C OMPOSITIO M ATHEMATICA
I AN M ORRISON
U LF P ERSSON
Numerical sections on elliptic surfaces
Compositio Mathematica, tome 59, n
o3 (1986), p. 323-337
<http://www.numdam.org/item?id=CM_1986__59_3_323_0>
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NUMERICAL SECTIONS ON ELLIPTIC SURFACES
Ian Morrison * and Ulf Persson **
© Martinus Nijhoff Publishers, Dordrecht - Printed in the Netherlands
§0.
IntroductionThroughout
this paper we letf :
X ~ B be arelatively
minimalelliptic
surface X over a smooth
complete
curve B of genus g. We assume that X has adistinguished
section 0 and that the Eulercharacteristic X
=~(OX)
ispositive (so
that X isnot
aproduct
of B with a curve of genusone).
If C is a divisor on X let C denote its class inNS(X).
Let F be afiber of X and
let E(X)
be the set of allsections; 03A3(X)
is the set of alleffective,
irreducible divisors S on X whichsatisfy
S. F = 1. An ex-amination of the
Leray spectral
sequence forf
shows that a section S also satisfiesS2 - -~ (cf. [10]).
From this it follows that a sectioncannot move
so that we mayidentify
the elements of03A3(X)
with theirclasses 03A3(X)
inNS(X).
We define the set of numerical sections of X to be thesubset 03A6(X) ~ NS(X) satisfying
the numerical conditions Ce F= 1 and
C2 = -~.
This paper isprimarily
devoted to thestudy
of03A6(X).
Forsimplicity,
we work here over C but the main resultshold,
modulo a few
locutions, over
any field of characteristic zero.By definition, 03A6(X) ~ 03A3(X)
and it is natural to ask whenequality
holds. We show
that 03A6(X) = 03A3(X)
if andonly
if all fibers of X areirreducible
(2.3
and3.8)
and then we say that X isf-irreducible.
Asecond natural
question
is whether the classes in03A6(X)
must be effective.The answer is yes and in Theorem 2.2 we
give
aprecise description
of theassociated
algebraic systems.
The effectiveness of the classesin 03A6(X)
turns out to be
equivalent
to certaininequalities (1.3)
on the restriction of the intersection form onNS(X)
to the span of thecomponents
of a reducible fibre of X. Wegive
some consequences of theseinequalities
((1.8)
and(2.4))
which lead to a criterion foridentifying 03A3(X)
as asubset
of 03A6(X)(2.5).
Our main focus of interest is in certain group laws on
03A3(X)
and03A6(X)
which we nowexplain.
We first showthat 03A6(X)
is a set of cosetrepresentatives
for the sublatticeU(X)
onNS(X) spanned by
the* Research supported by the National Science and Engineering Research Council of Canada.
* * Research supported by Swedish Research Council of Natural Sciences.
classes of the
distinguished
section 0 and of the fibre F.Similarly E(X)
is a set of coset
representatives
for the sublatticeL(X) spanned by
theclasses of O and of all divisors
supported
in the fibers of F(Theorem 3.1). By transport
of structure we obtain abelian group laws on03A6(X) and E(X),
which we then describe in terms of the addition onNS(X)
in(3.2)
and(3.6).
Theset E(X)
of sections of X has another natural group structure: we may add sectionsfibre-by-fibre
in theelliptic
curveF,
obtained
by using
o.F,, as
anorigin
onFh.
We show that thisoperation
and the
operation on 03A3(X)
described above agree(3.4).
Caution:although 03A3(X)
is a subsetof 03A6(X)
it is not asubgroup except
when X isf-irreducible.
In fact the inclusion ofU(X)
inL(X) yields
asurjec-
tion a :
03A6(X) ~ 03A3(X)
which we describegeometrically:
ifC ~ 03A6(X),
there
is aunique base
section S in the base locus of thealgebraic
system[C] ]
and a sends C toS(3.7). Although
the statements of these results make noréférence to it,
theproofs depend heavily
on the earlierstudy
ofthe
systems [C] for C ~ 03A6(X).
An immediate
corollary
of these results is a formula(3.7)
due to Tate[12]
and Shioda[11]
which was one of ourprincipal guides
in this work:if
kb
is the number ofcomponents
in the fibre off
over b EB,
rank
NS(X) = 2 + rank 03A3(X)+2b~B(Kb-1).
Ourdescription
of theoperation
euon 03A6(X) gives
a method forenumerating
the classes in03A6(X)
in terms of aprescribed
basis ofNS(X).
Aspromised
in[9],
weillustrate this in the case when the surface X is rational. In this case,
03A6(X)
was first enumeratedby
Manin[7];
wesimplified
hisproof
in[9].
Both methods
require
that one guess a formula for certain sumsin 03A6(X)
which is then
fairly easily
verifiedby
induction. A moreconceptual proof
of this formula was another of our
goals;
in§4,
we show that it is aformal
consequence
of ourtheory.
We also illustrate in§4
the criteria foridentifying 03A3(X)
and the kernel of themap 03A6(X) ~ 03A3(X)
as subsets of03A6(X)
with a rationalexample.
The rest of the paper is
organized
as follows.In §1,
welay
thegroundwork
for theinequalities
werequire
on the intersection form on X. In§2
we prove the effectiveness of the classes in03A6(X),
describe thecurves in them and
give
the related corollaries. Thestudy
of the group lawson 03A6(X) and E(X)
is done in§3
and theapplications
to rational Xare
given
in§4.
It is a
pleasure
to thank RobertSteinberg
forpointing
out Lemma 1.4to us. The
proof
of Theorem 1.3 based on this lemmareplaces
along
andtedious case
analysis.
We would also like to thank David Mumford forshowing
us thesimple argument
used to show the existence of the base section in theproof
of Theorem 2.2.§1. Inequalities
on the intersection formBefore
proving
theinequalities
in which we areinterested,
we recall somestandard facts about the structure of the reducible fibres of the map
f:
X - B. The most
complete
treatmentis Kodaira [6]; [1] provides
a morecompact
reference. We will denoteby
C the class inNS(X)
of a divisorC on
X,
but we willusually drop
the bars whencomputing
intersection numbers. We let[C] be
thealgebraic system
associatedto C,
thatis,
theset of effective divisors in the class
C,
and we say C is effective if[C] ~ Ø.
We denoteby Fb
the fibre off
over apoint b e B
andby
F ageneral
fibre of X. The letter S(possibly subscripted etc.)
willalways
denote a section of X and D will
always
indicate a divisor(not necessarily effective) supported
oncomponents
of fibres of X. Let~=~(OX).
We recallLEMMA 1.1
([10, VII, §3]) : KX
=(~
+(2 g - 2)) F.
Inparticular K x.
D = 0for
any divisor Dsupported
on thefibres of
X.Let
Fb = 03A3kl=003BBlDl
be thedecomposition
of a reducible fibreFb
off
into its irreducible
components
withmultiplicities h, à 1,
let = b
bethe span of the
D,
inNS(X)
andlet ~,~b
be the restriction to of the intersection form onNS(X).
Fix i for a moment and observe that 0 =D, - Fb = 03BBlD2l
+03A3j~l03BBj(Di· Dj).
Now eachÀl
ispositive
and eachintersection number
D, - D.
with i~ j
isnon-negative.
The connectedness ofFb implies
thatDl. D.
ispositive
forsome j =1= i,
hence thatD12
0.But then
using
the lemma0 Pa(Dl) = ( Dl2
+Ka - Dl)/2
+ 1 =(D12/2)
+ 1 1 so we must havePa (D,)
= 0. Thus eachDl
is a smoothrational curve of self-intersection
( - 2).
Since all the curvesD,
lie in afibre of the map
f :
X ~ B theHodge
index theoremimplies that ~,~b
is
negative
semi-definite. In fact sinceFb - D,
= 0 forall i, ~,~b
isstrictly
semi-definite.
To
Fb
we associate aweighted graph b; fb
has a vertex for eachcomponent Dl ,
andDl
andD. are joined by
anedge
ofweight aij = D, - Dj e
N.Conversely
to such aweighted graph Î we
may associate the lattice= ~kl=0ZDl
with itsdistinguished
basis{Dl}
and the bilinearform ~,~ on ~ZR
which is definedby
theconditions ( D,, Dl~
=-2and(D,, Dj~ = aij if 1 ~ j.
NIf ~,~
isnegative strictly semi-definite,
thenr
is one of thecompleted
Coxetergraphs Ãn, n 2; Dn, n 4;
orEn n = 6, 7,
8.Moreover there is a
unique
indivisiblepositive integral
elementk
F = 03A303BBl· D,
in the kernelof ~,~
Proofs of these assertions and atable of the
r’s showing
the coefficients03BBl
may be found in[1,
Lemma2.12]
or[5].
Eachf occurs
as thegraph fb
associated to a reducible fibreFb,
in which case Fgives
the divisor class ofFb. (We
will not need theseexistence results for which the reader may refer to Kodaira
[6]).
Now
suppose
thatDo
is acomponent
ofmultiplicity
one inFb.
Let Abe the span of
D1,..., Dk
inNS(X)
and continue to denoteby ~, ~b
therestriction to A of the intersection
pairing.
Letrb
be the associatedweighted graph
and letus
agree to continue to attach the ormer coeffi-cients Àl to
each vertexD,.
Thegraph fb
is the A -D-E Coxetergraph corresponding
to0393b;
inparticular, fb
does notdepend
on themultiplic- ity
onecomponent Do
chosen.The main result of this section is:
THEOREM 1.3 : Let r be one
of
thegraphs Tb . If D
=03A3kl=1alDl ~ A,
thenfor
eachz, (D, D~ -2l 03BB. 1
PROOF: It will be convenient to set
[ , ] = -~,~
and to prove that[ D, D] 2al/03BBl.
We first translate thisinequality
into thelanguage
ofroot
systems.
Indeed we mayidentify
r with the Coxetergraph
of thesimple
rootsystem
of the same name so that A becomes the rootlattice,
the
D,’s
become a fundamentalsystem
ofsimple
roots and[ , ]
becomesthe
Killing
form on A. The basic fact about rootsystems
which we will need is:LEMMA 1.4: Let
D = 03A3lj=1Rj
express D as a sumof
rootsof f ( not necessarily simple )
with 1 minimal. Then[D, D] 03A3lj=1[Rj, Rj].
PROOF: We claim that
if j ~ j’
then[Rj, Rj,]
0 from which the lemma followsimmediately by bilinearity.
If[Rj, Rl,] were negative
thenby [3,
Ch.
VI, §3,
Th.1]
eitherRj = -Rj,
orRl
+Rl,
isagain
aroot;_either
possibility
would contradict theminimality
of theexpression
for D.COROLLARY 1.5: The roots
of
r areexactly
the elementsof of shortest length fi.
PROOF :
Inspection
of the Planche for r in[3]
shows that indeed all roots of r are oflength 2. (This property,
infact, characterizes
the r oftypes A,
D andE).
If D is not a root thenwriting D = 03A3lj=1Rj
witheach
Rj
aroot and
1minimal,
we must havel 2.
Then[D, D]
03A3lj=1[Rj, Rj] = 21,
so D haslength
at least 2.Now let
R b
=03A3ki=103BBlDi. Comparing,
the table in[1,
Lemma2.12]
withthe Planche
for
r in[3]
shows thatRb
is thehighest
root of r withrespect
to theDl’s.
Thatis,
if R =03A3kl=103BCiDl
is any root,then 03BBl
IIIfor
each i .
Since [Rb, R b =
2by
thecorollary, we
can restate the theoremas: for all D
= 03A3ki=1alDi
in A and alli, [D, D]/[Rb, Rb] al/03BBl.
Thisis
clear from the definition ofRb
is D is a root. Otherwisewrite
D
=03A3lj=1 Rj
with eachRl
a root and 1 minimal and writeRj = 03A3ki=103BCjiDi.
Using
Lemma 1.4again,
COROLLARY 1.6:
If
S is a sectionof
X and Dis a
divisorsupported
on areducible
fibre Fb of
X such that S. D =0,
then D -( D 2/2) F
iseffective.
PROOF: The section S must meet
Fb
in apoint of
acomponent
ofmultiplicity
one which wemay take
to beDo.
Then D =’L7=lalDl E b
since
S - D 0.
HenceD-(D2/2)Fb=(-D2/2)D0+03A3nt=1
(al - B - D 2/2)Dl.
The coefficient ofDo
isnon-negative since ~,~b
isnegative definite
and thecoefficient
ofDl
isnon-negative by
Theorem1.3
applied
to D. Therefore D -(D2/2)F
is effective.We
conclude
this sectionwith a few other consequences
of Theorem1.3.
Any
D Eb
has the form D = aF + E withE ~ +b, the effective
cone in
b
cNS(X).
We let03B1(D)
be thegreatest such a, E(D)
be thecorresponding
E and defineIIb
the set ofbarely
effective elements ofb
to bethe
setof
D forwhich a(D) = 0
orequivalently D = E(D).
Note that
03A0b
=f D E +b|(D-F) ~ +}. Now let
us fixa component Do
ofmultiplicity
one inFb
and write ageneral
D =03A3kl=0alDl.
LEMMA 1.7:
( i )
There is an exact sequenceof
latticesgiven by T(D)
= D -a o F.
_(ii)
The map cp restricts to abijection from "b
tob.
(iii)
The groupstructure
E9induced
onII b by transport of
structurefrom A b
isgiven by
D E9 D’= D
+D’ - a( D + D’) F,
and the bilinearform
induced onIIb
is the restrictionof ( , )
tollb.
PROOF: The first
assertion
is clearand the
second follows from the fact that the map D -E(D) from b ~ 03A0b
is an inverse tocp
03A0b. As for(iii), if
Dand
D’are inII b,
then99(li
+D’ - 03B1(D+D’)F) = (D
+ D’-
a(D
+D’)F) - (ao
+a’ - a(D
+D’))F= (D - aoF) +(D’ - a’F)
=
~(D)
+~(D’),
and(p (D) - cp(D)’ = (D - aoF)(D’ - a’F’)
= D - D’.COROLLARY 1.8:
(i ) If D e IIb
andD,
is a componentof multiplicity
onein
Fb (i.e. Àl
=1),
then(D, D~ -2ai.
(ii) Suppose
D is aneffective
divisor on X whose support lies in a reduciblefibre Fb
but such that D -Fb
is noteffective,
and suppose S is asection
of
X. Then 2 SD +D2
0.PROOF:
(i)
We may take i = 0by the symmetry
ofrb.
LetD’
=~(D) ~
A.Then for some
i, 0
ai03BBi
since DE IIb. Thus -a003BBi a; =
ai -a003BBi
(1 - a0)03BBl. By
Theorem1. 3, (D, D~ = ~’, D’~ -2i/03BB
i-
2( a o - 1). Since (, )
is even, thisimplies that (D, D~ - 2 a o .
(ii)
We maysuppose that S
meetsFh
in apoint
ofDo.
Then2S.D+D 2 = 2ao + ~D, D~ 0 by (i).
§2.
Effectiveness of numerical sectionsNow we
let 03A3(X)
be the set of sectionsf :
X ~ B. Recall that a divisor Sis a section if and
only
if S is effective and irreducible and if S - F = 1.Since a section satisfies
S2 = -~
and we areassuming X > 0,
S isalways the unique
curve in[S] ]
and we can and doidentify 03A3(X)
and03A3(X) = {S|S ~ 03A3(X)}
itsimage
inNS(X).
Welet 03A6(X)
be the set ofdivisor
classes which
behavenumerically
like the classes ofsections;
thatis, 03A6(X)={C|C·F=1, C2=-~}. We call 03A6(X) the
set of numericalsections of
X.By definition, 03A3(X) ~ 03A6(X).
Infact 03A3(X)
is the set ofclasses
C~03A6(X)
for which[C] ]
contains an effective irreducible curveC.
In this paragraph,
we address ourselves totwo questions: first,
whendoes 03A3(X)=03A6(X)?;
andsecond,
which classesC in 03A6(X)
are effectiveand what do the curves in
[C ]
look like? As acorollary,
wegive
anumerical characterization
of 03A3(X)
as a subsetof 03A6(X).
The answer to the first
question
issuggested by
a formula due to Tate[12]
and Shioda[11].
The set03A3(X)
isnaturally
afinitely generated
abelian
group-for
details see§3.
Ifkb
is the number ofcomponents
in the fibreFb,
their formula isWe will prove this
(Corollary 3.7)
as acorollary
of ourstudy
of03A6(X).
For the
present,
it motivatesdefining X
to bef-irreducible
if every fibre of X is an irreducible curve. This condition iseasily
seen to begeneric
for
elliptic
surfaces over a fixed base curve B but we shall not need this fact. The basicproperty
off-irreducible X
isexpressed
in:LEMMA 2.1:
If X
isf-irreducible
and C is aneffective
curve on Xsatisfying
CF =
1,
thenC2 = -~(X) if
andonly if
C is irreducible.PROOF: Write C =
03A3ki=0Cl
+03A3lj=1 Fj
with eachFj
a fibre and eachCl
anirreducible curve not
equal
to a fibre. Since X isf-irreducible, Cl ·
F > 0 for each i. Thus C · F = 1implies
k = 0 andC0 · F=1.
SinceCo
isirreducible,
it is therefore asection;
henceC20 - -~.
But thenC2 =
-~(X) + 2l
soC2
- - x if andonly
if 1 =0;
this in turn isequivalent
to the
irreducibility
of C.Now let us turn to our second
question
for a moment: we claim thatevery divisor class
in 03A6(X)
is effective. Moreprecisely,
let us define adivisor D to be unifibral if the
support
of D is contained in asingle
reducible fibre
Fb and, following §1,
let us call such a Dbarely
effectiveif D is effective but D -
Fb
is not. ThenTHEOREM 2.2:
If C ~ 03A6(X),
then C iseffective
and[C] =
S +03A3l~IDl
+[aF] ]
where S is a sectionof X,
the curvesD,
arebarely effective
curvessupported
on distinct reduciblefibres of
X and a =Ll ~ I (Dl)2/2.
Thatis,
the curve S and the curves
D,
are base curvesof
thealgebraic
system[C] ]
and the
moving part of [ C ]
consistsof
afibres of
X.COROLLARY 2.2.
(i) If X is irreducible, 03A3(X) = 03A6(X).
(ii) 03A3(X) is
the setof
classes Cin 03A6(X)
such that[C] ]
contains anirreducible curve.
In
fact,
the converse ofpart (i)
is true but theproof
of this must waituntil
§3.
PROOF oF 2.2: First observe that
h2(X,
C +kF)
=h0(X, KX -
C -kF)
= 0 for
any k
since(KX - C - kF ) · F = -1.
Thusby Riemann-Roch,
h°(X, C + kF) 1 2 (C + kF)2 - KX(C + kF)) + ~ = k - g + ~. (We used
Lemma 1.1 and the
hypothesis C ~ 03A6(X).)
Ifk g,
then C + kF is effective. Pick a curve C’ =03A3li=0Cl
+L7=lDl
E[ C
+ kF] where
eachCl
isirreducible and does not lie in a fibre of X and each
Dj
is acomponent
of a fibre of X.
Using
C’ - F =1,
we see as in theproof
of(2.1)
that 1 = 0and
Co
is a section of X. We write S forCo.
There is a
unique expression
C’ = S+ 03A3li=1D’l
+ aF such that(i)
theD,’
aresupported
on distinct reducible fibres of X(ii) S. DÎ
= 0 for each i.The first condition determines each
D,’
up to amultiple
of F and thesecond condition then
specifies the D,"s and uniquely. Taking
self-intersection on
both sides
ofC + kF = S + 03A3li=1D’l + 03B1F gives
2k =03A3li=1D’2l + 203B1,
soC = S + 03A3ll=1((D’l-(D’2l/2)F). (As in 1,
allthe D:2
are
even.)
Butby Corollary 1.6,
each divisorclass D’l-(D’2l/2)F
iseffective,
hence C is effective. If C and C’ are in[C],
then theargument
above shows that C = S + D and C’ = S’ + D’ with S and S’ sections and D and D’ effective curvessupported
in fibres. If F is a smooth fibre of X and - denotes linearequivalence
onF, S · F ~ (OX(C)|F ~ m x( C’) 1 F - S’ . F. Linearly equivalent
effective divisors ofdegree
oneon a curve of genus one are
equal
so S - F = S’ - F. Since S and S’aresections, S
= S’. _Any
curveC ~ [C]
will now have aunique expression
of the form C = S + D + aF where D is a sum ofbarely
effective unifibral divisors.If D’ is another such
divisor,
then in every fibre of X there is acomponent
whosemultiplicity
inD_- D’
isnon-negative
and one whosemultiplicity
isnon-positive.
Thus D - D’ can be amultiple of
a fibreonly
if D = D’. If C’ = S + D’ + 03B1F is another curve in[C] ]
we find( a - 03B1’)F =
D’ - D hence D =D’ and a
= a’. Thiscompletes
theproof.
Note that unlike the classes
in 03A3(X)
thosein 03A6(X)
may move inarbitrarily large
linearsystems.
COROLLARY 2.4:
( i ) If S is a
sectionof
X and D isany
divisorsupported
on the
fibres of
X andsatisfying
2S. D +D 2
=0,
then D iseffective.
(ii )
Let({Dl}, , ~, ~) be
the dataof one of the graphs r
letDo
be acomponent of multiplicity
one(i.e. 03BB0
=1)
and let D =03A3ki=0aiDl. If
~D, D~ = -2a0,
then each al isnon-negative.
PROOF:
(i)
The class C = S + D liesin 03A6(X). By twisting by fibres, one
sees that S is
the
base section of the linearsystem [C].
Since C - S is effective so is D. Now(ii)
isjust
the translation of(i)
into thelanguage of §1.
We
conclude
this sectionby giving
a numerical characterization of theclasses 03A3(X) in 03A6(X).
PROPOSITION 2.5:
If C ~ 03A6(X),
thenC~03A3(X) if
andonly if
C·D 0for
every component Dof
eachfibre of
X.PROOF: If C is the class of a
section, then each
C - D0 since
C and Dare
distinct,
effective and irreducible. IfC ~ 03A6(X)
butC ~ 03A3(X),
thenby
Theorem 2.2 there is a curve in[C] of
the form S +03A3l~ I D,
+ aF witheach
D, barely
effective. If I isempty,
then a = 0 so C =S;
hence I isnot
empty.
NowC · Dl = S · Dl + (Dl)2 -(S·Dl)0 using Corollary
1.8
(ii).
IfS·Dl0,
thenC·Dl 0
and ifS·Dl = 0
thenC·Dl = D2l
- 2. In either case, since
D,
is an effective sum ofcomponents
of a fibre ofX,
C must meet some component in the support ofD, negatively.
§3. Group
laws on03A3(X)
and03A6(X)
In this
section,
we let O be adistinguished
section of X. We will first showthat 03A6(X) and 03A3(X)
re a natural set of cosetrepresentatives
forcertain sublattices of
NS(X) depending
on O. Then we describe the group structures so inducedon 03A6(X) and 03A3(X).
Inparticular,
the group structure on03A3(X)
is thatgiven by
fibrewise addition:taking O·Fb
asorigin
onFb
we add sectionsby adding
their intersections with each fibre in thecorresponding elliptic
curve._
The lattices which
concern
us areU(X),
the span inNS(X)
of O andF and
L(X),
the span of O and of all divisor classes Dsupported
infibres of X. We let R be the set of all
components
D of fibres of X such that D - 0 = 0. The set R islinearly independent
inNS(X)
and ifK(X)
denotes its span then
L(X) = U(X) ~ K(X).
Our first main result in this section is:THEOREM 3.1:
(1) 03A6(X) is a set of
cosetrepresentatives for U(X)
inN,S(X).
(2) 03A3(X) is a
setof
cosetrepresentatives for L ( X)
inNS( X).
PROOF : Given a class
C ~ NS(X),
letC’ = C + 03B2O.
ThenC’. F = C · F + 03B2
so if we set03B2 = 1-C·F
then C’. F = 1. Now let C" = C’ + 03B1F. Then C"-F=1 and(C")2 = (C’)2 + 203B1
so(C")2 = -~
ifand
only
if a =(-~- (C’)2)/2.
To prove(1),
we must show that this ais
integral.
We thereforecompute
To see
(2),
fixC ~ NS(X).
Write the irreduciblecomponents
of each fibreFb
asDo, Dl, ... , Dk
withDo
chosen so that0’Do=l
andD1, ... , Dk spanning
the latticeb
of§1.
Since the intersectionpairing
on
b
is nondegenerate there
isa unique Db ~ b
such thatDb · D,
= C. D,
for i > 0. Thenc Db
has intersection number zero withbEB
any element
ofK(X).
Thisproperty
is not affectedby adding multiples
of O or F so
arguing
asabove
we may find aunique C" congruent
to C’modulo
U(X),
hence to C moduloL(X) which
both liesin 03A6(X)
and isorthogonal
toK(X).
Since C" · F = 1 but C" isorthogonal
toK(X),
C" has
non-négative intersection number
with everycomponent
of every fibre of X. SinceC" ~ 03A6(X), C" ~ 03A3(X) by Proposition
2.5.By transport
of structure, the additions inNS(X)/U(X)
andNS(X)/L(X)
induce abelian group lawson 03A6(X) and E(X).
We wishto denote
by E9 both
theseoperations.
This risks some confusion since theoperation on 03A3(X)
is not obtainedby
restriction from thaton 03A6(X)
even
though 03A3(X) ~ F(X). (In fact,
sinceU(X) ~ L(X), 03C3(X)
isnaturally
aquotient of 03A6(X)). We resolve
thisby identifying
thesections
in 03A3(X)
and their classesin E(X)
asusual,
and thenusing (D to denote
thetransported opérations on 03A3(X)
andon 03A6(X).
ThenSl E9 S2
is a sumin 03A6(X), Sl E9 S2
the class of a sumin E(X).
Our nextgoal
is to relate theoperation
E9 to the addition inNS(X)
itself. Webegin
with03A6(X).
PROPOSITION 3.2:
If CI
andC2 are in 03A6(X),
thenC1 ~ C2 = C1 + C2 - O + 03B1F where 03B1=(C1+C2)·O-C1C2+~.
PROOF:
By definition, Cl E9 C2
isthe unique
element ofNS(X)
whichlies
in 03A6(X)
and iscongruent
toC1 + C2
moduloU(X).
The classC =
C,
+C2 -
0 + aF satisfies the congruence and theequation
C - F = 1for any a. The
remaining
conditionC2 = -~
holdsexactly
for thegiven
a.
Observe that the sublattice
U(X)
is unimodular so that thatNS(X)/U
and
U~
arecanonically isomorphic.
Welet 03C8
denote the inducedisomorphism 03C8: U~~03A6(X),
which we think of aslinearizing
theoperation
Et)on 03A6(X).
COROLLARY 3.3:
(1) 03A6(X) is torsion free of rank egual to
rankNS(X) -
2.PROOF:
Since 03A6(X) ~ U~ ~ NS(X),
all of(1)
willfollow
if we showthat
NS(X)
is torsionfree.
To seethis, suppose
thatT
is a torsion class inNS(X).
Thenh0(X, T) = 0
and T · C = 0 for allC ~ NS(X). Using
Riemann Roch we find
Therefore
h0(X, KX - T) = h2(X, T) > 0.
Pick a curveC ~ [KX - T].
Since C - F =
(KX - T) ·
F =0,
C issupported
in the fibres of X. If D is any irreduciblecomponent of a fibre
ofF,
thenusing
Lemma1.1,
C · D = (KX - T)·D = 0
hence C = aF for some a.If
Sis
asection
ofX,
thenC · S = KX · S so 03B1 = (2g - 2) + x. Therefore C = KX and T =
0.To
see (2), define 03C8(C) = O + C - (C2/2)F. A quick
check showsthat 03C8(C)·F=1 and 03C8(C)2 =-~,
hence that03C8(C) ~ 03A6(X).
Con-versely, if C ~ 03A6(X) then C’ = C - O - (C · O + ~)F ~ U~ and (C’)2 =
-2(~+C·O). Therefore 03C8(C’)=C’+O+(~+C·O)F=C, so Ç is
onto. To check
that 03C8=03C8,
it remainsonly
to observethat 03C8(C) ~
Cmodulo
U(X).
Now we turn on our attention
to 03A3(X).
Webegin by recalling
thedefinition of the
fibre-by-fibre
addition of of sections of X. The set(Fb)n,s
ofnon-singular points
of each fibreF,,
isnaturally
aprincipal homogeneous
space for a commutativealgebraic
group(cf [4]).
Thepoint Ob
= 0 -F.
isnon-singular
onFb
since 0 is a section.Taking
thispoint
as
origin
fixes a groupoperation
on(Fb)n.s
which we denote+ b . If ~b
denotes linear
equivalence
onFb
and the usual +sign
denotes addition ofdivisors,
theoperation +b
is characterizedby
therequirement
thatP
+ bQ
solve( P + bQ) - Ob ~ b(P - Ob)
+( Q - Ob )
orequivalently (P + bQ) ~ bP + Q - Qb.
Now weget
a first characterization of E9 onY-(X) by
PROPOSITION 3.4:
(1) S1
~S2 = SI
+,S2 -
0 +D(Sl’ S2)
whereD(Sl’ S2)
is a divisor
supported
on thefibres of
X.(2)(SlEeS2).Pb=(Sl.Fb)+b(S2.Fb). That is on 03A3(X),
~the oper-
ation
of fibre-by fibre
additionof
sections with 0 asorigin.
PROOF :
Since S1
El)S2
isCongruent
toS1
+S2
moduloL(X)
we musthave
SI
~S2 = S1
+S2
+ aO +D,
with Dsupported
on the fibres of X.Since
Si
~S2 ~ 03A3(X), ( Sl
~S2) .
F = 1 so a = -1 as in(1).
Nowusing
the
adjunction
formula and thetriviality
ofKx
restricted toFb,
we seethat
(1)
restricts to( Sl
~S) - Fb - b Sl - Fb
+S2. Fb - Ob
onFb
whichproves
(2).
COROLLARY 3.5:
(Tate-Shioda) If kb
is the numberof
components in thefibre Fb,
thenPROOF: Since
L(X) ~ U(X)
E9K(X),
rankU(X)
=2,
and rankK(X) =
03A3(kb - 1)
this followsimmediately
from theisomorphism
bEB
03A3(X) ~ NS(X)/L(X).
REMARK: Of course, in the
original
statements of this formula theimplied operation on 03A3(X)
was that of fibrewise addition. In thislight,
the
isomorphism 03A3(X) ~ NS(X)/L(X)
may be seen as a moreprecise
version of the Tate-Shioda formula
taking
torsion into account. Infact,
one of our
primary
motivations in this work was to better understand this beautiful formula._
To
complete
thedescription
of E9 on03A3(X),
we wish to toidentify
thedivisor class
D( S1, S1)
of(3.4).
Somepreliminary
definitions will berequired.
IfS ~ E(X),
writeDb(S)
for the component of the fibreFb meeting
S. Next for anycomponent
D ofFb
we define a divisor0394(D)
asfollows. If
D = Db(O)
thenà(D) = 0.
Otherwise0394(D)
is theunique barely
effective divisorsupported
onFb
for whichA(D)’D=1, 0394(D)·
Db(O)= -1
and0394(D) ·
D’ = 0 for all other irreducible components D’of
Fb.
Now observe that
Db(O)n.s.
is the connected component of theidentity Ob
on(Fb)n.s.
Therefore there is a grouplaw,
which we denote+ b,
on thecomponents
ofFb:
D+ b
D’ = D" if P+ b
P’ E D" wheneverP E
Dn.s.
and P’ eD’n.s..
Thecomponents
ofmultiplicity
one inFb
froma
subgroup
withrespect
to+ b.
Observethat,
since(S1 ~ S2) · Fb
=(S1 · Fb)+b(S2·Fb), Db(S1 ~ S2) = Db(S1)+bDb(S2).
Therefore if we setDb(S1, S2) = 0394(Db(S1) + b Db(S2)) - A(Db(Sl» - 0394(Db(S2)),
thenS1 ~ S2
and5B
+S2 -
0 +Db(Sl’ S2 )
have the same intersection num-ber with every
component
ofFb.
Next letD(S1, S2) = Db(Sl’ S2)
and let
T = S1 + S2 - O
+D(S1, S2 ). Then Sl ED S2
and T have the sameintersection
number withevery component
of every fibre of X.Finally
let T’ =
T-((T2 + ~)/2)F;
as in(3.1.1)
one checks thatT2 = ~(mod 2).
Then T’. F = 1 and
(T’)2
= -~ soT’ ~ 03A6(X). But if D is
any compo-nent of a
fibre,
T’ · D =T · D = (S1
E9S2) · D 0
soT’ ~ 03A3(X) by
Pro-position
2.5. Since T’ ~(S1
+S2 )
moduloL(X), T’ = S1
E9S2.
To sum-marize,
PROPOSITION 3.6:
S1 ~ S2 = S1 + S2 -
0 +D(S1, S2 )
+03B2F
whereWe conclude this section with a few remarks on the relation between
03A6(X) and 03A3(X).
The inclusionU(X) ~ L(X)
induces asurjection
T:NS(X)/U(X) ~ NS(X)/L(X)
and hence asurjection 03C3: 03A6(X)~03A3(X).
PROPOSITION 3.7:
(1)
The map a sends a class C to theunique
section S inthe base locus
of the system [C].
(2)
ker a ={O
+ D -(D2/2)F| D E K(X)}.
PROOF:
By
Theorem 2.3 any classC ~ 03A6(X)
hasthe
form C = S + D’with S a section
lying
in the base locus of[ C ] and D’ supported
on thefibres
of X. Since D’therefore lies on L(X), 03C4(C) = 03C4(S)
and hence03C3(C) = S.
If wewrite
D’ = D + aF withD ~ K(X)
then asabove 03B1 = -(D2/2).
If C ~ ker 03C3 then S = O soC = O + D - (D2/2)F
asclaimed
COROLLARY 3.8: X is
f-irreducible if
andonly if 03A6(X) = 03A6(X).
PROOF:
If 03A3(X) = 03A6(X),
then ker a is trivial. Therefore so isK(X)
i.e.all fibres of X are irreducible. The reverse
implication
isproved
inCorollary
2.2.1.§4. Applications:
The rational caseThe results of
§3 provide
a uniform method forobtaining
the coordi- nates of elementsof 03A6(X)
in terms of agiven
basis ofNS(X).
If inaddition the
types
of the reducible fibres of X are known then we canalso coordinatize
03A3(X)
and describe its torsionsubgroup.
In this para-graph
we wish to illustrate these methods in the case when X is rational.We recall that a rational
elliptic
surface X with section is obtainedby blowing up p 2
at the nine basepoints (some possibly infinitely near)
ofa
pencil
ofplane
cubic curves whosegeneric
member is smooth. Since~(Ox)= -1, 03A6(X)
is the set of classes Csatisfying
C · F = 1 andC2= - 1
andL( X)
is the set ofexceptional
curves of the first kind onX. The group
NS(X) has
asbasis H,
thepullback
to X of the class of aline in the
plane
andEi, ... , E9,
theclasses
of the nineexceptional
divisors of the
blow-ups (i.e. E2l = -1).
TheEl
are allin 03A6(X)
butthey
need not all be
exceptional
curves of the firstkind; they
will fail to besuch
exactly
when thepencil
of cubics hasinfinitely
near basepoints.
However,
at least theexceptional
divisor associated to the lastblow-up
will be of the first
kind,
and hence will be a section of X. Tokeep
ournotation consistent with that of
[7]
and[9] we
supposeEl is
asection
and take it as
origin section
O. As in§3,
let U be the span of O and F inNS(X) and let 03C8: U~ ~ 03A6(X) be the
naturalisomorphism.
The inverse ofÇ sends E, ,
1 à 2 toT = -
3H+ EI + 03A3j2 Ej.
Let A be the sublatticeof
U 1 spanned by
theT .
LEMMA 4.1:
( i )
The intersectionform
on A isgiven by T 2
- - 2 andTl·Tj = -1 if i~j.
PROOF: We leave
(i)
to the reader. To see(ii),
wecompute
the determi-nant of the intersection form on A.
By (i),
this form has matrixFirst,
subtract in succession each row from the one aboveproceeding
from
top
to bottom. Then add each column to the one on its leftproceeding
fromright
to left. We arriveat 0 )
whence the determi - nant is 9. Thus*/ has
order 9. ButNS(X),
U andU~
areunimodular so
*/U~ ~ U~/ ~ Z/3Z.
We can now
immediately recover the enumeration of 03A6(X)
due toManin
[7].
IfC ~ 03A6(X)
let@C
= C e ... ~ C and if A =( a 2, ... , a9)
~ Z8
letEA = ~9i=2
lE,
and letTA
=03A39l=2
alT,. If 03BE = 03C8 (A), then e
isthe