A NNALI DELLA
S CUOLA N ORMALE S UPERIORE DI P ISA Classe di Scienze
L UIS A. C AFFARELLI G IANNI G ILARDI
Monotonicity of the free boundary in the two- dimensional dam problem
Annali della Scuola Normale Superiore di Pisa, Classe di Scienze 4
esérie, tome 7, n
o3 (1980), p. 523-537
<http://www.numdam.org/item?id=ASNSP_1980_4_7_3_523_0>
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Monotonicity Boundary
in the Two-Dimensional Dam Problem (*).
LUIS A. CAFFARELLI - GIANNI GILARDI
Introduction.
Two reservoirs
containing
water with different levels areseparated by
a porous dam D : the water
flowing
from the first reservoir to the other wets a subset S2 of D.The purpose of this work is to
study monotonicity properties
of theflow in the two-dimensional
stationary
case. Ourconclusion,
in itssimplest form,
is that the freeboundary
D n 2D is a monotonegraph provided
aDitself satisfies suitable
geometrical assumptions.
As
part
of ourproof
we obtain theresult,
which isinteresting by itself,
that the
now
istangential
to theboundary
of the dam atpoints
of theseepage line.
At last we show how our
technique
allows us to control the number ofmonotone arcs of the free
boundary
in the case of several reservoirs.It must be
pointed
out that ourmonotonicity assumptions
on aD arealways
naturalhypotheses
since in the formulation of theproblem
no new reservoirs are allowed to be formed. It would beinteresting
to state theproblem
in which water can form such reservoirs and showmonotonicity properties
of the freeboundary
also in this case.1. - Statement of the
problem.
Let a, b,
c, a,,bl ,
y,, y, be real numbers andYo, Yi
be two real func-tions
satisfying
thefollowing assumptions:
(*)
This work ispartially supported by
the G.N.A.F.A. and the Laboratorio di Analisi Numerica of the C.N.R.(Italy).
Pervenuto alla Redazione il 3 Settembre 1979.
We shall use the
following
notations:Filially v
will be the exterior normal unit vector to 2D.Consider
thefollowing problem:
PROBLEM 1. Find a
pair icp, p f satisfying
thefollowing
condi-tions (1.4)-(1.7) :
setting
Q =f (x, y)
E D: y99 (x)l,
A =D -
S2 and X = characteristicfunc-
tion
of Q,
finally,
pv = - cos vy onTN
and p, - cos vy onTo
n aQ in thefollowing
weak sense
(1) :
The
graph
of Q will be called freeboundary.
It is well known that this
problem
has onesolution,
that 99 isanalytic
where
Q(x) y’(x) and p
EC’,’(-D)
da E]o,1[ (see [1], [2]).
In this paper we prove
that Q
isstrictly decreasing
in[a, b]
and thatQ(x)
exists andQ’ (x)
==Y’(x)
atpoint
x E[e, b[ satisfying gg(x)
=Y(x) (i. e.
8Q and aD aretangential).
Results of this kind were known
only
in someparticular
cases for theshape
of D(see
e.g.[3], [5], [6].
Forcomplete
references aboutproblem
1see
[4]).
We recall some known results that will be useful later:
LEMMA 1.1. Let Q be an open subset
of
W.If
T ED,
eo >0, u
EC°(,S2
nB20o ) ( 2)
andJu > I in S2 n B,Lo(.7v-), u > 0 in 12 (-) B,,L)(,(.T), u =: 0
on8Q n
B2Qo (x)
then(1)
Clearly
(1.7) also contains theequation Ap
+ Xv = 0.(2) B,(y)
andR,(y)
arerespectively
the open and closed ball ofcenter y
andradius e.
PROOF. It is sufficient to prove
(1.8)
with so e Q r1B(}o(x)
since the con-stant
1/2n
in(1.8)
does notdepend
on x° . Considerxo E , n Bo(x)
ande Q,, and take
v(x)
=u(x)
-u(xo)
-(1 /2n) l0153
-X,,l 2.
If v - 0(1.8)
is ob-vious. Let us suppose
v # 0.
We have v ECO(tJ
r1B2(}o(x)), Av >- 0
in Q r1Be(0153o);
thus if yo is a maximumpoint
for v inQ
nB-,,(x,,)
we haveyo E
8(Q m Be(xo)).
Inparticular v(yo)
> 0 sincev(x,,)
= 0. If follows that yo EaB,(x(,)
since w 0 on 8Q r1Bg(x,,).
Thusv(yo)
=u(yo)
-u(x,,)
-(1-/2n)e2,
and from
v(yo)
> 0(1.8) clearly
follows. aLEMMA 1.2. With the notations
of problem 1,
let a,(3,
y E R be such thatIntroduce the set
.D
=]a, f1[
X]y, oo[
and thef unct2on (3)
Then
PROOF. If
VJ E Ð(D), V -> 0,
we deduceby (1.5), (1.7):
that is
ZI p
+Xy:>O
inD.
ThusDy(Llw - X) 0
inD.
But 4 w - X = 0in
f)BD.
Hence(1.11)
follows. ·We deduce now the
following
COROLLARY 1.1. Let
(xo, yo)
be such that cx,b,
yo =gg(x,,)
=Y(x,,)
(i.e. (xo, yo) belongs
to the seepageline).
Then
positive
constants (20’ co exist such that(3) We
extend p and v
to the whole of R2by: p
= 0and Z
= 0 inR2BD.
The function (1.10) has been introduced first in [3] to solve the dam
problem
in itssimplest
form and has been used later in many other cases(see
e.g.[5]).
PROOF.
By
theprevious lemmas,
if po is smallenough,
we have(setting Be
instead of
B,(x,,, y,,)):
But for some 6 E
]0, 1[ (4)
we haveHence,
from(1.13), (1.14):
from which
(1.12)
followswith co
=5/8. a
2. - Behavior of the free
boundary
at the seepage line.The aim of this section is to prove that 8Q and aD are
tangential
at theseepage
line;
i.e. atpoints Po
=(x, Y(x))
such that c cxb, Y(x)
=T(0153).
The basic idea is the
following:
the lineargrowth of p (given by
corol-lary 1.1)
in aneighborhood
of such apoint Po
ispossible only
if 3D and8D are
tangential
atPo.
Our
proof
usesproposition 2.1y
which we consider to be ofindepend-
ent interest and state in n-dimensions. In order not to
distinguish
be-tween n = 2 and n >
2,
we will use the definition ofcapacity
of a com-pact
subset .K of an open set .R c R" asgiven
in[7].
Here and later .R will be the half ballBi (5)
and thecapacity
of K withrespect
toBi
will besimply
denotedby
cap .K.We first need some lemmas.
LEMMA 2.1..F’or any n > 2 and e
E ]0, 2 [
there exists a constant?o(8)
suchthat
for
anyf unction
g, which is continuous acnd nonnegative in 13i
and super-harmonic in
Bi ,
thefollowing
estimate holds:PROOF. Let
G(x, y)
be the Green function ofB’ (which
could be com-puted explicitly
from the one ofBl by reflecting
thepole).
It is easy to see(4) eo, 6 depend
on(xo, yo)
and the geometry.(5)
With the notations:Be
=B,(O)
andBe
=Be
UR’
that for some constant
cl(E)
we haveLet .K be the set
Ix
EB+:
x.,, > e,g(x) >I I with g satisfying
theassumptions
of the
present lemma,
and consider thecapacitary
distribution px and thecapacitary potential Vx
of K. We haveFrom
(2.2)-(2.4)
and the definition of .g we deduceimmediately
But
g(y) > TTA(y)
inBi
since g is nonnegative
andsuperharmonic
inB:
and
g > 1
on K.Therefore
(2.1 )
follows withco(s)
=cl(e)..
REMARK 2.1. If n = 2 there are some relations between
capacity
andlength
of arcs. We will be interestedonly
in circular arcs and confine our-selves to the
proof
of thefollowing:
LEBIBIA 2.2. There exist constants c1, cz , Cl > 0 such that
for
anycompact
circular arc L contained inBt
andhaving radius ;>Ca
thefollowing inequality
holds
PROOF. Notice first that the Green function G of
Bi
satisfiessince,
for fixedx E Bi ,
the functiong(y)
=G(x, y)
+ In(llx
-yl)
is har-monic in
Bi
and 0 onaB+.
Consider now a
compact
circular arc .L contained inBi
and denoteby
a its
length
andby
C the circlecontaining
L. If z and R are the center and the radius ofC,
supposeR >- 4
and notice that the closed ball13 BI2(Z)
doesnot intersect
Bi .
It will be convenient to use thefollowing
notations:for x E
Bi
define x E Laccording to ix -.Tl
=min tlx - yl : Y
EZ};
more-over
for x, y
E L denoteby oc(x, y)
thelength
of the arc contained in L andhaving x, y
asendpoints.
We havefor x, y
EBi
Thus, choosing 6
> 0 such that t-1 arcsin t c 2 for 0t 6,
weget
.Fix now
y E Bi
and denoteby
L’ the arc contained in C andhaving length
2aand 9
asmidpoint. Choosing
c, = max{4; 2/61
anddenoting
by ds
the differential of arcalong C,
we have ifR:> CS :
for some constant
c2 > 0 (since clearly a 4,
forinstance). Therefore,
ifwe consider the uniform
distribution It
on L of total massc,lln (a/8)1-1,
we
get
Hence we conclude
From lemma 2.1 we deduce
immediately
LEMMA 2.3. For any n > 2 and E E
]0, ![
there exists a constante(E)
> 0 such thatfor
anyf unction
v which is continuous and subharmonic inBi
andsatisfies v(x) c xn,
thefollowing
estimate holdsPROOF.
Choosing g(y)
=e-’(y,,
-v(y))
andapplying
lemma 2.1 weget (2.7) with e(E) = ec,(E). a
Now we are able to prove the
following
basicproposition.
PROPOSITION 2.1. Let B E
]0, 2 [
and Co > 0 begi1jen
constants and Zc a con-tinuous
function in B1,
snbharmonic inB1, satisfying
Define
and suppose that
Then
PROOF. We will prove
(2.11) by a
recurrenceargument.
By hypotesis (2.8)
holds.Suppose, inductively,
that for fixedk_>O
Define
1’(X)
=Ckl’2k’u(x.-k)
inBi
andapply
lemma 2.2. Then(2.7)
holds with
c(s) independent
of k and we havei.e.
That is we can choose Ck+l ===
Ck(l - C(£)Ylc)’
Hence weget
But,
sinceln (I - t) - t,
we haveHence if
(2.10)
holds theproduct
in theright
side of(2.14)
tends to 0a s k 2013> oo.
This
completes
theproof.
.In order to
apply proposition
2.1 to our situation we need thefollowing
LEMMA 2.4. Let u be a real
functions
which is continuous in thehalf
ballT3+
of R,
subharmonic inBt,
andsatisfies
Then
for
some co > 0 we havePROOF. Define 6 = dist
(oR;; ?Bi
n suppu)
and if = suptu(x); x C-,&+I.
By (2.15) 6
> 0. Choose co =M/3.
On
aB1
r1 supp n wehave u M e,, x,,;
moreover u =0 e,, x,,,
elsewhereon
9BJ’.
Therefore(2.17)
follows fromsubharmonicity.
aWe now
apply
theprevious
results to our situation and prove the fol-lowing
THEOREM 2.1..Let
Po T (xo, yo)
be apoint of
the seepageline,
i.e. c x,,b,
yo
T(x,)
=Y(0153o).
ThenPROOF.
By contradiction,
suppose that(2.18)
does not hold. Then thereexist p
> 0 and a sequence{xm} satisfying
Notice that the
segments 8m
={0153m} X [q;(0153m), Y(x.)]
do not intersect S-).By
lemma1.2,
p is subharmonic in someneighbourhood
ofPo.
Since Yis
C2,
there exist > 0 andQo
E R2 such that the ball B =BR(Qo)
does notintersect D and is
tangential
to 2 D atPo.
Define the inversion withrespect
to aB
by
means ofand set
Define now the Kelvin transform of p :
It is well known that
subharmonicity
ispreserved
under this transformation.Changing
coordinates andunits,
we may assume thatPo
=0, Q
cD
cc B/ c Ri and
(2.23) p
is continuous inBi
and subharmonic inBi .
From lemma 2.4 we
get,
for someCo>0
In order to
apply proposition
2.1 to the functionp,
consider the circulararcs
8m
=F(S,,): denoting
their radiiby Rm,
notice thatRm > Oo
for someOa > 0.
Clearly
there exist sequences(on;)
andtkl
and a constant vo > 0 such that-,Moreover,
if £ E]0, 9 [
is smallenough
withrespect
to p, the arcsalso
satisfy
for some constant v > 0
(depending
on fl, E,vo). Therefore,
if we definewe have:
length Li >,,v.
But,
since the radius ofL,
isk1Rmj>(!o’Skr,
from lemma 2.2 we de- duce the existence of /!. > 0 such thatNow we can
apply proposition
2.1 to the functionp: recalling (2.23), (2.24)
and that
fi>O,
weonly
have toverify
that(2.10)
holds. Sinceclearly Lj
is contained in the set
{(x, Y) E Bt; y:> s, p(2-k1. x, 2-1d. Y) === o}
and capa-city
is anincreasing
setfunction, (2.10)
isgiven by (2.25).
Therefore we obtain
that is
which is
impossible by corollary
1.1.Thus we
get
a contradiction and theproof
iscomplete.
aREMARK 2.2. It must be
pointed
out that theprevious proof
does notrequire
themonotonicity assumption (1.3).
Hence the same result is still valid in much moregeneral
cases.It is sufficient to know that 8D is a smooth
graph,
D n 3D is also agraph
and p satisfies(in
someneighbourhood
ofPo
onC D)
ahomogeneous
Dirichlet
boundary
condition and theinequality
p,, - cos vy in thesense of
(1.17).
In
particular
we will use the resultgiven by proposition
2.1 also in thecase of several
reservoirs,
that will be studied in sect. 4.3. -
Monotonicity
of the freeboundary.
In this section we
study monotonicity properties
of the freeboundary.
We assume that
hypotheses
of sect. 1 are satisfied and provethat Q
isitself monotone on
[a, b].
We
begin
with two lemmas.LEMMA 3.1..Let
xo c- [e, b[ be
such thatrp(xo)
=Y’(xo).
Then cp cannot take at xo either a local maximum or a local minimum.PROOF.
Clearly,
from(1.3)
and theorem 2.1-. a In thefollowing u
will denote the function p + y.LEMMA 3.2.
Let y be ac
real number in[Y2’ yl]
and w anon-empty
con- nectedcomponent of
the set{(x, y): u(x, y)
>y} (resp. y).
Thenul-
cantake a local maximum
(resp. minimum) only
onr, (resp. T2).
PROOF. Consider the first case. Let
Qo c a)
be a local maximum forulw.
For some ball B with center at
Qo, {ij
containstJ
n B. ThusQo
is a localmaximum
for uli,.
It follows(by
maximum andHopf principles)
thatQo belongs
to 8Q but not to D u1-’N . By
Lemma 3.1Qo
cannotbelong
toTo ,
so
Qo
eFl
U[’2.
But onr2
we have u =y2 c y.
ThereforeQo E Tl.
The
proof
of the other case in similar.Now we are able to prove the main theorem:
THEOREM 3.1. The
function 9? is strictly decreasing
in[a, b].
PROOF. First we observe
that q
cannot be constant in any subinterval of[a, b].
Indeed, by contradiction,
suppose that D r1 8Q contains some horizontalsegment
S. We have on S: u is constant and u, = 0. Thusuniqueness
resultsabout the
Cauchy problem
for theLaplace equation imply
that is constantin
f2,
which isimpossible
since Yl > Y2.Therefore,
if cp is monotone then it isstrictly
monotone.Now we observe that
if 9?
were notmonotone,
it would take a local maximum at somepoint
of]a, b[, since q
is continuous andcp(b) :qJ(x) C cp(a).
Therefore it is sufficient to prove
that q
cannot take in]a, b[
any local maximum and we shall do itby
contradiction.Let x* E
]a, b[
be a local maximum for q. Consider thepoint
P* =(X*, y*) == (x*, qJ(x*)):
from Lemma 3.1 weget
P* E D.On the other
hand,
the continuousfunction T
on[a, x*]
takes its minimum in somepoint
x* E[a, x*]. Clearly
x* > a and y* =cp(x*) c y*.
ThusP* =- (x*,Y*)ED.
But
Hopf principle implies
that P*(resp. P* )
cannot be a local maximum(resp. minimum)
forul.,
because zlu = 0 in!2 and u, = 0 at P*(resp. P*);
so the open set
{(X,Y)E!2:U(X,y»y*} (resp. {(X,Y)E!J:U(X,y)y*})
cannot be
empty
and has P*(resp. P* )
as aboundary point.
We denote m*(resp. m*)
its(or
one ofits)
connectedcomponents
whoseboundary
con-ta,ins P*
(resp. P*)
and look for thepoint P (resp. P) where - (resp. ulwJ
takes its maximum
(resp. minimum).
By
Lemma 3.2 we haveP
E.t1
and .P Et2.
Hence we conclude that M*and
w*
must have a commonpoint Q.
Then w e have
u(Q)
y* andu(Q)
>y*,
whiley* y*.
Therefore weget
a contradiction and the theorem is
proved.
a4. - Generalizations.
We want to show how results about
monotonicity properties
could begeneralized
to morecomplicated
situations.It will be sufficient to deal with the case of three reservoirs
-Ri, .R2 , .R3
with levels Yl, Y2, Ya. Without loss of
generality
we will suppose y1>y,,.We shall use the
following
notations:TN
still is theimpervious part
of aD
(which
bounds D frombelow), Ti === oD n aRi
andTo
= aD --
(7"i
UF2
Ur3
UFN).
As in sect.1,
smoothenssproperties
of aD areassumed to be satisfied.
Monotonicity properties
of 8D(see (1.3))
aregeneralized
as follows:defining
y = min yi andy
= max Yi, , D r1(R
X]y, y[)
issupposed
to haveexactly
two connectedcomponents,
say D’ and D"(with
D’ betweenRl
and
.R2
and D" betweenR2
andR3). Moreover,
all connectedcomponents
of aDr)To
and aD" nTo
are assumed to be monotone arcs(more
pre-cisely Y’
0 or Y’> 0 on each of thesearcs). Denoting
the freeboundary by T’,
T contains1-’1
UF2
UF3, and, clearly,
we shall beonly
interested inmonotonicity properties
of the two connectedcomponents
of 1-’-(r1
Ur2
UF3)
which are
given by
T’= F r)(aD’-.r,)
and T"== Tn(oD"-T3).
9?, and CP2 will denote the functions whichrepresent
T" and .T’"respectively.
Under the
previous assumptions
we still haveq T i y (j === 1,2)
andthe result
given by
Theorem 2.1 holds in thepresent
case.Therefore,
ifPo
E T nho
then 7"and
aD aretangential
atPo ;
inparticular
r is astrictly
monotone
graph
in aneighbourhood
ofPo.
We can prove the
following
theorems:THEOREM 4.1.
If y == Yi and Y
== y2 ,991 is strictly decreasing. If y
Y2and y
== y3 , 9?, isstrictly decreasing.
PROOF. We consider
only
thecase y
= yland y
= Y2, since the othercase is
quite
similar.As in the
proof
of Theorem2.1,
it is sufficient to show that Q1(6)
cannottake any local maximum.
By contradiction,
let x* be a local maximum for 9?1 and define x*by : Tl(x*)
= min{CPl(X):
xx*l.
Asabove,
thepoints
P* =
(x*, qi(z*))
andP* _ (x*, cp1(x*))
are in D and the open sets{(.r, y)
EE D:
t1(s, y)
>991(x*)l
andi(x, y)
E D:u(x, y) CPl(0153*)}
have connected com-ponents
w* and m*respectively
such that P* E 8m* andP*
E8m* . Defining P
andP by: u(-P)
= maxlu(x, y): (x, y) e Co*l
andu(l!.) ===
- min
{u(x, y) : (x, y )
ECO* I
weget easily
thatP
EFl U 7"3
and P EF2
U13 .
Im any case it follows that m* n w* =F- 0 which is
impossible.
MTHEOREM 4.2.
If 9
= y1and y
= y3, either 9?, orT2 is strictly decreasing.
PROOF.
By
contradiction suppose that CPl and T2 are both non-monotone.We prove first that inf gi y2 .
By
contradiction suppose inf cpl > y2 . Asabove, considering
a local maximum of 99, weget
a contradiction.With similar
arguments
we obtain sup Q2 > y2. Define now x*and x* by cp?(x*)
= max Q2 andggl(x*)
= min Tl, and consider the setsf(x, y)
E Q:U(Xl y) > q;2(0153*)}
andt(x, y )
E S2:u(x, y) q;I(X*)}.
As in theprevious proofs
we conclude that their connected
components
m* and 0)* whose boundaries(6)
By
definition, T, is defined in an open interval.contain
(x*, Q,(x*))
and(x*, T,(x*)) respectively
must have a commonpoint.
Thus weget
a contradiction. nREMARK 4.1. Theorems 4.1 and 4.2 allow us to conclude that in any
case either cpl or Q2 is.
strictly
monotone.The
following
theorem describes theshape
of non-monotone arcs of the freeboundary.
In all cases the theorem can be
proved
with theprevious arguments.
THEOREM 4.3.
Suppose
that either Q1 or Q2 is non-monotone. Then we havei f y
= yland y
= y2 , CP2 has a maximum and no localminima ;
’if Y
= yland y
= Y3, eith,er qi has a minimum and no local maximaor ’Q2 has a maximum and no local
minima ; i f y
= Y2and y
= Y3’ Q1 lias a minimum and no local niaxima. s We concludeby showing
that in some cases one of the two arcs of the freeboundary
cannot be monotone.We have indeed:
THEOREM 4.4.
If either yl
-Y2|
orIY2
-Y31
is smallenough
withrespect
to yl - y3 then Q1 and Q2 cannot be both monotone.
PROOF. We consider for instance the case
y
= yl, since thecase
= Y2 isquite
similar.For fixed yo yl ,
take y2
= yo + s andY3 = YO + 6
where e and ð will beproperly
chosen in the interval[0,
y1-yo[.
Denoteby Q2(x;
s,ð)
thefunction which
represents
thecorresponding
second arc of the freeboundary.
Consider now the case c = 6 = 0. We have
Yo :f{J2(X; 0, 0) y,
andQ2,(x; 0, 0)
cannot be monotone withoutbeing
constant since itslimits,
as xapproaches
theend-points
of the interval whereQ2(x ; 0, 0)
isdefined,
areequal
to yo . ButQ2(x; 0, 0)
cannot be constantby uniqueness
results aboutthe
Cauchy problem
for theLaplace equation unless yo
= yl , while y1 > yo.Therefore
T2(X; 0, 0)
is not monotoneand, by
Theorem 4.3Q2(J2 (x; 0, 0)
has a maximum
point.
Denoting by y*
thecorresponding
maximumvalue,
we have yoy * y, -
But it is easy to see that the pressure in D increases as levels
increase,
thus Q also increases.
Therefore, CP2(X;
e,ð)
is anincreasing
function withrespect
to each of the variables e and 3. It followsthat, fore, ð
E[0, y* - yo[,
gg,(x;
e,ð)
can.not be monotone withrespect
to x.REFERENCES
[1] H. W. ALT, A
free boundary problem
associated with theflow of ground
water,Arch. Rational Mech. Anal., 64 (1977), pp. 111-126.
[2] H. W. ALT, The
fluid flow trhough
porous media.Regularity of
thefree surface.
Manuscripta
Math., 21 (1977), pp. 255-272.[3] C. BAIOCCHI, Su un
problema
difrontiera
libera connesso aquestioni
di idraulica,Ann. Mat. Pura
Appl.,
(4), 92 (1972), pp. 107-127.[4] C. BAIOCCHI - A. CAPELO,
Disequazioni
variazionali equasi variazionali. Appli-
cazioni a
problemi
difrontiera
libera: vol. 1, Problemi variazionali; vol. 2, Pro- blemiquasivariazionali, Pitagora
Editrice,Bologna,
1978.[5] C. BAIOCCHI - V. COMINCIOLI - E. MAGENES - G. A. POZZI, Free
boundary
pro- blems in thetheory of fluid flow through
porous media: existence anduniqueness
theorems, Ann. Mat. PuraAppl.,
(4), 97 (1973), pp. 1-82.[6] A. FRIEDMAN - R. JENSEN,
Convexity of
thefree boundary
in theStefan problem
and in the dam
problem,
Arch. Rational Mech. Anal., 67 (1977), pp. 1-24.[7] L. L. HELMS, Introduction to
potential theory, Wiley-Interscience,
New York, 1969.School of Mathematics
University
of MinnesotaMinneapolis
MN 55455Istituto di Matematica dell’Universith Strada Nuova 65
27100 Pavia