C AHIERS DE
TOPOLOGIE ET GÉOMÉTRIE DIFFÉRENTIELLE CATÉGORIQUES
R ICHARD N. B ALL
A LEŠ P ULTR
Forbidden forests in Priestley spaces
Cahiers de topologie et géométrie différentielle catégoriques, tome 45, no1 (2004), p. 2-22
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© Andrée C. Ehresmann et les auteurs, 2004, tous droits réservés.
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Article numérisé dans le cadre du programme
FORBIDDEN FORESTS IN PRIESTLEY SPACES by
Richard N. BALL and Ale0160 PULTRCAHIERS DE TOPOLOGIE ET
GEOMETRIE DIFFERENTIELLE CATEGORIQUES
Volume XL V 1 (2004)
Dedicated to the memory
of Japie
VermeulenRESUME. . Les auteurs
pr6sentent
une formule dupremier
ordrecaract6risant les treillis distributifs L dont les espaces de
Priestley P(L)
necontiennent aucune
copie
d’une for6t finie T. Pour desalgebres
deHeyting
L le faitqu’il n’y
ait pas d’ordre fini T dansP(L)
est caracterise par des6quations
ssi T est un arbre. Ils donnent une conditionqui
caract6rise les treillis distributifs dont les espaces de
Priestley
necontiennent aucune
copie
d’une for6t finie avec un seulpoint
additionnel a la base.1. Introduction
Priestley duality provides
animportant
link between distributive lat- tices and(special)
orderedtopological
spaces. Someproperties
of dis-tributive lattices L are well-known to be
expressed
in forbiddenconfig-
urations in the order structure of the
corresponding spaces P(L). Thus,
for
instance,
L is a Booleanalgebra
iffP(L)
hasjust
onelayer,
thatis,
if it contains no non-trivial chain. Or L is
relatively
normal iff P(L)
isa
forest,
thatis,
if it contains no copy of the three element set ofFigure 1;
seeProposition
4.2. Or there are the distributive lattices of Adams and Beazer characterizedby
non-existence of an n-chain inP(L).
1991 Mathematics
Subject Classification. Primary: 06D50,
06D20; Secondary:06D22.
Key
words and phrases. distributivelattice,
trees andforests, Priestley
duality.The first author would like to express his gratitude to the Center for Theoreti- cal Studies for
affording
him the opportunity to spend adelightful
and productive sabbatical year inPrague.
The second author would like to express his thanks to the Institute of Theoretical
Computer
Science(ITI)
at CharlesUniversity
and to the Anne and Ullis Gudder Trust for making visits to Denver possible.FIGURE 1. A
poset
is a forest iff it contans no copy of thisposet.
The
question naturally
arises as towhether, given
a finiteposet T,
the lattices L for
which P(L)
does not contain a copy of T can be char-acterized
by
a first order condition in thelanguage
of latticetheory.
Inthis article we answer this
question
in thepositive
for trees and forestsT,
and for their duals.Moreover,
forHeyting algebras
L we show thattrees are
precisely
the forbiddenconfigurations
which determine sub- varieties(or, equivalently, subquasivarieties)
of thevariety
ofHeyting algebras.
The authors continue to
investigate
thegeneral problem:
to find"nice" conditions
characterizing
those lattices whosePriestley
spacesadmit no copy of a
given poset.
In thisarticle,
thetechniques
devel-oped
for forests are modified to treat forests with asingle
additionalpoint
at thebottom;
this is Theorem 6.6. The condition thatarises, however,
is not first order on itsface,
and we do not know if a firstorder condition exists.
Many
moretypes
ofposets
can be handled simi-larly,
and in fact a solution to thegeneral problem
seemspossible.
Butthese results constitute another article in
preparation.
2. Preliminaries
A
Priestley
space is an orderedcompact
space(X, T, )
such that for any two x, y E Xwith z $
y there is a closed openincreasing
U C Xsuch that x E U
and y /
U. Thecategory
ofPriestley
spaces and monotone continuous maps will be denotedby
PSp.
There is the famous
Priestley duality (see,
e.g.,[9], [10])
betweenPSp
and the
category
DLat
of bounded distributive lattices. The
equivalence
functorscan be
given
asx is a proper
prime
ideal onL}, clopen decreasing
P(L)
is endowed with a suitabletopology
andpartially
orderedby
in-clusion ;
in this article we will be concernedsolely
with thepartial
order.Finite
Priestley
spaces are the finitepartially
ordered sets(with
thediscrete
topologies).
Notethat, however,
the functor D associates witha finite
(X, )
the(lower)
Alexandrofftopology (not
the discreteone)
and that thus the restriction of D to the finite case coincides with the restriction of the
open-set-lattice
functor Q :Top
Frm to finiteTo-
spaces.
(Frm
is thecategory
offrames,
thatis, complete
lattices with thedistributivity (V ai)
A b =V(ai
Ab).)
The full
subcategory
of DLatconsisting
of theHeyting lattices, i.e.,
those lattices of DLat
admitting
theHeyting operation,
will be denotedby
HLat.
We will also consider the
variety
ofHeyting algebras
withHeyting
ho-momorphisms
and denote itby
Hey.
The letters a,
b,
c andd,
often decoratedby subscripts
orprimes,
willbe reserved for the elements of the distributive lattices. The
prime
ideals on such lattices L
(elements
ofP(L))
will betypically
denotedby
x, y, z. For a subset A C L we useAo
for some finite . andAo
for some finite .to
designate
the ideal andfilter, respectively, generated by
A. The setof all proper ideals on L
(ordered by inclusion)
will be denotedby
Definition 2.1. If A is an ideal and B a filter on L we set
Obviously, A |
B is an ideal and At
B is a filter. Forgeneral
subsetsA, B
C L we writeA |
Bmeaning Id1(A) | Fltr(B).
For elementsa, b E L we write a|B
andA|
b for{a} |
B andAt {b}.
Thus forinstance
a |
b ={c |
b A ca}.
The dual conventionsapply
toA |
Band
a |
b.Lemma 2.2. Let
A,
B C L. Then thefollowing,
and theirduals,
hold.(1) A C A | B.
(2) (A|B)|B=A|B.
(3) A |
B is properiff A
n B =0.
(4)
For an ideal A and afilter
B such thatA |
B is proper(that is,
A fl B =0)
there is an x EP(L)
such that A C x and x fl B =Vl.
Proof.
We leave theproofs
of the dual statements to the reader.(1)
1^aa.
(2) IfcE(A|B)|B there is a d E A|B and a b E B such
that b ^ c d. There is an a E A and a b’ E B such that b’ ^ d a;
hence
(b ^ b’) ^ c
a.(3) A|B is proper iff 1 E A|B iff b i.
a foranyaEAandbEB.
(4) Using
Zorn’s lemma we obtain an ideal J maximal withrespect
to J D A and J fl B =
0.
J isprime,
for if cl,C2 tfi
J it canonly
bebecause there
exist bi
E Idl(Cï, J)
flB,
from which weget
and this
implies
thatThe
symbol
will
designate
a finiteposet.
Thisposet
willplay a
central role in our considerations.Definition 2.3. A map m : T -3
J(L) (resp.
m : T ->P(L))
is said tobe monotone if
and m is said to be a copy
of
T if it is monotone andA
mapping
a : T -> L is aseparator
of a monotone map m : T ->3(L)
(resp.
m : T ->P(L)) provided
that for allt,T
ET,
We say that a
separates
m.We introduce a
handy
notation.Definition 2.4. For a map a : T -> L define an associated
map a’ :
T - L
by
the ruleThen a
separates
the monotone map m iff a’(t)
E m(t)
and a(t) E
m
(t)
for all t E T.Obviously
a monotone map with aseparator
is a copy, whether in 3(L)
or P(L).
The converse holds for monotone maps into P(L).
Lemma 2.5. Each copy : T ->
P(L)
has aseparator.
Proof.
Fix t E T. For eachT
t choose ab(T)
Ex(T) B x(t)
and seta(t) = !B,,-it b(r). Since x(t)
is prime, a(t) E x(t).
Of course a(t)
E z(T)
for all the
t t,
whichgives a’ (t)
E x(t).
03.
Prohibiting
forestsIn a
poset
we will writeand say that r is a descendent
of t,
or that t is an ascendentof
r, ifT t and if for every s, T s t
implies
that either s = r or s = t.Denote
by
O
max(T)
the set of all maximal elements ofT,
andby
O
min(T)
the set of all minimal elements of T.A finite
poset
T is said to be aforest
if each t E T has at mostone ascendent. A forest T with
exactly
one maximal element is calleda
tree,
and its maximal element will be denotedby
eT, orsimply by
e.
Obviously,
forests areprecisely
thedisjoint
unions of trees. From thispoint
until Theorem 5.1 we assume T to be aforest.
Without thisassumption
the nextresult,
which is crucial for our purposes, does not hold.Proposition
3.1. Let a : T - Lseparate
the copy J : T ->J(L). If
then there is a copy x : T ->
P(L), separated by
the same a, such thatz(t) D J(t) for
all t.Proof. First,
for maximal elements t of T choosex(t)
EP(L)
suchthat
x(t) ;2 J(t)
andx(t)
nFltr(a(t))
=0, by
Lemma2.2(4).
Thena(t) E x(t),
and for any other maximal t’ we havea(t’)
EJ(t)
gx(t).
Now suppose J has
already
been extended as desired on anincreasing
subset T’ of T
containing
max(T).
Let T" be T’augmented by
all thedescendents T of elements t minimal in T’. For T E T" w T’ with ascendent t we have
Indeed,
otherwise we would have b A a(T)
EJ(T)
for someb E x(t)
and hence b E
J(7) ¡ a(T)
=J(T)
CJ(t)
Cx(t),
a contradiction.Choose
by
Lemma2.2(4)
anx(T)
inP(L)
such thatx(,r) =-2 J(T)
andx(T)
nFltr((L w x(t))
U{a(T)} = 0.
Inparticular, a(7) fj. x(T)
anda’
(T)
E J(T)
C x(T) by
construction. When this process iscomplete,
it is clear that we have a monotone map x : T -> P
(L) separated by
a. 0
Definition 3.2. Let T be a forest and a : T - L any
mapping.
DefineIa :
T ->3(L) inductively by setting
Lemma 3.3.
If a separates
a copy x : T -P(L)
thenIa(t) 9 x(t) for
alltET.
Proof.
We induct on T from the bottom up. If t E min(T)
then anyc E
Ia(t)
satisfies c Aa(t) a’(t)
Ex(t).
Sincea(t) E x(t)
andx(t)
isprime,
c Ex(t).
Assume thatIa(T)
gx(T)
for all T « t. If c EIa(t)
wehave
for some
b,
EIa (T) C x(T)
9x (t),
T t. But then since a’(t)
E x(t)
we see that c A
a(t)
Ex(t),
and because x(t)
isprime
anda(t) E x(t),
c must therefore lie in
x(t).
0Lemma 3.4. Let a : T - L be any map. Then the
following
holdfor all t, E T.
then .
Proof. (1) yields
to asimple
induction on Tusing
Lemma2.2(1),
and(2)
follows from Lemma2.2(2).
0Theorem 3.5. Let T be a
finite forest
and let L be a bounded distributive lattice. ThenP(L)
does not contain a copyof T iff for
each a : T -> L there is a t E max(T)
such thatIa(t)
isimproper.
Proof.
LetP(L)
contain a copy x : T -3 Lseparated by
a : T - L.Then
by
Lemma 3.3 eachIa(t)
lies in the proper idealx(t).
On theother
hand,
if there is an a : T -> L such thatIa(t)
is proper for all t then from Lemmas2.2(3)
and3.4(2)
we can conclude that for all t ET,
a(t) E Ia(t)
since otherwiseIa (t)
would beimproper. Furthermore,
Lemma
3.4(1)
shows thata’(t)
EIa(t)
for all t. SinceIa
is monotonethere is a copy x : T ->
P(L) separated by a by Proposition
3.1. 0Our next
objective
is to show that the absence of a copy of T in P(L)
can be characterizedby
the satisfaction in L of aspecific
firstorder sentence
çT
in thelanguage
of latticetheory, Corollary
3.10. Forthat purpose let us rewrite the formulas of Definition 3.2 in a
slightly
more
specific
form. Recallthat a’ (t)
is thejoin
of the a(Q)’s with o, 4
t.Now if Q > T for some T t then o > t since T is a forest. Thus
Now those a’
(T)’s
with T t arealready
in theIa (T)’s by
Lemma2.2(1).
Therefore the formulas of Definition 3.2 can bereplaced by
This observation motivates the
following
definition.Definition 3.6. Let a : T -> L be any function.
A T-supplement of
ais a function c : T -> L such that for all t E
T,
A
T-complernent of
a isa T-supplement
c for which c(t)
= 1 for somet E max
(T).
The remarks
prior
to Definition 3.6 make it clear that c(t)
EIa (t)
for all t E T whenever c is a
T-supplement
of a. This allows us to reformulate Theorem 3.5 in terms ofT-complements
in Theorem 3.9.Example
3.7. Denoteby
n the chain10
1 ...n}.
An n-com-plement of
asystem (a0, a1,..., an) is
a(co,
cl, ... ,cn)
such thatand
Thus, (a,1)
hasexactly
one1 -complement, namely
the(c,1)
with c thecomplement of a
in L.Observe that
if (co, ... ,
Cn-1,cn)
is ann-complement of
asystem of
theform (ao,
... ,an- 1, 1)
then it is also ann-complerraent of (ao,
... , an-1)an) for
any an. Thus everysystem (ao,
... ,an)
has ann-corrapdement iff for
every smaller
system (ao,
...an-1)
there is some(co, ... , cn-1)
such thatand
Example
3.8. Let T be an antichain. Then a : T -> L has a T-complement iff
there is a t E T such thatTheorem 3.9. Let T be a
finite forest
and L a bounded distributive lattice. ThenP(L)
does not contain a copyof T iff
eachmapping
a :T -> L has
a T-complement. If T is a
tree this in turn isequivalent
torequiring
that each a : T -> L such thata(eT)
= 1 hasa T-complement.
Proof.
To use Theorem 3.5 fix a map a : T -> L. We havealready
remarked that if c is a
T-supplement
of a then c(t)
EIa (t)
for allt E T. Since the
Ia (t)’s
are all proper, no c(t)
can be 1. On the otherhand suppose that for some
to E
T we haveWithout loss of
generality
we may assume thatto E max (T).
Setc (to)
- 1. Then there must be elementsc (T),
Tto,
such thatNow we can
proceed inductively.
If c(t)
hasalready
been chosen inIa (t),
we have a(t)nc (t) Y T--(t
c(7)VY T--(t
a(T)
for some c(T)
EIa (T),
t t.
Proceeding
thus down to the minimum elements underto,
anddefining c (t)
- 0 for all t not belowto,
we obtain aT-complement
ofa. 0
We remark in
passing
that it is not difficult to show that for any mono-tone map a : T -> L and any t E
T, To (t)
={c (t) :
cT-supplement
ofa}.
Corollary
3.10. For anyforest
T there is a sentence1bT in
thefirst
order
language of
latticetheory
such thatfor
any bounded distributive latticeL, P (L)
contains no copyof T iff çT
holds in L.Moreover, ’OT
is
of
theform VZo, where 0 is quantifier-free
and built upfrom
atomicformulas by conjunction
anddisjunction. If
T is a treethen 0
is aconjunction of
atomicformulas.
Proof.
Letxt, yt, t E T,
besyntactic
variables. We think of maps a, c : T -> L asassigning
values a(t)
tovariables zt
and c(t)
to variablesyt, t E T.
Furthermore,
a look at Definition 3.6 reveals that most of theinequalities
which make c aT-complement
of a are combinedby conjunction,
with theonly disjunction being
where max
(T)
-ftl, t2, ... , tn}.
If T is a tree there isonly
asingle disjunct, i.e.,
the formula is atomic. The result follows from Theorem3.9. D
Example
3.11(Example
3.7revisited).
We obtain the characterizationof
Adams and Beazer[1] stating
thatP(L)
contains no chainof length
n
iff for
any ao, a,, ... , an-1 in L there are co, cl, ... , cn-1 in L such thatand
In
particular,
the order inP(L)
is trivialiff
L is a Booleanalgebra.
Example
3.12(Example
3.8revisited).
Each antichain inP(L)
hasat most n - 1 elements
iff for
any a,, ... , an in Lthere
is a k such thatExample
3.13. No antichain with at least nelements,
nfixed
and>
2,
has an upper bound inP (L) iff for
any al, ... , an E L there arec’, ... , c’n
E L such thatfor
allk,
ak^c’k Vi=k
aj, andVi
aj VVj cj
=1.
Replacing
theck by
Ck =Ck
VVjlk
aj, we see that no antichain withat least n
el ements,
nfixed
and >2,
has an upper boundin P(L) iff for
any al, ... , an E L there are cl, - - - , cn E L such that
for
allk,
and
Example
3.14.P(L)
has noindependent system of
n 1-chainsiff for
any a1, ... , an
and bl ... , bn
in L there are C1, ... , Cn in L and ako
suchthat
and
The characterizations in the theorems above can be
easily
modifiedfor dual trees and dual forests. Denote
by |P(L) the poset
structure ofP(L).
Aprime
ideal in L is aprime
filter inL°P,
and vice versa. Thuswe have an
anti-isomorphism
and
Hence,
T°P is forbiddenin P(L)
iff T is forbiddenin P(Lop).
For ex-ample,
since T isisomorphic
to TOP inExamples
3.11 and3.12,
theconditions that arise there must be
equivalent
to their duals. Infact, they
are self-dual. This is obvious in the case of Exercise3.11;
to seethat the condition of
Example
3.12 is selfdual,
suppose that for any subset{ai :
1 in}
g L there is a k such that akVj,4k
aj.Apply
this condition to to
get
a k for whichwhich shows
that ak > Ai:ok
ai,i.e.,
L satisfies the dual condition.4. Normal and
relatively
normal latticesWe
digress
for a brief discussion of normal andrelatively normal lat-
tices. Most of this material iswell-known;
we offerproofs only
becausethe ideas are very close in
spirit
to those of the rest of this article.Recall that a distributive lattice L is normal if for any two
a1, a2 E L
such that al V a2 = 1 there are cl, c2 E L such that al V
c1 >
a2,a1 Vc2 >
aI, and CIÂC2 = 0. This is anextrapolation
of thehomonymous
notion from
topology:
a space is normal iff the lattice of open sets is normal in the sensejust
defined. Thefollowing
characterization of normal lattices in terms of theirPriestley
spaces is well known and isessentially
due to Monteiro([7], [8]),
whoproved
it in the context of theopen set lattice of a space.
Proposition
4.1. Thefollowing
areequivalent.
(1)
L is normal.(2) Every point of P (L)
lies below aunique maximal point.
(3)
In P(L),
anypair of
elements with a common lower bound must have a common upper bound.Proof.
Theequivalence
of(2)
and(3)
is clear uponreflecting
on ageneral
fact about
Priestley
spaces: everypoint
lies below a maximalpoint
andabove a minimal
point.
That is because thefamily
ofprime
ideals ofa distributive lattice is closed under both the union and intersection of chains.
Suppose
that L isnormal,
and assume for the sake ofargument
that P(L)
contains apoint
X3 which lies below two distinct maximalpoints
x, and x2. Since Idl
(Xl, X2)
isimproper,
there are a, Ex, B
X2 anda2 E
X2 B
x, such that al V a2 = T. Find ci, c2 E L for which al V c2 =cl V a2 = 1 and CIÅ c2 = 0. Then because X3 is
prime,
it contains either ci or C2. But if ci E X3 then 1 = ci V a2 E X2 and if c2 E X3 then 1 = al V cz E xl, a contradiction in either case. We conclude that everypoint
of P(L)
lies below aunique
maximalpoint.
Now suppose that L is not
normal;
this means we have elements a, and a2 for which al V a2 = 1 butFltr (al t
a2, a2T al)
is proper. Let7
designate
the set ofpairs (F1, F2)
of filters on L with thefollowing properties.
O al
fix
a2C Fl
and a2t
al CF2.
O Fltr
(al fi Fl, a2 t F2)
is proper.Note that 7 is
nonempty
because it contains(al fi a2, az T al) by hypothesis.
Also notethat,
when orderedby
the ruleand .
7 is closed under
joins
of chains and so contains a maximal element(K1, K2).
Observe thatKl =
alt K1
andK2
= a2f K2 by maximality,
so that
al ft Kl
anda2 ft K2
lest the filters beimproper.
We claim thatKl
andK2
areprime.
Toverify
this claim considerb, b’ E K1.
Thisimplies
that there are elementski, k’
EKl
andk2, k’ E K2
such thatBut if we set
k"1
=k1 ^ k’1
EKl and kg
=k2
Vk’2 E K2
weget
which
implies
bV b’ E K1.
Theproof
thatK2
isprime
is similar.Let Xl, X2 be maximal elements of P
(L) containing
theprime
idealsL B Kl
andL B K2, respectively.
Then a, EXl B
X2 and a2 EX2 B
xl,so the maximal elements are distinct. Let X2 be maximal among ideals
disjoint
formFltr (K1, K2) .
Then X3 is a common lower bound for x1and x2 in P(L).
0A lattice L is
relatively
normal if for any two al, a2 E L there arecl, c2 such that a, V
c1 >
a2, a2 Vc2 >
al, and ci A c2 - 0. Intopol-
ogy this
corresponds
to therequirement
that each opensubspace
of thespace in
question
is normal. Relativenormality plays
afundamental,
though
sometimesunacknowledged,
role in several areas of mathemat- ics. Forexample,
the lattice of cozero sets of atopological
space isalways relatively
normal[6],
and it is no accident that relative normal-ity
is thekey ingredient
in the construction of what are called Wallmancovers of
topological
spaces[5].
A secondexample
is thepenetrating
and beautiful structure
theory
of lattice-ordered groups(t-groups
forshort), developed by
Conrad and his students([3]
is the bestgeneral reference),
based on the lattice of convexi-subgroups.
This lattice isalgebraic, i.e., complete
andgenerated by
itscompact elements,
and thecompact
elements themselves form arelatively
normal sublattice. The class ofjust
suchlattices,
devoid of any groupstructure,
was subse-quently extensively investigated by
Tsinakis and his students([4], [11], [12]).
Their work shows that alarge part
of thet-group
structure the-ory comes
directly
from the latticetheory,
and in fact from the relativenormality
of the sublattice ofcompact
elements of the lattice of convext-subgroups.
We content ourselves here with the observation that the relative nor-
mality
of L isequivalent
to P(L) being
a forest. This isessentially
dueto Monteiro
([7], [8]),
whoproved
it in the context of the open set latticeof a space.
Proposition
4.2. L isrelatively
normaliff P(L) is
aforest.
Proof.
The definition of relativenormality
is the dual of the condition ofExample
3.13 for n = 2. Thus L isrelatively
normal iff no two unrelated elements of P(L)
have a common lowerbound, i.e.,
iff P(L)
is a forest. D
Thus
Proposition
4.2 characterizes the relativenormality
of Lby
theprohibition
of theposet
ofFigure
1 in P(L).
The reader maynaturally
ask whether the
normality
of L can be likewise characterized. Theanswer is
negative.
Take a standardexample
of a normal space A withsubspace
B which is notnormal,
and let L and M be thetopologies (sets
of open
sets)
of A andB, respectively.
Let h : L -> M be themapping
which sends U to U n B. This is an onto lattice
homomorphism,
andit is easy to check that P
(h) :
P(M) ->
P(L)
is an orderembedding.
Now if
normality
of a lattice were characterizedby
the nonexistence ofa copy of a finite
poset
in itsPriestley
space then such a copy would exist in P(M)
but not in P(L),
a contradiction. ’5.
Equations forbidding
treesWe show that if L is a
Heyting algebra
then each map a : T - L hasa
largest T-supplement,
which we willdesignate aT . (We
order mapsa, b : T - L
by declaring
that a > b if a(t)
> b(t)
for all t ET.)
Thusany such map a will have a
T-complement
iffaT
is aT-complement.
Thisfact eliminates the existential
quantifier
in the sentence1bT
ofCorollary
3.10.
Consequently
theHeyting algebra
whosePriestley
spaces containno copy of a
given
fixed tree form avariety.
Thesurprise
is thatonly
trees have this
property;
this is the content of Theorem 5.9.For the rest
of
this section we assume that L is aHeyting lattice, i. e.,
that L is a bounded distributive lattice which admits theHeyting implication operation
->. Whenactually equipped
with thisoperation,
L becomes a
Heyting algebra
and the maps arerequired
to preserve ->as well as the lattice structure. We ask the reader to
keep
in mind thedefining
feature of ->,namely
that for a,b, c E L,
Definition 5.1. Let L be a
Heyting algebra.
For a : T -> L defineaT :
T -> Linductively
as follows.Lemma 5.2. Let L be a
Heyting algebra.
For any map a : T ->L, aT
is the
largest T-suPplerraent of
a.Proof. Compare
Definitions 3.6 and 5.1 inlight
of(*).
0Corollary
5.3. Let L be aHeyting algebra.
Then a map a : T -> L hasa T-complement iff aT is
aT-complement.
Corollary
5.4. Let L be aHeyting algebra.
For any map a : T ->L,
for
allCorollary
5.5. Let L be aHeyting algebra.
P(L)
contains no copyof
T
iff for
every map a : T - L we haveaT (t)
= 1for
some t E max(T).
Corollary
5.6. Let L be aHeyting algebra
and T be a tree withtop
element e. Then P
(L)
contains no copyof T iff aT (e)
= 1for
everymap a : T - L.
The condition of
Corollary
5.6 can becaptured by
the satisfaction ofa
particular
first-order formula in thelanguage
ofHeyting algebras.
Forthe
aT (t)’s
of Definition 5.1 build up towhere
pT
is apolynomial
in V and -> into which the values of a areinserted. Thus we have the
following.
Corollary
5.7. For every tree T there is apolynomial pT
in V andwith variables
indexed by
the nodesof
T such that aHeyting algebra
Lsatisfies
theequation pT (a)
= 1iff
P(L)
does not contain a copyof
T.We pause to review the main features of
Priestley duality
in the con-text of
Heyting algebras.
For asubspace
U of aPriestley
spaceX,
denote as usual
(The danger
ofconfusing
this notation with the use oft and |
elsewherein this article is
minimal,
since therethey designated binary
functionson subsets of the
lattice,
whereas herethey designate
unary functionson subsets of the
Priestley space.)
Remark 5.8. The
following facts
are well-known.(1)
D(X)
is aHeyting algebra iff |U is
openfor
every open U C X.(2)
TheHeyting operation in
D(X), in
termsof clopen
downsets Uand
V,
is then(3) If D (X)
and D(Y)
areHeyting algebras
then aPriestley
mapf :
Y - Xyields
aHeyting homomorphism
D( f ) :
D(X ) ->
D
(Y) iff for
all x EX,
The last fact will be crucial in the remainder of this section.
For the rest
of
this article zvesuspend
theconvention
that T is aforest,
and assumehenceforth only
that T is afinite poset.
Theorem 5.9. Let T be a
finite poset,
and let X be the classof Priestley
spaces X such that the
Priestley
dualof
X is aHeyting lattice,
and suchthat X contains no copy
of T.
Let V be the classof Heyting algebras
withPriestley
spaces(of
theunderlying lattices)
in X. Then thefollowing
statements are
equivalent.
(1)
T is a tree.(2)
V is asubvariety of Hey
determinedby
one extraequation
in Vand ->.
(3)
V is asubquasivariety of Hey, i. e.,
V is closed underproducts
and
subobjects.
Proof.
Theimplication
from(1)
to(2)
isProposition 5.7,
and from(2)
to
(3)
is trivial. So assume(3)
to prove(1).
Since V is closed underproducts,
X is closed under sums and hence T has to be connected.Now define
T
as the set of all words iv =tlt2 ... tn
in verticesti
of T such thattn
is maximal andti ti+l
for all i n. Ordert by declaring
iff for some
Define
f : T -+
Tby setting
Then
(a) f
is monotone andonto,
(b) f (|w) =|f (w), and
(c)
if w « w’ then w’ isuniquely
determined.If
L and
L are theHeyting algebras
withPriestley
spacesT
andT,
we have L
isomorphic
to asubalgebra
of Lby
Remark5.8(3).
HenceL 0 V
since otherwise L E V and T E X. ThusT
contains a copy ofT,
and
by (c)
and the connectedness we see that T is a tree. 0Restricting
ourselves to the finite case wesimilarly
obtain the follow-ing.
Theorem 5.10. Let T be a
finite poset,
let X be the classof finite posets containing
no copyof T,
and let V be the classof Heyting algebras
with
Priestley
duals(of
theunderlying lattices) lying
in X. Then thefollowing
statements areequivalent.
(1)
T is a tree.(2) V
is the classof finite algebras of
asubvariety
Vof Hey
deter-mined
by
one extraequations
in V and -.(3) V is
the classof finite algebras of
asubquasivariety of Hey.
6. Forests with a bottom
point
The
general problem
we would like to solve is tofind,
for any finiteposet T,
a "nice" condition on a lattice L which is both necessary and sufficient to insure that P(L)
admits no copy of T. In this section wemake use of our
techniques
toprovide
a smallstep
in the direction of thegeneral problem by treating
the case of a forest with one additionalpoint
at the bottom. The result is Theorem6.6,
and the reader mayjudge
whether the condition on L which arises there is nice.However,
this condition is not first order on its
face,
and we do not know if afirst-order condition exists.
Throughout
this section Tdesignates
a finiteposet
with least elementto
such that T’ -T B Itol
is anonempty
forest. We retain some of the notation usedheretofore;
forexample,
themap a’ :
T - L associatedwith the map a : T -> L is still
given by
the ruleNote in
particular
that a’(to)
=0,
and that asbefore,
aseparates
acopy m : T - 3
(L)
iff a’(t)
E m(t)
and a(t) V
m(t)
for all t E T. Wemust, however, modify slightly
the notion of aT-supplement
of a mapa: T -+ L.
Definition 6.1. Let a : T -3 L be any function.
A T-supplement of
ais a function c : T - L such that
A
T-complement of
a isa T-supplement
c for whichc (t)
= 1 for somet E max (T).
We letc is
a T-complement of a} .
The distinction between the two notions of
T-supplement, i.e.,
be-tween Definitions 3.6 and