A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
K UO -S HUNG C HENG C HANG -S HOU L IN
Compactness of conformal metrics with positive gaussian curvature in R
2Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 26, n
o1 (1998), p. 31-45
<http://www.numdam.org/item?id=ASNSP_1998_4_26_1_31_0>
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Compactness of Conformal Metrics with Positive Gaussian Curvature in R2
KUO-SHUNG CHENG - CHANG-SHOU LIN
Abstract. In this paper we consider the compactness of a sequence of solutions un of in
where K (x) is
positive
inR2
anddecays
like at oo for some b > 0.Assuming
that the limitof the total curvature of un satisfies
we prove that un must be bounded in
W o~ (II~2)
for any p > 1. We also construct aspecific
K (x ) = K (Ix I) to show that the total curvature of any solution u ofequation
(0.1) with thissatisfy
This appears to be in contrast with the statement of Theorem
Al
in [A]. In this respect, we show that forany K
whichdecays
likeIxl-b
for 0 b 2, there exists ao (K )> 2 2 b
such that the total curvature of any solution u of (0.1 ) mustsatisfy
1. - Introduction
In this paper, we consider the entire solution of the
equation
in
where A is the
Laplacian operator
ofR2
andK (x)
is agiven
function inJR2.
Equation ( 1.1 )
arises in theproblem
offinding
a Riemannian metric which is Pervenuto alla Redazione il 2 ottobre 1996 e in forma definitiva il 18giugno
1997.conformal to the flat metric of
R 2
and realizes thegiven
functionK(x)
as its Gaussian curvature. We refer the reader to[CN1]
for a briefdescription
of thebackground
and thehistory
of thisproblem.
In case K is
nonpostive
onJR2,
afairly complete understanding
of thethe solution set of
(1.1)
was achieved in[CN1], [CN2].
To state the results in[CN2],
we introduce al asThen the main result in
[CN2]
isTHEOREM A.
Suppose
that K 0 inJR2
and thatfor I large
and somepositive
constant m. Then we have:(I) 0,
then( 1.1 )
possesses no entire solution inJR2.
(II) If a
I >0,
then thefollowing
conclusions hold:(i)
For each a E(0, a 1 ), ( 1.1 )
possesses aunique
solution Ua such thatat c
(ii) The function
U(x ) given by
is an entire solution
of ( 1.1 )
inis
well-defined everywhere in JR2
and is a solutionMoreover, (iii)
Let u be anarbitrary
solutionof ( 1.1 )
in Then either u - U or u - uafor
some a E(0, al ).
(iv) If
0 af3
al, thenU(x) for
all x EJR2.
Furthermore, for
anygiven e
>0,
there exists a constant R = R(s)
suchthat for Ix I
>R,
In this
paper, K
isalways
assumedlocally
bounded andpositive
inJR2.
A solution u means u e for any p > 1 and satisfies
( 1.1 )
in thedistributional sense. For the case
K (x)
ispositive
inR~,
it is notexpected
thatresults similar to Theorem A should hold.
However,
for somespecial
as stated in Theorem 1.1
below,
we have thefollowing
result in thespirit
ofTheorem A.
THEOREM 1.1. Let
K(x)
=-1 for
1and K(x) - ~ for x ~ I
>1 for
some constant b > 0. Then the
following
statements hold:(i)
For every asatisfying
-2 amin{O,
b -2}, ( 1.1 )
possesses aunique C2
radial solution ua
(r) satisfying (1.4).
(ii)
Let u be anarbitrary
solutionof (1. 1) satisfying (1.4)for
some a, then asatisfies
-2 a
minjo,
b -2}
andu(x)
= where is the solution in(i)
above.
REMARK 1.2. On the constrast to the case K
0,
thefamily
of solutionua
(x)
in Theorem 1.1 does not have the monotoneproperty
in a as the case in Theorem A. Infact, by
the concrete construction of solutions in theproof
of Theorem
1. l,
it can be seen that ua(r)
and(r) exactly
intersects once forP.
Wehope
that it will be useful in a futurestudy.
Although
Theorem 1.1 areonly
concerned with somespecific K (x),
it stillprovides
aninteresting example
to the situaton whenK(x)
ispositive
inJR2.
In
[A],
Avilesproved
thefollowing theorem, (See
TheoremAl
in[A]).
THEOREM B. Assume K
(x)
> 0 inR 2
and K(x) Ix Ib
=1 for
somepositive
constant b > 0.Then, for
any asatisfying
there exists a solution u
of ( 1.1 ) satisfying
at (
Let
K (x )
be thespecific
funtiongiven
in Theorem 1.1 with 0 b 2.Then Theorem 1.1 contradicts to the result of Theorem B. In
fact,
Theorem 1.1 is not an isolated case to show that Theorem B does not hold. For a gen- eralK (x),
setthere is an entire solution u of
( 1.1 )
such thatat (
Our main result is
THEOREM 1.2.
Suppose
that K(x)
ispositive
andlocally
bounded inJR2
andsatisfies
for I x I
> 1 andfor positive
constantsA,
B and 0 b 2. Then Iwhere ao is
given
in( 1. 6).
Obviously,
Theorem 1.2implies
that Theorem B does not hold ingeneral.
We note that the real number a I in
(1.2)
is-~
ifK(x)
satisfies(1.7).
Theorem 1.2
provides
amajor
contrast to Theorem A for the caseK (x) s
0. We would like to remark that solutionspossessing
theasymptotic
behavior(1.4)
havea
geometric meaning. Following
conventionalnotations,
a solutionu (x) of (1. 1)
is said to have a
finite
total curvatureif K (x)e2u(x)
and thequantity
2 is called the total curvature o, f’u.
AssumeK (x)
satisfies(1.7).
2,, fR2
AssumeK(x)
satisfies(1.7).
A consequence of our
previous
results in[CLn]
is that a solution u has a finitetotal curvature if and
only
if u possesses theasymptotic
behavior(1.4),
or moreprecisely, u(x) / log Ix I exists,
and theidentity
are
always
true. Please see Lemma 2.1 in Section 2.Thus,
it isinteresting
toknow what is the
possible
range of a orequivalently,
thepossible
range of the total curvature of solutions. In[M],
McOwenproved
that if 0K (x) s
at oo, then for every a E
(-2, (b - 2) - )
where(b - 2) - = min(0,
b -2),
there exists a solution of( 1.1 ) satisfying (1.4). Together
with Theorem1.1,
we see that the result of McOwen is the bestpossible
for ageneral K
whichdecays
like at oo.
THEOREM 1.3.
Suppose X (x)
is apositive
continuousfunction
inR 2
andsatisfies
K(x) ixib
= 1for
some0
b 2. Assume Un is a sequenceof solutions of ( 1.1 )
such thatThen un is bounded in p > 1. Furthemore
if un
converges to u in2,p (JR2),
thenCOROLLARY 1.4.
Suppose
Ksatisfies
theassumption of
Theorem 1.3 andUn is a sequence
of
solutionsof ( 1.1 ). If 1~
as n - andfor
some So >0,
then wealways
haveCOROLLARY 1.5.
Suppose
Ksatisfies
theassumption of Theorem
1.3 andis
defined
in( 1.6). If ao (K) > - (2 - b),
thenao (K)
isachieved,
i. e. there exists a solution uof ( 1.1 )
withREMARK 1.6. When
K (x) decays
like forb > 2,
and un is a sequence of solutions of(1.4) satisfying
for some Eo >
0,
then un is bounded in Theproof
is easy, and willbe omitted.
The paper is
organized
as follows. In Section2,
we willgive
aproof
ofTheorem l.l. Both Theorem 1.2 and Theorem 1.3 will be
proved
in Section 3.2. - Proof of Theorem 1.1
Let K be
positive
inR 2
andsatisfy
for
I large,
where m is apositive
constant. A solution u of( 1.1 )
is said tohave a finite total curvature if
Ke2u
EL1(JR2),
and thequantity Ke2udx
is called the total curvature of u. Theorem 1.1 in
[CLn]
says that if u is asolution of
(1.1)
with a finite total curvature, thenj
I exists and log Ix IConversely,
it is easy to see that ifexists,
then .and
(2.2)
holds.Hence,
we haveLEMMA 2.1.
Suppose
Ksatisfies (2.1 ).
Thenif
andonly if l~
exists.Moreover, (2.2) always
holds.REMARK 2.2. In
fact,
Theorem 1.1 in[CLn]
also shows that for a solution uof
( 1.1 ) having
a finite total curvature a, there exists a constant C such thatholds.
Hence,
if forlarge
thenwhere
PROOF OF THEOREM 1.1. Let
and
where
B1
> 0 is a constant and Then it is not very difficultto
verify
that Ua is aC2-solution
of(1.1) provided
thatSince
UQ’ (0) = 2 log(4B1 ),
we see that7~
1 > 0 exhausts all radial solutions. It is easy to see that ua satisfies(1.4)
with a =-A2 -
1+ ~.
NowA2
is amonotonic function of
B1 satisfying
and
Hence a satisfies -2 a
min[O,
b -2}.
This proves(i).
Now suppose that u be an
arbitrary
solution of( 1.1 )
with finite totalcurvature. Since
K(x)
= isnonincreasing
in r andK (r) >
for any 0,8 1,
then from Theorem 1.7 in[CLn],
we conclude that u must be a radial function. Hence u - ua for some a in the range -2 amin[O, b - 2},
where ua is defined in
(2.4)
and(2.5).
This proves(ii).
03. - Proofs of
compactness
theoremsIn this
section,
webegin
with aproof
of Theorem 1.2.First,
we need thefollowing
result which wasproved
in[BM].
THEOREM 3.1
(Theorem
3 in[BM]).
Assume un is a sequenceof solutions of
in
satisfying
and
for
two constantsC1
andC2.
Then either un is bounded in or there exists asubsequence of un (still
denotedby un)
such that either Ununiformly
on anycompact
setsof Q
or theblow-up
set S is aset of finite
numberof points,
Un ~ -00uniformly
on anycompact
setof SZ B S,
andKn e2un
converges toI:i ai8pi
withai > 2TL’ and S =
Ui {pi }.
REMARK 3.2. When either
Kn
isuniformly convergent
or converges to apositive
constant then Theorem 3.1 can beimproved
to have ai > 4~ .PROOF OF THEOREM 1.2.
Suppose
ao= - ( 2 2 b ~ .
Since ao= - 2 2 b
can notbe achived
by
some sloution of( 1.1 ) by
Remark2:2,
there exists a sequence of solutions of Un such that the total curvatureSince K has a lower
positive
bound in anycompact
set ofJR2, by
Theorem3.1,
we have either un is
uniformly
bounded in anycompact
set or un isuniformly
convergent
to -oo in anycompact
set ofJR2.
STEP 1. We claim that un -~ -oo
uniformly
in anycompact
set ofR 2 Suppose
un isuniformly
bounded in anycompact
set ofJR2. By
theelliptic estimates,
we may assume Un - u inW o p (I~2)
for any p > 1. Inparticular,
u satisfies
(1.1)
and the total curvaturewhich
yields
a contradictionby
Remark 2.2.Hence, by
Theorem3.1,
we haveUn 2013~ -oo
uniformly
in anycompact
set ofJR2.
STEP 2. We claim there exists a constant C > 0 such that for
To
prove theclaim,
we assume there exists xn EJR2
such thatBy Step 1,
we have as SetThen vn
satisfieswhere
By
theassumption
onfor and
By
Theorem3.1,
we conclude thatun(0) s
C for some constantC,
whichyields
a contradiction to theassumption.
STEP 3. There exists a
positive
constant C such thatand for
In
[CLn],
we haveproved
that un has thefollowing representation
Thus,
we haveBy Step 2,
the firstintegral
can be estimatedby
For the second
integral,
we haveCombined these two estimates
together,
we haveSet Then
wn (x)
satisfiesSince for some constant
C4, by
Harnackinequality,
for any a >1,
there exists apositive
constantCS
=C5 (a)
such thatHence, Step
3 isproved.
STEP 4. For any s > 0 there exists R =
R (~)
> 0 such thatfor x I
>Rs
andlarge
n.Step
4 will beproved by
contradiction.Suppose
there exist apositive
number so > 0 and xn , yn with
--- --- -.
such that Let
Then vn
satisfieswhere
By Step 2,
For we have
By Step
3 and the Hamackinequality (3.9),
is bounded inBy
the
elliptic estimates,
we may assumevn (y)
-~ inW o p (I1~2)
for anyp > 1.
Suppose
there exists asubsequence
of xn(still
denotedby xn )
suchthat >
0,
thenby (3.10)
and(3.11),
we may assume~
Ko(y) weakly
inL~ (I1~2B{0}),
whereKo(y)
satisfiesfor some
positive
constantsC1
1 andC2,
andvo(y)
satisfiesFor any we have
Thus,
the total curvatureApplying Corollary
1.4 in[CLn], vo(y)
in fact satisfies infor
some ,B
ER, where 8 (0)
is the Dirac measure at theorigin,
and the function satisfiesin It is easy to see that
where
o( 1 )
denoteso(1)
-~ 0 as r -~ 0.Thus, putting (3.12)
and the abovetogether,
we haveObviously, 2 - b + 2p
> 0. Since at oo,by
Re-mark
2.2,
there exists no entire solution(3.14)
with the total curvatureequal
to.
Thus,
ityields
a contradiction. Hence we haveproved
as n then
vo(y)
is harmonic inJR2B{0}.
By Step 3,
By
Liouville’stheorem,
we havewhere both ao and C are constant. Since
vo (y)
isradially symmetric,
it obvi-ously yields
a contradiction to theassumption. Hence, Step
4 isproved.
STEP 5. Set
and
Define
by
Differentiating (3.15)
and(3.16)
withrespect
to r, we haveThus,
we haveSince
Fn (oo)
>n(2 - b),
set r,~ tosatisfy Fn (rn )
-n(2 - b). Obviously,
rn = +00. For any E >
0, by Step 4,
there exists R =R(s)
> 0 such thatHence,
for for
Since for any n, we have
By Step 1,
we note that theboundary
term at R tends to 0 as n - +oo.By letting n
- first and then E -~ 0 the aboveyields
a
contradiction,
where(2 - b)7r
is used.Therefore,
theproof
of Theroem 1.2 iscompletely
finished. DPROOF OF THEOREM 1.3.
Suppose
un is a sequence of solution of(1.1)
and satisfies theassumption
of Theorem 1.3.By
Remark3.2,
we may assume that either un isuniformly
bounded in anycompact
set or ununiformly
convergesto -oo in any
compact
set ofR 2. By
the the samereasoning
ofStep
1 andStep
2 of Theorem1.2,
there exists a constant C > 0 such thatinequalities
whenever hold.
First,
we want to prove un is bounded inSuppose
the claimis not true. As
before,
we want to prove theasymptotic symmetry
of un,i.e. for any E >
0,
there exists R = > 0 such thatfor y I
=R,
~. Assume the conclusion is not true. Then there exists rn --~ such that
with I
=I xn I
- rn for somepositive
constant Eo > 0. LetThen vn
is bounded in )y Hamackinequality
and satisfies inwhere
By
theassumption
on K and(3.20)
for anywe have
for ~ I
for
large
n. If thenusing (3.21)
and the sameargument
ofStep
4 of Theorem1.2, vn (y)
converges toin vhere ao and
Co
are constant. Sincevo (y)
isradially symmetric,
it
yields
a contradiction.If , then i
uniformly
in anycompact
set ofR’)(0).
Thenuo(y)
satisfiesin
as
where
p
E R and8 (0)
is the Dirac measure. For any ro >0,
Thus either
vo (y)
isregular
at 0 or -as y (
- +oo. Since andvo(y) = a log )y) +0(1)
asjyj
- for somea E
R,
we have 2a - b-2,
i.e.IYI-be2vo(y)
=0(1)IYI-2
asIyl
- +00.Hence,
we canapply
the method ofmoving planes
as in[CL]
and[CLn]
toprove
vo (y)
isradially symmetric
withrespect
to theorigin,
whichobviously yields
a contradiction. Hence theuniformly asymptotic symmetry
of un isproved.
To finish the
proof
of Theorem1.3,
we setand,
As in
(3.19),
we haveFor any - >
0,
let R = belarge
such thatholds for r > R. This
immediately
follows from theuniformly asymptotic symmetry
of un and theassumption
on K.Let rn satisfy Fn (rn )
-7r(2 2013~).
Suppose JJR2 K(x)e2Unex)dx (2 - b)
first. Then we can follow the sameproof
asStep
5 in Theorem 1.2 to obtainwhere
F(oo) == fR2 K(x)e2Unex)dx. Obviously,
the aboveyields F(oo) > 2n(2 - b),
a contradiction.Suppose fR2
>27r(2 - b).
Thenby (3.23),
wehave the reverse
inequality
for for
Integrating
the above andletting n
first and then 8 -0,
we havewhich
implies
Obviously,
ityields
a contradition. Hence the boundedness of un in isproved.
To prove
(1.9),
we may assume un 2013~ uo in for any p > 1.Obviously,
uo satisfies(1.1)
and has a finite total curvature. Inparticular,
Hence,
there existsRo
>0, So
> 0 and no such thatfor all r >
Ro and n >
no.Integratiang ( 1.1 ),
we havefor all ~- and where
Thus,
Applying
the Hamackinequality,
we havefor r >
Ro and n >
no whereC1
andC2
are constantsindependent
of n and r.In
particular,
could be
arbitraily
smallprovided
that r islarge. Thus, (1.9)
follows immedi-ately.
And theproof
of Theorem 1.3 is finished. DREFERENCES
[A] P. AVILES,
Conformal complete
metrics withprescribed
non-negative Gaussian curvaturein
R2,
Invent. Math. 83 (1986), 519-544.[BM] H. BREZIS - F. MERLE, Estimates on the solutions
of 0394u
= v (x) exp u (x) onR2,
Comm.Partial Differential
Equations
16 (1991), 1223-1253.[CL] W.-X. CHENG - C.-M. LI,
Classification of solutions of some nonlinear elliptic equations,
Duke Math. J. 63 (1991), 615-622.
[CLn] K.-S.CHENG - C.-S. LIN, On the
asymptotic
behaviorof
solutionsof
theconformal
Gaussian curvature
equation
inR2,
Math. Ann. 308 (1991), 119-139[CN1] K.-S. CHENG - W.-M. NI, On the structure
of the conformal
Gaussian curvature equationon
R2
I., Duke. Math. J. 62 (1991), 721-737.[CN2] K.-S. CHENG - W.-M. NI, On the structure
of the conformal
Gaussian curvature equationon R2
II, Math. Ann. 290 (1991), 671-680.[CY1] S. Y. A. CHANG - P. C. YANG,
Prescribing
Gaussian curvature onS2,
Acta Math. 159(1987), 215-259.
[CY2] S. Y. A. CHANG - P. C. YANG,
Conformal deformation of metric
onS2,
J. Differential Geom. 27 (1988), 259-296.[H] Z.-C. HAN,
Prescribing
Gaussian curvature onS2,
Duke Math. J. 61 (1990), 679-703.[M] R. MCOWEN,
Conformal
metric inR2 with prescribed
Gaussian curvature and positive total curvature, Indiana Univ. Math. J. 34 (1985), 97-104.Department
of Mathematics NationalChung Cheng University Minghsiung, Chiayi,
Taiwankscheng @math.ccu.edu.tw
cslin @ math.ccu.edu.tw