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LetC be a birational equivalence class of smooth projective varieties, modulo isomorphisms. One aims at finding a “simplest” member inC. IfX0andX1are members ofC, we write X1 X0 if there is a birationalmorphism X0→X1. This defines an ordering onC (use Exercise 4.8.5)).

We explain here one reason why we are interested in varieties with nef canon-ical bundles (and why we called themminimal models), by proving:

• any member ofC with nef canonical bundle is minimal (Proposition 8.25);

• any member ofC which contains no rational curves is the smallest element ofC (Corollary 8.24).

However, here are a few warnings about minimal models:

• a minimal model can only exist if the variety is not covered by rational curves (Example 9.14);

• there exist smooth projective varieties which are not covered by rational curves but which are not birational to any smooth projective variety with nef canonical bundle;4

• in dimension at least 3, minimal models may not be unique, but any two are isomorphic in codimension 1 ([D1], 7.18).

Proposition 8.23 LetX and Y be varieties, with X smooth, and letπ:Y → Xbe a birational morphism. Any component ofExc(π)is birational to a product P1×Z, whereπcontracts the P1-factor.

In particular, if π is moreover projective, there is, through any point of Exc(π), a rational curve contracted byπ(use Lemma 7.8).

Proof. LetE be a component of Exc(π). Upon replacingY with its normal-ization, we may assume thatY is smooth in codimension 1. Upon shrinkingY, we may also assume thatY is smooth and that Exc(π) is smooth, equal toE.

LetU0 =X Sing(π(E)) and letV11(U0). The complement of V1 in Y has codimension ≥ 2, V1 and E∩V1 are smooth, and so is the closure in U0 of the image of E∩V1. Letε1 :X1 →U0 be its blow-up; by the universal property of blow-ups ([H1], Proposition II.7.14), since the ideal ofE∩V1inOV1

is invertible, there exists a factorization in the exceptional locus ofπ1 and, upon replacingV1 by the complementV2 of a closed subset of codimension at least 2 andX1by an open subsetU1, we may repeat the construction. Afteristeps, we get a factorization

π:Vi πi the complement inY of a closed subset of codimension at least 2. LetEj ⊂Xj

be the exceptional divisor ofεj. We have KXi = εiKUi−1+ciEi

= (ε1◦ · · · ◦εi)KX+ciEi+ci1Ei,i1+· · ·+c1Ei,1, whereEi,j is the inverse image ofEj inXi and

ci= codimXi−1i1(E∩Vi1))−1>0

4This is the case for any desingularization of the quotient X of an abelian variety of dimension 3 by the involutionx7→ −x([U], 16.17); of course, a minimal model here is X itself, but it is singular.

([H1], Exercise II.8.5). Since πi is birational, πiOXi(KXi) is a subsheaf of OVi(KVi). Moreover, since πj(E∩Vj) is contained in the support of Ej, the divisorπjEj−E|Vj is effective, hence so isEi,j−E|Vi.

It follows thatOYKX+ (ci+· · ·+c1)E)|Vi is a subsheaf ofOVi(KVi) = OY(KY)|Vi. SinceY is normal and the complement ofViinY has codimension at least 2, OYKX+ (ci+· · ·+c1)E) is also a subsheaf of OY(KY). Since there are no infinite ascending sequences of subsheaves of a coherent sheaf on a noetherian scheme, the process must terminate at some point: πi(E∩Vi) is a divisor in Xi for some i, hence E∩Vi is not contained in the exceptional locus of πi (by 8.6 again). The morphism πi then induces a dominant map betweenE∩Vi andEi which, since, by Zariski’s Main Theorem, the fibers ofπ are connected, must be birational. Since the latter is birationally isomorphic to Pci−1×(πi1(E∩Vi1)), where εi contracts thePci−1-factor, this proves the

proposition.

Corollary 8.24 LetY andX be projective varieties. Assume thatX is smooth and thatY contains no rational curves. Any rational mapX 99KY is defined everywhere.

Proof. Let X0 ⊂ X ×Y be the graph of a rational map π : X 99K Y as defined in 5.17. The first projection induces a birational morphismp:X0→X.

Assume its exceptional locus Exc(p) is nonempty. By Proposition 8.23, there exists a rational curve on Exc(p) which is contracted byp. SinceY contains no rational curves, it must also be contracted by the second projection, which is absurd since it is contained inX×Y. Hence Exc(p) is empty andπ is defined

everywhere.

Under the hypotheses of the proposition, one can say more if Y also is smooth.

Proposition 8.25 LetX andY be smooth projective varieties and letπ:Y → Xbe a birational morphism which is not an isomorphism. There exists a rational curveC onY contracted byπ such that(KY ·C)<0.

Proof. LetE be the exceptional locus of π; by 8.6,π(E) has codimension at least 2 inX andE=π−1(π(E)). Letxbe a point ofπ(E). By Bertini’s theorem ([H1], Theorem II.8.18), a general hyperplane section ofX passing throughxis smooth and connected.

It follows that by taking dim(X)−2 hyperplane sections, we get a smooth surfaceS in X that meets π(E) in a finite set containing x. Moreover, taking one more hyperplane section, we get onS a smooth curve C0 that meetsπ(E)

only atxand a smooth curveC that does not meetπ(E).

C0!!

C0! g

ε π

S

X g(Ei) Y

Ei

E

C C0

x π(E)

Construction of a rational curveg(Ei)in the exceptional locus E ofπ By construction,

(KX·C) = (KX·C0).

One can writeKYlinπKX+R, where the support of the divisorRis exactly E. Since the curveC0−1(C) does not meetE, we have

(KY ·C0) = (KX·C).

On the other hand, since the strict transform C001(C0 π(E)) ofC0 does meetE=π1(π(E)), we have

(KY ·C00) = ((πKX+R)·C00)>((πKX)·C00) = (KX·C0) hence

(KY ·C00)>(KY ·C0). (8.7) The indeterminacies of the rational mapπ−1:S 99KY can be resolved (Theo-rem 5.18) by blowing-up a finite number of points ofS∩π(E) to get a morphism

g: ˜S−→ε S π

−1

99KY

whose image is the strict transform of S. The curve C00 = εC is irreducible andgC00=C0; forC0, we write

εC0=C000+X

i

miEi,

where the mi are nonnegative integers, the Ei are exceptional divisors for ε (hence in particular rational curves), and gC000 = C00. Since C and C0 are linearly equivalent onS, we have

C00linC000+X

i

miEi

on ˜S hence, by applying g,

C0lin C00 +X

i

mi(gEi).

Taking intersections withKY, we get

(KY ·C0) = (KY ·C00) +X

i

mi(KY ·gEi).

It follows from (8.7) that (KY ·gEi) is negative for somei. In particular,g(Ei) is not a point hence is a rational curve onY. Moreover,π(g(Ei)) =ε(Ei) ={x}

henceg(Ei) is contracted byπ.

8.9 Exercises

1) LetXbe a smooth projective variety and letM1, . . . , Mrbe an ample divisors onX. Show thatKX+M1+· · ·+Mris nef for allr≥dim(X) + 1 (Hint: use the cone theorem).

2) a) LetX→P2be the blow-up of two distinct points. Determine the cone of curves ofX, its extremal faces, and for extremal face, describe its contraction.

b) Same questions for the blow-up of three noncolinear points.

3) LetV be ak-vector space of dimensionnand letr∈ {1, . . . , n−1}. LetGr(V) be the Grassmanian that parametrizes vector subspaces ofV of codimension r and set

X ={(W,[u])∈Gr(V)×P(End(V))|u(W) = 0}.

a) Show that X is smooth irreducible of dimension r(2n−r)−1, that Pic(X)'Z2, and that the projectionX →Gr(V) is a KX-negative extremal contraction.

b) Show that

Y ={[u]∈P(End(V))|rank(u)≤r}

is irreducible of dimension r(2n−r)−1. It can be proved that Y is normal.

Ifr ≥ 2, show thatY is not locally Q-factorial and that Pic(Y) 'Z[OY(1)].

What happens whenr= 1?

4) Let X be a smooth complex projective Fano variety with Picard number

≥2. Assume thatX has an extremal ray whose contraction X → Y maps a hypersurfaceE⊂X to a point. Show thatX also has an extremal contraction whose fibers are all of dimension≤1 (Hint:consider a rayRsuch that (E·R)>

0.)

5) Let X be a smooth complex projective variety of dimension n and let R+r1, . . . ,R+rsbe distinctKX-negative extremal rays, all of fiber type. Prove s≤n (Hint: show that each linear form`i(z) =z·ri onN1(X)R divides the polynomialP(z) = (zn).)

6) LetX be a smooth projective Fano variety of positive dimension n, letf : P1 → X be a (nonconstant) rational curve of (−KX)-degree ≤n+ 1, letMf

be a component of Mor(P1, X; 07→f(0)) containing [f], and let ev:Mf −→X

be the evaluation map at∞. Assume that the (−KX)-degree of any rational curve onX is≥(n+ 3)/2.

a) Show thatYf := ev(P1×Mf) is closed inX and that its dimension is at least (n+ 1)/2 (Hint: follow the proof of Proposition 8.7.c)).

b) Show that any curve contained inYfis numerically equivalent to a multiple off(P1) (Hint: use Proposition 5.5).

c) Ifg:P1→Xis another rational curve of (−KX)-degree≤n+1 such that Yf∩Yg 6=∅, show that the classes [f(P1)] and [g(P1)] are proportional inN1(X)Q.

d) Conclude that N1(X)R has dimension 1 (Hint: use Theorem 7.5 to pro-duce ag such thatYg=X).

7)Non-isomorphic minimal models in dimension3. LetSbe a Del Pezzo surface, i.e., a smooth Fano surface. Set

P=P(OS⊕OS(−KS))−→π S

and let S0 be the image of the section of π that corresponds to the trivial quotient ofOS⊕OS(−KS), so that the restriction ofOP(1) toS0is trivial.

a) What is the normal bundle to S0in P?

b) By considering a cyclic cover of P branched along a suitable section of OP(m), for m large, construct a smooth projective threefold of general typeXwithKXnef that containsSas a hypersurface with normal bundle KS.

c) Assume from now on thatScontains an exceptional curveC(i.e., a smooth rational curve with self-intersection−1). What is the normal bundle ofC inX?

d) Let ˜X→X be the blow-up ofC. Describe the exceptional divisorE.

e) Let C0 be the image of a sectionE →C. Show that the ray R+[C0] is extremal andKX0-negative.

f) Assume moreover that the characteristic is zero. The rayR+[C0] can be contracted (according to Corollary 8.4) by a morphism ˜X →X+. Show thatX+ is smooth, thatKX+ is nef and thatX+ is not isomorphic toX.

The induced rational mapX 99KX+ is called aflop.

8) A rationality theorem. Let X be a smooth projective variety whose canonical divisor is not nef and letM be a nef divisor onX. Set

r= sup{t∈R|M+tKX nef}.

a) Let (Γi)iI be the (nonempty and countable) set of rational curves onX that appears in the cone Theorem 8.1. Show

r= inf

iI

(M ·Γi) (−KX·Γi). b) Deduce that one can write

r=u v,

withuandvrelatively prime integers and 0< v≤dim(X) + 1, and that there exists aKX-negative extremal rayRof NE(X) such that

((M +rKX)·R) = 0.

Chapter 9

Varieties with many rational curves

9.1 Rational varieties

Letk be a field. Ak-varietyX of dimensionnisk-rationalif it is birationally isomorphic toPnk. It isrationalif, for some algebraically closed extensionKof k, the varietyXK is K-rational (this definition does not depend on the choice of the algebraically closed extensionK).

One can also say that a variety isk-rational if its function field is a purely transcendental extension ofk.

A geometrically integral projective curve is rational if and only if it has genus 0. It isk-rational if and only if it has genus 0 and has ak-point.

9.2 Unirational and separably unirational