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Diagenetic Modelling

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1D Diagenetic modelling - Porous

Media

Arthur Capet, Marilaure Gr´egoire, Karline Soetaert

(2)

1. Reaction-Transport Models in 1D

2. Porous Media

3. Reaction-Transport in Porous Media

4. Diagenetic Reaction Processes

(3)

Reaction-Transport Models

Transport Reaction Equation

∂C

∂t = T + R

C Concentration mass/m3

t Time time

T Transport mass/m3/time

(4)

1D spatial contexts

Ex.: Rivers

I C : C (x , t)

I x : main axis of spatial

variability

I C is considered homogeneous

(5)

1D spatial contexts

Ex.: Rivers

I C : C (x , t)

I x : main axis of spatial

variability

I C is considered homogeneous

(6)

1D spatial contexts

Ex.: Rivers

I C : C (x , t)

I x : main axis of spatial

variability

I C is considered homogeneous

(7)

1D spatial contexts

(8)

1D spatial contexts

(9)

1D spatial contexts

(10)

1D spatial contexts

(11)

Reaction-Transport Models in 1D

Transport Reaction Equation in 1D

∂C ∂t = − 1 Ax ∂(Ax. J) ∂x | {z } Transport +R C Concentration mass/m3 t Time time

R Reaction mass/m3/time

Ax Surface m2

J Flux mass/m2/time

General flux expression

J = −D∂C ∂x | {z } Diffusion + vC |{z} Advection

D Diffusion Coefficient m2/time

(12)

Reaction-Transport Models in 1D

Transport Reaction Equation in 1D

∂C ∂t = − 1 Ax ∂(Ax. J) ∂x | {z } Transport +R C Concentration mass/m3 t Time time

R Reaction mass/m3/time

Ax Surface m2

J Flux mass/m2/time

General flux expression

J = −D∂C ∂x | {z } Diffusion + vC |{z} Advection

D Diffusion Coefficient m2/time

(13)

Reaction-Transport Models in 1D

∂C ∂t = − 1 Ax ∂(Ax. J) ∂x + R (1) J = −D∂C ∂x + vC (2) Spatial context Horizontal homogeneity

I Depth as the main axis →

Constant surface Ax = A

(1) + (2) → General 1D Diffusion-Advection-Reaction equation

∂C ∂t = ∂ ∂x  D∂(C ) ∂x − vC  + R

(14)

1. Reaction-Transport Models in 1D

2. Porous Media

3. Reaction-Transport in Porous Media

4. Diagenetic Reaction Processes

(15)

Multiple phases

Bulk Sediments = Solid + Liquid

Until now :

I Concentrations

Mass / Vol. of Bulk Sediments

Different transport processes → need to express different phases.

I for Solutes

Mass / Vol. of liquid

I for Solids

Mass / Vol. of solid

Useful for conversion: Porosity (φ)

I φ = Vol. Liquid / Vol. Bulk

(16)

Multiple phases

Bulk Sediments = Solid + Liquid

Until now :

I Concentrations

Mass / Vol. of Bulk Sediments

Different transport processes → need to express different phases.

I for Solutes

Mass / Vol. of liquid

I for Solids

Mass / Vol. of solid

Useful for conversion: Porosity (φ)

I φ = Vol. Liquid / Vol. Bulk

(17)

Multiple phases

Bulk Sediments = Solid + Liquid

Until now :

I Concentrations

Mass / Vol. of Bulk Sediments

Different transport processes → need to express different phases.

I for Solutes

Mass / Vol. of liquid

I for Solids

Mass / Vol. of solid

Useful for conversion: Porosity (φ)

I φ = Vol. Liquid / Vol. Bulk

(18)

Multiple phases

Bulk Sediments = Solid + Liquid

Until now :

I Concentrations

Mass / Vol. of Bulk Sediments

Different transport processes → need to express different phases.

I for Solutes

Mass / Vol. of liquid

I for Solids

Mass / Vol. of solid

Useful for conversion: Porosity (φ)

(19)

Multiple phases : porosity

Porosity : φ = volume of pore watersvolume sediments

Figure 1:Examples of porosity profiles

Figure 2:Upper porosity and grain size

(20)

Multiple phases : porosity

Porosity:

φ = Vol. Liquid / Vol. Bulk 1 − φ = Vol. Solid / Vol. Bulk

Example : Solid Dissolution

S (solid)−→ C (dissolved)γ

∂S

∂t = −γS (No Transport)

S Conc. in solid [mmol m−3solid]

γ diss. rate [d−1]

C Conc. in liquid [mmol m−3liquid]

The effect on liquid phase will be :

∂C

∂t = γS .

1−φ φ

(21)

Multiple phases : porosity

Porosity:

φ = Vol. Liquid / Vol. Bulk 1 − φ = Vol. Solid / Vol. Bulk

Example : Solid Dissolution

S (solid)−→ C (dissolved)γ

∂S

∂t = −γS (No Transport)

S Conc. in solid [mmol m−3solid]

γ diss. rate [d−1]

C Conc. in liquid [mmol m−3liquid]

The effect on liquid phase will be :

∂C

∂t = γS .

1−φ φ

(22)

Multiple phases : porosity

Porosity:

φ = Vol. Liquid / Vol. Bulk 1 − φ = Vol. Solid / Vol. Bulk

Example : Solid Dissolution

S (solid)−→ C (dissolved)γ

∂S

∂t = −γS (No Transport)

S Conc. in solid [mmol m−3solid]

γ diss. rate [d−1]

C Conc. in liquid [mmol m−3liquid]

The effect on liquid phase will be :

∂C

∂t = γS .

1−φ φ

(23)

Multiple phases : Different transport processes

Liquids

I Diffusion is due to molecular diffusion

I Advection is due to liquid flow with respect to the SWI.

Solid

I Diffusion is due to bioturbation

I Advection is due to solid advection with respect to the SWI

(sedimentation or compression) Liquids JLiq.= −Dsed ∂C ∂x + vLC Tortuosity Dsed = Dsea water 1 − ln(φ2) Boudreau, 1996

(24)

Multiple phases : Different transport processes

Liquids

I Diffusion is due to molecular diffusion

I Advection is due to liquid flow with respect to the SWI.

I Sedimentation

I Compaction

I Biological activity

I Pressure gradients in permeable sediments.

Solid

I Diffusion is due to bioturbation

I Advection is due to solid advection with respect to the SWI

(sedimentation or compression)

Liquids

JLiq.= −Dsed

∂C

(25)

Multiple phases : Different transport processes

Liquids

I Diffusion is due to molecular diffusion

I Advection is due to liquid flow with respect to the SWI.

Solid

I Diffusion is due to bioturbation

I Advection is due to solid advection with respect to the SWI

(sedimentation or compression) Liquids JLiq.= −Dsed ∂C ∂x + vLC Solids JSol . = −Db ∂S ∂x + vSS

(26)

Bioirrigation

Flushing of burrows with overlying waters

Allows diffusive exchanges between bottom waters and porewaters at depth, through burrow walls

→ 3D(2D) context.

However, Boudreau (1984) showed the equivalence of

I 3D set-up with cylindrical burrows

(27)

1. Reaction-Transport Models in 1D

2. Porous Media

3. Reaction-Transport in Porous Media

4. Diagenetic Reaction Processes

(28)

Reactive Transport in Porous Media

Solutes ∂φxC ∂t = − ∂ ∂x [φxJL] + φxRL Solids ∂(1 − φx)S ∂t = − ∂ ∂x [(1 − φx)JS] + (1 − φx)RS

Boundary Conditions (usual)

Solutes

@ Upper boundary (x = 0) Imposed conc. (Cbot. waters).

@ Lower boundary (x = ∞) Zero Gradient

Solids

@ Upper boundary (x = 0) Imposed flux (sedimentation).

@ Lower boundary (x = ∞) Zero Gradient

(29)

Reactive Transport in Porous Media

Solutes ∂φxC ∂t = ∂ ∂x  φx(Dsed ∂C ∂x − vLC )  + φxRL Solids ∂(1 − φx)S ∂t = ∂ ∂x  (1 − φx)(Db ∂S ∂x − vSS )  + (1 − φx)RS

Boundary Conditions (usual)

Solutes

@ Upper boundary (x = 0) Imposed conc. (Cbot. waters).

@ Lower boundary (x = ∞) Zero Gradient

Solids

@ Upper boundary (x = 0) Imposed flux (sedimentation).

@ Lower boundary (x = ∞) Zero Gradient

(30)

Reactive Transport in Porous Media

Solutes ∂C ∂t = 1 φx ∂ ∂x  φx(Dsed ∂C ∂x − vLC )  + RL Solids ∂S ∂t = 1 1 − φx ∂ ∂x  (1 − φx)(Db ∂S ∂x − vSS )  + RS

Boundary Conditions (usual)

Solutes

@ Upper boundary (x = 0) Imposed conc. (Cbot. waters).

@ Lower boundary (x = ∞) Zero Gradient

Solids

@ Upper boundary (x = 0) Imposed flux (sedimentation).

@ Lower boundary (x = ∞) Zero Gradient

(31)

Reactive Transport in Porous Media

Solutes ∂C ∂t = 1 φx ∂ ∂x  φx(Dsed ∂C ∂x − vLC )  + RL Solids ∂S ∂t = 1 1 − φx ∂ ∂x  (1 − φx)(Db ∂S ∂x − vSS )  + RS

Boundary Conditions (usual)

Solutes

@ Upper boundary (x = 0) Imposed conc. (Cbot. waters).

@ Lower boundary (x = ∞) Zero Gradient

Solids

@ Upper boundary (x = 0) Imposed flux (sedimentation).

@ Lower boundary (x = ∞) Zero Gradient

(32)

Reactive Transport in Porous Media

Solutes ∂C ∂t = 1 φx ∂ ∂x  φx(Dsed ∂C ∂x − vLC )  + RL Solids ∂S ∂t = 1 1 − φx ∂ ∂x  (1 − φx)(Db ∂S ∂x − vSS )  + RS

Boundary Conditions (usual)

Solutes

@ Upper boundary (x = 0) Imposed conc. (Cbot. waters).

@ Lower boundary (x = ∞) Zero Gradient

Solids

@ Upper boundary (x = 0) Imposed flux (sedimentation).

@ Lower boundary (x = ∞) Zero Gradient

(33)

Reactive Transport in Porous Media

Solutes ∂C ∂t = 1 φx ∂ ∂x  φx(Dsed ∂C ∂x − vLC )  + RL Solids ∂S ∂t = 1 1 − φx ∂ ∂x  (1 − φx)(Db ∂S ∂x − vSS )  + RS

Boundary Conditions (usual)

Solutes

@ Upper boundary (x = 0) Imposed conc. (Cbot. waters).

@ Lower boundary (x = ∞) Zero Gradient

Solids

@ Upper boundary (x = 0) Imposed flux (sedimentation).

@ Lower boundary (x = ∞) Zero Gradient

(34)

1. Reaction-Transport Models in 1D

2. Porous Media

3. Reaction-Transport in Porous Media

4. Diagenetic Reaction Processes

(35)

Organic Matter Lability I

Figure 3:Example of Org. C degradation

Large chain generally replaced by one step reaction Part. OrgC −R−→ DICG

RG = k.G .

X

i

FTEM,iFBIO,iFTEA,iFIN,iFT ,i

G Organic Matter RG Degradation rate,

k max degradation rate, i metabolic pathways, FTEM,i Temperature effect

FBIO,i Microbial biomasses

FTEA,i Terminal electron acceptor

FIN,i Inhibition by other TEA

FT ,i bioenergetic limitation (Gibbs energy)

According to complexity, several factors are empirically included in k

(36)

Organic Matter Lability II

Single G neglects

I Various organic compounds

in OM source :

I Refractory OM formed

during bacterial remin. Arndt,2013 (review) : I Multi-G model RG = P ikiGi I Continuous lability spectrum models RG = − ∞ R 0 kg (k)dk I OM degradation explicitely driven by ecosytem dynamics (incl. bact.)

(37)
(38)

Redox zonation II

(39)
(40)

Phosphorus cycling I

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1. Reaction-Transport Models in 1D

2. Porous Media

3. Reaction-Transport in Porous Media

4. Diagenetic Reaction Processes

(42)

Case Study : Oxygen diffusion

I We consider dissolved Oxygen (only liquid phase).

I Non-permeable sediments → No liquid flow, no advection.

I Constant oxygen consumption rate above a certain depth, 0 below.

∂O2(z) ∂t = ∂ ∂z[D ∂C ∂z] − γ(z) γ(z) = γ0. O2(z) O2(z) + ks (3) I Boundary conditions: O2|z=0= O2 b.w .; ∂O∂z2|z=∞= 0

I Steady-state solution : ∂O2

∂t = 0 φ Porosity D Diffusion coeficient γ0 Respiration rate ks “Oxygen Limitation” O2 b.w . [O2] bottom waters

(43)

Case Study : Oxygen diffusion

I We consider dissolved Oxygen (only liquid phase).

I Non-permeable sediments → No liquid flow, no advection.

I Constant oxygen consumption rate above a certain depth, 0 below.

∂O2(z) ∂t = ∂ ∂z[D ∂C ∂z] − γ(z) γ(z) = γ0. O2(z) O2(z) + ks (3) I Boundary conditions: O2|z=0= O2 b.w .; ∂O∂z2|z=∞= 0

I Steady-state solution : ∂O2

∂t = 0 φ Porosity D Diffusion coeficient γ0 Respiration rate ks “Oxygen Limitation” O2 b.w . [O2] bottom waters

(44)

Case Study : Oxygen diffusion

I We consider dissolved Oxygen (only liquid phase).

I Non-permeable sediments → No liquid flow, no advection.

I Constant oxygen consumption rate above a certain depth, 0 below.

∂O2(z) ∂t = ∂ ∂z[D ∂C ∂z] − γ(z) γ(z) = γ0. O2(z) O2(z) + ks (3) I Boundary conditions: O2|z=0= O2 b.w .; ∂O∂z2|z=∞= 0

I Steady-state solution : ∂O2

∂t = 0 φ Porosity D Diffusion coeficient γ0 Respiration rate ks “Oxygen Limitation” O2 b.w . [O2] bottom waters

(45)

Case Study : Oxygen diffusion

I Describe model implementation in R (using the Reactran framework)

I Compare with oxygen profile from the mud sediment core

I Infer diffusive flux at the Sediment-Water interface

I Extend the model :

I Include Solid phase for organic carbon

I Include Bioirrigation

(46)

Why do we consider cohesive sediments ?

Sands

→ Permeability

→ Needs to resolve flows through the sediment matrix → Needs higher dimensional context.

Figure

Figure 2: Upper porosity and grain size
Figure 3: Example of Org. C degradation

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