C AHIERS DE
TOPOLOGIE ET GÉOMÉTRIE DIFFÉRENTIELLE CATÉGORIQUES
S. B. N IEFIELD
K. I. R OSENTHAL
A note on the algebraic de Morgan’s law
Cahiers de topologie et géométrie différentielle catégoriques, tome 26, n
o2 (1985), p. 115-120
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
A NOTE ON THE ALGEBRAIC DE MORGAN’S LAW
by
S. B. NIEFIELD and K. I. ROSENTHAL*CAHIERS DE TOPOLOGIE ET
GÉOMÉTRIE
DIFFERENTIELLECAT#GORIQUES
Vol. XXVI-2 (1985)
RESUME.
P. T. Johnstone a montré que le localeO(X)
des ouvertsd’un espace
topoloqique
X satisfait la deuxieme loi de deMorgan
(DML), l (U/B V) = 1 U V lV
ssi X est extrêmement disconnexe. L’a-nalogue aig6brique
de la DML est1’equation
des id6auxdans un anneau commutatif R. Dans cet
article,
nous montrons que R satisfait la DMLalg6brique
ssi R est un anneau de Baer. Si R n’a pas denilpotents,
ceciéquivaut à
la disconnexit6 extr6male deSpec(R). Enfin,
nous montrons que si X estcompletement regulier, C(X)
satisfait la DMLalg6brique
ssi X satisfait la DMLtopologique.
In
[3 ],
P.T. Johnstone showed that the localeO(X)
of open subsets of atopological
space X satisfies the second deMorgan’s
lawiff X is
extremally
disconnected.Furthermore, O(X)
satisfies thelogical principle
(strong
deMorgan’s law)
iff every closed subset of X isextremally
dis-connected. Motivated
by
this result andusing
the fact that a locale and the lattice of ideals of a commutativering
are bothexamples
of closedposets,
in[5]
we characterized those commutativerings
R such that the Zariskispectrum Spec(R)
satisfiesstrong
deMorgan’s
law. This wasclosely
related to the ideal theoreticequation
the
algebraic analogue
of this law.Using
thetechniques
of[5],
it isnot difficult to show that if R has no
nilpotents, Spec(R)
isextremally
disconnected iff
for all ideals A and B of R
(the algebraic analogue
of second deMorgan’s law).
In this paper, wepresent
severalequivalent
characteriza- tions of this class ofrings
in terms of ideal theoreticproperties
andobtain the
extremally
disconnectedness of thespectrum
as acorollary.
The
rings
under consideration turn out to be Baerrings, i.e.,
commutative* The authors
gratefully
acknowledge the support furnished by National Science Foundation RUI Grant N° DMS-8407495.rings
R such that the annihilatorAnn(A)
of A is aprincipal
ideal gen- eratedby
anidempotent
element ofR,
for all ideals A of R.Let R be a commutative
ring
withidentity.
For anypair A,
B ofideals,
one can consider thefollowing algebraic analogues
of de Mor-gan’s
lawsAs in the
topological
case, it is astraightforward
exercise to showthat
(1)
holds for all ideals A and B of R. On the otherhand, although
the reverse containment does not hold in
general.
We shall refer to(2)
as the second deMorgan’s
la w(DML).
A related but weaker condition than
(2)
has also beenconsidered, namely
where a, b E R. We shall call
(3) :
weak deMorgan’s
la w(WDML).
Thiscondition was studied
by
Artico and Marconi in[1]
wherethey
showedthat if R has no
nilpotent elements,
then(3)
holds iff everyprime
idealcontains a
unique
minimalprime (possibly 0).
Recall that R is a Baer
ring
if for every idealA,
there exists anidempotent
e e R such thatAnn(A) =
R e. Since Re =Ann(1- e )
and 1- e isidempotent
whenever e isidempotent,
it follows that R is Baer iff for every idealA,
there exists anidempotent
e e R such thatAnn(A)
=Ann( e). Now,
if onerequires
that the above condition holds forprincipal
ideals Aonly,
orequivalently
for annihilators of elements ofA,
such aring
is called a weak Baerring.
There are several characterizations of weak Baer
rings.
Inpart- icular,
Artico and Marconi also show in[lJ
that aring
with nonilpotents
is weak Baer iff it satisfies weak de
Morgan’s
law and its minimal spec- trum iscompact.
Motivatedby
this result and our interest in second deMorgan’s law,
webegan studyirig
Baerrings.
We shall use the
following
three lemmas. Theproofs
arestraight-
forward and therefore left to the reader.
Lemma 1. If R satisfies
WDML,
then R has nonilpotents.
Lemma 2. If e and e’ are
idem potents,
thenLemma 3. If
Ann(A) = Ann(A’)
andAnn(B)
=Ann(B’),
thenTheorem 1. The
following
areequivalent
for a commutativering
R with
identity.
(a) Ann(AB) = Ann(A)
+Ann(B),
for all ideals A and B of R .(b)
R satisfies DML and R has nonilpotents.
(c) Ann(A)
®Ann(Ann(A))
=R,
for every ideal A of R .(d)
R is a Baerring.
(e) R
satisfies WDML andA nn(A) is principal,
for every ideal A of R .Proof. We shall show that
(a)
=>(b)
=>(c)
=>(d)
=>(e)
=>(a).
(a)
±(b)
If(a) holds,
then R has nonilpotents by
Lemma1,
and R sat-isfies DML since
(b)
=>(c) Suppose
R satisfies(b).
Since R has nonilpotents,
Applying DML,
weget
(c)
=:7(d) Suppose Ann(A)
9 B = R. Then 1 = x + y, where x 6 A andy E B.
Astraightforward
calculation shows that x2= x andAnn(A) =
Rx .(d)
=:7(e)
If R is a Baerring,
thenclearly Ann(A)
isprincipal
for everyA,
and R satisfies WDMLby
Lemma 2.(e)
=>(a) Suppose
that(e)
holds. Since R satisfiesWDML, by
Lemma3,
it suffices to show that for every ideal
A, Ann(A) = Ann( a),
for somea E R. Since the annihilator of every ideal is
principal,
we can writeAnn(A)
= Rx andAnn(x)
= Ra. ThenUsing
the abovetheorem,
we shall obtain anelementary ring
theoretic
proof
thatSpec(R)
isextremally
disconnected iffR/N
satisfiesDML,
where N denotes the nil radical of R. Note that this result canalso be obtained via a lattice theoretic
proof, using
thetechniques
of[5],
and Johnstone’s characterization[3]
ofextremally
disconnected spaces as those spaces X such that thetopos Sh(X)
of set-valued sheaveson X satisfies second de
Morgan’s
law.Recall that every open subset of
Spec(R)
is ofthe
formwhere A is an ideal of R. The
complement
ofD(A)
is denotedby V(A).
Lemma 4. If R has no
nilpotents,
then the closure ofD(A)
inSpec(R)
is
given by D(A)= V(Ann(A)).
Proof. If P is
prime,
and A CP,
thenAnn(A)
C P sinceA.Ann(A)
= 0.Hence, D(A)
CV(Ann(A)),
and soD(A)
CV(Ann(A)).
For the reversecontainment,
we shall show that if P EV(Ann(A)) (i.e., Ann(A)
CP),
then every
open neighborhood
of P meetsD(A).
LetD(B)
be such anopen
set, i.e., ’B ’l
P. ThenB I Ann(A),
sinceAnn(A)
C P.Hence,
AB #0.
Since R has nonilpotents, 0 C VA-B, wheref denoted
theprime
radical of an ideal. Therefore,
as desired.
Recall that a space X is
extremally
disconnected if the closure of every open set is open. These are theprojective
spaces in thecategory
ofcompact topological
spaces[6].
Theorem 2.
Suppose
R has nonilpotents.
ThenSpec(R)
isextremally
disconnected iff R satisfies DML.
Proof. It is well known that if R has no
nilpotents,
then A is a directsummand of R iff
V(A)
is an open subset ofSpec(R). Using
this and The-orem 1
(b)
=>(c),
R satisfies DML iffV(Ann A)
is open, for all A.By
Lemma
4, V(Ann A)
is open, for allA,
iffD(A)
is open, for allA,
iffSpec(R)
isextremally
disconnected.Now, Spec(R) £fSpec(R/N),
where N denotes the nilradical of R.Thus,
we obtain thefollowing corollary.
Corollary
1. Thefollowing
areequivalent
for a commutativering
Rwith
identity.
(a) Spec(R)
isextremally
disconnected.(b) R/N
satisfies DML.(c) R/N
is a Baerring.
We conclude
by examining
therelationship
between a space X and thering C(X)
of continuous real-valued functions on X. In thestudy
ofrings
of continuousfunctions,
it is shown thatC(X)
has nicecompleteness properties
as a lattice if X isextremally
disconnected(cf.[2]
or[4]).
In thefollowing theorem,
we show that acompletely regular
spaceX satisfies second de
Morgan’s
law(i.e.,
isextremally disconnected)
iffthe
ring C(X)
satisfies second deMorgan’s
law(i.e.,
is a Baerring).
Theorem 3. L et X be a
topological
space.(1)
If X isextremally disconnected,
thenC(X)
is a Baerring.
(2)
IfC(X)
is a Baerring
and X iscompletely regular,
then Xis
extremally
disconnected.Proof.
(1)
Let A be an ideal ofC(X).
We shallproduce
anidempotent
h E
C(X)
thatgenerates Ann(A).
If f E
A,
letU f
denote the cozero set off , i.e.,
Consider U
= fE U A Uf .
Then U is an open subset of X.Also,
if x EU,
then
f(x) 1
0 for some f cA,
and henceg(x) =
0 for all g EAnn(A).
Thus,
it follows thatLet h: X - R be
defined by
h -= 0 on U and h -= 1 onXBU.
Since X isextremally disconnected,
U is open, and therefore h is continuous. Then h isclearly idempotent,
and it is not difficult to show that hgenerates Ann(A). Therefore, C(X)
is a Baerring.
(2)
Let U be an open subset of X. To show that U is open,we shall show that
XBU= h (1),
for some h EC(X).
ConsiderThen A is an ideal of
C(X).
We claim that U =fUA U f ,
whereU f
denotes the cozero set of f.
Clearly, UfEA UfC
U.Conversely,
if x EU,
then since X is
completely regular,
there is a continuous functionSince f E
A,
it follows that x EU f ,
as desired.Next,
sinceC(X)
isBaer,
there exists h E
C(X)
such thatAnn(A) = (h).
Sincewe must have
h(U)
=0,
andhence,
h(U) =
0. To see thath-1(1) - XBU,
it remains to show that
h(XBU)=
1. Ifx U,
thenby complete regularity,
we can find
Since g E
Ann(A),
it follows thatgh
= g, and soh(x)
= 1.Thus,
h
-1(1) = XV,
and so 0 is open.Therefore,
X isextremally
disconnected.REFERENCES
1. G. ARTICO & U. MARCONI, On the compactness of the minimal spectrum, Rend. Sem.
Mat. Univ. Padova 56
(1977),
79-84.2. L. GILLMAN & M. JERISON, Rinqs of continuous functions, D.V. van Nostrand, 1960.
3. P.T. JOHNSTONE, Conditions related to de Morgan’s law, Applications of Sheaves,
Lecture Notes in Math. 753, Springer
(1980),
479-491.4. P.T. JOHNSTONE, Stone spaces, Cambridge Univ. Press, Cambridge, 1982.
5. S.B. NIEFIELD & K.I. ROSENTHAL, Strong de Morgan’s law and the spectrum of a
commutative ring, J. of
Algebra 93 (1985),
169-181.6. S. WILLARD, General Topology, Addison-Wesley, 1970.
Department of Mathematics Union College
SCHENECTADY, N.Y. 12308 U.S.A.