A NNALES DE LA FACULTÉ DES SCIENCES DE T OULOUSE
L ABROS D OKAS J OHN S TABAKIS
Comments on the completeness of order complements and on the Prüfer numbers
Annales de la faculté des sciences de Toulouse 5
esérie, tome 10, n
o1 (1989), p. 65-73
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65
Comments
onthe completeness of order complements
and
onthe Prüfer numbers
LABROS
DOKAS(1)
AND JOHNSTABAKIS(1)
Annales Faculté des Sciences de Toulouse Vol. X, nOl, 1989
ABSTRACT. - Given a poset we define two chain - extensions of it ; the
first is the system of all its chains without end points, the order is a system of directed sets for which a linear subset is cofinal therein. The latter is
complete, in a meaning, while the two completions applied to the set of non negative numbers ordered by division, give isomorphie complements. Each complement consists the underlying set for a system which is closed under the operations of the product, g.c.d. and l.c.m. of any number of elements
(Prufer numbers).
Subj.
Class. AMS1981, 06A10,
06A23.1. Introduction
The present note is concerned with two
order-complements
introducedby
the authors in[1]
and[5].
The aim of this reference is togive
a notionof
"completeness"
oforder-complements and,
as anapplication,
to makecomments on a
complement
of the setNo
of thenon-negative integers,
ordered
by divisibility.
The main theorems will include the
following
results :given
the orderstructure
(E, ~, symbolize by
E* and thef *
and the KRASNERcomplement respectively.
Thena) (~*)* -
E*.(1) University of Patras, Departement of Mathematics, 26110, Patras, Greece.
b)
In thecomplement E*
every cutof
a chain is not a gap.c)
Thecomplement
as well as the(No)*,
is the setof Prufer
numbers .
Propositions a)
andb)
state that thecompletion
of acomplement,
aswell as the restriction of the whole space to a chain
subset,
does notgive
new
elements ;
the structure iscomplete.
Thiscompleteness
is non valid inother cases, in say the Mac Neille’s
complement.
But it is remarkable that another version of thecompletion procedure,
forexample
the consideration of the lower classes A of the cuts(A, B)
instead of the cutsthemselves,
leadsto another
complement,
which is connected with the formerby
asurjective
isotone
function,
but has not such acompleteness.
This is the difference between the twocomplements
of our case.Statement
c)
says that thecorresponding complement
ofNo
is theunderlying
set of analgebraic system
whichgeneralizes
the well-knownPrfifer
groupp°°).
From another
point
of view the mentioned structures are not lattices ingeneral,
butthey
could becharacterized,
both ofthem,
as chain-extensions( ~2~, ~ I ) ; by
this we mean thatthey
are definedby
subsets wich are cofinal tototally
ordered sets.2. KRASNER
complement
andf*-complement
of an orderstructure
We
briefly
restate the twocomplements.
Wealways
refer to an orderstructure
(E, ).
2.1. Consider a subset L of E ordered
by
a total order a and an elementa E L. The subset
is called
final
sectionof
L withorigin
a. The structure(L, cx)
is calledmonotone, if a is the restriction on L of or >
(in
wich cases(L, a)
iscalled
increasing
ordecreasing resp.).
Such a structure(L, rx)
cannot beincreasing
and at the same timedecreasing
unless if it is asingleton.
Ifthere exists a final section
La
of(L, a)
such that(La, ce)
is monotone, then(L, 03B1)
is calledasymptotically
monotone(as. monotone )
and a theorigin
of
themonotony.
If for an a EL, (La, a)
admits a maximum orminimum,
(L, a)
is called as. constant.Two as. monotone structures
(L, a1 )
and(M, a2 )
are calledequivalent (L -
M insymbols)
if for eachorigin
ofmonotony a
of L and b ofM,
we can, for any x E
La,
find a y EMb
and a z ELa
such that x03B11z and y E(x, z~,
where~x, z~
is thesegment
of E. If L = M and L has a last element e, M also has e as lastelement,
otherwise L and M areincreasing
and
decreasing simultaneously.
Evidently
the relation is anequivalence.
If now
M(E)
is the set of monotone structures ofE,
define an orderin
M(E) : (L, (M, a2)
if there existorigins
ofmonotony
a and b of Land M
respectively
such that for any x ELa
and any y EMb, x
y. The order is an extension of,
so in thesequel
we use the samesymbol
forboth of them..
The set
M(E)/ =
orderedby
the above relation is called KRASNERcomplement of
E(symbolize by
In thecomplement,
an element e E Eis identified with a class a E
M(E),
whose elements are subsets of E that have e as last element.2.2 The
f*-complement
is an imitation of Mac Neille’scomplement,
whose classes are subsets cofinal to a
totally
ordered set.DEFINITION 1.
((5J,
A
couple (A, B)
of subsets of an ordered set E is calledf *-cut,
if it fulfilsthe next
properties :
(1)
The subsetsA, B
are directed(right
and leftrespectively).
(2) If x E A and y E B, x y.
(3)
There does not exist any element between x and y.(4)
There exist chainsL1, L2
subsets of A and Brespectively, L1 being
cofinal to A and
L2
coinitial to B(that is,
cofinal for theopposite direction).
(5)
If x E Aand x’
x,then x’
E A as well as if y E Band yy’, y’
E B.The subsets A and B are called the lower and the upper class resp. of
(A, B).
If there exists the maximum of A and the minimum ofB,
thef *-cut
is called
f *- jump,
if neither of themexists,
it is calledf*-gap.
Symbolizing by L*(E)
the set off*-gaps,
we callf*-complement of
Ethe set E* =
EUL* (E)
orderedby
thefollowing
order(extension
of thegiven ).
If x,y
belong
to E and ,( A2 , B2 ~
arenon-equal
elements ofL*(E),
then :Remark.-If
A* (E)
is the set of the classes of thef*-cuts
of E withoutend
points,
we define an order relation on E UA*(E)
in such a way thatthe new
complement
coincides with KRASNERcomplement.
To each lowerclass A of a
f *-cut (A, B),
as well as to each upper one, which is cofinal toa chain
L, corresponds
thepoint
ofExr
which has as arepresentative
thechain
L,
andinversely.
3. The
completeness
of thef*-complement
Henceforth,
E*symbolizes
thef*-complement
of an ordered set E. Thefirst result
concerning
to thecompleteness
of E* is the next.THEOREM 1.2014
(E* )*
= E*.The
proof
of theorem 1 followsimmediately
from the lemmas 1 and 2.LEMMA 1.- lem.
1~.
Between twocomparable
elementsof
t~~ef*-complement
E* lies at least one elementof
the set E. Moreover the trace on Eof
af *-cut of
E* is af *-cut of
E.LEMMA 2. - The trace on E
of
anf *-gap of
E* is also af *-gap of
E.Proof. - Let (A*, B*)
and(A, B)
be thef*-gap
of E* and its trace onE, respectively. Suppose
the classes A and B have not endpoints,
otherwisethese
points
are the endpoints
of A* and B* as well. The statements(1), (2), (3)
and(5)
of Def. 1 areevidently
fulfilledby A
and B.About the statement
(4) :
let L* be a chain of E cofinal to A*. The choiceaxiom
implies
that each chain has a well ordered subset which is cofinal to it. If I* =(xi )
is this subset ofL*,
we’llassign
to it a well orderedfamily
~ _
(x a )
of elements of A cofinal to I *So,
for any successive elementsxi,
,of E*
pick
up an element x= EA,
which isgreater
thanx~
and smalleror
equal
to Such an element exists because of lemma 1.The
procedure
goes oninductively,
withrespect
to the element x* of I* : :regardless
of x *being
next to an element of I* orbeing
a limitpoint
of afamily
ofpoints
ofI*, assign
to x* an element of A which lies between x*and the element of
I*,
which is next to x*. Theassigned x
consist a chaincofinal to A. It is evident that another chain of elements of
B ,
is cofinal(for
the
opposite direction)
to B.The
proof
of the theorem is an easy consequence : if(A, B)
is af*-gap
of
E*,
then its trace(A, B)
on E is also af*-gap
inE,
which defines anelement in E* not
belonging
to A* orB*,
absurd.Remark. - If a is an element of and it has as a
representative
a monotone
chain,
say theincreasing
chainA C E,
then a chain in the setEKT
cofinal toA, gives
in the set an element different than a(actually
it is smaller thana).
Thus from thispoint
of view the KRASNERcomplement
is not acomplete
one.’
We now
proceed
togive
two resultsreferring
to thecompleteness
of thechains which are maximal with
respect
to the inclusion into thecomplement
E*.
PROPOSITION 1.2014
Every
chain in thef*-complement,
maximal withrespect
toinclusion,
has not gaps.Hence the statement asserts that chains into the
f*-complement
arecomplete
subsets.Proof.
- Consider a chain I * maximal into theE* ,
a,nd a cut( A1, B~ )
of it.
Suppose
that the cut is a gap. Weproceed
to construct a cut(A*, B*)
of
E*,
in themeaning
of Mac Neille’scomplement ;
then either A* or B*has an end
point
a and the subset I * U~ a ~
will be a chainproperly greater
thanI*,
which is absurd.In fact. Put : B* =
(y
E E* : :(Vz
C~}
and A* ={:r
~ E* : :(Vy
EB* ) ~x y~ ~
The
couple (A*, B*)
is a cutand,
on the otherhand,
there exists af *-cut (A,, Bi)
such thatAl
CAi
andB1
CBE,
whilst it isA=
C A* andBi
C B*.Because of the non-existence of
f*-gaps
inE*,
at least one of the classesAa
andBi
has an endpoint
a.PROPOSITION 2. - The Dedekind
complement of
a chain Iof
E andevery maximal chain
of
thef*-complement
E* whose trace on E is thechain I are
isomorphic (that is,
there exists asurjective
and isotone mapof
the
former
onto the lastchain ).
Proof
-By
Dedekindcomplement
of I we mean thesimple complement
of a
totally
ordered set. IfID
is the Dedekindcomplement
of I and I * is amaximal
(with respect
to the inclusionrelation)
chain of E* whose trace onE is the chain
I,
define a mapf : : ID ~
I* as follows :for each x E
I, put f (x)
= x.Let e =
( I1, IZ )
be a gap of I. Consider the subsets :I2
={y
E 1* :(‘dx
EIi) [x
andI;
= The setI;
has notan end
point,
because if maxl~l
= a, then for x E a, hence a EI2
,false. On the other
hand,
the class because of prop. 1- has a minimum e *~. Thenput
= ~. .The map
f
isinjective
and preserves the order. Infact ;
let e =( Iz 12)
and e’ =
( I1, I2 )
be two gaps of I with e e’. Then there is x E12
nIi ,
hence x E I* and
f (e)
xf (e’).
It is evident that the last result isvalid,
when e or e’ is an element of I.
Finally f
issurjective :
let e* EI*BI;
consider the subsetsIi
={x
E I :x
e*}
and12
= . The subsets7i
and12
consist apartition
of Iwithout any
point x
E E between the elements of these two classes. On the otherhand,
neither of the two classes has an endpoint,
becauseif,
say,a = max
Ii
and e* =(A, B)
EL*(E),
then a E A and there exists x E11,
x > a, that is the element x lies between the classes
Ii
andI~,
absurd. Thuse =
I2)
is a gap of I and -by
the definition off -
it isI(e)
= e*. .4. The
f *
and KRASNERcomplements
ofNo
The last
paragraph
is devoted to aroughly speaking algebraic application
of the mentioned
complements.
Consider the set
No
ofnon-negative integers
orderedby divisibility.
Putm/n
if m dividesn(m,
n ENo).
The least commonmultiple
and thegreatest
common divisor of the natural numbers m1, m2, ... , are
symbolized by [mi,
m2, ... ,, mn~
and(mi,
m2, ... ,, mn) respectively.
The two
complements
ofNo coincide,
so we referexclusively
to thestructure
(No)Kr.
’
PROPOSITION 1.2014 The lattice
(No, l)
has not any gap.Proo,f
. Consider a cutE2)
inITo.
If m1, m2, ... , mibelong
toE~,
their m2, ....,
mz~
divides each n ~EE2
and if n2, ...belong
to
E2,
then each m EE~
divides theg.c.d.
of nl, n2, - ..Three cases are
possible.
(1) E2 = 0 ;
then2?i
=No, E~
has a maximumpoint 0,
hence(E1,E2)
is not a gap.
(2) E2 = ~o~ ;
then eachm ~
0 divides0,
hence mbelongs
toEi.
Theclass
E2
has a minimum and the cut(El E2 )
is not a gap.(3)
There exists n EE2, n 7~
0. Then each element m E.Ei
divides n and the classjE"i
has a finite number ofelements,
say.E1
= m2, ...If m = m2, ... , each proper divisor of m
belongs
toEl
and eachmultiple
of it toE2.
Thepoint
m itself eitherbelongs
toE1
or toE2
and ineach case it is the end
point
of therespective
class. Thus thecouple (E1, E2 )
is non-gap, even if m E
E2
is of the formpe f= 1,
where p is aprime.
Infact,
in this
exceptional
case, the classEi
is the set of the proper divisorsof pe
,(that
is the divisors of so eachE2
is amultiple
of and itdoes not need to be a
multiple of pe .
The
Prüfer
group(pOO)
is a famousexample
of an additive group whose each extension to aring
is a zeroring (e.g. [4],
p.60).
If ak is any root of theunity
withamplitude ~,
p is aprime, k E N,
then each numbera°~~
... where ENo, 1
i ~1 2 .. n
written in the additive form 03C31 a1 + 03C32a2 +...+belongs
to(pOO).
Theproduct
of twosuch elements is zero. The set
of Pru, f er’.s
numbers is the set of all numbers of the formwhere 03C9p is
non-negative integer
orinfinity
and P is the set ofprime
numbers.
The set is closed under the
operations
of theproduct,
of the9 .c.d.
aswell as of l.c.m. It could be characterized as a
generalization
of the set ofthe coefficients of Prufer
rings,
when theprime
p goesthrough
the set P ofprime
numbers(e.g. [3], §§35
and81).
THEOREM 2. -- The KRASNER
complement of (No /)
is the setof Prüfer’s
numbers.
Proof.
- Let e* be an element of(No, /)kr
and =(A, /)
a representa- tive of e, which we suppose to be monotone(considering a,
if it isneeded,
as a final
section).
If a and a are ofopposite kind,
then either A ={0},
inwhich case the
support
A has a last element a* =0,
orA ~ {0~
in whichcase there exists an element
a ~
0 and because a has a finite number ofdivisors,
A has a last elementa*,
hence e* = a*. On the otherhand,
if aand a coincide and A has a last element
a*,
we also have e* = a*.Suppose
now that a and a coincide and that A has not a last element.If a,
a’
, x are non zero elements of a anda/x / a’,
, then x divides a’ andthe number of these x’s is finite. Thus the chain A can be written as
{ a1, a2 , ...
, a=,... }
where ai for each i EN.Inversely
each sequenceof the above form is the
representative
of an elementnon-belonging
toNo.
Infact,
let p be aprime
number andwp(ai) the
order of ag withrespect
to p. Then >wp(aa)
and the function wp is anincreasing
function of i. If wp is
bounded,
itfinally gets
a fixedvalue,
otherwise itis
increasing infinitely.
Definewp(A)
as the fixed value in the former caseand the value +00 in the last one,
(put n
+00 for each nEN).
Ifb = (B, /) is a
monotone structure and a =b,
then b isincreasing
withouta last
element,
thus B ={ b1, b2,..., bz, ... ~,
whereb1 / b2 /
.../ bz / bi~.1 /
...for any az E A and any index
jo,
there existb~
EB, j
>jo
and ak E Asuch that ak. This shows that hence
wp(A) wp(B)
CWp(A)
orwp(A)
=wp(B).
Inversely,
if for eachprime
p,wp(B)
=wp(A),
it is a = b. Infact ;
let ~t E
A,
and a~ =prl
1p;2... p~’
a be theprime
factordecomposition
of ai. It is 7g
wpq (A)
= q =1, 2, ... ,
s. Hence there exist indices~1, ,~2, ... , js,
such that > aq. Butthen,
for agiven jo,
it
is j ~ j o where j
=max j q
and for all values of q, there holds : aq, hence a, ib;. Changing
the roles of a andb,
it is evident that there exists an ak such that
b~
ak, thus a = b. So theclass of
equivalence
e* of the structure a =(A, /)
which is monotone andhas no last
element,
iscompletely
definedby
theassignment :
:p -~
wp(A), p E P,
P the set ofprime
numbers.The element e* can be written under the form
~ pwp B .
pEP
Consider now a number of the form
~ where ~p E No
U
pEP*
’
and
p*
is an infinite subset ofP,
orp*
is finite but one of o~p is +00.Suppose
that all of the
prime
numbers pi , p2 , ... , , p=, ... i L -I-ao have been put73 in an
increasing
order. PutWe have to define the value of Put = 0 or Min
depending
onwhether q
> L or i > q. If A = a2, ... aZ,... ~
then weget
wp(A)
= O’~.The elements of the last form are the elements of .
Remark. . - It is evident that the
operation
of theproduct
and the opera- tions offinding
the least commonmultiple
and thegreatest
common divisorin the set
(No)kr,
is an extension of therespective
habitualoperations
inthe set
No,
thatis,
theseoperations
can be defined for any subset of them and notonly
for finite subsets. So the least commonmultiple
of any subset of elements of the set is zero.References
[1] DOKAS (L.).- Certains complétés des ensembles ordonnés munit d’opérations.
Complété de KRASNER, C.R.Acad. Paris, t. 256, 1963, p. 3937-39.
[2] ERNE (M.). 2014 Posets isomorphic to their extensions, Order, t. 2, 1985, p. 199-210.
[3]
FUCHS (L.). - Infinite Abelian Groups, Tomes I, II, Academic Press N. York London 1973.[4]
REDEI (L.).- Algebra., Pergamon Press. Oxford, 1967.[5]
STRATIGOPOULOS(D.),
STABAKIS (J.).2014 Sur les ensembles ordonnés(f*-coupes),
C.R.Acad. Paris, t. 285, 1977, p. 81-84.
(Manuscrit reçu le 18 avril 1988)