A NNALES DE L ’I. H. P., SECTION A
F ERNANDO C ARDOSO V ESSELIN P ETKOV L UCHEZAR S TOYANOV
Singularities of the scattering kernel for generic obstacles
Annales de l’I. H. P., section A, tome 53, n
o4 (1990), p. 445-466
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445
Singularities of the scattering kernel for generic
obstacles
Fernando CARDOSO
Vesselin PETKOV and Luchezar STOYANOV Department of Mathematics, Universidade Federal de Pernambuco
50739 Recife, Brazil
Institute of Mathematics, Bulgarian Academy of Sciences 1090 Sofia, Bulgaria
Vol. 53, n° 4, 1990, Physique théorique
1. INTRODUCTION
Let Q c
n _> 3, n odd,
be an open connected domain with C~ smoothboundary
~SZ and boundedcomplement
The
scattering
kernel s(t, 8, 0)
related to the waveequation
in R x Q withDirichlet
boundary
conditions on !R x ~SZ has the form(see [8])
Here
(8, o)
Esn - 1
xS" -1, w (r,
x;co)
is the solution of theproblem
v is the interior unit normal to aS2
pointing
intoS2, dSx
is the measureinduced on
3Q, C~=(-l)~~~~2’"7r~’~ and ( , )
is the innerproduct
in (Rn.
Annales de l’Institut Henri Poincaré - Physique théorique - 0246-0211 1
Vol. 53/90/04/445/22/$5.20/ © Gauthier-Villars
For fixed o, e we have
s (t, 8,
~’ Theanalysis
of thesingulari-
ties of
s (t, 6, o)
for fixed co, e isimportant
for some inversescattering problems.
The aim of this paper is to
study sing
supps {t, 8, co)
forgeneral (nonconvex)
obstacles.By
areflecting (0), 0)-ray
inQ
we mean a continuous curvein 03A9
formedby
a finite number of linearsegments
and two infinite linearsegments -
anincoming
one with direction o and anoutgoing
one with direction 8(cf
section 2 for a
precise definition).
If areflecting (co, 9)-ray
y inQ
has nosegments tangent
to then y will be calledordinary.
By
ageneralized (00, 0)-ray
we mean an infinite continuous curve yin ~ incoming
with direction ~ andoutgoing
with direction e which is aprojection on Q
of ageneralized
bicharacteristic of the waveoperator
D= a; -
A(cf [9])
and which contains at least onegliding segment
which is ageodesic
on a~2 withrespect
to the standard Riemannian metric.Finally, by
a(co, 8)-ray
we mean either areflecting
or ageneralized (o, 0)-
ray.
Throughout
this paper we consideronly
null bicharacteristics ofD,
i. e. bicharacteristics
lying
in the characteristic set E of D(see [9]).
For fixed co, e we denote
by 2 ro,
9 the setof all (co,
Forconsider the
sojourn
timeT y
of y(see
section 2 for adefinition).
As it wassuggested
in[4], [1 1],
thesingularities
ofs (t, ~, c~)
are related to thesojourn
times of the8)-rays.
In[1 1], [16], [17]
for somespecial
classesof obstacles all
singularities of s (t, 8,
have been examined.According
to thegeometry
of thegeneralized
bicharacteristics of D(see [5], [22]),
there could be somepoints
on T*IR)
such that there are more than onegeneralized
bicharacteristicpassing through
them. We shall say that ageneralized
bicharacteristic ð of D isuniquelly
extendible if for every z E Õ theonly generalized
bicharacteristic of Dpassing through
z isð. A
(D, 8)-ray
y inQ
will be calleduniquelly
extendible if y is aprojection
on Q
of auniquelly
extendible bicharacteristic.Note that if K is convex or K has a real
analytic boundary,
then everye)-ray
inQ
isuniquelly
extendible. The same is true if a~ has nopoints
where the curvature of SQ vanishes of infinite orderalong
somedirection. Another
example
is the case when K is a finite union ofdisjoint
convex obstacles. We refer to
[22]
for anexample
when there exists a bicharacteristic which is notuniquelly
extendible.Let
Zi
1 be ahyperplane
in [FTorthogonal
to o and such that the openhalfspace,
determinedby Z~
andhaving
o as an inwardnormal,
containsSQ. Given
u E Z1, put
Denoteby Ct (u)
the set of those zeT*
(R x Q)
such that there exists ageneralized
bicharac-teristic of D with Y
(t)
= z. For V cZ i
setAnnales de l’Institut Henri Poincaré - Physique théorique
Our first result is the
following.
THEOREM 1~ - Let
be fixed.
Assume that every(c~., 8)-ray
in~2
isuniquelly
extendible. ThenRemark 1. l. - The
assumption
of Theorem I concernsonly
thee)-
rays. Thus for fixed o the relation
( 1. 3)
shows that if K isconnected,
then the shadow of K with
respect
to (D does not contribute tosing
supp s(t, e,
if we make some observations with raysincoming
withdirection co. Note that some bicharacteristics of D which are not related to
8)-rays
can be notuniquelly
extendible.Remark 1.2. - The
assumption.
of Theorem 1 is satisfied also for( - 6, 2014 (D)-rays.
This agrees with the relation s(t,
- o, -e)
= s(t, e, co).
Remark 1. 3. - Under
stronger assumptions concerning
the rays incom-ing
with directions ± 0), the relation(1 . 3)
was examined in[11]..
The inclusion
(1.3)
is similar to the Poisson relation for the distributionoc
~(~)~ ~ cos.Àj t, whe~re ~ 7~3 ~~° 1
is thespectrum
of theLaplace operator
i
in a bounded domain with smooth
boundary (see [I ], [13]).
From
physical point
of view it is moreinteresting
tostudy
the obstaclesfor which
( ~ ~. 3}.
becomes anequality.
This- makes itpossible
to recover allsingularities of s (t, 6, eo)
and to considerthem
asscattering
data(see [16]
for a result in this
direction).
One way t.o attack thisproblem
is to fixand to consider
generic
obstacles. We follow this way in thepresent
paper and show thatgenerically
for someordinary (o, 9)-rays
y we have-
Ty
Esing
supp s(t, 6, co). (1. 4) Recently,
one of the authors[21] proved
that forgeneric
obstacles intR~
(1.4)
holds for any(co, 0)-ray
y. Theproof
of this result is based onTheorem 2 stated below and the fact that for
fixed 03C9 ~ 03B8
and.generic
obstacles K in
1R3
there are nogeneralized (co, 8)-rays
in. thecomplement
ofK.
Another way to
study ( 1 . 3)
is to fix K and 03C9 and to considergeneric
directions e. For some obstacles K it is known
(see [16], [12])
that forevery fixed there exists a residual
subset ?(00)
of such thatfor every all
(co, e)-rays
in areordinary.
For such direc- tions we canapply
Theorem 1 and obtain(1.4)
for all(0), 6)-rays.
Weconjecture
that for each obstacle and each fixed 03C9 it ispossible
to find aresidual subset 9t
(co)
with theproperties
mentioned above.To. state our second result we need some notations.
Let X = ðfl and let Coo
(X,
be the spaceof
all Coo maps of X into f~n endowed with theWhitney topology (cf [3],
ch.II).
Thesubspace
Vol. 53, n° 4-1990.
C:mb (X, of
all C °°embeddings
is open in C*(X,
hence it is Baire space. A subset R of atopological
space Z is called residual if 9t is acountable intersection of open dense subsets of Z.
GivenfE C:mb (X,
denoteby
the unbounded domain withboundary f(X)
andby 2 eo,
e, f the setof
all(m, 03B8)-rays
in Let 9,f (resp.
9,
f)
be the setof
allordinary (resp. generalized) (0), 9)-rays
inn
f. The results of section4,
combined with those in[14], [1 5], imply
the existenceof a residual subset R of
C:mb (X,
such that for eachf ~ R
we haveIn
particular,
if e,f = 0,
then every(co, e)-ray
is anordinary
one.If y is an
ordinary (o, 6)-ray,
we denoteby x (resp. Yy)
the first(resp.
the
last)
reflectionpoint
of y. Letmy
be the number of reflections of y and letdJY (uy)
be the differential of the mapJ~
introduced in section 2.Here
Uy
is theorthogonal projection of x
onZl’ Finally,
setOur second result is the
following.
THEOREM 2. - Let
8 ~ ~ be fixed.
Then there exists a residual subset ~of (X, R)
suchthat for
eachf ~ A
holds,
wheres f (t, 0, (0)
is thescattering
kernel related toMoreover, for
t
sufficiently
close to -TY
with ~y ELeo,
9, f,T,~ ~
(~ f, we havewhere C =
(203C0)(1 -
n)/2(-1)m03B3-1 fv
and6Y
related to a Maslov index.For the
proof
of Theorem 1 we use the results in[9]
forpropagation
ofCoo
singularities.
The crucialpoint
is theapplication
ofProposition 3.1,
where wegeneralize
an idea usedpreviously
in[ 11 ] .
Given p
(t + to)
E(!R")
withsupport
in a smallneighbourhood of - to,
we need to examine the
asymptotic
ofThe results for
propagation
ofsingularities
of the solution of( 1. 2)
arenot sufficient since some critical
points
of thephase
of I(~,)
make contribu- tions which must be cancelled fromphysical point
of view. Thus we aregoing
to use astationary approach
connected with the(i X)-outgoing
Greenfunction.
The
proof
of Theorem 2 is basedessentially
on somegeneric properties
of
9)-rays
with linearsegments.
Theseproperties
are obtained in section4
following
theapproach
in[13], [19].
Some of theseproperties
have beenAnnales de l’Institut Henri Poincaré - Physique théorique
previously
announced in[20], [ 15] .
The formula( 1. 6)
has been obtained in[11].
The paper is
organized
as follows. In section 2 we collect some notationsand definitions. Theorem 1 is
proved
in section 3. In section 4 we considerseveral
generic properties
ofreflecting e)-rays
and prove Theorem 2.2. PRELIMINARIES
2.1.
By
a segment in ~n we mean either a finitesegment [x, y]
or aninfinite one, that is a
straightline
raystarting
at somepoint
andhaving
agiven
direction.Let X be a smooth
compact (n - 1 )-dimensional
submanifold off~n, n >_ 2. If ll
andl2
are twosegments
in (Rn with a common endXEX,
wesay
that II
andl2 satisfy
the lawof reflection
at x(with respect
toX)
ifh
and
l2
makeequal
acuteangles
with a normal vector to X at x andand v~ lie in a common two-dimensional
plane.
2.2. DEFINITION. - Let o and e be two fixed unit vectors in (Rn.
k
Consider a curve y = where
]
are finitesegments
fori =1, ...,~-1(~1),
for alli, lo (resp. lk)
is the infinitesegment starting
at xi(resp. xk)
andhaving
direction - o(resp. e).
Then the curvey is called a
reflecting (0), 8)-ray on
X if thefollowing
conditions aresatisfied:
(i)
the opensegments Ii
do not intersecttransversally X;
(ii)
eitherli (~ li + 1= ~ xI + 1 ~
for every~=0,1,...~-1
or~=2~+1(~=0,1,...),
for~=0,1, ...,~
and... , m~ ,
(iii)
for every i thesegments /,
andh + 1 satisfy
the law of reflection at~+1 with
respect
to X.The
points
x~, ... , x~ will be calledreflection points of
y. If y is of thesame form and has the above
properties except (i)
fori = k,
we shall saythat y is a
(00, 9)-trajectory
on X. Note that everyreflecting (0), 0)-ray
is a(o, 9)-trajectory,
but the converse is not true ingeneral
since the lastsegment (which
is infinite and has direction8)
of a(o), 03B8)-trajectory
couldintersect X. Mention also that the second
part
of(ii)
isonly possible
for6= -co.
2 . 3.
IRn)
and is a sequence of opensubsets of IRn
with U Uk=
(~" and X for every k. Assume in additionK
that 9l contains a residual subset of
C:mb(X, Uk)
for every k. Then it iseasily
seen that ? contains a residual subset ofC:mb (X,
Vol. 53, n° 4-1990.
2 . 4. Let co,
o E ~’~ -1
be fixed andUo
be an open ball with radii a- > 0containing
X. LetZl
andZ2
be thehyperplanes tangent
toUo
such thatZl (resp. Zz)
isorthogonal
to 03C9(resp. 8)
and thehalfspace H1 (resp.. H2),
determined
by Zl
and 03C9(resp. by 22, and - 8)
containsUQ.
Given areflecting (e), 6)-ray
y on X with successive reflectionpoints
xl, ... , x~, thesojou .rn
timeT~
of y(cf.
Guillemin[4])
is definedby
where -
~i
are theorthogonal projections. Clearly, T y
+ 2 a is thelength
of this-part
of y which liesin HI Pt H.
We defineTY
when y is a03B8)-trajectory
or ageneralized e)-ray
so thatT03B3 + 2a
is. thelength
of this
part
of y which lies inH1 n H2.
It is known[4]
that the definitionof
Ty
does notdepend
on the choice of the ballUo.
Set andassume that y is a
(co, 8)-trajectory
which has. nosegments. tangent
to X.Then there exists a
neighbourhood W~
ofUy
inZ~
such that for everyU E W y
there areunique
andpoints
..., xk(u)
E X whichare the successive reflection
points
of a(o,
e(u))-trajectory
on X withTTi
(Xl (M))==M.
We set thusobtaining
a mapThis map was also introduced
by
Guillemin[4].
Given a set A and an
integer s >_ 2,
we set3~. SINGULARITIES OF THE SCATTERING KERNEL
where is fixed. Here with some
sO and
F = Or
for t i.By ~’ (R
xQ)
we. denote the space of all distributions in R x Qadmitting
extensions as distributionson IRt
xde l’Institut Henri Poincaré - Physique théorique
Consider the
integral
For the
proof
of Theorem 1 we need thefollowing
PROPOSITION 3 1. - Assume that
for
~, 0 E ~1,
we haveProof -
.Choose two functions E(R), fi (x)
such that:For the distribution we obtain the
problem
with
By
.a finitespeed
ofpropagation argument
we conclude that for~Ti+28, ~j~T~+TB+2s.
This shows thatP
:issingular only
forT 1
+c + 2 e.
Then theassumption (3.1) implies
Since
VoL 53, .n° -4-1 990.
by
a standard argument wededuce
that for each m>Othere exists s(m)O
so that -
We can take the
partial
Fouriertransformation
withrespect
to t ofv
and
F.
PutThe
existence
of the Fouriertransformation
ofh (t, x) follows
from the fact that is contained in the set ofhyperbolic
andglancing points
of D(see [5], [9]).
We obtain theproblem
V is a i
~,-outgoing
solution.The latter
condition
meansthat for x ~ -.
co wehave
therepresentation
Here the
integrals
are taken in the sense ofdistributions
andG~ (x)
isthe
(~-outgoing
Greenfunction
of theoperator ¿B + À 2 (cf [7]).
Moreprecisely,
Notice that
for ) x ) -
co we haveWe set in
(3 . 3)
andmultiply (3 . 3) by r~n -1 »2 Taking
the limit as r - oo, we get
where the
integrals
are taken in the sense ofdistributions.
The condition(3 . 2)
shows that theright-hand
side of(3 . 4)
can beestimated by
O() À /- m)
Annales de l’Institut Henri Poincaré - Physique théorique
for all Thus we deduce
Next,
The left-hand side can be estimated
by
O(I À "")
and thiscompletes
theproof
ofProposition
3 . 1.Proof of
Theorem 1. - We shall recall someproperties
of thegeneralized
Hamiltonian flow established
by
Melrose andSjostrand [9].
Our assump- tionimplies
that if there exists ae)-ray
ypassing through
pu, thenCf(M)=y(~),
wherey (t)
is thegeneralized
bicharacteristic theprojection
of which on
Q
is y.Consider the map
Zl
x -Cr (u).
Melrose andSjöstrand proved (cf
Theorem 3 . 22 in[9], II)
that is continuous withrespect
to the metric D(p, Jl) (cl
section 3 in[9],
II for the definition of D(p,
Inparticular,
for fixed 8>0 and T > 0 there exists aneighbourhood
U of uo inZ~ such
that for each u E U and eacht E [ - Po, T]
we haveLet -
to
be fixed so thatChoose T > 0
with I to
T. Since the setis
closed,
we can findEo > 0
such thatVol. 53, n° 4-1990.
k =
0;
theanalysis
of the others iscompletely analoguous.
Obviously,
we have tostudy
thesingularities
of wfor
Without loss of
generality
we may assume thateo=(0, ...~0,1). Consider
the
hyperplane
where ’t -.p.o is fixed . For E
~o ~L~n-1),
x’ =(xl,
...~.xn_ 1),
con-sider the
Cauchy problem
where
~T = ~ t E ~ : t > i ~,
and the mixedproblem
Clearly,
there exists acompact
setFic
such that ifsupp (p;
n 0,
thenThen we obtain
Set For
Fo
denoteby
/ thestraight-
line ray issued from uo in direction co. Let has a direction 03C9 for Assume that
that is
I (uo)
meets 3Konly
atpoints,
whereI(uo)
istangent
to ~K. ThenI (uo)
is theprojection on Q
of auniquelly
extendible bicharacteristic yo(t)
of D which is determined
uniquelly by
the Hamiltonian flow of D.Consequently,Ct(uo)=.Yo(t). Choosing
a smallneighbourhood W (uo)
ofuo and
cp J
with supptp J (uo),
the results onpropagation
ofsingularities [9]
and thecontinuity
of the discussedabove, imply (3.7) for I t _ T.
Thus for such
W~
we have(3.8).
Annales de l’Institut Henri Poincaré - Physique théorique
If the case described above does not occur, then has common
points
with the interior of K. Denoteby
.x~(uo)
thepoint
on suchthat the
seg.ment (uo)]
is the maximal one which has no commonpoints
with the interior of K. There .are twopossibilities:
(1) /(Mo)
meetstransversally
oK at x~(2) 1 (uo)
istangential
to oK at xl(uo)
and 03C9 is anasymptotic
directionfor aI~ at xl
(uo).
In the case
( 1 )
wemodify vj
in the interior of K in a smallneighbourhood
of xi
(uo), provided
supp issufficiently
small. We denote the modifiedv~
by Vj
and arrange for + E1,where t1 (u) :
while .(9
(uo)
and ~1 are chosensufficiently
small. In the case(2)
werepeat
the sameprocedure modifying vj
in the interior of K. This ispossible
since
I (uo)
enters the interior of K.Clearly,
for tsufficiently
close to T.Extending hj
as 0for t T, denote
by wj
the solution of theproblem
It is easy to see that
Indeed,
observe that for small E > ~0 we havev; = 0;
forThen
8 ~ ~ yields
Choose a function cx~
{t) ~
such thatThen we .obtain
(3 ..-10) applying
theargument
of theproof
ofProposition
Vol. 53, n° 4-1990.
Thus it remains to
study (X). Next,
for each uo EFo, satisfying (1)
or
(2),
we introduce asufficiently
smallneighbourhood
(~(uo)
cZ1,
andwe take supp
(uo).
Thus thesingularities
ofw~
are localizedalong
the
generalized
raysy (uo)
issued fromu0 ~ F0
in direction co.There are two cases.
Then for
all t ~
T we obtainIndeed,
assume that for somei _ t
we can find ageneralized
bicharacteristic y(î; uo)
c such thatThen y
(6; uo)
has direction e for and we obtain a contradiction with(3 .11 ).
By using
thecontinuity
ofCr (uo)
withrespect
to t and uo, we can finda small
neighbourhood
so that for all and allNow
let 03B2 (x)
EC~0(Rn)
be a function such thatApplying
the results forpropagation
ofsingularities
and(3. 12),
we con-clude that
It is easy to see that the Fourier transform
exists. To check this it is sufficient to use the
(i ~,)-outgoing
condition andto prove that the solution of the
problem
is a
tempered
distribution withrespect
to A.de l’Institut Henri Poincaré - Physique théorique
Setting À)
=Ft -+). (F~),
as in theproof
ofProposition
3.1 we obtainThen
the
relation(3.13)
leads toCase B. - For some 1 we have
Then there exists a
generalized
bicharacteristicy (t; uo)
issued from uo in direction 03C9passing through
somepoint y
for t = po, with direction e. Theprojection
of y(t; uo)
onQ
is a(m, e)-ray
y, and ourassumption yields Ct (uo)
= y(t; uo).
LetTY
be thesojourn
time of y and letIntroduce the numbers
Notice that
T 2 ~ T 3’
Thenwhere
s T2
will be chosen below. Asimple geometrical argument yields
for
T2~t~T3. By (3 . 5)
we obtainFor small
(uo), supp 03C6j
c (P(uo) T3
thesingularities
ofwj
arecontained in a small
neighbourhood
of y(t; uo).
This makes itpossible
tochoose O
(uo)
andT2 - s
so small thatand
Vol. 53, n° 4-1990.
Moreover,
we take so that either~)~K
E ~~ andis a
glancing point
for D. In the latter case(3 .14) implies
Fixing s,
we conclude thatsince
So/2 ~
Õ and p§(( ~ 6 ) - ~
+to)
= 0 for(t, y) satisfying (3.15).
To deal with
I~g~),
we takesufficiently
small and arrangeTo do
this,
weexploit (3.14)
and thecontinuity
ofCs (u)
for u E W(uo).
Since
WF{wj)
isclosed,
we can choose £>0 so thatSimilarly,
we use(3.16)
.to arrangeNext,
we take ..a function (X2(t)
E(R)
such thatBy applying (3.19),
for weget
On the other
hand,
forWj
we canapply
thearguments
.of theproof
o.fProposition 3.1,
since D satisfies(3 .. 2)
as a consequence of(3.18)
and the fini.te
speed
ofpropagation
ofsingularities. Finally,
we concludethat
In this way for each
u0 ~ F0
we have chosen aneighbourhood
We obtain a
covering { {9 (uo) :
uo eF.o }
.ofFo,
.and w.e may assumeAnnales de l’Institut Henri Poincaré - Physique théorique
Let
for j= 1, ...,N, N~M,
thepoints satisfy
theassump.tions
in( 1 )
o.r(2).
Choose apartition
ofof Z1
so thatsupp c W
(u{o ~)~ for j= 1,
... ,N and (supp n ~o
=0 for j >
M . SetThen
Consequently,
in03A9
and we canreplace w by 5
inJ(03BB).
The:by (3.8), (3.10), (3.17), (3.20)
we conclude that -to ~ sing
supp s(t, 0, M
This
completes
theproof
of Theorem 1. ..4. SOME GENERIC PROPERTIES O.F
(co, 0)-TRAJECTORIES
In this section we will use several times the
following
result of[15}.
be a smo.oth- map. such that
for
everyi =1 ?
..., s there exists ri, 1~
ri~ p,
with
Hri (y) ~ 0 for
all y EU,
y = ... , Let L : U - Rq be asmooth map such that dL
(y) ~ 0. for
every y E U with L(y): =
0’. Denoteby
T’the set
of
those(X,
suchthat , f or
every criticalpoint
xof H fs
we have Then T contains a residual subset
of
. 0
This is Theorem 3.1
(B).
of[13],
where theassumption
for L isstronger,.
namely,
it is-required
that~L(y)~0
for every y in U.However,
theproof
in
[15]
holds without anychanges
if we assumeonly
for thoseYE U
with L(y)
= 0.k
Let y =
U /,
be a(D, e)-trajectory
on X withk ~ 2.
Thenlo and lk
;.=o
cannot be
orthogonal
to X at their endpoints.
If in addition for every i =I, ... , k -1, li
=[xi, 1 is
notorthogonal
to X at xi and xi + 1, then y will be called anon-symmetric (m, 03B8)-trajectory
on. X. In this case we setd (Y) = k - s (the defect of y),
where s is the number of all different reflectionpoints
o.f y. If someIi
isorthogonal
to Xat xt
or then we mustVol. 53, n° 4-1990.
m
have e = - co, the second
part
of(ii)
in 2. 2 issatisfied,
and y = wheret=0
lm
isorthogonal
to X at In this case y is areflecting 9)-ray,
itwill be called a
symmetric
onX,
and we setd (y) = m - s +
1. Notethat if y is a
non-symmetric (o, 03B8)-trajectory,
thend (y) = 0
means that y passesonly
oncethrough
each of its reflectionpoints.
Forsymmetric
y,d(y)=0
means that y passesexactly
twicethrough
each of its reflectionpoints excluding
that of them at which y isorthogonal
to X.The first main result in this section is the
following.
THEOREM 4 . 2. -
Let be the set of
thosefE (X,
such thatevery
(00, e)-trajectory
onf(X)
has zerodefect.
Then ~ contains a residualsubset
of (X,
This theorem can be
proved using arguments
similar to those in theproof
of Theorem A in[19].
Here weproceed
in a different wayapplying
Theorem 4.1 above. This way is
simpler
andshorter,
and can also be used tosimplify
theproofs
in[19]
and[ 15] .
We
begin
with a combinatorical classification of8)-trajectories,
simi-lar to that used in
[ 13], [19]
forperiodic reflecting
rays.Let
k >_ s >_ 2
beintegers
and letbe a map with
If
holds whenever then a will be called a ns-map. If
k = 2 m + 1, (4.2)
holds for1~’/~~
andthen a will be called a s-map.
In this section we will
always
assume that a is a ns-map or a s-map, andby
definition we setSo a will be considered as a map
As in
[ 13], [19]
we will use the notationAnnales de l’Institut Henri Poincaré - Physique théorique
Fix an open ball
Uo
in !R"containing X,
and letZI
and x; be as in subsection 2 . 4. For y =(y l ,
...,y~)
we set yo and ys+ ~ - 1tz~x~)-
Denoteby Vex
the set of those y EUo}
whichsatisfy
thefollowing
two conditions:and
for every
i =1,
..., s if m,j, r, t
are distinct elements ofI~ (a),
theneither yI, or y~, Yr, Yt are not collinear.
Then
U0152
is an open subset of and the mapdefined
by
is smooth. If yl, ..., ys are all different reflection
points
of a(o, 8)- trajectory
y on X such that ya (1)’ ..., ya (k) are the successive reflectionpoints
of y, then y will be called a(o, 8)-trajectory
oftype
a. In this casewe have
~=(~1,
..., E and F(y)
isjust
thelength
of thispart
of y which lies inHI n H2. Moreover, y
is a criticalpoint
of the mapIt is also clear that for every
(co, 8)-trajectory
y there exists asurjective
map a which is either a ns-map or a s-map such that y is of
type
a.Proof of
Theorem 4. 2. - Fix anarbitrary surjective
ns-map(4. 1)
extended
by (4 . 3),
and suppose k > s. Denoteby
the set of thosefe (X, Uo)
such that there are no(0), 03B8)-trajectories
oftype
aon f (X).
We are
going
to prove thatcontains
a residual subset of(X, Uo).
To this end we will use Theorem 4.1 for U = =
1,
and H = F : R.As in the
proof
of Lemma 4. 3 in[ 13],
one caneasily verify
that for every and everyi =1
s ..., s thereexists j=1,
... , n such that(y) # 0.
Here are the
components
of the vector yt E [R".Since
k > s,
there existsi =1,
..., s suchthat ~’~(/)~>1.
Take twodistinct
elements ji , j2
ofoc -1 (i).
Thenm = a ( j 1-1 ), j = a ( j 1 + I ),
r= a
U2 - 1),
t = a(j2
+1)
are distinct elements ofIi (a). Clearly,
{~j}~{0~+
1},
so either mor j
is not contained1}.
We mayassume
~~{0,~+1} (otherwise
we canexchange
the notation:Similarly,
we may assumeY ~ ~ 0, s + 1}.
SetVol. 53, n° 4-1990.
We have to check that if for some then
Suppose y ~ U03B1
andL(y) = 0. If ~L1 (y) = 0
for every /=1, ..., n, by
direct~
calculations
we find that is collinear with +Note that y U03B1 implies v ~ 0.
Since1 M==0
and ym-yi ~ym-yi~ and yj-yi ~yj-yi~
are unit vectors, we obtain that is also collinear with v. Therefore the
points
yi, ymand yj
are collinear.Suppose
also that for every /=1,
... , n. Then in the same wayW
one
gets
that and 3~~ are collinear which is a contradiction with HenceFinally,
note that if y1, ..., ys are the reflectionpoints
of a(0), 8)- trajectory
oftype
a, then fory=(y1, ..., ys) ~ U03B1
we haveL(y)=0. Now, applying
Theorem4.1,
we find thatqø0153
contains a residual subset of’
If e = - co and a is a
surjective
s-map-(4.1)
with k> 2 s -1,
theargument
above with minorchanges
shows that~ again
contains a residual subsetof
Uo).
We omit the details in this case.Finally,
mention that ~ =Pt !!fi 0153’
where ex runs over thesurjective
mapsa
(4.1) which
are either ~-maps with k>s or s-maps with ~>2~-1.Therefo..re £& contains a residual subset of
(X, UJ
which proves the theorem.THEOREM 4.3. -
Let be the set of
thoseR")
such thatevery two
different (co, 03B8)-trajectories on f(X)
have no commonreflection points.
Then contains a residual subsettR").
Proof -
We have to considerpairs
of ns- or s-maps. We deal in detailsonly
with the case of two /M-maps. The other cases arequite
similar.Let
Uo, Z,
and~(~=1,2)
be as above. For agiven Y=/(X), Uo),
suppose yi and Yz are two differentnon-symmetric (0), H)- trajectories
onY,
and let ..., ys be all reflectionpoints
of yi and Y 2 takentogether.
Then there existintegers k, /~
1 and ns-maps(4.1)
andsuch that
de l.’In.stitul Poincaré - Physique théorique
y03B1(1),...,y03B1(k)
are the successive reflectionpoints ofyi
andy03B2(
1), ...,y03B2
(l) are the successive reflectionpoints
of y2. In this case we will say that(1’1’ y2)
is apair
oftype (a, fl) . Set 03B2 (0) = - 1 and 03B2 (I + 1)
= s +2,
thusextending 03B2
to a mapWe will use the notation
y _ 1= ~ 1 (y~ t 1 >~,
YS + 2 - ~2~Ya ~~~) ~
Define Fby
(4 . 4)
and(4. 5)
and G :U~ ~ f~ by
Then and y is a critical
point
for bothand
G 0 fS.
Let
(a, P)
be apair
of maps(4 . 1 )
and(4 . 7)
with(4 . 8), (4 . 9)
andDenote
by ~a, ~
the set ofthose fe (X, Uo)
for which there is nopair
of
(0), 03B8)-trajectories
onf(X)
oftype (a,
To prove that03B1, 03B2
contains a residual subset of
(X, Uo),
weproceed exactly
as in theproof
of Theorem 4. 2. We omit the details.Denote
by
the set of thosef E (X,
such thatTs
for every two different(co, 03B8)-trajectories
y and 8on . f’(X),
and the set of thosesuch that
if y
is anon-symmetric (m, 03B8)-trajectory on f (X ),
then any two different
segments
of y are notparallel,
and if y is asymmetric (o, 8)-trajectory
onf(X),
then there are no differentparallel segments
among the first half of thesegments
of y.The
following generic properties
of(o, 03B8)-trajectories
will beimportant.
THEOREM 4 . 4. - Each
of
the sets !7 contains a residual subsetof (X,
Proof -
We dealagain
with the intersections of and P withC mb (X, Uo).
whereUo
is a fixed open ballcontaining
X.If for two different
(03C9,03B8)-trajectories
y and Ö onY = f’(X), n ~.
there exist different elements such that yl, ... , Ykare the successive reflection
points
of y for somek s,
whileare the successive reflection
points
of 8.Moreover, F (y) = G (y),
whereF,
G : U - R are defined
by
Vol. 53, n° 4-1990.
Here U is the set of those such that for all
i = 2, ... , k - 1
andi = k + 1, ... , s - l , yk ~ [yk-1,
1t2Yk + 2~ ~
andApplying
Theorem 3 . 1 forH = (F, G) and L:U-~[R, L (y) = F (y) - G (y),
we obtain thatcontains a residual
subset
of(X, Uo).
Sincewe deduce that ~ contains a residual subset of
(X, Uo).
To deal with # we define F
by (4 .11 )
withk = s, exchanging
Usuitably.
For fixed
i and j
with 1~ i j _ s
we use the function L : U -~R",
where and to express the fact that
yL+
1]
and1]
areparallel.
We omit the details.Proof of
Theorem 2. - Denoteby
ff the set of thosef E (X, 0~‘~)
such that every
03B8)-trajectory of f(X)
has nosegments tangent
toI(X)
and det
dJy
# 0(cf
subsection2 . 4).
It followsby [14], [ 15]
that if we defineff’ in the same way
by
means ofreflecting (co, 8)-rays
instead of(co, 6)- trajectories,
then J ’ contains a residual subset of(X, Rn).
The sameargument
shows that ff has thisproperty,
too.Next,
denoteby
X the set of thosef E (X,
such that for everyYEf(X)
there are no directions0 ~
such that the curvatureof f(X) at y
withrespect
to v vanishes of order 2 n - 3. It can be derived from the results of Landis[6]
that Jf contains a residual subset of(X,
contains a residual subset of(X, R~).
We will show that the inclusion(1 4)
holds forprovided fEd.
Denote
by 200, e
the set of all8)-ray
in Note that the set is closed.Instead,
assume that for every m~N andTo. By
a standard argument we deduce the existence of a(co, 8)-ray
Yo with
sojourn
timeTo. Moreover,
thestarting point
of Yo is a limitpoint
of the set ofstarting
of the rays ym. If yo is formedonly by
linearsegments,
then all thesesegments
are nottangent to I(X), since f ~ J.
On the otherhand, if Yo
isordinary, then f ~ J
showsthat the rays
starting
in a smallneighbourhood
of z o inZi with
direction(D are not
(co, 8)-rays.
Thus Yo Eg03C9,
e fand f
is closed.Let y E e
(S2 f)
be anordinary reflecting (0), 0)-ray
withsojourn
timeTy. Since f ~ ~ P ~ J
and acontinuity argument implies
thatfor some
Eo >0
we have[Ty -
Eo,TY
+Eo]
for all Ö E ey ~ .
Annales de l’Institut Henri Poincaré - Physique théorique