C OMPOSITIO M ATHEMATICA
L. E. D OR
T. S TARBIRD
Projections of L
ponto subspaces spanned by independent random variables
Compositio Mathematica, tome 39, n
o2 (1979), p. 141-175
<http://www.numdam.org/item?id=CM_1979__39_2_141_0>
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Article numérisé dans le cadre du programme Numérisation de documents anciens mathématiques
http://www.numdam.org/
PROJECTIONS
OF Lp
ONTO SUBSPACES SPANNED BY INDEPENDENT RANDOM VARIABLESL. E.
Dor1,3
and T.Starbird2
© 1979 Sijthoff & Noordhoff International Publishers - Alphen aan den Rijn
Printed in the Netherlands
Abstract
If the closed linear span of a sequence of
independent
randomvariables in
Lp,
1 :5 p m, isisomorphic
totp,
then it iscomplemented
in
Lp.
Somegeneralizations
tomartingale-difference
sequences arealso discussed.
Analytic
conditions aregiven
which determinewhether a
given
sequence inLp
isequivalent
to the usuallp-basis.
Itis shown that if a modular sequence space is
isomorphic
tolp,
then itis identical with
tp.
1. Introduction
This paper is
mainly
concerned withsubspaces
ofLp, 1:5 P 00,
which areisomorphic
toep
and arespanned
eitherby
a sequence ofindependent
random variables orby
amartingale-difference
sequence.One main result in this
respect
isTHEOREM A: Let
1:5 p -,
and let( fi)
be a sequenceof
in-dependent
random variables inLp. If
the closed linear span[fi] of (fi)
is
isomorphic
toiep,
then[fi]
iscomplemented
inLp (i.e.
there is abounded linear
projection from L,
onto[ f; ]).
’ The contribution of the first-named author was partly supported by the National Science Foundation grants number MSP 73-08715 and MCS 76-07459.
2 The contribution of the second-named author was partly supported by the National Science Foundation grant number MCS 77-04140.
3 Current address: Wayne State University, Detroit, Michigan 48202.
0010-437X/79/05/0141-35 $00.20/0
For
1 p -, p 4 2,
none of theassumptions
of Theorem A isredundant.
Namely,
there areuncomplemented subspaces
ofLp
which are
isomorphic to tp (see [21] for
the case of 2 p 00, and[1]
for
1 p
2the
case of 1 p3
was done earlier in[22]
based onthe results of
[23]). Also,
for1:5 P 00, p 0 2,
there are uncom-plemented subspaces
ofLp
which arespanned by
sequences ofsymmetric independent
random variables. For2 p -
such sub-spaces were constructed
by
H. P. Rosenthal[21,
p.284].
For 1 :5 P 2 and any p r2,
there is asubspace
E ofLp spanned by
a sequence ofindependent
random variables which isisomorphic to t, (see [ 111,
for
example)
and therefore can not becomplemented there,
since E*does not embed
isomorphically
inLp (see [11]).
It is an open
problem
whether everyisomorph of t,
inLi
iscomplemented
there.In our work on Theorem A we obtained several structural results for unconditional basic sequences in
Lp, 2 p
00, which are interes-ting
in their ownright,
and may be summarized as follows:THEOREM B: Let
(fi)
be a normalized unconditional basic sequence inLp, 2 p -.
Assume that( fi)
is notequivalent
to the usualfp-basis.
Then(i) for
each À > 1 and n E N there aredisjoint finite
setsAI,..., An of integers
and elements xl, ..., Xn with xi E[fi: j
EAi] for
i n, so that(xi,
in)
isA -equivalent
to the usualen -basis.
(ii) If,
inaddition, (f;)
is a modularbasis,
then[fi]
contains asubspace isomorphic
tof2.
Recall that a basic sequence
(zi)
in a Banach space is called amodular basis if there is a sequence of Orlicz functions
(4)i)
such that for all sequences(a;)
of scalarslî=l
aizi converges if andonly
if forsome t > 0
£if=i Oi(laillt)-. (Then
thecorrespondence Li=1
a;z; -(ai)
is anisomorphism
of[z,]
onto the modular sequence spaceé.;>;
see
[ 1 la]
section4.d,
forexample.)
Two sequences(yi), (zi)
in Banachspaces are said to be
À-équivalent
if for allfinitely
non-zerosequences
(api)
ofscalars,
Part
(i)
of Theorem B was obtainedindependently
of usby
W. B.Johnson,
B.Maurey,
G. Schechtman and L. Tzafriri[6],
in the moregeneral setting
of Banach latticessatisfying
a suitableconvexity
condition. Both our
proof
of(i)
and thatgiven
in[6]
show first that the conclusion of(i)
holds for some value of À > 1. The extension to all values of À > 1 follows then from Krivine’s theorem[10].
It follows in
particular
from Theorem B(ii)
that for2 p oo,
every modular basis for
lp
isequivalent
to the usual basis oflp.
Infact,
this result holds for all values of1 p
00: for 1 p 2 this followsby duality
from the case statedabove,
andfor p
= 1 and p = 2 this followsby
default from the fact that all unconditional basesin éi (respectively é2)
areequivalent.
This latter result fort,
wasproved by
J. Lindenstrauss and A.
Pelczynski [12]
as anapplication
of Gro-thendieck’s
inequality.
Forl2
it followseasily
from theparallelogram
law
(see
also Fact 2.4(iii) below).
The
uniqueness
of modular bases inlp
relates to theproof
ofTheorem A as follows: Let
(fui)
be a sequence of mean zero in-dependent
random variables normalized inLp, 1 ::5 P 00. By
atheorem of H. P. Rosenthal
[20] (fi)
is then a modular basis for[ f i ]
inLp (see
also[2]
for theidentically
distributedcase).
If[fil
is isomor-phic
tolp, (fui)
is thus forced to beequivalent
to the usual basis oflp.
The
equivalence
of a sequence(fi)
ofindependent
random variablesin
Lp
to the usuallp-basis
is characterized inanalytical
terms inProposition
3.5.(Basically
the condition is that a sufficientpercentage
of the norm of thefi’s
can be obtained ondisjoint sets.)
Theseanalytical
conditions are then used toproduce
aprojection
onto[fi].
This last
component
of theproof
can be extended to show that aweaker version of Theorem A holds for
martingale
differences: if( f i )
is a
martingale-difference
sequence inLp,
1 p 00, and if(fi)
isequivalent
to the usualép-basis,
then[fi]
iscomplemented
inLp.
Thisis the content of Theorem 5.1 below. In the first draft of this paper this result was
proved only
for2 p
00. Theproof
for 1p
2 is due to G. Schechtman. We thank Professor Schechtman for per- mission toreproduce
hisproof
here.We now describe in
greater
detail theorganization
of the paper.Section 2 contains notation and some known
preliminary
facts.Section 3 contains three characterizations of sequences in
Lp
whichare
equivalent
to the usuallp-basis.
Theorem 3.3 is identical withpart (i)
of Theorem B stated above. It islocal-isomorphic
incharacter,
andconcerns
2 p oo.
Apreliminary
result isProposition 3.1,
whichstates that for every
1 :f:-: p -,
any normalized unconditional basic sequence inLp
whose elements arepositive
functions isequivalent
tothe usual
fp-basis.
Our second characterization isanalytic
in charac-ter. We show in
Proposition
3.4 that for2poo
the normalized unconditional basic sequence( f i )
inLp
isequivalent
to the usual basisof
lp
if andonly if l’ 1 gi Il 2pl(p -2)
°° for every sequence(gi)
whichcan be obtained from
( fi ) by
an isometricautomorphism
ofLp (i.e. by
a
change
ofdensity).
We also list in thatproposition
thecorrespond- ing
condition for1 - p 2,
which is the existence ofdisjoint
setsEi
such thatinfi JEi !/)>0.
Thispart
follows from known results of W.B. Johnson and E. Odell
[7]
and of the first-named author[4]. Finally
in
Proposotion
3.5 we show that theanalytic
conditions inProposition
3.4 may be
weakened,
in both cases, if we assume that thefi
areindependent
random variables.In Section 4 we prove results on modular sequence spaces. In Theorem 4.2 we show that for
2 p -,
every modular basic sequence inep
isequivalent
to the usualtp-basis.
This resulttogether
with a result of W. B. Johnson and E. Odell
[7] implies part (ii)
of Theorem B. The formulation of our result asgiven
in Theorem B(ii)
was
pointed
out to usby
H. P. Rosenthal. As outlinedabove,
Theorem 4.2 and known resultsimply
that for1 - p
00,tp
has aunique
modular basis. This fact is stated asCorollary
4.3. As apreliminary
to Theorem 4.2 wepresent
inProposition
4.1 a charac-terization of the containment
t(,b,)
Çé,;>
between two modular spaces,in terms of a certain
parameter relating
each of the functionsOi
to thecorresponding
function03C8i.
Several results of thistype
with variousdegrees
ofgenerality
are available(see [25]
and[27]).
We found the formulation inProposition
4.1 somewhat more concise and moreconvenient for our
proofs.
In Section 5 we prove Theorem
A,
andpresent
thegeneralization
tothe case of
martingale-difference
sequences(Theorem S.l)
referred to earlier. We alsopresent
inProposition
5.2 a related result of A.Pelczynski
and H. P. Rosenthal[16].
The main reason forincluding
this result here is that it is not stated
explicitly
in[16].
Ourproof
ofthis result is different from that of
[16].
2. Notation and
preliminaries
We consider here the spaces
Lp
=Lp [o, 1 ],
1 pwhere [0,1] is
endowed with the
Lebesgue
measureA---> JAI
on theu-algebra 0
ofthe
Lebesgue
measurable sets.However,
the resultseasily
extend toLp
on anarbitrary probability
space. The scalar field is either R or C.q will denote the
conjugate exponent
of p,(Ilp
+Ilq
=1).
If @ is a
family
of measurablefunctions, sî(f)
will denote thesmallest
o--algebra
withrespect
to which allf
E fffi are measurable. If H is au-subalgebra
ofY, 6u
will denote the conditionalexpectation
operator
withrespect
to 4(defined by
therelationship f A 6uf
=f A f,
all
f
ELi,
A E-çl). 6u
is a contractiveprojection
in allLp,
1 p 00.A sequence
( fi )
inLi
is called amartingale-difference
sequence if forall m n,
6u Jn
=0,
wheredm
=H( fi, ... , fm)’
If P andQ
areexpressions denoting
real numbers andK > 0,
then PK Q
will beused to abbreviate the relation
P/K _ Q s
KP.We use standard Banach space notation as in
[ 11 ] .
Inparticular
fora set S in a Banach space,
[S]
denotes its closed linear span.[si]
abbreviates
[fxi,
iE N}].
Aprojection
means a bounded linearidempotent operator.
Two basic sequences(xi)
and(yi)
in someBanach spaces are called
K-equivalent (denoted (xi) K (yi ))
if for all n and all scalars a,,.. *,an,[]£1 aixdl JEl][En1 aiYi Il,
and are calledequivalent (denoted (Xi) ~ (yi»
ifthey
areK-equivalent
for someK 00. A basic sequence
(Xi)
is called K-unconditional if for all choices ofEi = :i-- 1, (xi ) 1£ (EiXi ). (Xi)
is called semi-normalized ifinf lxil
> 0 andsupdlxdl
oc.For easy
reference,
we assemble here several well-knownfacts,
which will be used later. The first three are easy to
verify.
Fact 2.4 isa standard consequence of Khinchine’s
inequalities
and underliesmany of the known results on the
isomorphic
structure ofLp.
Weinclude a
simple proof probably
known infolklore,
which is however hard to extract fromexisting
literature.FACT 2.1: Let X be a Banach space, and let
(Xi)
be a basic sequence inX, equivalent
to the usualtp-basis,
1 p s 00. Then[xi]
is com-plemented
in Xif
andonly if
there is a sequence(x*i)
ç X* such thatx*(x;)
=5ij for
alli, j,
and such that there is K 00satisfying IIY- C 1= 1 1 K(Li=I ladq)I/q for all n
and all(ai).
FACT 2.2: Let X be a Banach space, Y and E
subspaces of
X withE
finite-dimensional.
Then Y iscomplemented
in Xif
andonly if
Y + E is.
FACT 2.3: Let
1 p
00 and let(fi)
be a sequenceof
mean zeroindependent
random variables inLp.
Then( fi )
is an unconditional basic sequence inLp.
Let us recall that the Rademacher functions
(ri)
are defined asindependent, symmetric, f - 1, 11-valued
random variables on[0, 1].
Khinchine’s
inequalities
say that for all 0 p 00, there are 0Ap
::;Bp
00 such that for all n E N and all scalars ai,..., an,The
right-hand inequality
for 0 p 2(the
left-handinequality
for2 p
(0)
followsimmediately
from Hôlder’sinequality
and theorthonormality
of(ri)
inL2,
withBp
= 1(respectively Ap
=1).
For aproof
see[26],
forexample.
FACT 2.4: Let
(gui)
be a sequence inLp,
1 :5 p 00. Then(i) for
any n E NIf,
moreover,(gi)
isK-unconditional,
then(ii) for
any n E N(iii) for
any n E Nif
1S p s 2
thenand
if
2 p 00, thenPROOF:
(i)
follows frompointwise application
of(2.1)
to theright-
hand side of the
equality
which
is,
of course,justified by
theFubini-Tonelli
theorem.To prove
(ii),
note that since(gi)
isunconditional, Eni=1 ri (s )gdl 1f11i=1 gill
for all 0 s 51,
andconsequently,
Now,
in view of(ii), (iii)
will follow if we establish that: for 1 p s2,
while for
2 ::; p
00,Fix
2 p ~
Then the left-hand sideinequality
in(2.6)
followsfrom the
elementary inequality (1 lc= [a;[)’s(I?=i la;/2)1/2
i.e.applied pointwise
withai= gi(t)
and in-tegrated
over t. Theright-hand
sideinequality
is immediate from thetriangle inequality
inLp/2 applied
to the sum of the functionsIgll2,
...,Ign 12
ELp/2-
Now fix 1
p 2.
Theright-hand
side of(2.5) follows,
asbefore,
from the
inequality (Li=l la;/2)1/2(Li=1 la;/P)l/p.
The otherinequality
in
(2.5)
comes from thetriangle inequality,
this time inf2lp:
We mayassume that
(gi)
aresimple functions,
i.e. there is a measurablepartition E1, ..., Em
of[0,1]
and scalars(cii)
such that gi1=1 CijlEi,
i =
1, ...,
n.Putting bij
=1 cij IP 1 Ej we get:
which is the
required inequality.
Thetriangle inequality
wasapplied
here to the sums of the vectors yi, ..., ym in
t2/p,
where yj(b1j, b2j, ..., bnj).
REMARK: All the lower estimates in Fact 2.4 are due to W. Orlicz
[15].
Hisproof
in(i)
and(ii)
is identical with the onegiven
here andmay be used to show also the upper estimates in
(i)
and(ii),
whichwere not stated there.
The upper estimates in
(iii)
are due to Kadec[8].
FACT 2.5: Let
(xi)
and(yi)
be two minimal sequences in a Banach space X.If (xi)
isequivalent
to the usualtp-basis,
1 p 00, andif y î= /lXi
-yillq
00, then(yi)
is alsoequivalent
to the usualtp-basis.
Asequence
(zi)
is called minimalif
there arez*
in the dual such thatzr(Zj) = 5ij,
alli, j.
PROOF:
By assumption,
there are a, b > 0 such that for all m El N and all scalars a 1, ..., am we haveLet zi = yi - xi, i E N .
Omitting
a finite number of terms in the sequence if necessary, we may assume that(j , 1 Il Zi Ilq) Ilq = - c a.
Then
111,m=,
]a;zill
Ç£11
I1 ailp)llp(EM 1= 1 IlZillq)llq I11
1laiIP)"P,
and so(a - c)(1,n=l
1l ai I P) IlP ":¿l
1«iyi II Ç (b + C)( m
1I«i IP) 1/P
for all m andall scalars ai,..., am.
REMARK: This fact was first observed
by Gohberg
and Markus[5].
3.
Sequences equivalent
to the usual1,-basis
We
present
in this section three characterizations of sequences inLP equivalent
to the usuallp-basis.
These results will be used in the other sections of the paper. Theorem 3.3 is identical with TheoremB(i)
stated in the introduction.Fix 2 p 00. Two well-known results describe the fact that
Lp
hasa rather small
variety
ofsubspaces.
TheKadec-Pelczynski
Theorem[9]
says that asubspace
ofLp
either embedsisomorphically
inl2
or
contains
asubspace isomorphic
totp,
while theJohnson-Odell
Theorem[7]
says that everysubspace
ofLp
either embeds inlp
orcontains a
subspace isomorphic
tol2.
Our first characterization ofsequences
equivalent
to the usual basis oflp, given
in Theorem3.3, gives
a local version of the
dichotomy expressed
in the Johnson-Odell Theorem. Webegin
with apreliminary result,
which may be ofindependent
interest.PROPOSITION 3.1: Let
l:5:p 00,
and let(gi)
be a sequenceof positive functions
inLp,
K > 0.(i) If for
all choicesof
n E N and E,, ..., En = ± 1then we have
for
all n,(ii) If (gi)
is K-unconditional and normalized then(gi)
is(2KBp)2-
equivalent
to the usualtp-basis.
PROOF
(i):
The left-handinequality
in(3.2)
iseasily proved:
for allt,
so
To see the
right-hand inequality
in(3.2),
let first 1 :::; p _ 2. Thenby
Fact
2.4(iii),
we havewhich
implies (3.2).
Now let 2 p 00. We have
by (3.1)
and Fact 2.4(ii). Let À==2KBp
andE = It -, Y- ic=, gi (t) ,
A(¿i=l 1 gi (t)’) "’1.
The idea of theproof
now is that alarge part
of the time(namely
onE), llc=l gi
iscomparable
with(ici lgil2)’I’-,
sinceby (3.3)
these two functions arecomparable
on the average. But thenyc 1=1
gi is alsocomparable
with(2?=i IgiIP)"P
whichbrings
us to theextreme
right-hand
sideexpression
in(3.2).
In detail:by
the definition of Eby (3.3).
Therefore we have
Now for
any t F= E
we haveThe first
inequality
is Hôlder’sinequality
withexponents 1/(2 - q)
andplq (note
that2 - q + qlp = 1):
the other one comes from the definition of E.Transferring
sides we have on E:Putting things together
by (3.4) by (3.3), i.e.
completing
theproof
of(i).
(ii).
Let a 1, ..., an bescalars;
thenreplacing
gi in(3.2) by 1 ai Igi,
weobtain:
the
inequalities being justified by (3.2),
theunconditionality
of(gi),
thetriangle inequality
forscalars,
and(3.2), respectively.
REMARK: After the first version of this paper was
completed,
asimpler proof
ofProposition
3.1 wassuggested by
G. Schechtman.Here is a modification of his
proof
which alsoimproves
the constantin
(3.2)
from(2KBp)2
to(KBp)2/Q:
by
Hôlderby
Hôlder.Transferring
sides andraising
to the power2/(qp)
we obtain fromhere
We will find it more convenient to use
Proposition
3.1(i)
in thefollowing contrapositive
form:COROLLARY 3.2: Given 1:5 p 00 and 5 > 0 there is M =
M(p, 5)
such that
for
all n and all sequences gl, ..., gn = 0 inLp, if
then there is a choice
of signs
Ei _ :t1, (i n), for
whichWe are now
ready
for our first characterization.THEOREM 3.3
(see
also[6]):
Let 2 p 00, and let(fi)
be anormalized unconditional basic sequence in
Lp.
Then either(i) (fi)
isequivalent
to the usual basisof e,,
or else(ii)
there is k 2:: 1 such thatfor
any n E N there aredisjoint finite
sets
A1, ..., An of integers
and linear combinationshi = Yi Ai C for
which(h 1, ..., hn)
isk-equivalent
to the usual basisof t2.
These
possibilities
aremutually
exclusive.Moreover, by
Krivine’sTheorem
([ 10],
see also[ 17]),
we mayreplace
thephrase
"there isk - 1"in the statement
(ii) by
thephrase "for
all À > 1".PROOF: Assume that
(i)
fails. Fix aninteger
n and s >0,
and letin the notation of
Corollary
3.2. Since(i) fails,
we can, in view of Fact 2.4(iii)
find aninteger m
and scalars a 1, ..., am such thatwhere K is the
unconditionality
constant of(fj)
inLp.
Set r =p/2,
andfor j
=1, ...,
m,let g; _ ifil 2@ 8j
=/aj/2.
Then we haveby
Fact 2.4(ii) by (3.7),
i.e.To conclude the
proof
we shall need thefollowing simple
LEMMA: Let x and y be nonzero elements in a Banach space, and let
sequently
PROOF OF LEMMA:
PROOF OF THE
THEOREM,
concluded: LetClaim. For each k _ n it is
possible
tofind
apartition of
the set{l,
...,m}
into kdisjoint
setsA 1,
...,Ak
so thatif
we set Xk =LjEA f3jgj for
i =1,
...,k,
thenWe shall prove the claim
by
induction on k :5 n. Assume it holds for acertain value of k n, and let
Ai,
xi be as in the claim. We haveby (3.8),
so for some value of ik,
which we shall fix now,Now
by (3.6), Mlk 2: M(r, s/2n)
soby Corollary
3.2 there are subsets B and C =Ai B B
ofAi
such thati.e.
putting
we have y + z = x;, and
Ily - zli, (,6/2n)llxill,
Thusby
the Lemma wehave
which
by
the inductionhypothesis implies
thatflylflyl/, - ull, ::;
(k
+I)Sln.
A similar assertion holds for z. Thusreplacing Ai by
thetwo sets B and C
and x; by
y and z, we obtain theobjects postulated
in the claim for k + 1.Let
A1, ..., An by
as in claim for k = n,let Xi = Y-j,.Ai I3jgb
and letThen for any
positive b,, ..., bn,
Now let cj =
1/y;
forall j:5 m,
andlet hi = ljEA, c; f;.
Then for anyscalars a,, ..., àn we have
The first
inequality
holdsby
theunconditionality
of(fi)
and Fact 2.4(ii),
while the second one comes from(3.10). Similarly
we getWe have thus shown that statement
(ii)
of the Theorem holds with 03BBequal
toKBp,
where K is the unconditional constant of(fi)
inLp (recall
thatAp
=1).
The other assertions of the Theorem are clear.
The
proof
of Theorem 3.3 shows also thefollowing quantitative
version of it:
THEOREM 3.3*: Let
2 p -,
and let 1 - K 00. Thenfor
everyn EN there is 0 M 00 so that whenever
( f; )
is afinite
orinfinite
normalized basic sequence in
Lp
with unconditional constant_ K,
then eitherIlli a;f;]] S M(Yi ladP)l/p for
ail choicesof
scalars(ai),
or else there aredisjoint
setsAl, ..., An of
indices andfunctions hi
E[fj: j
EAi],
i =1, 2,...,
n, such that(hh h2,
...,hn)
isKBp-equivalent
to the usual basis
of fi.
In basis theoretic
terminology,
Theorem 3.3 says that every nor-malized unconditional basic sequence in
Lp, 2 p
00, which is notequivalent
to the usuallp-basis
has apermutation
in which the usualbasis of
l2
isblock-finitely represented (see [17]).
It is not knownwhether it is necessary to use a
permutation
in this statement.Namely,
thefollowing question
is open:PROBLEM 3.A: Let
2poo,
and let(fi)
be a normalized un-conditional basic sequence in
Lp
which is notequivalent
to the usualtp-basis.
Is there A > 1 such thatfor
each n there aredisjoint
intervalsA1, ..., An
in N andfunctions hi
E[fj: j
EAi]
such that(hl, ..., hn)
is03BB -equivalent
to the usual basisof t2?
We now pass to an
analytic
characterization of sequencesequivalent
to the usuale, -basis.
In the case of 1 s p2,
this is theunion of the results of Johnson-Odell
[7]
and of the first-named author[4].
Let usexplain
thebackground
and notation of our result for 2 p 00.If 0
ELp
=Lp (À) and 0
> 0 almosteverywhere,
we setd,ko = c/JPdA,
and define forf
ELp(A), UJ
=flo. By
the Radon-Nik-odÝm
theoremU,
is anisometry
ofLp(A)
ontoLp(Aq,).
Such anisometry
is called achange
ofdensity.
One shouldkeep
in mind thatisomorphic
and isometricproperties
ofsubspaces
and subsets ofLp
are invariant under
changes
ofdensity,
while theshape
of functions and theirLr
norms for r# p, are not.PROPOSITION 3.4: Let
( f; )
be a semi-normalized unconditional basic sequence inLp
=Lp(,k),
1 sp 00,p#
2. Then(fi)
isequivalent
to theusual basis
of ép if
andonly if
(i)
1 s p2,
and there aredisjoint
measurable subsets(E;) of [0, 11,
and à > 0 such thatfE, Ifi(t)lPdt:c--
SPfor
all i E N.or
(ii)
2 p 00, andfor every .0
> 0 withJd 0(t)Pdt
=1,
we haveMoreover, for
2 p 00,if (ii)
holds then C =supf Co -, .0
>0,
fol 0(t)Pdt
=l} 00 and for all
n and all ai, ..., an,where K is the unconditional constant
of (fi).
PROOF: For 1 p
2,
the "if" statement of theProposition
is thecontent of Lemma 2 in
[7],
while the"only
if" statement follows from Theorem B of[4].
For 2 p oo, Fact 2.4
(iii) implies
that(fi)
has a lowerl3p-estimate.
By
Fact 2.4(ii), (fi)
will have an upperlp -e stimate
if andonly
if thereis M 00 such that for all n and all a 1, ..., an,
Also,
if such M exists we will haveby
Fact 2.4(ii)
thatfor all n and all a 1, ..., an.
Setting
g; =If;/2,
r =p/2, s
=p/( p - 2)
wesee that such finite M exists if and
only
if supMn
00 whereMi
=sup{(fJ’=ll3;gi(t)lrdt)llr;
,i=1 n ((3 i Ir = 1.
·sup.M.
is the smallest ad- missible value of M.Fix
n E N,
and letTn: ér- Lr
be definedby Tn((a;)) = I?=i ag;.
Then
(We
made the substitutionc/Jp-2
=t/J).
Thus we have supnMn
=C,
which shows that( f; )
isequivalent
to the usuallp-basis
if andonly
ifC 00,
and proves the "moreover" statement of theProposition.
Tocomplete
theproof
it isenough
to note that forc/Jp-2
=t/J, C§ = supn[]T§§Ji]],
and therefore ifCq, 00
forall > 0
inLp,
then for allt/J E Ls, sUPnIITt/J1l 00
and soby
the uniform boundednessprinciple,
C = SUPll4ll=1
C4
=sUPn1lT:1I1/2
00.REMARK: It is
interesting
to comparepart (ii)
of theProposition
with the
following result,
which is asimple
consequence of results of H. P. Rosenthal[19]
and B.Maurey [13] (apply
Théorème 2 and Théorème 10 of[ 13]
and Fact 2.4(ii):
Let 1 $:p oo, and let(fi)
be asemi-normalized
unconditional basicsequence in Lp.
Then(fi) is
equivalent to
the usuall2-basis if
andonly if
there is 0c/J
ELp
suchthat
(Of
course, for each fixed p one of these conditions isalways
satisfiedfor semi-normalized
( f; )).
In the final result of this section we
give
ananalytic
conditionwhich is necessary and sufficient for a sequence of
independent
random variables in
Lp
to beequivalent
to the usualfp-basis.
Thiscondition is satisfied
by
every sequence inLp
which isequivalent
tothe usual
fp-basis.
Forindependent
random variables inLp,
2 p 00,the essential
part
ofProposition
3.5 is due to H. P. Rosenthal[21].
PROPOSITION 3.5: Fix a value
of
p, 1 :S; p oc,p 0 2,
and let( f; )
be asequence in
Lp. Suppose that,
among thefollowing conditions,
allthose which are
pertinent
to thegiven
valueof
p aresatisfied:
(i) if 1 - p
00,( f; )
is a semi-normalized sequenceof independent
non-constant random
variables,
(ii) if
1 _ P2,
there exist 8 > 0 and a sequence(Ei) of
subsetsof [0, 1 ]
such thatThen
(fi)
is a basic sequenceequivalent
to the usual basisof (p’
Conversely, if
1:5 p 00p 0 2,
and(fi)
is a sequence inLp
which isequivalent
to the usual basisof tp,
then statements(ii), (iii)
and(iv)
hold.
Moreover,
statement(ii)
isactually
truefor
all valuesof
p, 1 _p 00,
p 0 2,
and the sets in(ii)
may be taken to beof
theform
for
suitable constants6i
> 0.PROOF: We shall first prove the converse statement of the Pro-
position. Suppose
that 1 :n:-: p 00,p 0 2,
and( fi )
is a sequence inLp
which is
equivalent
to the usual basis oft,. By
a result of the first named author[4],
there are à > 0 and a sequence(Ei)
ofdisjoint
measurable subsets of
[0, 1]
such that(3.12)
is satisfied. Thus(ii)
is valid for all 1:5 p 00,p 0 2,
in astronger
form. To see that(Ei)
may bereplaced by
a sequencesatisfying (3.13)
as well as(3.11 )
and(3.12) (with
apossibly
smaller value of 8 >0),
we needonly
showLEMMA: Let
(fi)
be a bounded sequence inLp,
1 _ p oo.If
b > 0 and(Ei)
is a sequenceof
subsetsof [0, 1],
such that(3.11)
and(3.12) hold,
then there areQ; = 0,
i E N such that the setsFi
=[Ifi [ & Q;]
satisfy Li=l 1 iFi 00
andf Fi [ f;(t)[Pdt * SP/2 for
all i E N.PROOF OF THE LEMMA: For i E
N,
letQ;
be theunique
number forwhich
Then we have
by (3.12)
and the secondinequality
in(3.14).
On the therhand, setting
K = supi
lifi Il,
andFi
=[[ f; 113il
for i E N , we havePutting
these twoinequalities together
wehave 1 Fi IIIEI 1 2KPISP,
andso 1 î= 1 1 Fi 1 00 by (3.11 ),
which concludes theproof
of the Lemma in view of the firstinequality
in(3.14).
We now return to the
proof
of the converse assertion of theProposition
and so resume ourassumption
that(fi)
isequivalent
tothe usual basis of
e,.
Statement(iii)
for 2 p oo followsimmediately
from
Proposition
3.4(ii) with 0
= 1. To prove statement(iv),
let1 p oo.
Consider the mapT: t, --> L, given by T«ai» = 1 î= 1 aifi.
Then we have T* :
Lq - éq
and soWe now prove the direct
implication
asserted in theProposition.
Assume that
(/,)
is a sequence inLp satisfying (i)-(iv).
Foreach i,
lethi
be anH(f;)-measurable
function inLq
withId hi ( t ) dt = 0
andfol fi(t)hi(t)dt
= 1. Then(hi)
is abiorthogonal
sequence to( fi ). Hence,
in order to show that(fi)
isequivalent
to the usualtp-basis
we maydiscard
finitely
many of thef;’s
and show that theremaining
sequence isequivalent
to the usualtp -basis.
We first make the additional
assumption
that everyfi
has mean 0. If2 p
-, Theorem 3 in Rosenthal’s paper[21]
renders then:(The
secondequivalence
follows from Hôlder’sinequality
and(iii),
while the third one follows from the fact that( fi )
issemi-normalized.)
Let now 1 p
2,
and assume that(ii)
holds.By
the Lemma wemay assume that the sets
(Ei )
are of the form[] f; ] * so Ei
Ed(fi),
for all
i E N ,
which makes themindependent
events.Discarding finitely
many valuesof i,
if necessary, we may assume thatleil
1 forall
i,
and so(3.11) implies
thatFor
each i,
letGi
=Ei B U j>i Ej.
ThenGi
aredisjoint
measurable sets, andby
theindependence
offi
wehave,
for alli,
(fui)
is an unconditional basic sequenceby
Fact 2.3. Thereforeby (3.15)
and Lemma 2 of[7] (or, equivalently, Proposition
3.4(i)), (fi)
isequivalent
to the usuallp-basis.
The
Proposition
is nowproved
for1 - p -, p 0 2
under theassumption
that allfi
have mean 0. We nowdrop
thatassumption.
LetCi =
Id f i ( t ) dt,
andlet gi
=f i -
ci, i E N.Then,
for 1 s p-, p 0 2, (g;)
is a semi-normalized sequence ofindependent,
non-constant, mean 0 random variabies inLp.
If 1 :::; p2,
note thatas ->oo.
So,
afterdiscarding finitely
many values ofi,
statement(ii)
holds for
(gi )
with a smaller value of 5. If2 p -,
note that1 cd ::; Ilfdh ::; Iifi Ih,
so"gdh::; 211fdh
and therefore(iii)
holds for(gi)
as itdid for
(/,). By
the casealready proved,
we mayconclude,
for1 - p -, p 0 2,
that(gi)
isequivalent
to the usualt,-basis.
Now note
that fi
= gi - ci. If 1 p-, p 0 2,
thenby (iv),
so
by
Fact2.5, (fi)
isequivalent
to the usualfp-basis. If,
on the otherhand,
p =1,
then there is a constant a > 0 such that for any n and anyal, ..., OEn,
which
completes
theproof.
REMARK: For
arbitrary
normalized unconditional basic sequences(/,)
inLp, 1 :f:-: p -, p gé 2
the conditions(ii), (iii)
and(iv)
are not sufficient to ensure that(fi)
isequivalent
to the usuallp-basis.
Forexample,
letAi, A2,...
bedisjoint
subsets of[0, 1] with }"::=1 nlanl
oo. Given 1:5 p 00, there are
Kp
00 and functions(fn,i; n EN,
in)
such that eachf n,i
is mean 0 andsupported
inAn
and(fn,i -, n
EN, i
z5n)
isKp-equivalent
to the usual basis ofn=l (î),en 2 ),.
This is im-mediate from Khinchine’s
inequality
and the fact thatLp(An)
isisometric to
Lp.
Thus(fn,¡)
is unconditional and notequivalent
to theusual
lp-basis.
But( fn,;)
satisfies(ii) (with En,;
=An,
and 5 =1),
and ifp >
2,
it satisfies also(iii), by
anapplication
of Hôlder’sinequality
asin
(5.3)
below.4. Modular séquence spaces
The main result of this section is Theorem 4.2 which states that for
2 p -, tp is,
up tonormalization,
theonly
modular sequence space that embedsisomorphically
ine,.
As a consequence of this and known results we obtain(Corollary 4.3)
that for all 1:5 p 00 a modular sequence space which isisomorphic to ep
must be identicalwith
ep (again,
up tonormalization).
Our interest in this result here stems from thefact, proved by
H. P. Rosenthal[20],
that for any sequence of mean 0independent
random variables(fi)
inLp
the set ofall sequences of scalars
(ai)
for whichlî=l aifi
converges in norm is amodular sequence space.
(In
the case when thefi
are, inaddition, identically distributed,
this result wasproved
earlierby
J.Bretagnolle
and D. Dacunha-Castelle
[2]).
We shall use Theorem 4.2 in con-junction
with this fact in ourproof
of Theorem Apresented
in thenext section.
We shall use the term
0-function
to denote astrictly increasing
continuous function from
R’
toR+
which is 0 at 0. If(4>i)
is asequence of
0-functions
then the modular sequence spacee(e,)
is thelinear space of all sequences
(ai)
of scalars which for some t > 0satisfy E=i $;([a; [/t) ce, é.;>
is made into acomplete
linear metricspace
by
the metric:d((a;), 0) = e V £bÎ=i $;(]a;]le) = e.
A convex0-
function is called an Orlicz function. Ifq5j
are all Orlicz functions then the metric d isequivalent
to the norm:[](a;)][ s e V £=i Oi(laillE):g
1.We start with a criterion for one modular sequence space to be a
subset of another one. A criterion for
equality
of two modularsequence spaces
given by
J. Woo[25]
is similar inspirit
to ours, but issomewhat more restrictive.
PROPOSITION 4.1: Let
(oi)
and(Vii)
be two sequencesof 0-func-
tions. Then the