Sharp upper bounds for a singular perturbation problem related to micromagnetics
ARKADYPOLIAKOVSKY
Abstract. We construct an upper bound for the following family of functionals {Eε}ε>0, which arises in the study of micromagnetics:
Eε(u)=
ε|∇u|2+1 ε
R2|Hu|2.
Hereis a bounded domain inR2,u∈ H1(,S1)(corresponding to the mag- netization) andHu, the demagnetizing field created byu, is given by
div(u˜+Hu)=0 inR2, curlHu=0 inR2,
whereu˜is the extension ofuby 0 inR2\. Our upper bound coincides with the lower bound obtained by Rivi`ere and Serfaty.
Mathematics Subject Classification (2000): 49J45 (primary); 35B25, 35J20 (secondary).
1.
Introduction
In this paper we study the following energy-functional, related to micromagnetics:
Eε(u):=
ε|∇u|2+1 ε
R2|Hu|2. (1.1) Here is a bounded domain in
R
2 with Lipschitz boundary, u is a unit-valued vector-field (corresponding to the magnetization) in H1(,S1) and Hu, the de- magnetizing field created byu, is given by
div(u˜+Hu)=0 in
R
2curlHu =0 in
R
2, (1.2)Received December 5, 2006; accepted in revised form November 22, 2007.
whereu˜is the extension ofuby 0 in
R
2\. For the physical models related toEε, we refer to [18] and all the references therein.We can rewrite (1.1) in the following form. Denoting by−1u˜ the Newtonian potential ofu, we observe that the vector-field˜ H¯u := −∇
div(−1u˜)
belongs to L2(
R
2,R
2). Moreover,
divH¯u= −divu˜ in
R
2 curlH¯u =0 inR
2. SoHu = ¯Huand we obtainEε(u)=
ε|∇u|2+ 1 ε
R2∇
div(−1u˜)2. (1.3) In [19] T. Rivi`ere and S. Serfaty proved the following theorem, giving compactness and a lower bound for the energies Eε.
Theorem 1.1. Letbe a bounded simply connected domain in
R
2. Letεn → 0 and un ∈ H1(,S1)with a liftingϕn ∈ H1(,R
)i.e., un = eiϕn a.e., and such thatEεn(un)≤C (1.4)
ϕnL∞()≤N. (1.5)
Then, up to extraction of a subsequence, there exists u andϕin∩q<∞Lq()such that
ϕn →ϕin ∩q<∞Lq() un →u in ∩q<∞Lq() . Moreover, if we consider
Ttϕ(x):=inf ϕ(x),t Ttu(x):=ei Ttϕ(x),
thendivxTtu is a bounded Radon measure on×
R
, with t →divxTtu continuous fromR
toD
(). In addition2
R
divxTtud x dt≤ lim
n→∞
2|∇ϕn·Hun| ≤ lim
n→∞Eεn(un) <∞. The main contribution of this paper is to establish the upper bound for Eε in the case whereuand its liftingϕbelong toB V. First of all we observe that ifεn →0,
Eεn(un) ≤ C, and un → u in Lq, where |un| = 1 and u ∈ B V then clearly
nlim→∞
R2|Hun|2=0, which implies
nlim→∞
R2u˜n· ∇δ= − lim
n→∞
R2Hun· ∇δ=0 ∀δ∈Cc∞(
R
2,R
) . Therefore, divu˜ =0 as a distribution,i.e.,
|u| =1 a.e. in , divu=0 in , u·n=0 on∂ .
(1.6)
The main result of this paper is the following theorem.
Theorem 1.2. Let be a bounded domain in
R
2 with Lipschitz boundary. Con- sider u ∈ B V(,S1), satisfyingdivu =0inand u·n=0on∂and assume there existϕ ∈ B V(,R
), such that u= eiϕ a e. in. Then there exists a family of functions{vε} ⊂C2(R
N,R
)satisfyingε→lim0+vε(x)=ϕ(x) in L1(,
R
) andε→lim0Eε(eivε)=2
R
divxTtud x dt. Moreover, ifϕ∈ B V(,
R
)∩L∞, then we haveε→lim0+vε(x)=ϕ(x) in Lp(,
R
) ∀p∈ [1,∞) .In order to construct{vε}we take the convolution ofϕ with a varying smoothing kernel, i.e., we setvε(x) := ε−2
R2ηy−x
ε ,x
ϕ(y)d y where η ∈ Cc2(
R
2×R
2) satisfiesR2η(z,x)d x = 1 for every x ∈ , and we optimize the choice of the kernel η. A similar approach was used in [16] and [17], but a new ingredient is required here, since the non-local term
R2|Hu|2gives certain difficulties.
1.1. The basic idea
We shall follow essentially the strategy of [16] and [17]. The main new ingredient here is the calculation of
ε→lim0+
1 ε
R2
∇
div(−1{χeivε})2. (1.7) We first calculate
L(l):= lim
ε→0+
1 ε
R2∇
div(−1{ϕε})2,
where ϕε(x):=ε−2
R2ly−x
ε ,x
ϕ(y)d y, with l ∈ Cc2(
R
2 ×,R
2)satisfyingR2l(z,x)d x =0 for every x ∈. Since∇
div(−1{φε})
has the same asymp- totic behavior asε−2
R2sy−x
ε ,x
ϕ(y)d y, wheres(z,x):=∇z
divz(−z1l(z,x)) , we can calculate the limit L(l)in a similar way to what was done in [16] and [17]
(see Lemmas 3.1 and 3.2 for the details). Using the results of [17] (see Proposition 2.2 below) it is easy to calculate
D(l):= lim
ε→0
1 ε
eivε −ϕε−u2d x.
Now, given a fixed η and a small δ > 0, we choosel = lδ in such a way that D(lδ) < δ. Then, using the estimate
R2∇
div(−1{χf})2≤C
|f|2, we deduce that
ε→lim0
1 ε
R2∇
div(−1{χeivε})2−1 ε
R2∇
div(−1{χϕε})2
≤ lim
ε→0C 1
ε
R2
∇
div(−1{χ(eivε−ϕε−u)})21/2
≤Cδ1/2. Finally, tettingδ tend to 0, we conclude that the limit in (1.7) should be equal to limδ→0L(lδ). We follow basically this strategy in the proof of Proposition 4.1.
ACKNOWLEDGEMENTS. I am grateful to Prof. Camillo De Lellis for proposing this problem to me and for some useful suggestions. Part of this research was done dur- ing a visit at the Laboratoire J. L. Lions of the University Paris VI in the framework of the RTN-Programme Fronts-Singularities. I am indebted to Prof. Haim Brezis for the invitation and for many stimulating discussions.
2.
Preliminaries
Throughout this section we assume thatis a bounded domain in
R
2with Lipschitz boundary. We begin by introducing some notation. For every ν ∈ S1 (the unit sphere inR
2) andR>0 we denoteB+R(x,ν)= {y ∈
R
2 : |y−x|< R, (y−x)·ν >0}, (2.1) B−R(x,ν)= {y ∈R
2: |y−x|< R, (y−x)·ν <0}, (2.2) H+(x,ν)= {y ∈R
2:(y−x)·ν >0}, (2.3) H−(x,ν)= {y ∈R
2:(y−x)·ν <0} (2.4)and
Hν0= {y ∈
R
2 : y·ν=0}. (2.5)Definition 2.1. Consider a function f ∈B V(,
R
m)and a pointx ∈.i) We say thatx is a point ofapproximate continuityof f if there exists z ∈
R
m such thatρ→lim0+
Bρ(x)|f(y)−z|d y
L
2Bρ(x) =0.In this casezis called anapproximate limitof f atxand we denotezby f˜(x). The set of points of approximate continuity of f is denoted byGf.
ii) We say thatx is anapproximate jump pointof f if there exista,b ∈
R
m and ν ∈SN−1such thata=bandρ→lim0+
Bρ+(x,ν)|f(y)−a|d y
L
2Bρ(x) =0, limρ→0+
Bρ−(x,ν)|f(y)−b|d y
L
2Bρ(x) =0. (2.6) The triple (a,b,ν), uniquely determined by (2.6) up to a permutation of (a,b) and a change of sign of ν, is denoted by(f+(x), f−(x),νf(x)). We shall call νf(x)the approximate jump vectorand we shall sometimes write simplyν(x)if the reference to the function f is clear. The set of approximate jump points is denoted by Jf. A choice of ν(x)for everyx ∈ Jf (which is unique up to sign) determines an orientation of Jf. At a point of approximate continuity x, we shall use the convention f+(x)= f−(x)= ˜f(x).We refer to [2] for the results on BV-functions that we shall use in the sequel.
Consider a function = (ϕ1, ϕ2, . . . , ϕd) ∈ B V(,
R
d). By [2, Proposi- tion 3.21] we may extend to a function¯ ∈ B V(R
2,R
d), such that¯ = a.e. in , supp¯ is compact and D(∂)¯ = 0. From the proof of Proposi- tion 3.21 in [2] it follows that if∈ B V(,R
d)∩L∞then its extension¯ is also in B V(R
2,R
d)∩L∞. Consider also a matrix valued function∈Cc2(R
2×R
2,R
l×d) For everyε >0 define a functionε(x):R
2→R
l byε(x):= 1 ε2
R2y−x ε ,x
· ¯(y)d y
=
R2(z,x)· ¯(x+εz)d z, ∀x ∈
R
2.(2.7)
Thanks to [17, Proposition 3.2], we have the following result. It generalizes Propo- sition 3.2 from [16] and provides the key tool for the calculation of the upper bound, both in [17] and in the current paper. In the proof of Lemma 3.2 we shall also follow the general strategy of its proof in [17].
Proposition 2.2. Let W ∈C1(
R
l×R
q,R
)satisfying∇aW(a,b)=0 whenever W(a,b)=0. (2.8) Consider∈B V(,
R
d)∩L∞and u ∈B V(,R
q)∩L∞satisfyingW R2(z,x)d z
·(x), u(x)
=0 for a.e. x∈ , where∈Cc2(
R
2×R
2,R
l×d), as above. Letε be as in(2.7). Then,ε→lim0
1 εW
ε(x),u(x) d x
=
J
0
−∞W
(t,x),u+(x) dt +
+∞
0
W
(t,x),u−(x) dt
d
H
1(x) , (2.9)where
(t,x)= t
−∞P(s,x)ds
·−(x)+ +∞
t
P(s,x)ds
·+(x), (2.10) with
P(t,x)=
Hν(x)0
(tν(x)+y,x)d
H
1(y) , (2.11) ν(x)is the jump vector ofand it is assumed that the orientation of Ju coincides with the orientation of JH
1a.e. on Ju∩J.Definition 2.3. Given f ∈ L∞(
R
2,R
k)with compact support, we define its New- tonian potential−1f (x):=
R2
1
2π ln|x−y| f(y)d y. Than it is well known that
R2∇2 −1f
(x)2d x =
R2|f(x)|2d x, (2.12) where givenv=(v1, . . . , vk):
R
2 →R
k we denote by∇2v∈R
k×2×2the tensor withli j-th component∂i j2vl.Definition 2.4. Let
V
be the class of all functionsη∈Cc2(R
2×R
2,R
)such thatR2η(z,x)d z=1 ∀x ∈ . (2.13) Let
U
be the class of all functionsl(z,x)∈Cc2(R
2×,R
2)such that
R2l(z,x)d z=0 ∀x∈
R
2. (2.14)In [17, Lemma 5.1], we proved the following statement. This statement generalize Claim 3 of Lemma 3.4 from [16] and was an essential tool in the optimizing the upper bound in [17].
Lemma 2.5. Letµ be positive finite Borel measure on andν0(x) : →
R
2 a Borel measurable function with |ν0| = 1. LetW
1 denote the set of functionsp(t,x):
R
×→R
satisfying the following conditions:i) p is Borel measurable and bounded,
ii) there exists M >0such that p(t,x)=0for|t|> M and any x ∈, iii)
R p(t,x)dt =1,∀x ∈.
Then for every p(t,x) ∈
W
1, there exists a sequence of functions{ηn} ⊂V
(see Definition2.4), such that the sequence of functions{pn(t,x)}defined onR
×bypn(t,x)=
Hν0 0(x)
ηn(tν0(x)+y,x)d
H
1(y),has the following properties:
i) there exists C0such thatpnL∞ ≤C0for every n,
ii) there exist M >0such that pn(t,x)=0for|t|>M and every x ∈, for all n.
iii) limn→∞
R|pn(t,x)− p(t,x)|dt dµ(x)=0.
With the same method it is not difficult to prove
Lemma 2.6. Letµ be positive finite Borel measure on andν0(x) : →
R
2 a Borel measurable function with |ν0| = 1. LetW
0 denote the set of functions q(t,x):R
×→R
2satisfying the following conditions:i) q is Borel measurable and bounded,
ii) there exists M >0such that q(t,x)=0for|t|> M and every x∈. iii)
Rq(t,x)dt =0, ∀x ∈.
Then for every q(t,x) ∈
W
0, there exists a sequence of functions{ln} ⊂U
(see Definition2.4), such that the sequence of functions{qn(t,x)}defined onR
×byqn(t,x)=
Hν0 0(x)
ln(tν0(x)+y,x)d
H
1(y), has the following properties:i) there exists C0such thatqnL∞ ≤C0for every n,
ii) there exist M >0such that qn(t,x)=0for|t|> M and every x ∈, for all n,
iii) limn→∞
R|qn(t,x)−q(t,x)|dt dµ(x)=0.
3.
First estimates
Throughout this section we assume thatis a bounded domain in
R
2with Lipschitz boundary.Letl ∈
U
(see Definition 2.4). Considerr(z,x) := −z1l(z,x). Then r ∈ C2(R
2 ×R
2,R
2) with suppr ⊂R
2 × K, where K . Moreover, sinceR2l(z,x)d z=0, for everyk=0,1,2. . .we have the estimates
|∇kxr(z,x)| ≤ Ck
|z| +1, ∇xk
∇zr(z,x)≤ Ck
|z|2+1, ∇kx
∇2zr(z,x)≤ Ck
|z|3+1,
(3.1)
whereCk >0 does not depend onzandx.
Lemma 3.1. Letϕ ∈ B V(,
R
)∩L∞and l ∈U
(see Definition2.4). For every ε >0consider the functionϕε ∈C1(R
2,R
2)byϕε(x):= 1 ε2
R2l y−x
ε ,x
ϕ(¯ y)d y =
R2l(z,x)ϕ(¯ x+εz)d z, (3.2) where ϕ¯ is some bounded B V extension ofϕ to
R
2 with compact support. Next consider r(z,x):=−z1l(z,x)and setξε(x):= 1 ε2
R2∇1
div1ry−x ε ,x
ϕ(¯ y)d y
=
R2∇z
divzr(z,x)
¯
ϕ(x+εz)d z,
(3.3)
where∇1(div1r)is the gradient of divergence of r(z,x)in its first variable, namely z. Then,
R2
1 ε∇
div(−1ϕε)
(x)2d x =oε(1)+
1
εϕε(x)·ξε(x)d x. (3.4) Proof. Sincel(z,x)=0 ifx∈/ K, whereK is some compact subset of, we have, in particular,ϕε(x)=0 for everyx∈
R
2\. Then, integrating by part two times, we conclude
R2
1 ε∇
div(−1ϕε) (x)2d x
= −
R2
1 ε
div(−1ϕε) (x)·
div(−1ϕε) (x)d x
= −
R2
1
εdivϕε(x)·
div(−1ϕε) (x)d x
=
1
εϕε(x)· ∇
div(−1ϕε) (x)d x.
(3.5)
Next consider the functionζε ∈C1(
R
2,R
2)given by ζε(x):= 1ε2
R2r y−x
ε ,x
ϕ(¯ y)d y=
R2r(z,x)ϕ(¯ x+εz)d z. (3.6) We will prove now that
ε2∇2ζε(x)−
R2∇z2r(z,x)ϕ(¯ x+εz)d z
≤Cε2/3 ∀x ∈ . (3.7) We shall denote by∇1l and∇2lthe gradient ofl(z,x)with respect to the variables zandx respectively. We have,
ε2∇2ζε(x)−
R2∇z2r(z,x)ϕ(¯ x+εz)d z
=
R2∇x2r y−x
ε ,x
ϕ(¯ y)d y− 1 ε2
R2∇12r y−x
ε ,x
ϕ(¯ y)d y
= −1 ε
R2
∇1∇2r y−x
ε ,x
+ ∇2∇1r y−x
ε ,x
ϕ(¯ y)d y
+
R2∇22r y−x
ε ,x
ϕ(¯ y)d y.
(3.8)
Therefore, by the H¨older inequality and the estimates in (3.1), we obtain ε2∇2ζε(x)−
R2∇z2r(z,x)ϕ(¯ x+εz)d z
≤ε2/3 1
ε2
R2
∇1∇2r y−x
ε ,x
+∇2∇1r y−x
ε ,x 6/d y5
5/6
R2| ¯ϕ(y)|6d y 1/6
+ε2/3 1
ε2
R2
∇22r y−x
ε ,x3d y 1/3
R2| ¯ϕ(y)|3/2d y 2/3
=ε2/3
R2
∇1∇2r z,x
+ ∇2∇1r
z,x6/5d z 5/6
R2| ¯ϕ(y)|6d y 1/6
+ε2/3
R2
∇22r
z,x3d z 1/3
R2| ¯ϕ(y)|3/2d y 2/3
≤Cε2/3 which gives (3.7). In particular,
ε2ζε(x)−ϕε(x) =
ε2ζε(x)−
R2zr(z,x)ϕ(¯ x+εz)d z
≤C0ε2/3.
(3.9)
Next by (3.5),
R2
1 ε∇
div(−1ϕε)
(x)2d x=
1
εϕε(x)· ∇
div(−1ϕε) (x)d x
=
1
ε ϕε(x)· ∇ div
ε2ζε(x) d x
−
1
ε ϕε(x)· ∇ div
−1
ε2ζε−ϕε (x)d x.
(3.10) The last integral can be estimated by
1
εϕε(x)· ∇ div
−1
ε2ζε−ϕε (x)d x
≤
1
ε|ϕε(x)|2 1/2
1 ε
R2
∇ div
−1
ε2ζε−ϕε (x)2d x
1/2
≤
1
ε|ϕε(x)|2 1/2
2 ε
R2
∇2 −1
ε2ζε−ϕε (x)2d x
1/2
=
1
ε|ϕε(x)|2 1/2
2
εε2ζε(x)−ϕε(x)2d x 1/2
. Then, since
1
ε|ϕε(x)|2≤C
1 ε|ϕε(x)|
≤ ¯C
1 ε
BR(0)l(z,x)
¯
ϕ(x+εz)−ϕ(x) d z
d x
≤ ¯C
BR(0)
1
ε|l(z,x)|
ϕ(¯ x+εz)−ϕ(x)d x d z
≤ ¯CDϕ(¯
R
2)BR(0)|l(z,x)| · |z|d z= O(1) ,
(3.11)
using (3.9), from (3.10) we infer
R2
1 ε∇
div(−1ϕε)
(x)2d x=oε(1)+
1
εϕε(x)·∇
div
ε2ζε(x)
d x. (3.12) Next we remind thatξε is defined by (3.3). By (3.7), we have,
∇ div
ε2ζε(x)
−ξε(x)≤ ¯Cε2/3 ∀x ∈ . (3.13)
Then as before,
1 εϕε(x)·
∇ div
ε2ζε(x)
−ξε(x)
d x
≤
1
ε|ϕε(x)|2 1/2
1 ε∇
div
ε2ζε(x)
−ξε(x)2d x 1/2
≤Cε1/6.
Therefore, from (3.12) we infer (3.4).
Lemma 3.2. Letϕ ∈ B V(,
R
)∩L∞and l ∈U
(see Definition2.4). For every ε >0and every x∈R
2consider the functionϕε ∈C1(R
2,R
2)as in(3.2). Then,ε→lim0
R2
1 ε∇
div(−1ϕε) (x)2d x
=
Jϕ
+∞
−∞ |ϕ+(x)−ϕ−(x)|2· ν(x)·
+∞
t
q(s,x)ds 2dt
d
H
1(x) , (3.14)where
q(t,x)=
Hν(x)0
l(tν(x)+y,x)d
H
1(y) , (3.15) andν(x)is the jump vector ofϕ.Proof. By Lemma 3.1 we have
R2
1 ε∇
div(−1ϕε)
(x)2d x =oε(1)+
1
εϕε(x)·ξε(x)d x. (3.16) From this point the strategy of the proof is similar to that in [16] and [17] (see also Proposition 2.2). The only difference is that here ξε is defined by a convolution of ϕ¯ with a kernel whose support is not compact. However, it turns out that this difference is not crucial and we can use almost the same approach.
Step 1. We prove a useful expression,
1
εϕε(x)·ξε(x)d x
= 1
0 R2
1 t2ε2
∩BRtε(y)
ξε(x)·l y−x
tε ,x y−x
tε d x
·d[Dϕ](¯ y)
dt, (3.17)
where ξε is as in (3.3) and R > 0 is such thatl(z,x) = 0 whenever|z| ≥ R.
As before, we shall denote by ∇1l and∇2l the gradient ofl with respect to the first and second variables respectively. Denote
ϕtε,1(x), ϕtε,2(x)
:= ϕtε(x)and l1(z,x),l2(z,x)
:=l(z,x). Then for everyt ∈(0,1], every j ∈ {1,2}and every x∈
R
2we haved
ϕtε,j(x)
dt = d
dt 1
t2ε2
R2lj y−x
tε ,x
ϕ(¯ y)d y
=− 1 t3ε2
R2
∇1lj y−x
tε ,x · y−x
tε +2lj y−x
tε ,x
ϕ(¯ y)d y
= − 1 t2ε
R2divy
lj y−x
tε ,x y−x
tε
¯ ϕ(y)d y
= 1 t2ε
R2lj y−x
tε ,x y−x
tε ·d[Dϕ](¯ y) .
(3.18)
Therefore, for anyρ∈(0,1)we have,
1 ε
ϕε(x)−ϕρε(x)
·ξε(x)d x
=
1
εξε(x)· 1
ρ
d ϕtε(x)
dt
d x
=
1 ρ ξε(x)·
1 t2ε2
R2l y−x
tε ,x
y−x
tε ·d[Dϕ](¯ y) dt
d x
= 1
ρ ξε(x)· 1
t2ε2
R2l y−x
tε ,x
y−x
tε ·d[Dϕ](¯ y) d x
dt
= 1
ρ R2
1 t2ε2
∩BRtε(y)
ξε(x)·l y−x
tε ,x y−x
tε d x
·d[Dϕ](¯ y)
dt. (3.19)
From our assumptions onϕ, by (3.1), it follows that there exists a constantC >0, independent ofρ, such thatξρ(x)≤C for everyρ >0 and everyx ∈. There- fore, lettingρtend to zero in (3.19), using the fact that limρ→0ϕρ(x)L1() = 0 (see (3.11)), we get (3.17).
Step 2. We prove the identity
R2
1 ε∇
div(−1ϕε) (x)2d x
=oε(1)+ 1
0 Jϕ BR(0)
l(z,x)·ξε(x−εt z) z d z
·d Dϕ
(x)
dt
+ 1
0 Gϕ BR(0)
l(z,x)·ξε(x−εt z) z d z
·d Dϕ
(x)
dt,
(3.20)
whereGϕis the set of approximate continuity ofϕ. By (3.16) and (3.17) we deduce
R2
1 ε∇
div(−1ϕε) (x)2d x
=oε(1)+ 1
0 R2
1 t2ε2
∩BRtε(y)
ξε(x)·l y−x
tε ,x y−x
tε d x
·d[Dϕ](¯ y)
dt
=oε(1)+ 1
0 R2
1 t2ε2
K∩BRtε(y)
ξε(x)·l y−x
tε ,x
y−x tε d x
·d[Dϕ](¯ y)
dt, (3.21) whereK
is a compact set (see Definition 2.4). But, for everyε <R1dist(K, ∂) we have
R2
1 t2ε2
K∩BRtε(y)
ξε(x)·l y−x
tε ,x
y−x tε d x
·d[Dϕ](¯ y)
=
1 t2ε2
K∩BRtε(y)
ξε(x)·l y−x
tε ,x
y−x tε d x
·d[Dϕ](¯ y)
=
1 t2ε2
R2
ξε(x)·l y−x
tε ,x
y−x tε d x
·d[Dϕ](¯ y) .
Therefore, by (3.21), we obtain
R2
1 ε∇
div(−1ϕε) (x)2d x
=oε(1)+ 1 0
1 t2ε2
R2
ξε(x)·l y−x
tε ,x
y−x tε d x
·d[Dϕ](¯ y)dt
=oε(1)+ 1
0 BR(0)
l(z,y−εt z)·ξε(y−εt z) z d z
·d Dϕ
(y)
dt
=oε(1)+ 1
0 BR(0)
l(z,x)·ξε(x−εt z) z d z
·d Dϕ
(x)
dt,
(3.22)
where in the last equality we used the estimate|l(z,x−εt z)−l(z,x)| ≤Cεt|z|. Therefore we obtain (3.20).
Step 3. We will prove that the second integral in the r.h.s of (3.20) vanishes as ε→0. For everyxinGϕwe have,
ρ→lim0+
1 ρ2
Bρ(x)| ¯ϕ(y)− ˜¯ϕ(x)|d y =0. Takingρ= Lε, for everyL >0, gives
ε→lim0+
BL(0)| ¯ϕ(x+εz)− ˜¯ϕ(x)|d z=0, forxinGϕ. (3.23) Using (3.1), since
R2∇z
divzr(z,x−εt y)
d z =0, for everyxinGϕ,y∈ BR(0), t ∈ [0,1]andL>0 we have,
|ξε(x−εt y)| =
R2∇z
divzr(z,x−εt y)
¯
ϕ(x+εz−εt y)d z
=
R2∇z
divzr(z,x−εt y)
¯
ϕ(x+εz−εt y)− ˜¯ϕ(x) d z
≤
BL(0)
∇z
divzr(z,x−εt y)·ϕ(¯ x+εz−εt y)− ˜¯ϕ(x)d z +
R2\BL(0)
∇z
divzr(z,x−εt y)·ϕ(¯ x+εz−εt y)− ˜¯ϕ(x)d z
≤AL
BL(0)| ¯ϕ(x+εz−εt y)− ˜¯ϕ(x)|d z+B
R2\BL(0)
1
|z|3+1d z
≤AL
B(L+R)(0)| ¯ϕ(x+εz)− ˜¯ϕ(x)|d z+B
R2\BL(0)
1
|z|3+1d z,
(3.24)
where B > 0 is a constant and AL > 0 depends only on L. Givenδ > 0 we can takeL>0 such that
B
R2\BL(0)
1
|z|3+1d z < δ ,
Then, using (3.24) and (3.23), we infer limε→0+|ξε(x−εt y)|< δand sinceδwas arbitrary,
ε→lim0+ξε(x−εt y)=0 ∀x ∈Gϕ, y∈ BR(0), t ∈ [0,1]. (3.25) Using (3.1), we also have|ξε(x −εt y)| ≤C, and therefore, plugging (3.25) into (3.20), we obtain
R2
1 ε∇
div(−1ϕε) (x)2d x
=oε(1)+ 1
0 Jϕ BR(0)
l(z,x)·ξε(x−εt z) z d z
·d Dϕ
(x)
dt. (3.26)
Step 4. Considerl¯(z,x):= ∇z
divzr(z,x)
. For everyε,t ∈ (0,1),x ∈ Jϕ and z∈BR(0), we have
ξε(x−εt z)=
R2
l¯(y,x−εt z)ϕ¯
x+ε(y−t z) d y
=
R2
l¯(y+t z,x−εt z)ϕ¯ x+εy
d y
=
H+(0,ν(x))
l¯(y+t z,x−εt z)ϕ¯ x+εy
d y
+
H−(0,ν(x))
l¯(y+t z,x−εt z)ϕ¯ x+εy
d y
=
H+(0,ν(x))
l¯(y+t z,x−εt z)ϕ+(x)d y
+
H−(0,ν(x))
l¯(y+t z,x−εt z)ϕ−(x)d y
+
H+(0,ν(x))
l¯(y+t z,x−εt z)
¯
ϕ(x+εy)−ϕ+(x) d y
+
H−(0,ν(x))
l¯(y+t z,x−εt z)
¯
ϕ(x+εy)−ϕ−(x) d y.
(3.27)