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Geometry of Certain Lie-Frobenius Groups

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HAL Id: hal-00005449

https://hal.archives-ouvertes.fr/hal-00005449

Preprint submitted on 18 Jun 2005

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Jean Michel Dardie, Alberto Medina, Hassène Siby

To cite this version:

Jean Michel Dardie, Alberto Medina, Hassène Siby. Geometry of Certain Lie-Frobenius Groups. 2005.

�hal-00005449�

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ccsd-00005449, version 1 - 18 Jun 2005

Jean Mihel Dardié, Alberto Medina and Hassène Siby

Abstrat. Let be Gn,p(K) = Mn,p(K) ⋊GL(Kn), K = R or C, the semi-diret produt of the additive group of matries Mn,p(K) by the

group GL(Kn) where the ation is done by multipliation of matries.

If n = kp,p ≥ 1 the Lie group Gn,p(K) admits an exat left invariant

sympletiform[10℄.Westudythegeometryofthissympletimanifold.

If n > p ( resp. n = p ) we prove that Gn−p,p(K) (resp Gn−1,1(K)

) is the sympleti redution of the sympleti orthogonal (Mn,p(K))

of Mn,p(K) in Gn,p(K) and reiproally that Gn,p(K) is a sympleti

double extension,inthesenseof[6℄, ofGn−p,p(K) (resp. ofGn−1,1(K)).

Moreover we show that Gn,p(K) admits two left transverse Lagrangian

foliations (with ane and losed leaves) . Consequently there exists (a

leftinvariant)aanonialtorsionfreesympletionnetiononGn,p(K).

Key words :

Exat sympletiLiegroup,AneLiegroup, SympletiRedution,Sym-

pleti double extension.

Introdution

The groupGn,1(K) =Af f(Kn) where K =R or Cadmits left invariant sympleti strutureswhihareall exat beause H2(af f(Kn),K) = 0([9℄).

To give an invariant sympleti form on Gn,1(K) is to give a linear form α

on the Lie algebra af f(Kn) suh thatthe 2-obound δα is non degenerate.

That isto sayα isa pointwith anopenorbit undertheoadjoint ationof Gn,1(K).These pointshave been haraterized in[9℄ within the framework of study of ane group representations and in [3℄ where is arried on the

study of left invariant sympleti struturesof ane groupinitiated in[4℄.

In [10℄, it showed that oadjoint ation of Lie group semi-diret produt

of Mn,p(K) and GL(Kn) by matriial produt, where Mn,p(K) indiate the

additive groupof(n×p)-matries, admitsopen orbitsifonlyifn=kp.We

extend to these groups denoted Gn,p(K) the result obtained in [3℄ for the

lassial anegroup:existeneofaunique sympletistruture upisomor-

phism (Theorem2.7),existeneoftransversesympletifoliations(Theorem

2.6),aswellasofaLagrangian bi-foliationwithlosedleaves(Theorem3.2).

Suh a pair of Lagrangian foliations is important in the quantization pro-

edure (polarization) and implies the existene of a anonial(torsion free)

sympleti onnetionon Gn,p(K).The natural leftation of Gn,p(K) onit-

self beinghamiltonianwe anprovide(Theorem 2.1)asimilarofstruture's

theorem ofsimplyonneted sympletiLie group from[5℄.

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Inthe third partwestudy upthebrationsofthis theoremforexpliitsug-

gestaonstrutionof Gn,p(K), dα+1

whenthegeneralizeddoubleextension

of [5℄ don'tapply inthis ase.

ToompletethisintrodutionreallthatasympletiLiegroup(G, ω+)has

an ane struture given bythe left invariant onnetion ( torsion free and

zero urvature )dened forall x, y, z∈Tε(G) by : ω+(∇+x+y+, z+) =−ω+(y+,[x+, z+])

where x+ denotes the leftinvariant vetoreldassoiated to x.

Then one says thatthe pair (G,∇+) isan ane Liegroup. Inthis ase the

produtonG,xy = (∇+x+y+)iswithassoiatorleftinvariantandveriesthe

ondition xy−yx= [x, y].Thisstruture playsa entral ruleinthis study.

1. Left invariant sympleti strutures on the Lie groups Gn,p

In what follows Gn(K) denotes thelassial anegroup where K=Ror

C and Gn(K) is its Lie algebra. By analogy, we denote Gn,p(K) the group

semi-diret produtMn,p(K)⋊Gl(Kn) withn=kp, p≥1 andGn,p(Kn),its

Liealgebra. ObviouslyGn,1(K)isisomorphito Af f(Kn).Considering that

H2(af f(Kn),K) = 0 (see [3℄) any left invariant alternate 2-form is invari-

antly exat. Thisresultbeomesgeneral to Gn,p(K) inthefollowing way:

1.1 Lemma.Every left invariant sympletiformon Gn,p(K) isexat.

Proof.Ifk=p= 1;G1,1 isisomorphi toaf f(K)and theresultfollows.

Assume that k (or p) is greater than 1.Let be ω ∈ Z2(Gn,p;K), Gn,p = Mp,n(K)⋊gl(n).Thismeans that wehave

I

ω([a, b], c) = 0 (*) for every a,b,c in Gn,p.

If we take a= (x, u),b= (y, v) andc= (0, Id)

(*) implies ω(x, y) = 0 for every x, y ∈ Mn,p, and onsequently ω(x, b) + ω(a, y) =ω(I, uy−vx+ [u, v]).

But this isequivalent to

ω(a, b) =ω(I, ux−vy)

=−δβ(a, b) with β =ω(I,·)

N.B In fatfor all Lie algebra G having an element a∈ G suh that ada

is projetor,wehave H2(G,K) = 0.

Remark 1.The mapping

Mp,n(K)×gl(n)−→(Mn,p(K)×gl(n)) (H, M)7−→α(H,M)

given by

α(H,M)(N, V) =tr(N.H) +tr(M.V)

is alinear isomorphism.

Inthefollowing,thedualspaeGn,p ofGn,pisidentiedwithMp,n(K)×gl(n).

Togiveaninvariantlosed 2-formonGn,p(K)itisequivalenttogivealinear

form α on Gn,p(K) . The 2-form+, where α+ denotes the left invariant 1-form dened by α is sympleti ifand only if α has an open orbit under

the oadjoint representation.

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Using the Remark1 and thenatural embedding of Gn,p inGL(Kn+p) we

an show

1.2 Lemma.Theoadjointrepresentations ofGn,pandGn,paregivenby

the following formulas:

(i) ad(0,u)(H, N) = (−H,[u, N])

(ii) ad(x,0)(H, N) = (0, x.H)

(iii) Ad(0,U)(H, N) = (H.U−1, U N U−1)

(iv) Ad(X,Id

Kn)(H, N) = (H, N +X.H)

This implies

Ad(X,U)(H, N) = (H.U−1, U N U−1+XHU−1)

Consequently the oadjoint orbit AdG

n,p(α) of α = (H0, N0) with H0 = (0, Ip)∈Mp,n and

N0 =

0 0 0

Ip 0 0 0 Ip 0

isopen.DenotebyH0the(p, n)-matrixwhosep×pbloksareallnullexept

forthelast,whihistheidentityofKp anddenotedbyN0 the(n×n)-matrix

whose p×pbloksareallnullexeptthesub-diagonalswhihareIdKp.The

previous formulas allow us toverifythattheorbit of (H0, N0) is open sine

the isotropysubalgebrais trivial.

2. SympletiRedution - Left invariant Sympleti foliation on

Gn,p(K).

Denote byω+=dα+,α= (H, N)∈ Gn,p aleftinvariant sympletiformon Gn,p.

The ation ofGn,p(K)on Gn,p(K) given by

LG:Gn,p(K)×Gn,p(K)−→Gn,p(K), (τ, σ) 7−→τ σ( produtinGn,p)

is a sympleti ation. Morever LG is a Hamiltonian ation; a momentum mapping for the ation isgiven by

µ:Gn,p(K)−→ Gn,p(K) σ7−→µ(σ) :x7−→ hα+(σ), x(σ)i

where x∈ Gn,pand x is theright invariant vetoreldassoiated to x.

ThesubgroupH:=Mn,pis(totally)isotropiforω+beauseHisanabelian

Lie group. Morever LH : H ×Gn,p −→ Gn,p is a hamiltonian ation and a momentum mapping for LH isgiven by:

m:Gn,p−→L(H) σ7−→µ(σ)|L(H)

where LH istheLiealgebra of H.We arrive at thefollowing theorem:

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2.1 Theorem .Let (Gn,p, d((H, N)+) dened asabove.Then

1.m−1(H) isa losed subgroupof Gn,p andH ⊂m−1(H)

2.The anonialexat sequene ofLie groups

(2) {ǫ} → H →m−1(H)→m−1(H)/H → {ǫ}

is split. Itis alsoan exat sequeneof aneLiegroups.

3.The reduedsympleti Liegroup m−1(H)/H isisomorphito : Gn−p,p(K) si n > p

Gp−1,1(K) si n=p >1

4.In the prinipal bundle

(3) m−1(H)−→i Gn,p(K)−→m Θ

where Θ is the set of matries of rank p in Mn,p ≡ Mp,n, the ber is an

ane Lie subgroup and m is ane relative to the usual ane struture of Θ⊂Knp.

We needthe following lemma forwhih theproof isobvious.

2.2 Lemma .The mapping mis a surjetivesubmersion.

Furthermore,

(4) m((X, T)) =H.T−1 where (X, T) is in Gn,p(K)

Proof. The formula (4) is a diretonsequene of the denition of m and

theLemma 1.2.Thus itislear thatmisasurjetive submersionon theset Θ ofmatriesof rankp of Mn,p(K).

Proof of the theorem 2.1.

Formula (4) implies that m−1(H) = {(X, T) ∈ Gn,p(K)/HT−1 = H} is a

(losed) subgroup of Gn,p(K) whih ontains H. Morever the fator group m−1(H)/H an be identied with {(0, T) ∈Gn,p/HT−1 =H}.Thus (2) is

an splitsequeneof Liegroups. Ontheotherhand,sine His ommutative

and ω+isexat,itfollowsthatL(H)⊂L(H) andastraightforward shows that L(m−1(H)) =L(H).

Moreverfrom theformula

ω(xy, z) =−ω(y,[x, z])

deningtheleftsymmetriprodutinGn,p(K)(seeformula(1))itturnsout

that L(H) is a left symmetri subalgebra of Gn,p(K) and that L(H) is a

two-side idealof L(H).Consequently (2) isanexat sequeneofane Lie groupsi.eH,m−1(H),m−1(H)/HareaneLiegroupsandtheappliations of formula (2)areane.

On the other hand a list of the elements of the matrix group {(0, T) ∈ Gn,p(K)/HT−1 = H} allows to observe that the group m−1(H)/H is iso-

morphi to the group Gn−p,p(K) if n > p and isomorphi to Gn−1,1(K) if n=p.Thisproves statement 3.

Now,weneed toshowthatthemanifoldΘisendowed withan anestru-

ture whihmakesthe momentum mapping ane.

Let F be the subbundle of T Gn,p(K) tangent to the LH-orbit and F its

sympletiorthogonal.DenotebyF andFtheassoiatedfoliationsrespe-

tively.SineHisnormalinGn,p(K),thefoliationFisdenedeitherbythe

left invariant form on Gn,p(K) given by ηj := i(e+j+ where (ei)'s form a

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basisofL(H)andidenotetheinteriorprodut,orbythelosed forms(thus

exat)ηj :=i(ej+.Obviouslytheηj arebasi forthebration.theforms

¯

ηj whiharetheprojetionsofηj bym denealoalparallelismon Θ.This

parallelism isglobal and ommutative beausetheη¯j areexat.Hene m is

ane.

Letα1andα2bethelinearformsonGn,p(K)denedrespetivelybyα1(x, u) = tr(H.x)and α2(x, u) =tr(N.u).Weget :

2.3. Theorem. ker(dα1) and ker(dα2) are supplementary sympleti Lie subalgebras of(Gn,p(K), dα).Sotheydetermine twotranversesympletifo-

liations leftinvariant on Gn,p(K)

Proof. Obviously ker(dαi) is a Lie subalgebra of Gn,p(K). In addition the

subspaes ker(dαi),i= 1,2 areindiretsum beause ker(dα1)T

ker(dα2)=

{0}.

If we take α = (H0, N0) we diretly observe that we have dim(ker(δα1))=

p2(k−1)k anddim(ker(δα2))= 2p2k.Weextendstheseresultsaboutthedi-

mensionforallα∈ Gn,p (K)withopenoadjointorbit.onsequentlyker(δα1)

and ker(δα2)aresympletiLie subalgebras of(Gn,p(K), dα).

Let C(N0) be the subalgebra ofgl(Kn) givenby:

 A0 A1 ...

.

.

. .

.

. .

.

.

Ak−1 · · · A1 A0

2.4. Sholie. The Lie algebra ker(dα1) is isomorphi to the Lie algebra Gn−p,p(K) if n > p and Gp−1,1(K) if n= p while ker(dα2) is isomorphi to

the semi-diret Mn,p(K)⋊C(N0) if n > p and to the semi-diret produt Mp,p(K)⋊C(N0) ifn=p.

The following result is the innitesimal version of Theorem 2.1. It gives a

more preise andomplete statement of Theorem 2.1.

2.5 Proposition. With the notations of Therem 2.1., if I = L(H), the

anonial sequeneof vetoriel spaes

0→I →I→I/I →0

is a split exat sequene of Lie algebras. It is also an exat sequeneof left

symmetri algebras.

Furthermore the Lie algebra Gn,p(K) deomposes as a diret sum of Lie

subalgebras I andC(N0) .

2.6 Theorem. The sympleti Lie group (Gn,p, dα+) is endowed with

two transversal left invariant sympleti foliations whose leaves are ane

submanifolds ofGn,p(K).

The following assertion speies the numberof open orbitsin Gn,p (K) as

wellasthe left invariant sympletistrutureson Gn,p(K).

2.7 Theorem.

a. There existtwo open orbitsof the oadjoint representation of Gn,p(K) if K=Rand only one ifK=C

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b. Up isomorphism there is only one left invariant sympleti struture on

Gn,p i.eifω andω aretwo leftinvariant sympletiformsonGn,p(K),then

there existsan automorphismϕof Liealgebra Gn,p(K) suh that: ωε(., .) =ωε(ϕ., ϕ.).

Thefollowing lemmassetupthemainstepsofthedemonstrationofThe-

orem 2.7. Thislemmaallow toount the AdG

n,p

-orbits

2.8 Lemma. If Orb(H,M) is the oadjoint orbit of (H, M) ∈ Gn,p ≡ Mp,n(K)×gl(n) then Orb(H,M) has an element (H0, M0) ∈ Gn,p suh that H0 = (0,· · ·, Ap)∈Mp,n.

Morever, if Orb(H,M) is open, then H0 an be taken asH0 = (0,· · · , Ip) = H0.

Proof. It sues to remark that there exists U ∈ GLo(Kn) suh that HU−1 = H0 , that is obvious if we look at H asthe matrix of a mapping

from Kn into Kp and U−1 asthe matrix of a hange of basisin Kn. Then the lastformulaoflemma 1.2showthe rstassertion.

Nowsupposethat Orb(H,M)=Orb(H

0,M0) isaopenorbit. Thisimpliesthat

wehave

(x, u)∈ Gn,p;ad(x,u)(α) = 0⇒(x, u) = 0

In partiular

ad(x,0)(H0, M) = 0⇒x= 0

In otherwords

(∗∗) tr(xH0u) = 0, u∈gl(n)⇒x= 0

with H0 = (0, Ap)

But astraight alulationshows that(**)impliesAp is invertible.

Finally there existsU ∈GLo(Kn) suhthat H0U−1 =H0,but this relation

xonlythelast diagonalblokofU to thevalueA−1.Thereforeifk≥2we

able to take an other diagonal blok egals to detA−1.IdKp and ompleting

the diagonalebythe 1,toonstrut asuhmatrix U in SL(Kn).

2.9Lemma.AnopenorbitOrb(H0,M)ontainsonlyoneelement(H0, M),

where the blokdeomposition ofM an be written : M =

M1 0 H1 0

with (H1, M1)∈ Gn−p,p .

Proof.Beause

Ad(X,Id)(H0, M) = (H0, M +X.H)

it islear thatthere isonly one X∈Mp,n suh thatM =M +M H0.

2.10 Lemma.Thelinearforms(H0, M)and(Ho, P)onGn,pwithM = (H1, M1) and P = (K1, P1), dened as in Lemma 2.9, belong to the same AdG

n,p

-orbitifandonly if(H1, M1) and (K1, P1) areinthesameAdG

n−p,p

-

orbit.

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Proof. (H0, M ) and (Ho, P ) are in thesame orbit ifand only if ∃U ∈ GLo(Kn) suhthat U MU−1 =P andH0U−1 =Ho.

The seond onditionimplies

U =

U 0 X1 Id

, with U1 ∈GL0(Kn−p)

OnotherhandU MU−1=Pingl(Kn)isequivalenttoAd(X1,U1)(H1, M1) = (K1, P1) inGn−p,p(K)

Proof of the theorem 2.7.

Following the previous Lemmas we have

ardinal

nopen AdG

n,p−orbito

= ardinal

nopen AdG

p,p−orbito

On the other hand,using similar arguments asthose ofthe lemmas we an

showthat

ardinal

nopen AdG

p,p−orbito

=ardinal

nopen AdG1,1−orbito

=

2 if K=R 1 if K=C

If K=C thereisonly one sympletistruture onGn,p.

In the aseK=R,itfollowsfrom the lemmasthateveryAdG

n,p

-openorbit

ontains an element (H0, N0)where

N0 =

 0 Ap ...

Ip

.

.

.

.

.

. .

.

.

Ip 0

withAp invertible

Neverthelesstwo matriesasN0 areonjugate byan element P of GL(n).

Howeverthe mapping

Gn,p −→ Gn,p , (g, M)7−→(Pt−1g, P−1M P)

is dualof themapping

θ:Gn,p−→ Gn,p (x, N)7−→(P−1x, P−1N P)

and these later isan automorphismof theLiealgebra Gn,p.

Consequently ifω+1 ,ω2+ aretwo leftinvariant sympletiforms onGn,p,we

have :

ω+12+).

Remark2.NotiethattheonlyoneleftinvariantanestrutureonGn,p

is givenby(H0, N0).

The following resultisan important onsequene oftheprevious study.

2.11Proposition.TheidentityomponentofGn,pisdieomorphitoan

open AdG

n,p

-orbit. Consequently Gn,p and

α ∈ Gn,pisPoisson-regular are dieomorphi.

Proof.(Byindution)Wemustprovethattheorbitalmappingin(H0, N0) (Gn,p)o−→ Gn,p , (X, U)7−→(H0U−1, U N0U−1+XH0U−1)

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