C OMPOSITIO M ATHEMATICA
B. H. N EUMANN Ascending derived series
Compositio Mathematica, tome 13 (1956-1958), p. 47-64
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To my parents, for their 80th birthdays by
B. H. Neumann
Manchester
§
1. Introduction.The term "derived
group"
and the notation H’ for the com-mutator
subgroup
of a group Hsuggests
ananalogy -
albeittenuous - to the derivative of a
function;
and this in turnsuggests
theproblem
of"integration" :
Given a groupG,
to finda group H whose derived group is
isomorphic
to G. There may not be such a group H at all: thesymmetric
group ofdegree
3, oforder 6, is not the derived group of any group
1),
and it is not difficult to make other similarexamples.
Thus one showseasily
that no
symmetric
group of finitedegree
> 2 and noproperly metacyclic
group2 )
can be the derived group of any group. Butbeyond this,
little seems to be known.The iterated commutator groups form the derived series
and this leads
naturally
to the moregeneral question: given
agroup G and a
positive integer n,
to find agroup H
such that G isisomorphic
to the nth derived groupH(n);
or to show that nosuch group exists. Next one may ask whether solutions exist for all n; it is with this
problem
that thepresent
paper islargely
concerned.
We are thus led to consider series of groups
such that
G
=G’+l
for i = 0, 1, 2, ..., and where we shallalways
assume that the first
(and
thereforeevery)
inclusion is proper.We call such a series an
ascending derived series,
and for clearerdistinction we call a series
(1.1)
adescending
derived series.A
descending
derived series may becomestationary
after a finite1) van Aardenne-Ehrenfest [1]; Lips [6].
2) Cf. e.g. Zassenhaus [11], p. 138, Satz 9.
number of
steps,
when we arrive at a group H(n) that is its own derived group. Thishappens
if H(n) is the trivial group, when H is called soluble of(derived) length
n.If,
on the otherhand,
H(n) =
H(n+1) ~ {1},
or if thedescending
derived series has infinitelength,
then H is insoluble.An
ascending
derived series can not becomestationary.
It canbreak off if we arrive at a group
Gn
that is not the derived group of any group; we then call n thelength
of the series. Anascending
derived series can,
however,
also go onindefinitely,
that is have infinitelength.
IfGo
is not its own derived group, then the series(1.2)
can be continued to theleft, possibly
for an infinite number of terms.By taking
infinite unions or intersections one caneasily
introduce derived series of various transfinite order
types;
butfor the
present
we shall be content with finite series and infinite series oftype
03C9.A finite derived series can be considered either as
descending
or as
ascending, according
as one thinks of one end or the other asgiven.
We shall here look upon the series asascending,
that is weshall derive
properties
of the series(1.2)
fromproperties
of thegroups with which it
begins.
Ourprincipal
result is that the seriesbreaks off if
G21GO
isfinitely generated. By
contrast it is notsufficient to assume
G,IGO
orG21G,
finite to ensure that the series breaks off. It follows that in aninfinite ascending
derived series nometabelian
factor Gi+21G,
i can befinitely generated,
whereas anabelian
factor Gi+l/Gi
can even befinite.
We mention two finiteness conditions that occur in the for- mulation of some of the results and that would
perhaps
meritcloser examination than
they
receive in thepresent
paper: the matcimal conditionf or
solublesubgroups,
and theascending
derivedchain condition
for subgroups. They
are introducedin §
4.An
auxiliary
result mayperhaps
claim someindependent
in-terest : It is that a
finitely generated strictly
metabelian group(that
is one that is notabelian)
has a finitestrictly
metabelianhomomorphic image.
The same is notgenerally
true of metabelian groups with aninfinity of generators;
nor is theanalogous proposi-
tion valid for
finitely generated
soluble groups oflength
3.§
2. Preliminaries.The
following
two lemmas are stated for later reference. The reader willeasily supply proofs.
LEMMA 2.1.
Il
0 is ahomeomorphism of
the groupG,
thenEquivalently, if
N is a normalsubgroup o f G,
thenLEMMA 2.2.
Il
M is asubgroup o f
G and.N a normalsubgroup of
G such that MN =G,
thenwhere
[M, NI is
the groupgenerated by
all commutators[a, b]
witha~M, b~N.
We denote
by
G* the union of the groups in anascending
derived series:
If the series has finite
length
n, then G* =Gn;
if the series isinfinite,
then G* is its direct(or "inductive" )
limit. In this caseG* is
evidently
its own derived group.If 0 is a
homomorphism
ofG*, then, by
Lemma 2.1,Thus if
Gi03B8 ~ Gi+103B8
forsome i,
thenis
again
anascending
derived series. Inparticular if
N is a normalsubgroup
of G* contained inGi,
then the groups4form an
ascending
derived serieswith the union and the factors
In order to ensure that N is a normal
subgroup
of G* it suffices to take N as a characteristicsubgroup
ofG,;
for asG,
is charac- teristic inGi+1,
then N is also characteristic inGi+1,
and in-ductively
in allGi+j.
Then N is afortiori
normal in allGi+j,
andthus normal
3)
in G*. We shall often find it useful to take N =Go;
the
resulting
series starts with the trivial group and consists of soluble groups.3) It is not permissible to conclude that N is characteristic in G*; cf. infra.
To make an
example 4 )
we takeGo
as a free group ofcountably
infinite rank. This is
isomorphic
to, but distinctfrom,
its derivedgroup; we may therefore consider it as the derived group of another free group
Gl
ofcountably
infiniterank;
and so we con-tinue,
to obtain an infiniteascending
derived series. The inductive limit G* is alocally
free group which coincides with its own derived group. The factor groupsGi+1/Gi
are free abelian groups ofcountably
infinité rank. If we reduce modulo6) Go,
that isif we consider the groups
Hi
=GIG,,
then we obtain anascending
derived series
consisting
of soluble groups. The limit group H* islocally
solublebut coincides with its own derived group.
§
8.Automorphisms
induced in a seriesWe take i fixed for the
present
and consider the effect onG,
of the inner
automorphisms
of G*. As a normalsubgroup G,
admits the inner
automorphisms
ofG*,
andthey
therefore inducea certain group
0393*i
ofautomorphisms
ofG,.
We obtainF*i
fromG*
by
ahomomorphism 03B8i
with the centralizerCi
ofG,
in G*as kernel. Transformation
by
the elements ofGk
induces a sub-group of
rt
onG,, namely
It follows that
becomes an
ascending
derived series after the omission ofpossibly equal
terms at thebeginning - provided,
of course, that not allthe terms of
(3.2)
areequal.
We note in
passing
that if ij,
thenC*i C*j,
and thus0;
k03B8j.
This means that0393ki
is ahomomorphic image
of0393kj.
Wealso remark
that 0393ki
consists of innerautomorphisms
ofG,
whenk ~
i. An incidental consequence of thefollowing
lemma is thatwhen k > 1 h 2,
rik
can never consist of innerautomorphisms only.
The lemma describes whathappens
when not all the in- clusions in(3.2)
are proper.4) The construction is well known.
6) There is an obvious automorphism of G* mapping each G, onto Gi+1. Hence Go, though of course normal, is not characteristic in G*; cf. footnote 3).
LEMMA 3.3. Let
0393k+1i = r: f or
some valuesi,
k. Then either i = 0, or k = 0, or i = 1 andGO,
=Go
andG,IGO
is contained inthe centre
o f Gk+1/G0.
PROOF. We suppose both i > 0 and k > 0, as otherwise there is
nothing
to prove. As in(3.2)
every term is the derived group of its successor, it follows thatUsing (3.1),
we obtainand modulo
Go
Here the left-hand side is contained in the centralizer of
G ¡/Go
in
G*/Go.
We see thatGk+1/G0
is contained in the centralizer ofG,IG,
inG*/Go.
If i 2k+1,
this wouldimply
thatGk+1/G0
isabelian,
hence thatGk/Go
is trivial: but this isincompatible
withour
supposition
that k > 0. Thus ik+1,
andGi/G0
is contained in the centre ofGk+1/G0·
This in turnimplies
thatG,IG,,
isabelian,
and thus i = 1.
Finally, intersecting
both sides of(3.4)
withG1,
we obtainwhere Z =
Ci
~G,
is the centre ofGl.
We form the derived group,using
Lemma 2.2:This
completes
theproof
of the lemma.§
4. Some corollariesThe lemma
gives
rise to sufficient conditions for anascending
derived series to break off. To formulate one of them we remind ourselves of the definition of the
automorphisms
class group of a group G: this is the factor group of the group of inner automor-phisms
of G in the group of allautomorphisms
of G. We denote itby 039B(G).
COROLLARY 4.1.
If 1 h
2 andif
theautomorphism
class groupA(G¡) satis f ies the
maximal conditionf or
-solublesubgroups,
thenthe
ascending
derived seriesbreaks
o f f .
The groups
form an
ascending
sequence of solublesubgroups
of039B(Gi);
notwo successive terms can become
equal, by
Lemma 3.2, as wehave assumed i ~ 2. The maximal condition for soluble sub- groups of
A(G;)
thenimplies
that the series breaks off.The maximal condition for soluble
subgroups
of a group hasapparently
notyet
received much attention. For soluble groups it coincides with the maximal condition forsubgroups,
and thussingles
out thepolycyclic groups6).
But for groups ingeneral
itis much less
restrictive;
it is e.g. satisfied in all free groups andlocally
free groups, and in a freeproduct provided
it is satisfied in the free factors.COROLLARY 4.3.
I f G21GO is finite,
then theascending
derived series breaksoff.
This is an immediate consequence of the
preceding corollary, coupled
with the remark(cf. § 2)
thatGo
can be factored out.We shall say that a group G satisfies the
ascending
derived chain conditionf or subgroups
if everyascending
derived series breaks off. This condition neitherincludes,
nor is includedby,
the maximal condition for soluble
subgroups:
Theexample
of thelocally
free group G*of §
2 shows that a group cansatisfy
thelatter without
satisfying
theformer;
a free abelian group of infiniterank,
on the otherhand,
satisfies the former and not the latter.COROLLARY 4.4.
If i ~
2 andi f
theautomorphism
class group039B(Gi) satisfies the ascending
derived chain conditionfor subgroups,
then the
given ascending
derived series breaksoff.
For the sequence
(4.2),
like(3.2),
is anascending
derivedseries,
and
by
theassumption
on039B(Gi)
it breaks off.§
5.Finitely generated
metabelian groups.We
interrupt
the discussion ofascending
derived series tosupply ourselves,
forsubsequent
use, with some facts onfinitely generated
metabelian groups. Some known facts have been re-derived here.
The
techniques employed
are, of course,well-known;
cf. e.g.Jacobson
[4], chapter
VI.6) Thèse groups were first studied by K. A. Hirsch in a series of papers [3].
The name "polycyclic" is due to P. Hall [2].
If G is a
metabelian 7)
group, we may consider G’ as an Q-module,
where 03A9 is thering generated by
theoperators
inducedby G/G’
in G’. To facilitate the distinction between G’ qua derived group of G(written multiplicatively)
and the 03A9-module(in
whichthe same
operation
appears asaddition),
we write YR for thelatter. Thus to every element g E G we have an
operator
oc E 03A9such that if x, y E G’ and
g-lxg
= y, and if u, v are the elements of 9Rcorresponding
to x, yrespectively,
under anisomorphism
2013 fixed once and for all - between G’ and
3R,
thefi uoe = v;moreover, if g and h induce the same
automorphism
ofG’,
thesame oc E 03A9
corresponds
to both. Thus one and the sameoperator corresponds
to the elements of a coset of G’. Theoperator ring Q
may be
thought
of as obtained from the groupring
over theintegers
ofG/G’ by reducing
it8)
modulo the annihilator ideal of 9x.To every submodule of M there
corresponds
asubgroup
of G’which admits
G,
in other words a normalsubgroup
of G contained inG’;
thiscorrespondence
is one-to-one; if asubgroup
of G’ isnormal in
G,
then theisomorphism
maps it onto asubgroup
ofM that admits
03A9,
that is a submodule of 3R.If G is
finitely generated,
let us sayby
g1, g2 ,..., gd, then G’ isgenerated by
thefinitely
many commutators[gi, gj]
andtheir
conjugates;
thus 9 is thenfinitely generated
qua .S2-module.It follows
9)
that 9 contains maximal propersubmodules;
in factevery proper submodule is contained in a maximal one.
A maximal proper submodule of 9R
corresponds
to a maximalproper
subgroup
N of G’ normal in G. The factor group whose derived group ishas the
property
that every normalsubgroup
either contains H’or meets H’ in the trivial
subgroup only.
Denoteby
Z a maximalnormal
subgroup
of Hmeeting
H’trivially:
7) For the sake of brevity we use "metabelian" in the strict sense, that is excluding
"abelian"; thus we here call G metabelian only if G’ is a non-trivial abelian group.
8) This reduction is not essential, and we could use the whole group ring, at any rate for the present.
9) by a familiar argument which we do not present; cf. [7]. We could instead
use the maximal condition for submodules of 9 which follows from Jacobson [4], p. 171; or the maximal condition for normal subgroups of G proved by Hall [2].
The existence of such a
subgroup again
followsby
familiar ar-guments 1°).
A normalsubgroup
that has trivial intersection with the derived group must lie in the centre; thus Z lies in the centre of H. The factorgroup K
=HIZ
has theproperty
that everynon-trivial normal
subgroup
contains the derived groupK’;
differently put, K
is a metabelian group but all its proper homo-morphic images
are abelian. Such a group may be calledonly just strictly metabelian;
it will here becalled,
somewhat am-biguously
but morebriefly, just
metabelian. We have thusproved
the
following
result.LEMMA 5.1.
Every finitely generated
metabelian group has ajust
metabelian
factor
group.It may be remarked that this is not true of metabelian groups in
general.
If an abelian group oftype poo
is extendedby
anabelian
automorphism
group, sayby
theautomorphism
of order2 which maps each element on its
inverse,
then theresulting
group is metabelian but has nojust
metabelianhomomorphic image:
every metabelian factor group is
isomorphic
to it and hasanother,
still
metabelian,
proper factor group. Thisexample
shows in-cidentally
that it does not suffice to assumeG/G’ finitely generated,
or even finite.
§
6. Just metabelian groups.We now consider a
just
metabelian group, which weagain
denote
by G;
thering 03A9
and the S2-module mare defined as before.Then flk has no proper non-zero
submodule,
in othér words 9Ris a
simple
03A9-module.LEMMA
6.1.11 ) Il
mis asimple
il-module whereilis a commutativering
and the annihilatoro f
9N is(0),
then il is afield
or consistsof
0only.
PROOF. We may suppose that .S2 contains a non-zero
element;
any such element does not annihilate
3K,
and thus also 3K containsnon-zero elements. The elements of 3R annihilated
by
03A9 form asubmodule,
and this then consists of 0only.
Now if U EIDl, u =1=-
0, then u03A9 is a non-zerosubmodule,
and thusIf 03C9 ~ 03A9 and uw = 0, then
1°) Cf. the preceding footnote.
’l) This is an almost immediate consequence of Schur’s Lemma; cf. e.g. Jacobson
[5],p.271.
whence (J) = 0. Next let
oc, p E
Q and oc --74- 0. Then uoc =1= 0 and thusThere exists then an element e a 03A9 such that in turn
This shows that division
by
non-zero elements can be carried out inQ,
and the lemma follows.LEMMA 6.2.
Il
af initely generated ring
is afield,
then it isf inite.
PROOF. Let 03A9 be a
ring generated by
al, a2, ..., 03B1d, and assume03A9 is a field. Then every element of 03A9 is a
polynomial
in al, a2, ..., ad with coefficients in theprime
field if 03A9 hasprime characteristic,
and with rational
integer
coefficients if S2 has zero characteristic.We first show that 03A9 is
algebraic
over itsprime
fieldP;
suppose not, and let 03C41, -C2, ..., Te be a basis of transcendental elements of S2. Then there arepolynomials 03C01(03C41, ...,03C4e),
...,03C0d(03C41,
...Te)
such that
are
integral
overP (Tl’ ...,03C4e).
Then to everypolynomial
oc inal, ..., ad there is an
integer
m(e.g.
itsdegree)
such thata.
(03C0103C02
...03C0d)m
isintegral
overP(03C41,
...,03C4e).
But if 11:0 is anirreducible
polynomial
in 03C41, ..., ie which does not divide anyof 03C01,
..., :1I;/l,then 1 03C00(03C0103C02...03C0d)m
is notintegral
overP(03C41,
...,Te)
for any m, and thus-
is notgenerated by
CXl’ ..., oc,. This contradicts the field
property
of03A9,
and we conclude that al, ..., ocd areabsolutely algebraic,
and that Q isa finite
algebraic
extension of itsprime
field P. Itonly
remainsto prove that P is
finite,
that is that Sz can not have characteristic 0.Assume the
contrary.
Let sl, ..., sd bepositive
rationalintegers
such that 8l CXl’ s203B12,..., sd03B1d are
algebraic integers.
Then everypolynomial
in 03B11, ...,03B1d withintegral coefficients,
that is every element ofS2
is of the form03B2 (s1s2...sd)m, where is an al-
gebraic integer
and m a suitable rationalinteger (e.g.
thedegree
of the
polynomial).
Butif p
is aprime
that divides none ofs1, s2, ..., 1 Sd then
1 /p
is not of thisform,
hence not in 03A9. Thisagain
contradicts theassumption
that 03A9 is afield,
and the lemma follows.More
briefly
one can argue as follows: If Tl is a non-trivial non-Archimedean valuation on
03A9,
then not all of 03B11, ..., ad can beintegers
withrespect
to V. Unless Sz is modular andabsolutely algebraic,
it has aninfinity
of non-trivial non-Archimedeanvaluations,
and no element can be anon-integer
for more than afinite number of them. If follows that 03A9 is modular and
algebraic,
and
being finitely generated,
it must be finite.THEOREM 6.3. A
finitely generated just
metabelian group isfinite.
PROOF.
By
Lemma 6.1 theoperator ring
03A9 is either trivial or afield. Assume first that 03A9 =
(0).
ThenSK, being
asimple
S2-module,
iscyclic
ofprime
order. Hence in this case G’ is acyclic
group of
prime
order p, say. Let Z be the centre of G. Then Z has no non-trivialsubgroup
with trivial intersection with G’. It follows that Z iscyclic
of order a power of p. Now in afinitely generated
group with finite derived group the centre has finite index12 ),
and it follows that G is finite. Next assume that S2 is afield;
then 12 isfinitely generated
quaring,
as it is ahomomorphic image
of the -evidently finitely generated
- groupring
ofG/G’.
Henceby
Lemma 6.2 03A9 isfinite,
andID1, being
of the form uS2 for some u ~ 0, has the same finite order as 03A9. In this casethe centre Z is in fact
trivial;
for if it were not, then there would be an element y E G’ ~Z, y ~
1, and thus an element v =1=- 0 of3K annihilated
by
the whole of Q. This isimpossible (cf.
theproof
of Lemma
6.1.) Using again
the fact that in afinitely generated
group with finite derived group the centre has finite
index,
we seethat also in this case G is
finite,
and the theorem follows.Before we
apply
thetheorem,
webriefly
indicate that it is in two ways a "bestpossible"
result.It would be unreasonable to
expect
theassumption
that thegroup is
finitely generated
to besuperfluous.
In fact the group of linearinhomogeneous
substitutionswith
fi ranging
over an infinite field S2 and a over its non-zeroelements,
is anexample
of ajust
metabelian group that is infinite and thus can not befinitely generated.
It
is,
on the otherhand,
conceivable that "metabelian" can bereplaced by
"soluble oflength
3". However this is not the case.12) By [9], Corollary 5.41.
Let G be the group with
generators
a,b,
c anddefining
relationswhere p(i)
is the ithprime
when i ispositive,
andp(i)
= 1 wheni is zero or
negative 13).
This group is"just
soluble oflength 3",
that is it is soluble of
length
3 but all its properhomomorphic images
are metabelian or abelian. It isinfinite, though
it isfinitely generated.
We omit theproof,
which is not difficult.Using deeper
results due to Hall[2],
one can also show the existence of infinitetwo-generator
groups that are"just
centre-extended-by-metabelian".
§
7.Application
toascending
derived series.An immediate consequence of Lemma 5.1 and Theorem 6.3 is the
following
fact.COROLLARY 7.1.
Every finitely generated
metabelian group has afinite
metabelianfactor
group.This can be
slightly strengthened by remarking
that in afinitely generated
group G every normalsubgroup
N of finite index contains asubgroup
N* which is characteristic in G and also of finiteindex;
for there areonly finitely
many normalsubgroups
of G whose factor groups are
isomorphic
toG/N:
their intersection will serve as N*. Thus we deduce fromCorollary
7.1:LEMMA
7.2.Every finitely generated
metabelian group contains a characteristicsubgroup
whosefactor
group isf inite
and metabelian.We
apply
this to extendCorollary
4.3.THEOREM 7.3.
Il
is an
ascending
derived series andi f G21GO
isfinitely generated,
thenthe series breaks
off.
PROOF. We may assume the series reduced modulo
Go,
orequivalently Go
={1}.
ThenG2
is afinitely generated
metabeliangroup, hence
by
thepreceding
lemma it contains a characteristicsubgroup
N of finite index whose factor group is still metabelian.Then N is normal in
G*,
andreducing
modulo N we obtain a newseries
13) This group is adapted from an example constructed elsewhere [8].
with
H2
=G21N
finite.By Corollary
4.3 the series breaksoff,
andso then does our
original series,
and the theorem follows.COROLLARY 7.4.
Il
G is afinitely generated
group andG" =1= G’,
then every
ascending
derived seriesthrough
G breaksoff.
This
corollary
deals e.g. with free groups of finite rank andmore
generally
with freeproducts
offinitely
manyfinitely generated
groups.COROLLARY 7.5. In an
infinite ascending
derived series nometabelian
factor G¡+2/G¡
can befinitely generated.
§
8. Crownproducts.
One
might expect
that it is sufficient to assumeG1/GO finitely generated
in order to ensure that theascending
derived seriesbreaks
off;
thisis, however,
not the case, as anexample
will show.The construction uses the iterated "wreath
product"
of twogroups, with a
slight
modification. Given an abstract group G and a transitivepermutation
group r defined on a set03A3,
we firstform the restricted direct
product
K ofisomorphic copies G,,
=G03B803C3
of
G,
indexedby
the elements o ofJC;
then K has an obvious auto-morphism
grouppermuting
the direct factorsaccording
to0393;
specifically
ifand if y E
l’,
then weput
The
splitting
extension of Kby
thisautomorphism
group(iso- morphic
to andagain
denotedby)
r is then known as the wreathproduct
of G and 0393. We denote itby
G Wr h. Now assume weare also
given
asubgroup
Z of the centre of G. Theisomorphism 03B803C3
maps Z onto thesubgroup Za
in the centre ofGa,
and theproduct
of all theZa
is asubgroup
of the centre of K. Denoteby
N the set of those elementsfor which
14)
Then N is
easily
seen to be a normalsubgroup
of the wreath 14) The product has only a finite number of factors ~ 1, because we are usingrestricted direct products.
product.
It isgenerated by
allquotients (z03B803C3)(z03B803C4)-1;
hencemodulo N all the different
copies Za
of Z coalesce to asingle
group, which we
again
denoteby
Z. Let the factor group thus obtained bewe
might
call it a "wreathproduct
withamalgamation",
or a"centrally
extended wreathproduct":
It could have been obtainedby forming
the(restricted)
directproduct
of theG,,
with amal-gamated subgroups 15) Z03C3,
andletting
Foperate
onthat;
alter-natively
it can bethought
of as an extension of the centre Zby
the wreath
product
ofGIZ
and h. Let us call it the crownproduct,
and denote it by
Like
G,
it contains Z in its centre; we can therefore form the crownproduct again,
with anotherpermutation
group L1. The wreathproduct
can be considered as thespecial
case of the crownproduct
in which the central
subgroup
Z is trivial.LEMMA 8.1.
Il
0393 is an abelian groupof
order greater than 2, then the second derived group P"o f
the crownproduct
contains a
subgroup isomorphic
to G’ and is ahomomorphic image of
a direct powerof
G’.PROOF. We first notice that P’ is contained in the direct
product
of the
Ga
withamalgamated Z;
this is the groupK/N
of ourconstruction,
which we shall now denoteby
L.Clearly
L is normal inP,
andand as 0393 is assumed to be
abelian,
P’ Ç L. It follows thatWe also note that L’ is the direct
product
of the derived groupsG’
with their intersections with Zamalgamated,
and thus ahomomorphic image
of a direct power of G’.Our
assumption
on the order of 0393implies
that the cardinal of the set 03A3 which 0393permutes
is at least 3. Let e, (1, T be three distinct elements ofE,
and let03B3, 03B4
E T be so chosen that16) For this notion, cf. [10].
This is
possible
because r actstransitively
on 1. Next let g, h be twoarbitrary
elements ofG,
and denoteagain by
g03C3,h03C3,
...their
copies
inG03C3,
.... Consider the second commutator(Note
that g,, commutes with ga ,ha , h03C4, and h.,
with gp, g03C3,ha . )
This
belongs
toP";
but as g, h werequite arbitrary
elements ofG,
then the whole ofG"
is contained inP",
that is P" containsa
subgroup isomorphic
to G’.Again,
as a wasarbitrary,
and
combining
this with(8.2)
we haveThe lemma then follows.
COROLLARY 8.4.
Il
F is abelian andof
order greater than 2, andif
G is solubleof length
n, then the crownproduct
GCrZ
r is solubleof length
n + 1.§
9. Construction of anexample.
We are now in a
position
to construct theexample
announcedat the
beginning of §
8; the reader caneasily satisfy
himself thatwe have sufficient freedom in each
step
of theprocedure
to makecontinuously
many differentexamples:
but we shall in fact describeonly
one.Let
H2
be thequaternion
group, andthe
cyclic
group of order 2, which is its centre. We takeFi (i
= 2, 3,...)
all as thecyclic permutation
group of order 4, which is transitive on the sert 1 ={0,
1, 2,3}.
Then we forminductively
the successive crownproducts
Thus
Hi+1
is obtainedby forming
the directproduct
of groupsHio, Hi1, H12e H,3
withamalgamated Z,
andextending by
thecyclic
group of order 4 as described in§
8. The four groupsH,,,,, (03C3
= 0, 1, 2,3)
areisomorphic
toHi,
and we canidentify Hi
with one of
them,
sayHio.
Thenbecomes an
ascending
sequence of groups, and weput
The centre Z has been
preserved
in eachstep
and thus Z is also asubgroup
of the centre of G*(it
is in fact the whole centre ofG*).
We
put Go
={1}
andG1
=Z,
and defineG2
as the groupgenerated by
all theisomorphic copies
that arise fromH2 by forming
thesuccessive direct
products
withamalgamated
Z. There are in-finitely
many suchcopies.
Moregenerally
wedefine,
for even i =2j only, G,
to be the groupgenerated by
theinfinitely
manycopies
ofHi
that are created in the process of construction: thusGi ,
for i = 2, 4, 6, ..., isgenerated by
ally*-1 H ¡ y*,
wherey*
ranges over the
permutations generated by 0393i+1, Fi+2,
... in G*.Differently put, G2j
is the normal closure ofH2j
in G*. We also define the odd-numberedG, simply
as the derived groups of their even-numbered successors:It is evident that
G* = ~ Gi.
Now we observe that if i is even, then
for it follows from Lemma 8.1, or rather from its
proof (cf.
especially (8.3)),
thatH,’
is the directproduct
of several(namely 16) copies
ofHi-2,
with Z= Hl amalgamated. Combining (9.4)
with the definition
(9.2),
we see thatthat is
(9.3)
is anascending
derived series. Thus we have shown that thecyclic
groupof
order 2 can be made thefirst
non-trivial groupo f
aninfinite ascending
derived series. It is not difficult to make similarexamples
with other abelian groups. The inductive limit group G* of ourexample is, incidentally, locally
finite-of-order-a-power-of-2,
and thus alsolocally nilpotent;
it is its ownderived group, and hence its upper central series must terminate with the centre
Gl,
as is indeedeasily
verifieddirectly.
§
10. A furtherexample.
It is now natural to ask whether it suffices to suppose
G21G, finite,
or evenfinitely generated only,
to ensure that theascending
derived series breaks off. This
is, however,
not the case, as wenow show
by
furtherelaborating
theexample of §
9. In order tohave the notation
available for the
ascending
derived series that is to beconstructed,
we now denote
by Fo, Fl, F2,
... and F*respectively
the groupsGo, G1, G2,
... and G*of §
9.Let A denote the abelian group of
type 200 ,
and form the wreathproduct
where F* is taken in its
regular permutation representation.
Wedenote
by
P the(restricted)
directproduct
of theisomorphic copies
ofA,
indexedby
the elements ofF*,
that go into the construction of B. The direct factors can be bracketedtogether
in
pairs
where c is the element of order 2 in the centre of
F*,
andfranges
over F*. We now
amalgamate
thepartners
in everypair
asfollows.
Consider the elements
where a ranges over A and
f over
F*.(Every
element(10.1)
arises
twice, namely again
as ale ale" =afcaf).
The group Ngenerated by
all these elements is normal inB;
for allconjugates
of an element
(10.1)
are obtainedby transforming by
elementsf* ~ F*,
andis
again
of the form(10.1). Reducing
modulo N weamalgamate paired
groupsAI, Ale
in such a way that elementscorresponding
to the same a E A become inverse to each other in the
amalgamated
copy.
We thus define the groups
and
generally
Then clearly
and the inductive limit of this sequence is
It remains to show that
(10.2)
is anascending
derived series. It is indeed clear thatGo
=Gi,
forCi
isabelian;
alsoGi
=G’i+1
for i = 2, 3, ..., because the factor groups
Gi/G1
areisomorphic
to
Fi-l’
for i = 1, 2, ..., andbecause,
as we shall showpresently, G, C G’i for i ~
2. Thus we needonly
examine the relation betweenGi
andG2.
Clearly
as
G2/G1 ~ Fl
is abelian. On the other hand every element a. EAI
is a square of another element inAt, by
our choice of Aas a group of
type 2~,
say NowThus the elements of P are
generated
modulo Nby
commutators of c and elements ofP,
that isCombining
this with(10.3),
we see that alsoG,
=G’2,
and thus(10.2)
is indeed anascending
derived series. It is an infiniteseries, though G2/Gl
isfinite, namely cyclic
of order 2. It may be added that G* isagain locally finite-of-order-a-power-of-2,
andin
particular locally nilpotent;
its centre is trivial and its derived group coincides with the whole of it.It is clear that the
example
can be modified in agreat
numberof ways. We
only
mention that one cansimilarly
construct in-finite
ascending
derived series in which some other factorGi+1/Gi
is an
arbitrarily prescribed
finite abelian group, butGi+2/Gi+l
and
Gi/Gi-1
then can not,by
what we haveshown,
befinitely generated.
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P. HALL
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K. A. HIRSCH
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B. H. NEUMANN
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