R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
M ICHELE E MMER
On the behaviour of the surfaces of equilibrium in the capillary tubes when gravity goes to zero
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Equilibrium
in the Capillary Tubes when Gravity Goes
toZero.
MICHELE EMMER
(*) (**)
Introduction.
In a
previous
work I have studiedby
a variational method theproblem
of the surfaces ofequilibrium
of a fluid in acapillary
tubeconsidering
also thegravity
force[1].
The functional of the energy is the
following:
where S~ is an open and bounded set in
Rn,
andis the
capillary constant,
with e =density
difference across the freesurface, g
=gravitational acceleration, a
= surfacetension;
v is alsoa constant
depending only
onphysical
conditions. The firstintegral
in
(0.1) represents
the surfacetension,
the second thegravity
andthe third the force of adhesion to the wall of the tube.
(*)
Indirizzo dell’A.: Istituto Matematico «G. Castelnuovo », Citth Uni- versitaria, Piazzale delle Scienze 5, 00185 Roma.(**) During
thepreparation
of this paper the author was at the Universite de Paris Sud, Bat. Mat. 425,Orsay, partially supported by
agrant
CNR-NATO.Moreover
t(x)
is the free surface of the fluid in the tube whose section is Q.In
[1]
I haveproved
a theorem of existence andunicity
for theminimum of the functional
Y(f)
in the class of functions with thefollowing hypotheses:
i)
8Qlipschitz;
where L is the
lipschitz
constant of aS~.I have also
proved
aregularity
theorem for the solution of theproblem.
I recall these results in the
following chapter.
In this work I will consider the behaviour of the surfaces of
equili-
brium in a
capillary
tube when thegravity
goes to zero.For each c > 0 let
fs
minimize the functionalREMARK 0.1.
Obviously
we have(0.4)
where
It
easily
followsHence it has no
meaning
to look for a functionminimizing
thefunctional
:Fo(f)
without any other condition.Many
authors have studiedby
different methods thisproblem
for the functional with a volumeconstraint,
that is with the conditionIn this work instead of
considering
a volume constraint I shall examine the behaviour of the free surface when thegravity
goes tozero.
The intuitive fact that the surfaces
fs
rise in the tube as thegravity decreases,
is first confirmedby
thefollowing
remark:So it
obviously
follows thatthat is the volume of the fluid continues to increase.
The
proof
of theprevious
well known remark is recalled in thefollowing chapter.
To prove the
monotonicity
of thefamily ~e
I will use astrong
maximum
principle
for the minimal surfacesoperator, analogous
tothe results of P. Concus and R. Finn
[12],
and acomparison
theorembetween the solutions of the minimum
problem
for the functional with two differentgravities.
Finally
I can prove thatthat is the
liquid
rises at everypoint
of~2;
in other words I can say that when thegravity
goes to zero we do not obtain a limit surface.To prove
(0.10)
I use atechnique
introducedby
E.Gonzalez,
U. Massari and I. Tamanini
[13]
in thestudy
of setsminimizing peri-
meter and
containing
anassigned
volume.In my
problem
I do not consider a volume constraint but a mean curvature term so thetechnique
issimplified.
I prove the result in various
steps;
first I suppose that(0.11)
isnot
satisfied,
that is it exists a number L E .R such thatThen I prove Lemma 3.1 which states
where
and
Then
by defining
it follows that for a
sufficiently
small e > 0 there exists apoint
7:* EE
[ao, bo]
such that(Proposition 3.2)
To prove
Proposition
3.2 I first prove a technical Lemma.I shall
study
in afollowing
paper theproblem
of the behaviourof the surfaces of
equilibrium
in acapillary
tube when thegravity
goes to zero
together
with a volume constraint.I want to thank M. Miranda and E. Gonzalez for the useful talks
on the
subject.
1. Let
i)
,S2 be an open and bounded set in Rn(n
>2)
and M2 be hisboundary;
ii)
aD belocally lipschitz,
i.e. for every x E aSZ there exists asphere
such that 8Q r1Be(z)
is thegraph
of a function u:J A - R where A is an open set and a
lipschitz
function.iii)
L be the maximum of thelipschitz
constants for the func- tions u.The functional will be considered in the natural space for varia- tional
problems
of this kind:i.e. the space of functions
f
E whose derivativesD1 f , ... , Dn f
in the sense of distributions are finite Radon meas- ures on Q. For functionsf
c it ispossible by
a result ofM. Miranda
[14]
to define the trace on and is a function in_____
The
symbol fV1 -f- IDI12
will indicate the total variation of the vector measures whosecomponents
are theLebesgue
measure and themeasures
D1 f ,
... ,Dn f,
i.e.Let us suppose the tube be made of an omogeneous
material;
thisfact
implies
that v is a constant.Physically v represents
the cosineof the
angle
between the exterior normal to the walls of thecapillary
tube and the normal to the free surface of the
liquid [15].
Then it is clear that v E
[-1, 1].
Let us consider the case v > 0 and therefore
f (x)
> 0. For ê ER,
ê > 0 let us consider the new functional
where the last
integral represents
thegravitational potential
energy.In
[1]
the author hasdemonstrated, using
thefollowing estimate,
where is a constant
depending
on thegeometry
ofS~,
thefollowing
result:
THEOREM
[1]. i)
If0 C v ~ 1~1~1 -~- Z2
thenii)
If 0 v-~- L2,
then everyminimizing
sequence is com-pact.
Moreover the functional is lower semicontinuous.Hence for every 8 > 0 there exists a solution for the
problem
In the same work
[1]
it was also demonstrated theuniqueness
andregularity
of the solutionusing
theregularity
methods of U. Mas- sari[16].
L.Pepe [17]
has thenproved
that the solution isanalytic
in S2 in every dimension
(see
also[18]).
For other conditions on the domain for the existence of solutions
see also I. Tamanini
[19],
R. Finn-C. Gerhardt[20].
For a discussion of the
physical meaning
see P. Concus - R. Finn[12].
For an
history
ofcapillarity phenomena
see[15], [21].
2. Let us now examine the
properties
of theFirst of
all,
as I havealready
said in theIntroduction,
I noticethat
In fact from the Eulei
equation
of/e
we obtainand
(2.1)
follows.REMARK 2.1. The
integral (2.2) represents
the volume of theliquid
which rises in thecapillary
tube.I will now prove a
strong
maximumprinciple
for the minimal surfacesoperator;
I will use thisprinciple
to demonstrate the mono-tonicity
of thesequence {fe}.
PROP. 2.1. Let 1VI be the minimal surfaces
operator.
If we havethen we
necessarily
obtain eitherPROOF. From
(2.3)
and(2.4)
wehave,
for everyfunction § > 0,
~
and then
Let us choose
now § =
We consider the casef (x)
>>
g(x) ;
then we haveand, by
theconvexity
of the areafunctional,
we obtainand then
the connected
components
of ,5~. Moreoveras the set where
(2.11)
is valid must besimultaneously
closed andopen.
Let us now prove that when the
gravity
decreases the free surfaces of the fluid rise inside thetube,
that is that thefamily
of functions(fs)
is monotone.PROPOSITION 2.2. Let
/1
be the solution of theproblem
infand
f,
be the solution of theproblem
Let besuch that
then
DIM. We know from
Proposition
2.1 that we can haveNow,
because minimizes the functional we obtainIn the same way we have
From
(2.10), (2.11)
we obtainand from
(2.10), (2.12)
it followsThen
by (2.13)
we obtainand
by (2.14)
Then,
as c >0,
e, > 0 we have a contradiction. So theonly possibility
is thefollowing:
So we have demonstrated that
together
with3. I can now prove that not
only
the volume of theliquid
risesbut also that the free surface of the
liquid
rises at everypoint
of S~.As I have
already
said in theIntroduction,
in theproof
I willuse a
technique
introducedby
E.Gonzalez,
U. Massari and I. Tama-nini [13].
The main result is the
following:
THEOREM 3.1. In the
previous hypothesis
we obtain thefollowing
behaviour for the free surface
We shall prove the theorem
by
severalsteps.
Let us suppose that there exists a number L E R such that
Let us define
The first
step
is to prove a Lemma whichgives
an estimate about theovergraph
offs
when e goes to zero. Moreprecisely
LEMMA 3.1. Let
then
DIM.
OBS. 3.1. It is obvious
by
thehypothesis (3.2)
thatLet us define
As minimizes the functional
5;",(f)
we obtainwhere = is the characteristic function of a set
A,
is the
perimeter
of the set .E in the open setA, A) [2 2 ] .
A
Now as
and also
we have
Let now
B(R, c)
be asphere
whose radius is R and the center is(0,
... ,c),
c > 0 and such thatREMARK 3.2.
By
conditions(3.12)
on thesphere
we haveMoreover it is obvious that
then, by (3.12)
Moreover
by (3.11 ), (3.14)
we obtainBy (3.15)
we alsoobtain, recalling (3.12),
Then
finally
In the end we obtain
By
the definition of vE(3.12)
we haveSo Lemma 3.1 is
proved.
We must now prove a technical Lemma. Let us first define
Let us consider three
points ti, t2, t3
s.t.and let us define
where
Let
We now demonstrate the
following:
LEMMA 3.2. There exists a constant Cl such that
where
PROOF. Let
We now consider two
spheres B1, B2
c s.t.By
theisoperimetric property
of thesphere
we obtainBy adding
the tworelationships (3.31)
for i =1, 2,
we haveREMARK 3.3. The set
I’E
is thecomplementary
set ofEe,
thenby
theminimizing property
ofEs
we obtain that realizes the minimum for thefollowing
functional:among all the
overgraphs
F such that+ oo) .
Then
by
Remark 3.3 we obtainand then
Now
by
the fact thatwe also have
From
(3.31), (3.37),
and alsoconsidering
that1,
weobtain
and then
Obviously
we haveMoreover
t C .L --~- 1; then, by considering (3.29), (3.40)
and thedefinition
of v,
we obtainand
finally
where
So we have
proved
Lemma 3.3.I can now prove Theorem
3.1; by
theregularity
of the functionst e
it is sufficient to prove the
following:
PROPOSITION 3.1. Let B > 0 be
sufficiently small,
then there exists t* Ebo~
such thatPROOF. We shall construct the
point
t* as the limit of two se-quences and
~b3~,
the first oneincreasing
and the second onedecreasing
towards t* and also such thatIn order to construct the two sequences and we shall use an iterative method
starting
withao = L -~- 2 , bo
= L+
1.Let us now suppose to have
constructed aj and bj with j > 0
andlet us define
Let now
be h
e(0,
we can find threepoints ti (i
=1, 2, 3)
s.t.and moreover
Let us define
Obviously
from(3.48)
we haveLet
By
Lemma 3.2 we haveas
h,
1. Let us now define thepoints
1Now we want to estimate the
quantities (3.46), (3.49), (3.50).
We haveMoreover
by (3.53)
we obtainthen
by (3.51), (3.56)
we obtainLet us now choose
It remains now to such that
By
the estimate(3.55)
we havethen, remembering (3.58)
Let us
put k
= 9 and thenWe have now to prove that
Now
by (3.57), (3.63)
we haveand then
where
then
Remembering
the Lemma 3.1 we haveand then
So Theorem 3.1 is
proved.
BIBLIOGRAPHY
[1] M. EMMER, Esistenza, unicità e
regolarità
nellesuperfici
diequilibrio
neicapillari,
Ann. dell’Univ, di Ferrara, 18 (1973), pp. 79-94.[2] U. MASSARI - L. PEPE, Su una
formulazione
variazionale delproblema
dei
capillari
in assenza digravità,
Ann. dell’Univ. di Ferrara, 20 (1975),pp. 33-42.
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capillary free surfaces
in the absenceof gravity,
Acta Math., 132 (1974), pp. 177-198.
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Man. Math.,28 (1979), pp. 1-11.
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