C OMPOSITIO M ATHEMATICA
D AVID M UMFORD
An analytic construction of degenerating curves over complete local rings
Compositio Mathematica, tome 24, n
o2 (1972), p. 129-174
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129
AN ANALYTIC CONSTRUCTION OF DEGENERATING CURVES OVER COMPLETE LOCAL RINGS
by David Mumford
Wolters-Noordhoff Publishing Printed in the Netherlands
This is the first half of a 2
part
paper, the first of which deals with the construction of curves and the second with abelian varieties. The idea ofinvestigating
thep-adic analogs
of classical uniformizations of curvesand abelian varieties is due to John Tate. In a very beautiful and influ- ential
piece
ofunpublished work,
he showed that if K is acomplete
non-Archimedean valued
field,
and E is anelliptic
curve over whosej-invariant
is not aninteger,
then E can beanalytically
uniformized. Thisuniformization is not a
holomorphic
map:generalizing
the universalcovering
spacen : C ~ E
( =
closedpoints
of anelliptic
curve overC),
but instead is a
holomorphic
map:generalizing
an infinitecyclic covering
03C02 over C:cvl one of the 2
periods
of E. Here you can takeholomorphic
map to meanholomorphic
in the sense of the non-Archimedean functiontheory
ofGrauert and Remmert
[G-R].
But the uniformization 03C02 is moresimply expressed by embedding
E inp2
anddefining
the threehomogeneous
coordinates of
n(z) by
threeeverywhere convergent
Laurent series.The purpose of my work is 2-fold: The first is to
generalize
Tate’sresults both to curves of
higher
genus and to abelian varieties. Thisgives
a very useful tool for
investigating
the structures atinfinity
of the moduli spaces. Itgives
for instance an abstractanalog
of the Fourier seriesdevelopment
of modular forms. Our work hereoverlaps
to some extentwith the work of Morikawa
[Mo]
and McCabe[Mc] generalizing
Tate’suniformization to
higher-dimensional
abelian varieties. The second pur-pose is to understand the
algebraic meaning
of these uniformizations.For
instance,
in Tate’sexample,
03C0 defines notonly
aholomorphic
map but also a formalmorphism
from the Néron model ofG.
to the Néronmodel of E over the
ring of integers
A c K. And from analgebraic point
of
view,
it is very unnatural to uniformizeonly
curves over thequotient
fields K of
complete one-dimensional rings
A : one wants to allow A tobe a
higher-dimensional
localring
aswell, (this
is essential in theapplica-
tions to moduli for
instance).
But when dim A >1,
there is nolonger
any
satisfactory theory
ofholomorphic
functions and spaces over K.In this
introduction,
1 would first like toexplain (in
the case K is adiscretely-valued complete
localfield)
what toexpect
for curves ofhigher
genus. We can do this
by carrying
a bit further theinteresting analogies
between the
real, complex
andp-adic
structures ofPGL(2)
asdeveloped recently by Bruhat,
Tits and Serre:(A)
real case:PSL(2, R)
actsisometrically
andtransitively
on the upperf plane
and theboundary
can be identified withRP’ (the
realline, plus ~):
(B) complex
case:PGL(2, C)
actsisometrically
andtransitively
on theupper
2-space 1 H’
and theboundary
can be identified withCP1:
1 The action of SL(2, C) on H’ is given by:
(C) p-adic
case:PGL(2, K)
actsisometrically
andtransitively
on thetree 0394 of
Bruhat-Tits, (whose
verticescorrespond
to thesubgroups gPGL(2, A)g-1,
and whoseedges
havelength
1 andcorrespond
to thesubgroups gBg-1, B = 1 (a bd)|a,b,c,d~A,c~m, ad~m} modulo A*)
and the set of whose ends can be identified with
Kpl (for details, cf. § 1,
below and Serre[S ]) :
In
A,
for any vertex v the set ofedges meeting v
isnaturally isomorphic
to
kPl,
theisomorphism being
canonical up to an elementof PGL(2, k) (where k
=A/m).
In the first case, if r c
PSL(2, R)
is a discretesubgroup
with noelements of finite order such that
PSL(2, R) jh
iscompact,
we obtainKoebe’s uniformization
of an
arbitrary compact
Riemann surface X ofgenus
2.In the
second,
if r cPGL(2, C)
is a discretesubgroup
which actsdiscontinuously
at at least onepoint
ofCP’ (a
Kleiniangroup)
andwhich moreover is free with n
generators
and has nounipotent
elementsin
it,
thenaccording
to a Theorem of Maskit[Ma],
r is a so-calledSchottky
group, i.e. if 0 = set ofpoints of CP1
where r acts discontinu-ously,
then Q is connected and up tohomeomorphism
weget
a uniformization:In
particular 03A9/0393
is acompact
Riemann surface of genus n and for asuitable standard basis al’ ..., an,
b1, ..., bn
of03C01(03A9/0393), 03C0
is thepartial
covering corresponding
to thesubgroup
N = least normal
subgroup containing
a1, ···, an .The uniformization n is what is called in the classical literature the
Schottky
uniformization. It is the one which hasa p-adic analog.
In the third case, let r c
PGL(2, K)
be any discretesubgroup
consist-ing entirely
ofhyperbolic
elements2.
Then Ihara[I] proved
that r isfree: let r have n
generators. Again,
let 03A9 = set of closedpoints of PK
where r acts
discontinuously (equivalently, Q
is the set ofpoints
whichare not limits of fixed
points
of elements ofF).
Then 1 claim that there is a curve C of genus n and a
holomorphic isomorphism:
Moreover
0394/0393
has a very niceinterpretation
as agraph
of thespecializa-
tion of C over the
ring
A. In facta)
there will be a smallestsubgraph (0394/0393)0
c4 /r
such thatwill be finite:
b)
C will have a canonicalspecialization C
overA,
whereC
is asingular
curve of arithmetic genus n made up from
copies
ofpi
with a finitenumber of distinct
pairs
of k-rationalpoints
identified to formordinary
double
points.
Such a curveC
will be called ak-split degenerate
curveof
genus n.
c) C(K),
the set of K-rationalpoints
ofC,
will benaturally isomorphic
to the set of ends of
4 /r; C(k),
the set of k-rationalpoints
ofC,
will benaturally isomorphic
to the set ofedges
of4 /r
that meet vertices of2 If K is locally compact, this is equivalent to asking simply that .h has no elements of finite order, since suitable powers of a non-hyperbolic element not of finite order must converge to the identity.
(0394/0393)0 (so
that thecomponents
ofC correspond
to theedges
of0394/0393 meeting
a fixed vertex of(4 /r)o
and the doublepoints
ofC correspond
to the
edges
of(4 /r)o ) ;
andfinally
thespecialization
mapis
equal,
under the aboveidentifications,
to the map:which takes an end to the last
edge
in the shortestpath
from that endto
(0394/0393)0.
EXAMPLES. We have illustrated a case where the genus is
2, C has
2components,
each with one doublepoint
andmeeting
each other once:Because all the curves C which we construct have
property (b),
we referto them as
degenerating
curves. Our main theoremimplies
that every suchdegenerating
curve C has aunique analytic
uniformization n :03A9/0393
C.Next 1 would like to
give
an idea of how I intend to constructalgebraic objects
whichimply
the existence of theanalytic
uniformization n, which express the way theanalytic
mapspecializes
overA,
and which willgeneralize
to the case dim A > 1. Given adiscretely-valued complete
local field
K,
one has:a)
thecategory
ofholomorphic spaces X
overK,
in the sense e.g. of Grauert and Remmert[G-R],
b)
thecategory
of formalschemes X
overA, locally
oftopological
finite
type
overA,
withm(!) fI’
as adefining
sheaf of ideals.There is a functor:
from the
category
of formal schemes to thecategory
ofholomorphic
spaces
given
as follows:i)
as apoint
setxan ~
set of reduced irreducible formal subschemes Z c !!l’ such that Z is finite overA,
butZ 4=
the closed fibre!!l’ 0;
ii) if 0 : xan ~
Max( ) = (closed points
ofx)
is thespecialization
map Z H Z n
0,
then for all U cX affine
open,Ø-1(Max U)
= Vis an affinoid subdomain of
!!l’an
with affinoidring 0393(U, (9x).
According
to results ofRaynaud,
thecategory
ofholomorphic
spaces looks like a kind of localization of thecategory
of formal schemes withrespect
toblowings-up
of subschemes concentrated in the closed fibre.In
fact,
he has proven that thecategory
ofholomorphic
spacesadmitting
a finite
covering by
afhnoids isequivalent
to this localization of thecatego-
ry of formal schemes of finite
type.
Whathappens
in our concrete situationis that the
holomorphic
spaces Q and C both have canonicalliftings
intothe
category
of formal schemes and theanalytic
map n : Q - C is inducedby
a formalmorphism.
For the uniformization of abelianvarieties,
dis- cussed in the 2nd paper of thisseries,
thelifting
turns out not to be canoni-cal ; however,
a whole class of suchliftings
can besingled
out, which isnon-empty
and for which n lifts too. Thus the whole situation is lifted into thecategory
of formal schemes where it can begeneralized
tohigher-dimensional
baserings
A. Let me illustrate thislifting
in Tate’soriginal
case of anelliptic
curve. First ofall,
what formal scheme overA
gives
rise to theholomorphic
spaceA£ - (0) = Gm, K?
If we take theformal
completion
of thealgebraic
groupG.
overSpec (A),
the holo-morphic
space that weget
isonly
the unit circle:If we take formal
completion
ofRaynaud’s
’Néron model’ ofGm
overSpec (A) (cf. [R]),
weget
thesubgroup:
To
get
the fullGm, K
start withPl
xSpec (A).
Blow up(0), (~)
in theclosed fibre
Pl;
then blow upagain
thepoints
where the 0-section and oo-section meet the closedfibre; repeat infinitely
often.(See figure
onnext
page.)
The result is a scheme
P~, only locally
of finitetype
overSpec (A).
If we omit the double
points
of the closedfibre,
weget Raynaud’s
’Néron model’.
However,
if we take the wholeaffair,
theholomorphic
space associated to its formal
completion
isGm, K .
On the otherhand,
the Néron model of E over
Spec (A)
will have a canonical’compactifica-
tion’ : it can be embedded in a
unique
normal scheme é proper overSpec (A) by adding
a finite set ofpoints.
It will look like this(possibly,
after
replacing K by
a suitablequadratic extension):
tf will in fact be
regular. Finally,
theanalytic uniformization
which wedenoted n2 will come from a formal étale
morphism
fromP~
to ewhich
simply
wraps the infinite chain in the closed fibre ofP 00
aroundand around the
polygon
which is the closed fibre of . We can now statefully
our main result:For every
Schottky
group r cPGL(2, K),
there is a canonical formalscheme 9
over A on which r actsfreely
and whose associated holo-morphic
space is the open set 03A9 cpi.
There is a one-onecorrespondence
between
a) conjugacy
classes ofSchottky
groupsr,
andb) isomorphism
classes of curves C over K which are the
generic
fibres of normal schemes W over A whose closed fibreC
is ak-split degenerate
curve, set upby requiring
thatYIF
isformally isomorphic
to W.Some notation
Pl = projective
line over KKP1 =
K-rationalpoints of PK’ = K+ K- (0, 0)/K*
u, v> =
modulegenerated by
u, vR(X)
= field of rational functions on anintegral
scheme X.=
formalcompletion
of a scheme X over acomplete
localring A, along
its closed fibre.1. Trees
Let A be a
complete integrally
closed noetherian localring,
withquotient field K,
maximal ideal m and residue field k =Alm.
LetS’ =
Spec (A), 9,1
=Spec (K)
andSo
=Spec (k):
We are interested in certain
finitely generated subgroups
ofPGL(2, K)
that we will call
Schottky
groups. First of all define amorphism:
by
Here and below we will describe elements of
PGL(2) by
2 x 2matrices,
considered modulo
multiplication by
ascalar,
without further comment.be
represented:
PROOF. On the one hand:
Conversely, suppose t-1(03B3)
= v E m, and let the matrix Crepresent
y.Then det C = v -
(Tr C)2
and the characteristicpolynomial
of C isBy
Hensel’slemma,
this has 2 distinct roots in K of the formThen y is also
represented by
the matrix C’ -Clu -
Tr C witheigenvalues
1 and
vlu’
E m. Therefore C’ has therequired
form.DEFINITION
(1.2).
The elementsy E PGL(2, K)
such thatt-1(03B3)~m
will be called
hyperbolic.
From the lemma it follows
immediately
that if y ishyperbolic,
then yas an
automorphism
ofP,
has 2 distinct fixedpoints
P andQ,
both rational overK,
and such that the differentialdylp
= mult.by
p inTp
(the tangent
space toPl
atP), ,u
E m, whiled03B3|Q =
mult.by ju-’;
P iscalled the attractive
fixed point
of y andQ
therepulsive fzxed point.
DEFINITION
(1.3).
ASchottky
group r cPGL(2, K)
is afinitely generated subgroup
such that every y Er, 03B3 ~ e,
ishyperbolic.
These are
probably
the most natural class of groups to look at.However,
there is aparticular type
which is easier to prove theorems about and which include allSchottky
groups in the case dim A = 1:DEFINITION
(1.4). A flat Schottky
group r cPGL(2, K)
has the extraproperty
that if 1 cKP’
is the set of fixedpoints
of the elements y Er,
then for anyP1, P2, P3, P4 E E, R(Pl , P2 ; P3 , P4)
or its inverse is inA,
i.e. the cross-ratio R defines amorphism
from toP1.
The construction of flat
Schottky
groups is not so easy and wepostpone
thisuntil §
4. For the timebeing,
wesimply
assume that one isgiven.
The structure of
PGL(2, K)
and of r is bestdisplayed, following
themethod of Bruhat and Tits
[B-T] by introducing:
0394(0) ~ {set of
sub A-modules M cK+ K,
M free of rank2,
modulo the identification M - À .M,
03BB EK*, (the image {M}
in0394(0)
of amodule M will be called the class of
M)}
~
{set
of schemesP/,S
withgeneric
fibrepi,
such that P ééP1S,
modulo
isomorphisml.
These sets will be identified
by
the mapThis is
easily
seen to be abijection
under which the set of A-valuedpoints
of P
equals
the set of elements x ~M-mM,
modulo A*.Intuitively,
P isthe scheme of one-dimensional
subspaces
of the rank 2 vector bundle M.DEFINITION
(1.5).
If{M}
e0394(0),
we denote thecorresponding
schemePIS by P(M).
Note that
PGL(2, K)
acts on0394(0):
Then the class
{X(M)} depends only
on theimage {X}
of X inPGL(2, K)
and on the class{M}.
The stabilizer of the module A+A is:
PGL(2, A)
= elements ofPGL(2, K) represented by
matricesand the stabilizers of the other modules M are
conjugates
ofx .
PGL(2, A) · x-l
inPGL(2, K).
Moreover
PGL(2, K)
actstransitively
on0394(0),
so0394(0)
can benaturally
identified with the coset spacePGL(2, K)/PGL(2, A).
Less obvious is the fact that any 3 distinct
points
xi , x2 , X3 EKP’
determined
canonically
an element of0394(0):
letw1, w2, w3 ~K+K
behomogeneous
coordinates for xi , x2 , X3. Then there is a linearequation:
a1w1+ a2w2+a3w3 = 0, unique
up to scalar. Let M =03A33i=1
A · aiwi.The class of
multiples {M}
of M is determinedby the xi
alone. We willwrite this class as
{M(x1,
x2 ,x3)}.
Unlike the case where dim A =
1,
the full set0394(0)
is rather unmanage- able. We need to introduce theconcept:
DEFINITION
(1.6). {M1},{M2} ~ 0394(0)
arecompatible
if there exists a basis u, v ofMl,
and elements 03BB EK*,
oc E A such that03BBu,
03BB03B1v is a basisof M2, (Mi representatives
of{Mi}).
It is easy to check that this definition is
symmetric
and that theprincipal
ideal
(oc)
isuniquely
determinedby (Mi )
and{M2}.
Since(03B1)
measuresthe ’distance’ of
{M1}
from{M2},
we write:Moreover,
when dim A =1,
everypair {Ml}, {M2}
iscompatible.
IfMi’
arerepresentatives
of the classes{Mi}
such thatwe call
Mi , M2’ representatives
in standardposition.
Now
then,
let0394(0)0393 =
set of classes{M(x1,
X2,x3)},
where Xl, X2, X3 EIl
1 = set of fixed
points
of elements of r.The flatness of the
Schottky
group r isobviously equivalent
to th(property:
This now
gives
us :PROPOSITION
(1.7). Any
2 classes{M1}, {M2} ~ 0394(0)0393
arecompatible.
PROOF. First note the
LEMMA
(1.8). If
Xl’ x2 , X3, X4 Epi
haveproperty (*),
thenfor
somei, j ~ {1, 2, 3},
with i i=j, {M(x1,
X2,X3)1 = {M(xi,
Xi,x4)}.
PROOF. Let Wi be coordinates for xi as in
(*).
Then if al anda2 ft
m,one checks that
M(x1,
x2 ,X3)
=M(Xl’
x2 ,X4);
ifal ft
m, a2 E m, thenM(x1,
x2 ,x3) = M(x2,
x3,X4);
and if al E m,a2 ft
m, thenNow let
{M1} = M(Xl,X2,X3)’ {M2} = M(Yl, Y2, Y3).
Choosecoordinates wi for xi and ui for yi such that
Next,
if the ratiosai : bi mod m
inkP’
are alldistinct,
one checksimmediately
that the u ; are relatedby 03BB1u1 + 03BB2u2 + 03BB3u3 =
0 whereÀi
EA, 03BBi ~
m. Thisimplies
thatM2 = (module generated by
theui)
=Ml ,
hence
Ml
andM2
areobviously compatible.
New if theratios ai : hi
mod m are not all
distinct,
then at least one of thetriples (0 : 1), (1 : 0),
(1 : 1)
is different from all threeratios ai : bi
mod m.Permuting
the threewi’s,
we may as well assume that(1 : 0)
does not cocur, i.e.bi 0 m
forall i.
Multiplying
uiby
aunit,
we can normalize it so that now:Now
by
thelemma, {M2} = {M(yi,
yj,x1)}
for some iand j.
The linearequation relating
ui, uj and w, is:Therefore
M( yi,
yj,xl )
is the modulegenerated by
ui , uj and(ai - aj)w1.
Thus ui and wi are a basis
of Ml
and ui and(ai - aj)w1
are a basis ofM2 .
Hence
{M1}
and{M2}
arecompatible.
Q.E.D.
1 claim that for any 3
compatible
classes ofmodules,
there is a multi-plicative triangle ’inequality’ relating
their ’distances’ from each other:PROPOSITION
(1.9).
Let{M1}, {M2}, {M3}
EJ(O)
be distinct but compat- ible. Let(ocij)
=03C1({Mi}, {Mj})
and letbe
representatives
in standardposition.
Thenif
N =M2
+M3,
there existu,vEMl
andîl, À2, À3
c- A such that:In
particular, for
allpermutations i, j,
kof 1, 2, 3, 03B1ij|03B1ik03B1jk.
CLUMSY PROOF. First choose u E
M2
such thatu 1= m . Ml . Secondly
choose i3 E
M11mMl
such that i3 is not in either of the 1-dimensionalsubspaces M2/M2
nmM,
orM3/M3
nmM1
ofM1/mMl.
Lift i3 tov E
Ml.
Then first of all il and vgenerate MllmMl,
hence u and vgenerate Ml. Secondly
u and 03B112v lie inM2
and sinceMl
andM2
arein standard
pcsition,
it is easy to see thatthey
mustgenerate M2. Thirdly,
for
some À1
EA, u + 03BB1v
EM3.
Then sinceMl
andM3
are in standardposition, u+03BB1v
and al 3 v mustgenerate M3.
Now use the fact thatlVl2
andM3
arecompatible:
forsome 03BE
EK*, M2 ~ 03BE· M3
and thispair
is in standard
position.
Thenand one of thèse is not in m .
M2.
Thisimplies that 03BE
eA, 03BE03BB1 = 03B6 ·
03B112,03BE03B113 = ~ ·
03B112,(where 03B6 and ~
eA),
and furthermore thateither 03BE, 03B6
or~ is a unit.
Firstly, suppose 03BE
is a unitbut 03B6
is not. Note that we mayreplace
uby u’ =
u + 03B112v then u’ and 03B112v stillgenerate M2
andu’ + 03BB’1v
and 03B113v
generate M3 where 03BB’1
=03BB1-03B112.
But then03BE03BB’1
-(’Ct12’
where03B6’ = 03B6 - 1
is a unit. Thereforeby
suitable choice of u, we can assume that03B6
is a unit.Secondly,
suppose ~ is a unitbut 03B6
is not. In this case, note thatu + 03BB’1v
and 03B113v stillgenerate M3 where 03BB’1
=03BB1 + 03B113.
And then03BE03BB’1 = 03BE03BB1 + 03BE03B113 = (03B6 + ~)03B112
=(’Ct12 where 03B6’
is a unit. Thus we canalways
assumethat 03B6
is a unit. Then ifÀ2 = Ç . (-1
andÀ3 = ~ · 03B6-1
itfollows that Ct12 =
03BB1 03BB2
and 03B113 =03BB103BB3
henceM2
andM3
aregenerated
as
required.
It followsimmediately
thatM2 + M3
isgenerated by
u andÀ1
v. To evaluate 03B123, note that the 2 modulesM2 ~ À2M3
are in standardposition (since 03BB2u + 03BB103BB2v
is inÀ2M3
but not inmM2 )
and thatÀ2M3
is
generated by 03BB2u + 03BB103BB2v and by 03BB203BB3u hence (03BB2 À3)
=03C1({M2}, {M3}).
Q.E.D.
COROLLARY
(1.10). If M1 ~ M2 ~ 03B112 M1, Mi =3 M3 ~ Ct13M1
arerepresentatives of 3 compatible
classes instandard position,
thenPROOF. In the notation of the
proposition,
bothparts
of(a)
areequiva-
lent to
03BB2 being
aunit;
bothparts
of(b)
areequivalent
to03BB1 being
a unit.This
Proposition
motivates:DEFINITION
(1.11).
A subset0394(0)*
c0394(0)
is linked ifa)
everypair
ofelements
{M1},{M2}~0394(0)*
iscompatible, b)
for everytriple {M1}, {M2}, {M3} ~ 0394(0)*,
if wepick representatives M1 ~ M2, M1 ~ M3
instandard
position,
thenM2 + M3 (which
is a free A-moduleby
theproposition)
defines a class{M2 + M3}
in0394(0)*.
We must check that
0394(0)0393
has both these fineproperties:
THEOREM
(1.12). 0394(0)0393 is
linked.PROOF.
Suppose {Mi} = {M(xi,
yi,zi)l,
i =1, 2, 3,
where all thesepoints
come from E. We saw above that all these classes arecompatible.
Choose
representatives M1 ~ M2, M1 ~ M3
in standardposition,
andchoose
homogeneous
coordinates ui, vi,Wi E Mi
for xi,yi and zi suchthat the linear relation
03B1iui+03B2ivi+03B3iwi
= 0 has theproperty
(Xb
03B2i,
’Yi E A*. SinceM2
~mM1,
one of u2’ v2, or w2 is in the setM1 - mM1. Renaming,
we can assumeU2 ft mM1. Similarly,
we canassume
U3 ft mMl . Next,
theimages u1, v1, Wl
of ul , vl , Wl inMlImm,
are all
distinct,
so one of them is different fromboth u2 and Ù 3. Renaming,
we can assume
fi t =1= fi 2
orfi 3.
Let us construct a module in the class{M(x1,
x2,X3)1 ~ 0394(0)0393.
We must find the linearequation relating
u1, u2, u3: since
fi 1 , fi 2’ fi 3 E M llmM 1
are relatedby
anequation dù 1 + 03B2u2 +iï3
=0,
wherea, /3
EAlm,
and03B2
=1=0,
it follows that ul , u2 , U3are related
by
anequation 03B1u1 + 03B2u2 + u3 = 0,
where03B1, 03B2 ~ A, 03B2 ~ m.
Therefore
On the other
hand,
if we choosegenerators
u, v EMl
as in theprevious Proposition,
it follows thatIf
À2,À3Em,
then sinceM2 + M3 = u, 03BB1v>,
it follows that U2 and U3 have distinctimages u2 ,u3 ~ M2 + M3/m · (M2 + M3).
ThereforeM2 + M3 u2, u3>
whose class is inA(O).
If eitherÀ2
orÀ3
is inA*,
thenM2 ~ M3
orM3 M2
andM2 + M3 equals
eitherM2
orM3 ,
whose class is in
0394(0)0393. Q.E.D.
Linked subsets
A «»
cA(’)
are very niceobjects. They
can be fittedtogether
in a natural way into a tree.TREE THEOREM
(1.13). If 0394(0)*
is a linked subsetof 0394(0),
then0394(0)*
is theset
of
a verticesof
a connected tree0394*
in which aprincipal
ideal(03B103C3)
isassociated to each
edge
03C3 and such thatfor
everypair of
classes{P}, {Q} ~ 0394(0)*, if they
are linked in the treeas follows :
then
PROOF.
First,
let us call{P}, {Q} ~ 0394(0)* adjacent
if there is no{R} ~ 0394(0)*
such that:Join 2
adjacent
classesby
anedge
u and set(03B103C3)
=p({P}, {Q}).
Thisgives
us agraph
in any case.Starting
now with any{P}, {Q},
considerall sequences
such that
By
the noetherianassumption
onA,
there is a maximal sequence of thistype.
Then eachpair {Mi}, {Mi+1}
must beadjacent
and this provesthat
{P}
and{Q} are joined
in ourgraph by
a sequenceof edges.
There-fore the
graph
is connected.To prove that our
graph
is a tree and to prove(*),
itsuffices, by
anobvious
induction,
to prove:Then either
or
PROOF OF LEMMA. Let
Mn-1 ~ Mn , Mn-1 ~ Mn - 2 , Mn-1 ~ M1 be representatives
in standardposition. By
theCorollary (1.10) Mn-1 ~ Mn-2 ~ Mi.
ConsiderMn-2 + Mn.
Since0394(0)*
islinked, {Mn-2 + Mn} ~ T.
Since
{Mn-1}
isadjacent
to{Mn-2}
andMn-2 ~ Mn-2+Mn ~ Mn-1, Mn-2+Mn equals Mn-1
orMn-2; similarly
since{Mn-1}
isadjacent
to{Mn}, Mn-2+Mn equals Mn
orMn-1.
Thus eitherMn-2+Mn
=Mn-1
or, if not, then
Mn
=Mn-2+M2
=Mn-2.
In the first case,Mn/Mn
~mMn-1
andMn-2/Mn-2 ~ mMn-1
are distinct one-dimensional sub- spacesof Mn-1/mMn-1.
But(0) ~ M11M1
~mMn-1
cMn-2/Mn-2 ~
mMn-1,
soMl/Ml
nmMn-1
must be the samesubspace
asMn-2IMn-2
~ m · Mn-1.
ThereforeMi
andMn together generate Mn-1/mMn-1,
hence
they generate Mn-1. By
Cor.(1.10) applicd
to thetriple Mi, Mn-1, Mn
this means thatCOROLLARY
(1.15).
In a canonical way,A (0)
is the setof
verticesof
atree 4r
on which r acts.COROLLARY
(1.16) (lhara).
r isa free
group.PROOF. 1 claim that r acts
freely
ondr .
Infact,
if y er, 03B3 ~
e, has a fixedpoint P,
then P is either a vertex or themidpoint
of anedge.
In thelatter case,
y2
fixes the 2endpoints
of thisedge.
But the stabilizers inPGL(2, K)
of the elements of0394(0)
are the varioussubgroups
Since every y E r is
hyperbolic,
neither y nory2
canbelong
to any suchsubgroup.
Thus r actsfreely
on a tree, hence r itself must be free.Q.E.D.
COROLLARY
(1.17) (Bruhat-Tits). If dim A
=1,
the wholeof 0394(0) is,
in a canonical way, the set
of
verticesof
a tree A on which ïhe whole groupPGL(2, K)
acts.It can be shown further when dim A = 1 that for all y E
PGL(2, K),
either y is
hyperbolic
and has no fixedpoint
onL1;
or y is nothyperbolic
and y has a fixed
point
on A in which case theny2
is in somesubgroup
g·PGL(2,A)·g-1.
For any linked subset
0394(0)*
c0394(0),
letA,
be the associated tree. Wecan add a
boundary
to4*
that has aninteresting interpretation:
let[Where
an end is anequivalence
class of subtreesof 4 * isomorphic
to:two such
being ’equivalent’
ifthey
differonly
in a finite set ofvertices].
Let 1* = 0394* ~ bd,:
this is atopological
space if an open set is a subset U uV,
where U c0394*
is open and V c~0394*
is the set of endsrepresented by
subtrees in U.PROPOSITION
(1.18). a)
There is a naturalinjection
c) If dim A
=1, 0394* = d,
then i is abijection of ~0394
andKpl.
PROOF. Let
{M1}, {M2}, ...
be an infinite sequence ofadjacent
verticesof
4*
which defines an end e E~0394*. Represent
theseby
modules instandard
position:
Then it is easy to check that
n:= 1 Nln
is a free A-module of rank 1 in K+K. If u e nMn
is agenerator,
u defines thepoint i(e)
eKP1.
Notethat
u ~ mM1
and if v eMi
is such that ù ~ v inM1/mMl,
thenwhere
(an)
=03C1({M1}, {M1}). Next,
let e’ be a 2nd end and assumee ~ e’. From
general properties of trees,
it follows that there is aunique
subtree of
0394* isomorphic
to:(we
call such a subtree aline) defining e
at oneend,
e’ at the other. Picka base
point {P}
onthis,
and let its vertices in the 2 directions be{M1}, {M2}, ...
and(Ni), {N2}, .... Represent
theseby
modules instandard
positions:
By
Cor.(1.10),
since03C1({Mk}, {Nk}) = 03C1({Mk}, {P}) · 03C1({P}, {Nk}),
itfollows that P =
Mk + Nk.
Thus if u is agenerator
of nMn
and v is agenerator
of nNn,
then P =u, v).
Inparticular
K· u and K. v aredistinct
subspaces
of K+K. But K · urepresents i(e),
K. vrepresents
i(e’).
Thereforei(e) ~ i(e’).
To prove(b),
note that whenJ* = Ar,
r acts on
4r ,
on8Jr
and onKP1
and i is r-linear. On the otherhand,
any fixed
point
freeautomorphism
y of a tree leaves invariant aunique
line
(its axis)
and it acts on its axisby
a translation. Thus y fixes 2 distinct ends of the tree. In our case, every y~ 0393, 03B3 ~
e, has therefore 2 fixedpoints
inDA,
hence ini(~03940393),
and hencei(~03940393)
contains the 2 fixedpoints
of y inKP1.
To prove(c),
let x EKpl
and let u E K+ K behomogeneous
coordinates for x. Let v E K+K be any vector that is nota
multiple
of u and letM. = u, 03C0nv>,
where(03C0)
= m, the maximal ideal in A. Then{Mn}n~0
is a half-line in the full tree A whose end ismapped by
i to x.Q.E.D.
DEFINITION
(1.19). i(ô4r) ce Kpl
will be denoted I and called thelimit point
set of r.In
fact,
when dim A =1,
it is easy to checkthat f
isprecisely
theclosure of r in the natural
topology
onKP1.
We can link
together
via themap i
several of the ideas we have beenworking
with:PROPOSITION
(1.20).
Let0394(0)* be
any linked subsetof 0394(0),
and letJ*
bethe
corresponding
tree. For any x, y, z E~0394*,
the class{M(ix, iy, iz)l
isin
0394(0)*
andequals
tounique
vertexof 0394*
such that thepaths from
v to the3 ends x, y, z all start
off
ondifferent edges.
PROOF. In
fact,
let the module Mrepresent v,
and let M ~Mx ,
M ~
My,
M ~Mz
berepresentatives
in standardpositions
of M andthe module classes next on the
path
from v to x, y and zrespectively.
Then
ix, iy, iz
arerepresented by homogeneous
coordinates u, v, w E K+ K such thatSince
{M}
is between{Mx}
and{My} in 0394*,
it follows from(1.10)
thatMx+My
= M henceû, v E M/mM
are distinct.Similarly
w is distinctfrom ù and D.
Therefore,
if03B1u + 03B2v + 03B3w
= 0 is the linear relation onu, v, w, it follows that a,
03B2, 03B3~A-m.
ThereforeCOROLLARY
(1.21). Every
vertexof Ar
meets at least 3 distinctedges.
PROPOSITION
(1.22).
Let0394(0)*
be any linked subsetof 0394(0)
and let0394*
bethe
corresponding
tree. Thenfor
any Xl’ x2 , x3, X4 E~0394*, R(ixl, ix2 , ix3, iX4)
E A orR(ixl , ix2 , ix3, iX4)-1
E A.PROOF. Let v be the vertex of
0394* joined
to x1, x2 , X3by paths starting
on different
edges. Represent
vby
M andixl , ix2 , iX3 by
coordinates ul , u2 , U3 E M- mM as in theproof
of theprevious Proposition.
Moreover we can
represent
X4by
coordinates U4 E M- mM too. ThenIn this case,
We can use
Proposition (1.20)
to prove theimportant:
THEOREM
(1.23).
Forall flat Schottky
groupsr, Arlr
isa finite graph.
PROOF. Let 03B31, ···, 03B3n be free
generators
of r and let v be any vertexof dr .
Let ui be thepath in dr
from v toy i(v)
and let S = 03C31 ~ ··· u 6n . S is a finite tree and 1 claim that S maps ontoA,IF.
This isequivalent
to
saying
thatis
equal
tod r .
Note first thatS
is connected. Infact,
if y Er,
write yas a word:
Then a
typical point
ofS
is on thepath
fromy(v)
toyyi(v).
It isjoined
to v
by
the sequence ofpaths:
where
at =
ai anda;l
=03B3-1i(03C3i) = (path
from v to03B3-1i(v)).
Notesecondly
that for every x E03A3,
the endi-1x
of03940393
isactually
an end ofthe subtree
S.
Infact,
if x is a fixedpoint
of y er,
it suffices tojoin
thepoints
by paths
inS.
The result is a line inS,
invariant under y,plus
an infiniteset of spurs one
leading
to each of thepoints ynv.
The 2 ends of this lineare the 2 ends of
A.
fixedby
y and one of these isi - lx.
Thusi -’x is,
in
fact,
an end ofS. Finally,
suppose w is a vertex ofdr - S.
Thenw =