A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
O SCAR L EMMERS
J AN W IEGERINCK
Reinhardt domains and the Gleason problem
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 30, n
o2 (2001), p. 405-414
<http://www.numdam.org/item?id=ASNSP_2001_4_30_2_405_0>
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405
Reinhardt Domains and the Gleason Problem
OSCAR LEMMERS - JAN WIEGERINCK
Ann. Scuola Norm. Sup. Pisa Cl. Sci. (4)
Vol. XXX (2001),
Abstract. As usual, let be the uniform
algebra
consisting of the functions which are holomorphic on S2, and continuous ona, and
let be the set ofbounded holomorphic functions on SZ. Throughout this paper S2 will be a bounded Reinhardt domain in C~ with
C2-boundary.
We show that the maximal ideal (both in and consisting of
functions vanishing at p E Q, is generated by the functions (z 1 - PI), (Z2 - P2 ) ~
at first for the case that Q is pseudoconvex, then without this condition.
Mathematics Subject Classification (2000): 32A07 (primary), 46J 15 (secondary).
1. - Introduction
Let S2 be a bounded domain in en. Let
(usually
orbe a
ring
ofholomorphic
functions that contains thepolynomials,
and let p =( pl , ... , pn )
apoint
of Q. Recall the Gleasonproblem,
cf.[7]:
is the maximal ideal inconsisting
of functionsvanishing
at p,generated by
the coordinate functions(zi - pi),
...,(zn - pun)?
One says that a domain Q has the Gleason
R property
if this is the casefor all
points
p E Q. We also say that it has theGleason-property
withrespect
to
R(S2).
Gleason mentioned the
difficulty
ofsolving
thisproblem
even for such asimple
domain as the unit ballB(O, 1)
incC2,
p =(0, 0),
=A (Q).
Thatcase was solved
by
Leibenzon([10]),
whoproved
that the Gleasonproblem
canbe solved on any convex domain in cCn
having
aC2-boundary. Using
differenttechniques,
this result wassharpened by Grange ([8],
for andby
Backlund and Fallstrom
([1]
and[2],
for andrespectively),
forconvex domains in cCn
having only
aCl+’-boundary.
Using
his theorem onsolvability
of the9-problem ([13]), 0vrelid proved
in
[14]
that astrictly pseudoconvex
domain in cCn withC2-boundary
has theGleason
A-property.
Thefollowing
results also use thisimportant
theorem.Pervenuto alla Redazione il 12 giugno 2000 e in forma definitiva il 10 novembre 2000.
Weakly pseudoconvex
domains S2 inC2
withC°°-boundary, having
theproperty
thatthrough
everypoint
p E SZ there is acomplex
line which inter- sects a S2only
instrictly pseudoconvex points,
have the GleasonA-property,
asBeatrous Jr.
proved
in[5].
Fomess and0vrelid proved
in[6]
that apseudo-
convex domain in
C2
with realanalytic boundary
has the GleasonA-property.
This was extended
by
Noell([12])
topseudoconvex
domains incC2 having
aboundary
of finitetype.
Expanding
ideas of[5],
Backlund and Fällströmproved
in[4]
that abounded, pseudoconvex
Reinhardt domain incC2
withC2-boundary
and contain-ing
theorigin,
has theGleason A-property.
For every p E S2they
constructed afinite open
covering
ofQ,
such that theGleason-problem
can be solvedeasily
on each of its open sets; moreover the
pairwise
intersections of its open sets intersect theboundary only
instrictly pseudoconvex points.
Then aglobal
so-lution is obtained
by formulating
an additiveCousin-problem
andagain using 0vrelids
theorem.By using
similartechniques,
we prove that the result of Backlund and Fallstrom also holds without theassumption
that the domain contains theorigin.
In the second part of this paper we show that the condition that Q needs to bepseudoconvex
can bedropped.
Note that the Gleason
problem
is notalways solvable;
infact,
Backlund and Fallstrom showed([3])
that there even exists an H°°-domain ofholomorphy
on which the
problem
is not solvable.MAIN RESULT
Let S2 a bounded Reinhardt domain in
C2
withC2-boundary.
Then S2 hasthe
Gleason-property
withrespect
to bothA(Q)
and In other words:given
a functionf
inA (Q)
that vanishes at p EQ,
there exist functionsfix, f2
EA (Q),
such thatf
=fl (Z I - P 1)
+f2(z2 - p2),
andsimilarly
forACKNOWLEDGEMENTS. Part of this paper was written while the first author
was
visiting
Mid SwedenUniversity,
Sundsvall. He would like to thank thedepartment
ofphysics
and mathematics for itshospitality.
The authors are alsograteful
for the critical remarks of thereferee,
which led to a betterpresentation of,
inparticular,
Lemma 1 and Theorem 9.2. - Some
definitions,
notations and lemmasWe denote
by S(Q)
the set ofstrictly pseudoconvex points
in theboundary
of Q. For a function
h,
letZh
:={z : h(z)
=0}
be its zero-set. We denote theboundary
of a set Dby aD,
andCo(D)
will stand for the convex hull of D.407 We recall that a domain in C’ is Reinhardt if it is invariant under the stan-
dard 7Cn action on C’
given by (O 1, ... , On) · (z 1, ... , zn) H (e‘ 01 z 1, , .. , ei8n zn) .
The map L : z =
(z 1, ... , Zn )
Hlog IZnD
sends S2 to itslogarithmic image
=L(S2).
Thelogarithmic image
ofZf
is denotedby L(Zf),
andS(w)
will stand for theC2 strictly
convexpoints
of cv.We recall some basic facts
(cf. [11])
about the relation between S2 and cv:Q is
pseudoconvex
~ cv is convex. If Q has aC2 -boundary, w
will also havea
C2 -boundary.
Also note that apoint
z(having
no zerocoordinate)
in 8Q isstrictly pseudoconvex
oL(z)
is astrictly
convexpoint
of acv.LEMMA 1. Let S2 be a bounded
pseudoconvex
Reinhardt domain ine2.
Let ~, be a smootha-closed (0, 1 ) farm
onQ,
whosecoefficients
are bounded on Q.If 8w n L (supph)
consistsof a finite
numberof bounded
setscontaining only C2 strictly convex points,
then there existsa function
u inC(Q)
f1 such that5u
= À.PROOF. First suppose that S2 does not meet the axes z I = 0 and Z2 = 0.
Then the
logarithmic image w
of Q is bounded. Thelogarithmic image
X ofsuppx n a o
is a closed subset of thestrictly
convexpoints
of Hence there exists a boundedstrictly
convex domain w cR 2
such that c~ C jo and XThen
SZ :
:={ (z 1, Z2)
EcC2 : L (z)
ECO)
is astrictly pseudoconvex
domain.The form h can be
trivially
extended(by defining
it to be 0 atQ)
to a C°°-form1
onS2.
Since SZ isstrictly pseudoconvex,
there exists a function u E such that8E = I ([13],
p.158-159).
The restriction u =üln-
has the desired
properties.
Next suppose that Q meets at least one of the axes.
Keeping
in mind that Q isC2
andpseudoconvex,
there are twopossibilities:
(1)
0 E Q. Then Q meets each axis in a disk about 0.(2) 0 ~
Q. Then Q meetsonly
one of the axes, say thez2-axis,
in an annulus.We will show how to deal with the second case, the first one
being completely
similar. Observe that
Qo
={(Z1~ Z2) : loglz21+clzl12 k, log IZ21-clz112 > --k~ IZII c, c, k >
0 isstrictly pseudoconvex
at the intersection of itsboundary
with thez2-axis.
Itslogarithmic image
isThe
logarithmic image
of Q is contained in ahalf-strip: ( y ( N,
x N.Let Y C 8w be a
(relative) neighborhood
ofX,
contained in thestrictly
convexboundary points
of w. Let cv’ be the intersection of thehalf-planes
that contain wand aretangent
at somepoint
of Y. Then w C w’. Now we takek > N and c so small that wo C w’. As in the case where w is
bounded,
we can find a
strictly
convex domain w(with C2-boundary),
theboundary
ofwhich contains Y and the
part
of theboundary
of cvo where x issufficiently
small. Now
lii
:= hasC2-boundary,
isstrictly pseudoconvex,
and weproceed
as in theprevious
case. 0LEMMA 2. Let S2 be a bounded
pseudoconvex
Reinhardt domain incC2
withC2-boundary.
Let p E S2. Then there existanalytic polynomials
g,h,
open setsUo, Ul, U2
and a constant E > 0 such that:~
Uo
isstrictly pseudoconvex,
and p EUo
C CQ,
~h~
.QCU¡Ui,
PROOF.
First,
we will construct theanalytic polynomials g
andh,
then weconstruct the open sets
Ul.
We start with the case that Q does not containpoints
with a zerocoordinate, using
thefollowing elementary
fact:let w a
bounded,
convex domain inR 2, having C2-boundary. Let q
E W. Then8w contains 3
strictly
convexpoints,
u, v and w, suchthat q
lies in the interior of thetriangle
u v w. Of course one can choose u, v and w such that theslope
of the lines qu and v w are rational numbers.
Given a line I in
R 2 passing through q - L(pi, P2)
with rationalslope
±11,
we construct apolynomial f
incC2
such thatL (Z f )
= I:If
n 0,
m, n >0,
we takef(z)
=If ~ > 0, m, n > 0,
we takezm pn
(Just
as in[4].)
Choose u, v, w E co as above.Let g
be apolynomial
oncC2
suchthat g
vanishes at p and thelogarithmic image
ofZg
is a line inR 2 passing through
u.Similarly,
let h be apolynomial
oncC2
such that h vanishesat p and the
logarithmic image
ofZh
is a line inR 2 parallel
tovw.
Now we are
ready
to construct the opencovering Uo
UUl
UU2
of Q.8w consists of 3 arcs,
namely J, (from
u tov), J2 (from v
tow),
andJ3 (from
w tou).
LetSl , S2, S3, S4
be open(in
the usualtopology
on8w) neighborhoods
of u, u, v and wrespectively, consisting only
ofstrictly
convexpoints,
such thatS,
cS2.
It is then
possible
to choose opensets Vi
CR 2
as follows: letVi
suchthat
J(Vi, L (Zh ))
> e,and Vi
n ac~= S2
U(s3 U J2
US4). V2 is chosen
suchthat
d(V2,L(Zg))
> E,For
sufficiently
small E there is astrictly
convex setVo
C C co such thatw C
U Vi
and CVI
UV2.
ThenVI n V2 n
acv containsonly strictly
convexpoints.
The setsUl :
:= fulfill therequirements
of Lemma 2.Suppose S2
meetsonly
one of the axes, say zi = 0(see [4]
for the case0 E
Q).
Let p =(PI, p2)
E S2. If PI = 0 one definesg(z)
:= zl,h(z)
:= z2-p2~and the rest is easy.
Otherwise,
thelogarithmic image
of Z2 = p2 intersects 8w inonly
onepoint,
a. Now draw a linethrough L(p) parallel
to thetangent
line in a. It intersects 8w at twopoints,
say b and c. Since theboundary
of 8wbetween a and
b, a
and c are notstraight lines,
and w is convex, there mustbe an extreme
point
d on the arcab,
and one, e, on the arc ac. Thesepoints
d and e can be chosen such that
they
haveneighborhoods
ofstrictly
convexpoints
in8w,
and that the line de has rationalslope (since co
is convex with409
C2-boundary).
Now we choose = z2 - P2, and h apolynomial
such thath vanishes at p and the
logarithmic image
ofZh
isparallel
to de. The setsUi
can be constructed as above. D3. - The Gleason
problem
forpseudoconvex
Reinhardt domainsThe
following
result was obtainedby
Backlund and Fallstrom([4])
underthe extra
assumption
that S2 contains theorigin.
THEOREM 3. Let S2 be a
bounded pseudoconvex
Reinhardt domain inC 2, having
C2-boundary.
Then S2 has the GleasonA-property.
PROOF. We solve the
Gleason-problem locally
andpatch
the solutions to-gether
to aglobal
solutionusing
Lemma 1. Let p E Q. Choose g,h, Uo, Ul
andU2
as in Lemma 2. Choose functionsq5k
E =0, 1, 2,
such that0 ~k
1 and 1 on Q. Letf
be a function inA (S2), vanishing
atp. Since
f
isholomorphic
onQ, Uo
ccQ,
the lemma of Oka-Hefer(cf. [ 11 ] ) implies
that there exist functions inA (Uo)
such thatand
Since g
is ananalytic polynomial, vanishing
at p, there are functions gl, g2 EH (cC2 )
suchthat 9
= onC2 .
A similar formula holds for h.Substituting
this in(*),
we obtain the existence of functionsflk
EA(Uk
fl =1, 2,
such thatand
give
a smooth solution of ourproblem.
We want to find u such thatand
are in
A (S2).
Define a form À as follows:This
form h is a a-closed(0, l)-form
onS2,
and can becontinuously
continuedto
0.
Hence its coefficients are bounded on S2. Thesupport
of h is contained inUi n Uj, i =1= j.
Hence we have thatsupph n a S2 c S ( S2) .
Lemma 1gives
the existence of a function u n such that au = À. With this u,
f i, f2
as defined at(**),
and
fl, f2
bothbelong
toA(~).
This proves that the maximal idealconsisting
of functions
vanishing
at p isgenerated by (zl - pl)
and(z2 - P2)-
04. - The Gleason
problem
for nonpseudoconvex
Reinhardt domainsTo prove that a bounded Reinhardt domain in
cC2,
withC2-boundary,
has theGleason-property
withrespect
toA(S2)
andH°°,
even if it is notpseudoconvex,
we need some more
machinery.
This isdeveloped
in thefollowing propositions
and corollaries.
DEFINITION. Given a set
V c
RI and apoint
v Ea V,
we say v is anextreme
point
of V if there do not existr, s E a V,
distinct from v, and~. E
(0, 1)
such that v =~,r -~- ( 1- ~.)s .
In other words: if v is an extremepoint
of
Note that V may be
strictly
convex at apoint
v without vbeing
an extremepoint
of V.LEMMA 4. =
at 0. Then
g"
exists at 0 andequals
0.PROOF. Without loss of
generality,
we take =g’(0)
= 0.Since g’
isincreasing,
we find for y > 0:so that
g’-(y)g(2y)
=o ( 1 ) .
Therefore the secondright
derivative of g at 0y - y
exists and
equals
0.Similarly
for the second left derivative. D PROPOSITION 5. Let cv a domain inJae2,
withC2-boundary.
Denoteby
E the setof extreme points of w.
Then Eo = E.PROOF. We endow with the relative
topology.
AsE’ C a Co (cv)
is clearly
open, E is closed in and Eo C E. Thecomplement
ofE° in
aCo(cv)
is a union ofdisjoint
open arcs. We will show that these arcs are in factstraight
line segments.Take p
in such an arc U c Ifp 0 E,
then pobviously
lies on astraight
linesegment.
So letp E E.
Then411 p Since w has
C2-boundary, Co(w)
hasC1-boundary (in
fact iteven has
C1,1-boundary,
cf.[9]).
Afterrotating
andscaling
we can assume that there existsf
EC2 [-1, 1 ]
and g E1 ]
with thefollowing properties:
p (0, f (0)) = (0,
.
. Y
= {(x, g(x)) :
x E[-1, I]} ~ aco(w)
f1[-1, 1]
x[min g, max g]
9 g is convex o
f > g
on[-1, 1 ].
Note that p E X n Y and therefore the
tangent
to aw at pequals
thetangent
to at p:
g’(0)
=f ’ (0) . Furthermore,
sincep E E, f"(0)
> 0. But iff " (o)
>0, then p
E E 0. Hencef " (0)
= 0. It follows thatg (0) + Xg’(0) g (x ) f(x)
=+ o (x 2 )
=g (0) +0(x2).
So
g(x)
=~(0)+jc~(0)+o(j~). Application
of theprevious
lemmagives
thatg" (o)
= 0. Since we canrepeat
theargument
for everypoint
ofY,
it follows thatg"
isidentically
0 on[-1, 1 ], meaning
that Y is astraight
linesegment.
Of course U is a
straight
line segment too. Thisyields
that U(and
any othersubset of
E°)
does not contain extremepoints,
hence E c E ° . 0LEMMA 6. Let wand E be as
above,
let e E E. There exists apoint
b E Earbitrary
close to e such that acv andaCo(cv)
coincide on aneighborhood
Bof
b.
Furthermore,
thisneighborhood
can be chosen such that it(as
partofaCo(w»
consists
only of strictly
convexpoints.
PROOF. E° =
E,
hence one can choose apoint a
E Earbitrary
close toe, such that there is a
neighborhood
A of acontaining only
extremepoints
ofw. Since the extreme
points
of wandCo(w)
are the same, 8w andcoincide on A. Hence the
defining
function p foraCo(cv)
can be chosen such that it is aC2-function
around A. There is apoint
b E A for whichp" (b)
> 0.Then there is a
neighborhood B
c A of b on whichp"
isstrictly positive.
DTHEOREM 7. A bounded Reinhardt domain SZ in
(C2,
withC2-boundary,
has theGleason-property
with respect to bothA (Q)
andPROOF. First let
f
EA (S2),
p E Q such thatf ( p)
= 0. Note thatf
extendsto the
holomorphic
hull ofQ,
and that =Suppose
cv is bounded. There are extremepoints
e2, e3 E 8w withthe
property L(p)
ECo(el, e2, e3). According
to theprevious
lemma there existpoints
a,b,
c,arbitrarily
close to e2, e3,having neighborhoods A, B,
Crespectively, containing only strictly
convexpoints
such thatA, B,
C Caw f1
aCo(cv).
These a, b and c could have been chosen such that theslopes
of the lines ab and
L(p)c
are rational. Just as in Lemma2,
we constructpolynomials
g and h that vanish at p, such thatL (Zg)
is a linethrough L(p)
and c, and
L(Zh)
is a linethrough L ( p) parallel
to ab. Then one can constructthe
appropriate covering
ofCo(w),
andsimply
copy theproof
of Theorem 3.Now suppose cv is not bounded. We
only
consider the case that SZ containspoints
of the form(0, a);
the other cases can be solvedsimilarly. Applying
the ideas of the second
part
of Lemma 2(to Co(w)
instead of tocv) yields
theappropriate polynomials
g, h and setsUi. Repeating
theproof
of Theorem 3 proves the assertion.Next let
f
EH°°(Q), p
E S2 such thatf ( p)
= 0. Likeabove,
we obtainan open
covering { Ui }
ofS2,
andmatching
functionsOi.
As in theproof
ofTheorem
3,
we obtain a(0, 1 )-form
~.:The functions
fl
are bounded andholomorphic. ok
ECr(Uk),
so isbounded. The function is bounded on
supph,
sinced(p, Ui nlU
> S. Hence the form h is bounded onS2,
and we canapply
lemma1 to find a function u E
C(S2)
flC°°(Q)
with au = À. Now copy theproof
ofTheorem 3. D
REMARK. The crux of this
approach
is to formulate aa-problem (au
=h)
on Q suitable for
solving
the Gleasonproblem,
in such a way that h can be extendedby
0 to alarger
domainS2
wherea u
= À has agood
solution. WhileS2
isstrictly pseudoconvex
in oursituation,
the method willgive
results in someother cases, e.g. when
S2
is ananalytic polyhedron
incC2.
PROPOSITION 8.
Let w
CR 2. If
the setof C2-boundary points of
w contains adense subset
of E,
then Eo = E.PROOF. We endow
aCo(cv)
and acv with the relativetopology.
As Ec cis
clearly
open, E is closed inaCo(cv),
thus E. To prove the otherinclusion,
suppose eE F
n E. Thispoint e
cannot be an isolatedpoint
ofE;
then it would be in this dense subset of E. But suchpoints
havea
neighborhood consisting
ofC2-boundary points
in8w,
thus aneighborhood consisting
ofC 1-boundary points
in8Co(w).
Therefore there would be a sequence
fen)
ofC2-boundary points
inthat converges to e.
However,
theproof
ofproposition
5 shows that suchpoints
en do not exist. This is a
contradiction,
henceEOc
n E =0,
and E CEo.
0 THEOREM 9. Let S2 C(C2
be a bounded Reinhardt domain.Suppose
w isbounded as
well,
and that the setof C2-boundary points of
w contains a densesubset
of
E. Then one can solve theGleason-problemfor
bothA (Q)
andH°° (S2).
PROOF.
Using proposition
8 we canrepeat
theproof
of Theorem 7. D REMARK. Theonly thing
that matters is that there areenough strictly pseudoconvex points
in theboundary
of Q to make a"good"
cover of Q.This
can e.g. be done in the
setting
of theorem 9 if wemerely
assume that0 V Q
instead
being
bounded. In that case,given
apoint
p EQ,
one takes413
= z2 - p2
(if
S2 containspoints
of the form(0, a ) )
org (z )
= ZI - p i(if
S2 contains
points
of the form(a, 0)),
andproceeds like,
e.g., in Lemma 2.We do not know if the Gleason
problem
can be solved for a bounded domain S2 CcC2
of theform IZI12 IZ21’ 21zl 12 for 1,
that is rounded off in astrictly pseudoconvex
way forlarger
z 1.5. - An
example
Let S2 be a bounded convex domain in C’. For every
f
Evanishing
at p, theLeibenzon-divisors 1fri
are defined in thefollowing
way:If in addition Q has
C2-boundary,
thenas Leibenzon
proved
in[10].
In[8] Grange
was able to show that the functions1/1’;
remain in if S2only
hasC1+-boundary.
There he also gave thefollowing exampl:
leth(x)
:= for x >0, h (0) :
:= 0. LetS2 is convex, is
C~,
even C°° andstrictly pseudoconvex
at thepoints (z 1, z2) E S2 , z2 ;
0. Then afunction 0
E wasgiven
for which the Leibenzon-divisor~2 ~
However, S2 satisfies the conditions as described in the remark after Theo-
rem 9 and hence there exist functions
f, and f2
in suchthat q$(z)
=REFERENCES
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lemmers @ science.uva.nl
janwieg @ science.uva.nl Department of Mathematics
University of Amsterdam
Plantage Muidergracht 24
1018 TV Amsterdam, The Netherlands