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BACCALAURÉAT GÉNÉRAL ET TECHNOLOGIQUE SESSION 2010

ÉPREUVE SPÉCIFIQUE MENTION « SECTION EUROPÉENNE OU DE LANGUE ORIENTALE » Académies de Paris-Créteil-Versailles

Binôme : Anglais / Mathématiques SEQUENCES

Sujet D3 - 4

The first part of this page is a summary that can be useful to do the exercises.

Sequences

A geometric progression (G.P.) is a sequence in which each term after the first is formed by multiplying the preceding term by a fixed number, called the common ratio.

If a1 is the first term and r is the common ratio, the nth term is: an = a1 rn-1.

Exercise:

A statistical study ordered by a theatre manager gave the following result: each year the rate of subscription renewal is 90% and there are 1000 new subscribers. Suppose that this observation is still valid for the following years. Today there are 7000 subscribers.

Let u be the number of subscribers today, 1 u be the number of subscribers for next year, etc.2 1. a) Prove that u2 equals 7300.

b) Write un1in terms of un.

2.

 

vn is the sequence defined by vn 10,000un Fill in the following table with exact values.

n 1 2 3 4

n

u

n

v

3. a) Could (un) be a geometric progression? What about (vn) ?

b) Knowing that vn110,000un1, prove that vn1 0.9vn. Conclude.

c) Write vn in terms of v1and n. Find vn then un in terms of n.

d) With this formula, check the results on the bottom line of the table, then find what the number of subscribers will be in ten years.

e) Could there be more than 10,000 subscribers?

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