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HAL Id: hal-00668163

https://hal.archives-ouvertes.fr/hal-00668163v2

Preprint submitted on 11 Feb 2012

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isolated or periodically arranged openings

Guillaume Gomard, Romain Peretti, Xavier Letartre, Emmanuel Drouard

To cite this version:

Guillaume Gomard, Romain Peretti, Xavier Letartre, Emmanuel Drouard. Propagation of an electro- magnetic lightwave through isolated or periodically arranged openings. 2012. �hal-00668163v2�

(2)

Propagation of an electromagnetic lightwave through isolated or periodically arranged openings

G. Gomard,*,1,2 R. Peretti,*,1 X. Letartre,*,1 † and E. Drouard *,1

* Université de Lyon, Institut des Nanotechnologies de Lyon (INL) UMR 5270 CNRS- INSA-ECL-UCBL 1 Ecole Centrale de Lyon, 36 avenue Guy de Collongue, 69134, Ecully Cedex, FRANCE 2 INSA de Lyon, Bat. Blaise Pascal, 7 avenue Jean Capelle, 69621, Villeurbanne, FRANCE

Abstract: The goal of this document is to provide a comprehensive description of the equations governing the propagation of an electromagnetic lightwave trough an opening.

The latter is first considered as isolated and then integrated within a periodically arranged array. The material in which the openings are drilled is supposed to be non-magnetic (µmaterialair). No other specific assumptions are made on the optical indices of the different regions involved in order to keep this study as general as possible.

Keywords: Maxwell’s equation, leaky waveguide, leaky modes, periodic array

Contents:

1. Isolated Opening ... 2

1.1 TE polarization... 2

1.1.1 General expression of the field ... 3

1.1.2 Continuity of the tangential component Ey ... 4

1.1.3 Continuity of the Hz component... 4

1.1.4 Condition on the parity ... 4

1.1.5 Even case B1=A1... 6

1.1.6 Odd case B1=-A1... 6

1.1.7 Transcendental equations ... 6

1.1.7.a Transcendental equations: Even case ... 6

1.1.7.b Transcendental equations: Odd case ... 7

1.1.8 Example ... 7

1.2 TM polarization... 8

1.2.1 General expression of the field ... 8

1.2.2 Continuity of the tangential component Hy... 9

1.2.3 Continuity of the Ez component ... 9

1.1.4 Condition on the parity ... 10

1.2.5 Even case B1=A1... 11

1.2.6 Odd case B1=-A1... 12

1.2.7 Transcendental equations ... 12

1.2.7.a Transcendental equations: Even case ... 12

1.2.7.b Transcendental equations: Odd case ... 13

Please contact us with suggestions for improvement or correction at: xavier.letartre@ec-lyon.fr

(3)

2. Periodically Arranged Openings ... 13

2.1 TE polarization... 14

2.1.1 General expression of the field ... 14

2.1.2 Continuity of the tangential component Ey ... 14

2.1.3 Continuity of the Hz component... 14

2.1.4 Transcendental equations ... 15

2.1.5 Example ... 15

2.2 TM polarization... 16

2.2.1 General expression of the field ... 16

2.2.2 Continuity of the tangential component Hy... 16

2.2.3 Continuity of the Ez component ... 16

2.2.4 Transcendental equations ... 17

3. References ... 18

1. Isolated Opening

The first case investigated is depicted on Figure 1 and corresponds to an isolated opening (with a width and a complex optical index denoted “d” and “n1”, respectively) drilled inside a material (with a complex optical index denoted “n2”). Both TE and TM polarizations are considered in the following. Please note that the subscript “1” (“2”) is attributed to the parameters of region 1 (region 2).

Figure 1: Isolated opening (region 1) drilled in a material with an infinite extent in the x, y and z directions (region 2). The lightwave is propagating along the z direction.

1.1 TE polarization

In TE polarization, only the Ey component exists. From Maxwell’s equations, one can obtain the equations below [1]:

Equation 1

( )

2

2 2

2y z y 0

E k k E

x

∂ + − =

(4)

, with:

Equation 2

( )

2 2 2

x z

k = kk

N.B: The imaginary part of k is supposed to be negative

The general form of Ey is:

Equation 3

( 2 z2) ( 2 z2)

jx k k jx k k

Ey =

Ae

+

Be

1.1.1 General expression of the field For x<-d/2

Equation 4

2 2

2 2

x x

jxk jxk

Ey =

A e

+

B e

For –d/2<x<d/2

Equation 5

1 1

1 1

x x

jxk jxk

Ey =

A e

+

B e

For x>d/2

Equation 6

2 2

2 2

x x

jxk jxk

Ey =

A e

+

B e

Because the system considered is not periodic (see Figure 1), to electrical field is decaying to zero when x tends to -∞ or +∞. This implies that:

For x<-d/2

Equation 7

2

2

jxkx

Ey =

A e

For –d/2<x<d/2

Equation 8

1 1

1 1

x x

jxk jxk

Ey =

A e

+

B e

(5)

For x>d/2

Equation 9

2

2

jxkx

Ey =

B e

1.1.2 Continuity of the tangential component Ey At x=-d/2

Equation 10

2 1 1

2 2 2

2 1 1

x x x

d d d

j k j k j k

A e

=

A e

+

B e

At x=+d/2

Equation 11

2 1 1

2 2 2

2 1 1

x x x

d d d

j k j k j k

B e

=

A e

+

B e

1.1.3 Continuity of the Hz component

Hz is related to Ey by the Maxwell’s equations through:

Equation 12

y

z

E j H

x ωµ

∂ = −

So the general form of Hz is:

Equation 13

(

2 2

)

2

2 2

x x

jxk jxk

x z

H =µωk

B e

A e

At x=-d/2

Equation 14

2 1 1

2 2 1 2 2

2 2 1 1 1

x x x

d d d

j k j k j k

x x

k k

A e B e A e

µ µ

   

=

   

 

At x=+d/2

Equation 15

2 1 1

2 2 1 2 2

2 2 1 1 1

x x x

d d d

j k j k j k

x x

k k

B e B e A e

µ µ

=  

 

′ −

1.1.4 Condition on the parity

It is then possible to combine the equations of continuity to derive the A1/B1 ratio.

(6)

At x=-d/2

2 1 1

2 2 2

2 1 1

x x x

d d d

j k j k j k

A e

=

A e

+

B e

2 1 1

2 2 1 2 2

2 2 1 1 1

x x x

d d d

j k j k j k

x x

k k

A e B e A e

µ µ

   

=

   

 

, which gives rise to:

Equation 16

1 1 1 1

2 2 2 1 2 2

2 1 1 1 1 1

x x x x

d d d d

j k j k j k j k

x x

k k

A e B e A e B e

µ µ

   

+ = −

   

   

Equation 17

1

1 2

1 2

1

1 1 2

1 2

x

x x

jdk

x x

k k

A

B kµ kµ

e

µ µ

 

+

 

 

= 

 

 

At x=+d/2

2 1 1

2 2 2

2 1 1

x x x

d d d

j k j k j k

B e

=

A e

+

B e

2 1 1

2 2 1 2 2

2 2 1 1 1

x x x

d d d

j k j k j k

x x

k k

B e B e A e

µ µ

=  

 

′ −

, which gives rise to:

Equation 18

1

2 1

1 2 1

1 2

1

1 2

x

x x

jdk

x x

k k

B

k k

A µ µ

e

µ µ

+

=

From the equations above, one can notice that:

Equation 19

1

2 1

2 1 1 1

1 2 1 1

1 2

x

x x

jdk

x x

k k

B A

kµ kµ

e

A B

µ µ

+

= =

So:

Equation 20

2 2

1 1

B = A . This leads to two cases:

(7)

Even case:B1= A1 Odd case: B1= −A1

1.1.5 Even case B1=A1 At x=-d/2

Using Euler’s formula:

Equation 21

2 1 2 2 2 1

1 1 2

2 sin

2

x

j kd x

x x

A k d

j k

A = − µ kµ

e

At x=+d/2

Equation 22

1 2

2 2 2

1

1 1 2

2 sin

2

x

j kd x

x x

k

B d

j k

A = − µ kµ

e

1.1.6 Odd case B1=-A1 At x=-d/2

Equation 23

1 2

2 2 2

1

1 1 2

2 cos

2

x

j kd x

x x

A k d

A = µ kµ k

e

At x=+d/2

Equation 24

1 2

2 2 2

1

1 1 2

2 cos

2

x

j kd x

x x

k

B d

A = − µ kµ k

e

1.1.7 Transcendental equations

1.1.7.a Transcendental equations: Even case At x=-d/2

Starting from:

1 2

2 2 2

1

1 1 2

2 sin

2

x

j kd x

x x

A k d

j k

A = − µ kµ

e

And:

(8)

2 1 1

2 2 2

2 1 1

x x x

d d d

j k j k j k

A e

=

A e

+

A e

, which can be rewritten as:

2 2 2

1 1

2 cos 2

x

j kd x

A d

A = k

e

We now find:

Equation 25

2

2 1 1

1

tan 2

x x x

k j k µ d k

µ

 

= − ×  

 

1.1.7.b Transcendental equations: Odd case At x=-d/2

Starting from:

1 2

2 2 2

1

1 1 2

2 cos

2

x

j kd x

x x

k

A d

A = µ kµ k

e

And:

2 1 1

2 2 2

2 1 1

x x x

d d d

j k j k j k

A e

=

A e

A e

, which can be rewritten as:

2 2 2

1 1

2 sin 2

x

j kd x

A d

j k

A = −

e

We now find:

Equation 26

2

2 1 1

1

cot 2

x x x

k jk µ d k

µ

 

=  

 

1.1.8 Example

As an example, one can assume that region 1 is air (n1=1) and that region 2 is an absorbing medium with an optical index n2= 5+i, which roughly corresponds to the indices of amorphous silicon in the blue region of the visible spectrum. The wavelength is set to 1 and the width of the hole is set to 0.5 (in lambda units). Using Equation 25, it is then possible to compute the x and z components of the wave vector in regions 1 and 2, which then gives:

- kx(region 1)= 6.039-0.729i - kx(region 2)= 31.335+6.156i

- kz(region 1)= kz(region 2)= 2.552+1.726i

The normalized field profile of the lightwave propagating through this subwavlength opening is reported in Figure 2.

(9)

Figure 2: Normalized field profile of a lightwave propagating in the direction indicated by the arrow (First order depicted). The field amplitude is maximum in the middle of region 1 (air) and is decaying both

laterally, towards the absorbing medium, and in the propagation direction.

1.2 TM polarization

In TM polarization, only the Hy component exists. From Maxwell’s equations, one can obtain the equations below:

Equation 27

( )

2

2 2

2y z y 0

H k k H

x

∂ + − =

∂ , with:

Equation 28

( )

2 2 2

x z

k = kk

The general form of Hy is:

Equation 29

( 2 z2) ( 2 2z)

jx k k jx k k

Hy =

Ae

+

Be

1.2.1 General expression of the field For x<-d/2

Equation 30

2 2

2 2

x x

jxk jxk

Hy =

A e

+

B e

(10)

For –d/2<x<d/2

Equation 31

1 1

1 1

x x

jxk jxk

Hy =

A e

+

B e

For x>d/2

Equation 32

2 2

2 2

x x

jxk jxk

Hy =

A e

+

B e

Because the system considered is not periodic (see Figure 1), to electrical field is decaying to zero when x tends to -∞ or +∞. This implies that:

For x<-d/2

Equation 33

2

2

jxkx

Hy =

A e

For –d/2<x<d/2

Equation 34

1 1

1 1

x x

jxk jxk

Hy =

A e

+

B e

For x>d/2

Equation 35

2

2

jxkx

Hy =

B e

1.2.2 Continuity of the tangential component Hy At x=-d/2

Equation 36

2 2 1 1

2 2 2 2

2 2 1 1

x x x x

d d d d

j k j k j k j k

A e

+

B e

=

A e

+

B e

At x=+d/2

Equation 37

2 2 1 1

2 2 2 2

2 2 1 1

x x x x

d d d d

j k j k j k j k

A e

+

B e

=

A e

+

B e

1.2.3 Continuity of the Ez component

Ez is related to Hy by the Maxwell’s equations through:

(11)

Equation 38

y

z

H j E

x ωε

∂ = +

So the general form of Ez is:

Equation 39

(

2 2

)

2

2 2

x x

jxk jxk

x z

E =εωk

A e

B e

At x=-d/2

Equation 40

2 2 1 1

2 2 2 2

2 2 1 1

2 2 1 1

2 2 1 1

x x x x

d d d d

j k j k j k j k

x x x x

k k k k

A e B e A e B e

ε ε ε ε

− = −

At x=+d/2

Equation 41

2 2 1 1

2 2 2 2

2 2 1 1

2 2 1 1

2 2 1 1

x x x x

d d d d

j k j k j k j k

x x x x

k k k k

A e B e A e B e

ε ε ε ε

− = −

′ ′

1.1.4 Condition on the parity

It is then possible to combine the equations of continuity to derive the A1/B1 ratio.

At x=-d/2

2 2 1 1

2 2 2 2

2 2 1 1

x x x x

d d d d

j k j k j k j k

A e

+

B e

=

A e

+

B e

2 2 1 1

2 2 2 2

2 2 1 1

2 2 1 1

2 2 1 1

x x x x

d d d d

j k j k j k j k

x x x x

k k k k

A e B e A e B e

ε ε ε ε

− = −

Assuming B2=0, this gives rise to:

Equation 42

1

1 2

1 2

1

1 1 2

1 2

x

x x

jdk

x x

k k

A

B kε kε

e

ε ε

 

 + 

 

= 

 − 

 

(12)

At x=+d/2

2 2 1 1

2 2 2 2

2 2 1 1

x x x x

d d d d

j k j k j k j k

A e

+

B e

=

A e

+

B e

2 2 1 1

2 2 2 2

2 2 1 1

2 2 1 1

2 2 1 1

x x x x

d d d d

j k j k j k j k

x x x x

k k k k

A e B e A e B e

ε ε ε ε

− = −

′ ′

Assuming A2=0, this gives rise to:

Equation 43

1

2 1

2 1 1

1 2 1

1 2

x

x x

jdk

x x

k k

B kε kε

e

A

ε ε

 

+

 

  =

 

 − 

 

From the equations above, one can notice that:

Equation 44

1

2 1

2 1 1 1

1 1

1 2

1 2

x

x x

jdk

x x

k k

B A

A B

kε kε

e

ε ε

 

 + 

  = =

 

 − 

 

So:

Equation 45

2 2

1 1

B = A . This leads to 2 cases:

Even case:B1= A1 Odd case: B1= −A1

1.2.5 Even case B1=A1 At x=-d/2

Using Euler’s formula:

Equation 46

2 2

1

1 1

2 2

2 sin

2 1 2

x

j kd

x

x

k d

x j k

k A

A e

ε

ε

 

= −  

 

(13)

At x=+d/2

Equation 47

2 2

1

1 1

2 2

2 sin

2 1 2

x

j kd

x

x

k d

x j k

k B

A e

ε

ε

 

= −  

 

1.2.6 Odd case B1=-A1 At x=-d/2

Equation 48

2 2

1

1 1

2 2

2 cos

2 1 2

x

j kd

x

x

k d

x k

k A

A e

ε

ε

 

=  

 

At x=+d/2

Equation 49

2 2

1

1 1

2 2

2 cos

2 1 2

x

j kd

x

x

k d

x k

k B

A e

ε

ε

 

= −  

 

1.2.7 Transcendental equations

1.2.7.a Transcendental equations: Even case At x=-d/2

Starting from:

1 2 2

2 2

1

1 1 2

2 sin

2

x

j kd x

x x

k

A d

j k

A = − ε kε

e

And:

2 1 1

2 2 2

2 1 1

x x x

d d d

j k j k j k

A e

=

A e

+

B e

, which can be rewritten as:

2 2 2

1 1

2 cos 2

x

j kd x

A d

A = k

e

We now find:

Equation 50

2 1

1

2 1

tan 2

x x

x

k k d

j k

ε ε

 

= −  

 

(14)

1.2.7.b Transcendental equations: Odd case At x=-d/2

Starting from:

1 2 2

2 2

1

1 1 2

2 cos

2

x

jdk x

x x

k

A d

A = εkε k

e

And:

2 1 1

2 2 2

2 1 1

x x x

d d d

j k j k j k

A e

=

A e

+

B e

, which can be rewritten as:

2 2 2

1 1

2 sin 2

x

j kd x

A d

j k

A = −

e

We now find:

Equation 51

2 1

1

2 1

cot 2

x x

x

k k d

j k

ε ε

 

=  

 

2. Periodically Arranged Openings

In this section, we study the propagation of an electromagnetic lightwave through an opening of width “d” which is a placed within a periodic array of openings with a periodicity denoted “P” (See Figure 3). As previously mentioned, the subscript “1” (“2”) is attributed to the parameters of region 1 (region 2) and two polarization states (TE and TM) will be successively considered. Once again, the goal is to describe the different steps leading to the transcendental equations, as can be found in [2]. In the following, we introduced the continuity of the field at the interfaces by assuming a null dephasing.

Figure 3: Opening (region 1) drilled in a material (region 2) with an infinite extent in the z direction, depicted over one period. The lightwave is propagating along the z direction.

(15)

2.1 TE polarization

2.1.1 General expression of the field For –d/2<x<+d/2

Equation 52

( )

1cos 1

y x

E = A xk

For x>+d/2

Equation 53

2cos 2

y 2 x

E A x Pk

=  −  

 

 

2.1.2 Continuity of the tangential component Ey At x=+d/2

Equation 54

1cos 1 2cos 2

2 x 2 2 x

d d P

AkA  k

= −

    

    

2.1.3 Continuity of the Hz component

Hz is related to Ey by the Maxwell’s equations through:

Equation 55

y

z

E j H

x ωµ

∂ = −

This implies that:

For –d/2<x<+d/2

Equation 56

( )

1

1 1

1

z sin x

H j k A xk

= − ωµ For x>+d/2

Equation 57

2

2 2

2

sin 2

z x x

A P

H k x k

ωµ

  

= −  −  

 

 

Due to the continuity of Hz: At x=+d/2

(16)

Equation 58

1 1sin 1 2 2sin 2

2 2 2

x x x x

d d P

k AkA k  k

= −

    

    

2.1.4 Transcendental equations

By dividing term by term the following formula:

1 1sin 1 2 2sin 2

2 2 2

x x x x

d d P

k AkA k  k

= −

    

    

1cos 1 2cos 2

2 x 2 2 x

d d P

AkA  k

= −

    

    

One can find:

Equation 59

1tan 1 2tan 2

2 2 2

x x x x

d d P

kkk  k

= − −

    

    

2.1.5 Example

So as to illustrate the equation above, we can study the same configuration as in section 1.1.8 (region 1 is air (n1=1), region 2 is a material with an optical index n2= 5+i and the width of the hole is set to 0.5 (in lambda units)) but in this example, a periodic condition along the x axis is introduced as shown on Figure 3. By setting P=2 (in lambda units), the x and z components of the wave vector can be computed again, which gives:

- kx(region 1)= 6.040-0.730i - kx(region 2)= 31.335+6.158i

- kz(region 1)= kz(region 2)= 2.552+1.729i

The normalized field profile of the lightwave propagating through this periodic array of subwavlength opening is reported in Figure 4.

(17)

Figure 4: Normalized field profile of an electromagnetic lightwave propagating in the direction indicated by the arrow (represented over one period for the first order). The field amplitude is maximum in the middle of

region 1 (air) and is decaying both laterally, towards the absorbing medium, and in the propagation direction.

2.2 TM polarization

2.2.1 General expression of the field For –d/2<x<+d/2

Equation 60

( )

1cos 1

y x

H =A xk

For x>+d/2

Equation 61

2cos 2

y 2 x

H A x Pk

=  −  

 

 

2.2.2 Continuity of the tangential component Hy At x=+d/2

Equation 62

1cos 1 2cos 2

2 x 2 2 x

d d P

AkA  k

= −

    

    

2.2.3 Continuity of the Ez component

Ez is related to Hy by the Maxwell’s equations through:

(18)

Equation 63

y

z

H j E

x ωε

∂ = +

This implies that:

For –d/2<x<+d/2

Equation 64

( )

1

1 1

1

z sin x

E j k A xk

= ωε For x>+d/2

Equation 65

2

2 2

2

sin 2

x

z x

k P

E j A x k

ωε

  

=  −  

 

 

Due to the continuity of Hz: At x=+d/2

Equation 66

1 2

1 1 2 2

1 2

sin sin

2 2 2

x x

x x

k d k d P

A k A k

ε ε

 

   

= −

    

    

2.2.4 Transcendental equations

By dividing term by term the following formula:

1 2

1 1 2 2

1 2

sin sin

2 2 2

x x

x x

k d k d P

A k A k

ε ε

 

   

= −

    

    

1cos 1 2cos 2

2 x 2 2 x

d d P

AkA  k

= −

    

    

One can find:

Equation 67

1 2

1 2

1 2

tan tan

2 2 2

x x

x x

k d k d P

k k

ε ε

 

   

= − −

    

    

(19)

3. References

[1] Tremblay P. Guide d’onde diélectrique à 3 couches. 38–49, 2007.

[2] Vadim Karagodsky, Forrest G. Sedgwick, and Connie J. Chang-Hasnain. Theoretical analysis of subwavelength high contrast grating reflectors. Opt. Express, 18(16):16973–

16988, Aug 2010.

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