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, (92)

where

¯λAB =

(FA1? FB1)(ωAB) (FA1? FB2)(ωAB)

...

(FAKdA ? FBKdB)(ωAB)

, (93)

is the locally tomographic part and

ηAB=

FAB1AB) ...

FABKdAdB−KdAKdBAB)

, (94)

is the holistic part. The probability for a joint outcomeFA? FB is given by:

(FA? FB)(ωAB) = ( ¯EFAE¯FBλ¯AB (95) Joint local effects are computed using the locally tomographic part of the state space only.

F.4 The reduced state space

The reduced states for Alice and Bob can be computed as follows:

ω¯A = (¯ΓdA(IA)⊗uBλAB (96) ω¯B = (uA⊗Γ¯dB(IB))¯λAB (97) Reduced states are determined using only the locally tomographic part of the global state.

G Toy model

In this appendix we show that the toy model introduced in section 4 meets consistency constraints C1 -C5(apart from associativity of the ?product).

G.1 Constraints C1 and C2

It is immediate that consistency constraintsC1and C2 are met by the toy model.

G.2 Constraint C3

We prove(FA? FB)(ψAφB) =FAA)FBB): (FA? FB)(ψAφB)

= tr|ψihψ|⊗2A |φihφ|⊗2B ( ˆFAFˆB+tr( ˆFAFˆB)

tr(SASB)AAAB)

=tr|ψihψ|⊗2A |φihφ|⊗2B FˆAFˆB

=FAA)FBB) . (98)

In the penultimate line we have used the fact that the overlap of product states|ψihψ|⊗2A |φihφ|⊗2B andAAAB

is0.

G.3 Constraint C4

In the following it will occasionally useful to label the two copies of CdA with 1 and 3 and to label the two copies ofCdB with 2 and 4. We write S˜A for the normalised projector onto the symmetric subspace of (CdA)⊗2. We make use of the identityS= 12(I+ SWAP) throughout this section.

In this section we show that normalised conditional states for Alice are valid states of a CdA system. We first show this for the specific case where the state is conditioned on the unit effect, i.e. is a reduced state.

A reduced state of Alice for a bi-partite system in pure state|ψABihψAB|⊗2 is:

ω¯A = trBSBABihψAB|⊗2+ SA

trSAtrABAAABABihψAB|⊗2 . (99) We show that these reduced states lie in the convex hull of|ψAihψA|⊗2.

Lemma 9. SBABi⊗2 =SASBABi⊗2 Proof.

ABi⊗2 =αi1i2αi3i4|i1i2i3i4i . (100) SBABi⊗2 = 1

2αi1i2αi3i4(|i1i2i3i4i+|i1i4i3i2i). (101) Let us relabeli1i3 in the last term:

SBABi⊗2 = 1

2(αi1i2αi3i4|i1i2i3i4i+αi3i2αi1i4|i3i4i1i2i). (102) SASBABi⊗2 = 1

4αi1i2αi3i4(|i1i2i3i4i+|i1i4i3i2i+|i3i2i1i4i+|i3i4i1i2i) . (103) Let us relabel i1i3 in the second term , i2i4 in the penultimate term andi1i3 and i2i4 in the last term :

SASBABi⊗2= 1

4(αi1i2αi3i4|i1i2i3i4i+αi3i2αi1i4|i3i4i1i2i (104) +αi1i4αi3i2|i3i4i1i2i+αi1i2αi3i4|i1i2i3i4i) = 1

2(αi1i2αi3i4|i1i2i3i4i+αi3i2αi1i4|i3i4i1i2i). (105)

From the above lemma we can write a reduced state ω:¯ ω¯A = trBSASBABihψAB|⊗2+ SA

trSA

trABAAABABihψAB|⊗2 . (106) Lemma 10. The reduced state ¯ωA can be written as:

ω¯A=SAAρA)SA+ (1−tr(SAAρA)SA)) ˜SA , (107) whereρA= trB(|ψihψ|AB).

Proof. We first show that:

trB(SASB|ψihψ|⊗2AB) =SAAρA)SA . (108) From the proof of Lemma 9:

SASBABi⊗2 = 1

4αi1i2αi3i4(|i1i2i3i4i+|i1i4i3i2i+|i3i2i1i4i+|i3i4i1i2i) . (109) Hence:

SASBABihψAB|⊗2 =1

4αi1i2αi3i4α¯j1b1α¯j3b2(|i1i2i3i4ihj1j2j3j4| (110) +|i1i4i3i2ihj1j2j3j4|+|i3i2i1i4ihj1j2j3j4|+|i3i4i1i2ihj1j2j3j4|). (111)

which implies:

trB(SASB|ψihψ|⊗2AB) = 1

2αi1b1αi3b2α¯j1b1α¯j3b2(|i1i3ihj1j3|+|i3i1ihj1j3|) . (112) We now computeSAAρA)SA.

|ψihψ|AB=αi1i2α¯j1j2|i1i2ihj1j2|. (113) ρA= trB(|ψihψ|AB) =αi1b1α¯j1b1|i1ihj1|. (114) ρAρA =αi1b1αi3b2α¯j1b1α¯j3b2|i1i3ihj1j3|. (115) SAAρA) = 1

2αi1b1αi3b2α¯j1b1α¯j3b2(|i1i3ihj1j3|+|i3i1ihj1j3|) . (116) SAAρA)SA =1

4αi1b1αi3b2α¯j1b1α¯j3b2(|i1i3ihj1j3|+|i3i1ihj1j3|) (117) +1

4αi1b1αi3b2α¯j1b1α¯j3b2(|i1i3ihj3j1|+|i3i1ihj3j1|) . (118) In the second term we relabel j1j3,i1i3 and b1b2 to obtain:

SAAρA)SA = 1

2(αi1b1αi3b2α¯j1b1α¯j3b2(|i1i3ihj1j3|+|i3i1ihj1j3|)) . (119) Hence,

ω¯A=SAAρA)SA+ (1−tr(|ψihψ|⊗2ABSASB)) ˜SA

=SAAρA)SA+ (1−tr(SAAρA)SA)) ˜SA . (120)

Lemma 11. The reduced states ¯ωA belong to the convex hull of the local pure states |ψihψ|⊗2. Proof. By Lemma10 the reduced state can be written as:

ω¯A=SAAρA)SA+ (1−tr(SAAρA)SA)) ˜SA , (121) whereρA= trB(|ψihψ|AB). In the following we drop the Alabel.

ρ=X

i

αi|iihi|, (122)

Here the |ii are not necessarily orthogonal. The trace of ρ is Piαi = 1, where αi > 0. Let us write Φij = 1

2(|i, ji+|j, ii) and observe:

X

i6=j

ijihΦij|= 2X

i<j

ijihΦij|=X

i6=j

(|i, jihi, j|+|i, jihj, i|) . (123) Consider the (not necessarily normalised) matrix

S(ρρ)S=S(X

ij

αiαj|i, jihi, j|)S =X

i

α2i|i, iihi, i|+X

i<j

αiαjijihΦij|, (124) The trace of this matrix is 1−Pi<jαiαj; hence:

ω¯ =X

i

α2i|i, iihi, i|+X

i<j

αiαjijihΦij|+X

i<j

αiαjS .˜ (125)

We now show that this arbitrary mixed state ¯ω can be expressed as a convex combination of local pure states|ψihψ|⊗2. Consider the general vector

|ψi=X

i

ej

αj|ji , (126)

whereαj ≥0 and for allj. Normalisation impliesPjαj = 1. Now, let us write the pure product state

|ψihψ|⊗2 = X

j,k,j0,k0

ejeke−iθj0e−iθk0

αjαkαj0αk0|j, kihj0, k0|. (127) Let us make the following observations. When j6=j0:

Z π

−π

e−iθjej0jj0 = 0 . (128) When j=j0:

Z π

−π

e−iθjej0jj0 = (2π)2 . (129) Now consider:

Eθi|ψihψ|⊗2 = 1 (2π)4

Z π

−π

X

j,k,j0,k0

ejeke−iθj0e−iθk0

αjαkαj0αk0|j, kihj0, k0|dθjkj0k0 . (130) The non zero contributions will arise from the following terms:

j=j0 =k=k0:

Z π

−π

|ej|4jkj0k0 = (2π)4 . (131) j=j0 6=k=k0:

Z π

−π

|ej|2|ek|2jkj0k0 = (2π)4 . (132) j=k0 6=k=j0:

Z π

−π

|ej|2|ek|2jkj0k0 = (2π)4 . (133) All other contributions will be zero.

Now, we write the mixed state corresponding to the uniform average over all values of the phases θi, ω¯1 =Eθi|ψihψ|⊗2=X

j,k

αjαk|j, kihj, k|+X

j6=k

αjαk|j, kihk, j|, (134) where the first term arises from contributions (131) and (132) and the second term arises from contribu-tion (133). Then we can write

ω¯1 =X

i

α2i|i, iihi, i|+ 2X

i<j

αiαjijihΦij|, (135) Let us take the state:

ω¯2=X

i

α2i|i, iihi, i|+ 2X

i<j

αiαjS .˜ (136)

This is a mixture of states of the form|ψihψ|⊗2 since ˜S =R |ψihψ|⊗2 andPiα2i + 2Pi<jαiαj = 1. If we take the mixture 12ω1+ ¯ω2) we obtain (125).

We now consider the more general case where Alice’s state is conditioned on an arbitrary effectFB. The conditional state for Alice given one of Bob’s effectsFB is:

ω¯A|FB = TrB(SAFˆB|ψihψ|⊗2AB) + Tr(|ψihψ|⊗2ABAAAB)Tr( ˆFB) Tr(SB)

S˜A . (137)

Although effects of the formFˆB =|φihφ|⊗2 are not valid (since the complement effects would not be of the required form), we calculate the conditional state for such effects, as this will allow us to later determine conditional states for general effectsFˆB =Piαiiihφi|⊗2.

Lemma 12. For ˆFB =|φihφ|⊗2:

TrB(SAFˆB|ψihψ|⊗2AB) =SAψA|φρψA|φ)SA =ρψA|φρψA|φ, (138) whereρψA|φ= Tr((IA⊗ |φihφ|B)|ψihψ|AB) .

Proof.

TrB(SAFˆB|ψihψ|⊗2AB) =SATrB( ˆFB|ψihψ|⊗2AB) =SAψA|φρψA|φ) . (139) Let

ρψA|φ= Tr (IA⊗ |φihφ|B)|ψihψ|AB= X

i1,j1

αi1α¯j1|i1ihj1|. (140) We assume without loss of generality that|φi is one of the basis vectors|ii.

ρψA|φρψA|φ= X

i1,i3,j1,j3

αi1α¯j1αi3α¯j3|i1i3ihj1j3|. (141)

SAA|φρA|φ) =1 2( X

i1,i3,j1,j3

αi1α¯j1αi3α¯j3|i1i3ihj1j3|

+ X

i1,i3,j1,j3

αi1α¯j1αi3α¯j3|i3i1ihj1j3|) . (142)

We relabeli1i3 on the last line to obtainSAA|φρA|φ) = (ρA|φρA|φ).

SAA|φρA|φ)SA= 1 4( X

i1,i3,j1,j3

αi1α¯j1αi3α¯j3|i1i3ihj1j3|

+ X

i1,i3,j1,j3

αi1α¯j1αi3α¯j3|i3i1ihj1j3|+ X

i1,i3,j1,j3

αi1α¯j1αi3α¯j3|i1i3ihj3j1|

+ X

i1,i3,j1,j3

αi1α¯j1αi3α¯j3|i3i1ihj3j1|) . (143) We relabelj1j3 on the last two lines to obtainSAA|φρA|φ) =SAA|φρA|φ)SA.

We need one more lemma before proving that normalised conditional states belong to the convex hull of the local pure states|ψihψ|⊗2A .

Lemma 13. If S(ρρ)S =ρρ with Tr(ρ) = 1 thenρρ=Pipiiihψi|⊗2. Proof. By Lemma11 this is a valid reduced state and belongs to conv(|ψihψ|2).

We observe that since all pure states are such thatS(|ψihψ|⊗2)S=|ψihψ|⊗2 andTr(|ψihψ|⊗2) = 1, we can characterise the state space of the systems of the toy model as being given byconv(ρ⊗ρ)for all normalised density operators such thatS(ρρ)S=ρρ.

Lemma 14. The normalised conditional states ˜ωA|FB belong to the convex hull of the local pure states

|ψihψ|⊗2.

Proof. We first show that the conditional state is a valid local state for effects ˆFB =|φihφ|⊗2. As a conditional state, this state can be subnormalised.

ω¯A|FB = TrB(SAFˆB|ψihψ|⊗2AB) +cS˜A , (144)

wherec= Tr(|ψihψ|⊗2ABAAAB)Tr( ˆTr(SFB)

B). By Lemma12 we have the equivalence:

TrB(SAFˆB|ψihψ|⊗2AB) = (ρψA|φρψA|φ). (145) The normalised conditional state is:

ω˜A|FB = ω¯A|FB

Tr(¯ωA|FB) . (146)

Let us set e= Tr(¯ωA|FB) and d= Tr(SAFˆB|ψihψ|⊗2AB) = Tr(ρψA|φρψA|φ);e=c+d.

ω˜A|FB = 1

eA|φρA|φ) +c e

S˜A . (147)

We use the equalityρψA|φρψA|φ=d( ˜ρψA|φρ˜ψA|φ) where ˜ρψA|F is a standard normalised quantum conditional state.

ω˜A|FB =d

e( ˜ρψA|φρ˜ψA|φ) +c e

S˜A . (148)

By Lemma 12 ρ˜ψA|φρ˜ψA|φ = SA( ˜ρψA|φρ˜ψA|φ)SA hence by Lemma 13 it is a valid normalised state (i.e. of the form Pipiiihψi|⊗2). Since 0 < de <1, 0 < ce <1 and d+ce = 1 the above is a convex combination of ρ˜ψA|φρ˜ψA|φ and ˜SA which are both valid states. Hence the state ˜ωA|FB is a valid local state.

LetFB =Pαiiihφi|⊗2, withαi>0.

ω¯A|FB =X

i

αi(TrB(SAFˆBiihφi|⊗2|ψihψ|⊗2AB) + Tr(|ψihψ|⊗2ABAAAB) 1 Tr(SB)

S˜A)

=X

i

αiψA|φ

iρψA|φ

i) +ciS˜A) . (149)

Lete= tr(ωA|FB) anddi = tr(ρψA|φ

iρψA|φ

i). We havee=Piαi(ci+di). From above:

ω˜A|FB =X

i

αi(di

e( ˜ρψA|φ

iρ˜ψA|φ

i) +ci

e

S˜A) . (150)

Since 0 < αiedi < 1 and 0 < Pi αieci < 1 and Piαi(cie+di) = 1 the above is a convex combination of ( ˜ρψA|φ

iρ˜ψA|φ

i) with coefficients αiedi and the state ˜SA with coefficient Pi αieci. G.4 Constraint C5

In this section we show that every OPFs in FdG

AdB applied to a product state ψAφB has a corresponding OPFFA0 inFdL

A. LetFAB be an arbitrary effect inFdL

AdB. The corresponding operator is FˆAB=X

i

αi|xiihxi|12⊗ |xiihxi|34 . (151) We evaluate it on product states:

FABAφB) =X

i

αiTr |ψihψ|⊗2A |φihφ|⊗2B (|xiihxi|⊗2AB)

=X

i

αiTrA(|ψihψ|⊗2A TrB(|φihφ|⊗2B (|xiihxi|⊗2AB)))

=X

i

αiTrA(|ψihψ|⊗2A SATrB(IA|φihφ|⊗2B |xiihxi|⊗2AB))

= TrA(|ψihψ|⊗2A (X

i

αi(SAxA|φiρxA|φi )SA))). (152)

By Lemma13(SAxA|φ⊗ρxA|φ)SAis of the formPjβjjihφj|⊗2withβj ≥0. HenceFˆA0 = (Piαi(SAxA|φiρxA|φi )SA) is a valid effect on A as long as its complement is also of the form Piγiiihφi|⊗2. Since the complement ofFˆAB is of the formPiαi|xiihxi|12⊗ |xiihxi|34it follows that the associated effect on A(which is the complement of FˆA0) is of the required form. From this it follows that FˆA0 is a valid effect. The set FdG

AdB also contains effects FA? FB which are not necessarily of the form given above. However since these are product effects they trivially are consistent with C5.

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