R ENDICONTI
del
S EMINARIO M ATEMATICO
della
U NIVERSITÀ DI P ADOVA
D. N. D IKRANJAN E. G REGORIO A. O RSATTI
Kasch bimodules
Rendiconti del Seminario Matematico della Università di Padova, tome 85 (1991), p. 147-160
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D. N. DIKRANJAN - E. GREGORIO - A.
ORSATTI (*)
0. Introduction.
Let A and R be two
rings
with a non zeroidentity.
Denoteby 5lA
thefull
subcategory
of Mod-Aconsisting
of all submodules of thefinitely generated
modules in Mod-A andby Rsl
theanalogous subcategory
ofR-Mod. Observe that
5lA
andRS
arefinitely
closed.Let A be a Kasch
ring,
i. e. aring
with aperfect duality [K].
It iseasy to check that the functors
HomA (-, AA)
andHomA (-, AA)
inducea
duality between 5lA
andAM
On the other
hand, by
well known results ofAzumaya [Az],
ifAA
and
RR
areartinian,
then everyduality
between twofinitely
closedsubcategories
of Mod-A andR-Mod,
bothcontaining
allfinitely
gener-ated
modules,
induces aduality
betweenTA
andRIT-
This paper is devoted to the
study
of the bimodulesRKA
with theproperty
that the functorsHomA ( -, KA )
andHomR (-, RK) give
rise toa
duality
betweenSA
and Such a bimodule will be called a Kasch bi- Since~’A
andRs
arefinitely
closedsubcategories
of Mod-A and R-Modrespectively,
the aboveduality
is aspecial
case of Morita duali-ty,
thusRKA
is a Moritabimodule,
i. e.RKA
isfaithfully
balanced andKA
and
RK
are(injective) cogenerators.
Moreover A and B aresemiperfect rings.
This paper is subdivided into three
parts.
In the firstpart
wegive
the
following
characterization:(*) Indirizzo
degli
AA.: DIKRANJAN: Institute ofMathematics, Bulgarian Academy
ofSciences,
1090 Sofia(Bulgaria);
E.GREGORIO,
A. ORSATTI:Diparti-
mento di Matematica Pura e
Applicata,
via Belzoni 7, 35131 Padova(Italy).
Let
RKA
be a Moritabimodule;
thenRKA
is a Kasch birrcoduleif
andonly if RK
andKA
arefinitely generated, if
andonly if AA
andRR
arel.c.d.
(i.e. linearly compact
in the discretetopology)
and with essentialsocle.
Moreover, if RKA
is a Kasch bimodule andif AA
is acogenerator of Mod-A,
then A is a Kaschring.
In the second
part
relations between Kasch bimodules andsemiper-
fect
rings
areinvestigated.
Inparticular,
we obtain ageneralization
ofAzumaya’s
Theorem 6 in[Az]
in thefollowing
way:Let A be a
ring.
Then there exist aring
R and a Kasch bimoduleRKA if
andonly if:
1) AA
is l.c.d. with essentialsocle;
2)
Mod-A contains afinitely generated injective cogenerator.
If A is
commutative,
thenonly
condition1)
sufficesby
a very recent result ofAnh [An].
Moreover,
in thispart
wegive
thefollowing
form of Moritaequivalence:
If
F:TR
is anequivalence,
then F extends to a Moritaequiva-
lence between Mod-A and Mod-R.
This fact will be
substantially
used in thesequel.
In the third
part
we obtain ourprincipal
results:Let
RKA
be a Kasch bimodule and letB(R)
andB(A)
be the basicrings of
R and A. Then there exists auniquely
determined Kasch bi- moduleB(R)HB(A)
whereB(R)H
is a minimalinjective cogenerator of B(R)-Mod
andsimilarly for HB(A).
Using
thisfact,
weget
our main result which can be summarized as follows:Let
RKA
be a Kasch bimodule with R and A basicrings
aycd assumethat
AA
is acogenerator of
Mod-A. ThenWe end this introduction with some notations and conventions. All
rings
considered in this paper have a non-zeroidentity
and all modulesare unital. For every
ring
R we shall denoteby
Mod-R(resp. R-Mod)
the
category
of allright (resp. left)
modules over R. Thesymbol MR
is used toemphasize
that M is aright (left)
module. All cate-gories
and functors will be additive.Every subcategory
of agiven
cate-gory will be full and closed with
respect
toisomorphic objects.
Recall that a
subcategory ~A
of Mod-A isfinitely
closed if~
is closed undertaking submodules, homomorphic images
and finite directsums. We assume that the reader is familiar with the
elementary
prop- erties oflinearly compact rings
and modules in the sense ofLeptin [L].
We denote
by
Z thering
ofintegers, by Q
the field of rationals andby
N the set of
positive integers.
1.
Finitely generated injective cogenerators.
1.1. Let A and R be two
rings.
A bimoduleRKA
is called a Morita bimodule ifRKA
isfaithfully
balanced and bothKA
andRK
areinjective cogenerators
of Mod-A and R-Modrespectively.
This definition is moti- vatedby
thefollowing
well known result of Morita[Mo]:
The bimoduteRKA is
a Morita bimoduleif and only if the subcategories 8A of
Mod-Aof
R-Modconsisting of K-reflexive
modules arefinitely
closedand contain all
finitety generated
modules.If
RKA
is a Moritabimodule,
thenby
a known result of Muller[Mu]
AA, RR, KA
andRK
are 1. c. d. modules(i. e. linearly compact
in the dis- cretetopology).
Inparticular,
therings
A and R aresemiperfect.
1.2. Let
RKA
be a Morita bimodule. Then thesubcategory TA
ofMod-A
consisting
of all submodules of thefinitely generated
modules iscontained in
Similarly Rtf
Ingeneral
the Morita bimoduleRKA
does not induce a
duality
betweenSTA
andalthough TA
and~
arefinitely
closedsubcategories
of Mod-A and R-Modrespectively.
1.3. DEFINITION.
a)
LetRKA
be a Morita bimodule. We say thatRKA
is a Kasch bimodule if the functorsH,
=HomA (-, KA)
andH2
=- HomR (-,~7~) give
aduality
between5lA
andRtf.
b)
Let A be aring.
We say that A has aright
Kaschduality
ifthere exist a
ring
R and a Kasch bimoduleRKA.
c)
Recall that aring
A is said to be a Kaschring
if bothAA
andAA
are
injective cogenerators
of Mod-A and A-Modrespectively.
We shall see in the
sequel
that if A is a Kaschring,
then the bimod-ule
AAA
is a Kasch bimodule.1.4. PROPOSITION. Let
RKA be
a Morita bimodule. Thefollowing
conditions are
equivalent:
(a) RKA is
a Kaschbimodule;
(b) KA
andRK
arefinitety generated;
(c) AA
andRR
arefinitely cogenerated;
(d) AA
andRR
are l. c. d. with essential socle.PROOF.
(b) ~ (c)
It is well known that theassignment (I)
defines a latticeantiisomorphism
between the lattice2(AA)
ofright
ideals of A and the lattice of submodules of
RK.
(c) ~ (d)
is evident.(a) ~ (b) KA
is a submodule of afinitely generated
moduleFA
E Mod-A. SinceKA
isinjective, KA
is a direct summandof FA.
ThusKA
isfinitely generated.
(b)
~(a)
Let M ETA
There exists an exact sequencein Mod-A such that F is
finitely generated,
i. e. there exists an exact se-quence A n ~ F -~ 0.
Dualizing
weget
henceDualizing (1)
we obtain the exact sequencetherefore
HI (M) e R6l
D1.5. COROLLARY. Let A be an
arbitrary ring.
ThenAAA
is a Kaschbimodule
if
andonly if
A is a Kaschring.
1.6. The
following proposition
shows a further connection between Kasch bimodules and Kaschrings.
1.7. PROPOSITION. Let
RKA
be a Kasch bimodule and assume thatAA is
acogenerator of
Mod-A. Then A is a Kaschring.
PROOF. Mod-A has
finitely
manynon-isomorphic
modules since A issemiperfect.
On the other handAA
is acogenerator
of Mod-Aby hy- pothesis. Then, by
Theorem 12.5.2 from[K], AA
is aninjective
cogen- erator of Mod-A. SinceAA
is l. c. d. with essential socleby Proposition 1.4,
we canapply
Theorem2.10. a)
from[DO] (due
to ClaudiaMenini,
see also
[Me])
to conclude thatAA
isquasi-injective
andconsequently injective. Again by
Theorem 12.5.2 from[K],
everysimple
module inA-Mod is
isomorphic
to a left ideal of A. ThusAA
is aninjective
cogen- erator of A-Mod. Hence A is a Kaschring.
DThe
following corollary
is a consequence of a well knownproperty
of Kaschrings.
1.8. COROLLARY. Under the
hypotheses of the
aboveproposition,
Ainduces a
duality between SA
andAs defined by
meansof
the linearforms. Consequently R~
andAT
areequivalent categories.
1.9. PROPOSITION. Let A be
right
artinianring.
Then A admits aMorita
duality
with aring
Rif
andonly if
A admits a Kaschduality
with R. In this case
5lA
coincides with thecategory of finiteLy generated
modules in Mod-A and
similarly for Rtf.
PROOF.
By
a resultessentially
due toAzumaya [Az] (see
e.g.Tachikawa
[T],
Theorem3.8),
A has aright
Moritaduality
if andonly
ifMod-A has a
finitely generated injective cogenerator.
1.10. COROLLARY.
Every
commutative artinianring
admits aKasch
duality
withitself.
PROOF. It is
enough
to show this for a local commutative artinianring
with maximal ideal m.By
a well known result of Matlis[Ma],
the moduleKA
=E(A/rrt),
theinjective envelope ofA/m,
is aLoewy
modulewith finite
Loewy length
and finiteLoewy
invariants. ThereforeKA
isa module with finite
length
in the usual sense. MoreoverEnd(KA) =
= A.
1.11. EXAMPLE. Let
RKA
be a Kasch bimodule. Ingeneral,
therings
R and A need not beself-injective,
as thefollowing example
shows.
Let A be a commutative local artinian
ring
with maximal ideal m, and setKA
=E(A/xrt).
Assume that A isself-injective
and observe thatSoc(A)
is essential inA,
so thatAA
is aninjective cogenerator
of Mod-A. We will show
that,
in this case,Soc(A)
must besimple. Indeed,
let nbe the
length
ofSoc(A).
Then A =E(Soc(A))
= Kn.Dualizing
weget
K =
HomA (A, K)
=HomA (Kn , K)
= A" = Kn and this ispossible
ifand
only
if n =1,
so thatSoc(A)
issimple.
This is not true in
general:
let k be a field and set A = k X1~ 2,
thetrivial extension of the module
k 2 by
thering
k.1.12. EXAMPLE. Let
RKA
be a Kasch bimodule. Ingeneral Soc(AA)
and
Soc(RR)
do not contain a copy of eachsimple
module in Mod-A or inR-Mod
respectively.
Consider thefollowing example.
Let
Z2
be the field with two elements and setthe
ring
of 2x 2 uppertriangular
matrices overZ2.
Then A is both left andright
artinian and both Mod-A and A-Mod have afinitely generat-
edinjective cogenerator (for instance,
aninjective cogenerator
of Mod-A isHomz (A, (a/Z)). Thus, by Proposition 1.9,
A admits a left anda
right
Kaschduality.
Consider the maximal two-sided ideal
Clearly
there is amonomorphism
ofright
A-modulesA/m - AA if
andonly
if there exists a EA,
a #0,
such that arrt = 0. Let us see that suchan element does not exist. In
fact,
let a= x
y with x, y,
z EZ2.
Thenarrt = 0
yields
hence x = y = z = 0.
Consequently
a = 0.1.13. EXAMPLE OF A NON ARTINIAN COMMUTATIVE KASCH RING.
Let R be a noetherian commutative local
ring
with maximal ideal m andassume that R is
complete
in its m-adictopology.
Set E =E(R/m): by
well known results of Matlis
[Ma], R = EndR (E).
Consider the trivial extensionClearly
A is a commutative local I,c,d,ring
and moreover A is subdi-rectly
irreducible.Then, by
animportant
result ofAnh (cf. [An],
Theo-rem
7),
A isself-injective.
ThereforeAA
is aninjective cogenerator
of Mod-A.This
example generalizes
the one in ex.(11)
in[K], Chap.
12.1.14. Other
examples
of the kindgiven
in 1.13 can be obtained in thefollowing
way. Let A be any commutative I,c,d,ring.
For a EA,
a ~ 0 and let I be an ideal of A which is maximal with
respect
to theproperty
a I I. ThenAII
is an 1. c. d.ring
withsimple
and essential so-cle. On the other
hand, by
the result ofAnh, A/I
isself-injective.
ThusA/I
is a Kaschring.
2. Kasch bimodules and
semiperfect rings.
We
begin
with a theorem whichgives
a necessary and sufficient condition for aring
A in order to have aright
Kaschduality.
2.1. LEMMA. Let A be a
ring
which is 1. c. d. on theright, KA
an in-jective cogenerator of
Mod-A with essential socle and R = End(KA ).
Then the
following
conditions areequivalent:
(a) KA
isl.c.d.;
(b) RK
is aninjective cogenerator of R-Mod;
(c) RR
is 1. c. d.PROOF. See
[DO], Corollary
5.12. 02.2. THEOREM. For any
ring
A thefollowing
conditions areequiva-
lent :
(a)
A has aright
Kaschduality;
(b) AA
is L. c. d. with essential socle and Mod-A hasa finitely
gen- eratedinjective cogenerator KA.
If (b)
isfulfilled, then, setting
R = End(KA), RKA
is a Kaschbimodule.
PROOF.
(a) ~ (b)
follows fromProposition
1.4.(b) =>(a)
Set R == End
(KA );
thenRKA
isfaithfully
balancedby Proposition
2.10 of[DO].
The module
KA
is I.c.d. since it is ahomomorphic image
ofA n,
for asuitable n E N.
By
Lemma 2.1 andby
Müller’s Theorem 1 in[Mü], RKA
is a Morita bimodule.
Finally,
sinceAA
isfinitely cogenerated, RK
isfinitely generated.
DWhen A is a commutative
ring,
the above theorem can beimproved
as follows.
2.3. THEOREM. Let A be a commutative
ring.
Then A has a Kaschduality if
andonly if
A is L. c. d. with essential socle.PROOF. The condition is necessary
by
the above theorem. For thesufficiency,
note thatA, being 1. c. d. ,
has a Moritaduality by
the citedresult of
Anh. By
theorem 3 of[Mü],
A has a Moritaduality
withitself,
so that there is a Morita bimodule
AKA.
Since A isfinitely cogenerated,
KA
isfinitely generated.
R2.4. PROPOSITION. Let A and R be two
rings,
let~A
be the subcate-gory
of
Mod-Aconsisting of
all submodulesof
thefinitely generated
modules in
Mod-A,
let~R
be theanalogous subcategory of
Mod-R andsuppose that there exists an
equivalence
Then the
rings
A and R are Moritaequivalent.
PROOF. Set
PR
=F(A);
then A = End(PR ),
so we have the bi-module
APR.
Let M E~’R
and consider the naturalisomorphisms
inMod-A
Then G -
HomR (PR , - ) (G
isnaturally equivalent
toHomR (P~, 2013)).
We show next that F - -
OAP.
The module
PR
is agenerator of FR
incategorical
sense, sinceAA
is agenerator
of Take a module M E~’R
and setAssume T is a proper submodule of M and consider the canonical
projection
Then 7r "* 0 and since both M and
M/T belong
to~’R
andPR
is agenerator
of there exists a
homomorphism f : PR -
M such that7rOf=l= 0,
a con-tradiction,
sinceIm f c
T = ker 7r. Therefore T = M.Now assume that M E
~’R
isfinitely generated.
Thenby
the aboveargument
there exist n E N and asurjective homomorphism
M.This shows that
PR generates
allfinitely generated
modules inMod-R, consequently
it is agenerator
of Mod-R. It is well known that in such a caseAP
isprojective and,
inparticular,
flat. Thisyields
F -== -OAP.
Infact,
let L E Then there exist afinitely generated
module N E~’A
and an exact sequence On the other
hand, N OR P
is ahomomorphic image
ofPR ,
for somen E N,
so that LOR P
E since~’R
isfinitely
closed. Thus -(8) R P,
restricted to is theunique adjoint
of G. Now set T = -(8) AP
and H =HomR (PR , - ).
Since
PR
is aprojective object
in it follows thatPR
isquasi-pro- jective
in Mod-R. Let us prove now thatPR
isfinitely generated.
Infact,
let be a directedfamily
offinitely generated
submodules ofPR
withPR
= limVx.
Sincemorphisms, subobjects
andquotients
in~
are the usual ones, we
get
There exists (J. E ~1 such that
H(V,)
=A,
thenT(A)
=TH(V,) == Vp.,
theisomorphism being
canonical. Then P =V,
isfinitely generated.
Thisshows that
PR
is aquasi-progenerator
in the sense ofFuller,
because itis a
finitely generated quasi-projective generator
of Mod-R. Nowby
Theorem 2.6 in
[Fu]
the functor T defines anequivalence
betweenMod-A and
Mod-R,
so that A and R are Moritaequivalent.
D2.5. PROPOSITION. Let the
rings
A and R be Moritaequivalent.
Then
a) if AA
is 1. c. d. then alsoRR
isl.c.d.;
b) if Soc (AA)
is essential inAA,
then alsoSoc (RR)
is essentialin
RR;
c) if AA
issemiperfect
andAA
is acogenerator of Mod-A,
then al-so R is
semiperfect
andRR
is acogenerator of Mod-R;
d) if
A is a Kaschring,
then also R is Kasch.PROOF. Let
be a Morita
equivalence represented by
thefaithfully
balanced bimod-ule
APR
=T(A)
which is aprogenerator
on both sides.a)
Follows from Lemma 1.7 in[G].
b)
Observe that for every M E Mod-A there exists an isomor-phism
between the lattice2(M)
of submodules of M and the lattice2(T(M)
of submodules ofT(M).
This observation provesb),
sinceis essential in M if and
only
ifSoc(T(M))
is essential inT(M).
Inparticular Soc (PR )
is essential inPR,
sinceSoc (AA )
is essential inAA.
There exists a
surjective homomorphism
(n E N),
thusRR
is a direct summand ThereforeSoc (RR)
is essen-tial in
RR,
sinceSoc (PR)
is essential inPR.
c)
First of all we note that theequivalence (2)
preservesfinitely generated
modules andprojective
covers, so that R issemiperfect,
since every
finitely generated
module in Mod-R has aprojective
coverby
therespective property
of Mod-A.By
Theorem 12.5.2 in[K], AA
is acogenerator
of Mod-A if andonly
if every faithful module in Mod-A is agenerator.
Since Mod-R hasonly
a finite number ofnon-isomorphic simple modules,
we canapply
the same theorem to show thatRR
is a co-generator
of Mod-R. In order to do this it suffices to note that theequivalence (2)
takesgenerators
togenerators
and faithful A-modules to faithful R-modules. Wegive
aproof
of the latter fact.A module M EMod-A is faithful if and
only
ifn (kerf: f E
E
HomA (A,
= 0. Thus for a faithful module M EMod-ATo prove that EMod-R is
faithful,
it suffices to show thatIt follows from
(3)
that pn = for a submodule X of P ".Clearly (4) implies
Let r E I. To prove that r =
0,
it suffices to show that the element(0, r)
of P’
belongs
to the intersection(5).
Infact, for p:
P n ~T(M)
consider the restriction palof p
to101
@72.Clearly p(O~) = pi(0,r)
= 0by
thechoice
of r,
since pal can be considered as an element ofHomR (R, 7W)).
d)
Followsobviously
froma), b)
andc).
D2.6. EXAMPLE OF A NON ARTINIAN NON COMMUTATIVE KASCH RING.
Let A be a Kasch
ring
and letAn (n
>1)
be thering
of n x n matricesover A. Then
An
is Moritaequivalent
to A and so is a Kaschring by Proposition 2.5,
but is not commutative since n > 1.3. Reduction of a Kasch bimodule to a Kasch
ring.
3.1. Now we need some
properties
ofsemiperfect rings (cf. [AF], Chapter 7, §2).
a)
Asemiperfect ring
B is said to be a basicring
ifB/J(B) _
n
Di,
where theDi
are divisionrings. Lifting
theidempotents
ofi=1
B/J(B)
toB,
weget
thefollowing decomposition
of Bwhere is a
complete system
ofpairwise orthogonal primitive idempotents
of B. The left ideals{Bei : i
=1, ... , n} provide
acomplete
irredundant set of
representatives
of theprojective indecomposable
modules in B-Mod. For
i = 1,..., n EndB (Bei)
= eiBei
is a localring.
b)
Let R be anarbitrary semiperfect ring.
Then R is Moritaequivalent
to a basicring
B which isuniquely
determined up to isomor-phism.
This basicring
will be called the basicring of R
and denotedby B(R).
Letbe a Morita
equivalence.
Then the modules pro- vide acomplete
irredundant set ofrepresentatives
of theprojective
in-decomposable
modules in R-Mod.c)
Twosemiperfect rings
are Moritaequivalent
if andonly
iftheir basic
rings
areisomorphic.
3.2. LEMMA. Let
RKA
be a Morita bimodule acnd suppose that R is a basicring.
ThenKA
is the minimalinjective cogenerator of
Mod-A.PROOF. Since
RKA
is a Moritabimodule,
Soc(KA )
= Soc andthis is an essential submodule both in
KA
and inRK. Applying
the func-tor
HomA (-, KA)
to the exact sequencewe
get
the exact sequenceClearly HomA (K/Soc (K), KA )
coincides with the ideal of Rconsisting
of the
endomorphisms of KA vanishing
on Soc(KA)
i.e.having
essentialkernel. Since
KA
isinjective, HomA (K/Soc (K), KA)
coincides with theJacobson radical
J(R)
of R. Thereforewhere the
Di
are divisionrings.
Thisyields
that Soc is a directsum of
pairwise
nonisomorphic simple
A-modules(cf. [DO],
Lemma7.4).
03.3. PROPOSITION.
a) If RKA
is a Kasch bimodule urith A and R ba- sicrings,
thenRK
andKA
are the minimalinjective cogenerators of
R-Mod and Mod-A
respectively.
b)
LetRKA
be a Kasch bimodules and letR
aycdA
berings
Moritaequivalent
to R and Arespectively.
Then there exists a Kasch bimod- uleRHA. If R
=B(R)
and A =B(A)
are thebasic rings,
then isuniquely
determinedby
theproperty of being
a minimalinjective
co-generator
on both sides.PROOF.
a)
followsdirectly
from the above lemma.b)
Consider a Moritaequivalence
Then
clearly EndR
=A,
so we have the bimodulei-?F(RK)A. By Proposition 2.5, RR
is 1. c. d. with essential socle and is afinitely generated injective cogenerator
ofR-Mod. By
virtue of Theorem2.2, i-?F(RK)A
is a Kasch bimodule.Now consider a Morita
equivalence
and set
It can be shown as above that the bimodule
RHA
is a Kasch bimod- ule.The
uniqueness
of H in the case whenR
=B(R)
andA
=B(A)
fol- lows froma).
03.4. THEOREM. Let
RKA
be a Kasch bimodule with both A and R ba- sicrings.
Thefollowing
conditions areequivalent:
(a) AA
is acogenerator of Mod-A;
(b)
A is a Kaschring;
(c) RR
is acogenerator of R-Mod;
(d)
R is a Kaschring;
(e) RK ~-_RR, KA
=AA
and A i R.PROOF.
(a)=>(b)
and(c)=>(d)
follow fromProposition
1.7.(b)
-(c)
A is a Kaschring; by setting E(M)
=HomA (M,AA)
forM E A-Mod,
weget
a Kaschduality
Taking
thecomposition
with the Kaschduality
given by
the bimoduleRKA,
weget
anequivalence
hence aMorita
equivalence A-Mod --~ R-Mod, by Proposition
2.4.By Proposi-
tion 2.5
c), RR
is acogenerator
of R-Mod.(d)
=>(e)
Let R be a Kaschring.
We show first thatRK -RR. By
virtue of
Proposition
3.3a),
it suffices to show thatRR
is a minimal in-jective cogenerator
of R-Mod.By (6)
of 3.1 we can writewhere are
pairwise
nonisomorphic indecomposable
modules. Since
RR
isinjective
with essentialsocle,
alsoRei
isinjective
with essential socle. Thus
Rei
is theinjective envelope
of asimple
mod-ule. Since the modules
Rei
arepairwise
nonisomorphic, RR
is a minimalinjective cogenerator
of R-Mod andconsequently RK = RR .
SinceRKA
isfaithfully balanced,
we have alsoThis
isomorphism implies
alsoAA = KA.
(e) ~ (a)
is obvious. DIn contrast with the above theorem we prove the
following.
3.5. PROPOSITION. Let A a commutative
ring.
Then thefollowing
conditions are
equivalent:
(a)
A admits a Kaschduality;
(b)
A is a subdirectproducts of
afinite
numberof subdirectly
ir-reducible Kasch
rings.
PROOF.
(a)
~(b) By
Theorem 2.3 A is 1. c. d. with essential socle. On the otherhand, by
1.14 A is a subdirectproduct
ofsubdirectly
ir-reducible Kasch
rings.
SinceSoc (A)
isfinitely generated,
thisproduct
can be taken finite.
(b) ~ (a) Clearly
A is l. c. d. with essentialsocle,
so that Theorem2.3
applies again.
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