C OMPOSITIO M ATHEMATICA
H ASSLER W HITNEY
On regular closed curves in the plane
Compositio Mathematica, tome 4 (1937), p. 276-284
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by
Hassler
Whitney
Cambridge, Mass.
We consider in this note closed curves with
continuously turning tangent,
with anysingularities.
To each such curve may beassigned
a"rotation
number" y, the totalangle through
whichthe
tangent
turns whiletraversing
the curve.(For
asimple
closed curve,
-y = ± 2n.)
Ourobject
istwo-fold;
to show thattwo curves with the same rotation number may be deformed into each
other,4)
and togive
a method ofdetermining
therotation number
by counting
thealgebraic
number of times that the curve cuts itself(if
the curve hasonly simple singula- rities,
- see Lemma2).
This paper may be considered as a continuation of a paper of H.
Hopf 2);
we assume aknowledge
of the firstpart
of his paper.1.
Regular
closed curves.Ordinarily,
a curve in theplane
is defined as apoint
set withcertain
properties;
but when we allowsingularities,
this modeof definition cannot be used.
(See
footnote3).)
Our first purpose is therefore to define aregular
closed curve.Let E be the Euclidean
plane.
Let E’ be the vectorplane (which
wemight
let coincide withE),
withorigin
0. Let I bethe closed interval
(0, 1). Any
differentiable functionf(t)
withvalues in E
has,
as itsderivative,
a functionf’(t)
=dt
withvalues in E’.
By
aparametrized regular
closed curve, or para- metrized curve forshort,
we shall mean a differentiable functionf(t)
defined in I and with values inE,
such that1) Presented to the American Mathematical Society, Sept., 1936.
2) HEINz HoPF, Über die Drehung der Tangenten und Sehnen ebener Kurven
[Compositio Math. 2 (1935), 50--62].
277
The first two conditions are the conditions for the curve to be
closed;
the last condition makes t a"regular parameter".
Toany such
f
therecorresponds
aunique
differentiable functionf
defined in( -
oo,oo),
such thatand
conversely.
It is natural to call two
parametrized
curvesequivalent
if onecan be obtained from the other
by
achange
ofparameter (pre- serving orientation).
The exact definitionis : f and
g areequivalent ( f ·v g)
if there exists afunetion I(t)
in(- 00, oo )
whose first derivative is continuous andpositive,
and is such thatObviously f - f, 1 rooJ
gimplies
g -f,
andf -
g and g - himply f -
h. Hence theparametrized
curves fall intoclasses;
we call each of these a
regular
closed curve, or curve for short.With any curve C is associates many
(equivalent) parametri-
zations
f.
LetC
be thecorresponding
set ofpoints
in theplane
E
(all points f (t)) .
C isby
no means determinedby C 3).
Given any
C,
aparametrization
g may be chosen so thatIg’(t)1
is constant, that
is,
so that theparameter
is a constant times the arclength.
To prove
this,
setL =
L (C)
is thelength
of C. Asf ’(t)
*- 0,L (t )
is a differentiableincreasing function;
hence we may solve L. 8 =L (t)
for t,giving t --=:= il (s).
The derivativeil’(s)
is continuous andpositive. As f is
periodic,
hence
1](8+1) == 1](8) + 1.
Therefore3) Let C be the unit circle in E ; then for each integer n 0 there is a corres- ponding curve Cn with
Cn
= C, determined by letting f(t) traverse C in the po- sitive sense n times while t runs over I. Again, if we take an ellipse and pull theends of the minor axis together till they are tangent, then there are four cor-
responding curves, in each of which the corresponding f(t) traverses each point but one of the ellipse only once.
is a
parametrization
of C.Moreover,
If
h is anyparametrization with 1 h’(t)1 = k,
then k = L andh(t)
=g(t-f-a) for
some constant a. -First,
as h,-....J g, there is an q such thath(t)
=fl(q(t)) .
Aswe have
and k - L. Hence
q’(1)
= 1, and7î(t)
= t + a.Let
fo
andf,
beparametrized
curves. We say one may bedeformed
into the other iffu(t)
may be defined for 0 u 1 such that it is continuous in both variables for0
t 1,o u
1, and eachf u
is aparametrized
curve.If fo and f1
areparametrizations of C,
then one may bedeformed
into the other within
C,
thatis,
we can make eachlu
aparametri-
zation of C.
To prove
this, say fl(t) ==fo(,q(t».
Setfor 0
u
1. ThenrJo(t)
= t,rJ1(t) = q(t ),
so that10
andfi
bear the proper relation to
fo
andfI.
Aseach
f u is
aparametrized
curveequivalent
tofo.
We say C may be deformed into C’ if some
parametrization
of C may be deformed into one of C’.
By
the above statement,this is
independent
of theparametrizations
chosen.2. The
deformation
theorem.The
following
lemma is fundamental in this section.LEMMA 1. Let
f’(t)
be a continuous vectorfunction
inI,
suchthat
f’(t)
# 0.If
p is apoint of E,
then279 is a
parametrized
curveif
andonly if
This is obvious. The last relation may be stated as follows:
The average value of
f’(s)
is O.Given any
parametrized
curvef,
we define its rotation numbery(f)
as the totalangle through
whichf’(t)
turns as t traverses I.The function
f*(t)
=If’(t)
is a map of I into the unitcircle;
I f’(t) 1
y(f)
is 2n times thedegree
of this map.(See Hopf.
loc.cit.,
le,and our
equation (11).)
If f may be deformed
into g, theny(f) = y(g).
For
y(f.)
is continuousin u,
and is anintegral multiple
of2n; hence it is constant.
Hence, by 1,
we may definey(C)
fora curve C as
y(f}
for anyparametrization f
of C.THEOREM
1 4).
The curvesCo
andCI
may bedeformed
into eachother
if
andonly if y(Co)
=y(C1).
One half of the theorem was
proved
above.Suppose
now thaty(Co} = y ( C1 )
= y. Let go andfi
beparametrizations
ofCo
andCl
such thatSet
this deforms the
parametrized
curve go into one gl. Setf o
= gl;then
1 f 0 ’l I = I g Ll.
We must deformfo
intofi .
The
proof
runs as follows. We consider themaps fô
andf,
of Iinto the circle K of radius
LI. They
are both ofdegree 2013 ;
henceone map may be deformed into the
other,
sayby
the mapshu.
We alter each
h. by
a translation to obtain a mapfû
whoseaverage lies at
0;
these functions then define therequired deformation,
at least ify #
0.We
begin by defining
the vector functionthis
gives
anangular
coordinate t in K.Suppose
firstthat y
0.By
rotations in theplane
E we may alterfo
andf,
so that4) This theorem, together with a straightforward proof, was suggested to me by W. C. GRAUSTEIN.
f§ (o ) = f§ (o )
=0(o ).
Asf[(t)
lies onK,
we maygive
it anangular
measure
F(t):
(See Hopf.,
loc.cit., la.) Then, by
definition of y,Set
It is clear that
is an
integral multiple
of 2n,Finally,
asy :É
0 and hencehu(t)
passes over allof K,
its average value lies interior toK;
therefore for no t doeshu(t ) equal
theaverage, and
J’(t) *’
0. This proves that eachlu
is aregular
closed curve. As
f.(t)
is continuous in bothvariables,
and itreduces to
fo and fi
for u = 0 and u = 1, it is a deformation offo
intof 1,
asrequired.
Suppose
now that y = 0. If we alterFu(t)
so that it is constantfor no u, then
again J’(t) =F
0, and the aboveproof
will hold.Choose a
to
for whichF1(tO) =F
0, and deformFo(t)
in a smallneighborhood of to
intoF1(t)
in thisneighborhood;
now deformthe new
Fo
intoFi by
the processgiven
above. Then(as Fu(O) == 0)
noF.
is constant.3.
Crossing points of
curves.Let f( t)
be aparametrized
curve.Let p
be apoint
of theplane.
If there are
exactly
two numbers tl,t2,
such thatand
if f" (t,) and f’(t,)
areindependent
vectors, we call p a(simple )
crossing point
of the eurve. This isevidently independent
of the281
parametrization.
If the curve has nosingularities
other than afinite number of
simple crossing points,
we say the curve is normal.LEMMA 2.
Any
curve may be made normalby
anarbitrarily
small
deformation.
Given e > 0, cut I into intervals
Il, ..., Iv
so small that eachcorresponding
arcAi = f (Ii)
is of diameter c, and thetangents
at different
points
ofAi
differby
at most 8.By
a small defor- mation we mayclearly
obtain arcsA’.
such that neither end ofany A’
touches otherpoints
of the curve. Now forany i and
it is easy to
replace A by
an arcA’.’ arbitrarily
near it and with the same ends so thatA;’
cutsAi
insimple crossing points only5).
Alter thus
A’
in relation toA";
thenA 3
in relation toA i;
thenA 3
in relation to
A 2, altering
it soslightly
that its relation toA 1
isnot
impaired,
etc.Let
f
be aparametrized
curve, and letC
be thecorresponding
set of
points f(t)
in theplane.
We sayf
has an outsidestart1np, point.
if there is a line ofsupport
toC 6) containing f( 0).
Let
f( t1) = f(t2), 11 t2,
be acrossing point.
If the vectorsf’(tl) and f’{t2)
are oriented relative to each other in theopposite
manner to the
(fixed)
x- and y-axes, we say thecrossing point
is
positive; otherwise, negative 1).
If we setg{t) = f(t+ -r)
withtl 7: t2,
then the abovecrossing point changes
itstype.
Corresponding
to any normalparametrized
curve are the numbersThese may be found
by following
the curve from itsstarting point,
andwatching
the intersections with thepart
of the curvealready
traversed.THEOREM 2.
If f
is a normalparametrized
curve with an outsidestarting point,
thenI f
the axes are moved so that the x-axis is the lineof support
at5) The proof is shnplified by first replacing f(t) by a function g(t) 1;ith con-
tinuous second derivatives. The lemma is contained in Theorem 2 of H.WHITNEY, Differentiable manifolds [Annals of Math. 37 (1936)]. (ive replaee I by the unit
circle M and use (b) of the
theorem. )
6) That is, a straight line touching C and having each point of C on it or on
a single side of it.
7) An example of a positive crossing point is giyen in Fig. 2.
f( 0)
and the curve is on the sa1ne sideof
this line as thepositive y-axis,
then ,u = + 1 or - 1according’
asf’ (0 )
is in thepositive
or
negative
x-direction.In
particular,
if the curve has nosingu- larities,
then y = rb 2Jc, which is the,,Um-
laufsatz".Let T be the
triangle
of allpairs
ofnumbers
Let
l(t1, t2)
be the smaller oft2
-t1
and(1 + il) - t2 -
Sety is continuous in
T,
and is 0 at(t1, t2 )
if andonly
if tlt2 (but not t1 = 0, t2
=1),
andf (t1 ) = f (t2 ),
i.e. if andonly
iff{tl)
is a
crossing point 8).
Fig. 2. Fig. 3.
Take any
crossing point
p= f(SI)
=f(s,);
suppose it ispositive.
As 81 82’ P =
(si, 82)
is not on thehypothenuse
of T. Asf(o)
is an outside
point,
it isobviously
not acrossing point;
hencej(O) *’I(t)
for 0 t 1, and P is on neither side of T. AsP -# (0,1),
it follows that P is interior to T. Choose numberst1, ti
very close to si, andt2, t2
very close to s2, so that8) This function replaces the function /(SI’ 82) of Hopf (p. 54). It will be seen
that _BT = ¿BT+ - A’’ is the algebraic number of times that T covers 0 under iy (see footnote 10».
283
and
f{t1), f(t’), f(t2)1 f(t§)
areequidistant
from p.Let
Q
be therectangle
in Tcontaining P,
with coordinates(tl, t2),
etc. It iseasily
seen that if we run aroundQ
once in thepositive
sense, thecorresponding y
runs around 0 once in thepositive
sense. Forrunning
around each side ofQ
turns thevector 1p through
anangle
ofapproximately 2 (see
thediagram);
hence it turns, in
all, approximately
2n; but it turns anintegral multiple
of 2yr, and henceexactly
2n9).
If thecrossing point
isnegative,
the result isobviously -
2n.Let
Pi,
...,Pm
be thepoints
of Tcorresponding
tocrossing points,
and letQI’
...,Q m
becorresponding rectangles enclosing them,
no two of which have commonpoints.
Cut the rest of Tinto
triangles Q m+Í’ ..., Qr.
If we run around theboundary
ofany
Qm+Í’ 1p
runs around 0 zero times1°).
To showthis,
considerthe vector
1J!* = 1:1.
This is definedthroughout Qm+i’
and itslvi
values are on the unit circle. Hence an
angular
coordinate may bedefined, giving
theposition
ofy* throughout Qm+i (see Hopf,
loc.
cit., lb ).
If we run around theboundary
ofQm+i,
theangular
coordinate comes back to its
original value,
andhence y
hasturned around zero times.
Let Cl1’...’ Cll be all sides of
triangles
orrectangles
in T.Let Cl1’ ..., Clk be those
lying
on theboundary
B ofT,
orientedthe same as
T ;
theremaining
oci are orientedarbitrarily.
Witheach oc2 we associate a number
99(oci),
theangle through
whichy turns when oci is traversed in the
positive
direction.Let qq(Qi)
be the
angle through which
turns when theboundary
ofQi
is traversed in the
positive direction; similarly
forqJ(T).
NowFor each
lp(Qi)
may beexpressed
as asum (i) :!: q;{(Xj), summing
over the
boundary
lines ofQi ;
when these sums areadded,
thetwo terms
corresponding
toeach aj
interior to Tcancel,
and weare left with the sum over
the oej
on theboundary
of T.1) By choosing the proper degree of approximation, it is easy to make this
reasoning rigorous.
10) Hence, in all cases, cp( Qi) (see below) is the algebraic number of times
that the map y of Qj covers 0.
We have seen above that
Suppose u -
1. IfSi, S2
and H are thepositively
oriented sides andhypotenuse
of T(see Fig. 1),
it iseasily
seen that(See Hopf,
pp. 54-55. Thechange
insign
is causedby
the dif-ference in orientation of
S1
andS,
from that usedby Hopf.)
Hence, using (17)
and(18),
which
gives (15).
If fi = - 1, theonly change
is thatP(Sl) = P(S2) ==
n, and(15) again
follows.(Received December 21th, 1936.)