C OMPOSITIO M ATHEMATICA
K ENNETH O. L ELAND
Topological analysis of differentiable transformations
Compositio Mathematica, tome 18, n
o3 (1967), p. 189-200
<http://www.numdam.org/item?id=CM_1967__18_3_189_0>
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189
of differentiable transformations
by
Kenneth O. Leland
1. Introduction
In Section 3 of
[4]
the author extended thetopological
methodsdeveloped by
Porcelli and Connell[9]
forhandling
isolatedsingu-
larities of
complex
differentiable functions to the case of morecomplicated singularities.
Inparticular
he was able to resolveby topological
methods the case when thesingularity
was a rectifiablearc. In this paper the results of
[4]
aregeneralized
to the case ofcomplex (Frechét )
differentiable functions on acomplex
Euclideanspace into itself. In
particular
the removablesingularity problem,
when the
singularity
is a "rectifiable interface"separating
twoadjacent cells,
is resolved.The
topological
index ofWhyburn [12]
isreplaced by degree
theoretic methods from
algebraic topology [1, 2].
The
topological analogue
of ourresults,
wherein therequirement
of
complex differentiability
isreplaced by
therequirement
ofbeing light
andlocally
sensepreserving,
may be found in the work of Titus andYoung [10].
We are unable to
generalize
thealgebra
of differencequotients developed
in[4,
6, 9,12]; however,
the need for suchauxiliary
functions is obviated
by
use of ageometric
characterization of harmonie functions[Theorem 4.1].
Let B and C be Banach
spaces, f
a continuous function on anopen set S in B into
C,
and p e S.Then f
is said to be(real Frechét)
differentiable
[3]
at p if there exists a bounded linearoperator
Afrom B into
C,
such that for all e > 0, there exists t5 > 0, such that||x|| 03B4, x-f-p ~ S, implies ||f(x+p)-f(x)-A(x)||~ 03B5||x||.
In Section 3
degree
theoretic methods areemployed
to prove Maximum Modulus Theorems. In Section 4 the basicmachinery
for
handling
removablesingularities
isdeveloped.
In Section 5 thismachinery
isapplied
to the case when thesingularity
is a "recti- fiable interface".No use is made in this paper of Jacobian matrices or
determinants,
or of kernel
integrals.
2. Notation and definitions
Let R denote the real
numbers,
K thecomplex numbers,
and 03C9the
positive integers. Throughout
thispaper E
shall denote a fixed Euclidean space and m shall denoteLebesgue
measure on E. Forx~E, 03B4
> 0, setIf
A, B,
C Ç E andf
and g are functions on A into Z and B into Z for Z =R, K, E,
then we set(f+g)(x)
=f(x)+g(x)
forx e A n
B,
and we letIIC
be the function h on A n C such thath(x)
=f(x)
for x e A n C. Iff
and g are functions we shall writefg
for thecomposition
off
and g.B [E, E]
shall denote the Banachalgebra
of linear transformations of E into E.By
I shall be meant the element ofB[E, E]
such thatI(x)
= x. We shall denoteby G(E)
the rotation group ofE,
thatis the group of
unitary
transformations ofB[E, E].
Asubgroup
G of
G(E)
is said to be transitive if for all x, y eB0(1),
there exists g eG,
such thatg(x)
=g(y).
DEFINITION 2.1. Let F be a collection of continuous functions
on open subsets of E into
R,
and G asubgroup
ofG(E).
Then Fis called a TG
family [7]
if:1.
ForceR, f eF, cf
e F.2. For
f,geF, I+g
e F.3. For
f e F,
S an open set inÈ, Ils
lies in F.4. For
f e F,
and x eB,
the functionfx
lies inF,
wheregx(y)
=I(y-ae) for y
e E such that y-x e domainf.
5. For
f
eF,
g eG, f g
e F.A function
f
e F is said to maximummodular,
if for all open sets S inE,
such thatS C dom f,
we havef|(x)|
~ sup{|f(t)|;
t ~ -S}
for all x e S. A TGfamily
F is called a TGMfamily
ifF contains the constant function
1,
and if all elements of F are maximum modular.Let S be an open set in E
containing V0(1),
and letf
be a con-tinuous function on S into E. If p is a
point
ofE- f (B),
whereB =
B0(1),
then thedegree 03BCB(f, p)
off
withrespect
to B and p may be defined. If x is apoint
ofS,
such that there exists 03B4 > 0,such that
f(y)
~f(x)
forall y --A x,
y eVx(03B4)
nS,
then the localdegree 03BCx(f)
off
at x may be defined. For formal definitions anddevelopment
ofdegree theory
one may refer to Alexandroff andHopf [1]
or Cronin[2].
Our notation isinspired by
that usedby Whyburn [12]
in the two dimensional case.We shall need the
following
facts fromdegree theory:
2.1.
03BCB(f, P)
=03BCB(f-p, 0).
2.2. If
03BCB(f, p) =1=
0, then p ef[V0(1)].
2.3. If H =
1-1(p)
t1V0(1)
isfinite,
thenPB(f, p) = 03A3x~H 03BCx(f).
2.4. If p
and q
arepoints
of the samecomponent
ofE- f(B), then PB(f, p) = 03BCB(L, q).
2.5. If M and N are elements of the same
component
of the set of invertible elementsI[E, E]
ofB[E, E], then 03BC(M) =,uB(M, 0)
=
03BCB(N, 0)
=p(N)-
2.6. If for some p e
V0(1),
the derivative A off
at p exists and isinvertible,
then there exists 03B4 > 0, such thatfor q
=f(p), Vp(03B4) ç V0(1), Vq(03B4) ~ f[V0(1)], f(x) ~ f(p)
for all x c-Vp(03B4),
x ~ p, and
03BCx(f)
=03BCp(f)
=03BC(A)
for x EVp(03BC).
We shall also need the
following
form of Sard’s Theorem:THEOREM 2.1. Let
f
be a(Frechét) differentiable function
on anopen set S in E into
E,
and let H be setof
allpoints
x eS,
suchthat the derivative
Ax of f
at x does not invert. Thenm[J(H)]
= 0.In the form found in Cronin
[2, 32-36]
the firstpartial
deriva-tives of
f
arerequired
to exist and be continuous. Thisimplies
theexistence and
continuity
of the Frechét derivative off.
This con-tinuity, however,
is not assumed here. Theargument
for the caseof
complex
differentiable functions from K to K may be found inWhyburn [12, 72-73.
PROOF. Let a > 0, and let
Q
be a cube of side a in S. For n e cv,let
Fn
be the subdivision ofQ
intoequal
cubes of sidea/2",
wheren is the dimension of E. Let
Ho
= H nQ,
and for m e co, setHm
={x ~ H0; ||Ax|| ~ m}.
ThenHo
=U~1Hm.
Let a > 0, e 1, and let m e cv. Let x e
Hm.
Then there exists t5 > 0, such thatVx(03B4) ~ S,
and such thatNow there exists k ~ 03C9, and an the element
Ex
ofFk containing x
which lies in
Vx(03B4).
Let D ={Ex;
x~ Hm}.
For each xeHm,
thereexists
~Hm,
such thatExE ,
and such thatEx
is not aproper subset of any element of D. Since
U~1Fi
iscountable, Do
={E; x~Hm}
is countable.Clearly
A = B or A n B is a"face" cube of dimension n -1 for all
A, B E Do .
Let x e
Hm, set y
={y-;
y eE},
and set A =Ax.
Then thereexists an n -1 dimensional
subspace
T of E such thatA(J)
T.For
y e E, set 03B4(y) = inf{||y-t||; t~T},
and letP(y)
be theorthogonal projection of y
into T.For y
eJ,
and
where s is the side of
J.
Thus for ye J, 03B4[f(+y)- f()] ~ 03B5~ns,
and
P[f(+y)-f()]
eV0(m~ns+03B5~ns)
=V0[(m+03B5)ns].
Thenwhere
Cn-1
is a constant determinedby
n-1, andWe note that
f(E)
lies in a"cylinder"
with the subsetof T as a
base,
and with altitude03B5~ns.
ThenSince 8 is
arbitrary, m[f(Hm)]
= 0. Thus3. Maximum
modularity theory
Let
f
be acomplex
differentiable function on an open set S in K into K. Thenf
satisfies the Maximum Modulus Theorem. Foroe
E S, t
eE2
=K,
setAx(t)
=f’(x)
t. ThenAx
is the Frechétderivative of
f
at x, andAx
is an element of thefamily
W of elementsof
B[E2, E2]
of the formrU,
where r eR,
and U is a rotation of index 1. The maximummodularity
off
can be deduceddirectly
from the fact that W is a linear space all of whose elements which invert have index 1. The
argument
isindependent
of the dimensionof the space in
question,
and does not involve K.THEOREM 3.1. Set U =
Vo(l)
and E* =B[E, R]
and letf
be acontinuous
function
onTJ
intoE,
and H a nowhere dense subsetof U,
such thatfor
xe U-H,
the derivativeAx of f
at x exists. Thenif
1. For all x E U-H and r e
R,
such thatA.-rI
isinvertible,
we
have 03BC(Ax-rI)
= 1; and2. For all r e
R, m[f-rI)(H)J
= 0, then andfor all x~U, L~E*.
PROOF. Let L e
E*,
and let e > 0. There exists a countable subset X ofU-H,
dense in U. For x EX,
letCz
be the set of allr e
R,
such thatAx-rI
does not invert.Clearly,
for x eX, Cx
isfinite or
empty,
and thusUx~XCx
is countable.Let ro
be an elementof
R,
such that ro > 0, ro 03B5, andro e Ux~XCx.
ThenAx-r0I
is invertible for all x e X. Set
f0
=f-r0I.
Let S be a
component
ofE-f0[B0(1)],
such that S nf(U) ~
0.Then P =
f-10(S)
is an open set inU,
and hence open in E. Thus there exists x~X,
such that x e P. Since the derivative off o
at xis
invertible,
from Fact 2.6, we have thatS D f0(P)
contains anopen set
Q.
Let K be the set of allpohits z
eU-H,
such that the derivative off o
at x does not invert. Then from Sard’sTheorem, m[f0(K)]
= 0, and hencef0(K) is
nowhere dense in E.By hypothesis f o(H)
is nowhere dense in E. Thenis nowhere dense in
Q.
Let p eQ-Qo Ç S,
and let M =f-1(p) ~
U.Since M is
compact,
from Fact 2.6, M is finite.By hypothesis,
the derivative of
fo
at x is of index 1 for all x e M. Hence from Fact 2.6, for x eM, 03BCx(f0)
= 1, and thusIÀ.8 (/0, p)
= k > 0, where k is the number of elements of M. Then from Fact 2.2, S ÇF(U).
Assume there exists
z e U,
such thatILfo(z)1
> sup{|Lf0(t)|;
t e
B0(1)}.
Thenf0[B0(1)]
D ={x ~ E; |L(x)| |Lf0(z)|},
andfo(z)
e E-D. Thenfo(z)
lies in the unboundedcomponent
P ofE-lo[BO(l)],
and hence Pfo(U).
Butfo(tJ)
iscompact
andhence bounded.
Similarly
for zEU, Ilfo(z)11
~sup{||f0(t)||;
teB0(1)}.
Since s is
arbitrary
the theorem follows.THEOREM 3.2. Let S be an open set in
E,
H and X nàsetqof S,
and
f a
continuousfunction
on S into E such that:1. H is nowhere dense in
S,
andm[/(H)]
= 0.2. For x e
(S-H)
uX,
the derivativeAx of f
at xexist8,
and iso f
index 1i f
invertible.3. X is dense in
S,
andfor
x eX, Ax
is invertible. Theni f f
islight, f
is open[12, 75-76].
PROOF. Let x E S. Since
f
islight,
from the Zoretti Theorem[12, 35],
there exists an open set Tcontaining
x, suchthat T C S,
T ishomeomorphic
to170(l),
and such that(-T)
nf-lf(x)
=0.
Thus
f(x)f(-T).
Then from Fact 2.6, we see that the com-ponent
V ofE- f(-T) containing 1(x)
lies inf(T),
and thusf(x)
lies in the open subset V off(S).
4. Removable
singularities
DEFINITION 4.1. Let
f
be a continuous function on an open set S in E intoE,
and A a subset of S. Thenf
is called aPA
functionif for every x e
A,
there existsMz
> 0, such thatIt may be
readily
shown[4,
Theorem3.2]
thatif f is a PA
functionand
m(A)
= 0, thenm[f(A)]
= 0.THEOREM 4.1. Let G be a
compact
transitivesubgroup of G(E),
and F a TGM
family of
E. Then the elementsof
F are harmonicfunctions
and hencecontinuously differentiable.
PROOF. This lemma may be found in
Lowdenslager [8, 468-469]
and
[7].
Set U =
V0(1),
and let W be thefamily
of all continuous functions h onU,
such thathl U
lies in F. For h e w andz~,
setL(h)
= CfU hdm,
andÂ(z) = fG hg(z)du(g), where p
is normalized Haar measure onG,
and C-1 =m(U).
Then for h eW, x
eU,
andg e
G, Îg(x) = À(x).
Hence for 0 r ~ 1, since G istransitive,
Â(x)
=À(y)
for all x, y eBo(r).
Fix h e W. Then
A
lies in the closure of W and hence must be maximummodular,
and thus must be a constant function. ThusThus the elements of W
satisfy
the volume mean characterization of harmonic functions.THEOREM 4.2. Let
f
be a bounded continuousfunction
on an open set S in E intoE,
H a subseto f S,
and A an elementof B[E, E], A ~
0, such that:1. There exists a
polynomial P,
irreducible overR,
such thatP(A) = 0.
2. For x e
S - H, the
derivativeAx o f f
at xexists,
and is such thatAxA
=AAx.
3. Either :
a.
m(H)
= 0, andf is
aPH function;
ORb. H is countable.
Then
f
isdifferentiable
onS,
andA x A
=AAx f or
all x eS.PROOF : Let Z be the
subalgebra
ofB[E, E] generated by A,
andlet T be the set of all elements B of
B [E, E]
such that A B = BA.Since A is irreducible over
R,
Z isisomorphic
to thecomplex
field K. For x e
E,
c eZ,
set cx =c(x).
Then E can be consideredas a
complex
Hilbert space H overZ,
with T =B[H, H].
Letx E S - H. Then
Ax
eT,
andPx = {c
eZ;
A - cI does notinvert}
is finite. Thus there exists an arc W in Z with
endpoints Ax
andI, containing
nopoints
ofPx.
ThusW CI [E, E],
and from Fact 2.503BC(Ax)
=p(I)
= 1. Set G =G(H) Ç B[H, H] C B[E, E].
ThenG is a
compact
transitivesubgroup
ofG(E).
Let V be the
family
of all continuous functions h on open subsets of E intoE,
such that there existsHh Ç
domh,
such that h andHA satisfy
thehypothesis
and conditions 1, 2 and 3.a of this theorem.Let L e
E*,
and setV L
={Lh;
h~V}.
ThenL f
~VL.
For h
E V ,
since h is differentiable onS-HA,
where S = domh,
h is aPs
function. Lethl,
...,hm
eV,
rI, ..., rm eR,
m e m.Then, setting H
=Um1Hhi, m(H)~ 03A3mi=1 m(HAi)
= 0.Clearly
h= 03A3mi=1 rihi
is a
Ps function,
and hence h is aPH
function. ThenV L
is a TGfamily.
For r eR,
and h eV,
since h-rI andHh satisfy
condition3.a,
m[(h-rI)(Hh)]
= 0, and hence from Theorem 3.1, Lh is maximum modular. ThusV L
is a TGMfamily.
From Theorem 4.1, the elements of
VL are
harmonic functions and hencecontinuously
differentiable. Since E is finitedimensional,
we
readily
deduce[3]
that the elements of Tl arecontinuously
differentiable. For h e
V,
sinceHh
is nowhere dense inE,
and T isclosed, Ax
must lie in T for all x eHA.
The
argument
in the case that H satisfies condition 3.b. is similar.REMARK 4.1. Theorem 4.1 asserts that the elements of a TGM
family
F are harmonic functions. Hence the elements of F areactually analytic.
It is then easy tostrenghten
the conclusion of Theorem 4.2 to an assertion ofanalyticity.
REMARK 4.2. In the two dimensional
theory [4,
6, 9,12] strong
use is made of
auxilary
functions of the formhowever in the
higher
dimensional case, ingeneral,
no similarfunctions,
are available. Forexample,
let M be a closedsubspace
of dimension
greater
than one of acomplex
Banach space B. Assume there exists acomplex
differentiable function g onM-{0}
into B orinto
K,
suchthat ||g(x)|| = ||x||-1
forx~M-{0}.
Now there existsa
subhyperplane
N ofM,
such that0
N. ThengiN
is a boundednon-constant
complex
differentiable function onN, contradicting
Liouville’s Theorem
[3, 5].
The
only
extension the author is aware of involves the space ofquaterneons Q.
Let H be a closed nowhere dense subset of U =V0(1),
and letf
be a continuous function on U intoQ,
suchthat for x e
U-H,
the derivativeAx
off
at x exists and is such that thereexists qx~ Q,
such thatAx(y)
= qxy forall y
eQ.
Letxl, x2
E S-H,
and set, for i = 1, 2,Ti(h) = [f(xi+h)-f(xi)]h-1
for all h E
Q, h ~
0, such thatxi+h
eH,
and setTi (h) = qxi
forh = 0.
Then for i = 1, 2,
Ti
is continuous at 0, and the derivativeHix
ofTi
at x exists for ah x e domTi, x ~
0. Let x e domT’1
n domT2,
x ~ 0. Then for i = 1, 2,
by
directcomputation
where pix=qx-[f(xi+x) (H1x-H2x)(t)= (P1x-P2x)tx-1.
Since Q
is a skew fieldH1x-H2x
isidentically
0 or inverts. In the latter case there exist continuous functions u and v on[0,1]
intoQ - (0),
such thatu(0)==v(0)=1, u(1)=p1x-p2x,
andv(1)=x-1.
For s e
[0, 1],
te Q,
setg8(t)
=u(s)t . v(s).
Then g8 is invertible for all s e[0, 1],
and hence from Section 2,03BC(H1x-H2x) =03BC(g1)=
p(go) = peI)
= 1. Then if U-H hasfinitely
manycomponents,
and
m(H)
= 0 andf
is aPH function,
or in theterminology
of[4]
there exists an Mfamily
ofpartitions E
of H andf
is a Z’function,
we conclude thatT1-T2
satisfies the Maximum Modulus Theorem. Thenworking
with sequences of differencequotients (cf.
[9]
or[4,
Theorem3.3])
we deduce thatf
is differentiable on U.5. Rectifiable interfaces
DEFINITION 5.1.
Throughout
this section H shall denote a.fixed finite dimensional
complex
Hilbert space with an involutionx~x*, x~H.
If
f
is a differentiable function on an open subset S of H intoH+
then
f
is said to besymmetrically
differentiable if for all xe S,
y, z e
H, [fx(y), z*]
=[f’x(z), y*].
We letf(n)xdenote
the n-th derivativeof
f at r for z e S, n e m.
We observe that if we
replace
Hby
a three dimensional real Euclidean space that therequirement
ofsymmetric differentiability
of a function g reduces to the
requirement
that the curl ofg, V
X g, vanishesidentically.
THEOREM 5.1. Let
f
be asymmetrically differentiable function
onU =
V0(1)
into H. Then there exists acomplex differentiable function
h on U into
K,
such thatfor
x EU,
y eH, h’x(y) = [J(x), y*].
PROOF. Let x e
U, s
eH,
and p e K. Then for all t eH,
(ps), t*]
=[fx’ (t), (03C1s)*]
= p[fx’ (t), s* ]
=p [1.’ (s), t*],
and thus-fx(ps)
=pfx(s)
andf
iscomplex
differentiable. Then(cf.
Remark4.1 and
[3], [5]) f(n)
exists for all n e ro, and the power series03A3~0 fÕn) (x, ..., x)/n!
convergesuniformly
oncompact
subsets of U tof(x).
For n e cv, xE H,
setkn(x) = f(n)0 (x,
...,x)/n!
andhn(x)= [f(n)0 (x, ..., x), X*].
Let e > 0, x e U. Then there exists 0 03B4
1-||x||,
such thatfor y e
Ux(03B4), s, t
eH, ||f’x+y-f’x-f’’x(y)||~ 03B5||y||/2,
and hence sincef
issymmetrically differentiable,
and thus
Continuing
this process we deducethat
Now
îor x, t
eH,
and
uniformly
oncompact
subsets of U to a differentiable limit functionh, and for x~U, t~H,
Now for
and thus h is
complex
differentiable.THEOREM 5.2. Set U =
Vo(1 ),
let M > 0, and let h be a homeo-morphism of ET
ontotl,
suchthat ||h(y)-h(x)||
~Mlly-xll I
and||h-1(y)-h-1(x)||~ Mlly-aell for all z, y e U. Let z e E, ||z||
= 1, and setAo
={x
eU; [x, z]
=0},
andSo
=h(Ao),
and letf
be acontinuous
function
onU
intoU.
Thenif f
issymmetrically dif- ferentiable
onU-So, f
issymmetrically differentiable
on U.PROOF. Set
Al
={x
eU; [XI ZI 0}, A2
=(x~ U; [XI z]
>0},
and
SI
=h(A1), S2
=h(A2).
From Theorem 5.1,making
use ofthe line
integral analogue
of[4] (or equivalently
themonodromy
theorem of
analytic
continuationtheory),
for i = 1, 2, acomplex
differentiable function gi on
Si
into K isfound,
such that forx e
Si, (gi)’(y)
=[f(x), y*]
for all y e H.We shall show that gl and g2 can be
continuously
extended to1 and 82
in such a way thatthey
can bepieced together
to forma
single
function g onU
which satisfies aLipschitz
condition on U.We will then
apply
Section 4 to g and deduce itsdifferentiability,
and hence that of
f, everywhere
on U.If W is a rectifiable arc in
H,
letL(W)
denote thelength
of W.Let i = 1, 2, and let x, y e
A,.
Then the interval[x, y] Ç A,
andh([x, y])
is a rectifiable arc inSi
such thatL(h[x, y]) M||y-x||.
Then from the suitable form of the mean value theorem
[3, 5], setting
N = sup{||f(t)||; t ~ },
Thus
gi h
and hence g, =(gih)h-1
isuniformly
continuous onS;,
and thus gi can be
continuously
extended to a continuous functiong, on Si.
Let e > 0. Then there exists 03B4 > 0, such
that ||y-x||~03B4,
x, y~, implies ||f(y)-f(x)||03B5.
LetO03C10~03B4/2M,
and0 p po and set for x
~J
={y
EAo ;
y-poz,y+03C10z~U},
and
Since s is
arbitrary, |c(v)-c(u)| = 0,
and c is a constant function Q.Set
g(x) = gl(x)
forx e Sl,
andg(x) = 2(x)+03C3
forx~2-S0.
Then g is continuous on
U.
Clearly
forand
m(So)
= 0. Hence from Theorem 4.2 and Remark 4.1,glU
is at least twice
continuously differentiable,
and thusf
is sym-metrically
differentiable on U.REFERENCES P. ALEXANDROFF and H. HOPF,
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