strain energy density reads [12] :
Let us first assume that the rods are infinite (the
concentration of chain ends vanishes) and that mass density of the medium is constant p
=po. Therefore
we have [13] :
and the term of compressibility vanishes also in (2).
We shall investigate the more drastic case in which pfS vanishes completely ; i.e. the rods are at constant distances and the hexagonal packing of rods is pre- served (angularly and metrically) locally. These geo- metrical properties imply the following :
For the metrical properties : Consider any surface 1
generated by a set of rods which are neighbors 2 by 2 (we shall call r lines the lines representing the rods).
This surface can be defined unambiguously because
the distances between neighboring r lines are small, compared to their length, and we can safely use the
continuous limit when this distance goes to zero. In such a 1 all the rods are parallel (in the sense of parallelism on a surface). Hence the orthogonal trajectories G of T lines are geodesic lines on E. It
(1) We
uset, rather than
n(the classical notation for the direc-
tor), because
nwill have here the meaning of the principal normal
at
apoint
on a curvealong
arod.
can be shown that these metrical properties imply,
as stated already above :
Angular properties : Two surfaces Il and L 2 which
intersect along a common r line make a constant angle ; hence, according to Joachimsthal’s theo-
rem [14], either r is a line of curvature on both LI
and L 2’ or is on none. Hence we have to distinguish
two cases :
Let us study the case when r is a line of curvature
on Il and 12. It is therefore a line of curvature on
any E passing through T and we shall assume that
there is a domain in which any r is a line of curvature.
The G lines, which are orthogonal trajectories to the lines, are also lines of curvature of the L’S. Being at
the same time lines of curvatures and geodesic lines, they are plane (no torsion). Therefore there exist H
planes which are perpendicular to the whole set of
r lines of the specimen, and any straight line in such Il planes intersects orthogonally the T lines. More- over, since there are surfaces normal to the T lines,
we also have
and the energy density reduces to a pure term of
bending. We have here obtained, by demonstrating
the existence of planes II, the fundamental possible geometrical feature of an hexagonal phase in which
the strain energy density vanishes. This result was
proposed without demonstration by Y. Bouligand [8].
J. Mérucci [7] insisted only on the existence of straight
lines perpendicular to the rods.
Let us now assume that we are in the less interesting
case (at least energetically speaking) when all the r lines of a given domain of the sample are not lines
of curvature of the E’s. We shall show that this case
is impossible.
Since the angle between two E’s is constant all along r, the geodesic torsion 1/r of r is the same on
both I’s, and in fact on all I’s passing through r.
1/t is simply related to the twist of the rod. We can indeed show that
The non-vanishing of the twist indicates that there
are no surfaces perpendicular to the rods. But the r lines have orthogonal trajectories G, as in the preceding case, which are still geodesic lines of the L’S, for the same reason as above, i.e. because the T line
are parallel on any 1. This implies that the osculating planes of the G lines contain the director t. There- fore the center of curvature of a G line is the point of
intersection of two straight lines bearing two neigh- boring t directors t and t’ on two different r lines,
when t and t’ approach each other infinitesimally
along the G line. If such a point of intersection is at
finite distance, this implies some elastic distortion of
the two-dimensional hexagonal packing. But we
have excluded this case. Therefore the radius of
curvature of a G line is infinite and the G lines are
straight. r lines are therefore still lines of curvature and there is only one class of solutions to our problem.
We can express this result in other words, by stating
that there is a class of distortions of an hexagonal liquid crystal in which angular properties are con- served, but metrical properties are not.
We shall here restrict to the case where angular
and metrical properties are conserved. For reasons
which will appear shortly, we call developable domains
the regions in which eqs. (3) and (4) are satisfied.
2. Description of the F lines ; reciprocity with a
fixed line of singularity.
-Two neighboring r lines (r 1 and T 2) have parallel tangents at their intersec- tion with a given II plane (Fig. 1).
Fig. 1.
2013Two neighboring r lines at their intersection with
ail
plane.
It is easy, by differentiating
t
(where v is an unit vector which, in the Frenet trihe- dron ni, bi, tl, reads v
=ni cos m + bi sinw), to
obtain
with
1 / T1 and 1 /R are the standard torsion and curvature
of T1 in Pl. si and s2 are curvilinear abscissae on T1,
1and T2.
Let us express that t1
=t2. One gets
Since ti
=t2, the principal normals n, and n2, and the binormals bi and b2 are parallel, and we get
Condition (7a) is equivalent to t. rot t
=0. Eq. (8a)
means that the centers of curvature-C of the different r
curves intersecting II are on a straight line D which is perpendicular to n (Fig. 2).
Fig. 2.
-Centers of curvature C and principal normals of r
curvesin plane 77.
It is clear that D is an axis of instantaneous rotation of the plane II (and of the lines T) and as such is the limit of the intersection of H with a neighboring plane
H’. In other words the set of planes II envelop a developable surface S; the lines D are the straight
lines of S. Call M the characteristic point of D : it is
the point where two neighboring lines D and D’
intersect when D’ tends towards D. The locus of M is a twisted curve L which is a singular line on S (the
so-called cuspidal edge of S). A clear description of the geometrical properties of developable surfaces is
given by Hilbert and Cohn-Vossen [15] (Fig. 3).
The physical lines T exist in one of the regions of
space delimited by the two sheets of S ; this region is
defined by the possibility of drawing at least one real plane P tangent to S. For example, if S is a cone (in
Fig. 3.
-A developable surface S generated by straight lines D
and its cuspidal edge L which divides L into two sheets.
740
which case the cuspidal edge is reduced to the apex),
the physical region is the external one. It is clear in this
example that we have to consider physically only an
half of the plane II, i.e. a region bounded by the line D.
The system contains a surface of singularity S (to
which r lines are orthogonal) and a line of singularity
L. The name of developable domain appears now
justified.
The existence of L, S, and D has been demonstrated
by Y. Bouligand who however did not try to get formulae (7) and (8). We shall now see that 1/R and 1/Tare in duality with similar quantities relative to the cuspidal edge L.
Consider in the same II plane the Frenet trihedron in P (a point in H) on the T line passing through P
and in M (the characteristic point of D) on the cus- pidal edge L. The tangent to L is p
=b, the normal
to L is q
=n, the binormal is r
= -t, where b and n
are respectively the principal normal and the binormal in P along r. Let us write Frenet formulae for both
curves rand L. We call u the curvilinear abscissa on L, 1/p and 1 /s the curvature and torsion of L in M. We get which leads to
Table 1.
-Frenet formulae on a rod r and on the cuspidal edge L of the developable domain.
There is complete reciprocity between T and L.
On each plane II(u), TIR
= -p/s is a constant.
One can analyze the instantaneous motion of each
plane II as a torsion about its normal t and a rotation about D. If the coordinate Q is considered to grow with unit velocity, lines D rotate about r with angular velocity d03C8/da
=1/p. Since t
= -r, each plane 77
suffers a torsion of opposite velocity - 1/p (we avoid
here the term of twist about t, just since we are consi- dering geometries in which what we usually call twist, i.e. t. rot t, is absent). Normals to planes 77 rotate
about D at a rate dqJjda
=1/t.
3. First results on the energy of a developable
domain. Angular components of a domain.
-Equa-
tion (9) allows for a simple calculation of the bulk energy
We use curvilinear coordinates : in each plane II(6)
the y-axis is along D(Q). R is the value of the x-coordi- nate (see Fig. 2) ; ds is the elementary length along the
normal to ll(u). Hence
Call lx and ly typical sizes of the domain. We get
where we have
and b is some molecular length (a cut-off length near
the developable surface S). A surface energy term has to be added to (11), and it is clear that this term will make all the difference, since (11) does not depend
on the precise geometry of S and L. But other remarks
are interesting at this stage.
Let us notice that the bulk energy depends linearly
on the strength 03A9 of the line ; this is unusual. Also, the energy does not depend on the evident other strength of the domain, viz. :
We call Qil the longitudinal angular component or longitudinal strength of the developable domain,
since the axis of the infinitesimal rotation do-/T is along the cuspidal edge L ; this axis is also perpendi-
cular to the rod and is of constant direction (along b)
in the moving frame t, n, b.
We call Ql. the transversal angular component (or
transversal strength) of the developable domain, since
the axis of the infinitesimal rotation da / p is along the
binormal to the cuspidal edge, i.e. the tangent t to F.
t is also a constant vector-in thé moving frame and
is a direction of rotational symmetry of the hexagonal phase, of order 3 or 6 according to the case. (b, in general, is not a direction of rotational symmetry of the hexagonal phase.)
We shall discuss in the last paragraph of this paper the nature of a developable domain in terms of defects.
Let us first look to a very simple example.
4. A disclination built on a developable domain (in collaboration with P. Oswald).
-The simplest
type of developable domain is one in which the deve-
lopable is a circular cylinder of radius a ; the cuspidal edge is a point at infinity. The pattern of the rods is the
same in any orthogonal section of the cylinder : the
rods are curved in evolutes of the circular section of the
cylinder (Fig. 4). Clearly, such a configuration is
that one of a disclination line of strength S
=+ 1,
of core radius rc > a (we have to establish a relation- ship between rc and a). Let us limit the sample to a
size Ro (measured along a tangent to the circle of radius a) and compute the energy per unit length.
It is simpler here not to use eq. (11), but start from the
formula of definition
which here leads, for the bulk energy per unit length of cylinder, to :
(one will notice that the strength
does not appear in this expression as foreseen in
eq. (11) ; this is because any rod crosses many times a
given II plane, in fact21n Q II times so that the effective
longitudinal strength is 2 n, which is also the strength
of the disclination).
Fig. 4.
-The rods
areevolutes of the circle of radius
a.The whole
configuration is equivalent to
adisclination of strength unity, with
core
radius rc
> a.We have to add to eq. (12) a term of surface energy
(the core is empty in our model). We write the surface tension as the sum of an isotropic term yo and of
anisotropic terms
where (Jc is the angle between the rod and the plane
tangent to the circle rc. We have
If we limit ourselves to the first term of anisotropy,
we obtain
and the total energy has to be minimized with respect
to the two variables a and r,. One gets :
Such a solution demands 0 1 2 yo - y 1 Yo.
We shall discuss this example in more details, as
well as the existence of lines of half integral strength (S
=-1 built on developable domains, in another paper, in the light of experimental results obtained on
discotic mesomorphic phases.
5. Hpw to obtain aU developable domains. -‘ An important property of a developable surface S is of
course that it is developable on the plane. In such a mapping the cuspidal edge L becomes a line £’in the
plane. The straight lines D of S become the tangentes D
to C. The straight lines of the two sheets Si and S2 of S map on one or the other half infinite segments D 1
and D2 of D bounded by the point of contact u1L on C.
Lengths and angles are preserved in these operations ;
this remark implies that the curvatures of Land L at
corresponding points are the same. But torsion, which is an instantaneous rotation about the unit vector
tangent to L, is not preserved. In the sequel, we call P
the plane of mapping.
Let us now consider the inverse problem : start from
a curve £ in the plane P and build a developable surface
from it. The essential thing is that the result is not
unique. We quote Hilbert and Cohn-Vossen [14].
« If we proceed the other way around, starting with a
convex arc ô in the plane, and removing the portion
of the plane lying on the concave side of the arc, then
we can bend the remaining part of the plane in such a
way that the curvature at every point of the space
curve d into which ô is transformed is the same as the curvature at the corresponding point of 03B4. As can be
proved analytically we can, at the same time, give the
space curve d any torsion we wish. This type of defor- mation of a space curve, in which arc length and first
curvature are preserved while torsion is changed,
will be referred to simply as a twisting of the curve in question. »
Since any torsion function i(6) can be chosen in order to build L, it is clear that an other way’of map-
ping the developable domain on P is to untwist it, i.e.
decrease its torsion function without changing its
curvature, until the torsion vanishes. Any interme-
diary situation in the course of such a process is a
742
developable domain which possesses the same repre- sentation in the plane P. In particular the final state
in P is a developable domain in which all planes are
reduced to the same plane P. But this means also that
all the hexagonal patterns drawn on each 17 map on the same pattern on P, while at the same time each physical rod r becomes a straight line perpendicular
to P (see Fig. 5) (2).
Fig. 5.
-Representation of a developable domain in the plane P ; the
curveL maps
on£, and the straight lines of the two sheets of the
developable map
onthe set of tangents to C. Each plane 77 maps
on
the entire plane P, while the 2 dimensional hexagonal patterns of the n’s map
on aunique hexagonal lattice
onP. For simplicity
we