A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
S. K AMIN
L. A. P ELETIER
Large time behaviour of solutions of the heat equation with absorption
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 12, n
o3 (1985), p. 393-408
<http://www.numdam.org/item?id=ASNSP_1985_4_12_3_393_0>
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Large
of the Heat Equation with Absorption.
S. KAMIN - L. A. PELETIER
1. - Introduction.
In this paper we consider the
large
time behaviour ofnonnegative
solu-tions of the
Cauchy
Problemin
which n ~ 1,
p >(n + 2)/n and
anonnegative
function in whichdecays
to zero asIxl
- oo at aprescribed
rate:where a and A are
positive
numbers.We shall also consider several
generalizations
of thisproblem.
In thefirst we allow the constant A in
(1.2)
to vary with theangle
co of the rayalong
whichIxl -
oo : A =A(w) (Theorem 2),
and in the second wemerely require
to beuniformly
bounded in R"(Theorem 3). Finally
in thethird
generalization
wereplace
theabsorption
term - upby
a moregeneral nonpositive
which hasprescribed
behaviour as(Theorem 4).
A number of results are
already
known about theasymptotic
behaviourof solutions of Problem I as t -~ oo
[4]:
(a)
If0 ce 2/(p -1 ),
thenPervenuto alla redazione il 28 Dicembre 1983 ed in forma definitiva il 25 Gen- naio 1985.
where )
uniformly
on sets of the form(b)
If a > n and p >(n + 2)/n,
thenfor some
nonnegative constant co
-whichdepends
on uuniformly
on setsIn
this paper we shall be concerned with the case a n.Assuming
inaddition
that p
>(n + 2)/n
and hence2/(p - 1)
n, we candistinguish
three cases:
(i)
I(ii) , (iii) .
In the absence of
absorption,
the solution w of theproblem
in
which 99
satisfies(1.2)
for some cx c-(0, n)
and A >0,
has theproperty
uniformly
on setsPa, a >
0. Herefo
is the solution of theproblem
in
Ixilti
andprimes
denote differentiation withrespect
to q.Property (1.3)
can beproved by
means of the Poissonintegral
formula orby
thescaling
methods used in this paper. Thus the solution converges to asimilarity
solution of the heatequation
which isuniquely
determinedby
the twoparameters
oc and A in(1.2).
In this paper we are interested in the effect of
absorption
on this behav-iour, and
inparticular
of a term of the form - uP in which p >(n + 2)/n.
We shall show that
(Theorems
1 and3):
1) I f 2/~p -1 )
a n, thenuniformly
on sets .Hence,
in this case, as t -~ oo, the effect of theabsorption
term vanishesand,
in view of(1.3): if 2/(p - 1)
a n, thenuniformly
on setsPa , a > 0.
Our second result concerns the intermediate case when a =
2/(p - 1 ),
in which-as it turns out-the effects of diffusion and
absorption just
balance.Specifically
we prove(Theorem 1) : II) I f a = 2/(p -1 ),
thenuniformly
on setsPa,
a >0,
wherefl satisfies
Thus,
in this case,u(x, t)
converges to asimilarity
solution of the full equa- tion(1.1)
which reflects the effects of both diffusion andabsorption.
We note that as a
by-product
of ouranalysis,
we prove the existence of solutionsf o
andf 1 of, respectively,
Problems III and IV.Finally,
for the first case, when a2/(p - 1)
and converges to zeroas - oo less fast than in the
previous
two cases, it has been shownby
Gmira and Veron
[4]
that it is the effect of the diffusion term which vanishes as t 2013~ oo.Specifically they
prove that in this casewhere c* =
(1/(p -1))1~~~°-1~ uniformly
on setsPa,
a > 0.Theorems 1-4 are
proved by
amethod,
first used in[5],
which consists inconsidering
thefamily
of solutions ER+}
ofproblems
obtained fromProblem I
by scaling
the variablesby
means of thesimilarity transformation
and
by studying
thebehaviour
of thefunctions u,
= u’ as k - 00.The same method may be used to
study
thelarge
time behaviour of solu- tions of theequation
in which m > 1. However this case
requires
different estimates. For thisreason we shall
present
it elsewhere.Equation (1.8)
with(1.2),
but without theabsorption
term has beendiscussed
by
Alikakos and Rostamian[1].
2. - Preliminaries.
Let R+ =
(0, oo),
and let for anyT > 0, ST = T].
Assume that p >
(n + 2)/n
andthat cp
E 0.DEFINITION. A solution u of Problem I on
[0, T]
is anonnegative
func-tion u E which satisfies the
identity
for
any C
E which vanishes forlarge Ixl
and at t = T.The existence and
uniqueness
of such a solution is well established[6].
By
means of standard interior estimates[2]
it can be shown that u EC2,1(8 T).
For any a e
[2/(p - 1), n)
we say that an initialfunction
has the prop-erty
.H’1 iffor
somepositive
constant A.Here,
the limit is understood in thefollowing
distributional sense: forf
We say
that cp
has theproperty
.IC2 if:f or
somepositive
constant BFor
k > 0,
we define thefamily
of functionst)
=k2t).
It follows
by
substitution that if u is a solution of Problem Ithen uk
is asolution of the
problem
in S in Rn
in which v =
oc(p 2013 1) 2013
2 and =REMARKS.
1)
Since a >2/(p - 1)~ ~ 0.
Inparticular,
if a =2/(p - 1),
then v = 0
and Uk
isagain
a solution ofequation (1.1).
2) If 99
has theproperty Hl,
then for any y ENote that the
singularity
at theorigin
in(2.2)
isintegrable
because a n.To
provide
bounds for thefunctions uk in S,
we shall use the solution Wof the
problem
in S
in
If
a n,
and hencew(., 0)
E the existence anduniqueness
of aclassical solution ~V’ is
ensured,
i.e. TP E02,1(8) t1 C(S§((0, 0)))
and sat-isfies
(V)
in the classical sense.Note that if
W (x, t)
is a solution of ProblemV,
then so is the functionk2 t)
for any k > 0.Hence,
since Problem V hasonly
onesolution,
for all ;
Thus if we set k2 t =
1, we
find that ~ can be written in the formSubstituting
thisexpression
into ProblemV,
we find thatf
is apositive
solution of the
equation
that
/’(0)
=0,
and that at any x ER-B{O},
or
Thus, f
is apositive
solution of Problem III with A = 1. It follows from theuniqueness
of W that Problem III canonly
have one solution.LEMMA 1.
Suppose
99 has theproperty
H2. Then there exists apositive
const,cant a such that
for
any k > 0PROOF. Since g~ E
LCO(RfI)
and 99 has theproperty H2,
there exists aconstant a > 0 such that
Hence
Set
z(x, t)
=k2 t -~-1 )
Then z is a solution of the heatequation
and
z(x, 0)
=Therefore, 1ny
theComparison Principle,
COROLLARY.
Suppose
99 hasproperty
H2. Then there exists apositive
con-stant M such that
for
all k > 0PROOF.
By
Lemma 1 and(2.3):
a
max I
where .~ = a max .
By
means of classical Bernsteintype arguments-see
for instance[6,
Lemma
4]-we
may conclude from(2.4)
that for each 1 > 0 there exists aconstant
Ci(i)
which does notdepend on k,
such thatBy [3]
thisimplies
the existence ofpositive
constants andð(1’),
whichdo not
depend
on keither,
such thatif
It
-tol 3(1). Thus,
we haveproved
thefollowing
lemma.LEMMA 2.
Suppose
99 has theproperty
H2. Thenfor
each z~ >0,
thefamily of functions t) :
k >0~
isuniformly, locally,
H61der continuous in withexponent
1 in xand 1
in t.3. - The main result.
Let
T >
0 and i E(0, T ),
and define the setsST
=B,
=~x f0153l C R)
andQ,(I)
=B,
X(1/1, T],
I= 1, 2,
....By
Lemma2,
and the theorem ofArzela-Ascoli,
there exists for each I > 1 asubsequence
and a function IT E such thatBy taking
adiagonal subsequence
we obtain a sequence~uk.~
and a functionrI E such that
for any
compact
subset .g of8p:
Note that
by
Lemma1,
for 0We shall show that ZT is a classical solution of the
problem
where 0=0 if
a > 2/(p - 1 )
and 0 = 1 if a =2/(p - 1).
We
begin
with two technicalauxiliary
results.PROPOSITION 1.
satisfies
.H’2. Then there exists a constanto E
R+,
which d oes notdepend
on k > 0 such thatPROOF.
By
Lemma1,
where denotes the area of
oBI, 8
= and s = t+
s.Since f
is asolution of Problem
III,
and hence 2013~ as q -~ 00,for some
positive
constant C*. Thuswhich
completes
theproof.
PROPOSITION 2.
Suppose
99satis f ies
H2. Then there existpositive
constants01
andO2,
which do notd ep end
onk,
such thatwhere y = n - cxp
+
2.PROOF.
Proceeding
as in theproof
ofProposition 1,
we obtainThe remainder of the
proof
consists of anelementary, but
involved compu- tation of an upper bound of theintegrals
on theright
hand side of(3.4).
We omit it here.
LEMMA 3. Let g~ have the
properties
HI and H2. Then U is a classical solutionof
Problem VI.PROOF.
By
the definitionof uk
we can write for any 7: E(0, T),
and any test-functionC,
Let s > 0 be
given. Then, by Propositions
1 and2,
there existpositive
numbers T and
ko
such that if k >ko,
thenand,
because Il ayYby
Lemma 1 andPropositions
1 and2,
By (3.1)
we have as 1~’ -omitting
theprimes,
yand
by
and(2.1),
Putting (3.5)-(3.9) together
we obtainSince s can be chosen
arbitrarily small,
it follows thatand
hence, because C
was anarbitary
testfunction,
~I is a weak solution of Problem VI in the sense of the definitiongiven
in section2,
with theonly
difference that in Problem
VI, Z7(x, 0)
EIn view of Lemma
2,
and the(locally)
uniform convergence of uk, to Uas k’-> oo in
ST,
for anycomplact
subset ..g’ ofST: Hence, by
standard interiorregularity results,
U C-C2~1(ST),
and thus satisfies theequation
in the classical sense.We shall now show that the entire sequence uk converges to This will follow from the
uniqueness
ofIT,
which will be established in the next lemma.LEMMA 4. Let ul and u2 be classical solutions
of
ProblemVI,
in whichwhich
satisfy (3.2) for
ThenUI = U2 in
PROOF. For 0 =
0,
Lemma 4 is well known.Thus,
we shallonly
considerthe case 0 = 1.
Let .R >
0,
andlet C
be any function in X(0, T])
which vanishes at t = T and onaBR
X(0, T]. Then u1
and U2satisfy
theidentity
whence v = UI - U2 satisfies the
identity
in which
Note that c is a smooth
positive function, which
is bounded in for any T E(0, T).
Let FE
Oc;(Sp),
and choosefor C
the solution of theproblem (3.10a)
(3.10b) (3.10e)
ln ..
on
on
Since c and F are smooth
functions,
y the existence anduniqueness of C
isensured.
Let C
be the solution of theequation
which satisfies
(3.10b
andc). Then,
becausec > 0,
it follows from the maximumprinciple
thatand hence that
Finally,
we let R - oo. It can be seen from the Poissonintegral
formulathat --~ 0.
Hence, because 1’01
is bounded forlarge lxi,
we obtainin the limit
Remembering
that .~" was anarbitrary
function inO;’(Sp)
and that v is con-tinuous in
Sp,
we conclude that v = U2 = 0 inSp.
LEMMA 5. Let q; have the
properties
.H’1 and H2. Thenuniformly
on everycompact
subsetof
where U is the(classical)
solutionof
Problem VI.
The
proof
isstandard,
and we omit it here.REMARK. If a =
2/(p - 1 ),
then ifZT (x, t)
is a solution of Problem V inS,
then so is the function
IT (kx, k2t)
for any k > 0.Hence,
if ~" isbounded for
large ~x~ and
t >0,
it follows from Lemma 4 thatTherefore,
ZT can be written in the formSubstituting
thisexpression
into ProblemVI,
we find thatf 1
is apositive
solution of the
equation
that
f’(0)
=0,
and that the initial condition(3.3b) implies
thatThus, fi
is apositive
solution of Problem IV. It follows from theuniqueness
of
P’y
that Problem IV canonly
have onepositive
solution.Having
determined the limit of the sequence as k --~- oo, and char- acterized the limit functionU,
we now turn to thedescription
of the be-haviour of the solution
u(x, t)
of Problem I as t 2013~ 00.We have
proved
thatuniformly
oncompact
subsets of R".Thus,
if we write kx = x’ and k2 =t’,
weobtain, omitting
theprimes again
uniformly
on setsPa,
a > 0.THEOREM 1.
Suppose
p >(n + 2)fn. Let
u be the solutionof
ProblemI,
in which 99 has the
properties
.H’1 andH2, and, 2/(p -1 )
a n. Thenuniformly
on setsPa,
a 20,
where is thepositive
solutionof
theproblem
in which 6 = 0
i f oc > 2 / ( p - 2 )
and 0=1if a = 2 / ( p - 1 ) .
REMARK. We
conjecture
thatby letting
A -* one can retrieve the fact thatwhere
uniformly
on setsPa,
a> 0proved
in[4].
4. - Generalizations.
Lemma 1 and Lemma
2,
whichyield
thecompactness
of the set arebased on
property
.g’2only.
Thisproperty
allowed us to bound uand Uk by a multiple
of W.Thus,
we mayexpect
that some convergence theorem still holds if we relax or even omit Hl.As a first
generalization,
we do not make thesymmetry-assumption
thatthe limit of as oo is the same
along
every ray.Hl* For every
fixed
=1,
in which 0
( ~ 0 ) .
Proceeding
asbefore,
we obtain:THEOREM 2.
Suppose
p >(n + 2)/n.
Let u be the solutionof
Problem Iin
which (p
has theproperties
H1 * andH2,
and2/(p - 1)
a n. Thenuni f ormty
on setsPa,
a >0,
whereh(~)
is apositive
solutionof
theproblem
in which 0 =
0 if
a >2/(p - 1)
and 9 =1 i f
a =2/(p - 1).
The existence and
uniqueness
of apositive
solution of Problem VII is ensuredby
theproof
of Theorem 2.EXAMPLE. Let n =
1, P
= 5 and a= 3 (= 2/(p - 1 ).
Then Problem I becomesSuppose
Then
(4.1) implies
thatwhere h satisfies
Note that the function
h(~)
is notsymmetric.
Fig.
1. - The functionh(~)
in theExample.
’
If we
only
assumeH2,
it is stillpossible
togive
some characterization of thelarge
time behaviour ofu(x, t)
if a >2/(p - 1).
THEOREM 3.
Suppose
p >(n + 2)/n.
Let u be the solutionof
Problem Iin
which 99
has theproperty H2,
and2/(p - 1)
oc n. Thenuniformly
on setsPa ,
a >0,
where w is the solutionof
theproblem
in S in R" .
PROOF. Define the functions
wk(x, t)
= k2t)
andThen,
for any T >0,
zk satisfies theintegral identity
Thanks to the
properties
of ux~ and Wk I there exists asubsequence
and a function Z E
C(ST)
suchthat zx,
-> Z as k--* oouniformly
on anycompact
subset ofST.
As in Lemma 3 we prove thatSince Z satisfies
(3.2)
it follows from Lemma 4 thatZ(x, t)
= 0 for all(x, t)
EST.
Thus the entire sequence z,. converges to Z = 0.The
proof
iscompleted
as in(3.11)
and(3.12).
Thus,
if a >2/(p - 1),
thelarge
time behaviour of the solution u of the nonlinearequation (1.1)
is up to ordero(t-a2)
the same as that of the solu- tion w of the muchsimpler
heatequation,
which can be determinedby
thePoisson
integral
formula.We conclude with a
generalization
of Theorems 1-3 for solutions of theproblem
in which 99 is as in Problem I and g a
nonnegative
OI-function. We find that ifg(., u)
behaves like uP near u = 0 and p >(n + 2)/n,
the threetheorems continue to hold. As an
example,
we formulate theanalogue
ofTheorem 1..
THEOREM 4. Let u be the solution
of
Problem VIII.Suppose for
someoc n,
(1 )
99satis f ies
Hl andH2;
(2)
There exists a constacnt ~, E{0, 1~
such thatuniformly
withrespect
to x Then the conclusionof
Theorem 1holds,
with 0 = Â.
Note added in
proof.
After this paper was submitted a paperby Galaktionov, Kurdjumov,
Samarskii [7]appeared,
which contains part of our results,proved,
however,by
different methods.REFERENCES
[1]
N. D. ALIKAKOS - R. ROSTAMIAN, On theuniformization of
the solutionof
the porousmedium
equation
in Rn,israel
J.Math.,
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B. H. GILDING, Höldercontinuity of
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(1976),
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Large
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the solutionsof
a semilinear para- bolicequation
in Rn, J. Diff.Equ.,
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Theasymptotic
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the solutionof
thefiltration equation,
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O. A. OLEINIK - S. N. KRUZHKOV,Quasilinear
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with many
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V. A. GALAKTIONOV - S. P. KURDJUMOV - A. A. SAMARSKII, Onasymptotic
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