C OMPOSITIO M ATHEMATICA
P AWEŁ G AJER
Poincaré duality and integral cycles
Compositio Mathematica, tome 98, n
o2 (1995), p. 193-203
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Poincaré duality and integral cycles*
PAWEL GAJER
Mathematics Sciences Research Institute, Berkeley, California, U.S.A.**
Received 23 November 1993; accepted in
final
form 3 July 1994Abstract. We show that the Alexander-Lefschetz duality can be thought of as a homotopy equivalence
between a space of integral cycles and a space of maps into integral cycles on a sphere.
© 1995 Kluwer Academic Publishers. Printed in the Netherlands.
Let M be an orientable manifold of dimension n. For
every k
0 and everycompact polyhedron
A C M - 9M there is the Alexander-Lefschetzduality isomorphism
that
specializes
to the Poincaréduality isomorphism
when aM is
empty
and A = M[7].
In 1956 Dold and Thom
proved
that forevery k
0 and everypolyhedron
Xwhere
AG(X)
is a free abeliantopological
groupgenerated by
thepoints
ofX
[1].
A few years laterAlmgren generalized
this resultproving
that for everyk ) r ) 0
where
ZT (X )
is the group ofintegral
r-dimensionalcycles
on X[2].
Let
r(Sn) = Zr(Sn)
for r > 0 and let0(Sn)
be the connectedcomponent
of 0 inZ0(Sn) (that
is the space of0-cycles
ofdegree
0 onsn). Almgren’s isomorphism implies
that the spacer(Sn)
is aK(Z, n - r).
This observationtogether
with the classical resultgives
forevery k
r 0 anisomorphism
* Research at MSRI supported in part by NSF grant #DMS 9022140.
** Current address: Department of Mathematics, Texas A&M
University,
TX 77843, U.S.A.It is easy to see that if A c M is a deformation retract of an open set U
C M,
then forevery k
r 0Combining
theAlmgren
Theorem with the aboveisomorphisms
weget
thatfor
every k
r 0Thus it is natural to
expect
thatZT(A)
andMap((M,
M -U), (Zr(Sn), 0))
are
homotopy equivalent.
The aim of this note is to construct ahomotopy equiv-
alence
that induces the Alexander-Lefschetz
duality isomorphism (1).
Actually,
we will prove thefollowing
result.THEOREM A.
If
M is a smooth orientablemanifold of
dimension n, thenfor
every r 0 and every
polyhedron
A C M - ~M there is aneighborhood
Uof
A in M and a map
so that
for
everyk
r 0 thehomomorphism
induced
by -1)
is theAlexander-Lefschetz duality isomorphism
In
Appendix
we included aproof
of the classicalisomorphism
where
Hn(X;Z)
stands for the nthsingular cohomology
group of X andAGo(X)
is the connected
component
of 0 inAG(X).
Theproof
is based on the Dold-Thom Theorem and some basic results of
simplicial homotopy theory
and isessentially
different from the classicalproof,
that uses obstructiontheory
andidentifies 7roMap(X, AGo(sn))
with the nth cellularcohomology
group of X.The paper has two
sections,
which is a reflection of the fact that in thecase of zero dimensional
cycles
there are two constructions of themap 03A6
fromTheorem A.
One,
allows the extension of Theorem A to the case where M isa
topological
manifold but has no obviousgeneralization
forhigher
dimensionalcycles. Another,
is done in the context of smooth manifolds andeasily generalizes
to
higher
dimensionalcycles.
Therough
idea of theproof
of Theorem A is to liftZr (M)
to sections of ar(Sn)-bundle
associated with thetangent
bundle of M.The
orientability
of M is shown to beequivalent
to thetriviality
ofthis
bundle.Thereby, identifying
sections of this bundle with the maps from M toZr (Sn).
1 am
grateful
to Blaine Lawson forsuggesting
to me the extension of the smooth case construction to thetopological
case and many very useful com- ments.1. Zéro dimensional
cycles
on atopological
manifoldIn this section we shall describe a
homotopy equivalence
mapfor M
being
atopological
manifold.Actually,
we shallreplace
the spaceZo(X)
of 0-dimensional
integral cycles (with
the flat normtopology) by
the free abeliangroup
AG(X) generated by
thepoints
of X with thecompactly generated topol-
ogy on it
[1]. Zo(X)
andAG(X)
have the same set of elements but differenttopologies. However, they
arehomotopy equivalent.
THEOREM B.
If
M is atopological
orientablemanifold of
dimension n, thenfor
everypolyhedron
A C M - OM there is aneighborhood
Uof
A in M anda map
so that
for
everyk
0 thehomomorphism
inducedby -1)
is the
Alexander-Lefschetz duality isomorphism
Proof.
Let M be a closed orientabletopological
manifold. First we will con- struct a mapIt will have the
property
that for every A C M the restriction of 03A6 toAG(A)
induces a map
for some
neighborhood
U of A in M.Let W be a
neighborhood
of thediagonal
of M x M so the thediagram
represents
thetangent
microbundle TM of M where A : M - W is thediagonal
map and 1rl is the
projection
on the first factor. The Thom spaceTM
of TM is thequotient
M xM/(M
x M -W).
We will denote thequotient
map from M x M ontoTM by
7r.An orientation of M induces a Thom class U E
Hn(03C4M;Z) [4].
Sincethe class U can be
represented by
a map u :TM - AGO (Sn)
that extends toWith every
cycle
c= 03A3nixi
EAG(M)
we can associate afamily
ofcycles
For any c E
AG(M)
we define03A6(c)
as thecomposition
of the continuousmaps
It is easy to see that for every
subspace
A of M and everycycle
c EAG(A)
the map
03A6(c)
is constant zero on acomplement
of someneighborhood
U of Ain M
(U depends
onW).
Thus the restriction of 03A6 toAG(A)
induces a mapIf M is a
manifold,
A is apolyhedron
contained inM,
and U is a smallneighborhood
of A inM,
then U ishomotopy equivalent
to A andThus under the above
assumptions -*
induces forevery k à
0 a homomor-phism
It is easy to see that if A is a
point, 03A6*
is anisomorphism. Hence,
it is also anisomorphism
for Abeing
anysimplex
of atriangulation
of M. In order to provethat
03A6*
is anisomorphism
for anypolyhedron
A C M - OM one uses inductionon the number of the
top
dimensionalsimplices
of Atogether
with theMayer-
Vietoris
argument (note
that03A6*
iscompatible
withMayer-Vietoris sequences).
For details see for
example
theproof
of the Alexander-Lefschetzduality
in[7].
In order to see that
03A6*
coincides with the classical Alexander-Lefschetzduality
map note that
they
coincide for Abeing
asimplex
and then use aMayer-Vietoris
argument
and the induction on the number ofsimplices
of A.2.
Integral cycles
on smooth manifoldsIn this section we
present
aproof
of Theorem A. Forsimplicity
we start fromthe zero dimensional case.
First,
note thatMap(M, Z0(Sn))
can bethought
of as a space of sections of the trivial fiber bundle M x2o(S’)
over M. It tums out that such a bundle isinduced
by
thetangent
bundle of M when M is orientable.Let M be a smooth
(not
necessaryorientable)
manifold of dimension n andlet
PM
be theprincipal O(n)-bundle
associated with thetangent
bundle TM of M. Thedelooped determinant fibration
of M iswhere the action of
O(n)
on0(Sn)
is induced from theone-point compactifi-
cation of the linear action of
O(n)
on Rn. The name Bndet(TM)
isjustified by
the fact that the fibration
where
U(03A9n(0(Sn)))
consists of thecomponents
ofS2n(Zo(Sn))
that cor-respond
to{±1}
under thehomotopy equivalence
z -03A9n(Z0(Sn))
is thePetterson-Stong determinant fibration [6].
The fibration is fiberwisehomotopy equivalent
to the determinantprincipal (Z/2Z)-bundle
of M. If M is an orientablemanifold,
then the determinant line bundle of M is trivial and Bndet(TM)
ishomotopically
trivial.Actually,
we prove thefollowing
result.LEMMA. A smooth
manifold
M is orientableif
andonly if
there is a continuousmap
that is a
homotopy equivalence
onfibers.
Proof. Suppose,
that M is a smooth orientable manifold. The Thom spaceTM
of thetangent
bundle of M can be identified with thequotient
where M
O(n)
oo denotes theinfinity
section ofPM O(n)
Sn.Since M is
orientable,
thetangent
bundle of M has a Thom class that isrepresented
inby
a continuous mapThe
composition
of u with thequotient
mapgives
the mapthat can be extended in a natural way to the map
whose
restriction to every fiber0(TxM)
of Bndet(TM)
coincides with0(t I£M).
Since t is inducedby
the Thomclass,
the restriction of t to every fiberTxM
ofPM O(n)
Sn is a maptx :
Sn ~0(Sn) representing
agenerator
of03C0n(0(Sn)). Hence,
the induced mapis a
homotopy equivalence*.
Suppose,
now that there is a mapthat is a
homotopy equivalence
on fibers. Thanis a fiber-wise
homotopy
trivialization ofHence,
the determinant bundle of Mis trivial as well.
Therefore,
M is an orientable manifold.* This follows from the isomorphisms
Now,
we aregoing
to construct a continuous mapwhere
r(M,
Bndet(TM))
is the group of continuous sections of Bndet(TM).
Choose a Riemannian
metric g
on M and e > 0 so that e is less than theinjectivity
radius of M. Thegeodesic
E-disc centered at x E M will be denotedby Dx(03B5).
For every x E M the
surjective
mapextends to the continuous map
that coincides
with tx
onDz (e)
and sends thecomplement
of this disc to thepoint
atinfinity
o0 ofTx M.
Letbe defined
by
the formulaSince
Z0(TxM)
is atopological
group andFx depends
in a continuous way onx the same is true for ’Px. Thus we
get
a continuous mapNote that T induces the map
The
composition
of cp with T*gives
a mapNote that for any
polyhedron
A c M - OM the restriction of -1) toZo(A)
induces a map
where
Ué(A)
is thee-neighborhood
of A in M. It is easy to see that for 6’sufficiently
smallU03B5(A)
is a deformational retract of A and forevery k
0Using
the samearguments
as in thetopological
case one proves that 03A6 is ahomotopy equivalence.
In order to
generalize
the construction of -1) = T* o ~ tohigher
dimensionalcycles
wereplace
cpby
the mapwhere for k > 0
and
replace
Tby
a mapdefined as follows.
The trivialization map
induces the map
Since both
03A9k0(Sn)
andZk(Sn)
areK(Z, n-k)s, they
arehomotopy equivalent
and any
homotopy equivalence
mapinduces the
following
fiberwisehomotopy equivalence
of fibrationsWe define
03C4k
as thecomposition hk
o03A9k03C4
oHk.
Appendix
The aim of this
appendix
is to prove theisomorphism
where
Hn(X;Z)
stands for the n-thsingular cohomology
group of X.The
following proof
is based on the Dold-Thom theorem and theequivalence
of the
homotopy categories [Top], [0394(Sets)], [A(Gr)], D(K+) of topological
spaces,
simplicial
sets,simplicial
groups, and chaincomplexes
bounded frombelow
respectively [5, 3].
For Cbeing
one of the abovecategories Homc(X, Y)
stands for the set of
morphisms
of C between theobjects X,
Y of C. ThusMap = HomTop.
Let us start
by recalling
some basic definitions.Let
(A*, d*)
be a chaincomplex
The shifted
complex (A*[p], d*[p])
is defined as followsAny
two chaincomplexes (A*, dA), (B*, dB)
induce a cochaincomplex (Hom*
(A*, B*), 03B4*)
so thatand the
coboundary operator
is defined
by
the formulaTwo chain maps
f*, g*: A* ~ B*
arehomotopic
if there is a chain mapso that
Homotopy
is anequivalence
relation and the group ofhomotopy
classes ofchain maps from
A*
toB*
is denotedby 1ToHomK+ (A*, B*).
Astraightforward
consequence of the above definitions is the
following isomorphism
To every
simplicial
abelian group G =(G*, â*, s*)
one canassign
a chaincomplex C* (G)
so thatCn (G)
=Gn
anddn : Cn(G) - Cn-1(G)
isgiven by
the formula
The classical result of Dold and Kan says that
C* : 0394(Gr) ~ K+
induces anequivalence
of theappropriate homotopy categories
Let
AGS(X)
be the free abeliansimplicial
group of thesingular complex S(X)
of X. The chain
complex C* (AGS(X))
isnothing
but thesingular
chaincomplex
of X. In the
sequel
we will denote itby C*sing(X).
Let
Z*
denote a chain(simplicial) complex
so thatand all
boundary (face
anddegeneracy) operators being
the zero maps. It is easy to see that the cochaincomplex
is
isomorphic
to thesingular
cochaincomplex Csing(X)
of X. From the isomor-phism (2)
it follows thatSince the chain
complexes Z*[n]
andC*(AG0S(Sn))
arequasi-isomorphic 03C00HomK+ (Csing*(X),Z*[n]) ~ 03C00HomK+ (Csing*(X), C*(AG0S(Sn))).
From the fact that
C*: [A(Gr)]
~D(K+)
is anequivalence
ofcategories
it follows that
Every
mapAGS(X) ~ AGoS(S")
is determinedby
its restriction toS(X).
Thus
From the Dold-Thom
isomorphism AGos(sn)
ishomotopy equivalent
toS(AG0(Sn)).
HenceSince for every
simplicial
set T and atopological space X
we have
Finally,
because forevery X
the spaces X and|S(X)|
arehomotopy equiv- alent,
weget
therequired isomorphism
References
1. Dold, A. and Thom, R.: Quasifaserungen und unendliche symmetrische produkte, Ann. Math.
67(2) (1956), 230-281.
2. Almgren Jr., F. J.: Homotopy groups of the integral cycle groups,
Topology
1 (1962), 257-299.3. Gabriel, P. and Zisman, M.: Calculus of Fractions and Homotopy Theory, Springer-Verlag, Berlin, 1967.
4. Hsiang, W. C. and Wall, C. T. C.: Orientability of manifolds for generalised homology theories, Trans. Amer. Math. Soc. 118 (1965), 352-359.
5. May, J. P.: Simplicial Objects in Algebraic Topology, Univ. of Chicago Press, Chicago, IL, 1982.
6. Petterson, R. R. and Stong, R. E.: Orientability of bundles, Duke Math. J. 39 (1972), 619-622.
7. Switzer, R. M.: