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Cyclicity in the harmonic Dirichlet space

Evgueni Abakumov, Omar El-Fallah, Karim Kellay, Thomas Ransford

To cite this version:

Evgueni Abakumov, Omar El-Fallah, Karim Kellay, Thomas Ransford. Cyclicity in the harmonic Dirichlet space. Conference on Harmonic and Functional, Analysis, Operator Theory and Applications.

1–10, Theta Ser. Adv. Math., 19, Theta, Bucharest, 2017., Jun 2015, Bordeaux, France. �hal-

01261077�

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E. ABAKUMOV, O. EL-FALLAH, K. KELLAY, AND T. RANSFORD

Abstract. The harmonic Dirichlet space is the Hilbert space of functions f ∈ L

2

(T) such that

kf k

2D(T)

:= X

n∈Z

(1 + |n|)| f b (n)|

2

< ∞.

We give sufficient conditions for f to be cyclic in D(T), in other words, for {ζ

n

f (ζ) : n ≥ 0} to span a dense subspace of D(T).

1. Introduction

Let X be a topological linear space of complex functions on the unit circle T such that the shift operator S, given by

S(f )(ζ ) := ζf(ζ), f ∈ X , is an isomorphism of X onto itself.

A closed subspace M of X is called invariant if S(M) ⊂ M. It is said to be 1-invariant (or simply invariant) for S if S(M) ( M, and it is called 2-invariant (or doubly invariant) if S(M) = M. The latter condition is equivalent to the invariance of M under multiplication by both ζ and ζ.

Let Z denote the integers and let N := {n ∈ Z : n ≥ 0}. Given f ∈ X , we write

[f ] N := Span X {z n f : n ∈ N}, [f ] Z := Span X {z n f : n ∈ Z}.

A function f is said to be 1-invariant if the space [f ] N is 1-invariant for S. We say that a function f ∈ X is cyclic (resp. bicyclic) for X if [f ] N = X (resp. [f ] Z = X ).

2010 Mathematics Subject Classification. Primary 46E22; Secondary 31A05, 31A15, 31A20, 47B32.

Key words and phrases. Harmonic Dirichlet space, capacity, cyclic vectors.

Research of OEF partially supported by Hassan II Academy of Science and Technology. Research of TR supported by NSERC and the Canada Research Chairs program.

1

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Let us begin with the classical case, namely X = L 2 (T). By a well- known theorem of Wiener, the 2-invariant subspaces have the form

M = {f ∈ L 2 (T) : f = 0 a.e. on T \ σ},

where σ is a Borel subset of T (see e.g. [11, p.8, Theorem 1.2.1]). It follows from Szeg˝o’s infimum theorem that a function f is 1-invariant in L 2 (T) if and only if log |f | ∈ L 1 (T) (see e.g. [10, p.12, Corollary 4]).

For X = C (T), Makarov [7] gave a complete description of the in- variant subspaces of S. He also obtained the following characterization of 1-invariant functions of C (T).

Theorem (Makarov [7, p.3]). A function f is 1-invariant in C (T) if and only if log |f | ∈ L 1 (T).

The case X = C n (T) (n ≥ 1) is more complicated, and no charac- terization of 1-invariant functions is known ([7, p.3], see also [8, Theo- rem 1.3] or [9, Theorem 5]).

We shall focus our attention on the harmonic Dirichlet space D(T).

This is the set of functions f ∈ L 2 (T) whose Fourier coefficients satisfy D(f ) := X

n∈Z

| f(n)| b 2 |n| < ∞.

It becomes a Hilbert space if endowed with the norm k · k D(T) , given by kf k 2 D(T) := kf k 2 L

2

(T) + D(f) = X

n∈Z

| f(n)| b 2 (1 + |n|).

According to Douglas’ formula [3], we have D(f ) = 1

2 Z Z

T

2

|f (ζ) − f (ζ )| 2

|ζ − ζ | 2 |dζ | |dζ|.

This can also be written

D(f) = 1 2π

Z

T

D ζ (f ) |dζ|,

where D ζ (f ) is the so-called local Dirichlet integral of f at ζ, given by D ζ (f ) := 1

2π Z

T

|f (ζ) − f(ζ )| 2

|ζ − ζ | 2 |dζ |, ζ ∈ T.

As D(T) is dense in L 2 (T), if a function f is cyclic for D(T), then it is also cyclic for L 2 (T). So by Szeg˝o’s theorem we have

f is cyclic for D(T) ⇒ Z

T

log |f(ζ )| |dζ | = −∞.

In [12], Ross, Richter and Sundberg gave a complete characteriza-

tion of the 2-invariant subspaces M of D(T) in terms of their zero

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sets. In order to state their result, we need to introduce the notion of logarithmic capacity (see for instance [6, §2.4]).

The energy of a Borel probability measure µ on T is defined by I(µ) :=

Z Z

T

2

log 1

|ζ − ζ | dµ(ζ )dµ(ζ ) = X ∞

n=1

| µ(n)| b 2 n .

Then we define the logarithmic capacity of a Borel subset E of T by c(E) := 1/ inf{I(µ) : µ ∈ P (E)},

where P (E) denotes the set of probability measures supported on a compact subset of E. We say that a property holds quasi–everywhere (q.e.) if it holds everywhere outside a set of logarithmic capacity zero.

It is known that, if f ∈ D(T), then the radial limit of the Poisson integral of f exists q.e. and is equal to f a.e. (for more details we refer to [12] and the references therein). In the sequel, f will denote this limit, and will therefore be defined q.e. on T. We shall write Z (f) for the zero set of f, namely

Z (f ) := {ζ ∈ T : f (ζ) = 0}.

Note that this set is defined up to sets of logarithimic capacity zero.

Theorem (Richter–Ross–Sundberg [12]). M is a 2-invariant subspace of D(T) if and only if there exists a measurable set E ⊂ T such that

M = D E := {f ∈ D(T) : f|E = 0 q.e.}.

Note that the problem of characterization of 1-invariant subspaces of D(T) remains open. It was proved in [1, 13] that, for each n ∈ N ∪ {∞}, there exists an invariant subspace M of D(T) such that dim(M/S(M)) = n. This suggests that the lattice of 1-invariant sub- spaces has a very complicated structure.

As a direct consequence of the Richter–Ross–Sundberg theorem, we obtain the following necessary conditions for cyclicity in D(T).

Theorem 1. If f is cyclic for D(T), then Z

T

log |f (ζ)| |dζ| = −∞ and c(Z(f)) = 0.

Our goal in this paper is to give sufficient conditions for a function f ∈ D(T) to be cyclic.

For β ∈ (0, 1], we shall denote by Lip β (T) the set of functions f continuous on T such that

kf k Lip

β

(T) := kf k C(T) + sup

ζ,ζ

∈T

|f (ζ) − f (ζ )|

|ζ − ζ | β < ∞.

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For α ∈ (0, 1), we set

C 1+α (T) := {f ∈ C 1 (T) : f ∈ Lip α (T)}.

Of course, if f belongs to Lip β (T) or C 1+α (T), then Z (f) is closed in T.

We shall establish the following result.

Theorem 2. Let f ∈ D(T) such that |f | ∈ C 1+α (T), where α ∈ (0, 1).

Suppose further that log |f | ∈ / L 1 (T). Then [f 2 ] N = D Z(f) . Combining Theorems 1 and 2, we deduce

Corollary. Let f ∈ D(T) such that |f| ∈ C 1+α (T), where α ∈ (0, 1).

Then the following assertions are equivalent:

(1) f 2 is cyclic for D(T);

(2) log |f | ∈ / L 1 (T) and c(Z (f )) = 0.

A closed set E ⊂ T is said to be a Carleson set (and we write

E ∈ (C)) if Z

T

log 1

d(ζ, E) |dζ| < ∞.

For background information on Carleson sets, see e.g. [6, §4.4]. Note that, if f ∈ Lip β (T) and Z (f ) ∈ / (C), then log |f| ∈ / L 1 (T).

It is known that Lip β (T) ⊂ D(T) if and only if β > 1/2. The inclusion Lip β (T) ⊂ D(T) for β > 1/2 can easily be obtained from Douglas’ formula.

We shall establish the following theorem.

Theorem 3. Let f ∈ Lip β (T), where β ∈ ( 1 2 , 1]. If Z (f) ∈ / (C), then [f ] N = D Z(f ) . If furthermore c(Z (f )) = 0, then f is cyclic for D(T).

2. Proof of Theorem 2

For the proof of Theorem 2, we shall need the following standard result.

Lemma 4. Let f ∈ D(T). The following assertions are equivalent:

(1) [f ] N = [f] Z ; (2) f ∈ [Sf ] N ;

(3) inf{kpf k D(T) : p ∈ H , pf ∈ D(T) and p(0) = 1} = 0.

Proof. Since S is invertible, (1) and (2) are equivalent.

If f ∈ [Sf ] N , then there is a sequence (p n ) of polynomials such that p n (0) = 1 and k(1 − p n )fk D(T) → 0. This proves that (2) implies (3).

Finally, suppose that (3) holds. Let (p n ) ⊂ H be a sequence such

that p n (0) = 1, p n f ∈ D(T) and kp n fk D(T) → 0. Writing p n = 1 − zq n ,

by [12, Proposition 3.4] we have zq n f ∈ [Sf] N . Since zq n f converges

to f, it follows that f ∈ [Sf ] N , so that (2) holds.

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We shall also need the following result, which is a special case of a theorem due to Carleson–Jacobs–Havin–Shamoyan [2, Theorem 6.1].

Lemma 5. Let F be an outer function on D that is continuous on D.

If |F | ∈ C 1+α (T), where α ∈ (0, 1), then F ∈ Lip (1+α)/2 (D). Further- more, the Lipschitz constant associated to F on D depends only on the Lipschitz constants and bounds for the derivatives of |F | on T.

Proof of Theorem 2. Let p ǫ be the outer function such that

|p ǫ (ζ)| = e −M

ǫ

|f (ζ)| + ǫ a.e. on T, where the constant M ǫ is chosen so that p ǫ (0) = 1. Thus

M ǫ = Z

T

log 1

|f(ζ)| + ǫ |dζ|

2π ,

and since log |f | ∈ / L 1 (T), it follows that M ǫ → ∞ as ǫ → 0 + . We are going to prove that

ǫ→0 lim

+

kp ǫ f 2 k D(T) = 0.

If this holds, then by Lemma 4 we have [f 2 ] N = [f 2 ] Z , and since clearly Z(f 2 ) = Z(f ), we can apply the Richter–Ross–Sundberg theorem to obtain the desired result.

We have

kp ǫ f 2 k 2 D(T) = kp ǫ f 2 k 2 L

2

(T) + D(p ǫ f 2 ).

For the first term, we have kp ǫ f 2 k 2 L

2

(T) =

Z

T

e −2M

ǫ

|f| 4 (|f | + ǫ) 2

|dζ |

2π ≤ e −2M

ǫ

kf 2 k 2 L

2

(T) → 0 as ǫ → 0 + . The second term we estimate using Douglas’ formula, namely

D(p ǫ f 2 ) = 1 4π 2

ZZ

T

2

|(p ǫ f 2 )(ζ ) − (p ǫ f 2 )(ζ )| 2

|ζ − ζ | 2 |dζ | |dζ |.

Let

Γ := {(ζ, ζ ) ∈ T 2 : |f (ζ )| ≤ |f (ζ)|}.

Then, by symmetry, D(p ǫ f ) = 2 1

2 Z Z

Γ

|(p ǫ f)(ζ) − (p ǫ f )(ζ )| 2

|ζ − ζ | 2 |dζ | |dζ|.

Now, for all ζ, ζ ∈ T, we have

|(p ǫ f 2 )(ζ) − (p ǫ f 2 )(ζ )| 2

= |p ǫ (ζ)(f 2 (ζ) − f 2 )) + f 2 )(p ǫ (ζ) − p ǫ (ζ ))| 2

≤ 2|p ǫ (ζ)| 2 |f 2 (ζ) − f 2 )| 2 + 2|f 2 )| 2 |p ǫ (ζ ) − p ǫ (ζ )| 2 .

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Hence ZZ

Γ

|(p ǫ f 2 )(ζ) − (p ǫ f 2 )(ζ )| 2

|ζ − ζ | 2 |dζ | |dζ| ≤ 2A ǫ + 2B ǫ , where

A ǫ :=

Z Z

Γ

|p ǫ (ζ)| 2 |f 2 (ζ) − f 2 )| 2

|ζ − ζ | 2 |dζ | |dζ|

and

B ǫ :=

ZZ

Γ

|f 2 )| 2 |p ǫ (ζ ) − p ǫ )| 2

|ζ − ζ | 2 |dζ | |dζ|.

We estimate A ǫ directly as follows:

A ǫ = e −2M

ǫ

Z Z

Γ

|f(ζ) + f (ζ )| 2 (|f(ζ)| + ǫ) 2

|f(ζ) − f(ζ )| 2

|ζ − ζ | 2 |dζ | |dζ |

≤ 4e −2M

ǫ

ZZ

T

2

|f(ζ) − f (ζ )| 2

|ζ − ζ | 2 |dζ | |dζ|

≤ 4e −2M

ǫ

2 D(f).

Hence A ǫ → 0 as ǫ → 0 + .

To estimate B ǫ , we consider the outer function F ǫ such that

|F ǫ (ζ)| = |f (ζ)| + ǫ a.e. on T.

By Lemma 5, since |F ǫ | ∈ C 1+α (T), we have F ǫ ∈ Lip (1+α)/2 (T) ⊂ D(T) and there exists a positive constant D, depending only on |f|, such that D(F ǫ ) ≤ D for all ǫ ∈ (0, 1). We then have

B ǫ = ZZ

Γ

e −2M

ǫ

|f 2 )| 2 (|f(ζ)| + ǫ) 2 (|f (ζ )| + ǫ) 2

|1/p ǫ (ζ) − 1/p ǫ (ζ )| 2

|ζ − ζ | 2 |dζ | |dζ |

≤ e −2M

ǫ

Z Z

Γ

|F ǫ (ζ) − F ǫ (ζ )| 2

|ζ − ζ | 2 |dζ | |dζ |

≤ e −2M

ǫ

2 D(F ǫ ).

Thus B ǫ → 0 as ǫ → 0 + . This completes the proof of Theorem 2.

3. Proof of Theorem 3

To prove Theorem 3, we shall need the following additional lemma.

Lemma 6. Let f ∈ Lip β (T), where β > 1/2. Then, for η ∈ (0, 2β−1 ),

we have Z Z

T

2

|f (ζ) − f(ζ )| 2−2η

|ζ − ζ | 2 |dζ | |dζ | < +∞.

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Proof. Since β > 1/2(1 − η), we get Z Z

T

2

|f(ζ ) − f (ζ )| 2−2η

|ζ − ζ | 2 |dζ | |dζ| . Z Z

T

2

|dζ | |dζ|

|ζ − ζ | 2(1−(1−η)β) < ∞.

Note that here, and in what follows, we write A . B to mean that there is an absolute constant C such that A ≤ CB.

Proof of Theorem 3. By [12], it suffices to prove that [f] N is 2-invariant, which is equivalent to proving that f ∈ [Sf ] N .

Let ǫ, γ > 0, where γ will be taken small. Let E be a closed subset of Z (f) such that |E| = 0 and E / ∈ (C). Let p ǫ be the outer function satisfying

|p ǫ (ζ)| = e −M

ǫ

(d(ζ, E) γ + ǫ) 1/2 a.e. on T, where the constant M ǫ is chosen so that p ǫ (0) = 1. Thus

M ǫ := 1 2

Z

T

log 1

d(ζ, E ) γ + ǫ |dζ |

2π ,

and since E / ∈ (C), it follows that M ǫ → ∞ as ǫ → 0 + . By Lemma 4, it suffices to prove that

ǫ→0 lim

+

kp ǫ f k D(T) = 0.

Now

kp ǫ fk 2 D(T) = kp ǫ f k 2 L

2

(T) + D(p ǫ f).

For the first term, we have

kp ǫ fk 2 L

2

(T) . e −2M

ǫ

Z

T

d(ζ, E) d(ζ, E) γ |dζ |.

Thus kp ǫ f k L

2

(T) → 0 as ǫ → 0 + , provided that γ < 2β.

For the second term we again use Douglas’ formula, namely D(p ǫ f ) = 1

2 ZZ

T

2

|(p ǫ f)(ζ) − (p ǫ f )(ζ )| 2

|ζ − ζ | 2 |dζ | |dζ|.

Let

Γ := {(ζ, ζ ) ∈ T 2 : d(ζ , E) ≤ d(ζ, E)}.

Arguing as in the proof of Theorem 2, we have D(p ǫ f ) .

ZZ

Γ

|p ǫ (ζ)| 2 |f(ζ) − f(ζ )| 2

|ζ − ζ | 2 |dζ ||dζ | +

Z Z

Γ

|f(ζ )| 2 |p(ζ) − p(ζ )| 2

|ζ − ζ | 2 |dζ||dζ |

= A ǫ + B ǫ , say.

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To estimate A ǫ , let η ∈ (0, (2β − 1)/(2β)) and let γ < 2βη. Then A ǫ = e −2M

ǫ

ZZ

Γ

|f (ζ) − f (ζ )| d(ζ, E) γ + ǫ

|f(ζ) − f (ζ )| 2−2η

|ζ − ζ | 2

|dζ| |dζ |

≤ 2Ce −2M

ǫ

Z Z

T

2

d(ζ, E) 2βη d(ζ, E) γ

|f (ζ) − f (ζ )| 2−2η

|ζ − ζ | 2

|dζ| |dζ |

≤ 2C −2M

ǫ

Z Z

T

2

|f(ζ) − f(ζ )| 2−2η

|ζ − ζ | 2 |dζ| |dζ |,

where C depends only on f , and the double integral is finite, thanks to Lemma 6. Hence A ǫ → 0 as ǫ → 0 + .

To estimate B ǫ , we introduce the outer function F ǫ satisfying

|F ǫ (ζ)| = d(ζ, E) γ + ǫ a.e. on T.

By the Carleson–Richter–Sundberg formula [6, Theorem 7.4.2], we have

D ζ (F ǫ ) = Z

T

|F ǫ (ζ)| 2 − |F ǫ (ζ )| 2 − 2|F ǫ (ζ )| log |F ǫ (ζ)/F ǫ (ζ )|

|ζ − ζ | 2

|dζ | 2π . Therefore

B ǫ . e −2M

ǫ

ZZ

Γ

d(ζ , E)

(d(ζ, E ) γ + ǫ)(d(ζ , E) γ + ǫ)

|F ǫ (ζ) − F ǫ (ζ )| 2

|ζ − ζ | 2 |dζ | |dζ | . e −2M

ǫ

ZZ

T

2

|F ǫ (ζ) − F ǫ (ζ )| 2

|ζ − ζ | 2 d(ζ , E) 2(β−γ) |dζ | |dζ | . e −2M

ǫ

Z

T

D ζ (F ǫ )d(ζ, E) 2(β−γ) |dζ | . e −2M

ǫ

ZZ

T

2

|F ǫ (ζ)| 2 − |F ǫ )| 2 − 2|F ǫ )| log |F ǫ (ζ)/F ǫ )|

|ζ − ζ | 2

×

d(ζ, E ) 2(β−γ) + d(ζ , E) 2(β−γ)

|dζ | |dζ |.

Exchanging the roles of ζ and ζ , and taking the average, we obtain B ǫ . e −2M

ǫ

ZZ

T

2

(|F ǫ (ζ)| 2 − |F ǫ (ζ )| 2 ) log |F ǫ (ζ)/F ǫ (ζ )|

|ζ − ζ | 2

×

d(ζ, E) 2(β−γ) + d(ζ , E) 2(β−γ)

|dζ| |dζ |.

Thus

B ǫ . e −2M

ǫ

Z Z

T

2

δ γ − δ ′γ

|ζ − ζ | 2 log δ γ + ǫ δ ′γ + ǫ

2(β−γ) + δ ′2(β−γ) ) |dζ | |dζ |,

(3.1)

where δ := d(ζ, E) and δ := d(ζ , E).

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Let (I j ) be the connected components of T \ E, and set N E (t) := 2 X

j

1 {|I

j

|>2t} , 0 < t < 1.

Then, for every measurable function Ω : [0, π] → R + , we have Z

T

Ω(d(ζ, E)) |dζ| = Z π

0

Ω(t)N E (t) dt.

Using similar ideas to those in [4, 5], we obtain

J :=

Z Z

T

2

δ γ − δ ′γ

|ζ − ζ | 2 log δ γ + ǫ δ ′γ + ǫ

2(β−γ) + δ ′2(β−γ) ) |dζ| |dζ |

. Z π

0

Z π 0

((s + t) γ − t γ )

s 2 log (s + t) γ + ǫ t γ + ǫ

(t + s) 2(β−γ) N E (t) ds dt

. Z π

0

Z t 0

((s + t) γ − t γ ) log[(s + t) γ /t γ ]

s 2 (t + s) 2(β−γ) N E (t) ds dt +

Z π 0

Z π t

((s + t) γ − t γ )

s 2 log[1/(t γ + ǫ)](t + s) 2(β−γ) ds N E (t)dt

= J 1 + J 2 , where

J 1 . Z π

0

t 2β−γ−1 Z 1

0

((1 + x) γ − 1)

x 2 log(1 + x) dx N E (t) dt .

Z π 0

t 2β−γ−1 N E (t) dt = O(1),

and

J 2 . Z π

0

t 2β−γ−1 log[1/(t γ + ǫ)]

Z π/t 1

(1 + x) γ − 1)

s 2 (1 + x) 2(β−γ) dx N E (t)dt .

Z π 0

log[1/(t γ + ǫ)]N E (t) dt

. Z

T

| log(d(ζ, E) γ + ǫ)| |dζ | = 2M ǫ .

Thus J = O (M ǫ ). Combining this with the estimate (3.1), we get B ǫ . M ǫ e −2M

ǫ

.

Hence B ǫ → 0 as ǫ → 0 + . This completes the proof of Theorem 3.

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4. Concluding remarks

1. In order to produce cyclic functions for D(T) using Theorem 3, we need to construct closed subsets E ⊂ T such that E / ∈ (C) and c(E ) = 0. An easy example can be given by countable sets. Indeed, taking E β := {e i/(log n)

β

: n ≥ 2} with β ≤ 1 provides such an example.

Using Cantor-type sets, it is also possible to construct perfect sets E such that E / ∈ (C) and c(E) = 0.

2. One can consider weighted harmonic Dirichlet spaces instead of the classical harmonic Dirichlet space. More precisely, given α ∈ [0, 1), the weighted harmonic Dirichlet space D α (T) is the space of functions f ∈ L 2 (T) such that

kf k 2 D

α

(T) := X

n∈Z

| f b (n)| 2 (1 + |n|) 1−α < ∞.

We define the α-capacity of a Borel subset E ⊂ T by c α (E) = 1/ inf{I α (µ) : µ ∈ P(E)},

where P (E) is the set of all probability measures supported on a com- pact subset of E and I α (µ) := P

n≥1 | b µ(n)| 2 /n 1−α is the α-energy of µ.

We say that a property holds c α -quasi-everywhere if it holds everywhere outside a set of c α -capacity zero.

It is well known that Lip β (T) ⊂ D α (T) if and only β > (1 − α)/2.

Theorem 3 may be extended to show that, if f ∈ Lip β (T), where β ∈ ((1 − α)/2, 1], and if Z (f) ∈ / (C), then

[f ] N = {g ∈ D(T) : g| Z(f ) = 0 c α -quasi-everywhere}.

3. One can equally well consider the holomorphic Dirichlet space, namely D := {f ∈ D(T) : f(n) = 0 (n < b 0)}. Here too the problem of characterizing the cyclic functions is still open. For more on this topic, see e.g. [6, Chapter 9].

Acknowledgement

Part of the research for this article was carried out while the authors were visiting the University of Bordeaux to participate at the Confer- ence on Harmonic Analysis, Function Theory, Operator Theory and Applications in honor of Jean Esterle. The authors thank the Institut de Mathmatiques de Bordeaux for its support and hospitality.

References

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Canad. J. Math. 48 (1996), no. 2, 225–243.

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[2] J. E. Brennan, Approximation in the mean by polynomials on non-Carath´eo- dory domains, Ark. Mat. 15 (1977), no. 1, 117–168.

[3] J. Douglas, Solution of the problem of Plateau, Trans. Amer. Math. Soc. 33 (1931), no. 1, 263–321.

[4] O. El-Fallah, K. Kellay, T. Ransford, On the Brown–Shields conjecture for cyclicity in the Dirichlet space, Adv. Math. 222 (2009), no. 6, 2196–2214.

[5] O. El-Fallah, K. Kellay, T. Ransford, Cantor sets and cyclicity in weighted Dirichlet spaces, J. Math. Anal. Appl. 372 (2010), no. 2, 565–573.

[6] O. El-Fallah, K. Kellay, J. Mashreghi, T. Ransford, A Primer on the Dirichlet Space, Cambridge University Press, Cambridge, 2014.

[7] N. G. Makarov, Invariant subspaces of the space C

, Mat. Sb. (N.S.) 119(161) (1982), no. 1, 1–31, 160.

[8] N. G. Makarov, Sets of simple invariance. Investigations on linear operators and the theory of functions, X, Zap. Nauchn. Sem. Leningrad. Otdel. Mat.

Inst. Steklov. (LOMI) 107 (1982), 104–135, 230.

[9] N. G. Makarov, Sets of 1-invariance and 1-invariant subspaces (smooth func- tions), Dokl. Akad. Nauk SSSR 262 (1982), no. 5, 1072–1075.

[10] N. K. Nikolskii, Treatise on the Shift Operator, Springer, Berlin, 1986.

[11] N. K. Nikolski. Operators, Functions, and Systems: An Easy Reading, Vol. 1:

Hardy, Hankel, and Toeplitz, Amer. Math. Soc., Providence RI, 2002.

[12] S. Richter, W. Ross, C. Sundberg, Hyperinvariant subspaces of the harmonic Dirichlet space, J. Reine Angew. Math. 448 (1994), 1–26.

[13] W. Ross, Invariant subspaces of the harmonic Dirichlet space with large co- dimension, Proc. Amer. Math. Soc. 124 (1996), no. 6, 1841–1846.

LAMA, UMR CNRS 8050. Universit´ e Paris–Est, 5 boulevard Descartes, Champs–sur–Marne, 77454 Marne–la–Vall´ ee cedex 2, France

E-mail address : [email protected]

Laboratoire Analyse et Applications URAC/03, Mohammed V Uni- versity in Rabat, B.P. 1014 Rabat, Morocco

E-mail address : [email protected]

IMB, Universit´ e de Bordeaux, 351 cours de la Lib´ eration, 33405 Talence, France

E-mail address : [email protected]

D´ epartement de math´ ematiques et de statistique, Universit´ e Laval, 1045 avenue de la M´ edecine, Qu´ ebec (QC), Canada G1V 0A6

E-mail address : [email protected]

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