A NNALES DE L ’I. H. P., SECTION B
M. C RANSTON
Y. LE J AN
On the noncoalescence of a two point brownian motion reflecting on a circle
Annales de l’I. H. P., section B, tome 25, n
o2 (1989), p. 99-107
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On the noncoalescence of
atwo point Brownian
motion reflecting
on acircle (*)
M. CRANSTON
Y. LE JAN University of Rochester
C.N.R.S., Paris
Vol. 25, n° 2, 1989, p. 99-107. Probabidites et Statistiques
ABSTRACT. - We consider two
particles
drivenby
the same Brownianmotion while in the interior of the unit disc in the
complex plane
andnormally reflecting
off theboundary.
We show that withprobability
onethe
particles
do not meet in finite timethough
the distance between them decreases to zero.They
also do not meet almostsurely
whenmoving
inthe exterior of the disc with normal reflection off the
boundary.
Key words : Skorohod equation, noncoalescence.
RESUME. - On considère deux
particules
soumises au même mouvementbrownien et reflechies sur un cercle.
Lorsque
lesparticules
sont a l’intérieur ducercle,
leur distance mutuelle tend vers 0 mais les deuxparticules
ne serejoignent
pas entemps
fini.It is well known
(see,
forexample,
McKeans’book[2])
that one mayconstruct a
strong
solution to the Skorohodequation
onClassification A.M.S. : 60 J 65, 60 H 10.
(*) This research partially supported by N. S. F. grant D.M.S. 8701629.
Annales de l’Institut Henri Poincaré - Probabilités et Statistiques - 0294-14,49. ,
Vol. 25/89/02/99/9/$2,90/ cU Gauthier-Villars :~ #’.~ ‘Y ~- - _ -_ - " . ,
100 M. CRANSTON AND Y. LE JAN
Here
Bt
is Brownian motion on~2,
cpt anincreasing
processincreasing only
whenXt
is on aD(the
localtime). Actually
it has been shownby
Tanaka
[3]
and Lions-Sznitman[1],
one can construct apath-by-path
solution to this
equation.
Let xl, x2 be two different
points
inD,
andxi, X~
the associatedpath- by-path
solutions of(1)
withXb = Xi’ i = l, 2.
Let~pl
andcp2
be theassociated local times.
The processes
Xi
andXt
are drivenby
the same Brownian motion whilethey
are both interior to D. Inparticular,
the distance betweenxi
and
Xt
remains constant when neither ofcpt
andcpr
arecharging.
If oneconsiders such a two
point
process on a one dimensional interval or asquare, one will see that the two
points
will meet and coalesce after afinite amount of time. In a Ph. D. thesis
by Weerasinghe,
it was shownthat the distance
( I/2
goes to zero at leastexponentially
fastbut whether the
points
meet in a finite time was left unanswered.This
question
has been raisedby
StevenOrey.
The answer is thatT = inf ~ t > O : zt = 0 ~
is a. s. infinite. We also consider the behaviorof zt
when
xi
andX;
arereflecting
in the exterior of D.1. The interior
problem
The
proof begins by reducing
the number of dimensions as follows. Set andfor t ,
.Let j = i1
where for(x, y)
Ef~2, (x, y)1= (y, - x).
Notice then thatXt
= mt + ztit, X t
= mt - ztit.
Finally
define xt=
mt, cpt + Then the equa-tions for
dzt, dxt
anddyt
areeasily computed.
Since
Annales de l’Institut Henri Poincaré - Probabilités et Statistiques
Indeed, yt~0
ifX2t~~D
and ifX/ e OD
since(
mt, it~=1 2zt[~ Xf ~2 - ] ] X/ ~2]. Thus,
when zt>0,
’
.
since )) ( =1, d~~
isparallel
Observe thatand on
taking
the innerproduct with jr
Thus and
consequently djt = it
Vol. 25, n° 2-1989.
102 M. CRANSTON AND Y. LE JAN
Lastly,
In the
expressions
fordxt
anddyt, dWt
anddW;
are the differentials ofindependent
Brownian motions.The
asymptotic growth
of thecpr, i =1, 2
is well-known. Ingeneral
it isdetermined
by solving
the Neumannproblem
AM === 1 inD,
= c onaD,
’ andnoticing
that Green’s formula forces the choiceof c = - Ito’s formula for i =1 or
2,
~
(aD)
on
dividing by
t,sending t
toinfinity
andsumming
onf,
,. q).
cr(3D) _ ,
...r2
= 201420142014. In the
present
case u(r, 8)
= 2014.t -.00 t
m (D)
4We wish to observe that the formula for
dz~ implies
~=~-d/2)pj~__ B ~ ~ o ~~ for tT. Thus and
together
with the above mentionedasymptotics
for z~ tends to zero at leastexponentially fast,
which was realizedby Weerasinghe.
The process
~
=(Xt,
~,z,)
is areflecting
diffusion inL={(x, y, z):z~0, x2+(|y| +z)2~1}.
In the interior of is a two-dimensional Brownian motion in the first two
components
while the third z~component
is frozenuntil ~
hits ~ when z~again
decreases.Annales dc l’Institut Henri Poincaré - Probabilités et Statistiques
Introduce the notations
Nt = xt + {yt + 1 )2,
andfor t T.
LEMMA 1. -
On ~ T oo ~, inf ut is
almostsurely finite.
tT
Proof. -
First observeu (x, y)
is harmonic on the horizontal(z = c)
sections of L so the second order terms in the Ito
expansion
fordut
vanish.For
tToo,
we havewhere
Mt
is alocally
squareintegrable
continuous localmartingale.
Hence,
Note
that - - -
=4 Y~ .
ThereforeLt Nt L,N,
The coefficient of the first
dcpt
term ispositive.
While the coefficient of the seconddqB
term is notnecessarily positive,
it does hold thatsince
x2t and x2t are bounded by
one. SinceNt L, m (D)
can
only
occur in the case T~ when infMt=-
oo.tT
The last can
only
occur when supM~
=00.However,
tT
and the bounded variation term in the Ito
expansion
is bounded belowVol. 25, n° 2-1989.
104 M. CRANSTON AND Y. LE JAN
This makes sup
Mt
=00impossible
and so ThistT tT
proves the Lemma..
THEOREM 1. - The time T = 00 a. s.
Proof. -
OnT 00,
andcomputing
the sto-Zt B Zt /
chastic differential for
log (zf Lt Nt)
one has .2dzt
tZt
with the same
dMt
as in theprevious
Lemma.However,
where we have used the fact that
xr + ( ~ yt I + zt)2 =1
on the set of timescharged by dcpt. Thus,
..By
Lemma1,
when oo there is a such thatfor all This
implies
the existence of another constantci (m)
such that for
again
when Then fortToo,
Now T 00
holding
on a set ofpositive probability
wouldby
Lemma 1imply MT _ - -
oo which isimpossible..
Annales de I’Institut Henri Poincaré - Probabilités et Statistiques
2. The exterior
problem
Now the two
particles satisfy
the Skorohodequation dXit
=dBt
+X
i=l,2
As before andT = in f
{
t > 0: Zt =O. }
S et mt=X1t +X2t 2
an d f or tT, it X1t-X1t 2zt
,Jt ..l. =
It ,T=inf { t>0:zt=0}.
Set2 and
fort T, 1 2 _ zt , jt=i|t,
and cpt =
cpt
+cpt .
Then~t
= Yt,zt)
is a diffu-sion
z) : z >_ 0, x2
+( I y ~ - z)Z >_ 1 ~.
The stochasticequations
of motion are
with
dW2t
the increments oforthogonal
standard Brownian motions.Also,
z, =e~1~2~ ~t
/ B ~o - - ~ . i
ie-~1~2~
~sholds
for t T.Now set
Lt = aCt -~- ~Yt -1)2, Nt = xt ~- ~Yt ’~’ 1)2,
For
zt > 2
neitherLt
norNt
will be zero since this musthappen
outsidethe
support
ofdcpt
and the motion(xt, Yt)
is a Brownian motion there which will not hit thepoints (0, 1)
or(0, 2014 1).
To avoid apossible problem
at
(x, y, ~)=(0, 1, 2)
or(0, -1, 2)
introduce fory - 4
fixed thestopping
time
Then for
(xt, yt)
will remain in theregion
whereu (x, y)
isharmonic. Thus the second order terms in the
expansion
fordut
whenvanish.
LEMMA 1. - A T
00 },
inf ut is almostsurely finite.
Vol. 25, n° 2-1989.
106 M. CRANSTON AND Y. LE JAN
Proof -
For one hasConvergence
to minusinfinity
canonly
arise from the bounded variationterm. Given r > 0 as
above,
select swith ->~>0 y
E > 0 so that also 82 - r 8 I - s + 1- s .
We argue that ut can not converge to minusinfinity
in finite time before
Tr/2.
In theexpansion
fordut
the term(LtNt)-1 xf |yt| zt)
is ispositive positive
and therefore and therefore can can not not causecausesuch behavior.
Suppose
If the termis
positive
and noproblem
arises. If then on thesupport
ofI
yt|-zt|1, |yt| ztz0e(1/2)03C6t,
(LtNt)-1E-4
and so noexplosion
tominus
infinity
may occur in finite time for When eitherLt s2
orNt EZ
and we suppose the former holds.Thus so and
1- s yt 1 + s.
Inaddition,
(
holds on thesupport
ofdcpt
so either1 + E - i. e.
Zt is
small or 1-E+1- E zt 2 + E.
In thelatter case yt,
zj
iswithin - y
of(0, 1, 2) since r,
2 8
I yt -1 I E ~ 8
andI Zt - 21 r 8 by
the choice of s. This contradicts tTr~2
so Zt 1 + E -
/120148~
holds.Consequently,
and both thedcpt
coeffi-cients are
positive implying
no convergence to minusinfinity
before1
Next we prove the two
point
process in the exterior of the disc does not coalesce.THEOREM 2. - For the two
point
motionreflecting
in thecomplement of
the
disc,
T = 00 a. s.Annales de l’Institut Henri Poincaré - Probabilités et Statistiques
Proof. -
Notice that4 xt - Lt N~ = 4 xt - (xl
+yt
+1 ) 2
+ 4yt = - (xt
+yi -1 ) 2
and on the
support
ofdcpt
soConsequently,
4xr - Lt Nt - - zr (2 |yt I - zt)2.
This leads to, for tTr/2
AT,
By
the sameargument
as in theprevious
case we can conclude thata. s. define where 9 is the
shift
operator
andStarting
at~T1, apply
thestrong
Markovproperty
and the sameargument
to show T >
T2 = Tr~2 ~
Obviously zt
cannot hit zero on the interval[Tr~2, T 1]. Continuing
inthis manner on the various
pieces
of thepath,
T = oo a. s. follows..Most natural
questions
remain open in this area: Find a noncoalescence condition forgeneral piecewise
smooth domains. Determine what kind ofinstability
is createdby concavity.
Our work should be viewed as aninvitation to go further.
Remark. - There cannot exist a flow of
homeomorphism ~t
such thatwould be
equal
to xt a. s.Indeed,
anhomeomorphism
of D or ofD~
preserves theboundary
aD.REFERENCES
[1] R. F. ANDERSON and S. OREY, Small Random Perturbations of Dynamical Systems with Reflecting Boundary, Nagoya Math. J., 60, 1976, pp. 189-216.
[2] A. BENSOUSSAN and J. L. LIONS, Diffusion Processes in Bounded Domains... Probabilistic Methods in Differential Equations, Lecture Notes in Math., No 451, Springer, 1974,
pp. 8-25.
[3] H. Doss and P. PRIOURET, Support d’un processus de réflexion, Z.f.W., Vol. 61, 1982,
pp. 327-345.
[4] P. L. LIONS and S. A. SZNITMAN, Equations with Reflecting Boundary Conditions, C.P.A.M., vol. XXXVII, No. 4, July 1984, pp. 511-537.
[5] H. P. MCKEAN, Stochastic Integrals, Academic Press, New York, 1969.
[6] H. TANAKA, Stochastic Differential Equations with Reflecting Boundary Condition in
convex regions, Hiroshima Math. J., Vol. 9, 1979, pp. 163-177.
(Manuscrit reçu le 15 février 1988.)
Vol. 25, n° 2-1989.