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5. Proof of the main theorem

5.1. The regular case

Fix integersd, e >0 and fixμ∈ P. Assume that the weights oμ,−, oφ,− have the level

−e−N and−d−N respectively.

Letw∈Iμ,+ and putu=w−1, v =w−1 andz =w. Note thatu∈Iφ,+μ , v∈Iφ,−μ andz∈Iμ,−.

The first step is to compare the algebraswAμ,+ = EndwOμ,+(wPμ,+)op and vA¯μφ,− = ExtvOμφ,−(vLμφ,−)op, and, then, the algebras wA¯μ,+ = ExtwOμ,+(wLμ,+)op and vAμφ,− = EndvOμφ,−(vPμφ,−)op. More precisely, we prove the following.

Proposition 5.1. If x wIμ,+ and y = x1, then y vIφ,−μ . We have a k-algebra iso-morphism wAμ,+ =vA¯μφ, such that 1x 1y for each x∈wIμ,+. We have a k-algebra isomorphismwA¯μ,+=vAμφ,such that1x1y for eachx∈wIμ,+. The gradedk-algebras

wA¯μ,+ andvA¯μφ,are Koszul and are Koszul dual to each other. Further, we have1x= 1!y for each x∈wIμ,+.

Proof. ByCorollaries 4.34, 4.49, composingH,Vk yields k-algebra isomorphisms

wAμ,+=wAμ,+=vA¯μφ,−, (5.1) which identify the idempotents 1y vA¯μφ,− and 1x wAμ,+,wAμ,+ for each x∈ wIμ,+

andy=x−1 .

Now, we claim thatvAμφ,− has a Koszul grading. ByLemma 2.2and Section3.5, it is enough to check thatvAφ,− has a Koszul grading. This follows from the matrix equation inProposition 4.29and from [5, thm. 2.11.1], becausevAφ,− =vAφ,− as k-algebras by Corollary 4.34.

EquipvAμφ, with the Koszul grading above. Then, Lemma 2.1implies that

vAμ,!φ,= ExtvOμφ,−v Lμφ,op

=vA¯μφ,. (5.2) Thus, the graded k-algebra vA¯μφ,− is also Koszul. Since wAμ,+ =vA¯μφ,− as a k-algebra, this implies that thek-algebrawAμ,+ has a Koszul grading.

ApplyingLemma 2.1once again, we get

wA!μ,+= ExtwOμ,+w Lμ,+op

=wA¯μ,+. (5.3)

In particular, the gradedk-algebrawA¯μ,+ is also Koszul.

Finally, using(5.2),(5.1)and(5.3)we getk-algebra isomorphisms

vAμφ,=vA¯μ,!φ,=wA!μ,+=wA¯μ,+.

They identify the idempotent 1yvAμφ, with the idempotent 1xwA¯μ,+. 2

Remark 5.2. The Koszul grading on vAμφ, can also be obtained using mixed perverse sheaves on the ind-schemeX as in[5, thm. 4.5.4],[1]. Note that there is no analogue of [5, lem. 3.9.2] in our situation, becausevRφ,− is not Koszul self-dual.

The second step consists of comparing the k-algebras zA¯μ,− = ExtzOμ,(zLμ,−)op,

uAμφ,+ = EnduOμφ,+(uPμφ,+)op and the k-algebras zAμ,− = EndzOμ,+(wPμ,−)op, uA¯μφ,+ = ExtuOμφ,+(uLμφ,+)op.

We cannot argue as in the previous proposition, because we have no analogue of the localization functorΦinProposition 4.47for positive levels. Hence, we have no analogue of Proposition 4.48andCorollary 4.49.

To remedy this, we’ll use the technic of standard Koszul duality. To do so, we need the following crucial result.

Lemma 5.3.The quasi-hereditary k-algebrawAμ,+ has a balanced grading.

Now we can prove the second main result of this section.

Proposition 5.4. If x∈zIμ, andy =x−1+ then y uIφ,+μ . We have a k-algebra isomor-phismzA¯μ,=uAμφ,+ such that1x1y for eachx∈zIμ,, and ak-algebra isomorphism

zAμ,− =uA¯μφ,+ such that 1x 1y for each x∈zIμ,−. The graded k-algebrasuA¯μφ,+ and

zA¯μ,− are Koszul and are Koszul dual to each other. Further, we have1x= 1!y for each x∈zIμ,−.

Proof. ByProposition 3.9, the Ringel dual ofwAμ,+ iswAμ,+=zAμ,. Thus, since the k-algebrawAμ,+ has a balanced grading by Lemma 5.3, we deduce that the k-algebra

zAμ, has a Koszul grading.

We equip zAμ,− with this grading. Then,Lemma 2.1implies that

zA!μ,= ExtzOμ,−z Lμ,−op

=zA¯μ,−. (5.4)

Hence, the gradedk-algebrazA¯μ, is Koszul and balanced.

Therefore, [29, thm. 1], Proposition 3.9and (5.4)yield ak-algebra isomorphism

zA¯μ,− =zA!μ,=z

Aμ,!

=w A!μ,+

.

Hence, using (5.3)and Propositions 5.1, 3.9, we get ak-algebra isomorphism

zA¯μ,−=wA¯μ,+=vAμ,φ,=uAμφ,+

such that 1x1y. So, thek-algebrauAμφ,+ has a Koszul grading which is balanced.

We equip uAμφ,+ with this grading.Lemma 2.1implies that

uAμ,!φ,+ = ExtuOμφ,+u Lμφ,+op

=uA¯μφ,+. (5.5)

Hence, the gradedk-algebrauA¯μφ,+ is Koszul and balanced.

Therefore,[29, thm. 1],Proposition 3.9yield

uA¯μφ,+=uAμ,!φ,+=u

Aμ,φ,+!

=v Aμ,!φ,

.

So, using(5.2)andPropositions 5.1, 3.9, we get ak-algebra isomorphism

uA¯μφ,+=vA¯μφ,

=wAμ,+=zAμ,. 2 Now, let us proveLemma 5.3.

Proof of Lemma 5.3. We equip wAμ,+ with the grading given by vA¯μφ,−, see Proposi-tion 5.1. Since vA¯μφ, is Koszul, we must prove that vA¯μ,!φ, is quasi-hereditary and that the grading onvA¯μ,φ, is positive, see Section2.6.

We have vA¯μ,!φ,− =wA¯μ,+ byProposition 5.1. Hence, it is quasi-hereditary. Next, the grading ofzA¯μ,− is positive byRemark 4.30. Thus, to prove the lemma, it is enough to check that we have a gradedk-algebra isomorphism vA¯μ,φ, =zA¯μ,.

First, we check thatwAμ,+=zAμ, as (ungraded)k-algebras.

To do this, note thatProposition 3.9(c) yields ak-algebra isomorphismwAμ,+=zAμ,. Further, we have zAμ,− = EndzOμ,−(zPμ,−)op and, by Proposition 3.9(b), the Ringel equivalence takeszOΔμ, to zOΔμ,+. Thus, Propositions 2.4(b),4.33(c) yield

wAμ,+= EndzOμ,+

z Tμ,+

op

=kEndzOS0,μ,+z

TS0,μ,+op

=kEndzZS0,μ,+z

CS0,μ,+op

=zAμ,−, where the last equality isDefinition 4.28.

Now, we must identify the gradings of vA¯μ,φ,− and zA¯μ,− under the isomorphism

wAμ,+=zAμ,− above.

First, we consider the grading onvA¯μ,φ,. LetwT¯μ,+be the gradedvA¯μφ,-module equal to wTμ,+ as an wAμ,+-module, with the natural grading (this is well-defined, because

vA¯μφ,− is Koszul). Then, by Section2.6, we havevA¯μ,φ,−= EndwAμ,+(wT¯μ,+)op.

Next, we consider the grading on zA¯μ,−. By Corollary A.6, we have zA¯μ,− = kEndwZS,μ,+(wC¯S,μ,+) = EndwZμ,+(wC¯μ,+).

Let us identifywAμ,+=wAμ,+ via(5.1). We must prove the following.

Claim 5.5.There is a graded k-algebra isomorphism EndwAμ,+wT¯μ,+

= EndwZμ,+

wC¯μ,+

. To do that, we’ll need some new material.

Consider the graded categories given by wO¯μ,+ = wA¯μ,+-gmod and wO¯S,μ,+ =

wA¯S,μ,+-gmod. Since we have wT¯μ,+ vA¯μφ,-gmod and wA¯μ,+ = vA¯μφ, by Corol-lary 4.49, we may viewwT¯μ,+ as an object of wO¯μ,+.

We have an isomorphism of graded S-algebras wA¯

S,μ,+ = EndwZS,μ,+(wB¯S,μ,+)op. Consider the pair of adjoint functors ( ¯VS¯S) betweenwO¯S,μ,+andwZ¯S,μ,+-gmodgiven by

S =wB¯S,μ,+wA¯S,μ,+:wO¯S,μ,+wZ¯S,μ,+-gmod, ψ¯S = HomwZS,μ,+(wB¯S,μ,+,•) :wZ¯S,μ,+-gmodwO¯S,μ,+. We consider the object wT¯S,μ,+ ofwO¯S,μ,+ given bywT¯S,μ,+= ¯ψS(wC¯S,μ,+).

Recall the functor VS0 :wOΔS0,μ,+ wZΔS0,μ,+ studied in Proposition 4.33. It yields anS0-algebra isomorphism EndwOS0,μ,+(wPS0,μ,+)opwAS0,μ,+. Thus, sincewPS0,μ,+

is a pro-generator of wOS0,μ,+, the functor φS0 = HomwOS0,μ,+(wPS0,μ,+,•) identifies

wOS0,μ,+ with the categorywAS0,μ,+-mod.

Consider the functor ψS0 : wZS0,μ,+-mod wAS0,μ,+-mod given by ψS0 = HomwZS0,μ,+(wBS0,μ,+,•). We have the commutative triangle

wOΔS0,μ,+ VS0

φS0

wZΔS0,μ,+

ψS0

wAS0,μ,+-mod,

(5.6)

such that VS0(wTS0,μ,+) = wCS0,μ,+. Now, we define the module wTS0,μ,+ = ψS0(wCS0,μ,+) in wAS0,μ,+-mod. It is identified with wTS0,μ,+ by φS0, because (5.6) is commutative. ByProposition 4.33(c), the functor ψS0 yields ak-algebra isomorphism EndwZS0,μ,+(wCS0,μ,+)EndwAS0,μ,+(wTS0,μ,+). Note thatφS0andψS0 are both exact.

Since taking Hom’s commutes with localization, we have ε(wA¯S,μ,+) = wAS0,μ,+. Thus, forgetting the grading and taking base change yield a functor ε : wO¯S,μ,+

wOS0,μ,+ which is faithful and faithfully exact, see Section4.2. LetwO¯ΔS,μ,+wO¯S,μ,+

be the full subcategory of the modules taken towOΔS0,μ,+ byε.

We identify wOS0,μ,+ withwAS0,μ,+-modbyφS0. We have the following.

Claim 5.6. We have the following commutative diagram

wO¯ΔS,μ,+ V¯S

ε

wZ¯ΔS,μ,+

ε ψ¯S

wO¯ΔS,μ,+

ε wOΔS0,μ,+ VS0 wZΔS0,μ,+

ψS0 wOΔS0,μ,+.

SincewAS0,μ,+ is Noetherian, any finitely generated module has a finite presentation.

ByProposition 4.33(c), the functorVS0 is exact and we haveVS0(wPS0,μ,+) =wBS0,μ,+. We identify wOS0,μ,+ with wAS0,μ,+-mod as above. By the five lemma, the canonical morphism wBS0,μ,+wAS0,μ,+ • → VS0 is an isomorphism. We deduce that the left square inClaim 5.6is commutative.

Next, by definition we haveε◦ψ¯S =ψS0◦ε. From the diagram5.6, we deduce that ψS0 maps intowOΔS0,μ,+ and is a quasi-inverse toVS0.Claim 5.6follows.

FromClaim 5.6 we deduce thatε(wT¯S,μ,+) =wTS0,μ,+ andwT¯S,μ,+wO¯ΔS,μ,+. Next, since ε : S-gmod S0-mod is faithfully exact by Section 4.2 and ψS0 gives an isomorphism EndwZS0,μ,+(wCS0,μ,+)EndwAS0,μ,+(wTS0,μ,+), we deduce from Claim 5.6 that ¯ψS gives a graded k-algebra isomorphism EndwZS,μ,+(wC¯S,μ,+) EndwAS,μ,+(wT¯S,μ,+).

Finally, since the functor ψS0 is exact and ε is faithfully exact by Section 4.2, we deduce fromClaim 5.6 that ¯ψS is exact onwZ¯ΔS,μ,+.

Now, by Definition 4.28, we have wA¯

μ,+ = kwA¯

S,μ,+. Thus, the specialization atk gives the modulekwT¯S,μ,+ inwO¯μ,+=wA¯μ,+-gmod.

Claim 5.7.We have kwT¯S,μ,+=wT¯μ,+.

The specialization gives a graded ring homomorphism kEndwAS,μ,+(wT¯S,μ,+) EndwAμ,+(kwT¯S,μ,+). Since ε(wT¯S,μ,+) = wTS0,μ,+, forgetting the grading it is taken to the obvious map kEndwOS

0,μ,+(wTS0,μ,+) EndwOμ,+(kwTS0,μ,+). The latter is an isomorphism by Proposition 2.4(b). Since kwT¯S,μ,+ = wT¯μ,+, we deduce that kEndwAS,μ,+(wT¯S,μ,+) = EndwAμ,+(wT¯μ,+).

Since we have kEndwZS,μ,+(wC¯S,μ,+) = EndwZμ(wC¯μ,+) and EndwZS,μ,+(wC¯S,μ,+) = EndwAS,μ,+(wT¯S,μ,+), this impliesClaim 5.5.

Now, we proveClaim 5.7. The grading ofwT¯μ,+is characterized in the following way.

First, we have a decomposition wT¯μ,+ =

xwT¯(xoμ,+) where wT¯(xoμ,+) is the natural graded lift of wT(x•oμ,+). SincewT(xoμ,+) is indecomposable inwOμ,+, it admits at most one graded lift in wO¯μ,+, up to grading shift. Let ¯V(xoμ,+) be the gradedvA¯μφ,-module equal toV(xoμ,+) as anwAμ,+-module, with the natural grading (this is well-defined, becausevA¯μφ,− is Koszul). The natural grading is characterized by the fact that there is an inclusion ¯V(xoμ,+)wT¯(xoμ,+) which is homogeneous of degree 0.

The graded objectwT¯S,μ,+ satisfies a similar property. Indeed, by Lemma 4.24, the graded S-sheaf wC¯S,μ,+(x) is filtered by shifted Verma-sheaves, and the lower term of this filtration yields an inclusion ¯VS,μ(x)l(x) ⊂wC¯S,μ,+(x). Further, consider the object

wT¯S(xoμ,+) inwO¯S,μ,+given bywT¯S(xoμ,+) = ¯ψS(wC¯S,μ,+(x)). Then, we have the decompositionwT¯S,μ,+=

xwT¯S(xoμ,+).

For each x wIμ,+, we consider also the object ¯VS(xoμ,+) in wO¯S,μ,+ given by V¯S(xoμ,+) = ¯ψS( ¯VS,μ(x))l(x). Since ¯ψS is exact, we deduce that wT¯S(xoμ,+)

is filtered by ¯VS(yoμ,+)’s, and the lower term of this filtration yields an inclusion V¯S(xoμ,+)wT¯S(xoμ,+) which is homogeneous of degree 0.

Now, by Proposition 4.33(c), we haveVS0(VS0(xoμ,+)) =VS0(x). From the proof of Claim 5.6, we deduce thatψS0(VS0(x)) =VS0(xoμ,+). Thus

εV¯S(xoμ,+)

=εψ¯S

V¯S,μ(x)

=ψS0εV¯S,μ(x)

=VS0(xoμ,+).

SinceVS0(xoμ,+) is free overS0, we deduce that ¯VS(xoμ,+) is free overSby Section4.2.

Therefore, the inclusion ¯VS(xoμ,+)wT¯S(xoμ,+) gives an inclusionkV¯S(xoμ,+) kwT¯S(xoμ,+) which is homogeneous of degree 0.

Hence, to prove Claim 5.7 we are reduced to check that we have ¯V(xoμ,+) = kV¯S(xoμ,+) inwO¯μ,+. Note that ¯V(xoμ,+) and kV¯S(xoμ,+) are both graded lifts of the Verma module V(xoμ,+), which is indecomposable. Thus they coincide up to a grading shift.

To identify this shift, recall that byLemma 4.24we have a surjection wB¯S,μ,+(x) V¯S(x)l(x). We define wP¯S(xoμ,+) = ¯ψS(wB¯S,μ,+(x)). Since ¯ψS is exact, we have a surjectionwP¯S(xoμ,+)→V¯S(xoμ,+).

Now, since vA¯μφ,− is Koszul, we can consider the natural graded lift wP¯(xoμ,+) of wP(xoμ,+) in wO¯μ,+. By definition of the natural grading, we have a surjection

wP(x¯ oμ,+)→V¯(xoμ,+).

So, we must prove that wP¯(xoμ,+) = kwP¯S(xoμ,+) in wO¯μ,+. This is obvious, because wP¯(xoμ,+) = wA¯

μ,+1x by definition of the natural grading ofwP(x•oμ,+), and becauseDefinition 4.28 yields the chain of isomorphisms

wP¯S(xoμ,+) = ¯ψSwB¯S,μ,+(x)

= EndwZS,μ,+wB¯S,μ,+op

1x=wA¯

μ,+1x. 2 We can now prove the following graded analogue of Corollary 4.34. See also Corol-lary 4.49.

Corollary 5.8.Assume that u∈Iφ,+μ . Let z =u−1 ∈Iμ,. We have an isomorphism of gradedk-algebrasuA¯μφ,+ zA¯μ, such that 1y1x withx=y−1 for each y∈vIφ,+μ . Proof. By[29, thm. 1]and Lemma 5.3, the gradedk-algebravA¯μ,φ, =zA¯μ,− is Koszul.

By Proposition 5.4, the graded k-algebrauA¯μφ,+ is Koszul and is isomorphic to wAμ,−

as a k-algebra. By Proposition 5.4, we have vA¯μφ, =wAμ,+ as ak-algebra. Finally, by Proposition 3.9, the Ringel dual ofwAμ,+ is wAμ,+ =zAμ,. Thus we have a k-algebra isomorphism zAμ, = zAμ,, which lifts to a graded k-algebra isomorphism uA¯μφ,+ =

zA¯μ, by unicity of the Koszul grading[5, cor. 2.5.2]. 2 5.2. The general case

We can now complete the proof ofTheorem 3.12. We first prove a series of preliminary lemmas.

Fix parabolic typesμ, ν ∈ P and integersd, e, f > 0. Choose integral weights oμ,−, oν,−, oφ,− of level−e−N,−f −N and −d−N respectively.

Fix an element w W. Let τφ,ν : wOμ,+ wOνμ,+ be the parabolic truncation functor, see Section3.5. Applying the functorτφ,νto the modulewPμ,+, we get ak-algebra homomorphismτφ,ν :wAμ,+ wAνμ,+.

Lemma 5.9.Assume that w∈Iμ,+ν . Then, thek-algebra homomorphism τφ,ν :wAμ,+

wAνμ,+ is surjective. Its kernel is the two-sided ideal generated by the idempotents1xwith x∈wIμ,+\wIνμ,+. Further, we have τφ,ν(1x) = 1x for each x∈wIνμ,+.

Proof. By Section3.5, the functorτφ,νtakes the minimal projective generator ofwOμ,+

to the minimal projective generator ofwOνμ,+. Letiν,φbe the right adjoint of τφ,ν. For anyM the unitM →iν,φτφ,ν(M) is surjective. Hence, for any projective module P we have a surjective map

HomwOμ,+(P, M)HomwOμ,+

P, iν,φτφ,ν(M)

= HomwOνμ,+

τφ,ν(P), τφ,ν(M) . Thus, thek-algebra homomorphismτφ,ν is surjective.

LetI wAμ,+ be the 2-sided ideal generated by the idempotents 1x such that x∈

wIμ,+ and τφ,ν(1x) = 0. By Section 3.5(c), the latter are precisely the idempotents 1x withx∈wIμ,+\wIνμ,+.

We have ak-algebra isomorphismwAμ,+/I wAνμ,+, becausewOνμ,+ is the Serre sub-category ofwOμ,+generated by the simple modules killed byI. Under this isomorphism, the mapτφ,ν is the canonical projectionwAμ,+wAμ,+/I.

The last claim in the lemma follows from Section3.5(b). 2 Now, letv∈Iν,− andw=v+1. We havew∈Iφ,+ν .

We equip thek-algebras vAν,, vAφ, with the gradingswA¯νφ,+, wA¯φ,+, see Proposi-tion 5.4. Consider the categoriesvO¯ν,−=wA¯νφ,+-gmodandvO¯φ,−=wA¯φ,+-gmod, which are graded analogues of the categoriesvOν,− andvOφ,−.

To unburden the notation, we’ll abbreviateLν =vLν,andLφ=vLφ,. Let ¯Lν, ¯Lφbe the natural graded lifts invO¯ν,,vO¯φ,of the semi-simple modulesLν,Lφrespectively.

Forv∈Iν, andd+N > f, we’ll use the following graded analogue of the translation functorTφ,ν:vOφ, vOν, inProposition 4.36.

Lemma 5.10.Assume that v ∈Iν,− and d+N > f. Then, there is an exact functor of graded categories T¯φ,ν : vO¯φ, vO¯ν, such that T¯φ,ν( ¯Lφ) = ¯Lν and T¯φ,ν coincides withTφ,ν when forgetting the grading.

Proof. First, note that the translation functor Tφ,ν : vOφ,− vOν,− is well-defined, becaused+N > f andv∈Iν,−. See Section4.6for more details.

Now, byCorollary 4.34, we havevOν,− =vAν,−-mod andvOφ,− =vAφ,−-mod. By Corollary 4.50, we can viewvBν,,vBφ,as right modules overvAν,,vAφ,respectively.

Consider the functors Vk : vOν,− vZν,− and Vk : vOφ,− vZφ,− given by Vk =

vBν,−vAν,−andVk =vBφ,−vAφ,−.

By Proposition 4.33, the functors Vk on vOν,, vOφ, are exact and we have Vk(vAν,) = vBν,, Vk(vAφ,) = vBφ,. Further, since vAν,+, vAφ,+ are Noetherian, any finitely generated module has a finite presentation. Thus, by the five lemma, the obvious morphism of functorsVkVk is invertible.

Next, by Corollary 5.8, we have wA¯νφ,+ = vA¯ν,− and wA¯φ,+ = vA¯φ,− as graded k-algebras. Thus, we have vO¯ν,− = vA¯ν,−-mod and vO¯φ,− = vA¯φ,−-mod. Consider the functors on vO¯ν,−, vO¯φ,− given by ¯Vk = vB¯ν,−vA¯ν,− , ¯Vk = vB¯φ,−vA¯φ, respectively. We have the commutative squares

vO¯ν,−

¯Vk

vZ¯ν,−

vOν,− Vk vZν,−

vO¯φ,−

V¯k

vZ¯φ,−

vOφ,− Vk vZφ,−.

Now, letvO¯projφ, vO¯φ,− be the full subcategory of the projective objects. We define

vO¯projν,−,vOprojν,− andvOprojφ, in a similar way.

The functor Vk is fully faithful on vOprojν,− and vOprojφ, byCorollary 4.50. Hence, the functor ¯Vk is fully faithful on vO¯projν,− and vO¯projφ,. Therefore, we may identify vO¯projν,−,

vO¯projφ, with some full subcategoriesvZ¯projν,−,vZ¯projφ, ofvZ¯ν,,vZ¯φ, via ¯Vk

The functor ¯θφ,ν inRemark 4.42 gives an exact functorvZ¯projφ, vZ¯projν,−. We define the functor ¯Tφ,ν : vO¯projφ,− vO¯projν,− so that it coincides with ¯θφ,ν under ¯Vk. It gives a functor of triangulated categories Kb(vO¯projφ,−) Kb(vO¯projν,−), where Kb denotes the bounded homotopy category.

SincevO¯projν,− andvO¯projφ,− have finite global dimensions, there are canonical equivalences Kb(vO¯projφ,−) Db(vO¯φ,−) and Kb(vO¯projν,−) Db(vO¯ν,−). Thus, we can view ¯Tφ,ν as a functor of triangulated categoriesDb(vO¯φ,−)Db(vO¯ν,−).

By Proposition 4.36(b), the functor Tφ,ν gives an exact functor vOprojφ,− vOprojν,. ByRemark 4.42, the functor ¯Tφ,ν coincides withTφ,ν when forgetting the grading. The functor Tφ,ν yields a functor of triangulated categoriesDb(vOφ,−)Kb(vOν,−) which is t-exact for the standard t-structures and which coincides with Tφ,ν when forgetting the grading. Hence, the functor ¯Tφ,ν is also t-exact. Thus, it gives an exact functor T¯φ,ν :vO¯φ,vO¯ν, which coincides with Tφ,ν when forgetting the grading.

Now, we concentrate on the equality ¯Tφ,ν( ¯Lφ) = ¯Lν.

Since ¯Tφ,ν coincides withTφ,ν when forgetting the grading, by Proposition 4.36(d), for each x∈wIν,− there is an integerj such that ¯Tφ,ν( ¯L(xwνoφ,−)) = ¯L(x•oν,−)j. We must check thatj = 0.

Let ¯Tν,φbe the left adjoint to ¯Tφ,ν, seeRemark 5.11below. ByCorollary 5.8we have

vO¯ν,− = vA¯ν,−-mod and vO¯φ,− = vA¯φ,−-mod. The graded k-algebras wA¯νφ,+, wA¯φ,+

(= vA¯ν,, vA¯φ,) are Koszul. The natural graded indecomposable projective modules

are of the formvA¯ν,−1x,vA¯φ,−1xwithx∈vIν,−,vIφ,− respectively. We must check that T¯ν,φ(vA¯ν,−1x) =vA¯φ,−1xwν for eachx∈wIν,−.

By definition of ¯Tφ,νwe have an isomorphism ¯θφ,νkk◦T¯φ,νof functors onvO¯projφ,. Further, by definition of ¯Vk, we have ¯Vk(vA¯ν,1x) = vB¯ν,(x) and ¯Vk(vA¯φ,1xwν) =

vB¯φ,(xwν). Therefore, it is enough to check that ¯θν,φ(vB¯ν,(x)) =vB¯φ,(xwν).

ByRemark 4.42, this follows from Proposition 4.41(f) by base change. 2

Remark 5.11.General facts imply that the functor ¯Tφ,νhas a left adjoint ¯Tν,φ:vO¯ν,−

vO¯φ,−, see the proof ofProposition 4.36. By definition ofTν,φand the unicity of the left adjoint, the functor ¯Tν,φcoincides withTν,φwhen forgetting the grading.

Now, we prove the following lemma which is dual toLemma 5.9.

Lemma 5.12.Assume that v ∈Iν,− and d+N > f. Then, the functor Tφ,ν : vOφ,−

vOν,− induces a surjective graded k-algebra homomorphism Tφ,ν : vA¯μφ,− vA¯μν,. Its kernel contains the two-sided ideal generated by{1x; x∈vIμφ,, x /∈Iν,+}. Further, for x∈vIμφ,∩Iν,+ we have xwν vIμν, andTφ,ν(1x) = 1xwν.

Proof. First, note that, sincev∈Iν,andd+N > f, the functorTφ,ν:vOφ, vOν,

is well-defined and it takesvOμφ,− intovOμν,− byProposition 4.36(c).

We’ll abbreviate Lφ = vLμφ,− and Lν = vLμν,−. By Proposition 4.36(f), we have Tφ,ν(Lφ) =Lν. Thus, sinceTφ,ν is exact, it induces a graded k-algebra homomorphism Tφ,ν:vA¯μφ,−= ExtvOμφ,−(Lφ)opvA¯μν,= ExtvOμν,−(Lν)op.

ComposingTφ,νwith its left adjointTν,φ, we get the functorΘ=Tν,φ◦Tφ,ν. To prove that Tφ,ν is surjective, we must prove that the counit Θ 1 yields a surjective map ExtvOμφ,−(Lφ)ExtvOμφ,−(Θ(Lφ), Lφ).

The parabolic inclusionvOμφ,vOφ,is injective on extensions by Section3.5. So we must prove that the counit yields a surjective map ExtvOφ,−(Lφ)ExtvOφ,−(Θ(Lφ), Lφ).

Let us consider the graded analogue of this statement. Set ¯Θ = ¯Tν,φ◦T¯φ,ν, where T¯ν,φ, ¯Tφ,ν are as inLemma 5.10 andRemark 5.11. We have

ExtvOφ,−(Lφ) =

j

ExtvO¯φ,

L¯φ,L¯φj , ExtvOφ,−

Θ(Lφ), Lφ

=

j

ExtvO¯φ,−

Θ( ¯¯ Lφ),L¯φj .

Thus we must prove that for eachi, j the counitη: ¯Θ→1yields a surjective map ExtivO¯φ,−

L¯φ,L¯φj

ExtivO¯φ,−

Θ( ¯¯ Lφ),L¯φj

. (5.7)

ByLemma 5.10, we have ¯Tφ,ν( ¯Lφ) = ¯Lν. Further, since vO¯ν,− = wA¯νφ,+-gmod and

vO¯φ,−=wA¯φ,+-gmod, the gradings onvO¯φ,− andvO¯ν,− are Koszul byProposition 5.4.

Hence, since the right hand side of(5.7)is ExtivO¯ν,−( ¯Lν,L¯νj), it is zero unlessi=j.

Now, we define the integer = min{d; ¯Θ( ¯Lφ)d = 0}. Recall that the grading on

wA¯φ,+ is positive. Further, sincevO¯φ,=wA¯φ,+-gmod, we can view ¯Θ( ¯Lφ) as a graded

wA¯φ,+-module. Thus ¯Θ( ¯Lφ) is a quotient of ¯Θ( ¯Lφ) which is killed by the radical of

wA¯φ,+. We deduce that ¯Θ( ¯Lφ)top( ¯Θ( ¯Lφ)).

Next, we claim that for any simple gradedwA¯φ,+-module ¯Lsuch that ¯Tφ,ν( ¯L)= 0, the map η( ¯L) : ¯Θ( ¯L)→L¯ yields an isomorphism top( ¯Θ( ¯L))→L. Indeed,¯ η( ¯L) is surjective because it is non-zero, and for any simple quotient ¯Θ( ¯L)→L¯ we have

0= HomvO¯φ,−

Θ( ¯¯ L),L¯

= HomvO¯ν

T¯φ,ν( ¯L),T¯φ,νL¯ .

ByProposition 4.36(d), (e) this implies that ¯Tφ,ν( ¯L) = ¯Tφ,ν( ¯L), and that it is non-zero.

Therefore, we have ¯L= ¯L, proving the claim.

Recall that ¯Lφ is a semi-simple module, see Section 3.4. Applying the claim to the simple summands ¯L⊂L¯φsuch that ¯Tφ,ν( ¯L)= 0, we get that top( ¯Θ( ¯Lφ)) = Imη( ¯Lφ). In particular top( ¯Θ( ¯Lφ)) is pure of degree zero. This implies that we have= 0. Therefore, the kernel of η( ¯Lφ) lives in degrees>0. Hence, by Koszulity of the grading of vO¯φ,, we get

ExtivO¯φ,−

Kerη( ¯Lφ),L¯φi

= 0.

Hence the surjectivity of (5.7) for i =j follows from the long exact sequence of Ext’s groups associated with the exact sequence

0Ker η( ¯Lφ)

→Θ( ¯¯ Lφ)→L¯φ.

This proves that the map Tφ,ν is surjective, proving the first part of the lemma.

Next, we have Iν,μ ={xwν; x∈Iφ,−μ ∩Iν,+}by Corollary 3.3(a). Further, we have Tφ,ν(1xwν) = 0 forx /∈Iν,−byProposition 4.36(e), andxwν∈Iν,+if and only ifx∈Iν,−. This proves the second claim of the lemma. Finally, the last claim of the lemma follows from Proposition 4.36(d). 2

Next, we prove the following.

Lemma 5.13. Assume thatw∈Iμ,+ν . Letv =w−1 . We have v∈Iν,−μ . Assume also that d+N > f and e+N > d. There is a k-algebra isomorphism pμ,ν : wAνμ,+ vA¯μν,−

such that pμ,ν(1x) = 1y for eachx∈wIνμ,+, where y=x−1 , and such that the following square is commutative

wνwAμ,+

(5.1) τφ,ν

vA¯μφ,

Tφ,ν

wAνμ,+ pμ,ν vA¯μν,−.

(5.8)

Proof. We havev=wμw1wν. Note thatwνw∈Iφ,−ν ∩Iμ,+, because byLemma 3.2we havew−1∈Iν,+μ , hencew−1wν ∈Iφ,+μ ∩Iν, andwνw= (w−1wν)−1∈Iμ,+∩Iφ,ν.

Let πμ,ν : wνwAμ,+ vA¯μν, be the composition of the k-algebra homomorphism Tφ,ν:vA¯μφ,vA¯μν,−inLemma 5.12and of thek-algebra isomorphismwνwAμ,+=vA¯μφ, in(5.1).

Note that wνwAνμ,+ = wAνμ,+. We must construct a k-algebra isomorphism pμ,ν :

wAνμ,+vA¯μν,− such thatπμ,ν=pμ,ν◦τφ,ν.

Letx∈wνwIμ,+. Thuswμx1vIμφ,. ByLemma 5.12, we have

πμ,ν(1x)= 0 Tφ,ν(1wμx−1)= 0 wμx1∈Iφ,μ∩Iν,+. ByLemma 5.9, we have

τφ,ν(1x)= 0 x∈Iμ,+ν . Again byLemma 3.2, we have

wμx−1∈Iφ,−μ ∩Iν,+ xwμ∈Iφ,+ν ∩Iμ, x∈Iμ,+ν .

Hence, we have τφ,ν(1x) = 0 if and only if πμ,ν(1x) = 0. Thus, we have Ker(τφ,ν) Ker(πμ,ν), because the left hand side is generated by the 1x’s killed byτφ,ν and the right hand side contains the 1x’s killed byTφ,ν.

This proves the existence of ak-algebra homomorphismpμ,νsuch thatπμ,ν =pμ,ν◦τφ,ν andpμ,ν(1x) = 1wμx−1 for eachx∈wIνμ,+. The mappμ,ν is surjective, because the map Tφ,ν is surjective byLemma 5.12.

Now, we prove thatpμ,ν is injective. By Section3.5, the parabolic inclusion functor iμ,φ :vOμν,− vOν,− yields a gradedk-algebra homomorphismiμ,φ : vA¯μν,− vA¯ν,−. Setz=v1=wνwwμ. The following is proved below.

Claim 5.14.We have the commutative diagram

wνwAμ,+

(5.1) Tμ,φ

vA¯μφ,

Tφ,ν

iμ,φ

vA¯μν,

iμ,φ

zAφ,+

(5.1)

vA¯φ, Tφ,ν

vA¯ν,.

(5.9)

Note thatz∈Iμ,, hence the mapTμ,φ is well-defined.

Now, by Proposition 4.36(g), the translation functor Tμ,φ yields a map wAνμ,+

wwμAνφ,+. Consider the diagram

wνwAμ,+ τφ,ν

Tμ,φ

wAνμ,+ p

μ,ν

Tμ,φ

vA¯μν,

iμ,φ

zAφ,+

τφ,ν

wwμAνφ,+ pφ,ν vA¯ν,−.

(5.10)

ByClaim 5.14, the outer rectangle in(5.9)is commutative. Thus, the outer rectangle in(5.10)is commutative. The left square in(5.10)is commutative, byProposition 4.36(c).

Thus, sinceτφ,ν is surjective, the right square in (5.10)is also commutative.

The middle vertical map in (5.10) is injective by Remark 4.38. Therefore, to prove thatpμ,ν is injective it is enough to check thatpφ,ν is injective.

Now, it is easy to see that the map pφ,ν is indeed invertible, because it is surjective by the discussion above (applied to the choice ν=φ) and dim(wwμAφ,+ν

) = dim(vA¯ν,) byProposition 5.4.

Finally, to finish the proof ofLemma 5.13we must check thatpμ,ν(1x) = 1y for each x∈wIνμ,+, wherey=x−1 .

To do that, it suffices to observe that x=wνxwμ, and that, byProposition 5.1and Lemmas 5.9, 5.12, the square of maps in(5.8)gives the following diagram

1x (5.1)

τφ,ν

1wμx1

Tφ,ν

1x pμ,ν 1wμx1wν.

Now, we prove Claim 5.14. The right square in (5.9) is commutative, by Proposi-tion 4.36(c).

Let us concentrate on the left square. We must prove that the isomorphismswνwAμ,+=

vA¯μφ,− andwAφ,+=vA¯φ, inProposition 5.1yield a commutative square

wνwAμ,+

(5.1) Tμ,φ

vA¯μφ,−

i zAφ,+

(5.1)

vA¯φ,−.

(5.11)

By Proposition 4.36(g), the module Tμ,φ(wνwPμ,+) is a direct summand of zPφ,+. By Proposition 4.41(f) and Remark 4.42, the sheaf θμ,φ(wBμ,+) is a direct summand of

wBφ,+. Thus, we have the following diagram

wνwAμ,+

Vk

Tμ,φ

Endwν wZμ,+(wνwBμ,+)op

θμ,φ

zAφ,+ Vk EndzZφ,+(zBφ,+)op.

Note that the horizontal maps are invertible byCorollary 4.50. This diagram is commu-tative by Remark 4.42, see also Proposition 4.41(a). Next, byProposition 4.48(c) and Corollary 4.49, we have a commutative diagram

Endwν wZμ,+(wνwBμ,+)op

θμ,φ

vA¯μφ,−

H

i

EndzZφ,+(zBφ,+)op H vA¯φ,.

Finally, the horizontal maps in(5.11)are equal to the composition ofHandVk. 2 Finally, we prove our main theorem.

Proof of Theorem 3.12. Since the highest weight categorieswOνμ,+,vOμν,−do not depend on e, f by Remark 3.10, we can assume that there is a positive integer d such that d+N > f ande+N > d. Thus the hypothesis ofLemma 5.13is satisfied.

By Propositions 5.1, 5.4 the k-algebra wAμ,± has a Koszul grading. Thus, by Lemma 2.2and Section3.5, thek-algebrawAνμ,± has also a Koszul grading.

Let us equip wAνμ,± with this grading. By Lemma 2.1, we have wAν,!μ,± = wA¯νμ,± as gradedk-algebras. Therefore, the gradedk-algebrawA¯νμ,± is Koszul and its Koszul dual is isomorphic towAνμ,± as ak-algebra.

We havewA¯ν,!μ,+ =wAνμ,+ as a k-algebra. By Lemma 5.13, we have also a k-algebra isomorphismwAνμ,+ =vA¯μν,. Thus, we havewA¯ν,!μ,+ =vA¯μν, as k-algebras. By unicity of the Koszul grading, we deduce thatwA¯ν,!μ,+=vA¯μν,− as gradedk-algebras.

The involutivity of the Koszul duality implies that we have also wA¯ν,!μ,− = vA¯μν,+ as gradedk-algebras, andwAνμ,− =vA¯μν,+ ask-algebras.

Finally, we must check that under the isomorphismwA¯ν,!μ,+=vA¯μν,− we have 1!x= 1y

withy=x−1 for eachx∈wIνμ,+.

Ifν=φthis isProposition 5.1. Ifμ=φthis is Proposition 5.4.

The isomorphismwA¯ν,!μ,+ =wAνμ,+ above, which is given byLemma 2.1, identifies the idempotents 1!x and 1x for each x wIνμ,+. Thus, by Lemma 5.13, the isomorphism

wA¯ν,!μ,+=vA¯μν,− identifies the idempotents 1!x and 1y, wherey=x1. 2 6. Type A and applications to CRDAHA

Fix integerse, , N >0. Letg=gl(N).

6.1. Koszul duality in the type A case

Let b,t gbe the Borel subalgebra of upper triangular matrices and the maximal torus of diagonal matrices. Let (i) be the canonical basis ofCN. We identifyt =CN, t=CN andW =SN in the obvious way. Putρ= (0,1, . . . ,1−N) andαi=ii+1 for eachi∈[1, N).

We define the affine Lie algebra gofgas in Section3.2. For any subsetX C and

We define the affine Lie algebra gofgas in Section3.2. For any subsetX C and

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