C OMPOSITIO M ATHEMATICA
D AVID B. J AFFE
On sections of commutative group schemes
Compositio Mathematica, tome 80, n
o2 (1991), p. 171-196
<http://www.numdam.org/item?id=CM_1991__80_2_171_0>
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On sections of commutative group schemes
DAVID B. JAFFE*
Department of Mathematics and Statistics, University of Nebraska, Lincoln, NE 68588-0323, U.S.A.
Received 25 July 1990; accepted 21 January 1991
©
Introduction
Many
groups inalgebraic
geometry admit additional structure.Suppose,
forsimplicity,
that theground
field is C.Suppose given
a groupG,
and supposegiven
the additional data of a functorG:
«nonsingular
varietiesover C ))° - «groups»
such that
G(’)
= G. Then G defines the structure of atopological
group onG,
which has the strongest
topology
such that for everynonsingular variety T,
and for every~~G(T),
the induced map T - G is continuous with respect to the usualtopology.
Inpractice,
the functor G will often be defined on thelarger
category of allC-schemes,
but this additional information is not needed totopologize
G.For
example,
if X is a propervariety,
thenG = Pic(X)
inherits a Lie group structure fromG(S)
=Pic(X
xS)/Pic(S). (It
may haveinfinitely
many compo-nents.)
But for many groupsG,
the inducedtopology
is either infinite-dimensional, non-Hausdorff,
or both.Nevertheless,
it may be tractable.Shafarevich
[23]
has shown that the groupAut(A")
may bethought
of as aninfinite-dimensional
algebraic
group. We are not aware of any other structure theorems fornon-representable
groups inalgebraic
geometry. There do existnegative characterizations,
such as Mumford’s argument([19]; [6]
lecture1)
that if X is a
complex projective
surface withpg(X)
>0,
thenCHO(X)
is not finitedimensional. As Bloch writes
[5], "algebraic
geometers have dealt with non-representable objects
before(stacks, algebraic spaces)
but these havealways
been in some sense very close to
algebraic
varieties. With thecycle
groups, one encounters for the first timeobjects
which aregeometric
in content and yetjoyously non-representable."
We would like to find structure in such
non-representable
groups. To thisend,
we consider in this paper the
following example.
Let X be a smooth commu-tative group scheme over a
complex variety
S.Identify
X with the induced*Partially supported by the National Science Foundation.
representable
functor from«S-schemes»’
to«groups».
Letf: S -+ Spec C
bethe canonical map. Let G =
f*X,
which is the functor from«C-schemes»’
to«groups» given by
Our main theorem
(6.3)
characterizes the restriction of G to the category of reduced C-schemes.We find that either G is
representable by
acomplex
Lie groupH,
or else it is of the formH x (~~i=1 Ga).
Forexample,
ifS = A1,
andX = Ga X A1,
thenG =
~~i=1 Ga.
· If thegeneric
fiber ofX/S
hasfinitely generated
component group, then so does H. If thegeneric
fiberof X/S
has nounipotent
part, then the infinite-dimensional form does not occur. As a consequence(6.7)
of the maintheorem,
we are able to describe thetopology
which is inducedby
G on thegroup G of sections of
X/S.
The behavior of G on the category of all C-schemes does not admit such a
simple description.
However, in order to prove the maintheorem,
it is necessary tokeep
track of thediscrepancy
between the behavior of G on«reduced
C-schemes»,
and its behavior on«C-schemes».
We do thisby constructing
afunctor
Go,
which isrepresentable (in
the abovegeneralized sense),
and anilimmersion of functors
Go -
G.In the
important
case where S is proper, and X isquasiprojective
overC,
our main theorem is aspecial
case of arepresentability
theorem of Grothendieck([9] 195-13, 221-20).
In thissituation,
Grothendieck’s theoremimplies
thatG is
representable
as a functor on«C-schemes».
In this sense, Grothendieck’s result is much stronger than our main theorem. On the otherhand,
the finitegeneration
of the component group of H cannot be deduced from Grothendieck’s result.It would be
interesting
to look for ananalog
of the main theorem when C isreplaced by
analgebraically
closed field ofpositive
characteristic. It would also beinteresting
tostudy
the sections of non-commutative group schemes.In a later paper, we
hope
toapply
the main theorem togive
adescription
ofPic(X),
where X is ancomplex variety,
notnecessarily
proper. We expect thatPic(X)
will have the formH/D
orH/D
x(~~i= 1 C),
where H is as above and D is afinitely generated subgroup.
1. Generalities and conventions about functors
All
rings
in this paper are commutative. Let k be a field.DEFINITION. A k-functor is a functor
A
morphism
of k-functors is a natural transformation of functors. Anfppf
k-functor is a k-functor which is also a sheaf with respect to the
fppf topology.
Anétale k-functor is a k-functor which is also a sheaf with respect to the étale
topology.
We have:
These three
categories
have the samemonomorphisms,
but differentepimorph-
isms. The
monomorphisms
are functors F such thatF(X)
isinjective
for all k-schemes X.
Depending
on context, the k-functors under consideration may take values in«sets», «groups»,
or«abelian groups».
Modulo set-theoretic
difficulties,
if F is ak-functor,
there exists anfppf
k-functor
Ffppf
and a map F ~Ffppf
which is universal for such maps(cf. [17]
p.
57).
This associated sheaf construction also works for the étaletopology.
Modulo the same
difficulties,
thecategories
of(abelian group)-valued
k-functors, (abelian group)-valued
étalek-functors,
and(abelian group)-valued fppf
k-functors are abelian. Thesecategories
have différent exact sequences.If X is a
k-scheme,
then there is an inducedk-functor,
also denotedby
X andgiven by X(S)
=Homk (S, X).
I ngeneral,
we do notdistinguish
between a schemeand the
corresponding representable functor. Representable
functors arefppf
sheaves.
DEFINITION. A k-functor is discrete if it is
representable by
adisjoint
unionof
copies
ofSpec(k).
One can define an
fppf
C-functorby giving
its value on all affine C-schemes.For a
C-algebra R,
the notationN(R)
meansN(Spec(R)). Also,
the notationNi )
means
N(Spec(C)).
DEFINITION. Let X and Y be k-schemes. Then
Hom(X, Y)
is the k-functorgiven by
T ~Homk(X
x T,Y).
DEFINITION. Let S be a k-scheme. Let X be an S-scheme. Then
Sect(X/S)
isthe k-functor
given by
We have
Sect(X/S)
=f*X,
wheref : S ~ Spec C
is the canonical map.Observe that Hom is a
special
case of Sect:The k-functors
Hom(X, Y)
andSect(X/S)
arefppf
sheaves.DEFINITION. A
morphism 0:
F - G of k-functors is a closed immersion if for every k-schemeT,
and for everymorphism
T ~G,
the inducedmorphism
offunctors F xG T ~ T "is" a closed immersion of schemes.
REMARK 1.1. Let F, G be k-functors.
Let 0:
F ~ G be amorphism. Then 0
is aclosed immersion if and
only
if it is amonomorphism,
and if for every k-schemeT,
and every q eG(T),
there exists a closed subschemeTo
cT,
such that if Y is ak-scheme and
f :
Y ~ T is anyk-morphism,
thenf(~)~F(Y)
if andonly
iff
factors
through To.
One can also consider closed
subfunctors
of agiven
k-functor. Let F be an(abelian group)-valued fppf
k-functor. It is not true ingeneral
that every direct summand of F is a closed subfunctor.Indeed,
this will be true if andonly
if theinclusion 0 F is a closed immersion. This condition holds for every functor we
shall be interested
in,
but not e.g. for thefppf
sheaf associated to the functor defined onk-algebras by
R HR/N(R),
whereN(R)
denotes the set ofnilpotent
elements of R.
Miscellaneous
facts
2022 The property of
being
a closed immersion of functors is stable under base extension.. A closed subfunctor of an
fppf [resp. étale]
sheaf is anfppf [resp. étale]
sheaf..
If (Fi)i~I
are closed subfunctors of a k-functorG,
then so isni., Fi.
. A fiber
product
in«k-functors»
offppf
sheaves is anfppf
sheaf.2. Additive x
algebraic
functorsDEFINITION. An
(abelian group)-valued
C-functor is additive if it is isomor-phic
to thefppf
sheafgiven
onC-algebras by R ~ ~i~IR,
for some set 7. Weshall
always
make the additionalrequirement
that 7 is countable.DEFINITION. An
(abelian group)-valued
C-functor isalgebraic
if it is repre- sentableby
some C-schemeX, locally
of finite type over C.To be consistent with the
literature,
we shouldprobably
call such functorslocally algebraic,
but forbrevity
we do not. We recall thefollowing
theorem:THEOREM 2.1. Let
be
an fppf -exact
sequenceof (abelian group)-valued fppf C-functors.
Assume thatF’ and F" are
algebraic.
Then so is F.DEFINITION. An
(abelian group)-valued
C-functor is additive xalgebraic
if itis
isomorphic
to a functor of the form A x R where A is additive and R isalgebraic.
The two main results of this section are
(2.5),
which asserts that any extension of additive xalgebraic
functors is additive xalgebraic,
and(2.6),
which assertsthat any closed
sub-group-functor
of an additivex algebraic
functor is additive xalgebraic.
There are two kinds of additive x
algebraic
functors.Firstly
there are thosewhich are
algebraic. Secondly
there are those of the form A xG:,
whereG:
denotes the
fppf
sheaf associated to the C-functor X ~~~i=
1r(X, lDx).
Note thatif X is
quasicompact
then:Also, Gâ
may be viewed as thecoproduct
in«fppf C-functors»
ofcountably infinitely
manycopies
ofGa. Any
additive xalgebraic
functor is anfppf
C-functor. The
following
notions make sense for an additive xalgebraic
functor F:2022 whether or not F is
connected;
. the connected component
of
theidentity
ofF;
2022 the component group of F.
If G is an
algebraic functor,
one knows that there existfppf-exact
sequences:and
where
GO
isconnected,
D isdiscrete, A
is an abelianvariety,
andk,
n areintegers.
Furthermore
(see 2.2, below),
the sequence(*) splits.
Forproofs relating
to(**),
see e.g.
([20] 7.2.1, 4.1.3,
3.9(p.553))
and([21]
Theorem16).
We use thesedecompositions repeatedly.
LEMMA 2.2. Let
be
an fppf -exact
sequenceo. f ’fppf C-functors,
whereFo is
additive xalgebraic
andconnected,
and D is discrete. Then(~) splits.
Proof.
The map F - D issplit surjective
as a map of set-valuedfppf
C-functors. Hence
Ext(D, F0) ~ Ext(D(·), F0(·)),
where the latter Ext iscomputed
in«abelian groups».
From(**), above,
one concludes thatFo(.)
is divisible.Hence
Ext(D(.), Fo(-»
= 0. 1:1LEMMA 2.3. Let
be an
fppf-exact
sequenceof (abelian group)-valued fppf C-functors,
in whichV ~
G:
and A is connectedalgebraic.
Then there exists an(abelian group)-valued fppf C-functor
M c F such that the induced map M ~ A isfppf-onto
and suchthat M n V is a
representable
closedsubfunctor of
Jt:necessarily of the form Gka for
some
integer
k.Proof.
There exists a scheme X andmorphisms
p: X ~ A, u: X ~ F such thatp is fppf
and 11: 0 Q = p. Let X3 = X x X x X. There is an induced map U3: X3 -+ Fgiven by
Let X3 denote the
fppf image
of U3. Then X3 is a set-valuedfppf
C-functor.Define a C-functor P
by
the fiberproduct diagram:
Since 0 ~ A is a closed
immersion,
so is V - F. Hence the map P - X3 is aclosed immersion. In
particular,
P is a scheme of finite type over C. HenceV(P) = ~~i=1 r(P, Op),
so the map P ~ V factorsthrough
a finite dimensionalgroup-subfunctor V0 ~ V,
sayV0 ~ G:.
It follows that X3 n V cVo.
Let M = X3+ Vo,
i.e. the set-valuedfppf
subfunctor of F associated to the C- functorgiven
onC-algebras by
We will show that M is in fact a
group-subfunctor.
Forthis,
it suffices to showthat if
Write
(We
omit references toQ.)
We must show thatIn the course of the argument, we may
replace R by
anyfppf R-algebra
S. Weshall do this
repeatedly
withoutadjusting
the notation. Observe that themap X - A
is onto as a map offppf
sheaves.Replacing R by
somefppf R-algebra
S, we may find an elementy1~X(R)
such that03C0(y1-x1-x’2)=0.
Then
y1-x1-x’2
EVo(R). Therefore,
it suffices to show thatSimilarly,
we may find an elementy2 E X(R)
such that03C0(y2-x2-x3)=0.
Itsuffices to show that
y1-y2-x’1 +x’3~ M(R). Similarly,
we may find an elementy3~X(R)
such that03C0(y3-y1-x’3=0.
It suffices to show thaty3-y2-x’1~M(R).
This follows from the definition ofM(R).
Hence M is agroup-valued fppf
C-functor. Moreover, M n V =Vo.
D LEMMA 2.4. Let G be anadditive x algebraic C-functor.
Let H bean fppf
C-functor.
Let k e{0,1,2,..., ~.
Thenany fppf-exact
sequence:splits.
Proof.
In any abelian categoryA,
one can define abelian groupsExt(X, Y)
which
classify equivalence
classes of extensionsof X by Y,
see[7]. Furthermore,
if
arbitrary products
andcoproducts
exist inA,
thenand
Taking W
to be the category offppf
C-functors(with
values in abeliangroups),
we may thus reduce to
showing
thatExt(Ga, G)
= 0. Write G =Go
x D x Vwhere
Go
is a connected group scheme of finite type overC,
D isdiscrete,
andv E
{0, G~a}.
It suffices to show thatExt(Ga, L)
= 0 wheneverL~{G0,
D,G~a.
First suppose that
L~{G0, Dl. By (2.1)
this isequivalent
toshowing
that any group scheme extension ofGa by
such an Lsplits.
In case L =Go
this follows from([22] §8.2, Prop. 2).
The case L = D is left to the reader.Finally
suppose that L =G~a.
We must show that anyfppf-exact
sequence offppf
sheavessplits. By (2.3)
there exists anfppf
C-functor M c F such that M maps ontoG.
and M n L éé
Gà
for someinteger
k. Thus we have anfppf-exact
sequenceof fppf
C-functors:
This sequence
splits.
Hence the exact sequencesplits.
THEOREM 2.5. Let
be
an fppf -exact
sequenceof (abelian group)-valued fppf C-functors.
Assume thatF’ and F" are additive x
algebraic.
Then so is F.Furthermore, f
F’ and F" havefinitely generated
component groups, then so does F.Proof.
Given any list ofpieces
from which F" may be built up from viaextensions,
we may reduce to the cases where F" is one of thosepieces.
Thus wemay assume that
F"~{G~a, G, D}
where G is connectedalgebraic,
and D isdiscrete.
Case I:
F" = G~a.
This case followsimmediately
from(2.4).
Case II: F" = G. Write F’ = I’ x A’ where 7’e
{0, G~a
and A’ isalgebraic.
Wehave
fppf-exact
sequences:and
Assume for the moment that
(FIA’)fppf
is additive xalgebraic.
Writewhere I * E
{0, Gâ 1
and A* isalgebraic.
We obtainfppf-exact
sequences:and
By (2.1),
H isalgebraic. By (2.4), (t) splits,
so F is additive xalgebraic.
Therefore(to
prove CaseII)
it suffices to prove the theorem when F’ ~G~a
and F" is connectedalgebraic.
In that case,
by (2.3),
there is anfppf
C-functor M c F such that M maps onto F" and such that M n F’ ~Gà
for someinteger
k. We have anfppf-exact
sequence:
By (2.1),
we conclude that M isalgebraic. Furthermore,
We have an
fppf-exact
sequence:By (2.4),
this sequencesplits.
Hence F is additive xalgebraic.
Case III: F" = D. Then the map F - F" admits a
splitting
in the category offppf
C-functors(with
values insets).
If F’ has no discrete part, then(by 2.2),
any extension of Dby
F’splits,
so F is additive xalgebraic.
In any case one has anfppf-exact
sequence offppf
C-functors:where D’ is the discrete part of F’. Hence
(F/D’)fpp is
additive xalgebraic.
LetE=(F/D/)fppf.
There exists a subfunctor 1 c E such thatI~{0,G~a}
andEII
isconnected
algebraic.
LetFI
be thepreimage
of 1 in F. Then one has anfppf-exact
sequence:
By (2.4),
this exact sequencesplits.
HenceFI
is additive xalgebraic.
Since(F/F¡)fppf
is connectedalgebraic,
Case III follows from thefppf-exact
sequence:and from Case II. The assertion
regarding
finitegeneration
of componentgroups is left to the reader. El
PROPOSITION 2.6. Let F be a closed
sub-group-functor of
anadditive x
algebraic functor
G. Then F is additive xalgebraic. Furthermore, if
Ghas
finitely generated
component group, then so does F.Proof.
The statementregarding
finitegeneration
of component groups is leftto the reader. We may assume that G is not
algebraic,
so G ~ H x 7 where H isalgebraic
and I ~G:.
FilterI:I1
c12
c c 7 whereIn ~ G:.
LetFn
= F n(H
xIn).
ThenFn
is a closedsub-group-functor of H x In.
LetHn
be thefppf image
of the mapFn ~
H. ThenHn
is a closedsub-group-scheme of H,
andH1 c H2 ~ ···.
Since there is amonomorphism Fn+1/Fn ~ Ga,
and anepimor- phism Fn+1/Fn ~ Hn+1/Hn,
we haveHn+1/Hn~{0, Ga}.
Hence the sequenceH1 c H2
~ ··· must stabilize. It follows that thefppf image F
of the map F - H is a closedsub-group-functor
of H.We have an
fppf-exact
sequence:As F n I is a closed
sub-group-functor
of I, it is clear that F n 7 is additive.By
(2.5),
F is additive xalgebraic.
0COROLLARY 2.7. Let F be an additive x
algebraic functor.
LetFI
andF2
beclosed
sub-group-functors of
F. ThenF1 n F2
is additive xalgebraic.
Proof.
The property ofbeing
a closed immersion of functors is stable under baseextension,
soFln F2 ~ F1
is a closed immersion of functors. SinceFi -
Fis also a closed immersion of
functors,
so isFln F 2 -+
F.By (2.6), Fln F2
isadditive x
algebraic.
03.
Nilpotent
functorsDEFINITION. A
(abelian group)-valued
k-functor F isnilpotent
if it is anfppf
sheaf and if
F(T)
= 0 for every reduced k-scheme T.It would be better to call these functors
infinitesimal,
but that would make thesubsequent terminology excessively bulky.
DEFINITION. A
morphism
03C8: F ~ G of k-functors is a nilimmersion if it is aclosed immersion and if
cp(T)
is anisomorphism
for every reduced k-scheme T.EXAMPLE 3.1. The
fppf
C-functor Ngiven
on affine C-schemesby
is
nilpotent.
The functor N is notrepresentable,
but it may be viewed as a direct limit ofrepresentable C-functors,
where the direct limit is taken in«fppf
C-functors».
A suitable directed system isFor any
C-algebra
R, one may think ofN(R)
as the set of solutions(in R)
of theinfinite system of
equations
where almost all of the variables are
required
to be zero. In this way N may be viewed as a closed subfunctor ofG~a,
but the inclusion N -Gt
is not a grouphomomorphism.
EXAMPLE 3.2. Let M be the
fppf
C-functor whose behavior on affine C- schemes isgiven by: M(R) = (R[x])*/R*.
ThenM(R)
may be identified withTherefore,
as a functor to sets, M may be identified with~~i=
1 N. One may also describe M as the solution functor of a certain infinite system ofequations,
inwhich almost all of the variables are
required
to be zero.Thus,
as in the case of N, M may be embedded as a closed subfunctor ofG:,
but not as a closed sub-group-functor.
The functor M arises in ouranalysis
of group scheme sections:we have
Hom(A1, Gm) = Gm
x M.DEFINITION. A
(abelian group)-valued
C-functor F isnilpotent
x additivex
algebraic
if it is of the form N x U x R where N isnilpotent,
U isadditive,
andR is
algebraic.
LEMMA 3.3. Let
be an exact sequence
of C-functors.
Assume that L is additive xalgebraic
and thatB is
nilpotent.
Then(~)
admits aunique splitting.
Proof.
If L isrepresentable,
it isreduced,
soF(L) ~ L(L)
is anisomorphism,
and hence
(t)
admits aunique splitting.
If L is notrepresentable,
there exists afiltration
L1 c L2
c - - - c Lby representable subfunctors,
such thatL =
(U~i=1 Li)fppf.
For each i, base extendby Li ~
L to obtain an exact sequenceof C-functors:
As
Li
isrepresentable,
this sequencesplits uniquely.
We thus obtain acompatible
system of mapsLi ~
F. These define a mapU~i=1 Li ~
F. Since Land B are
fppf sheaves,
so is F. Hence we obtain a map L - F whichsplits (t).
The
uniqueness
of thesplitting of (~)
follows from theuniqueness
of thesplitting
of the
(t,).
DCOROLLARY 3.4. Let
be an
fppf-exact
sequenceof fppf C-functors.
Assume that F’ isnilpotent
x additive xalgebraic
and that F" is additivex algebraic.
Then F isnilpotent
x additive xalgebraic. Furthermore, if
we aregiven
adecomposition
F’ = N’ x A’ where N’ is
nilpotent
and A’ is additive xalgebraic,
then we obtain(canonically)
adecomposition
F = N’ x Afor
some additive xalgebraic functor
A.Proof.
Write F’ = N’ x A’ where N’ isnilpotent
and A’ is additive xalgebraic.
We have an exact sequence of C-functors:
Since A’ and F" are
fppf sheaves,
it follows thatF/N’
is anfppf sheaf and
that thisexact sequence is
fppf-exact. By (2.5), F/N’
is additive xalgebraic.
We have anexact sequence of C-functors:
By (3.3),
this sequencesplits uniquely.
REMARK 3.5.
Suppose
that one has an exact sequence:of C-functors. Assume that L is additive x
algebraic
and that B isnilpotent.
Does(t) split?
An affirmative answer to this would allow one to conclude that any closedsub-group-functor
of anilpotent x
additive xalgebraic
functor isnilpotent
x additive xalgebraic.
4. Sections of tori
The purpose of this section is to prove
(4.5),
which describesHom(X, Gm),
whereX is a
variety.
This reduces to apurely ring-theoretic problem,
which we nowconsider. The
problem
is to describe the units in thering
A~k B
where k is analgebraically
closedfield,
A is a domaincontaining k,
and B is anyring containing
k. First we consider thespecial
case where B is a domain(4.2),
thenthe case where
Spec(B)
is connected(4.3),
andfinally
the case where B isarbitrary (4.4).
LEMMA 4.1. Let V be an open
subvariety of a
normalprojective variety ,
overan
algebraically closed field
k. LetD1,..., D,
denote the irreducible componentsof
P -
Vhaving
codimension onein .
Then there is a canonicalisomorphism of
thegroup
0393(V, OV)*/k*
with the groupDivo(V) consisting of
thoseformal
7L-linearcombinations D
= al Dl
+ ..- +arDr
with theproperties
that D is Cartier and that(9 f, (D) -- mv.
Proof.
WhenV is nonsingular,
the reader willprobably
agree that the lemma isgeometrically
obvious. In any case, wegive
a formalproof.
LetDiv(V)
denotethe group of Cartier divisors on Y. Let
Weil( V)
denote the free abelian group onthe set of codimension one subvarieties of V. Since V is
normal,
one knowsby ([10] 21.6.9)
that the canonical mapDiv(V) ~ Weil( V)
isinjective.
LetKv
be thefunction field of Y. We have a commutative
diagram
with exact rows:A
diagram
chase shows thatCoker(a) ~ Ker(b)
nKer(c).
DLEMMA 4.2. Let k be an
algebraically
closedfield.
Let A and B berings containing
k. Assume that A is adomain,
and that B is adomain,
or moregenerally
a reduced
ring
such thatSpec(B)
is connected. Let u E AQk
B be a unit. Thenu = a (D b
for
some units a E A and b E B.Proof.
We may assume that A and B arefinitely generated
over k.Suppose
that B is a domain.By localizing
at nonzeroelements,
we mayassume that A and B are
regular.
Let X =Spec(A)
and Y =Spec(B).
Embed X[resp. Y]
as an opensubvariety
of aprojective
normalvariety X [resp. Y].
Notethat if resolution of
singularities
wereavailable,
we could assume thatX
andare
nonsingular.
Apply (4.1)
in three separate cases:We have an
injective map 0: Divo(X)
xDivo() ~ Divo(X
xY).
Tocomplete
theproof,
it suffices to showthat 4J
issurjective.
We first assume resolution of
singularities,
as this makes theproof simpler.
We may assume
that X
and arenonsingular.
Consider an element ofDivo(X
xY).
It may beexpressed
in the form D + E where D is a Cartier divisorsupported
on(X - X)
xY
and E is a Cartier divisorsupported on X
x( - Y).
We know that the
image [D
+E]
of D + E inPic(X x )
is zero. Tocomplete
theproof
it suffices to show that[D]
= 0 and[E]
= o. Thus thecomposite:
is zero and we have to show that the first arrow is zero. It suffices to show that the second arrow is
injective.
This is clear. Theproof (when
B is adomain)
is nowmorally complete.
We
explain
how tobypass
the use of resolution ofsingularities.
Consider anelement of
Divo(X
x).
It may beexpressed
in the form D + E where D is a Weildivisor
supported
on(X - X) x
and E is a Weil divisorsupported
onX
x(Y - Y).
In order toapply
the method which we used whenX
andY
werenonsingular,
it suffices to show that D and E are both Cartier. This willcomplete
the
proof (when
B is adomain).
LetS ~ X x
be( - X) x ( - Y).
LetU
= (X
x) 2013 S.
SinceDiu
does not meetE|U,
we see thatDiu
andEl u
are Cartier.We show that
Dju
is induced from a Cartier divisoron X
via the canonical map U ~X. Certainly
D is thepullback
of a Weil divisorDo
fromX.
It sufficesto show that
Do
is Cartier. Let y E Y be any closedpoint.
Thecomposite:
is an
isomorphism.
HenceDo
=D| x {y}
is Cartier. ThusDiu
is induced from aCartier divisor on
X.
HenceD|U
extends to a Cartier divisorD’ on X
x.
Since(X
xY) -
U has codimension two in ix ,
it follows that D = D’. Hence D is Cartier.Similarly
E is Cartier. Thiscompletes
theproof
when B is a domain.Now suppose that B is not
necessarily
adomain,
but that B is reduced and thatSpec(B)
is connected.Let p1,..., pn
be the minimalprimes
of B. Letx E (A
QB)*.
For each i, let xi be itsimage
in A QB/Pi.
SinceB/pi
is adomain,
we may write
xi = ai ~ bi
for some unitsai~A
andbi~B/pi.
Let=B/p1 x ··· x B/pn.
Since B isreduced,
we have aninjective
mapB ~ . Identify bi
with the element(o, ... , bi, ... , 0) E B, where bi
is in the i th spot.Identify
x with itsimage
in A 0 B. Then(in
A 0B):
Let m c A be a maximal ideal. Let x be the
image
of x in B =(A/m)
~ B. In(A/m)
0B,
we have x =(ci ’ b1)
+ ··· +(en. bn),
for suitable constants cl, ... , cnE k,
all nonzero since the ai are units.Adjusting
theoriginal ai’s
andbi’s slightly,
we may assume that theci’s
are allequal
to one:x = b
+ ···+ bn.
Hencethere exists some b E B which lifts
b1,..., bn.
Suppose
thatV(pi)
meetsV(pj).
The existence of bimplies
thatbi=bj
onV(pJ
nV(:pj).
Hence ai=aj. SinceSpec(B)
isconnected,
a l =··· =an. Hencex=a1 ~ b.
We now
generalize
the lemma to the case where B is notnecessarily reduced,
still
assuming
thatSpec(B)
is connected.COROLLARY 4.3. Let k be an
algebraically closed field.
Let A and B berings
containing
k. Assume that A is a domain and thatSpec(B)
is connected. Let m c Abe a maximal ideal. Then
(A pk B)*
is the direct sumof
the twosubgroups
A*B*and 1
+ (m
0Nil(B)),
whereNil(B)
denotes the nilradicalof
B.Proof.
First we show(I)
that A*B* and 1+ (m
ONil(B)) together generate (A
QkB)*.
Since(by 4.2)
A*B*surjects
onto(A
OBred)*’
it suffices to show thatKer[(A
0B)* ~ (A
OBred)*] ~
A * B* .[1 + (m
ONil(B))].
Evidently
this kernel is 1 +[A
ONil(B)],
so it suffices to show thatLet
Write
Let
Then
Hence
This proves
(I).
Now we show
(II)
that:Indeed,
let x lie in the intersection. Writewhere
u E A*, v E B*,
ai~m,biENil(B). Passing
toA/m,
we conclude that v E k.Similarly,
we conclude that u E k. Then x -1 is anilpotent
elementof k,
so x = 1.This proves
(II).
DAs a final
generalization,
we allow B to bearbitrary.
COROLLARY 4.4. Let k be an
algebraically
closedfield.
Let A and B berings containing
k. Assume that A is a domain. Let m c A be a maximal ideal.. For any
decomposition B=B1
x... xBn,
there is asubgroup:
of (A (8)k B)*,
whereNil(Bi)
denotes the nilradicalof Bi.
lu For any x E
(A (8)k B)*,
there exists adecomposition
B =B,
x ... xB.
such thatx E
03BC(B
1, ...,Bn).
.
If
B hasonly finitely
manyidempotent
elements(e.g. if
B isnoetherian),
we canwrite
B=B1 x ··· x Bn for rings Bi having
connected spectra. Then03BC(B1,..., Bn)=(A (8)kB)*.
COROLLARY 4.5. Let S be a
variety
over analgebraically closed field
k. Thenfor
each choiceof
closedpoint
x ES,
one obtains a canonicaldecomposition of
k-functors :
where F is
representable by
a group schemeof the form Gm x
7Ln( for
some n0)
and 1 is
nilpotent.
The inclusion F ~Hom(S, Gm)
isindependent of
x.Proof.
Let F be thefppf
k-functor associated to the k-functorFo given by
T~
r(S, (Os)*0393(T, (9T)*.
The latter group is asubgroup
ofso F is a subfunctor
of Hom(S, GJ.
It follows from(4.1)
that D =r(S, Os)*/k*
isfree abelian of finite rank. Since k* is
divisible,
the exact sequence:splits.
Choose asplitting.
This choice determines anisomorphism
ofFo
with thefunctor
given by T ~ 0393(T, UT)*
x D. Hence F isrepresentable
as claimed.Suppose
now that T is reduced. We wish to show that the inclusionF(T) - Hom(S, Gm)(T)
issurjective.
For this we may suppose that T is connected and affine. Then(see
e.g.[11] 9.3.13(i))
one knows thatr(S
xT, (OSxT)
=r(S, Us)
Or(T, (9T). Surjectivity
now follows from(4.2).
Finally,
let m cr(S, (9s)
be the maximal idealcorresponding
to the closedpoint
x~S via the map S ~Spec r(S, (9s).
Let 1 be thefppf
subsheaf ofHom(S, G.)
associated to the k-functorgiven by
T ~ 1 +
(m
QNil(0393(T, (OT))).
From
(4.4),
it follows that the canonical mapF ~ I ~ Hom(S, Gm)
is anisomorphism.
DREMARK 4.6. The k-functor
I,
viewed as a functor to sets, admits thedecomposition
I =~~i
1 N(or
I =0),
whereN(R)
is the set ofnilpotent
elementsin a
ring
R(cf. 3.2).
Thus 7 may be embedded as a closed subfunctor ofG~a ,
butnot as a closed
sub-group-functor (unless I=0).
5. Sections of abelian schemes
LEMMA 5.1. Let A be a
complex
abelianvariety.
Let S be avariety. Then for
each choice
of
a closedpoint
x ES,
one obtains a canonicaldecomposition of
c-functors Hom(S, A)
= A x D x N where D ~Zn for
some n 0 and N isnilpotent.
REMARK 5.2. Let A be an abelian
variety,
and let S be avariety.
The functorHom(S, A)
is ingeneral
notrepresentable.
Forinstance, Hom(A 1, A)
is neverrepresentable. Certainly
the natural map A ~Hom(A1, A)
isbijective
on Tvalued
points,
for any reduced T. But it is notsurjective
on T valuedpoints
whenT =
Spec C[E]/(E2),
becauseA(T)
=T(A)(.)
but(Here T(A)
stands for the tangent bundle ofA.)
Proof of 5.1.
There is a mapHom(S, A) ~
A of C-functorsgiven by
evaluationat x. There is also a map:
of abelian groups. Let D be its
image. Identify
D with thecorresponding representable
functor. We construct a map of C-functorsHom(S, A) ~
D, as follows. It suffices to construct a map 03BB:Hom(S
x T,A) ~ D,
for each connected C-scheme T. If T is of finite type overC,
we couldpick
a closedpoint
t~T,
and let03BB(f)
=H1(f|Sx{t}, Z).
Then À would beindependent
of the choice te T.Consider the
general
case, where T is anarbitrary
C-scheme. Letf : S x T ~ A.
Let U c T be a connected open affinesubscheme,
say U =Spec(R).
There exists asubring Ro c R
which isfinitely generated
overC,
and a
morphism f0 : S
xU0 ~ A, compatible
withf. (Here Uo
=Spec(Ro).)
Letu E