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(1)

ESAIM: Proceedings

Elasticite, Viscoelasticite et Contr^ole Optimal Huitiemes Entretiens du Centre Jacques Cartier URL:http://www.emath.fr/proc/Vol.2/

ESAIM: Proc., Vol. 2, 1997, 215{224

MODELING AND OPTIMIZATION OF A NON-SYMMETRIC PLATE.

L.J. ALVAREZ-VAZQUEZ AND J.M. VIA~NO

Abstract. In the rst part of this paper we present a limit model for non-symmetric elastic plates derived from three-dimensional elasticity by use of an asymptotic method and we prove existence and uniqueness of a solution of this model. In the second part we try the shape opti- mization of the plate, we obtain the existence of an optimal prole and we propose its numerical solution by means of penalty methods.

Key words:

Non-symmetric plates, asymptotic analysis, shape optimiza- tion, penalty methods.

Mathematics subject classication:

73K10, 73K40, 73C02, 35C20.

1. Introduction

The use of asymptotic methods for obtention and mathematical justica- tion of plate models in the framework of the theory of elasticity has been shown to be a successful technique during the last decades. First fundamen- tal contributions in this direction were obtained by Ciarlet - Destuynder 7]

with the justication of the classical bi-harmonic model of Kirchho - Love for the bending of symmetric plates. The application of this method to dif- ferent situations (linear and nonlinear elasticity, composite and anisotropic materials, static, dynamic and thermoelastic cases, homogenization and so on) has provided important contributions. A complete analysis of plate models with exhaustive bibliographic references may be found in Ciarlet 6].

Asymptotic methods have also reached an important development in the case of shells (Destuynder 11], Ciarlet - Paumier 9], Ciarlet - Miara 8]) and rods (Trabucho - Via~no 16], Cimetiere et al. 10]).

All of the above works have been exclusively devoted to the study of symmetric plates. The case of non-symmetric plates has so far remained, as far as we know, completely unreported. The rst aim of this paper is the obtention of a mechanical model for non-symmetric plates in the frame- work of linear elasticity. In section 2 we describe the physical problem, we obtain the mathematical model by use of an asymptotic analysis of the three- dimensional problem and we prove existence and uniqueness of a solution for such a model.

In section 3, we study the optimal design problem of minimizing the weight of the non-symmetric plate under some geometric and technological constraints, with some imposed bounds on the deection. In structural op- timization, these problems can be formulated as state constrained optimal control problems governed by an elliptic dierential equation, the control being a small parameter appearing in the coecients of the dierential op- erator (cf. Casas 3], Haug - Arora 13], Hlavacek - Bock - Lovisek 14], 15], Haslinger - Neittanmaki 12]). In this section we pose such a problem and obtain the existence of, at least, an optimal prole.

Article published by EDP Sciences and available at http://www.edpsciences.org/proc or http://dx.doi.org/10.1051/proc:1997002

(2)

In order to carry out the numerical solution of the optimal shape prob- lem, we propose in the last section the use of penalty techniques, obtaining necessary optimality conditions and some convergence results.

2. Modeling of a non-symmetric plate

Let

"

be a positive real parameter and

!

be a domain in

R

2 with coordi- nates axis

x

1

x

2

:

Let

h

2

W

21(

!

) be a \thickness" function verifying

h

(

x

1

x

2)

>

0

for all (

x

1

x

2)2

!:

(1) We consider the non-symmetric elastic plate of thickness

"h

occupying the reference conguration " dened by

"=f(

x

1

x

2

x

"3) : (

x

1

x

2)2

!

0

< x

"3

< "h

(

x

1

x

2)g

:

(2) We denote by

@

"

v

=

@

v

the derivative

@v=@x

and by

@

3"

v

the derivative

@v=@x

"3

:

Here and along the whole work we use, as it is customary in elas- ticity theory, the summation convention on repeated indices, supposing that the Latin indices range over f1

2

3gand Greek ones overf1

2g

:

We study the physical problem corresponding to the mechanical behav- ior of a non-symmetric elastic plate, supposed to be clamped on the lateral surface and submitted to body and surface forces. We assume the constitu- tive material of the plate to be a homogeneous isotropic elastic material of Saint Venant-Kirchho's type with Young's modulus

E

and Poisson's ratio

:

Then, in the linearized elasticity framework, the displacement eld

u

"and the Piola-Kirchho stress tensor

" are the solution of the following mixed variational formulation (see Ciarlet 5]):

u

"2

V

(") "2(") :

Z

"

(1 +

E

"ij;

E

"kk

ij)

"ij

dx

";Z

"

"ij(

u

")

"ij

dx

"= 0

8

"2(")

(3)

Z

"

"ij

"ij(

v

")

dx

"=

Z

"

f

"i

v

"i

dx

"+

Z

;

"

+

;

"

;

g

"i

v

"i

da

"

8

v

"2

V

(")

(4) where

;"0 =f(

x

1

x

2

x

"3) : (

x

1

x

2)2

@!

0

< x

"3

< "h

(

x

1

x

2)g

(5)

;"+=f(

x

1

x

2

x

"3) : (

x

1

x

2)2

! x

"3 =

"h

(

x

1

x

2)g

(6)

;";=f(

x

1

x

2

x

"3) : (

x

1

x

2)2

! x

"3 = 0g

(7)

V

(") =f

v

"(

v

"i)2

H

1(")]3 :

v

"i= 0 on ;"0g

(8) (") =

L

2(")]9S =f

"(

"ij)2

L

2(")]9 :

"ij=

"jig

(9) and

"(

u

") = (

"ij(

u

")) is the linearized strain tensor

"ij(

u

") = 12(

@

"i

u

"j+

@

"j

u

"i)

:

(10) We consider the reference symmetric plate of constant thickness 1 occupying the volume where

=f(

x

1

x

2

x

3) : (

x

1

x

2)2

!

0

< x

3

<

1g=

!

(0

1)

(11) and we dene

;0 =f(

x

1

x

2

x

3) : (

x

1

x

2)2

@!

0

< x

3

<

1g=

@!

(0

1)

(12)

;+=f(

x

1

x

2

x

3) : (

x

1

x

2) 2

! x

3= 1g=

!

f1g

(13)

;;=f(

x

1

x

2

x

3) : (

x

1

x

2) 2

! x

3= 0g=

!

f0g

:

(14)

(3)

We can dene the change of variable from " to the xed domain :

":

x

(

x

1

x

2

x

3)2;!

"(

x

1

x

2

x

3) =

(

x

1

x

2

"x

3

h

(

x

1

x

2))(

x

1

x

2

x

"3)

x

"2"

:

(15) Now we scale the dierent elds appearing in the variational formulation (see Ciarlet - Destuynder 7]) and we dene

u

(

"

) and

(

"

) by

u

(

"

)(

x

) =

u

"(

x

")

u

3(

"

)(

x

) =

"u

"3(

x

")

(16)

(

"

)(

x

) =

"(

x

")

3(

"

)(

x

) =

"

;1

"3(

x

")

33(

"

)(

x

) =

"

;2

33" (

x

")

:

(17) Also we assume that the applied forces are such that

f

"(

x

") =

f

(

x

)

f

3"(

x

") =

"f

3(

x

)

(18)

g

"(

x

") =

"g

(

x

)

g

"3(

x

") =

"

2

g

3(

x

)

(19) where

f

i 2

L

2()

g

i 2

L

2(;+ ;;) are independent of

":

Then, we ob- tain that (

u

(

"

)

(

"

)) is the only solution of the following scaled variational problem posed in :

u

(

"

)2

V

()

2() :

; Z

h

hij(

u

(

"

))

ij

dx

+

Z

h

f1 +

E

(

"

);

E

(

"

)

g

dx

+

"

2Z

h

f21 +

E

3(

"

)

3;

E

(

33(

"

)

+

(

"

)

33)g

dx

+

"

4Z

h E

1 33(

"

)

33

dx

= 0

8

2()

(20)

Z

h

ij(

"

)

hij(

v

)

dx

=

Z

hf

i

v

i

dx

+

Z

;

h

(

"

)

g

i

v

i

da

8

v

2

V

()

(21) where

V

() =f

v

(

v

i)2

H

1()]3 :

v

i = 0 on ;0g

(22)

() =

L

2()]9S

(23)

h

(

"

) = 1 +

"

2(

@

1

h

)2+

"

2(

@

2

h

)2]1=2

(24) and

h(

v

)(

hij(

v

)) is the generalized strain tensor dened by

h(

v

) = 12

@

v

+

@

v

;

x

3

h

;1

@

h@

3

v

;

x

3

h

;1

@

h@

3

v

]

(25)

h3(

v

) = 12

@

v

3+

h

;1

@

3

v

;

x

3

h

;1

@

h@

3

v

3]

(26)

33h(

v

) =

h

;1

@

3

v

3

:

(27) In order to obtain the convergence of the scaled three-dimensional problem as

"

tends to zero we are going to show several technical results. In what follows, j j0D and jj jjmD denote the

L

2(

D

)-norm and

H

m(

D

)-norm, respectively.

Let

E

h() be the space

E

h() =f

v

(

v

i)2

L

2()]3 :

hij(

v

)2

L

2()g

endowed with the norm

jj

v

jjh=fj

v

j20+X3

ij=1

j

hij(

v

)j20g1=2

for all

v

2

E

h()

:

(28) We have the results whose complete proofs can be seen in 1].

(4)

Theorem 1.

H

()] =

E

h() and the norms jj jjh and jj jj1 are equivalent.

We introduce the space of displacements of Kirchho-Love

V

hKL() =f

v

(

v

i)2

V

() :

hi3(

v

) = 0g

:

(29) We have the following characterization for this space.

Theorem 2. The space

V

hKL() is characterized by

V

hKL() =f

v

(

v

i) :

v

3(

x

1

x

2

x

3) =

3(

x

1

x

2)

32

H

02(

!

)

v

(

x

1

x

2

x

3) =

(

x

1

x

2);

x

3

h

(

x

1

x

2)

@

3(

x

1

x

2)

2

H

01(

!

)(30) Remark 3. We write (30) in the following shortened form

V

hKL() = f

v

(

v

i) :

v

3 =

3

v

=

;

x

3

h@

3

3 2

H

02(

!

) 2

H

01(

!

)g

and we note that the following mapping is an isomorphism

j

:

(

1

2

3)2

H

01(

!

)]2

H

02(

!

);!

;!

j

(

) = (

1;

x

3

h@

1

3

2;

x

3

h@

2

3

3)2

V

hKL(

:

) (31) Theorem 4. The semi-normj jh dened by

v

2

V

();!j

v

jh=fX3

ij=1

j

hij(

v

)j20g1=2 is a norm over

V

() equivalent to jj jj1

:

Corollary 5. The mapping

v

2

V

hKL();!j

v

jh=f X2

=1

j

h(

v

)j20g1=2 is a norm over

V

hKL() equivalent to the norm jj jj1

:

Corollary 6. The mapping jj jjKL dened by (see (30))

v

2

V

hKL();!jj

v

jjKL=fjj

1 jj21!+jj

2 jj21!+jj

3jj22!g1=2 is a norm over

V

hKL() equivalent to the norm j jh and, consequently, to the norm jj jj1

:

The rst step in order to obtain convergence of the sequence (

u

(

"

)

(

"

)) consists of the following a priori estimates.

Theorem 7. There exist

"

0

>

0 and a constant

C

=

C

(

h!

) such that for all 0

< " < "

0 we have

jj

u

(

"

)jj1

C

j

(

"

)j0

C

j

"

3(

"

)j0

C

j

"

2

33(

"

)j0

C:

Corollary 8. The sequencesf

u

(

"

)g">0 andf

(

"

)g">0 verify the following weak convergences

u

(

"

)

* u

in

V

()

(

"

)

*

in

L

2()

"

3(

"

)

*

0 in

L

2()

"

2

33(

"

)

*

0 in

L

2()

(5)

where

u

is the unique element in

V

hKL() solution of the problem

Z

1;

E

2

h

f(1;

)

h(

u

)

h(

v

) +

h(

u

)

h(

v

)g

dx

=

Z

hf

i

v

i

dx

+

Z

;

g

i

v

i

da

for all

v

2

V

hKL()

(32) and

is given by

=

E

1;

2f(1;

)

h(

u

) +

h (

u

)

g

:

(33) Corollary 9. The following strong convergences hold true:

u

(

"

)!

u

in

V

()

(

"

)!

in

L

2()

"

3(

"

)!0 in

L

2()

"

2

33(

"

)!0 in

L

2()

:

Remark 10. We can make the limit problem (32) more explicit by taking

u

= (

1;

x

3

h@

1

3

2;

x

3

h@

2

3

3)

(34)

v

= (

1;

x

3

h@

1

3

2;

x

3

h@

2

3

3)

(35) for

2

H

01(

!

) and

3

32

H

02(

!

) and by letting

g

i+(

x

1

x

2) =

g

i(

x

1

x

2

1)

g

i;(

x

1

x

2) =

g

i(

x

1

x

2

0)

:

Then the limit problem takes the following form:

1;

E

2f

Z

!

h

(1;

)

(

)

(

) +

(

)

(

)];

Z

!

h

2

2 (1;

)(

(

)

@

3+

(

)

@

3) +

(

(

)

@

3+

(

)

@

3)]

+

Z

!

h

3

3 (1;

)

@

3

@

3+

@

3

@

3]g=

Z

!

h

Z

1

0

f

i]

i;

Z

!

h

2

Z

1

0

x

3

f

]

@

3+

Z

!

g

i;+

g

i+]

i;

Z

!

hg

+

@

3

for all

2

H

01(

!

) 3 2

H

02(

!

)

:

Remark 11. If we assume an asymptotic expansion of the form (

u

(

"

)

(

"

)) = (

u

0

0) +

"

2(

u

2

2) +

"

4(

u

4

4) +

:::

and if we substitute this expression into the scaled variational problem, we obtain that the rst term (

u

0

0) veries

u

0=

u

0 =

i03 =

x

3

i0

@

h

;Z x3

0

@

(

h

i0 );

g

i;;Z x3

0

hf

i

:

Remark 12. We can return to the reference conguration "taking into ac- count that

u

is a limit approximation of

u

(

"

)

:

Performing the inverse change of variable and the inverse scaling, we obtain that the limit displacement eld

u

0" in " is given by

u

0"(

x

") =

u

(

x

) =

(

x

1

x

2);

x

3

h

(

x

1

x

2)

@

3(

x

1

x

2) =

=

(

x

1

x

2);

"

;1

x

"3

@

3(

x

1

x

2) =

"(

x

1

x

2);

x

"3

@

3"(

x

1

x

2)

u

03"(

x

") =

"

;1

u

3(

x

) =

"

;1

3(

x

1

x

2) =

3"(

x

1

x

2)

(6)

where

"=

"

3=

"

;1

3

:

Letting

g

i"+(

::

) =

g

"i(

::"h

(

::

)) and

g

i";(

::

) =

g

"i(

::

0) we have

g

" =

"g

and

g

3"=

"

2

g

3

:

Then, we obtain that

"2

H

01(

!

) and

3"2

H

02(

!

) are the unique solution of the following problem which is the obtained model

1;

E

2f

Z

!

"h

(1;

)

(

")

(

) +

(

")

(

)];

Z

!

"

2

h

2

2 (1;

)(

(

")

@

3+

(

)

@

3")+

(

(

")

@

3+

(

)

@

3")]

+

Z

!

"

3

h

3

3 (1;

)

@

3"

@

3+

@

3"

@

3]g=

Z

!

Z "h

0

f

"i+

g

i";+

g

i"+]

i;

Z

!

Z "h

0

x

"3

f

"+

"hg

"+]

@

3

for all

2

H

01(

!

) 3 2

H

02(

!

)

:

3. Optimization of a non-symmetric plate

We consider an homogeneous, isotropic, elastic non-symmetric plate oc- cupying the reference conguration

h=f(

x

1

x

2

x

3)2

IR

3 : (

x

1

x

2)2

!

0

< x

3

< h

(

x

1

x

2)g

clamped on its lateral surface and submitted to body forces of density

f

h (

f

hi) on hand surface forces of density

g

h+(

g

ih+) on ;h+and

g

h;(

g

ih;) on ;h; where

;h+ =f(

x

1

x

2

x

3)2

IR

3 : (

x

1

x

2)2

! x

3=

h

(

x

1

x

2)g

;h;=f(

x

1

x

2

x

3)2

IR

3 : (

x

1

x

2)2

! x

3 = 0g

:

We denote by

u

h (

u

hi) : h;!

IR

3the displacement eld corresponding to the above conditions. In the sequel we identify the functions

u

h

f

h and

g

h with the functions

u

(

h

) : ;!

R

3

f

(

h

) : ;!

R

3 and

g

(

h

) : ; ;!

R

3 such that

u

(

h

)(

x

1

x

2

x

3) =

u

h(

x

1

x

2

x

3

h

(

x

1

x

2))

f

(

h

)(

x

1

x

2

x

3) =

f

h(

x

1

x

2

x

3

h

(

x

1

x

2))

g

+(

h

)(

x

1

x

2

1) =

g

h+(

x

1

x

2

h

(

x

1

x

2))

g

;(

h

)(

x

1

x

2

0) =

g

h;(

x

1

x

2

0)

:

For simplicity, we assume from now on that the applied forces are such that

f

(

h

) =

f

and

g

(

h

) =

g

where

f

and

g

are independent of

h:

As it was shown in the previous section the displacement eld

u

(

h

) can be approximated by the only solution of the following variational problem:

u

(

h

)2

V

hKL()

a

h(

u

(

h

)

v

) =

l

h(

v

)

for all

v

2

V

hKL()

where for all

uv

2

V

hKL(),

a

h(

uv

) =

Z

1;

E

2

h

f(1;

)

h(

u

)

h(

v

) +

h(

u

)

h(

v

)g

dx

(36)

l

h(

v

) =

Z

hf

i

v

i

dx

+

Z

;

g

+i

v

i

da

+

Z

;

g

i;

v

i

da:

(37)

(7)

The optimal design problem deals with minimizing the weight of the non- symmetric plate h

or equivalently its volume (since the material is homo- geneous), that we denote by

J

(

h

) =R!

h:

The plate must be designed in such a way that allowed deections be less than a given bound

e:

As

u

3(

h

)2

H

02(

!

) we impose:

jj

u

3(

h

)jj1!

e:

In addition, we impose to the thickness some constraints of technological nature:

i

) The plate is designed in order to be constructed later, and this con- struction would not be possible if the plate is too thick or too thin. This fact leads us to impose the constraint:

0

< a

h

(

x

)

b <

1

for all

x

2

!:

ii

) We also need that the variation of the thickness be slow and progres- sive. Then, we require

jj

@

h

jj1!

c

jj

@

h

jj1!

d:

These technological constraints lead us to work in the set of feasible thick- ness:

U

ad=f

h

2

W

21(

!

) :

a

h

(

x

)

b

jj

@

h

jj1!

c

jj

@

h

jj1!

d

g which is a convex, closed and bounded subset of

W

21(

!

)

:

If we dene the set

K

h = f

v

2

V

hKL() : jj

v

3 jj1!

e

g which is a convex, closed subset of

V

hKL()

we can formulate the following optimal design problem:

(

P

)

Find h

2

U

ad

such that

:

u

(

h

)2

K

h

J

(

h

) =

inf

f

J

(

h

) :

h

2

U

ad

u

(

h

)2

K

hg

:

Our rst aim is to study the existence of a solution for problem (

P

)

:

In order to do so, we consider

J

as a function dened in the space

W

11(

!

)

J

:

h

2

W

11(

!

);!

J

(

h

) =

Z

!

h

2

IR

and we dene the set

B

=f

h

2

U

ad :

u

(

h

) 2

K

hg that we assume to be non empty. Then, problem (

P

) can be written in the following form:

(

P

)

Find h

2

B such that J

(

h

) =

inf

f

J

(

h

) :

h

2

B

g

:

Since

J

is continuous, to obtain the existence of a solution it should be enough to prove that

B

is compact in

W

11(

!

)

:

In order to prove this fact, we write problem (

P

) in a more suitable form.

We recall that the denition of h implicitly assumes that

h

is in the subset

A

(

!

) of the space

W

11(

!

) given by

A

(

!

) =f

h

2

W

21(

!

) :

h

(

x

)

(

h

)

>

0

for all

x

2

!

g

:

We denote by

L

2(

V

hKL()) the space of continuous bilinear forms on

V

hKL() and by

L

(

V

hKL()

V

hKL()0) the space of continuous linear forms from

V

hKL() on its dual. We also introduce the functions

T

:

h

2

A

(

!

);!

T

(

h

) =

l

h 2

V

hKL()0

F

:

h

2

A

(

!

);!

F

(

h

) =

a

h 2

L

2(

V

hKL())

G

:

a

2

L

2(

V

hKL());!

G

(

a

) =

A

2

L

(

V

hKL()

V

hKL()0)

(8)

where

A

(

y

)(

z

) =

a

(

yz

)

for all

yz

2

V

hKL()

:

Of course,

G

is an isometric isomorphism.

With each bilinear form

a

h =

F

(

h

) we associate the operator

A

h =

G

(

a

h) =

G

(

F

(

h

))

:

Since

a

h is

V

hKL();elliptic for all

h

2

A

(

!

), it fol- lows from Lax-Milgram lemma that for each

l

h 2

V

hKL()0 there exists a unique element

u

(

h

) 2

V

hKL() such that

A

h(

u

(

h

)) =

l

h

:

Then,

A

h is an isomorphism from

V

hKL() onto

V

hKL()0 and the following function is well dened and of class

C

1:

u

:

h

2

A

(

!

)

W

11(

!

);!

u

(

h

) =

A

;1h (

l

h)2

V

hKL()

H

1()]3

:

This is the key to prove that

U

ad and

B

are compact in

W

11(

!

)

:

Conse- quently, if

l

h is of the form (37) then problem (

P

) has at least one solution.

Remark 13. For

hk

2

A

(

!

) we dene

m

hk =

DT

(

h

)(

k

)2

V

hKL()0

a

hk =

DF

(

h

)(

k

)2

L

2(

V

hKL())

:

Then we have from (37)

m

hk =

Z

kf

i

v

i

:

In the same way we obtain from (36) that for all

uv

2

V

hKL() given by (34),(35)

a

hk(

uv

) =

E

1;

2f

Z

!

k

(1;

)

(

)

(

) +

(

)

(

)];

Z

!

hk

(1;

)(

(

)

@

3+

(

)

@

3)+

(

(

)

@

3+

(

)

@

3)]+

Z

!

h

2

k

(1;

)

@

3

@

3+

@

3

@

3]g

:

Let

A

hk =

G

(

a

hk)2

L

(

V

hKL()

V

hKL()0)

:

Then we have

p

=

Du

(

h

)(

k

) =

A

;1h

m

hk;

A

hk(

u

(

h

))]

:

This equation will be helpful for the numerical computation of

Du

(

h

)(

k

) in the next section.

4. Penalty method

In order to obtain the numerical solution of problem (

P

) we will use penalty techniques, dening a family of problems (

P

) which approximate problem (

P

) and which have a suitable numerical solution. Besides, we will obtain necessary optimality conditions for the penalty problem (

P

)

:

For

>

0 we dene the function

J

:

h

2

A

(

!

);!

J

(

h

) =

J

(

h

) + 12

jj

u

(

h

);

P

Kh(

u

(

h

))jj2KL2

R

where

P

Kh :

V

hKL() ;!

K

h denotes the projection in the Hilbert space

V

hKL() over the closed and convex subset

K

h

which is a continuous function (Barbu-Precupanu 3], Cea 11]). Thus,

J

is also a continuous function.

We consider the following problem:

(

P

)

Find h

2

U

ad

such that J

(

h

) =

inf

f

J

(

h

) :

h

2

U

adg

:

Due to the compacity of

U

adand the continuity of

J

the problem (

P

) has, at least, one solution.

(9)

If for each

>

0 we note

h

a solution of problem (

P

) then we have the following result.

Theorem 14.

i

) If

1

<

2

then

J

2(

h

2)

J

1(

h

1)hinf

2B

J

(

h

)

(38)

jj

u

(

h

1);

P

Kh 1

(

u

(

h

1))jjKL jj

u

(

h

2);

P

Kh 2

(

u

(

h

2))jjKL

(39)

J

(

h

2)

J

(

h

1)hinf

2B

J

(

h

)

:

(40)

ii

) The family f

h

:

>

0g is bounded in

W

21(

!

) and there exist sequences f

ng

f

h

ng such that if

n

!1

then

n!0

h

n !

h

in

W

11(

!

)

:

Each of these limits

h

is a solution of problem (

P

)

:

iii

) It is veried that

lim!0

J

(

h

) = lim

!0

J

(

h

) = infh

2B

J

(

h

)

:

As an immediate consequence, we obtain the following convergence result.

Corollary 15. If problem (

P

) has a unique solution

h

and, for each

>

0

h

denotes a solution of the problem (

P

)

then as

!0 we have

h

!

h

in

W

11(

!

)

:

In order to obtain optimality conditions for the problem (

P

) we rst prove the following result.

Theorem 16. The function

J

:

A

(

!

);!

R

is of class

C

1 and

DJ

(

h

)(

k

) =

J

(

k

) +

a

hk(

u

(

h

)

z

);

m

hk(

z

)

where

u

(

h

) and

z

verify

A

h(

u

(

h

)) =

l

h

(41)

p

=

I

;

P

Kh

(

u

(

h

))

(42)

A

h(

z

) +

p

= 0

(43) and where

A

h:

V

hKL();!(

V

hKL())0 is the adjoint operator of

A

h

:

A point

h

2

U

ad is said to be a stationary point for problem (

P

) if and only if it veries

DJ

(

h

)(

h

;

h

) 0

8

h

2

U

ad

:

Since

U

ad is a convex set, we have that if

h

2

U

adis a solution of (

P

) then

h

is a stationary point for (

P

) (cf. Cea 4]). This fact supplies us the following necessary optimality condition.

Theorem 17.

h

2

U

ad is a stationary point for (

P

) if and only if there exist

p

u

z

2

V

hKL() verifying

A

h(

u

) =

l

h

p

=

I

;

P

Kh

(

u

)

A

h(

z

) +

p

= 0

J

(

h

);

J

(

h

) +

a

hh;h(

u

z

);

m

hh;h(

z

)0

8

h

2

U

ad

:

References

1] L.J. Alvarez-Vazquez and J.M. Via~no. Modeling and optimization of non- symmetric plates.To appear.

2] V.Barbuand T.Precupanu.Convexity and optimization in Banach spaces.Sijtho and Noordho, Bucharest, 1978.

3] E.Casas.Optimality conditions and numerical approximations for some optimal de- sign problems.Control Cibernet., 19, pp 73-91 (1990).

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